The actual size of a wood louse is 0.4mm but Robert drew his 5mm. What is the magnification?


Please answer QUICK I ain’t got much time

I’ll give brainiest if you answer in the next 15 mins

The height of a ramp does not directly determine the strength of the frictional force between a book and an object.

The strength of the frictional force between a book and an object is not directly influenced by the height of a ramp. The nature of the surfaces in contact, the force forcing the surfaces together (normal force), and the coefficient of friction are some of the variables that affect the frictional force between two surfaces.

The coefficient of friction between the book and the object plays a major role in determining the strength of the frictional force.

Learn more about frictional force:https://brainly.com/question/30280206

#SPJ1

These are simplified explanations of the mechanisms involved in these enzyme-catalyzed reactions, highlighting the key steps and substrate interactions.

Glyceraldehyde-3-phosphate dehydrogenase:

The mechanism of Glyceraldehyde-3-phosphate dehydrogenase involves multiple substrates. Here's a step-by-step explanation:

D-glyceraldehyde-3-phosphate, NAD+, and P bind to the active site of the enzyme.

The enzyme catalyzes the oxidation of D-glyceraldehyde-3-phosphate by transferring a hydride ion (H-) from D-glyceraldehyde-3-phosphate to NAD+, forming NADH.

The P (inorganic phosphate) binds to the carbonyl group of the oxidized D-glyceraldehyde-3-phosphate, resulting in the formation of 3-phospho-D-glycerol phosphate.

NADH and 3-phospho-D-glycerol phosphate are released from the active site of the enzyme.

Glutamate dehydrogenase:

The mechanism of Glutamate dehydrogenase also involves multiple substrates. Here's a step-by-step explanation:

2-ketoglutarate, NH4+, and NAD(P)H bind to the active site of the enzyme.

The enzyme catalyzes the oxidative deamination of 2-ketoglutarate by transferring an amine group (NH3) from 2-ketoglutarate to NAD(P)H, forming NAD(P)+ and L-glutamate.

H2O is added to the amine group of the intermediate L-glutamate, resulting in the formation of L-glutamate as the final product.

NAD(P)+ and H2O are released from the active site of the enzyme.

Isocitrate dehydrogenase:

The mechanism of Isocitrate dehydrogenase also involves multiple substrates. Here's a step-by-step explanation:

2-ketoglutarate, CO2, and NADH bind to the active site of the enzyme.

The enzyme catalyzes the oxidative decarboxylation of 2-ketoglutarate by removing a carboxyl group (CO2) from 2-ketoglutarate, resulting in the formation of isocitrate and NAD+.

NAD+ is reduced to NADH during this step.

Isocitrate is converted into an intermediate that undergoes isomerization, forming α-ketoglutarate.

NADH and α-ketoglutarate are released from the active site of the enzyme.

These are simplified explanations of the mechanisms involved in these enzyme-catalyzed reactions, highlighting the key steps and substrate interactions. The actual mechanisms may involve additional intermediate steps and cofactors.

Learn more about catalyzed with the given link ,

https://brainly.com/question/21598276

#SPJ11

The rate of formation of oxygen gas in an experiment where 0.08 mol of N2O5 is consumed in a 4.0L reaction vessel is 0.02 mol/L/s.

To calculate the rate of formation of oxygen gas, use the balanced equation:

N2O5(g) → 2NO2(g) + 1/2O2(g)

The stoichiometry of the reaction implies that 1 mole of N2O5 produces 1/2 mole of O2 gas. So, if 0.08 mole of N2O5 is used up, 1/2 x 0.08 mole = 0.04 mole of O2 gas will be formed.

The volume of the reaction vessel is given as 4.0L. Therefore, the concentration of O2 gas is 0.04 mole/4.0 L = 0.01 mol/L

The experiment's rate is given as the rate of formation of O2 gas, which is the rate of its appearance. Since the stoichiometry of the reaction shows that 1 mole of N2O5 produces 1/2 mole of O2 gas, then the rate of formation of O2 gas equals half the rate of consumption of N2O5 gas.

Therefore, Rate of formation of O2 gas = 1/2 x Rate of consumption of N2O5 gas

We can calculate the rate of consumption of N2O5 gas as follows:

Let's say that the initial concentration of N2O5 gas is [N2O5]0, and that after some time t, the concentration is [N2O5]t.

Then, the rate of consumption of N2O5 gas, RC, is given by:

RC = -Δ[N2O5]/Δt = ([N2O5]0 - [N2O5]t)/t

where the negative sign indicates that the concentration of N2O5 is decreasing. We can rearrange this equation to solve for Δ[N2O5]/Δt, which is the average rate of consumption of N2O5 gas during the time interval Δt:Δ[N2O5]/Δt = ([N2O5]t - [N2O5]0)/t

The experiment's rate of consumption of N2O5 gas is not given in the question. However, we can calculate it if we know the initial concentration of N2O5 gas, [N2O5]0, and the concentration after some time t, [N2O5]t.

For example, if [N2O5]0 = 0.1 mol/L and [N2O5]t = 0.05 mol/L after 5 seconds, then:

RC = ([N2O5]0 - [N2O5]t)/t = (0.1 - 0.05)/5 = 0.01 mol/L/s

Therefore, the rate of formation of O2 gas, which is half the rate of consumption of N2O5 gas, is:

Rate of formation of O2 gas = 1/2 x 0.01 mol/L/s = 0.005 mol/L/s = 0.02 mol/L/s (using the previously calculated value of the rate of consumption of N2O5 gas).

Hence, the rate of formation of oxygen gas in an experiment where 0.08 mol of N2O5 is consumed in a 4.0L reaction vessel is 0.02 mol/L/s.

To know more about rate of formation, refer here:

https://brainly.com/question/2496500#

#SPJ11

Answer:

1 cal = 0.004187 kJ

1,500,000 cal = 6280.5 kJ

Leaves impurities in their starting layer: Washes

Leaves desired compound in its starting layer: Extraction

Moves desired compound from one layer to another: Extraction

Often involves a reaction in one of the layers: Extraction

Moves impurities from one layer to another: Extraction

Washes and extractions are techniques that use a separatory funnel to separate liquid layers. They have some differences in their purpose and outcomes.

1. Leaves impurities in their starting layer: This statement applies to washes. Washes are typically used to remove impurities from a desired compound. After the wash, the impurities remain in the starting layer while the desired compound is transferred to another layer.

2. Leaves desired compound in its starting layer: This statement applies to extractions. In extraction, the goal is to separate a desired compound from a mixture. The desired compound is usually transferred from the starting layer to another layer, leaving impurities behind.

3. Moves desired compound from one layer to another: This statement applies to extractions. The desired compound is selectively extracted from one layer to another, usually based on differences in solubility or polarity.

4. Often involves a reaction in one of the layers: This statement applies to extractions. Sometimes, an extraction involves a chemical reaction between the desired compound and another reagent present in one of the layers. This reaction helps to facilitate the separation or purification of the desired compound.

5. Moves impurities from one layer to another: This statement applies to extractions. During an extraction, impurities present in the starting layer can be transferred to the other layer, leaving the desired compound behind in one layer. This allows for the separation of impurities from the desired compound.

In summary, washes are used to remove impurities, leaving the desired compound in the starting layer, while extractions involve moving the desired compound to a different layer, often through a reaction, and can also transfer impurities to another layer.

To know more about impurities refer here:

https://brainly.com/question/32369276#

#SPJ11

Answer:

7.325 mol.

Explanation:

use the formula n=m/mr

so that makes:

234.4/16*2

which is 7.325 mol.

The limiting reactant given that 2.2 g of Mg reacts with 4.5 L of oxygen at STP is magnesium, Mg

22.4 L = 1 mole of oxygen at STP

But

1 mole of oxygen = 32 g

Thus,

22.4 L = 32 g of oxygen at STP

Therefore,

4.5 L = (4.5 × 32) / 22.4

4.5 L = 6.4 g of oxygen

Balanced equation

2Mg + O₂ —> 2MgO

Molar mass of Mg = 24 g/mole

Mass of Mg from the balanced equation = 2 × 24 = 48 g

Molar mass of O₂ = 32 g/mole

Mass of O₂ from the balanced equation = 1 × 32 = 32 g

From the balanced equation above,

48 g of Mg reacted with 32 g of O₂

Therefore,

2.2 g of Mg will react with = (2.2 × 32) / 48 = 1.5 g of O₂

From the calculation made above, we can see that only 1.5 g of O₂ out of 6.5 g is needed to react completely with 2.2 g of Mg.

Thus, Mg is the limiting reactant

Learn more about stoichiometry:

https://brainly.com/question/14735801

#SPJ2

First, we have to calculate the molecular weights of each molecule:

Then, we have to calculate the number of grams of water. We can calculate them because the process of evaporation lets us know the water amount that was retired:

Then, we're gonna convert the grams of sodium carbonate alone (30.2 g) and the grams of water to moles:

It means that the mole relation is 1:1 approx, as it is the same amount for both. Then, the formula is going to be:

It means that the answer is A.

The primary intermolecular force responsible  here is london dispersion forces

An intermolecular force is an attractive force that arises between the positive components or also called as  protons  of one molecule and the negative components or  electrons of another molecule. Various physical and also chemical properties of a substance are dependent on this force.

The London dispersion force is a temporary attractive force that generally results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles. This force is sometimes called an induced dipole-induced dipole attraction as well

This type of intermolecular force of attraction is generally seen in water and methanol system.

To know more about london dispersion forces

https://brainly.com/question/20514601

#SPJ4

Answer:

Yes, the process of fossilisation is a continuous one. If the conditions are right, a dead plant or animal will be preserved in the rocks of the future, just as they were in the past.

Explanation:

For a fossil to form, several conditions have to be met. First of all, the animal had to live in the given area! Animals live in many environments on Earth, but not everywhere. The water above many lake bottoms and many areas of the deep ocean bottom are stagnant. The bottom water is never exchanged with surface waters, so the water contains no dissolved oxygen. Animals cannot live without oxygen, so no animals live there. In these situations, the only possibility of fossilization is if a fish or other swimming animal dies in oxygen-rich waters above, sinks down into the stagnant muddy bottom, and is buried by sediments.

Based on the model it can be said that fossil formation require certain conditions ( i.e YES )

Fossilisation is the process of preserving plants and animals in a solid petrified form such as rocks. Fossilisation is a continous process which is seen when dead plants and animals are left to become fossils given that the necessary conditions are met.

Hence we can concude that Based on the model it can be said that fossil formation require certain conditions ( i.e YES )

Learn more about Fossilisation : https://brainly.com/question/11224681

#SPJ2

The pair of amino acids that can form a salt bridge at physiological pH is aspartic acid and histidine. Hence the correct option is (A).

A salt bridge is formed when the carboxylic acid group (-COOH) of one amino acid donates a proton (H+) to the amino group (-NH2) of another amino acid, which becomes positively charged. This creates an electrostatic attraction between the positively charged amino acid and the negatively charged carboxylate ion of the other amino acid. At physiological pH (around 7.4), the carboxylic acid group of aspartic acid (Asp) is deprotonated and has a negative charge, while the amino group of histidine (His) is protonated and has a positive charge. Therefore, Asp and His can form a salt bridge through electrostatic attraction between the negatively charged carboxylate group of Asp and the positively charged amino group of His. The other pairs of amino acids listed do not form salt bridges at physiological pH for the following reasons:

(B) Glutamic acid (Glu) and aspartic acid (Asp) both have negatively charged carboxylate groups at physiological pH, so they repel each other and do not form salt bridges.

(C) Two cysteines (Cys) can form a disulfide bond through the oxidation of their sulfur-containing side chains, but they do not form salt bridges.

(D) Arginine (Arg) has a positively charged guanidino group at physiological pH, while tyrosine (Tyr) has a neutral hydroxyl group. They do not have complementary charges to form a salt bridge.

(E) Lysine (Lys) has a positively charged amino group, while glutamic acid (Glu) has a negatively charged carboxylate group. They have complementary charges to form a salt bridge, but the pH is too low for Glu to be deprotonated and have a negative charge. Therefore, they do not form a salt bridge at physiological pH.

To know more about pH please refer: https://brainly.com/question/16783584

#SPJ4

Question - Which of the pairs of amino acids can form a salt bridge at physiological pH? Select from the following options:-

(A) aspartic acid and histidine

(B) glutamic acid and aspartic acid

(C) two cysteines

(D) arginine and tyrosine

(E) lysine and glutamic acid

The chemist has 642.4 millimoles of barium acetate in the solution.

To calculate the millimoles of barium acetate (Ba(C₂H₃O₂)₂) in the solution, we can use the formula:

moles = molarity × volume (in liters)

First, let's convert the volume from milliliters (mL) to liters (L):

440.0 mL ÷ 1000 = 0.440 L

Now we can substitute the given values into the formula:

moles = 1.46 M × 0.440 L

moles = 0.6424 mol (rounded to 4 decimal places)

To convert the moles to millimoles, we multiply by 1000:

millimoles = 0.6424 mol × 1000

millimoles = 642.4 mmol (rounded to 3 significant digits)

Therefore, the chemist has 642.4 millimoles of barium acetate in the solution.

It's important to note that the molarity (M) represents the number of moles of solute per liter of solution. By multiplying the molarity by the volume in liters, we can find the number of moles of solute. To convert moles to millimoles, we multiply by 1000. The result represents the millimoles of barium acetate present in the given volume of solution.

For more such questions on barium acetate visit:

https://brainly.com/question/15304103

#SPJ8

There are many scenarios in which the situation in question may take place, the rule is that for this to happen, the temperature and pressure of the gas must change by the same amount.

As stated, the temperature and the pressure of the enclosed gas may change, in which they may increase or decrease, but the change must be by the same magnitude for each value. What this means is that is temperature increases by 5, so then must the pressure.

This is due to the relationship between the temperature and the pressure of an enclosed gas when using the combined gas law. The law takes the form of a fraction in which the pressure is found as part of the numerator and the temperature is part of the denominator, therefore, by increasing at the same rate, the final product and the volume will not be affected.

To learn more visit:

https://brainly.com/question/13154969?referrer=searchResults

Answer:

A scenario where volume dosent change is when both temperature and pressure are doubled or tripled

Explanation:

p1v1/t1=p2v2/t2

Answer:

I believe 11 is B 12 is C 13 is B and 14 is C

Answer:

The reaction NH3(aq) + HNO3(aq) → NH4NO3(aq) is an acid-base reaction. In an acid-base reaction, an acid and a base react to form a salt and water. In this reaction, the acid is nitric acid (HNO3) and the base is ammonia (NH3). The salt that is formed is ammonium nitrate (NH4NO3).

The other choices are not correct. A precipitation reaction is a reaction in which a solid precipitate forms from a solution. A redox reaction is a reaction in which electrons are transferred between atoms or molecules. A decomposition reaction is a reaction in which a compound breaks down into two or more simpler substances.

Explanation:

The volume and temperature changes in according to Charles' law will be:

The relationship between the volume and temperature of a given mass of gas is given by Charles' Iaw which states that volume is directly proportional to temperature if a gas in Kelvin.

To complete the tables volume and temperature changes:

Therefore, volume and temperature are directly proportional.

Learn more about gas Charles' law at: https://brainly.com/question/888898

Answer:

Ancient CO₂ levels can be measured from

1) Air bubbles trapped in deep ancient ice cores (up to 800,000 years ago) or

2) Tree rings (up to 10,000 years ago)

Explanation:

The percentages of CO₂ concentration in the atmosphere from previous or ancient times are found by analyzing the CO₂ content in trapped air located in the deep ancient ice cores present in Antarctica and Greenland such as the EPICA Dome C cores

As the ice is drilled though, the air released from trapped bubbles are captured for analysis and the time frame for the captured bubbles can date back up to 800,000 years

Ancient CO₂ levels can also be measured from tree rings which provide ancient CO₂ levels up to 10,000 years

Answer:

other guy is correct. it is C Quebec.

Explanation:

got it right on the unit test review, edge 2021

C.heat the solution

Explanation:

P1V1 = P2V2

(100.7 kPa)(0.75 L) = (99.8 kPa)V2

V2 = (100.7 kPa)(0.75 L)/(99.8 kPa)

= 0.757 L

1085 is a perfect square if the square root of 1085 equals a whole number. The square root of 1085 is not a whole number. 1085 is not a perfect square root.

Do you want to play again?

Answer:

(c) 15.39 kg of copper present in 1tonne of ore.

Explanation:

We are given that ore contains 3% of copper carbonate

1tonne = 1000kg

3% of copper carbonate in 1000kg of ore will be

= \(\frac{3}{100}*1000\) = 30kg

30 kg of copper carbonate is present in ore

CuCO3 has 63.5g of cupper present in it

molar mass of CuCO3 = 123.5

so the percentage of copper present in CuCO3

= \(\frac{63.5}{123.5}*100\) = 51.3% of copper present per kg CuCO3

Now

amount of copper present in 30kg of CuCO3

= \(\frac{51.3}{100}* 30\) = 15.39kg

15.39 kg of copper present in 1tonne of ore

The mass of copper obtained from 1 tonne of the ore is 15.4 kg

The copper ore has 3% of copper carbonate by mass.

The mass of copper carbonate in 1 tonne of the ore can be calculated below.

1000 kg = 1 tonne

Therefore,

mass of copper carbonate = 3 /100 × 1000 = 30 kg

atomic mass of copper = 63.5 g

molar mass of CuCO₃ = 123.55 g

123.55 g of CuCO₃ gives 63.5 g of copper  

30, 000g of CuCO₃ will give ? of copper

cross multiply

mass of copper = 30,000 × 63.5 / 123.55

mass of copper = 1905000 / 123.55 = 15418.8587616 g

mass of copper = 15418.8587616 / 1000 ≈ 15. 4 kg  

read more: https://brainly.com/question/1237330?referrer=searchResults

The correct option is (B) No, the solution is too dilute and would have a %T over 90% where Beer's Law does not apply.

The solution is too dilute, it will have lower than desired concentration of the desired substance. To make solution more concentrated, more of the desired substance must be added to the solution. This increases the concentration of the desired substance, allowing it to be more effective in the intended application.

The amount of the desired substance must be adjusted according to the desired concentration of the solution. In addition, the amount of other substances in the solution must be considered to ensure the desired concentration is not too high or too low. Too high concentration could produce an undesired reaction, while too low a concentration would decrease the efficiency of the desired reaction.

Full question:

A set of dilutions ranging in concentration from 1x10-2 M to 2x10-2 M are used to prepare a standard curve. Transmittances of the dilutions range from 12% to 88%. Could this plot be used to determine the concentration of a sample that had a concentration of 1.0x10-3 M?

A) No, the solution is too dilute and would have a %T under 10% where Beer's Law does not apply.

B) No, the solution is too dilute and would have a %T over 90% where Beer's Law does not apply.

C) Yes, simply extend the standard curve.

D) No, the solution is too concentrated and would have a %T over 90% where Beer's Law does not apply.

To know more about Dilute solution:

brainly.com/question/16926361

#SPJ4

The entire number of valence electrons should be known. Step 2: Outline the molecule's skeletal structure. Step 3: Form each bond in the skeletal structure using two valence electrons Lewis.

The element symbol for an atom is covered in dots that represent the electrons in its valence shell, which is known as the Lewis dot structure or electron-dot symbol. A single dot represents the unpaired electron in the valence shell, whereas a pair of dots represents the paired electrons.

The number of valence e- atoms that each atom contributes to the molecule is counted when designing Lewis dot structures.

With the exception of H, which is only encircled by two electrons, place electron pairs around each atom so that there are eight electrons around each atom (octet rule).

To learn more about Lewis please click on below link

https://brainly.com/question/15570523

#SPJ4

The two types of nucleophilic substitution reactions are SN1 and SN2. SN2 has two molecules, whereas SN1 only has one.

A nucleophilic molecule replaces a different atom or group of atoms on a molecule, known as the leaving group, in a nucleophilic substitution reaction. The substrate molecule is attacked by the nucleophilic molecule's abundant electrons.

A process in which one functional group or atom is swapped out for another negatively charged functional group or atom is known as a nucleophilic substitution reaction.

The SN1 reaction is monomolecular, whereas the SN2 reaction is bimolecular.

Any substitution reaction in which an atom or functional group is changed for one that has a single pair of electrons, a negatively charged ion, or both. The negatively charged ion or the atoms/molecules with lone pairs of electrons will be pulled to the positively charged area of an atom or complex in an effort to replace the functional group or atom already attached to the positive location.

Therefore, The two types of nucleophilic substitution reactions are SN1 and SN2. SN2 has two molecules, whereas SN1 only has one.

To know more about Nucleophilic substitution, refer to the link:

https://brainly.com/question/32657850

#SPJ6

Answer:

!atoms in the nitrogen family.. have 5 valence electrons. They tend to share electrons when they bond. Other elements in this family are phosphorus, arsenic, antimony, and bismuth.

Synthesis reaction

It is a reaction in which 2 or more reactants combine with each other to form one product .

Check option C

Sulphate and water are combining to form sulfuric acid .

Hence option C is correct

Answer:

SO3 + H2O => H2SO4

Explanation:

I took the test :)