The correct option is A.
The advantage of using the scientific method is that it is having a well-cautious building of evidence-based understanding that is dependable and logical.
The scientific method includes rigorous observation in addition to logic as a system of reasoning for organizing but for deducing beyond what is known from observation. Induction, prediction, and analogy are only a few examples of different reasoning techniques.
Evidence, as used in legal contexts, is generally defined as information, facts, or data that supports (or refutes) a claim, assumption, or hypothesis. In reality, anything could qualify as proof provided it is deemed to be true, trustworthy, and pertinent.
Although scientists frequently utilize evidence in other ways, such as when applying ideas to real-world issues, scientific evidence is evidence that helps to either support or refute a scientific theory or hypothesis.
Generally speaking, scientific evidence is founded on the knowledge that has been acquired via the application of the scientific method. This indicates that the evidence's underlying assumptions have undergone testing and general acceptance in the scientific community.
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Please LOTS OF POINTS. WILL MARK BRAINLIEST
Calculate the Resulting movement using the formula:
Perpendicular distance x Force
1]F1*D1=F2*D2
10N×2m=5N*3m
20N=15Nm
The seesaw will turn anti clock wise.
2]
F1*D1=F2*D2
3N*4m=2N*6m
12Nm=12Nm
It will neither rotate toward anti clock wise nor clock wise
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air? Part 1 of 2 The speed of the plane in still air is Part 2
The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.
Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.
The distance traveled with the wind in 3 hours is 408 miles.
Therefore, we can write the equation as:
3(x + y) = 408
Divide both sides by 3:
x + y = 136 .... (1)
The distance traveled against the wind in 4 hours is also 408 miles.
Therefore, the equation can be written as:
4(x - y) = 408
Divide both sides by 4:
x - y = 102 .... (2)
Now we can solve these two equations using the elimination method.
Add equations (1) and (2):
x + y + x - y = 136 + 1022x = 238x = 119 mph
Therefore, the speed of the plane in still air is 119 mph.
Now, substitute this value of x in equation (1):
119 + y = 136y = 17 mph
Therefore, the speed of the wind is 17 mph.
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The correct question is:
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?
Which of the following is true of Earth’s atmosphere?
A. It is mostly made up CO2.
B. It gets more dense as you go higher in altitude.
C. It has more nitrogen than oxygen.
D. No one has ever been above it.
Answer:
c) It has more nitrogen than oxygen.
Explanation:
Our Earth’s atmosphere has more nitrogen (78%) than oxygen (21%). Hence, the option (c) is the correct answer.
Answer:
C. It has more nitrogen than oxygen.
Explanation:
Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases. These gases are found in layers (troposphere, stratosphere, mesosphere, thermosphere, and exosphere).
Please help!!! 80 feet/sec to miles / hour
Test populations are studied. Population one is found to obey the differential equation dy1/da=o.2y1 and the population two obeys dy2/da = -0.3y2 , where t is the time in years? Which population is growing and which is declining
Answer:
Population 1 indicates growth while Population 2 indicates a declining population
Explanation:
Here, using the given rate of change of the population, we want to determine which of the two is growing and which is declining
From the rate of change of both, we can determine this. Looking at the differential equation for the first one, we can see that it is of positive value. Looking at the differential equation for the second one. we can see it is of negative value
While a positive change rate indicates growth, a negative change rate will indicate otherwise
Hence, we can conclude that the one with a negative rate change will indicate a declining population
numeade how much work does a supermarket checkout attendant do on a can of soup he pushes 0.600 m horizontally with a force of 5.00 n?
Work done on the can of soup by the attendant is 3J.
A supermarket checkout attendant can do a considerable amount of work on a can of soup when they apply a force of 5.00 N over a distance of 0.600 m.
Work is defined as the product of force and displacement and is calculated by multiplying the force applied (5.00 N) by the distance moved (0.600 m). Therefore, the work done on the can of soup is:
5.00 N * 0.600 m = 3.00 Nm.
To understand this concept further, it's important to know that the unit of work, joule (J), is equal to 1 Newton meter (Nm). So, the 3.00 Nm of work done on the can of soup is also equal to 3.00 J.
The amount of work done on the can of soup by the checkout attendant is directly proportional to the amount of force and displacement applied. If either of the two is increased, then the total work done will increase.
For example, if the checkout attendant applies a force of 10.00 N over a distance of 0.600 m, then the total work done will be 10.00 N * 0.600 m = 6.00 Nm, or 6.00 J.
In conclusion, a supermarket checkout attendant can do a considerable amount of work on a can of soup when they apply a force of 5.00 N over a distance of 0.600 m. This work is equal to 3.00 Nm or 3.00 J.
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For the PE formula, why is the height required for calculations? Why do we need to know the height in order to determine PE? *
Answer:
Answer in Explanation
Explanation:
Whenever we talk about the gravitational potential energy, it means the energy stored in a body due to its position in the gravitational field. Now, we know that in the gravitational field the work is only done when the body moves vertically. If the body moves horizontally on the same surface in the Earth's Gravitational Field, then the work done on the body is considered to be zero. Hence, the work done or the energy stored in the object while in the gravitational field is only possible if it moves vertically. This vertical distance is referred to as height. This is the main reason why we require height in the P.E formula and calculations.
The derivation of this formula is as follows:
Work = Force * Displacement
For gravitational potential energy:
Work = P.E
Force = Weight = mg
Displacement = Vertical Displacement = Height = h
Therefore,
P.E = mgh
Compare the duration of electrical activity (emg) and force of contraction. how do they differ?
EMG lasts only for a short period of time while comparatively force contraction lasts longer.
Electromyography (EMG) is a technique for measuring muscle response or electrical activity in response to nerve stimulation of your muscle. The test is used to aid in the diagnosis of nerve and muscle problems.
Force of contraction occurs when tension-generating sites within muscle cells are activated.
Muscle force and smoothed rectified EMG typically have a linear relationship during static isometric contractions (SRE). However, it should be remembered that many muscles are typically contracting at once near a joint. This suggests that there is no requirement for a linear relationship between the SRE of a single muscle and the total joint moment.
Additionally, EMGS during concentric movements is greater than EMGS during isometric movements. The force signal's much lower frequency content than the rectified EMG is another factor to take into account when relating force to EMG.
Finally, the slow rate of activation and deactivation results in a 50 to 200 ms delay in muscle force relative to EMG.
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even with infinitely powerful telescopes, we can look back in time only until:
Even with infinitely powerful telescopes, we can look back in time only until the Cosmic Microwave Background (CMB), around 380,000 years after the Big Bang.
The Cosmic Microwave Background is the earliest observable stage of the universe's history. Before the CMB, the universe was in a hot, dense state known as the "opaque plasma" where photons were constantly scattered by charged particles, making it impossible to see through.
Approximately 380,000 years after the Big Bang, the universe cooled down enough for atoms to form, allowing photons to travel freely. This event is called "recombination," and the released photons created the CMB. Even with infinitely powerful telescopes, we cannot observe anything prior to the CMB because light did not travel freely in the opaque plasma.
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How might the rate of conduction be affected if the fiber absorbs moisture ?
Answer:
Moisture absorbed by fabric material in a humidity environment or liquid water ... Perspired moisture penetrating into the hydrophobic fiber can increase ... Moisture content within the porous insulating materials greatly affect thermal ... When the ambient humidity increase or decrease
Explanation:
How do conditions in the wild differ from conditions in captivity?
The wild offers more natural structures and temperatures that keep animals adapted to their surroundings. However, in captivity animals tend to differ from their wild counterparts. For one thing, the wild cultivates an animal's hunting skills but, when or if they are releasing into the wild, they do not know what to do whereas they have been sheltered their entire life. They don't know how to find natural structures to keep warm in, what places are safe or even survival strategies. The conditions in the wild teach an animal to survive while the conditions from man-made structures just give them an easy survival.
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Benda setinggi 3 cm diletakkan pada jarak 10 cm di depan cermin cekung yang berjari-jari
kelengkungan 10 cm. Tentukan:
Jarak bayangan
Perbesaran bayangan
Sifat bayangan
Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
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A 25-W soldering iron runs on 110 V dc. What is its resistance?
a) 0.48 kohms
b) 4.4 ohms
c) 0.0020 ohms
d) 2.8 kohms
On 110 V dc, a 25-W soldering iron operates. R=484 denotes its resistance.
What does resistance mean in its simplest form?The Greek letter omega stands in for the ohm, a unit of resistance measurement. Georg Simon Ohm (1784–1854), a German physicist who investigated the connection between voltage, current, and resistance, is the name given to the unit of resistance.
We know that
V = P/I
Ohm's law, where P stands for power, V for external voltage, and I for internal current.
I = V/R
V = P(VR)
P=V²/R
The power is
P =25W
The potential being provided is
V = 110V
According to Ohm's law:
P = V²/R
R = V²/P
figuring out the resistance R's value as follows:
R = (110V)²/25W
R=484Ω
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You find a rubber band that has a natural length of 0.05 meters but can be stretched to 0.2 meters without snapping. It has a spring constant of 17 You use it to power a rubber band car that has mass 0.5kg. a. How fast can the rubber band car go if all of the elastic potential energy is converted into kinetic?
The rubber band car can go approximately 1.24 m/s when all the elastic potential energy is converted into kinetic energy.
To determine how fast the rubber band car can go when all the elastic potential energy is converted into kinetic energy, we can use the principle of conservation of energy.The elastic potential energy stored in the rubber band can be calculated using the formula:
Elastic potential energy = (1/2)kΔx^2
Where:
k is the spring constant,
Δx is the change in length of the rubber band.
Given:
Natural length of the rubber band (x₀) = 0.05 m
Maximum stretched length of the rubber band (x) = 0.2 m
Spring constant (k) = 17 N/m
The change in length (Δx) = x - x₀ = 0.2 m - 0.05 m = 0.15 m
Now, we can calculate the elastic potential energy:
Elastic potential energy = (1/2) * 17 N/m * (0.15 m)^2
Elastic potential energy = 0.3825 J
According to the principle of conservation of energy, this elastic potential energy will be converted entirely into kinetic energy.
The kinetic energy of an object can be calculated using the formula:
Kinetic energy = (1/2)mv^2
Where:
m is the mass of the rubber band car, and
v is the velocity of the rubber band car.
We need to solve for v:
0.3825 J = (1/2) * 0.5 kg * v^2
Simplifying the equation:
v^2 = (2 * 0.3825 J) / 0.5 kg
v^2 = 0.765 J / 0.5 kg
v^2 = 1.53 m^2/s^2
Taking the square root of both sides:
v = √1.53 m^2/s^2
v ≈ 1.24 m/s
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The speed of sound through argon is shown.
A 3 column by 3 row table.
Column 1 is titled Element and includes the following entries: Argon (gas), Argon (liquid).
Column 2 is titled Temperature (degrees Celsius) and includes the following entries: 27, negative 1.86
. Column 3 is titled Speed of Sound (meters per second) and includes the following entries: 323, 813.
If argon could exist as a solid, what would best represent the speed through solid argon?
10 m/s
250 m/s
500 m/s
3200 m/s
Answer:
3200
Explanation:
Answer:
D
Explanation:
WILL MARK BRAINLIEST pls help
Explanation: for the one that is labeled as "Plan" just type what your plan is of the design and just label it. For the one labeled "Test", just type out step by step how it works or how to make it work ig, and the last one, just describe it, like what is it, how it works/how to get it to work. It seems pretty ez but it doesn't give a lot of info so I don't have a lot to say
Two conducting concentric spherical shells have radii a = 0.125 m and b = 0.23 m.
(a) Express the capacitance of the two concentric shells in terms of radii a and b and the Coulomb constant k.
(b) Calculate the numerical value of the capacitance in F.
(c) Express the capacitance C through the potential difference ΔV across the capacitor and charge Q.
(d) If the charge in the inner sphere is +Q = 3 μC, the outer sphere –Q = -3 μC, calculate the electric potential difference ΔV between the outside and the inside conductors in V.
(a) The capacitance of the two concentric shells is given by C = 4πε₀[(a * b) / (b - a)].
(b) Using the given radii a = 0.125 m and b = 0.23 m, and ε₀ ≈ 8.854 × 10⁻¹² F/m, the capacitance is numerically calculated as C = [value in Farads].
(c) The capacitance C can be expressed as C = Q / ΔV, where Q is the charge and ΔV is the potential difference across the capacitor.
(d) Given +Q = 3 μC and -Q = -3 μC, we can find ΔV using the equation ΔV = k * (Q / a - Q / b), where k ≈ 9 × 10⁹ N·m²/C².
How to calculate capacitance and potential?(a) The capacitance of the two concentric spherical shells can be expressed as:
C = 4πε₀[(a * b) / (b - a)]
where:
C is the capacitance,
ε₀ is the vacuum permittivity (C²/(N·m²)),
a is the radius of the inner shell,
b is the radius of the outer shell.
(b) To calculate the numerical value of the capacitance, we need the value of the vacuum permittivity, ε₀. The vacuum permittivity is approximately ε₀ = 8.854 × 10⁻¹² F/m. Using this value and the given radii a = 0.125 m and b = 0.23 m, we can calculate the capacitance:
C = 4π(8.854 × 10⁻¹² F/m)[(0.125 * 0.23) / (0.23 - 0.125)]
(c) The capacitance C can be expressed in terms of the potential difference ΔV across the capacitor and the charge Q as:
C = Q / ΔV
(d) Given that the charge in the inner sphere is +Q = 3 μC and the outer sphere is -Q = -3 μC, we can calculate the electric potential difference ΔV between the outside and inside conductors. Since the potential difference is the work done per unit charge to move from one conductor to another, we can use the equation:
ΔV = k * (Q / a - Q / b)
where:
k is the Coulomb constant (k ≈ 9 × 10⁹ N·m²/C²),
Q is the charge,
a is the radius of the inner shell,
b is the radius of the outer shell.
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Sunidhi made a study chart about changes in states of
matter.
Which headings best complete the chart?
X
melting
sublimation
Y
freezing
deposition
X: Solid Directly to Liquid
Y: Liquid Directly to Solid
OX: Liquid Directly to Solid
Y: Solid Directly to Liquid
O X: Heat Is Released
Y: Heat Is Absorbed
X: Heat Is Absorbed
Y: Heat Is Released
Answer:
freezing melting sublimating x y
x and
Explanation:
To drop a table of states of matter the best headings must be
table name: matter state
freezing melting sublimation x y
This order goes from the solid state to the gaseous state, which is obtained by introducing heat into the system
Answer: D on edge
X: Heat Is Absorbed
Y: Heat Is Released
Explanation:
sublimation and melting are both absorbing heat(aka getting warmer)as they change state while freezing and deposition are releasing heat(aka getting colder)as they change state
A graph can be described as:
a. a mathematical diagram.
b. a scientific model.
c. a way to show relationships between variables.
d. All of the above
Compare and contrast speed and velocity using a Venn diagram.
Answer:
Similarities:
Both speed and velocity are measured in m/s SI unit.
Both are physical quantities.
Differences:
Speed
scalar quantity
rate of change of position of an object/an object's position in any direction
may or may not be equal to velocity.
always positive.
always has the same value
measures the distance travelled over the change in time.
describes how fast a body moves.
Velocity.
vector quantity
rate at which an object changes a direction at some position/velocity is the rate and direction of an object's movement
can be positive, negative, or zero
measures displacement/change in position over the change in time.
describes the object's speed and the direction it takes while moving.
can take on different values.
in travelling 65cm along the barrel of a rifle a bullet accelerates from rest to 230 m/s. Find the acceleration and the time the bullet is in the barrel.
Answer:
\(2ax=v_{2}^{2}-v_{1}^{2}\\2a(\frac{65}{100})=230^{2}-0^{2}\\a=40692\frac{4}{13}m/s^{2}\\\\x=\frac{1}{2} at^{2}\\\frac{65}{100}=\frac{1}{2}(40692\frac{4}{13})t^{2}\\t=0.0101896s\)
I've written all the needed equations for you. All you have to do is some replacements.
Please do not hesitate to ask further questions.
160 km
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When the liquid line is restricted, the supply of refrigerant to the metering device is reduced. What is the effect on suction pressure and superheat
Answer:
The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.
Explanation:
1. The five components of refrigeration are:
Fluid refrigerantCompressorCondenser coilEvaporator coilExpansion device.The compressor limits the vapor released by the refrigerant. This
causes a rise in pressure (in refrigerant), which then pushes the
vapor into the coils on the outside of the refrigerator.
2. Now when the cooler air meets the warm gas present in the coils, it
gets converted into liquid form.
3. Thus, when the liquid form is at high pressure, the refrigerant then
cools down as it flows through the coils placed in the fridge ( in both
freezing and normal sections).
4. The refrigerant also absorbs the warm air present in the fridge, which
causes it to evaporate and flow back through the compressor and the
cycle repeats in the same form.
Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.
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How did the Planck mission help scientists learn about the age of the universe
Answer:
By using observations from the Atacama Cosmology Telescope (ACT) in Chile, the new findings match the measurements of the Planck satellite data of the same ancient light.
Explanation:
all large astronomical telescopes are reflectors because
All large telescopes are reflectors because large lenses are expensive to make and because large lenses sag under their own weight.
Telescopes are instruments used to observe celestial objects in the night sky. They work by collecting and focusing light, allowing astronomers to see distant stars, galaxies, planets, and other objects. Telescopes come in different types, including refracting telescopes, reflecting telescopes, and compound telescopes.
Compound telescopes, on the other hand, use a combination of lenses and mirrors. Telescopes have revolutionized our understanding of the universe by allowing us to study distant objects in great detail. They have helped us discover new planets, stars, galaxies, and even black holes. With the help of telescopes, astronomers have been able to make groundbreaking discoveries in the fields of astrophysics, cosmology, and planetary science, and they continue to be an essential tool in the study of the cosmos.
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Complete Question: -
Why are all large astronomical telescopes reflectors?
cAN A central force give rise to a torque about that point
Answer:
In rectilinear motion F = M a describes the motion of a particle
Γ = I α (torque equals moment of inertia times angular acceleration is the equivalent law in circular motion)
A fixed central force is perpendicular to the direction of motion and cannot change the torque about the point. (for mechanical forces)
However, for electrical forces, F = Q V X B and a changing magnetic field at the center of motion can produce a force perpendicular to the direction of motion.
Perhaps, the question needs to be more specific.
If the centripetal force acting on an object in uniform circular motion is removed the object will.
a. continue moving in a spiral until it reaches the center of the circular path.
b. stop moving.
c. continue moving in a straight line with constant speed.
d. move depending on the type of force providing the centripetal force.
Answer:
If the centripetal force acting on an object in uniform circular motion is removed, the object will continue moving in a straight line with constant speed.
In uniform circular motion, the centripetal force is responsible for keeping the object moving in a circular path. If this force is removed, there is no longer a force acting towards the center of the circle to change the object's direction, and the object will move in a straight line with a constant speed tangent to its previous circular path.
Option c. "continue moving in a straight line with constant speed" is therefore the correct answer.
1) why is star formation more likely to occur in cold molecular clouds than in regions where the temperature of the interstellar medium is several hundred thousand degrees?
Colder clouds are less resistant to gravity and therefore can collapse more easily because pressure is greater in heat & lower in cold stuff.
What is temperature explain?Temperature is a unit used to represent hotness or coolness on any of a number of scales, include Fahrenheit and Celsius. Temperature shows the direction of spontaneous heat transfer, which is from a region of high temperature to a cooler body.
What temperature is too hot for humans?People frequently cite a 2010 study that concluded the highest limit of safety would be a humid temperature of 35 C, or 95 F at 100% humidity or 115 F at 50% humidity.
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A plane is going at a speed of 300 km/h at 63 W of N. The wind hits the plane at a direction of 65 km/h at 52 S of E. What is the final direction of plane and the speed at which it is moving?
Some drops a ball off of the top of a 125-m-tall building. In this prob-lem, you will be solving for the time it takes the ball to hit the ground.(a)Define your coordinate system, be thorough.(b)Write down the given infor-mation, be sure to include hidden information.(c)State what physics principleis at play here. How do you know this?(d)Select an equation.(e)Solve forthe time it takes for the ball to hit the ground.
Answer:
t = 5.05 s
Explanation:
This is a kinetic problem.
a) to solve it we must fix a reference system, let's use a fixed system on the floor where the height is 0 m
b) in this system the equations of motion are
y = v₀ t + ½ g t²
where v₀ is the initial velocity that is v₀ = 0 and g is the acceleration of gravity that always points towards the center of the Earth
e) y = 0 + ½ g t²
t = √ (2y / g)
t = √(2 125 / 9.8)
t = 5.05 s
Mr. Bari drops a 3 kg ball from 1 feet above the glass. Find the velocity of the ballwhen it hits the glass. Use appropriate significant figures.
We have that the velocity of the ball when it hits the glass.Using the appropriate significant figures is
V=4.43ft/s
From the question we are told that
Mr. Bari drops a 3 kg ball from 1 feet above the glassthe velocity of the ball when it hits the glassGenerally the equation for the Velocity is mathematically given as
\(V^2=2as\\\\Therefore\\\\V=\sqrt{2*9.8*1}\\\\V=4.43ft/s\)
Therefore
the velocity of the ball when it hits the glass.Using the appropriate significant figures is
V=4.43ft/s
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