Suppose we replacebothhover pucks with pucks that are the same size as the originals but twice as massive. Otherwise, we keep the experiment thesame. Compared to the pucks in the video, this pair of pucks will rotateHint 1.How to approach the problemThis question asks you to relate the mass of a rotating object to the object’s angular speed(rate of rotation).You can do that using angular momentum:. In this equation, the moment of inertiais the "mass" term, equivalent toin the equation forlinear momentum.So, how does the pucks moment of inertiarelate to their mass? Is the relationship linear ()? Or is it quadratic () or inverse square()? To see the answer, try writing the general equation that defines.Now, how will doubling the mass of the pucks affect,, and?

When the number of hours changes, the number of miles traveled by a car at a constant speed of 65 miles per hour will increase or decrease proportionally. This relationship is determined by the formula: distance = speed × time.

If the number of hours increases, the car will cover a greater distance, and if the number of hours decreases, the car will cover a shorter distance. For example, if the car travels at 65 miles per hour for 2 hours, the distance covered would be 65 × 2 = 130 miles. If the number of hours doubles to 4, the distance covered would also double to 65 × 4 = 260 miles. Similarly, if the number of hours is halved to 1 hour, the car would cover 65 × 1 = 65 miles.

Therefore, the number of miles covered is directly proportional to the number of hours traveled when the speed remains constant. In simple terms, the more hours the car travels, the greater the distance it will cover, and vice versa, as long as the speed remains consistent.

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The speed of impulse conduction along an axon can be increased by several factors and mechanisms like Myelination, Axon diameter, Temperature, and Synaptic transmission efficiency.

The presence of myelin sheath, which is a fatty insulating substance, around the axon enhances the speed of impulse conduction.

Axons with larger diameters generally conduct impulses faster compared to axons with smaller diameters.

Higher temperatures can increase the speed of nerve impulse conduction.

At the synapses between neurons, the efficiency of neurotransmitter release and reception can impact the speed of impulse conduction.

These factors interact with each other and can collectively contribute to the speed of impulse conduction along an axon.

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The Milky Way and the Milky Way Galaxy are actually the same things. However, term-wise, the "Milky Way" is the band of diffuse light around (our) celestial sphere, why the Milky Way Galaxy is a spiral galaxy (that our solar system is in).

The Milky Way is a spiral-shaped galaxy that contains our Solar System, including the Earth and the Sun. It is one of the billions of galaxies in the observable universe and is home to an estimated 100 billion stars.

The term "Milky Way" is often used to refer to the band of light that we can see in the night sky, which is actually the combined light of billions of stars in our galaxy. However, the term "Milky Way Galaxy" is also used to refer to the entire galaxy itself. So, in short, there is no difference between the Milky Way and the Milky Way Galaxy; they are two terms used to refer to the same thing.

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Answer:

\(Q_t= 8.3 * 10^3 C\)

Explanation:

From the question we are told that:

Resistor \(R=1000ohms\)

Voltage \(v=120_V\)

Capacitance of c_1 \(c_1=20 \mu F\)

Capacitance of c_2 \(c_2=60 \mu F\)

Time \(t=0\)

Generally the equation for charges is mathematically given by

\(For C_1\\Charge\ on\ C_1 = CV = 20*120 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2.4 x 10^-3 C\\\)

\(ForC_2\\Charge on C_2 = 60*120 =7200 μC = 7.2 x 10^-3\\Charge on C_2 = 7.2 x 10^-3\)

Generally the equation for voltage across capacitors is mathematically given by

\(V_c(t)=V(1-e^{-t/RC})\)

\(C=C_1+C_2=80 \mu f\\t=2RC=>160000s\)

\(V_c(t)=120(1-e^{-(160000)/1000*(80)})\)

\(V_c(t)=103.7598\)

Generally the equation for charges is mathematically given by

\(Q1(t) = C1Vc(t)\\Q1(t) = 20*103.7598\\Q1(t) = 2075.196\\\\Q2(t) = 60*103.7598\\Q2(t) = 6225.6\\\)

Generally the equation for total charges \(Q_t\) is mathematically given by

\(Q_t=Q1(t)+Q2(t)\)

\(Q_t= 8.3 * 10^3 C\)

Answer:

The speed of the faster ship is 22.5 m/s

Explanation:

The length of the ships are;

Ship 1 = 200 m

Ship 2 = 100 m

The time it takes for the ships to completely cross each other when travelling in opposite directions = 10 seconds

The time it takes both ships to cross each other when travelling in the same direction = 25 seconds

Let x represent the speed of the first ship, ship 1, and y represent the speed of the second ship, ship, 2, we have;

(x + y) × 10 = 200 + 100 = 300

10·x + 10·y = 300...(1)

(x - y) × 20 = 200 + 100 = 300

20·x - 20·y = 300...(2)

Multiply equation (1) by 2, to get;

(x + y) × 10 × 2 = 300 × 2

20·x + 20·y = 600...(3)

Adding equation (1) to equation (3) gives;

20·x + 20·y + 20·x - 20·y = 600 + 300

40·x = 900

x = 900/40 = 22.5

x = 22.5

The speed of the first ship, ship 1 = x = 22.5 m/s

From equation (1), we have;

10·x + 10·y = 300

y = (300 - 10·x)/10 = (300 - 10×22.5)/10 = 7.5

y = 7.5

The speed of the second ship, ship 2 = y = 7.5 m/s

Therefore, the faster ship is ship 1 with a speed of 22.5 m/s

The personality trait which helps you to use straightforward and confident communication with others is referred to as Assertive and is therefore denoted as option D.

This is defined as the process in which information is passed or exchanged from one person or place to another through various means and forms.

Assertiveness is a personality which is characterized by self assuredness without exhibiting aggressiveness in making points clear to other people.It is also known as a straightforward and confident communication with others.

This is therefore the reason why option D was chosen as the most appropriate choice.

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Answer: assertive

Explanation:

A) Angular acceleration = -2.47 rad/s²

B) 23.54 seconds

C) The total distance covered = 294.23m

The number of revolutions = 62

Angular distance, θ = 62 x 2π

θ = 62 x 2 x 3.142

θ = 389.608 radians

Diameter, d = 0.86 m

Radius, r = d/2 = 0.86/2

r = 0.43m

Initial velocity, v₁ = 90 km/h = 90 x (1000/3600)

v₁ = 25 m/s

Angular velocity, w₁ = v₁ / r

w₁ = 25/0.43

w₁ = 58.14 rad/s

Final velocity, v₂ = 59 km/h = 59 x (1000/3600)

v₂ = 16.39 m/s

Angular velocity, w₂ = v₂ / r

w₂ = 16.39 / 0.43

w₂ = 38.12 rad/s

Using the equation of motion:

Angular acceleration = -2.47 rad/s²

B) Amount of time required for the car to stop if it continues to decelerate at this rate

Initial angular speed, w₁ = 58.14 rad/s

When the car stops, final angular speed, w₂ = 0 rad/s

Using the equation of motion below:

C) The total distance

Use the equation of motion below:

The total distance covered = 294.23m

Answer:

postural is the answer you're looking for

Answer:

postural is the answer for you question

Given the amount of work done in pushing the car over the given distance, the amount of force applied is 2400 Newtons.

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where f is force applied and d is distance travelled.

Given that;

W = F × d

60000kgm²/s² = F × 25m

F = 60000kgm²/s² ÷ 25m

F = 2400kgm/s²

F = 2400N

Given the amount of work done in pushing the car over the given distance, the amount of force applied is 2400 Newtons.

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Answer:

1. B

2. B

3. D

4. A

Hope this was correct! A lot of the answers are already in the article itself and the wording is just different. I suggest now that for information retainment, you read the article again with the correct points in mind and see if you can spot the points where the answers are stated!

Moped riding represent angry customers in the model from the lesson.

Moped riding refers to the riding of a special type of small motorcycle, generally having a less stringent licensing requirement than full motorcycles or automobiles.

Generally, the word "moped riding" describes any two-wheeledth with a step-through chassis and footrest platform. These two-wheeled vehicle are usually equipped with bicycle-like pedals that the rider uses to propel the vehicles.

Although motorcycles are usually very harder to learn to ride

The following are other types of riders:

So therefore, moped riding represent angry customers in the model from the lesson.

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Answer:

22

Explanation:

Answer:

the third one

Explanation:

Part A: The speed of the charge when it moves infinitely far from the origin is 14.04 m/s.

Part B: the distance of the charge from the origin, when it attains half the speed it will have at infinity, is 0.155 m.

Part A: For the electric potential energy gained by the charge when it moves from a point P to infinity:

PE = qV

Where, PE denotes electric potential energy gained by the charge

q is the magnitude of the charge

V is the electric potential at the point P

The electric potential due to a point charge of q Coulombs located at a distance r from the point P is:

V = kq/r,

where k = 9 × 109 Nm2/C2 is the Coulomb constant.

Thus, the electric potential energy of a charge of q Coulombs at a distance r from the origin is:

PE = qV = kq2/r

Thus, the electric potential energy gained by the charge when it moves from (1.25 m, 0.570 m) to infinity is:

PE = kq2/r

where, r is the distance of the charge from the origin, i.e.,

r2 = (1.25 m)2 + (0.570 m)2 = 1.44 m2

Thus, PE = kq2/1.44 m

The kinetic energy gained by the charge when it moves from rest to infinity:

K = PE = kq2/1.44 m

where, K is the kinetic energy of the charge m is the mass of the charge

rv is the velocity of the charge

The kinetic energy of the charge is:

K = (1/2)mv2

where, v is the velocity of the charge

Thus,

(1/2)mv2 = kq2/1.44

mv2 = (2kq2/1.44 m * m)1/2v2 = (2kq2/1.44 m)1/2

v2 = (2 × 9 × 109 Nm2/C2 × (3.15 × 10-6 C)2/1.44 × 2.85 × 10-3 kg)1/2

v2 = 197.3 m2/s2

v = (197.3 m2/s2)1/2

v = 14.04 m/s

Thus, the speed of the charge when it moves infinitely far from the origin is 14.04 m/s.

Part B:The speed of the charge when it attains half the speed it will have at infinity is half of the final speed. Thus,

vf/2 = (197.3 m2/s2)1/2/2

vf/2 = 9.92 m/s

Thus, we need to find the distance of the charge from the origin, when its speed is 9.92 m/s.The kinetic energy of the charge when its speed is 9.92 m/s is:

K = (1/2)mvf2/2

where, vf is the speed of the chargeThus,

(1/2)mvf2/2 = kq2/r

where, r is the distance of the charge from the origin, i.e.,

r2 = (1.25 m)2 + (0.570 m)2 = 1.44 m2

Thus, (1/2)mvf2/2 = kq2/1.44

mvf2/2 = (kq2/m)1/2 * 1.44

mvf2/2 = (2kq2/m)1/2vf2 = (4kq2/m)

vf2 = (4 × 9 × 109 Nm2/C2 × (3.15 × 10-6 C)2/2.85 × 10-3 kg)1/2

vf2 = 394.7 m2/s2

vf = (394.7 m2/s2)1/2

vf = 19.87 m/s

Thus,

r = kq2/(mvf2/2)

r = (9 × 109 Nm2/C2 × (3.15 × 10-6 C)2)/((2.85 × 10-3 kg) × (19.87 m/s)2/2)

r = 0.155 m

Thus, the distance of the charge from the origin, when it attains half the speed it will have at infinity, is 0.155 m.

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A(n) ledger is maintained for each financial statement item, whereas a(n) general ledger contains all of the accounts of the company.

In accounting, a ledger is a book or electronic record that contains individual accounts for specific financial statement items, such as cash, accounts receivable, accounts payable, and inventory. Each financial statement item has its own ledger, which tracks the transactions and balances related to that item.

On the other hand, the general ledger is a comprehensive record that contains all the accounts of the company. It consolidates the individual ledgers and provides a complete overview of the company's financial transactions and balances.

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Part A. We are given that a dart travels from rest to a velocity of 30 m/s with an acceleration of 330 m/s^2 to determine the time we will use the following equation of motion:

Where:

Since the dart is launched from rest this means that the initial velocity is zero, therefore:

Now, we divide both sides by "a":

Now, we plug in the values:

Solving the operation:

Part B. Now, we are asked to determine the distance. To do that we will use the following equation of motion:

Now, we divide both sides by "2a":

Now, we plug in the values:

Solving the operations we get:

Therefore, the distance is 1.36 meters.

The time taken for the bee to reach the flower is 3.87 seconds.

The time of motion of the  bumblebee is calculated by applying the following kinematic equation as shown below.

s = vt + ¹/₂at²

where;

23.4 = 4.09t   +  ¹/₂(1.01)t²

23.4 = 4.09t + 0.505t²

0.505t² + 4.09t - 23.4 = 0

solve the quadratic equation using formula method;

t = 3.87 seconds

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To choose a right-hand side that gives no solution, we can use the equation 6x + 4y = 20. When we compare this equation to 3x + 2y = 10, we can see that the two equations have different coefficients. Therefore, there is no solution to the system.
To choose a right-hand side that gives infinitely many solutions, we can use the equation 6x + 4y = 30. When we compare this equation to 3x + 2y = 10, we can see that the two equations have the same coefficients. Therefore, the system has infinitely many solutions.
As for the solutions to the system 3x + 2y = 10 and 6x + 4y = 30, any pair of values (x, y) that satisfies both equations would be a solution. For example, (2, 2) and (4, -1) are two possible solutions to this system.

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Answer:

energy, waves

Explanation:

In quantum mechanics, a central concept is that both matter and energy are alternate forms of the same entity and therefore both exhibit dual characteristics of particles and of waves.

Matter can be defined as anything that has mass and is able to occupy space.

Thus, any physical object or substance that is found on Earth is typically composed of matter.

Similarly, energy is highly affected by the mass of a any physical object or substance just like matter,

Hence, both energy and matter are known to be made up of atoms and as a result of this fact, exhibit dual characteristics of particles and of waves.

A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.

In conclusion, this central concept makes it easier for us to better understand the behavior of tiny particles such as electrons.

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Answer:

Destructive interference occurs when the maxima of two waves are 180 degrees out of phase: a positive displacement of one wave is cancelled exactly by a negative displacement of the other wave. The amplitude of the resulting wave is zero.

Explanation: hope it helps :)

Answer:

The basic requirement for destructive interference is that the two waves are shifted by half a wavelength. This means that the path difference for the two waves must be: R1 R2 = l /2.

Explanation:

Answer: It's 29.4 or 29.5

Explanation: I did this before and I can't remember.

The initial speed of the car with a length of the skid mark of about 64 m long and kinetic friction of 0.70 is 29.63 m/s.

A force that acts between moving surfaces is referred to as kinetic or sliding friction. It is the frictional force that prevents relative motion between surfaces in contact. The formula to calculate this kind of friction is, \(f _k =\mu_kN\) where uk is the coefficient of friction and N is the normal force.

Given the length of the skid mark (Δd) is 64 m and the coefficient of kinetic friction is 0.70. The final velocity vf is 0 because the car stops.

Let us assume the initial velocity vi, mass m,  and deceleration a. Then, the normal force acting on the car is N = mg. The kinetic friction will be,

\(f _k =\mu_kN\\f_k=\mu_kmg\)

Let's assume the only force acting on the system is kinetic friction, then friction force=ma. Solve this equation with the above equation,

\(\begin{aligned}ma&=\mu_kmg\\a&=\mu_kg\end{aligned}\)

Then, the initial speed is calculated as follows

\(\begin{aligned}v_f^2&=v_i^2-2a\Delta d\\0&=v_i^2-2\mu_kg\Delta d\\v_i^2&=\mathrm{2\times0.70\times9.80\;m/s^2\times64\;m}\\v_i^2&=\mathrm{878.08\;m^2/s^2}\\v_i&=\mathrm{29.63\;m/s}\end{aligned}\)

The answer is 29.63 m/s.

The complete question is -

Police investigators, examining the scene of an accident involving two cars, measured 64 m long skid marks on one of the cars, which nearly came to a stop before colliding. The coefficient of kinetic friction between rubber and the pavement is about 0.70. Estimate the initial speed of that car, assuming a level road.

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Given:

The height from the ground is h = 350 m

The gravitational potential energy is GPE = 120,200 J

To find the mass of the hiker.

Explanation:

The mass of the hiker can be calculated by the formula

Here, g =9.8 m/s^2 is the acceleration due to gravity.

On substituting the values, the mass of the hiker will be

Thus, the mass of the hiker is 35.044 kg

The velocity equation is \(v_{final} =v_{initial} +at\\\)

Known facts:

Plug into equation known quantities:

   \(v_{final} = (-3.04) * 3.83 = -11.6432m/s\)

Thus the final velocity is -11.6432m/s

Hope that helps!

a) R= Resultant vector  R=A+B+C ,D=12 steps i^−48 steps j^​

The resultant vector is described as a single vector with the same consequence as several other vectors taken together.

R = A + B.Formula 2: To obtain the resultant, opposing vectors are subtracted from one another.Here, a vector B is pointing in the opposite direction of the vector A, as well as the resulting vector is called R.

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Answer:

follows are the responses to the given question:

Explanation:

The kinetic energy of every object moving.  \(PK=m \times v^2\) any entity lifted against the strength of gravity stores elastic potential of gravity.

\(PE = height \times mass \times g\)

Its total power of an independent device stays constant underneath the Mass conservation on Energy and it is, the kinetic energy plus potential energy is just like a fixed \((KE+PE=Standard)\). So, if KE improves, it is valid that PE declines.

If the PE is now at least then KE has been at the highest. It is also valid that KE is reduced as PE is increased as well as the maximum PE, the minimum KE.

Answer:

A.) 18 m/s

B.) 12 m/s

Explanation:

Given that a school bus moves at 15 m/s relative to an outside observer. If a student walks toward the front of the bus at 3 m/s relative to the bus, how fast is the student moving relative to the observer ?

Since the student direction is in the direction of the bus, the student velocity relative to the bus velocity will be:

15 + 3 = 18 m/s

Therefore, the observer will see the student moving very fast at a speed of 18 m/s

 If the same student turns around and walks to the back of the bus at 3 m/s, the student will be moving in an opposite direction. The relative velocity of the student to the observer will be 15 - 3 = 12 m/s

Therefore, the observe will see the student moving very fast at a speed of 12 m/s

The friction between the two solid surfaces depends on the weight of the objects on the surface and the roughness of the object surfaces.

When the two bodies are in contact such that a force acts to restrict the motion of each body, then the force is known as frictional force. And the phenomenon is called friction.

The expression for the frictional force is given as,

\(F = \mu \times N\)

Here,

\(\mu\) is the frictional coefficient and N is the normal reaction. (N = mg)

Clearly, the frictional force is dependent on the frictional coefficient of the surfaces and in turn, depends on the roughness of object surfaces. Also, friction depends on a normal reaction whose value is equivalent to the weight of objects on the surface.

Thus, we can conclude that the friction between the two solid surfaces depends on the weight of the objects on the surface and the roughness of the object surfaces.

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Answer:

A,d

Explanation:

the weight of the objects and the roughness of the objects’ surfaces i took the test