subtract 2 16/21 - (-8 5/21). reduce if possible​

Answer:

3.9375 Hope that answered your question

Answer:

the Letter A:x=6+3/10 jjjjjmk

Answer:

Set your calculator to Degree mode.

a² = 17² + 20² - 2(20)(17)cos(89°)

a² = 677.13236

a = 26.0 in.

sin(89°)/26.02177 = (sin B)/17

sin B = 17sin(89°)/26.02177

B = 40.8°

C = 50.2°

Answer:

x=−2

Step-by-step explanation:

−2x+5−5=9−5

−2x=4

-2x/-2 = 4/-2

x=−2

Answer:

Answer is, 26.4

Step-by-step explanation:

By subtracting 51.82 by 26.37, you're left with a total of 26.37, and by rounding that to the tenths place, you get 26.4

Answer:

true

Step-by-step explanation:

first divide then multiply then add then subtract

Let's assume that John buys x boxes of Cereal A and y boxes of Cereal B. Then, we can write the following system of inequalities based on the nutrient and calorie requirements:

10x + 5y ≥ 500 (minimum 500 units of vitamins)

5x + 10y ≥ 600 (minimum 600 units of minerals)

15x + 15y ≥ 1200 (minimum 1200 calories)

We want to minimize the cost, which is given by:

0.5x + 0.4y

This is a linear programming problem, which we can solve using a graphical method. First, we can rewrite the inequalities as equations:

10x + 5y = 500

5x + 10y = 600

15x + 15y = 1200

Then, we can plot these lines on a graph and shade the feasible region (i.e., the region that satisfies all three inequalities). The feasible region is the area below the lines and to the right of the y-axis.

Next, we can calculate the value of the cost function at each corner point of the feasible region:

Corner point A: (20, 40) -> Cost = 20

Corner point B: (40, 25) -> Cost = 25

Corner point C: (60, 0) -> Cost = 30

Therefore, the minimum cost is $20, which occurs when John buys 20 boxes of Cereal A and 40 boxes of Cereal B.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  lower bound is  \(0.0234\)

The  upper bound is  \(0.100\)

So from the value obtained the solution to the question are

  1  Does not include

  2 sufficient

 3  not different  

Step-by-step explanation:

From the question we are told that

The  sample size of  individuals who earned in excess of​ $100,000 per​ year is   \(n_ 1 = 1205\)

The  number of  individuals who earned in excess of​ $100,000 per​ year  that said yes is

    \(w = 712\)

The  sample size  individuals who earned less than​ $100,000 per​ year is \(n_2 = 1310\)

The  number of  individuals who earned less than​ $100,000 per​ year that said yes is

       \(v= 693\)

The sample proportion of  individuals who earned in excess of​ $100,000 per​ year  that said yes is

           \(\r p _ 1 = \frac{w}{n_1 }\)

substituting values

          \(\r p _ 1 = \frac{712}{1205}\)

          \(\r p _ 1 =0.5909\)

The sample proportion of  individuals who earned less than​ $100,000 per​ year that said yes is

          \(\r p _ 1 = \frac{v}{n_2 }\)

substituting values

         \(\r p _ 1 = \frac{693 }{1310}\)

        \(\r p _ 1 = 0.529\)

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \(\alpha = 1 -0.95\)

           \(\alpha = 0.05\)

 Next we obtain the critical value of  \(\frac{\alpha }{2}\) from the normal distribution table the value is  \(Z_{\frac{\alpha }{2} } = 1.96\)

    Generally the margin of error is  

   \(E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{ \r p _1 (1- \r p_1 )}{n_1} + \frac{ \r p _2 (1- \r p_2 )}{n_2} } }\)

substituting values

   \(E = 1.96 * \sqrt{ \frac{ 0.5909 (1- 0.5909 )}{1205} + \frac{ 0.592 (1- 0.6592 )}{1310} } }\)

    \(E =0.03846\)

Generally the 95% confidence interval is  

        \((\r p_1 - \r p_2) - E < p_1 - p_2 <( \r p_1 - \r p_2 ) + E\)

substituting values

        \((0.5909 - 0.529 ) - 0.03846 < p_1 - p_2 < (0.5909 - 0.529 ) + 0.03846\)

         \(0.02344 < p_1 - p_2 < 0.10036\)

The  lower bound is  \(0.0234\)

The  upper bound is  \(0.100\)

So from the value obtained the solution to the question are

  1  Does not include

  2 sufficient

 3  not different  

The lower bound is 0.0234 and the upper bound is 0.100. Then the 95% confidence interval is (0.0234, 0.100)

The probability or the chances of error while choosing or calculating a sample in a survey is called the margin of error.

The research group asked the following question of individuals who earned in excess of​ $100,000 per year and those who earned less than​ $100,000 per​ year.

The sample size of individuals who earned in excess of $100,000 per year will be

\(\rm n_1 =1205\)

The sample size of individuals who earned less than $100,000 per year will be

\(\rm n_1 =1205\)

The number of individuals who earn an excess of $100,000 per year that said yes will be

\(\rm w = 712\)

The number of individuals who earn less than $100,000 per year that said yes will be

\(\rm v= 693\)

Then the sample proportion of individuals who earned in excess of $100,000 per year that said yes will be

\(\rm \hat{p}_1=\dfrac{w}{n_1}\\\\\hat{p}_1=\dfrac{712}{1205}\\\\\hat{p}_1= 0.5909\)

Then the sample proportion of individuals who earned less than $100,000 per year that said yes will be

\(\rm \hat{p}_2=\dfrac{v}{n_2}\\\\\hat{p}_2=\dfrac{693}{1310}\\\\\hat{p}_2= 0.529\)

The confidence level is 95% then the level of significance is mathematically represented as

\(\alpha =1-0.95\\\\\alpha =0.05\)

Then the critical value of α/2 from the normal distribution table. Then the value of z is 1.96, then the error of margin will be

\(E = z_{\alpha /2} \times \sqrt{\dfrac{\hat{p}_1(1-\hat{p}_1)}{n_1} + \dfrac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\E = 1.96 \times \sqrt{\dfrac{05909(1-0.5909)}{1205} + \dfrac{0.529(1-0529)}{1310}}\\\\E = 0.03846\)

The 95% confidence interval will be

\(\begin{aligned} (\hat{p}_1-\hat{p}_2)-E & < p_1-p_2 < (\hat{p}_1-\hat{p}_2) + E\\\\(0.5909 - 0.529) - 0.03846 & < p_1-p_2 < (0.5909 - 0.529) + 0.03846\\\\0.02344 & < p_1-p_2 < 0.10036 \end{aligned}\)

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Answer:

21,866,655ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Answer: 21866655

Step-by-step explanation:

Usando el área del círculo, se encuentra que el area da la pizza es de 2123.7 cm².

----------------------

El área de un círculo de radio r está dada por

\(A = \pi r^2\)

----------------------

\(r = \frac{d}{2} = \frac{52}{2} = 26\)

\(A = \pi r^2 = \pi(26)^2 = 2123.7\)

La area da la pizza es de 2123.7 cm².

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The Gwen draws lines or connects junctions using a straightedge, whereas Saul connects points or intersections with a line through two points button.

Lines that intersect at a right angle are named perpendicular lines. Lines that are always the same distance apart from each other known as parallel lines.

The main difference between their methods is that Saul utilizes a compass to generate an arc, whereas Gwen does not.

In addition, Gwen draws lines or connects junctions using a straightedge, whereas Saul connects points or intersections with a line through two points button.

Aside from that, they will both form the same figure or structure.

Thus, the Gwen draws lines or connects junctions using a straightedge, whereas Saul connects points or intersections with a line through two points button.

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Answer:

3, 2√2, √7

Step-by-step explanation:

compute the square roots of the next three prime numbers:

√7

√11

√13

Therefore, the next three terms of the sequence are:

{1, √2, √3, 2, √5, √7, √11, √13}

chatgpt

chat

Answer:

\(x=8, y=3\)

Step-by-step explanation:

Recall that if a matrix multiplication of two matrices is defined, then the number of columns of the first matrix is equivalent to the number of rows of the second matrix.

Since matrix M has (11-x) columns and matrix N has y rows, and MN is defined, so it follows:

\(y=11-x----(1)\)

Since matrix N has (y+5) columns and matrix M has x rows, and NM is defined, so it follows:

\(y+5=x----(2)\)

Substitute (1) into (2):

\(11-x+5=x\\2x=16\\\therefore x=8--(3)\)

Substitute (3) into (1):

\(y=11-8=3\)

Answer:

4,500

5 or above give it a shove, 4 or below, let it go

The travelled distance of the traveller is equal to 195 kilometers.

According to the statement of the problem, a traveller already walked a third part of his trail and if he travels the half of his trail, then the half of his trail shall be covered. Mathematically, the travelled distance shall be described by following expression:

x = d / 3

x + 65 = d / 2

Where:

Now we proceed to determine the travelled distance:

d / 3 + 65 = d / 2

d / 2 - d / 3 = 65

3 · d - d = 390

2 · d = 390

d = 195

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The calculated value of x at g(x) = 2 is x = 2.5

from the question, we have the following parameters that can be used in our computation:

f(x) = 3x - 1

Also, we have

g(x) = 2x - 3

When g(x) - 2, we have

2x - 3 = 2

So, we have

2x = 5

Divide by 2

x = 2.5

Hence, the value of x at g(x) = 2 is x = 2.5

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Answer:

7,8.5

Step-by-step explanation:

Answer: First, take a picture that isn't blurry

Step-by-step explanation: Re-post so I can help Mr. or Ms. eeeeeeeeeeeeeeeeeeeeeeeeee

The equation for the plane passing through Q and perpendicular to line PQ is r (2 i + 3 j + 6 k) + 28 = 0.

Let position vector of point P be:

p = 3 i + j + 2 k

Let position vector of point Q be:

q = i - 2 j - 4 k

So, PQ = Q - P

PQ = n = i - 2 j - 4 k - (3 i + j + 2 k)

n = i - 2 j - 4 k - 3 i - j - 2 k

n = - 2 i - 3 j - 6 k

The Equation of plane passing through point Q and perpendicular to PQ will be:

(r - q).n = 0

r n = q n

q n = (i - 2 j - 4 k) . (- 2 i - 3 j - 6 k)

q n = - 2 + 6 + 24

q n = 28

r n = 28

r (- 2 i - 3 j - 6 k) = 28

r (2 i + 3 j + 6 k) + 28 = 0

Therefore the equation for the plane passing through Q and perpendicular to line PQ is r (2 i + 3 j + 6 k) + 28 = 0.

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Answer:

(C)\(6t^2+5\)

Step-by-step explanation:

Given the distance, d(t) of a particle moving in a straight line at any time t is:

\(d(t) = 2t^3 + 5t - 2, $ where t is given in seconds and d is measured in meters.\)

To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).

\(v(t)=\dfrac{d}{dt}\\\\v(t) =\dfrac{d}{dt}(2t^3 + 5t - 2) =3(2)t^{3-1}+5t^{1-1}\\\\v(t)=6t^2+5\)

The correct option is C.

Answer:

6t2+5

Step-by-step explanation:

A system may or may not be:

a.) Memoryless: Yes, Time Invariant: Yes, Linear: Yes, Casual: No, Stable: Yes

b.) Memoryless: No, Time Invariant: No, Linear: No, Casual: No, Stable: Yes

c.) Memoryless: No, Time Invariant: No, Linear: No, Casual: Yes, Stable: Yes

d.) Memoryless: Yes, Time Invariant: No, Linear: No, Casual: No, Stable: Yes

e.) Memoryless: Yes, Time Invariant: No, Linear: No, Casual: No, Stable: Yes

f.) Memoryless: No, Time Invariant: Yes, Linear: Yes, Casual: No, Stable: Yes

g.) Memoryless: Yes, Time Invariant: Yes, Linear: No, Casual: Yes, Stable: Yes

A memoryless, time invariant, linear, casual, and stable system is an idealized system in which the output is directly proportional to the input and the output at any given time is independent of the outputs at any other time.

The system is stable in the sense that the output does not grow indefinitely as the input increases, and it is casual in the sense that the output at any given time is only affected by the inputs at previous times.

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Answer:

$ 74.80

Step-by-step explanation:

The subtotal cost of the meal was $91.22  including tax.

The 18% tip is added for six or more.

The tip added should reduce the meal subtotal by 18 %

Reduce $91.22 by 18%  to get ;

82/100 * 91.22 = $ 74.80

Answer:

t ≥ 7.4.

Step-by-step explanation:

To solve the equation 2(t - 6.7) ≥ 1.4 for t, we can follow these steps:

  2t - 2(6.7) ≥ 1.4

  2t - 13.4 ≥ 1.4

  2t - 13.4 + 13.4 ≥ 1.4 + 13.4

  2t ≥ 14.8

  (2t)/2 ≥ 14.8/2

  t ≥ 7.4

The required difference between ratios, rates, and unit rates has been shown.

The ratio can be defined as the proportion of the fraction of one quantity towards others. e.g.- water in milk.

Here,
Ratios, rates, and unit rates are the fraction value of one with respect to the others. the basic difference between the ratios, rates, and unit rates is given as ratios are the fraction between either dependent or non-dependent values, while rates are changes of value with respect to other values. unit rate is a change of value per unit change in the respective value.

Thus, the required difference between ratios, rates, and unit rates has been shown.

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Answer:

Step-by-step explanation:

For the first wrestler, we can see that from month \(3\) to \(4.5\), the wrestler's weight gets to be from \(95\) kilograms to \(101.75\) kilograms. This means that the diet made the wrestler gain \(\red{6.75}\) kilograms of weight every \(\red{1.5}\) month. We can also see that it's consistent with from month \(4.5\) to \(6\).

For the second wrestler, we can see on the graph that the diet makes the wrestler gain weight in linear fashion. This means that their weight gain is consistent. Let's find how much the wrestler is gaining weight for every \(1.5\) months. At the moment when the wrestler started to diet, their weight is \(\red{75}\) kilograms. At month \(1.5\), we can see that the wrestler's weight is \(82.5\). Now we can see that the wrestler gains \(\blue{7.5}\) kilograms of weight every \(\blue{1.5}\) months.

The first wrestler gains \(\red{6.75}\) kilograms of weight every \(\red{1.5}\) month while the second wrestler gains \(\blue{7.5}\) kilograms of weight every \(1.5\) months. The second wrestler gains weight more quickly.

The second wrestler weighed \(\blue{75}\) at the beginning of the diet. We are not provided of weight of the first wrestler when they started dieting but we do know that they gain \(\red{6.75}\) kilograms of weight every \(1.5\) months. The first wrestler must weigh twice of \(\red{6.75}\) kilograms of \(95\) kilograms because month \(3\) is twice \(1.5\) months.

\(\red{90 -6.75 \cdot 2} \\ \red{90 -13.5} \\ \red{76.5}\)

The first wrestler weighed more at the beginning of the diet.

Answer:

The first wrestler weighed more at the beginning of the diet.

The second wrestler gains weight more quickly.

Step-by-step explanation:

For the first wrestler, we can see that from month  to , the wrestler's weight gets to be from  kilograms to  kilograms. This means that the diet made the wrestler gain  kilograms of weight every  month. We can also see that it's consistent with from month  to .

For the second wrestler, we can see on the graph that the diet makes the wrestler gain weight in linear fashion. This means that their weight gain is consistent. Let's find how much the wrestler is gaining weight for every  months. At the moment when the wrestler started to diet, their weight is  kilograms. At month , we can see that the wrestler's weight is . Now we can see that the wrestler gains  kilograms of weight every  months.

The first wrestler gains  kilograms of weight every  month while the second wrestler gains  kilograms of weight every  months. The second wrestler gains weight more quickly.

The second wrestler weighed  at the beginning of the diet. We are not provided of weight of the first wrestler when they started dieting but we do know that they gain  kilograms of weight every  months. The first wrestler must weigh twice of  kilograms of  kilograms because month  is twice  months.

The first wrestler weighed more at the beginning of the diet.

Answer:

I exactly don't know the answer

Answer:

-2x + 6y = 3

4x + 3y = 9

Answer: 2

Explanation:

-2(2)x + 6y = 3

4x + 3y = 9

-8x + 10y = 16

-4x - 5y = 13

Answer:  -1/2

Explanation:

-8(-1/2)x + 10y = 16

-4x - 5y = 13

3x - 8y = 1

6x + 5y = 12

Answer: -2

Explanation:

3(-2)x - 8y = 1

6x + 5y = 12

10x - 4y = -8

-5x + 6y + = 10

Answer: 1/2

Explanation:

10(1/2)x - 4y = -8

-5x + 6y + = 10

Answer:

Step-by-step explanation:

Step-by-step explanation:

2C – 3B = 2(1+5n-6n²)-3(n+4n²)

= 2+10n-12n²-3n-12n²

= 2 +7n -24n²

The expression (2C-3B) equals to (-24x²+7x+2)

Expressions in maths are mathematical statements that have a minimum of two terms containing numbers or variables, or both, connected by an operator in between.

Given are two expression, C = 1+5n-6n² and B = n+4n²

2C = 2+10n-12n²

3B = 3n+12n²

2C-3B = 2+10n-12n² - 3n-12n²

= -24n²+7n+2

Hence, The expression (2C-3B) equals to (-24x²+7x+2)

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Answer:

Expressions A, C, D are equivalent

Step-by-step explanation:

Equivalent expressions:

Two expressions are equivalent if they give the same result. So

Option A:

3(2 + 4x)  =3*2 + 3*4x = 6 + 12x

So equivalent

Option B:

3(2 + 6x) + 2x = 3*2 + 3*6x + 2x = 6 + 18x + 2x = 6x + 20. So not equivalent

Option C:

5(1+2x) + 1 + 2x = 5*1 + 5*2x + 1 + 2x = 5 + 10x + 1 + 2x = 6 + 12x.

Equal, so equivalent

Option D:

7*(1+2x) - 2x - 1 = 7*1 + 7*2x - 2x - 1 = 7 + 14x - 2x - 1 = 6 + 12x

Equal, so equivalent.

Option E:

7*(1+2x) + 2x - 1 = 7*1 + 7*2x - 2x - 1 = 7 + 14x + 2x - 1 = 6 + 16x

Different, so not equivalent.

Answer:

  C:  y = -(x +3)² -1

Step-by-step explanation:

You want the vertex-form equation of the parabola with vertex (-3, -1) and opening downward.

For vertex (h, k), the vertex form equation of a parabola is ...

  y = a(x -h)² +k

Given that (h, k) = (-3, -1), the equation will have the form ...

  y = a(x -(-3))² + (-1)

  y = a(x +3)² -1 . . . . . . . . . . matches choice C

The value of 'a' will be negative when the parabola opens downward. Here, its value is -1.

  y = -(x +3)² -1

__

Additional comment

Once you identify the left-shift of 3 units as resulting in an equation with (x +3)² as a component, you can make the appropriate answer choice without considering anything else. Of course, the fact that the curve opens downward immediately eliminates choices A and B.

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