The an unknown weak acid with a concentration of 0.070 m has a ph of 1.80. what is the ka of the weak acid?

Answers

Answer 1

The Ka of the unknown weak acid is approximately 4.64 * \(10^{-4}\).

How to find the acid dissociation constant?

To determine the Ka of the unknown weak acid with a concentration of 0.070 M and a pH of 1.80, follow these steps:

1. First, find the H+ ion concentration using the pH formula: pH = -log[H+]. In this case, the pH is given as 1.80.
2. Calculate the H+ ion concentration: [H+] = 10^(-pH) = 10^(-1.80) = 0.0158 M.
3. Now, set up the expression for the Ka of the weak acid: Ka = ([H+][A-])/[HA], where [HA] is the concentration of the weak acid, [H+] is the concentration of the H+ ions, and [A-] is the concentration of the conjugate base.
4. Since the weak acid only partially dissociates, the change in [HA] and [A-] can be represented as: [HA] = 0.070 - x, and [A-] = x, where x is the change in concentration due to dissociation. Also, [H+] = 0.0158, which is approximately equal to x (as the contribution of H+ ions from the weak acid is significant).
5. Substitute the values into the Ka expression: Ka = (0.0158 * 0.0158) / (0.070 - 0.0158).
6. Solve for Ka: Ka ≈ (0.0158^2) / 0.0542 ≈ 4.64 * 10^(-4).

The Ka of the unknown weak acid is approximately 4.64 * \(10^{-4}\).

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Related Questions

What do you call a rock that cooled rapidly outside a
volcano?

What do you call a rock that cooled rapidly outside avolcano?

Answers

Explanation:

intrusive rocks.....

.

The beaker contains a 25% salt solution and the bag inside contains pure water. The bag is semi-permeable. A: Explain which direction the water will move. B: explain a scenario where water might move the other direction

Answers

The direction of the water between the beaker containing a 25% salt solution and the bag inside with pure water would be from beaker to bag with pure water.

If the beaker had pure water and the bag with salt solution, the water would move from bag to beaker with pure water.

The beaker has salt solution (salt (solute) + water (solvent)). The bag has pure water without any solute. The water normally moves from higher concentration to lower concentration.

Water containing solute would have higher concentration than pure water. Thus, water moves from beaker with higher concentration to bag with lower concentration. The process is called osmosis.

Similarly, if we change the components in beaker and bag, the water would move from bag with higher concentration to beaker with pure water of lower concentration.

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Which of the following best describes hair? O Hair is made of mostly tightly packed living cells Hair does not help control body temperature. O Hair growth occurs in the hair follicle O Hair grows at 2.5mm a month.​

Answers

Answer:

(A) Hair is made of mostly tightly packed living cells.

Explanation:

i just took the exam :) yw

a like would be nice thanks!

Answer:

A

Explanation:

Just did the exam :) Good Luck!

The concentration of barium ion, Ba2+, in solution is 0.010 M.
a) What concentration of sulfate ion, SO42–, is required to begin precipitation of BaSO4?
b) When enough SO42– has been added so that the concentration of sulfate ion in solution reaches 0.015 M, what concentration of Ba2+ will remain in solution?

Answers

a) To begin precipitation of BaSO₄, a concentration of at least 87 M of sulphate ion is required.

b) When the concentration of sulphate ion reaches 0.015 M, the concentration of Ba₂⁺ remaining in solution is 7.3 x 10⁻⁹ M.

(a) The concentration of sulfate ion required to begin precipitation of BaSO₄ can be calculated using the solubility product constant (Ksp) of BaSO₄. The Ksp expression for BaSO₄ is:

 Ksp = [Ba₂⁺][SO₄²⁻]

At the point of precipitation, the concentration of Ba₂⁺ that reacts with SO₄²⁻ to form a solid BaSO₄ is equal to the concentration of Ba₂⁺ that remains in solution. Therefore, we can assume that the concentration of Ba₂⁺ in solution is equal to the solubility of BaSO₄.

Solving for the concentration of SO₄²⁻:

   Ksp = [Ba₂⁺][SO₄²⁻]

          = (solubility)² [SO₄²⁻]

⇒    0.010 = (solubility)² [SO₄²⁻]

⇒   [SO₄²⁻] = 0.010/(solubility)²

The solubility of BaSO₄ can be found in a reference table or calculated from its Ksp value. For BaSO₄, Ksp = 1.1 x 10⁻¹⁰, so:

⇒      solubility =√(Ksp)

                     =√(1.1 x 10⁻¹⁰)

                    = 1.05 x 10⁻⁵ M

Substituting the solubility into the expression for [SO₄²⁻], we get:

[SO₄²⁻] = 0.010/(1.05 x 10⁻⁵)² = 87 M

Therefore, a concentration of at least 87 M of sulfate ion is required to begin precipitation of BaSO₄.

(b) When the concentration of sulfate ion reaches 0.015 M, the concentration of Ba₂⁺ remaining in solution can be calculated using the Ksp expression and the initial concentration of Ba₂⁺:

⇒               Ksp = [Ba₂⁺][SO₄²⁻]

⇒       1.1 x 10⁻¹⁰ = [Ba₂⁺](0.015)

⇒            [Ba₂⁺] = (1.1 x 10⁻¹⁰)/0.015

                         = 7.3 x 10⁻⁹ M

Therefore, the concentration of Ba₂⁺ remaining in solution is 7.3 x 10⁻⁹ M when the concentration of sulfate ion reaches 0.015 M.

The solubility product constant Ksp can be used to calculate the concentration of ions in solution at the point of precipitation of a sparingly soluble salt like BaSO₄. The concentration of Ba₂⁺ remaining in solution after precipitation begins can be calculated using the initial concentration of Ba₂⁺ and the concentration of sulfate ion in solution.

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Can someone please help me

Can someone please help me

Answers

Answer:

its ez

Explanation:

f=ma

Using the following equation:
2NaOH + H2SO4 = 2H2O + NaSO4
How many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid?

Answers

Taking into account the reaction stoichiometry, 355 grams of Na₂SO₄ will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid.

Reaction stoichiometry

In first place, the balanced reaction is:

H₂SO₄ + 2 NaOH  → Na₂SO₄ + 2 H₂O

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

H₂SO₄: 1 moleNaOH: 2 moles  Na₂SO₄: 1 moleH₂O: 2 moles

The molar mass of the compounds is:

H₂SO₄: 98 g/moleNaOH: 40 g/moleNa₂SO₄: 142 g/moleH₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂SO₄: 1 mole× 98 g/mole= 98 gramsNaOH: 2 moles× 40 g/mole= 80 gramsNa₂SO₄: 1 mole× 142 g/mole= 142 gramsH₂O: 2 moles× 18 g/mole= 36 grams

Mass of Na₂SO₄ formed

It can be applied the following rule of three: if by reaction stoichiometry 80 grams of NaOH form 142 grams of Na₂SO₄, 200 grams of NaOH form how much mass of Na₂SO₄?

mass of Na₂SO₄= (142 grams of Na₂SO₄×200 grams of NaOH) ÷80 grams of NaOH

mass of Na₂SO₄= 355 grams

Finally, 355 grams of Na₂SO₄ are formed.

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identify the label(s) required for 12 kg of un1454, calcium nitrate to be transported on a passenger aircraft.

Answers

The label(s) required for the transportation of 12 kg of UN1454 calcium nitrate on a passenger aircraft would include the UN number and the appropriate hazard warning labels.

When transporting hazardous materials on a passenger aircraft, specific labeling requirements must be followed to ensure safety. In the case of 12 kg of UN1454 calcium nitrate, there are certain labels that need to be applied to the packaging.

Firstly, the package should bear the UN number "UN1454," which is the unique identifier for calcium nitrate as designated by the United Nations. This number helps to identify the specific substance being transported.

Secondly, appropriate hazard warning labels should be affixed to the package. These labels typically include symbols and text indicating the hazards associated with the substance. In the case of calcium nitrate, which is considered an oxidizing substance, the appropriate hazard warning label would be the Class 5.1 Oxidizing Agent label.

These labels serve as visual indicators for handlers and transport personnel, highlighting the nature of the substance being transported and ensuring that proper precautions are taken during handling, loading, and unloading of the package on the passenger aircraft.

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did you notice any significant changes when the congo red fabric was treated with acid

Answers

Yes, there were significant changes observed when the Congo red fabric was treated with acid.

Congo red is a pH indicator dye that changes color depending on the acidity or alkalinity of the solution it is in. When the Congo red fabric is treated with an acid, the pH of the solution around the fabric decreases, causing the dye to shift from a reddish color to a blue-green color. This color change indicates a significant change in the pH level of the fabric, which can affect its properties and potential uses.

Thus, the observation of a color change in the fabric after treatment with acid can be considered a significant change.

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Directions: Identify each chemical equation as a synthesis, decomposition,
single-displacementor, or double displacement reaction.
a. Synthesis b. Decomposition c. Single Displacementor
d. Double Displacement
9.2H2O(→ 2H2(9 +0f9
10.0129 +2KBr(aq) + 2KBr(aq) + Bry()
11. CaO3 + H2O() - Ca(OH)() (
12. HCl(aq) + NaOH(aq) → NaCl(aq) + H2O()
+

Directions: Identify each chemical equation as a synthesis, decomposition,single-displacementor, or double

Answers

Answer: 9. decomposition 10. single displacement 11. synthesis 12. double displacement

Explanation: just know I know

Given the standard enthalpy changes for the following two reactions
Given the standard enthalpy changes for the following two reactions:



(1) 2C(s) + 2H2(g)C2H4(g)...... ΔH° = 52.3 kJ



(2) 2C(s) + 3H2(g)C2H6(g)......ΔH° = -84.7 kJ



what is the standard enthalpy change for the reaction:



(3) C2H4(g) + H2(g)C2H6(g)......ΔH° = ?

Answers

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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A 25. 0-ml sample of 0. 150 m hydrocyanic acid is titrated with a 0. 150 m naoh solution. What is the ph beforeany base is added? the ka of hydrocyanic acid is 4. 9 × 10-10.

Answers

Answer:

stars,auroras,a neon sign

Explanation:

just did it

what is the number of moles of co2 in a 220 gram sample of co2

Answers

The number of moles of CO2 in a 220 gram sample can be calculated by dividing the mass of the sample by the molar mass of CO2.

The molar mass of CO2 (carbon dioxide) is calculated by adding the atomic masses of carbon (C) and oxygen (O) in one mole of CO2. The atomic mass of carbon is approximately 12.01 grams/mol, and the atomic mass of oxygen is approximately 16.00 grams/mol (rounded values).

Therefore, the molar mass of CO2 is approximately 12.01 + (16.00 x 2) = 44.01 grams/mol. To determine the number of moles of CO2 in a 220 gram sample, divide the mass of the sample (220 grams) by the molar mass of CO2 (44.01 grams/mol). The result will be the number of moles of CO2 in the given sample.

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Question 13
You would like to determine whether a specific substrate concentration has an effect on the velocity of a chemical reaction. You conducted total of 30 experiments, in which 15 experiments use a substrate concentration of 1.5 moles per liter, and the other 15 experiments using a substrate concentration of 2.0 moles per liter. Let the average velocity of a chemical reaction using the 1.5 moles per liter substrate, and 2 velocity of a chemical reaction using the 2.0 moles per liter substrate. What type of hypothesis test would you use?
One mean
Two mean unpaired
Two mean paired
One-sided lower tail
One-sided upper tail
Two sided Question 15
The PSU Creamery would like to determine whether there is a significant difference in the calorie content of Mint Nittany ice cream when two different types of milk, A and B are used. By using the lot number, a food scientist can determine whether Type A or Type B milk was used as a raw ingredient. This scientist collects 20 samples where Type A milk was used and 25 samples where Type B milk was used. The food scientist found that for a ½ cup serving size, the samples where Type A milk was used had an average of 169.2 calories with a standard deviation of 11.1; samples where Type B milk was used had an average of 181.2 calories with a standard deviation of 20.2. Assume that the caloric contents were normally distributed, and that a level of significance of 1% be used.
One mean
Two mean unpaired
Two mean paired
One-sided lower tail
One-sided upper tail
Two sided
Z test statistic
Ottest statistic

Answers

Two mean unpaired is the type of hypothesis test you should use. If the caloric contents were normally distributed, and that a level of significance of 1% be used you should use two mean unpaired hypothesis test. Option B is correct.

13: Since you have two independent groups (1.5 moles per liter and 2.0 moles per liter), and you want to compare the means of these two groups, you would use a Two mean unpaired hypothesis test. This test compares the means of two independent groups to determine if there is a significant difference between them.

Therefore, Option B is correct.

15: Since you have two independent groups (Type A milk and Type B milk) you would also use a Two mean unpaired hypothesis test.

Therefore, Option B is correct.

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Suppose the car now accelerates from 0 m/s to 30. 0 m/s in 5. 00 s. If the wheels have a radius of 24. 1 cm, what is their angular acceleration?.

Answers

If the car now accelerates from 0 m/s to 30. 0 m/s in 5. 00 s. If the wheels have a radius of 24. 1 cm, then their angular acceleration is 24.9 rad/s².

To calculate the angular acceleration of the car's wheels, we need to first find their angular velocity. We know that the car accelerates from 0 m/s to 30.0 m/s in 5.00 s, so we can calculate the average acceleration:

a = (vf - vi)/t = (30.0 m/s - 0 m/s)/5.00 s = 6.00 m/s²

Next, we can use the formula for linear acceleration in terms of angular acceleration and radius:

a = αr

where α is the angular acceleration and r is the radius of the wheels. Solving for α, we get:

α = a/r = 6.00 m/s² / 0.241 m = 24.9 rad/s²

Therefore, the angular acceleration of the car's wheels is 24.9 rad/s².

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2. Which metal reacted most vigorously when placed in the acid? Give evidence to
support your answer.

Answers

Answer:

The alkali metals (Li, Na, K, Rb, Cs, and Fr) are the most reactive metals in the periodic table – they all react vigorously or even explosively with cold water, resulting in the displacement of hydrogen.

Explanation:

The metal that reacted most vigorously when placed in the acid is sodium, as it is an alkali metal.

What are alkali metals?

At standard temperature and pressure, all of the bright, soft, extremely reactive alkali metals rapidly shed their outermost electron to create cations with charge +1.

One of the most reactive metals is the alkali metal. They have greater atomic radii and low ionization energies, which contribute to this. They have an oxidation state of 1, and they frequently give electrons during reactions. These metals stand out for their supple texture and silvery hue.

The alkali metals (Li, Na, K, Rb, Cs, and Fr) are the most reactive metals in the periodic table – they all react vigorously or even explosively with cold water, resulting in the displacement of hydrogen.

Therefore, the correct option is d. sodium.

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The question is incomplete. Your most probably complete question is given below:

Oxygen

magnesium

iron

sodium

The reaction A -> B is catalyzed by an enzyme that follows Michaelis-Menton kinetics. If the initial rate of the reaction is measured under conditions where [A] = 2/3Km, at what percentage of Vmax will the velocity of the reaction be

Answers

The velocity of the reaction under the given condition is 40% of Vmax. So the answer is 40%

Given: The reaction A → B is catalyzed by an enzyme that follows Michaelis-Menton kinetics.

If the initial rate of the reaction is measured under conditions where [A] = 2/3Km, at

We are supposed to determine the percentage of Vmax for the reaction which is catalyzed by an enzyme that follows Michaelis-Menton kinetics.

Let us first write down the equation for Michaelis-Menton Kinetics: V = Vmax * [S]/([S] + Km )Initial velocity of the reaction can be calculated using the Michaelis-Menton equation.

When [S] = Km, V=Vmax/2When [S] = 2Km, V=Vmax(2/3)Vmax is the maximum velocity attained by the reaction.

Therefore the percentage of Vmax for the reaction under the given conditions

where [A] = 2/3Km can be calculated as follows:[A] = 2/3Km  => [S] = 2/3Km

Substituting the values in the Michaelis-Menton equation: V = Vmax * [S]/([S] + Km )

V = Vmax * (2/3Km) / [(2/3Km) + Km]

V = Vmax * (2/3) / (5/3) = 2/5

Vmax, Therefore, the velocity of the reaction under the given condition is 40% of Vmax. So the answer is 40%.

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1.Which type of text structure describes events in sequential order? A.sequence B.Cause and Effect. C. Problem And Solution. D. Compare and Contrast



2.This type of writing considers similarities and differences
A.Discripsion B.Compare and Contrast C. Sequence. D.Cause and Effect


3.in this type of writing,the reader will see words/phrases such as cause,as a result of,and due to.
A.Cause and Effect
B.Promlem and Solution
C.Order And Sequence
D.Compare And Contrast​

Answers

Answer:

1 would be a. sequence

2 would be b. compare and contrast

3 would be a. cause and effect

27.5 cm³ of a solution of NaOH neutralizes 25.0cm³ of 0.5 MHCL solution. Calculate the
concentration of NaOH in
b. gdm
a. Moldm-3

Answers

a)The concentration of NaOH in g/dm³ is approximately 18.18 g/dm³, and b)The concentration in mol/dm³ is approximately 0.4545 mol/dm³.

a)To calculate the concentration of NaOH in g/dm³ (grams per cubic decimeter) and mol/dm³ (moles per cubic decimeter), we need to know the amount of NaOH used in the reaction and the volume of the NaOH solution.

From the given information, we have:

Volume of NaOH solution = 27.5 cm³

Volume of HCl solution = 25.0 cm³

Molarity of HCl solution = 0.5 M

Since the reaction between NaOH and HCl is a 1:1 stoichiometric ratio, the moles of NaOH used can be determined from the moles of HCl used:

Moles of HCl = Molarity × Volume = 0.5 M × 25.0 cm³ = 12.5 mmol (millimoles)

Since the moles of NaOH used is also equal to the moles of HCl, we have:

Moles of NaOH = 12.5 mmol

b)To calculate the concentration of NaOH in g/dm³, we need to convert moles to grams using the molar mass of NaOH, which is approximately 40 g/mol:

Mass of NaOH = Moles × Molar mass = 12.5 mmol × 40 g/mol = 500 g

Now, we can calculate the concentration in g/dm³:

Concentration of NaOH (g/dm³) = Mass of NaOH / Volume of NaOH solution

= 500 g / 27.5 cm³

≈ 18.18 g/dm³

To calculate the concentration of NaOH in mol/dm³, we can use the same approach:

Concentration of NaOH (mol/dm³) = Moles of NaOH / Volume of NaOH solution

= 12.5 mmol / 27.5 cm³

≈ 0.4545 mol/dm³

Therefore, the concentration of NaOH in g/dm³ is approximately 18.18 g/dm³, and the concentration in mol/dm³ is approximately 0.4545 mol/dm³.

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what is a mixture of elements and compounds

what is a mixture of elements and compounds

Answers

The substance in the image above would be classified as a mixture of elements (option E).

What is a compound and mixture?

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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In a new social setting, strangers __________. experience very few situations as potentially problematic lack the natives' knowledge of shared realities are not aware of things unnoticed by the natives are typically treated as equals with natives

Answers

In a new social setting, strangers usually. experience very few situations as potentially problematic lack the natives' knowledge of shared realities are not aware of things unnoticed by the natives are typically treated as equals with natives

Based on the given answer choices, the most appropriate answer is a. Strangers experience very few situations as potentially problematic. In a new social setting, strangers typically encounter unfamiliar situations and interactions.

They may not have prior knowledge or shared realities of the environment or the people they are interacting with. However, it doesn't necessarily mean that every situation is perceived as potentially problematic.

While it is true that strangers may lack the natives' knowledge of shared realities and may not be aware of certain things unnoticed by the natives, it does not imply that all situations are problematic. People entering new social settings often exhibit curiosity, adaptability

The behavior of strangers in a new social setting can vary depending on individual personalities, cultural backgrounds, and previous experiences. While some individuals may feel discomfort or hesitation in unfamiliar situations, others may embrace the opportunity to connect with new people and explore different social dynamics

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a student is testing a solid material to determine whether it is a pure substance or a mixture which observation would much likely indicate the material is a mixture.

Answers

Answer:

the material has two different color crystals

Explanation:

There are two types of mixture, one is homogeneous mixture and other is heterogeneous mixture. Therefore, If the material has two different color crystals, then we can see  whether material is a pure substance or a mixture.

What is mixture?

When two or more compounds are combined but each ingredient retains its chemical identity, the result is referred to as a mixture. In other words, there is no chemical interaction between the parts of a combination.

According to how consistent they are and how well the components' particle sizes match up, mixtures are categorized. If the material has two different color crystals, then we can see  whether material is a pure substance or a mixture.

Therefore, if the material has two different color crystals, then we can see  whether material is a pure substance or a mixture.

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please helpppppppp
helpppppppppppppppppppppppppppp

please helpppppppphelpppppppppppppppppppppppppppp

Answers

Protons are positive

If a screwdriver was used to pry open a door, where would scratches/striations be found?

Answers

Answer: Most likely around the knob area or by the bolts that hold the door up.

Explanation:

If you attempted to pry open a locked window with a screwdriver, the screwdriver would leave a tool mark on the window and windowsill.

The impressions made by a tool when it comes in contact with an object are called as tool marks. These tool marks exhibit a variety of impressions depending upon the type of tool, its shape and its use. They are classified into different types depending upon the force with which they are made.

The study of tool marks is very useful in forensic science which includes information about the analysis of tool marks at the crime scene and in the laboratory, the interpretation and assessment of challenges for examination and interpretation and also the way in which tool mark evidence can be presented in a courtroom.

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I need itttttt pleasee somebobdy answer my question

I need itttttt pleasee somebobdy answer my question

Answers

Choice 3 2 of c 8 of h 6 of o

I need help with question 2 please help quickly this is due in 3 hours! For this activity,
you need to find reliable Internet or library sources about energy resources. You will
research their advantages and disadvantages. Advantages are positive impacts, or
benefits. Disadvantages are negative impacts. Resources include coal, oil, natural gas,
nuclear power, biomass, wind, hydropower, geothermal energy, and solar energy. Their
positive and negative effects can depend on how they are obtained and the pollution they
cause when used. Their effects may also depend on how much the resource we use.
How much we use a resource can be described by its per capita consumption.
I
Part 1: Identifying Sources (5 points)
2. Identify three websites you will use to start your research. If you use other websites to
complete the research questions in Part 2, add them to this list. Cross out any websites
that don't end up helping you complete the activity. (3 points)

I need help with question 2 please help quickly this is due in 3 hours! For this activity,you need to

Answers

Coal is abundant and cost-effective, providing stable energy.

Coal extraction damages the environment, and burning it releases high levels of CO2 and air pollutants. Oil has high energy density and infrastructure, but its combustion contributes to climate change and spills cause environmental harm.

Natural gas emits less CO2, is versatile, and is abundant, but extraction techniques like fracking can harm ecosystems and water resources. Nuclear power produces large amounts of electricity without CO2 emissions but faces concerns about radioactive waste disposal and safety risks. Biomass is renewable but competes with food production and can release emissions.

Wind, solar, hydro, and geothermal offer renewable sources, but their scalability, intermittency, and land use impacts vary. Per capita, consumption affects the magnitude of their environmental effects.

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Which material from the table is a liquid at 50°C and a gas at 300°C?

Which material from the table is a liquid at 50C and a gas at 300C?

Answers

Answer:

Phosphorus

Explanation:

Melting point is the exact temperature where it changes from solid to liquid. So if the temp 50°C, it is higher than 44°C meaning that the element already melted and is staying as a liquid.

Boiling point is the exact temperature where it changes from liquid to gas. So if the temp 300°C, it is higher than 28°C meaning that the element already evaporated and is staying as a gas.

Is Geology chemistry?

Answers

yes geology is chemistry
Geology is a form of science as they look for nutrients in the ground ect

What is 0.866 km to mm in scientific notation

Answers

Answer:

866000

Explanation:

because one kilometer (km) = 1000000 millimeters (mm)

The amount of chlorine added to water minus its chlorine residual equal?
a) The combined chlorine residual
b) The chlorine demand
c) The free chlorine residual
d) The total chlorine residual

Answers

The amount of chlorine added to water minus its chlorine residual equals: b) The chlorine demand

The difference between the amount of chlorine applied to water or wastewater and the amount of residual chlorine left after a specific contact time is known as chlorine demand. With dosage, time, temperature, pH, and the kind and quantity of contaminants in the water, chlorine demand may alter.

Chlorine Demand = Chlorine Applied - Chlorine Residue

The correct answer is, The amount of chlorine added to water minus its chlorine residual equals: b) The chlorine demand

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how many atoms are in 3.5 moles of arsenic atoms?

Answers

Answer:

1 mol of atoms = 6.022 ×1023 atoms. 3.5mol × 6.022 × 1023 atoms 1mol = 2.11 × 1024 atoms =.........

Explanation:

2160.64 atoms!

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