strontium salts are also used in highway safety flares. when an electron from strontium relaxes from its prevalent excited state, a photon with a wavelength of 660 nm is emitted. approximately how much energy is released upon emission?

Answer:

0.241 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

HBr + NaOH —> NaBr + H₂O

From the balanced equation above,

The mole ratio of acid, HBr (nₐ) = 1

The mole ratio of base, NaOH (n₆) = 1

Finally, we shall determine the concentration of the NaOH solution. This can be obtained as follow:

Volume of base, NaOH (V₆) = 20 mL

Volume of acid, HBr (Vₐ) = 24.1 mL

Concentration of acid, HBr (Cₐ) = 0.2 M

Concentration of base, NaOH (C₆) =?

CₐVₐ / C₆V₆ = nₐ/n₆

0.2 × 24.1 / C₆ × 20 = 1/1

4.82 / C₆ × 20 = 1

Cross multiply

C₆ × 20 = 4.82

Divide both side by 20

C₆ = 4.82 / 20

C₆ = 0.241 M

Therefore, the concentration of the NaOH solution is 0.241 M

(a) Carbon monoxide (CO) emissions from internal combustion engines increase in colder climates. Thus, the environmental damage from CO emissions is worse in the winter months than in the summer months.

Nonetheless, air quality control authorities use a standard for CO that is uniform throughout the year with no allowance for seasonal effects. Suppose you are in charge of setting a policy for CO emissions. The marginal damages cost (MD) in the winter is 3E and in the summer is 2E. The MAC of CO emissions in both winter and summer is 60-E. To ensure an allocatively efficient outcome across the two seasons, the marginal damage cost (MD) and the marginal abatement cost (MAC) should be equal. At the point where MD=MAC, social welfare will be maximized. Therefore, equating marginal damage cost (MD) and marginal abatement cost (MAC) in both winter and summer gives: 3E = 60 - E2E = 60 - EE = 20. Thus, the government should set a uniform CO emission standard for winter and summer seasons at 20 to ensure an allocatively efficient outcome across the two seasons.

(b) If the government sets a policy that says emission level for winter and summer will be equiproportion, i.e., E = 15, determine the change in net benefit or welfare loss associated with this policy. MD of CO emission in winter = 3E = 3(15) = 45MD of CO emission in summer = 2E = 2(15) = 30 MAC of CO emission in both winter and summer = 60 - E = 60 - 15 = 45. For a policy that says emission level for winter and summer will be equiproportion, the level of CO emission will be E = 15. The corresponding net benefit can be found as: NB = MB - MC = (MD - MAC) * E = (45 - 45) * 15 = 0. Therefore, the net benefit or welfare loss associated with this policy is zero.

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Answer:

The bottom number is the proton number, it is simply the number of protons in an atom of the element.

Explanation:

Answer:

There are three ways to make solids dissolve faster: Break the solute into smaller pieces. Stir the mixture. * Heat the mixture.

Explanation:

Substances can dissolve in water three ways—by dissociation, dispersion, and ionization.

Answer:

he is right, top right

Explanation:

Answer:

24g of NaOH are required

Explanation:

Molarity, M, is an unit of concentration widely used in chemistry defined as the ratio between moles of solute (In this case, NaOH), and volume of solution in liters.

We can find the moles of NaOH and its mass with the volume and desired concentration as follows:

Moles NaOH:

400.0mL = 0.400L * (1.50mol / L) = 0.600 moles NaOH

Mass NaOH -Molar mass: 40.0g/mol-:

0.600 moles * (40.0g / mol) =

Answer:

a)loudness has been changed

b) pitch has been changed

Explanation:

J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. ... Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus.

there u go :>

The experiment that proved atoms  positive, negative, and neutral particles is the J.J. Thomson's experiments with cathode ray tubes, which showed that all atoms contain  negatively charged s electrons, on the other hand  Rutherford's gold foil experiment showed the atom  is present in mostly empty space with a tiny, dense, positively-charged nucleus.

J J Thomson's experiment was used to determine the existence of corpuscles or electrons which says the cathode rays are charges of negative electricity which is carried by particles of matter.

He studied about electric discharge with high vacuum cathode ray tube and there were many other scientists who also have done the same experiment on the similar field.

Cathode ray is made up of of negatively-charged particles and these particles must exist as part of the atom and the mass of the particle is only ∼ 20001​ start fraction, 1, divided by, 2000, end fraction the mass of a hydrogen atom.

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Answer:

After a charge touches a conductor, electrons are transferred from a charged object to the conductor

Answer: The average valence electron energy (AVEE) of this element =

1014.2 KJ/ mol  or  1.0142mJ/mol.

Explanation:

The average valence electron energy =  (number of electrons in s subshell  x  Ionization energy of that subshell) + (number of electrons in p subshell  x  Ionization energy of that subshell) / total number of electrons in both subshells of the valence shells.

The 5A elements are non-metals like Nitrogen and Phosphorus with the metallic character increasing as you go down the group, So a new 5A element will have characteristics of its group with 5 valence electron in its outermost shell represented as ns2 np3

Therefore  the average valence electron energy (AVEE) of this element will be calculated as

The average valence electron energy = (2 x 1370  kJ/mol + 3 x 777 kJ/mol.) / 5

2740+2331/ 5 =5071/5

=1014.2 KJ/ mol  or  1.0142mJ/mol.

False. The chemical activity known as photosynthesis does not support the complete food chain on Earth. Plants and certain microorganisms employ a process called photosynthesis to transform solar energy into chemical energy, which is subsequently used to create sugars, the plant's primary source of nutrition.

Since this process creates oxygen, which is necessary for the majority of life forms, it is significant for the environment's health. However, other mechanisms that certain microorganisms and some animals utilise, such chemosynthesis and carnivory, also contribute to maintaining the food chain.

Additionally, photosynthesis is not the only process that transfers energy via the food chain. Sunlight provides energy to plants via the mechanisms through the microorganisms.

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A single-nucleotide polymorphism (SNP) is a change in the genome's DNA sequence at a particular site. SNPs can have many alleles, or alternate gene types .

Single-nucleotide polymorphisms (SNPs), which differ in one of the DNA's building blocks from person to person, are differences in the DNA sequence. The majority of genetic variations, known as SNPs, are present throughout the human genome. They are essential to genetic research because they may be used to investigate the relationship between complicated features like disease susceptibility and genetic variation. Additionally, populations' ancestry and evolutionary history can be determined using SNPs. SNPs can appear in both protein-coding and non-coding sections of the genome. SNPs in protein-coding regions have the potential to alter the protein's structure and consequently, its function. This might have repercussions later on.

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What is a single-nucleotide polymorphism (SNP) and what are its different alleles?

The reaction is product-favored as written because the cell potential (E) is positive at +0.60 V. Zinc undergoes oxidation, and the reaction is not at equilibrium.

For the reaction Zn (s) + SnBr₂ (aq) → ZnBr₂ (aq) + Sn (s) with a cell potential (E) of +0.60 V, a positive E value indicates that the reaction is spontaneous and product-favored. However, it's important to note that zinc is undergoing oxidation, not reduction, as it loses electrons when it transforms from Zn (s) to ZnBr₂ (aq).

On the other hand, tin (Sn) is undergoing reduction as it gains electrons, converting from SnBr₂ (aq) to Sn (s). As the reaction is spontaneous and not at equilibrium, it will continue to proceed until the reactants are used up or the conditions change.

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A. Ammonia is the limiting reactant.

B. Theoretical yield of urea is 215.3 kg.

C. Percent yield for the reaction is 86.0%

D. The mass of the excess carbon dioxide left is approximately 54.1 kg.

a) To identify the limiting reactant, we should compare the amount of products formed from each reactant. The chemical equation for the formation of urea \((NH_2CONH_2)\) by combining ammonia \((NH_3)\) and carbon dioxide \((CO_2)\) is as follows:

\(2 NH_3 + CO_2 - > NH_2CONH_2 + H_2O\)

The stoichiometry of the balanced equation indicates that the ratio of ammonia to urea is 2:1.

We can find the number of moles for each reactant using the following masses:

Moles of ammonia = 122.0 kg / 17.03 g/mol = 7.17 mol

Moles of carbon dioxide = 211.4 kg / 44.01 g/mol = 4.80 mol

It takes 14.34 moles of ammonia to react completely with the available carbon dioxide because the ratio of ammonia to urea is 2:1. But the amount of ammonia we have is less than we need - only 7.17 mol. As a result, ammonia is the limiting reactant.

b. Based on the limiting reactant, it is possible to calculate the theoretical yield of urea. We can use the moles of ammonia, which is the limiting reactant, to calculate the moles of urea:

Moles of urea = 7.17 mol / 2 = 3.58 mol

We can determine the theoretical yield of urea using the molar mass of urea (60.06 g/mol) as a starting point:

Theoretical yield of urea = 3.58 mol * 60.06 g/mol = 215.3 kg

C. The actual yield (185.1 kg) is calculated by dividing it by the theoretical yield (215.3 kg), then multiplying the result by 100%.

Percent yield = (185.1 kg / 215.3 kg) * 100% = 86.0%

D. We can calculate the amount of non-limiting reactant that has not reacted yet to determine the excess reactant. Since ammonia is the limiting reactant, we must determine how much excess carbon dioxide there is:

Moles of excess carbon dioxide = Moles of carbon dioxide initially - Moles of carbon dioxide used

= 4.80 mol - (7.17 mol / 2) = 1.23 mol

We can determine the mass of excess carbon dioxide using the molar mass of carbon dioxide (44.01 g/mol):

Excess carbon dioxide = 1.23 mol * 44.01 g/mol = 54.1 kg

Therefore, the mass of the excess carbon dioxide left is approximately 54.1 kg.

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Answer:

Explanation:

25.2 mol

The sample of nitrogen (\(N_{2}\)) occupying 0.37 grams at a temperature of 300 K and a pressure of 154.2 kPa occupies approximately 21.6 mL of volume.

We first convert the mass of nitrogen to moles using the molar mass of nitrogen, which is approximately 28.0134 g/mol.

\(\frac{0.37 g N_{2}}{ 28.0134 g/mol} = 0.0132 mol N_{2}\)

Applying the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature. The gas constant R is \(0.0821 L\cdot atm/(mol\cdot K)\).

1 atm = 101.325 kPa

So, 152 kPa is approximately equal to 1.5 atm.

\(V = \frac{(nRT)}{P}\)

\(= \frac{(0.0132 mol\cdot 0.0821 L\cdot atm/(mol\cdot K)\cdot(300 K)}{1.5 atm}\)

= 0.216 L

We convert this volume into mL.

So, 0.216 L = 21.6 mL.

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Answer:

The answer is diagram D.

When the solutions dissolve in an aqueous solution they dissociate to form ions

That's

AgNO3 → Ag+ NO3-

NaCl → Na+ Cl-

Upon mixing Ag+ pairs with Cl- and Na+ pairs with NO3 -

That's we have

AgCl and NaNO3

I hope this helps you.

No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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Answer:

the ability to do work.

Explanation:

Iron(III) chloride is used to assess the purity of aspirin because it reacts with unreacted salicylic acid present in the synthesized sample.

The reaction requires the presence of phenolic OH groups, which are present in salicylic acid but not in aspirin. Therefore, a color change upon adding iron(III) chloride indicates the presence of salicylic acid, suggesting impure aspirin.

Summary: Iron(III) chloride helps determine aspirin purity by reacting with salicylic acid's phenolic OH groups, showing whether any unreacted salicylic acid remains in the synthesized sample.

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Three uses of metals are

Metal is any of a class of substances characterized by high electrical and thermal conductivity as well as by malleability, ductility, and high reflectivity of light.

Three uses of metals​ are as follows:

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The oxidation number of Na in the compound Na2CO3 is +1.

To determine the oxidation number of Na in Na2CO3, we need to consider the known oxidation numbers of other elements and the overall charge of the compound.

1. The compound Na2CO3 contains two Na atoms and one C atom, along with three O atoms.

2. Oxygen (O) typically has an oxidation number of -2, unless it is in a peroxide where it is -1.

3. Carbon (C) is more electronegative than hydrogen (H) but less electronegative than oxygen (O), so it usually has an oxidation number of +4 in compounds.

4. The compound Na2CO3 has a neutral charge, which means the sum of the oxidation numbers of all the elements must be zero.

5. Let's assign the oxidation number of Na as x. Since there are two Na atoms, the total oxidation number contribution from Na is 2x.

6. The oxidation number of C in CO3 is +4, and the oxidation number of O is -2. Since there are three O atoms in CO3, the total oxidation number contribution from O is 3*(-2) = -6.

7. Setting up the equation: 2x + 4 + (-6) = 0.

8. Solving the equation: 2x - 2 = 0, 2x = 2, x = 1.

Therefore, the oxidation number of Na in Na2CO3 is +1.

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Number of (NH4)2SO4 molecules = 2.16 × 10^25 molecules / 2 = 1.08 × 10^25 (NH4)2SO4 molecules. There are approximately 1.08 × 10^25 molecules of ammonium sulfate in 35.8 moles of (NH4)2SO4.

To determine the number of molecules in 35.8 moles of ammonium sulfate ((NH4)2SO4), we need to use Avogadro's number, which states that there are 6.022 × 10^23 particles (atoms, molecules, or ions) in one mole of any substance.

The molecular formula of ammonium sulfate indicates that there are two ammonium ions (NH4+) and one sulfate ion (SO4^2-) in each molecule.

To calculate the number of molecules in 35.8 moles of (NH4)2SO4, we can follow these steps:

Determine the number of moles of (NH4)2SO4 by multiplying the given value by Avogadro's number:

Number of moles = 35.8 moles × (6.022 × 10^23 molecules/mole) = 2.16 × 10^25 molecules

Since each molecule of (NH4)2SO4 contains one ammonium ion and one sulfate ion, the number of molecules can be divided by two to obtain the number of (NH4)2SO4 molecules:

Number of (NH4)2SO4 molecules = 2.16 × 10^25 molecules / 2 = 1.08 × 10^25 (NH4)2SO4 molecules

Therefore, there are approximately 1.08 × 10^25 molecules of ammonium sulfate in 35.8 moles of (NH4)2SO4.

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Answer:

A=4

B= 4+2 =6

C=Carbon

D=10

E=22

F=Argon

Answer:

A = 8

B = 8

C = O

D = 26

E = 30

F = Fe

Explanation: I got it wrong from both of the answers on the other answer. These were the correct ones.

Answer:

6.14x10^24

Explanation:

convert the given 47.0g to mols then to molecules.

\(\frac{47.0g}{} x\frac{1mol}{46.07g}x\frac{6.022x10^{23} }{1 mol}\)

46.07 is the molar mass of ethanol

6.022x10^23 is avogadros number

Answer:

salicylate ion

Explanation:

The spectroscopic analysis of aspirin will involve the complexing of iron(III) to the deprotonated form of salicylic acid (salicylate ion) to give a purple solution.

The aspirin, which is of the carboxylic acid group, is deprotonated by salicylate ions.

Deprotonation is the removal of a proton from an acid, in an acid-base reaction.

When a proton is added to acid, the process is called protonation.

This process happens in Brønsted Lowry acids.

The aspirin, which is of the carboxylic acid group, is deprotonated by salicylate ions.

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Answer:

is B

Explanation:

it isnt C or D so let's look at A and B so the answer is more likely going to be B because A your muscles cant change shape and C your muscles are protien and D humans and animals do not have cell walls that only have cell membrane

Answer:

No B. is incorrect, the REAL answer is actually C.

Explanation:

The main function of muscles is to move body parts by contracting, which requires a lot of energy. so C. is the only answer that concludes with this. The cell structure that produces energy is the mitochondrion.

Therefore, the best prediction is that muscle cells contain a large number of mitochondria in order to provide more energy.

So that means B. would be an assumable answer.

I hope this helps!

The mass of dinitrogen tetroxide the number of Nitrogen atoms are 46 x 10^9 gram

Given:

number of nitrogen atoms = 1 x 10^12 atoms

To Find:

mass of dinitrogen tetroxide

Solution:

From the molecular formula of dinitrogen tetraoxide;

molar mass of dinitrogen tetraoxide = 92 g/mol

92 g of dinitrogen tetraoxide contains 2 atoms of nitrogen

x g of dinitrogen tetraoxide will contain 1 * 10^12 atoms of nitrogen

x = 92*1* 10^ 9/2

x = 46 x 10^9 gram

Hence, the number of Nitrogen atoms are

Hence, the number of Nitrogen atoms are 46 x 10^9 gram

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Answer:

The mass of dinitrogen tetroxide the quantity of Nitrogen particles are 46 x 10^9 gram

Number of nitrogen atoms = 1 x 10^12 atoms

Explanation:

From the atomic Formula of dinitrogen tetraoxide;

molar mass of dinitrogen tetraoxide = 92 g/mol

92 g of dinitrogen tetraoxide contains 2 molecules of nitrogen

x g of dinitrogen tetraoxide will contain 1 * 10^12 molecules of nitrogen

x = 92*1* 10^ 9/2

x = 46 x 10^9 gram

the quantity of Nitrogen molecules are 46 x 10^9 gram