Suppose that you exert 300 N horizontally on a 50-kg crate on a factory floor, where friction between the crate and the floor is 100 N. What is the acceleration of the crate?
Answers
The acceleration of the crate is 4 m/s²
To find the acceleration of the crate, we can use Newton's second law of motion,
Force (F) = mass (m) × acceleration (a).
In this case, we have an applied force of 300 N and a frictional force of 100 N acting against it.
The net force (F_net) will be the difference between the applied force and frictional force:
F_net = 300 N - 100 N = 200 N.
Now, we can use Newton's second law:
F_net = m × a
200 N = 50 kg × a
To solve for acceleration (a), divide both sides by the mass (50 kg):
a = 200 N / 50 kg
a = 4 m/s²
So, the acceleration of the crate is 4 m/s².
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Related Questions
Write 3.5 x 105 in standard form.
Answers
sorry if this is wrong
A shopper in Whole Foods pushes their cart with a force of 40 N directed at an angle of
30 degrees downward form the horizontal. Find the work done by the shopper on the
cart as he moves down a 15 m aisle to the tofu section.
If the mass of the cart (24kg), from problem 1, and we neglect friction, how fast will the cart
be moving when it reaches the tofu section if it started from rest?
The shopper brings the cart to rest is 2.7 s when he reaches the tofu. What power
does he exert in stopping the cart?
You take the bus with your bike to the top of Twin Peaks in San Francisco. You are
facing a long descent: the top of Twin Peaks is 600 m higher than its base. The
combined mass of you and your bicycle is 85 kg. How much gravitational potential
energy do you have before your descent?
• On an unknown airless planet an astronaut drops a 4 kg ball from a 60 m ledge. The
mass hits the bottom with a speed of 12 m/s. What is the acceleration of gravity g on
this planet?
You descend. If all that potential energy is converted to kinetic energy, what will your
speed be at the bottom?
The planet has a twin in an alternate universe with exactly the same acceleration of
gravity. The difference is that this planet has an atmosphere. In this case, when
dropped from a ledge with the same height, the 4 kg ball hits bottom at the speed of 9
m/s. How much energy is lost to air resistance during the fall?
A 1500 kg car starts at rest and speeds up to 3 m/s with a constant acceleration. If the
car reaches its final speed in 1.2 s, what is its acceleration?
•
How far does the car travel in that time?
• What is the car's gain in kinetic energy?
• What power is exerted by the engine?
Answers
Answer:
Work done by the shopper on the cart: The force of 40 N at an angle of 30 degrees downward from the horizontal can be resolved into its horizontal and vertical components. The horizontal component of the force is:F_horizontal = F * cos(theta) = 40 N * cos(30) = 34.64 N
The work done by the shopper on the cart is equal to the force applied multiplied by the distance moved, multiplied by the cosine of the angle between the force and the displacement. In this case, the displacement is 15 m, and the angle between the force and the displacement is 30 degrees. Therefore:Work = F * d * cos(theta) = 34.64 N * 15 m * cos(30) = 448.5 J
Speed of the cart at the tofu section: The initial potential energy of the cart and shopper is equal to their combined mass (85 kg) multiplied by the acceleration due to gravity (9.81 m/s^2) multiplied by the height of Twin Peaks (600 m).
Therefore: Potential energy = m * g * h = 85 kg * 9.81 m/s^2 * 600 m = 498,690 J
Since the shopper neglects friction, all of the potential energy is converted into kinetic energy at the bottom of the hill. The kinetic energy of the cart and shopper can be found using the formula:
Kinetic energy = 0.5 * m * v^2
where m is the mass of the cart and shopper, and v is their speed.
Therefore:Kinetic energy = 0.5 * 85 kg * v^2 Since the potential and kinetic energies are equal, we can set them equal to each other and solve for the speed v: Potential energy = Kinetic energym * g * h = 0.5 * m * v^2v = sqrt(2 * g * h) = sqrt(2 * 9.81 m/s^2 * 600 m) = 109.43 m/s
Power exerted by the shopper in stopping the cart:The shopper brings the cart to rest over a distance of 15 m in a time of 2.7 s. The average force exerted by the shopper on the cart can be found using Newton's second law: F = m * a = m * (v_f - v_i) / twhere m is the mass of the cart, v_i is the initial speed of the cart (which is zero), v_f is the final speed of the cart, and t is the time taken to stop the cart. Solving for F gives:F = m * (v_f / t)The work done by the shopper in stopping the cart is equal to the force applied multiplied by the distance moved, which is 15 m. Therefore:Work = F * d = m * (v_f / t) * d = 24 kg * (0 - 0) / 2.7 s * 15 m = 0 JSince no work is done in bringing the cart to rest, the power exerted by the shopper is zero.Acceleration due to gravity on the unknown planet:The final speed of the 4 kg ball is 12 m/s, and it falls a distance of 60 m. The initial speed is zero, so the final velocity is equal to the velocity acquired due to gravity. The final velocity can be found using the formula:v_f^2 = v_i^2 + 2 * g * hwhere v_i is the initial velocity (which is zero), h is the height fallen, and g is the acceleration due to gravity.
To change the temperature from kelvin to degree Celsius
TK= ( )⁰C
Answers
Answer:
-272.1
Explanation:
1K − 273.15 = -272.1°C
balance of chemical equations
Answers
Answer:
an equation is balanced when the same number of each element is represented on the reactant and product sides. equations must be balanced to accurately reflect the law of conservation of matter.
what’s the equation for this
Answers
You pull a sled with a package on it across a snow-covered flat lawn. If you
apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. What is the
combined mass of the package and the sled? (Assume there is no friction.)
Answers
Answer:52.5
Explanation:
You pull a sled with a package on it across a snow-covered flat lawn. If you apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. The combined mass of the package and the sled m = 52.50 kg
The given data to find Mass,
The force applied to the sled, F = 65.1 N
Acceleration of the sled, a = 1.24 m/s²
What is force?Forces are defined by both strength and direction.
Force is a vector quantity. It is a quantity that is described by Magnitude and Direction. The strength of a force is its magnitude and the direction, well it is the direction the magnitude is applied on the object.
We need to find the combined mass of the package and the sled. Let it is m. Using definition of force as follows :
F = ma
m = F/a
m = 65.1 /1.24
Mass, m = 52.5 Kg.
If you apply a force of 65.1 N to the sled, it accelerates at 1.24 m/s2. The combined mass of the package and the sled m = 52.50 kg
Hence, Option C is the correct answer.
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If two covalently bonded atoms move closer than a distance of the bond length, the potential energy of the atoms.
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If two covalently bonded atoms move closer than a distance of the bond length, the potential energy of the atoms increases
Which bond possesses the highest possible energy?Stronger bonds have lower potential energy than weaker ones. The weaker connection has a higher potential energy. Ionic bonds are stronger than covalent ones, hence covalent bonds have higher potential energy.
The tremendous repulsive interactions between the positively charged nuclei of the bound atoms cause the energy of the system to dramatically rise if the atoms move closer to one another than the ideal bond distance.
If there is an attractive force between the two, the potential energy will rise with more separation, but if there is a repulsive force, the potential energy will fall with greater separation.
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Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to _____.
Answers
Increasing the distance between an electromagnet and the compass will cause the observed effect of the compass to decrease in strength
What would the Increasing the distance between an electromagnet and the compass cause?
The strength of the magnetic field produced by an electromagnet decreases as the distance from the electromagnet increases. This means that if the distance between the electromagnet and the compass increases, the magnetic field that the compass is experiencing will weaken.
As a result, the observed effect of the compass will decrease in strength as the distance between the electromagnet and the compass increases.
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Standing waves are created in the four strings shown in Figure 25. All strings have the same mass per unit length and are under the same tension The lengths of the strings are given. Rank the frequencies of the oscillations, from largest to smallest
Answers
Answer:
The rank of the frequencies from largest to smallest is
The largest frequency of oscillation is given by the string in option D
The second largest frequency of oscillation is given by the string in option B
The third largest frequency of oscillation is given by the string in option A
The smallest frequency of oscillation is given by the string in option C
Explanation:
The given parameters are;
The mass per unit length of all string, m/L = Constant
The tension of all the string, T = Constant
The frequency of oscillation, f, of a string is given as follows;
\(f = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L}\)
Where;
T = The tension in the string
m = The mass of the string
L = The length of the string
n = The number of overtones
\(Therefore, \ {\sqrt{\dfrac{T}{m/L} } } = Constant \ for \ all \ strings = K\)
For the string in option A, the length, L = 27 cm, n = 3 we have;
\(f_A = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 27} = \dfrac{2 \times K}{27} \approx 0.07407 \cdot K\)
For the string in option B, the length, L = 30 cm, n = 4 we have;
\(f_B = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 30} = \dfrac{ K}{12} \approx 0.08 \overline 3\cdot K\)
For the string in option C, the length, L = 30 cm, n = 3 we have;
\(f_C = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 30} = \dfrac{K}{15} \approx 0.0 \overline 6 \cdot K\)
For the string in option D, the length, L = 24 cm, n = 4 we have;
\(f_D = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 24} = \dfrac{5 \times K}{48} \approx 0.1041 \overline 6 \cdot K\)
Therefore, we have the rank of the frequency of oscillations of th strings from largest to smallest given as follows;
1 ) \(f_D\) 2) \(f_B\) 3) \(f_A\) 4) \(f_C\)
The order of the frequencies is \(f_D>f_B>f_A>f_C\)
Standing waves:The frequency of the standing wave in a string tied at both ends is given by:
\(f=\frac{nv}{2L}\)
where n is the mode of frequency
v is the velocity of the wave
and L is the length of the string.
Now the velocity of a wave in a string tied at both ends is given by
\(v=\sqrt{\frac{T}{\mu}}\)
where T is the tension and μ is the mass per unit length.
Since T and μ are the same for all the strings, velocity \(v\) will be the same for all.
Now to find the mode of frequency we can calculate the number of nodes (including the nodes at the ends) in the given figure and subtract by 1. Nodes are the point where the amplitude of the wave is zero.
\(f_A=\frac{3v}{2\times27}=\frac{v}{18}\;s^{-1}\\\\f_B=\frac{4v}{2\times30}=\frac{v}{15}\;s^{-1}\\\\f_C=\frac{3v}{2\times30}=\frac{v}{20}\;s^{-1}\\\\f_D=\frac{4v}{2\times24}= \frac{v}{12}\;s^{-1}\)
Hence, \(f_D>f_B>f_A>f_C\)
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A computational model predicts the maximum height that a roller coaster car can reach when the lowest height of its journey is at ground level, where it has a speed of 20 m/s. Given these conditions, what is the maximum height?(1 point)
196 m
4.8 m
20.4 m
2.0 m
Answers
Answer: 20.4 m
Explanation: \(\frac{9.8^{2} }{Velocity} = Max Height\)
The answers to this test are:
1. What is the maximum speed when the conditions are mass = 450 kg, initial height = 30 m, and the roller coaster car is initially at rest?
24.2 m/s
2. A computational model predicts the maximum height that a roller coaster car can reach when the lowest height of its journey is at ground level, where it has a speed of 20 m/s. Given these conditions, what is the maximum height?
20.4 m
3. A computational model predicts the speed of a roller coaster car at different heights given its speed at the lowest height of its journey, which is at ground level. The speed at the lowest point is 30 m/s. What is the prediction for its speed when it is at a height of 20 m?
22.5 m/s
4. A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lowest point of its journey. Its mass is 350 kg, and it speed at a height of 0 m is 25 m/s. What is the prediction for its maximum potential energy?
109,375 J
5. What is the benefit of using simple computational models in a spreadsheet application, like the one used in this course, to predict mechanical energy and related values?
It is easy to calculate new scenarios.
to stop your vehicle when the brakes fail, a. work the parking brake gradually to prevent locking up the wheels and sending the car out of control. b. pump your foot down on the accelerator. c. shift up to a higher gear to slow the car down. d. all of the above
Answers
The correct answer is option A.
To stop your vehicle when the brakes fail, work the parking brake gradually to prevent locking up the wheels and sending the car out of control.
Due to advanced technology, a complete brake failure has never occurred. However, there is the possibility of an unlikely scenario while driving your vehicle.
If you ever come across such an unfortunate situation where a brake failure occurs in your vehicle while driving here is the advice to act upon.
The few things which are essential to do are:
Keep pressing the brake pedal
Gradually pull down on the parking brake of your vehicle.
If it does not work, shift your attention to the lower gear and make sure one gear at a time to slow down your vehicle.
Drive into less hazardous areas make sure there are no people around you and do not turn off your engine until your vehicle is completely stopped.
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12.5.65 Question Help Given two lines in space, either they are parallel, they intersect, or they are skew (lie in parallel planes). Determine whether the lines below, taken two at a time, are parallel, intersect, or are skew. If they intersect, find the point of intersection. Otherwise, find the distance between the two lines. L1: L2: L3: x= 1-t, y=2-2t, z=2-t, -00
Answers
Lines L1, L2, and L3 are skew (they do not intersect and do not lie in parallel planes). The distance between L1 and L2 is 3 units.
Given lines in space L1, L2, and L3 such thatL1: x= 1-t, y=2-2t, z=2-t,L2: x= -1+3t, y=-1-t, z=3+5tL3: x= 2+s, y= 1+2s, z= -2-3s. Determine whether the lines below, taken two at a time, are parallel, intersect, or are skew (lie in parallel planes) If they intersect, find the point of intersection. Otherwise, find the distance between the two lines.The general equation of a line is given by L1: r = a + λ b Here, (x, y, z) are the coordinates of any point on the line. `a` is the position vector of a known point on the line, `λ` is a scalar parameter, and `b` is the direction vector of the line.L1 : x = 1 - t, y = 2 - 2t, z = 2 - t => r = i + 2j + 2k + (-i - 2j - k)λ = i + 2j + k + t(-i - 2j - k)L2: x = -1 + 3t, y = -1 - t, z = 3 + 5t => r = -i - j + 3k + (3i - j + 5k)λ = 2i - j + 8k + t(3i - j + 5k)L3: x = 2 + s, y = 1 + 2s, z = -2 - 3s => r = 2i + j - 2k + si + 2sj - 3sk = (2 + i) + (1 + 2s)j + (-2 - 3s)k Since the direction vectors of L1 and L2 are not equal and neither are their direction vectors proportional to each other, L1 and L2 are skew lines. Likewise, the direction vector of L3 is not proportional to the direction vector of either L1 or L2 and hence L3 is also skew to the other two lines.The distance between skew lines is the shortest distance between them. It is perpendicular to both the lines. Therefore, we need to find the normal to the plane containing L1 and L2. The normal to the plane containing L1 and L2 is given by the cross-product of their direction vectors. n = b1 × b2 = (-1-2) i + (-2-(-1)) j + (1-4) k = -3i - j - 3k Now, to find the shortest distance, we can take any point on L1 and find its perpendicular distance from L2. For example, we can take the point (1, 2, 2) on L1. The distance is |(r2 - r1).n/|n|| where r1 = i + 2j + 2k is a point on L1 and r2 is the position vector of a point on L2. r2 = -i - j + 3k + 3λi - λj + 5λk. r2 - r1 = -2i - 3j + k + 3λi - λj + 5λkTherefore, the shortest distance between L1 and L2 is |(-2i - 3j + k + 3λi - λj + 5λk).(-3i - j - 3k)/√(9 + 1 + 9) = 3√11/√11 = 3. Therefore, the lines are skew and the distance between L1 and L2 is 3.For more questions on parallel planes
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Please answer correctly.
Will give the brainliest !!!
Urgent !!!
Please help !!
Answers
two planets are orbiting a star in a distant galaxy. both planets follow an elliptical orbit but the semi-major axis of planet b is twice as large as that of planet a. how does the orbital period of planet b compare with that of planet a?
Answers
The semi-major axis an of the ellipse and the period of revolutions T of a planet around the sun are related by the formula T2 = k a3.
Do elliptical machines help people lose weight?An elliptical helps speed up the process of losing body fat since it burns more calories per minute than some other cardio equipment, such as the stationary cycle. This is particularly true if you emphasize interval training.
Is a treadmill preferable than an elliptical?The best machine for you will depend on your specific requirements. Keep using the elliptical if you have a neuromuscular ailment or are prone to injuries. if you really want to increase your calorie burn while strengthening your legs.
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state the law of the conservation of mechanical energy
Answers
Answer:
The law of the conservation of mechanical energy states that the total mechanical energy of a closed system remains constant, unless there is work done by non-conservative forces or heat transfer to or from the system.
In other words, the law states that the sum of the kinetic energy (energy of motion) and potential energy (energy due to position) of a system remains constant as long as there are no non-conservative forces acting on the system. Non-conservative forces are forces that dissipate energy, such as friction and air resistance. If these forces are present, they will convert some of the mechanical energy of the system into other forms of energy, such as heat or sound.
For example, if you lift a book off the ground, you are doing work on the book, which increases its potential energy. At the same time, the kinetic energy of the book decreases, because it is not moving. If you then release the book, it will fall to the ground, converting its potential energy back into kinetic energy. If there are no non-conservative forces present, the sum of the kinetic energy and potential energy of the book will remain constant throughout this process. This is an example of the conservation of mechanical energy in action.
The law of the conservation of mechanical energy states that the total mechanical energy of an isolated system remains constant, unless external forces are present. This means that the sum of the kinetic energy and potential energy within the system will remain constant over time, unless the system is subjected to external forces such as friction or gravity. This law is based on the principle that energy cannot be created or destroyed, but rather it can only be transferred or transformed. Therefore, any changes in the mechanical energy of a system must be due to the transfer or transformation of energy from one form to another, rather than the creation or destruction of energy itself.
Step-by-Step on how to calculate 14N = 3.5 kg × 4 m/sec²?
Answers
The formula for calculating force is:
force = mass x acceleration
The force is 14 Newtons (N).
What is force?
Force is a physical quantity that describes the interaction between two objects, resulting in the acceleration of one or both objects. Force can cause a stationary object to move or change its direction, or it can alter the speed or direction of a moving object. Force is measured in the unit of Newtons (N) and is represented by the symbol F.
In this case, we have a mass of 3.5 kg and an acceleration of 4 m/sec². To find the force, we simply multiply the two values:
force = 3.5 kg x 4 m/sec²
To calculate this, we can use a calculator or do the multiplication by hand. Here's how to do it step-by-step:
Write down the values given in the problem:
mass = 3.5 kg
acceleration = 4 m/sec²
Write down the formula for force:
force = mass x acceleration
Substitute the values given in the problem into the formula:
force = 3.5 kg x 4 m/sec²
Multiply the two values:
force = 14 kg m/sec²
Simplify the unit by replacing kg m/sec² with Newtons (N), which is the unit of force:
force = 14 N
Therefore, the force is 14 Newtons (N).
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What is the electric field amplitude of an electromagnetic wave whose magnetic field amplitude is 2.20 mT
Answers
6.6 * \(10^{5}\) V/m is the electric field amplitude of an electromagnetic wave whose magnetic field amplitude is 2.20 mT
Given the data in the question:Magnetic field amplitude = Bm = 2.20 mT = 2*\(10^{-3}\) T
Electric field amplitude = Em = ?
Electric field:An electric field is a field created by electrically charged particles that attracts or repels other electrically charged particles surrounding it.
The greatest strength of the electric and magnetic fields is known as the electric field amplitude.
It can be said to be,
Em = c * Bm
Where, c is the speed of light(c = 3 * \(10^{8}\) m/s)
Bm is the magnetic field amplitude
On substituting the values we get,
Em = c * Bm
Em = 3 * \(10^{8}\) m/s * 2.20 * \(10^{-3}\) T
Em = 660000 V/m
Em = 6.6 * \(10^{5}\) V/m
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By solving the equation A) f(t)= = B) f(t): C) f(t) D) f(t)= = on [² f(u)du = t_ -L₁ €² 2 f(u)du is obtained: Jo 1+e²t 1 1+ e2t t = 1 1 2t 1-e²t
Answers
By solving the given equation on [² f(u)du = t_ -L₁ €² 2 f(u)du is obtained, we can find t.= J 1+e²t / 1 + e2t / 1-e²tdt. Now, we need to solve the integral,∫ 1+e²t / (1 + e2t)(1-e²t) dt.
For this integral, let u = 1+ e²tSo, du/dt = 2e²And, dt = du/2e²= 1/2e² ∫1+e²t / (u)(1-e²t) du= 1/2e² ∫ (1/u) - (e²/(1-e²t)) du= 1/2e² [ln|u| - ln|1-e²t|] + c.
Now, substituting back the value of u,= 1/2e² [ln|1+ e²t| - ln|1-e²t|] + c= 1/2e² ln|1+ e²t / 1-e²t| + c.
Now, putting the limits in the above expression and solving it, we get the value of t.= [1/2e² ln|1+ e²t / 1-e²t|] t = 1 2t / [1 + e²t] - L₁ 2t / [1-e²t].
Hence, the answer is D) f(t)= 2t / [1 + e²t] - L₁ 2t / [1-e²t].
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-Three positive things about meditation?
-Why is it important?
-Three reasons why you should not eat junk food?
Answers
There are three positive things about meditation:
Gaining a new perspective on stressful situations.Building skills to manage your stress.Increasing self-awareness.Meditation helps you manage anxiety, stress, and depression.
There are three reasons you should not eat junk food:
One of the most common and perceivable effects of junk food is a rise in obesity in an individual.Learning and memory problems. Loss of appetite and digestion.
Meditation can increase alertness and focus but extremes can lead to insomnia and other sleep disorders. I also found it high Meditation is the habitual process of training the mind to focus and redirect one's thoughts. Meditation is growing in popularity as more people discover its many health benefits. You can use it to increase awareness of yourself and those around you.
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please help its URGENT!!
1) Jupiter
2) Mars
3) Mercury
4) Pluto
5) Saturn
A) Smallest of the terrestrial planets.
B) Most habitable other than Earth.
C) Has the most visible rings.
D) Has the giant red dot.
E) Is a Kuiper belt object.
Answers
Answer:
Jupiter - Giant red spot
Mars - Most habitable other than earth
Mercury - Smallest terrestrial planet
Pluto - Is a Kuiper belt object
Saturn - Most visible rings
How did the Japanese Tsunami (2011) happen and explain why it did happen?
Answers
just ask safari
Explanation:
Two bodies P and Q on a smooth horizontal surface are connected by a light cord. The mass of P is greater than that of Q. A horizontal forceF (of magnitude F) is applied to Q, accelerating the bodies to the right. The magnitude of the force exerted by the connecting cord on body P will be___
Two bodies P and Q on a smooth horizontal surface
A) greater than F. B) zero.
C) equal to F. D) less than F but not zero.
Answers
The force exerted by the connecting cord on body P will be less than F, but not zero.
The magnitude of the force exerted by the connecting cord on body P will be D) less than F but not zero. This is because as the force F is applied to body Q, it accelerates to the right and pulls body P along with it due to the connecting cord. However, since the mass of body P is greater than that of Q, it will experience a smaller acceleration than Q. Force is a physical quantity that describes the influence that one object exerts on another. It can be defined as a push or a pull on an object that causes it to accelerate, change direction, or deform. Force is typically measured in units of newtons (N) or pounds (lbs).
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Suppose that you have left a 200-mL cup of coffee sitting until it has cooled to 30âC , which you find totally unacceptable. Your microwave oven draws 1100 W of electrical power when it is running. If it takes 45 s for this microwave oven to raise the temperature of the coffee to 60âC , what is the efficiency of heating with this oven?
e=(what you get/what you had to pay)
A) Which of the following is the quantity you would label as "what you got"?
B) Which of the following is the quantity you would label as "what you had to pay"?
C) Find the efficiency e of the oven. You will need to use the fact that 4.2 J of energy is required to raise the temperature of 1.0 mL of coffee by 1.0âC .
D) The oven draws 1100 W of power, and you have determined that it heats with an efficiency of 51%. Using this information, determine the time t it would take to bring 240 mL of water from 25âC to 100âC . Note that 4.2 J of energy is required to raise the temperature of 1.0 mL of water by 1.0âC (the same as for the coffee above).
Answers
A) The quantity labeled as "what you got" is the increase in thermal energy of the coffee, which is given by the equation:
ΔQ = mcΔT
where m is the mass of the coffee, c is the specific heat capacity of coffee (assumed to be the same as water), and ΔT is the temperature increase.
B) The quantity labeled as "what you had to pay" is the electrical energy consumed by the microwave oven, which is given by the equation:
E = Pt
where P is the power of the microwave oven and t is the heating time.
C) We can first calculate the thermal energy gained by the coffee:
ΔQ = mcΔT = (0.2 kg)(4.2 J/g°C)(60°C - 30°C) = 504 J
Next, we can calculate the electrical energy consumed by the microwave oven:
E = Pt = (1100 W)(45 s) = 49500 J
The efficiency of heating is then:
e = ΔQ/E = 504 J/49500 J = 0.0102 or 1.02%
D) We can use the same equations as above, but solve for the heating time instead of the efficiency:
ΔQ = mcΔT = (0.24 kg)(4.2 J/g°C)(100°C - 25°C) = 2268 J
E = Pt = (1100 W)t
e = ΔQ/E = 0.51 = 2268 J/(1100 W)t
Solving for t, we get:
t = ΔQ/(0.51E) = 2268 J/(0.51)(240 mL)(4.2 J/g°C)(75°C)(1 kg/L)(1100 W/s) = 925 seconds or 15.4 minutes.
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What is the exact value of sin 60°? radical 3 over 2 radical 2 over 2 one half 0
Answers
The precise value of sin 60 degrees is 3/2, as solved by trigonometry.
What is the value of sin 60°?0° Cos = Sin 90° = 1
Cos 30°= Sin 60°= 1/32
45° Cos = Sin 45° = 1/2
60° Cos = Sin 30° = 1/2
90° Cos = Sin 0° = 0
Also,
Tan 0 degrees = Sin 0 degrees/Cos 0 degrees = 0 degrees
Tan 30 degrees = Sin 30 degrees/Cos 30 degrees = 1/3
Tan 45 degrees = Sin 45 degrees/Cos 45 degrees = 1
Sin 60°/Cos 60° = 3
Sin 90°/Cos 90°= Tan 90°
The above trigonometric ratio values are in degrees. We can also talk about the values in terms of radians. Radians are used for unit circles with radius one. The radian is represented as.
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Which wave measure is changing by the greatest amount in the image?
A. amplitude
B. wavelength
C. speed
D. frequency
Answers
Answer: frequency
Explanation:
amplitude is the max height at which the wave reaches
wavelength distance b/w two waves
the speed at which the wave is oscillating
frequency is no. of oscillations of a wave per unit length
6. An elephant is putting 25,000 newtons of force on Leah. The elephant
is accelerating at a rate of 10 mIs? what is its mass?
Answers
2,500 kg
Explanation:
Mass= force/acceleration
25,000/10=2,500
When the rocket launched the astronauts aboard experienced an acceleration of 32 m/s^2. If one of the astronauts had a mass of 65 kg, what net force in newtons did the astronaut experience?
Answers
Answer:
The question is somewhat vague in that acceleration is not exactly defined:
Usually a = (v2 - v1) / t which would imply that
a = 32 / g = 32 / 9.8 = 3.27 the acceleration due to change in speed of the rocket
One can also say that the astronaut experiences an acceleration of 9.8 m/s^2 just by being motionless on the surface of the earth.
Then a = (32 - 9.8) / 9.8 = 2.27 due to the acceleration of the rocket
If we assume the first condition then
F = 65 kg * 3.27 * 9.8 m/s^2 = 2083 N
the critical angle for an air glass interface is 30 degrees. when a light ray in air is incident to the surface, if the reflected ray is 100% polarized, what is the angle of the refracted ray
Answers
The critical angle (θ\(_{c}\)) for an air-glass interface is the angle of incidence at which the refracted ray becomes parallel to the interface. When the angle of incidence exceeds the critical angle, total internal reflection occurs. Therefore, the angle of the refracted ray is 60 degrees.
Given that the reflected ray is 100% polarized, we can assume that the incident light is incident at the polarizing angle, which is the angle of incidence at which the reflected and refracted rays are perpendicular to each other.
In this case, the polarizing angle is equal to the angle of incidence (θ\(_{I}\)) plus the angle of refraction (θ\(_{r}\)):
θ\(_{I}\)+ θ\(_{r}\)= 90 degrees
Since the refracted ray is perpendicular to the reflected ray, the angle of incidence and angle of refraction are complementary angles:
θ\(_{I}\)+ θ\(_{r}\) = 90 degrees
θ\(_{I}\) = 90 degrees - θ\(_{r}\)
Now, let's find the angle of refraction (θ\(_{r}\)) using the critical angle (θ\(_{I}\)) of 30 degrees:
θ\(_{I}\) = 90 degrees - θ\(_{r}\)
θ\(_{c}\)= 30 degrees
Since the critical angle is the angle of incidence at which total internal reflection occurs, the angle of incidence in this case is equal to the critical angle:
θ\(_{I}\) = θ\(_{c}\)
Substituting the values:
30 degrees = 90 degrees - θ\(_{r}\)
Solving for θ\(_{r}\):
θ\(_{r}\) = 90 degrees - 30 degrees
θ\(_{r}\)= 60 degrees
Therefore, the angle of the refracted ray is 60 degrees.
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What is the wavelength of a 285-Hz sound wave when the speed of sound is 375 m/s?A. 1.2 mB. 1.32 mC. 106.875 kmD 0.76 m
Answers
ANSWER
\(B.\text{ }1.32\text{ }m\)EXPLANATION
The speed of a wave is given by the formula:
\(v=\lambda *f\)where λ = wavelength
f = frequency
Hence, the wavelength of the wave is:
\(\lambda=\frac{v}{f}\)Therefore, the wavelength of the sound wave is:
\(\begin{gathered} \lambda=\frac{375}{285} \\ \lambda=1.32\text{ }m \end{gathered}\)The answer is option B.
If Argon's melting point is -309 degrees then what is its freezing point?
Answers
The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.
The freezing point is the temperature at which the substance changes its phase from liquid to solid.
The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.