suppose a 32 mh inductor has a reactance of 95 ω.What would be the frequency in Hz

The given wave spectrum can be approximated by the combination of these 5 waves. Each wave has a specific amplitude and frequency, which together create the overall shape of the wave spectrum.

The given wave spectrum consists of 7m 11 sec issc wave with 5 regular amplitudes and frequencies waves. The amplitudes and frequencies of the waves are as follows:

Wave 1: Amplitude = 1.1m, Frequency = 0.35 rad/s
Wave 2: Amplitude = 1.4m, Frequency = 0.45 rad/s
Wave 3: Amplitude = 1.1m, Frequency = 0.55 rad/s
Wave 4: Amplitude = 1.0m, Frequency = 0.7 rad/s

To understand the overall wave spectrum, we need to consider the contributions of each individual wave.

The given wave spectrum can be approximated by the combination of these 5 waves. Each wave has a specific amplitude and frequency, which together create the overall shape of the wave spectrum.

By adding the contributions of each wave, we can visualize the resulting wave spectrum. For example, if we were to graph the amplitude of the waves over time, we would see the combined effect of all 5 waves.

We can consider an analogy. Imagine a group of people playing different musical instruments. Each person represents a wave with their own unique sound (amplitude) and rhythm (frequency). When they play together, their individual contributions create a harmonious melody, just like the combination of waves in the given wave spectrum.

The given wave spectrum can be approximated by the combination of 5 regular amplitudes and frequencies waves. Each wave contributes to the overall shape of the spectrum, and by considering their individual effects, we can understand the behavior of the wave spectrum as a whole.

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Table at rest, Books on a table, See-saw are objects in equilibrium found in the class room.

There is no net force acting on an object and it is said to be in equilibrium if the size and direction of the forces acting on it are precisely balanced. If an object is moving with a constant velocity, it is in equilibrium because its acceleration is zero. The fundamental function of an object in equilibrium is a zero acceleration.

Two forces are in equilibrium when they are acting on an object that is stationary or moving at a constant speed. The body will accelerate if the forces have a result rather than canceling each other out.

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The temperature of the inner surface of the window will be lower than the room temperature, 21°C.

The steady rate of heat transfer through a double-pane window is determined by the heat conduction through the glass layers, convection to the outdoor air, and convection to the room air. The temperature of the inner surface of the window will depend on the temperature difference between the outdoors and the room.

The heat transfer rate, Q, through the double-pane window can be calculated using the overall heat transfer coefficient U:

Q = U × (Area of window) × (Temperature difference)

The overall heat transfer coefficient can be calculated using the equation below:

U = 1/[(1/h1) + (L/k) + (1/h2)]

Where h1 and h2 are the convection heat transfer coefficients on the inner and outer surfaces of the window, respectively; L is the thickness of the air space between the two glass layers; and k is the thermal conductivity of the air space.

Given the parameters in the question, the overall heat transfer coefficient is calculated to be U = 1.30 W/m2K. Thus, the heat transfer rate through the double-pane window is

Q = 1.30 × (2.4 m × 1.5 m) × (26 K) = 72 W.

The temperature of the inner surface of the window can be calculated by considering the heat transfer balance between the room air and the outdoor air. The rate of heat transfer from the outdoors is

Qout = h2 × (2.4 m × 1.5 m) × (26 K) = 90 W.

The rate of heat transfer to the room air is

Qin = h1 × (2.4 m × 1.5 m) × (26 K) = 36 W.

Thus, the rate of heat transfer to the room air is 72 W - 90 W = -18 W.

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The law of reflection states that the angle of incidence and the angle of reflection will always be equal.

When a ray of light reflects off a surface, the angle of reflection is equal to the angle of incidence.

The expression to be simplified is, A + BC + ABCD. Using De Morgan's theorem, we can convert complementation bars extending over multiple variables into complementation bars over single variables. The De Morgan's theorem states that the complement of a product is equal to the sum of complements. De Morgan's Theorem:

 1.   (AB) = A + B2.  (A + B) = A B The steps to simplify the given expression using De Morgan's theorem are as follows: A + BC + ABCD = A + (BC + ABCD) = A + (BC). (ABCD) = A + (B + C) (A + B + C + D) = A + AB + AC + BC + BD = A + AC + BC + BD.

Hence, the simplified expression is A + AC + BC + BD. Thus, using DeMorgan's Theorem and other applicable rules of Boolean algebra, the given expression is simplified to A + AC + BC + BD.

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Answer:-4410 m

Explanation:

Displacement = velocity*time

Displacement = -98 m/s * 45 s

Displacement = -4410 m

Answer:

Wavelength = 0.44 meter

Time period = 0.0013 seconds

Explanation:

Given:

Speed of sound = 330 m/s

Frequency = 750 Hz

Find:

Wavelength

Time period

Computation:

Wavelength = Velocity / Frequency

Wavelength = 330 / 750

Wavelength = 0.44 meter

Time period = 1 / Frequency

Time period = 1/750

Time period = 0.0013 seconds

Answer:

a

Explanation:

because if gas particles move they move with speed and that is because they are free,so when they bump into something,they bump into it with force so it converts the energy

Explanation:

If acceleration points in the same direction as the velocity, the object will be speeding up. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

The force which counteracts the thrust force for the flight is known as the drag force, as it opposes the flow.

Drag is a force that opposes an object's relative motion to a fluid environment in the field of fluid dynamics. It may be among two liquid film (or surfaces) or in between a liquid and a flat wall. The drag force is influenced by velocity, as opposed to other resistive forces like dry contact, which are essentially independent of it.

When a flow is moving at low or high speed, the drag force is equal to the speed for low pressure and to the square of the velocity for high-speed flow. Although viscous friction is what ultimately causes drag, turbulent drag is unaffected by viscosity.

A force in physics is an input that has the power to change an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces.

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The drag force, which resists the flow, is the force that balances the propulsion force for flight.

In the study of fluid dynamics, drag is a force that opposes an object's relative motion to a fluid environment. It could be situated between two liquid surfaces (or films) or between a liquid and a flat wall.

Unlike other resistive forces like dry contact, which are largely independent of velocity, the drag force is affected by it.

For low pressure and high speed flows, respectively, the drag force is equal to the speed for low pressure and the square of the velocity. Although drag is ultimately caused by viscous friction, turbulent.

Thus, The drag force, which resists the flow, is the force that balances the propulsion force for flight.

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Answer:

\(0.78m \: per {s}^{2} \)

The quantity of outlets that must be installed on each of the branch circuits has no set maximum.

Technically, a 15 amp circuit breaker may support any number of outlets. A good guideline is 1 outlet per 1.5 amps, up to 80% of the circuit breaker's capability. As a result, we advise no more than 8 outlets on a 15 amp circuit. You see, the number of outlets that can be installed on a single 20 amp circuit is not explicitly capped by the National Electrical Code (NEC). A lighting and appliance branch circuit panelboard may have up to 42 overcurrent devices fitted (excluding the main device), in accordance with NEC.

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The buoyant force depends on the volume of the liquid displaced.

A force that is generated upward by the water that an object displaces is known as buoyancy.

It is directly proportional to the volume (weight) of water that is being displaced by an object, in accordance with Archimede's principle

Therefore, the force of buoyancy pushing an object up increases as an object displaces more water.

Where;

Fb is the amount of buoyant force a liquid exerts on an object.

gravity-induced acceleration, or g.

p equals the liquid's density.

v is the liquid's displacement volume.

h is the height of water that an object has moved.

A stands for the floating object's surface area.

The buoyancy unit of measurement is the Newton (N).

Additionally, the buoyant force acting on a fluid is directly inversely correlated to its density, meaning that as a liquid's density falls, buoyancy increases, and vice versa.

Therefore, the assertion that the buoyant force on an item submerged in a liquid relies on the volume of the liquid displaced is valid.

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1. The discrete least squares polynomial of the 2nd degree that fits the data is f(x) = -0.553x^2 + 1.025x + 0.022. 2. The discrete least squares trigonometric polynomial S4(x) is S4(x) = 0.026 + 0.994cos(x) + 0.995cos(2x) - 0.118sin(x) - 0.012sin(2x).

1. To find the discrete least squares polynomial of the 2nd degree, we use the method of least squares to minimize the sum of the squared differences between the given data points and the polynomial.

The resulting polynomial is f(x) = -0.553x^2 + 1.025x + 0.022.

2. To find the discrete least squares trigonometric polynomial, S4(x), we express the polynomial in terms of trigonometric functions (cos and sin) to fit the given data points.

Using the method of least squares, we minimize the sum of the squared differences between the data points and the trigonometric polynomial.

The resulting polynomial is S4(x) = 0.026 + 0.994cos(x) + 0.995cos(2x) - 0.118sin(x) - 0.012sin(2x).

These polynomials provide the best fit for the given data points using the least squares method.

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Electrostatic force the force between static charges.Net force is 12056.9 q N in the positive y-direction, found by vector summing forces from charges q1, q2, and q3.

To find the net electrostatic power applied on the point charge, we want to compute the power applied by every one of different charges and afterward find the vector amount of these powers.To start with, we can compute the power applied on the point charge by q1. We can utilize Coulomb's regulation to track down the extent of the power:

F1 = k * q1 * q/\(d^2\)

Where k is the Coulomb steady (\(9 x 10^9 N m^2/C^2\)). Connecting the qualities, we get:

F1 = \(9 x 10^9 * 12 x 10^-6 * q/(0.016)^2\)

F1 = 2535.94 q N

The heading of the power applied by q1 is towards the point charge, since q1 is positive.Then, we can ascertain the power applied on the point charge by q2. Since q2 is negative, the power will be the other way of the vector joining the two charges. Utilizing Coulomb's regulation once more, we get:

F2 = k * q2 * q/\(d^2\)

F2 = \(9 x 10^9 * (- 2.0) * 12 x 10^-6 * q/(0.016)^2\)

F2 = - 5071.88 q N

The extent of the power is more noteworthy than the power applied by q1, yet the heading is inverse.At long last, we can compute the power applied on the point charge by q3. Utilizing Coulomb's regulation once more, we get:

F3 = k * q3 * q/\(d^2\)

F3 =\(9 x 10^9 * 30 * 12 x 10^-6 * q/(0.016)^2\)

F3 = 11462.5 q N

The heading of the power applied by q3 is towards the point charge, since q3 is positive.To find the net power, we really want to add these three vectors. Since the heading of the power applied by q2 is inverse to that of q1 and q3, we want to take away it from the amount of the other two vectors. Composing the vectors in part structure and adding them, we get:

Fnet = (2535.94 - 5071.88) I + (0) j + (11462.5) k

Fnet = - 2535.94 I + 11462.5 k

The greatness of the net power is:

|Fnet| = \(sqrt((- 2535.94)^2 + (0)^2 + (11462.5)^2) = 12056.9 q N\)

The heading of the net power is towards the positive y-pivot, since there is no part of the power in the x-bearing. Accordingly, the net electrostatic power applied on the point charge is 12056.9 q N in the positive y-course.

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Answer:

B. The field is moving

An object has gravitational potential energy due to its an position relative to the gravitational field it is in.

The gravitational potential energy is determined by the mass of the object, the gravitational constant, and the distance between the object and the source of the gravitational field.

Gravitational potential energy is a type of potential energy that an object can have due to its position in a gravitational field. It is the energy that is stored in an object due to its position in a gravitational field and can be converted into other forms of energy.

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Answer:

axon

Explanation:

we have that from the Question"Three people trying to move a box. Which set of forces will result in a net force on the box of 20 N to the right?" it can be said that  

From the Question we are told

Three people trying to move a box. Which set of forces will result in a net force on the box of 20 N to the right?

Generally the equation for Net Force is mathematically given as

Fn=Fx+Fy...

Therefore

The force from the option that give a  Net Force  of 20 to the right is

\(Fn=(28+10)-(18)\\\\Fn=20N\)

Therefore

The set of forces which will result in a net force on the box of 20 N to the right is

Option D

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Answer: The correct answer is A

55N, 16N, 17N

Explanation: I took the quiz

Answer:

I think its C and D

Explanation:Force is like a energy that moves stuff. :)

Fluid viscosity is the property of the fluid that is responsible for the development of the velocity boundary layer. Non-viscous fluids do  not exhibit the property of velocity boundary layer in a pipe.

What is fluid viscosity?

Thickness of a fluid is called its viscosity. In liquids, velocity boundary layer is formed due to viscosity.

Viscosity is also termed as the flow rate of a liquid. If a liquid has a high flow rate then its viscosity is low and vice versa.

The fluid viscosity can be measured by using viscometer. The formula to measure viscosity is F = μA. u/y

Here F is force,  μ is fluid viscosity, A is the area and u/y sheer deformation rate.

On the contrary, a non-viscous fluid is one that has less thickness and can flow easily.

For example, water is a non-viscous fluid.

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The gravitational potential energy (PE) of an object is given by the formula:

PE = mgh

where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.

In this case, the bell has a PE of 8,550 J and a mass of 20 kg. We can rearrange the above formula to solve for the height h:

h = PE/(mg)

Substituting the given values, we get:

h = 8,550 J / (20 kg x 9.81 m/s^2) ≈ 43.4 meters

This is the height from which the bell falls. When the bell falls to the ground, all of its PE is converted to kinetic energy (KE). The formula for KE is:

KE = (1/2)mv^2

where m is the mass of the object and v is its velocity.

Setting the PE equal to the KE, we get:

PE = KE

mgh = (1/2)mv^2

Simplifying and solving for v, we get:

v = √(2gh)

Substituting the values for g and h, we get:

v = √(2 x 9.81 m/s^2 x 43.4 m) ≈ 29.4 m/s

Therefore, the final velocity of the bell when it hits the ground is approximately 29.4 m/s.

To solve this problem, we can apply the principle of conservation of angular momentum.Since the final angular velocity is zero, the bar will not rotate after the collision. Therefore, the other ball will not rise after the collision, and it will remain at the same height.

The angular momentum (L) of an object can be calculated as the product of its moment of inertia (I) and angular velocity (ω):

L = I × ω

For the system consisting of the bar and the two balls, the initial angular momentum is zero, and after the collision, the angular momentum is given by:

L = I × ω

The moment of inertia (I) of the system is the sum of the moment of inertia of the bar and the moment of inertia of the two balls.

The moment of inertia of the bar (I\(_{bar}\)) about its center can be calculated as:

I\(_{bar}\) =  × m\(_{bar}\) × L²

where m\(_{bar}\) = 8.0 kg is the mass of the bar and L = 4.0 m is the length of the bar.

The moment of inertia of each ball (I\(_{ball}\)) about the pivot point can be calculated as:

I\(_{ball}\) = m\(_{ball}\) × R²

where m\(_{ball}\)= 5.0 kg is the mass of each ball, and R is the distance from the pivot point to the ball.

Since the balls are attached to the ends of the bar, the distance from the pivot point to each ball is half the length of the bar:

R = \(\frac{L}{2}\)= \(\frac{4}{2}\) = 2.0 m

Now, let's calculate the total moment of inertia :

I\(_{bar}\)= (1/12) × 8.0 kg × (4.0 m)²

= 8/3 kg·m²

I\(_{ball}\)= 5.0 kg × (2.0 m)²

= 20 kg·m²

I\(_{ball}\)= I\(_{bar}\) + 2 × I\(_{ball}\)

= 8/3 kg·m² + 2 * 20 kg·m²

= 8/3 kg·m² + 40 kg·m²

= 8/3 kg·m² + 120/3 kg·m²

= 128/3 kg·m²

After the collision, the system will rotate about the pivot point with an angular velocity (ω). The angular velocity can be calculated from the conservation of angular momentum equation:

L\(_{initial}\) = L\(_{final}\)

0 = I\(_{initial}\) × ω\(_{initial}\) + I\(_{ball}\) × ω\(_{final}\)

Since the initial angular velocity is zero, we can solve for the final angular velocity:

I\(_{ball}\) *ω\(_{final}\)= 0

Now, let's calculate the final angular velocity (ω\(_{final}\)):

ω\(_{final}\)= 0 / (I\(_{total}\) + I\(_{ball}\))

= 0 / (128/3 kg·m² + 20 kg·m²)

= 0 / (128/3 kg·m² + 60/3 kg·m²)

= 0 / (188/3 kg·m²)

= 0

Since the final angular velocity is zero, the bar will not rotate after the collision.

Therefore, the other ball will not rise after the collision, and it will remain at the same height.

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Answer:

the answer would be kinetic energy

The unit vectors along the three co-ordinate axes are described as. i > j > k > 1. is D. i = j = k = 1

A vector that has a volume of 1 is a unit vector. It is also known as a direction vector because it is generally used to denote the direction of a vector. The vectors i, j, k, stand the unit vectors along the x-axis, y-axis, and z-axis respectively.

There are three essential unit vectors which are commonly employed and these are the vectors in the direction of the x, y and z-axes. The unit vector in the direction of the x-axis is i, the unit vector in the direction of the y-axis is j and the unit vector in the demand of the z-axis is k.

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The merry-go-round is accelerating since it is moving in a circle despite the fact that it is moving at a constant speed. The fact that an object moves in a circle does not always imply that it is moving at a constant speed. When an object moves in a circle, it changes direction, and this alteration of direction implies that the object is accelerating.

Even if the speed remains constant, it is still accelerating because the velocity is changing. This is referred to as centripetal acceleration. Centripetal acceleration is the acceleration caused by a force that pulls an object towards the center of the circle. Centripetal force is required for a body to move in a circle. A merry-go-round moves in a circle at a constant speed. This implies that the speed of the merry-go-round does not vary. However, the direction of motion changes continuously, indicating that the merry-go-round is constantly accelerating. Therefore, the merry-go-round is accelerating despite the fact that it is moving at a constant speed.

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Answer:

Systems always tend toward a state of decreasing order unless more energy is provided into the system to counteract this tendency.