stavrinidou, e. et al. direct measurement of ion mobility in a conducting polymer. adv. mater. 25, 4488–4493 (2013).

Answer: C

Explanation:

Increasing the temperature increases the rate of dissolving.

The given reaction is the calcium carbide reaction of calcium hydroxide with water to produce acetylene.

The balanced equation is CaC2+2H2OCa(OH)2+C2H2.

Molar mass of acetylene, C2H2 = 2x12+2x1 = 26 g/mol

we get 64 g of CaC2 becomes 26 g of C2H2. 5.0g CaC2..

Molecular weight of Ca(OH)2=1(atomic weight of Ca)+2(atomic weight of O)+2(atomic weight of H)=40+2(16)+2(1)=40+32+2=74.

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Answer:

aswer is A

Explanation:

because the CL,K,AR is correct since it is order right

a) The Gibbs free energy change for the melting of 1.00 mol of ammonia at 170 K is -3.49 kJ.

b) The Gibbs free energy change for the conversion of 3.60 mol of solid ammonia to liquid ammonia at 170 K is -12.60 kJ.

c) Ammonia will melt spontaneously at 170 K since the Gibbs free energy change is negative, indicating a favorable process.

d) Solid and liquid ammonia will be in equilibrium at a temperature of 170 K and a pressure of 1 atm.

a) The Gibbs free energy change (ΔG) can be calculated using the equation ΔG = ΔH - TΔS, where ΔH is the enthalpy of fusion, ΔS is the entropy of fusion, and T is the temperature in Kelvin.

Plugging in the values, we have ΔG = (5.65 kJ/mol) - (170 K)(28.9 J/(K·mol)) = -3.49 kJ.

b) To calculate the Gibbs free energy change for 3.60 mol of solid ammonia, we multiply the value from part (a) by the number of moles: ΔG = (-3.49 kJ/mol) * (3.60 mol) = -12.60 kJ.

c) Since the Gibbs free energy change for melting ammonia is negative, the process is thermodynamically favorable and ammonia will melt spontaneously at 170 K.

d) The equilibrium temperature can be determined by setting the Gibbs free energy change to zero: ΔG = 0 = ΔH - TΔS. Solving for T, we find T = ΔH/ΔS = (5.65 kJ/mol)/(28.9 J/(K·mol)) = 195.5 K. Therefore, solid and liquid ammonia are in equilibrium at a temperature of 195.5 K, which is approximately 170 K.

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The speed of a wave can be calculated using this formula:

v = f x λ

Where:

v is the wave speed in metres per second, m/s

f is the frequency in hertz, Hz

λ (lambda) is the wavelength in metres, m

Calculation:

Given:

f = 20 Hz

λ = 100m

Using the equation:

v = f x λ

v = 20 x 100

v = 2000 m/s

Therfore, the speed of the wave is 2000 m/s

A sound wave has a wavelength of 100 m and a frequency of 20 Hz. The wave's speed is 2× 10^3 m/s.

assuming frequency = 20 Hz and wavelength = 100 m

utilized concept: v= = 20×100 = 2×10³ m/s

The frequency in physics is the quantity of waves passing a fixed location in a unit of time. It also indicates how many cycles or vibrations a body in periodic motion experiences in a given unit of time.

A sort of energy created by vibrations is sound. The molecules of the air surrounding an item vibrate as a result.. These molecules vibrate because they collide with nearby molecules, which also vibrate as a result.

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The reaction is 2NOCl (g) ⇌2NO (g) + Cl₂ (g). The expression for the equilibrium constant will be 4.337 × 10⁻⁴ M

The forward reaction velocity constant and the backward reaction velocity constant are multiplied to produce the equilibrium constant. According to some sources, it is "the ratio of product to the molar concentration of product to product of the molar concentration of reactants." The difference between the equilibrium product and reactant concentrations is the equilibrium constant of a reaction. The concentration terms are elevated to suitable powers that are equivalent to stoichiometric coefficients.

Given, the reaction is 2NOCl (g) ⇌2NO (g) + Cl₂ (g).

K = \(\frac{[NOCl^2]}{[NO]^2 [Cl2]}\)

Δ \(n_{g}\) = (2+1) -2 = 1

Temperature T, 500 K

\(K_{p}\) value = 1.8 × 10⁻²  bar⁻¹

Now

\(K_{p} = K_{c} (RT)^{-ng}\)

= 1.8 × 10⁻² × (0.083 × 500)⁻¹M

= 4.337 × 10⁻⁴ M

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Answer: C. Gas

Explanation:

A gas is a state of matter that has no definite shape or volume, and its particles are usually far apart and moving quickly in random directions.

The scientist who proposed a model of the atom in which the individual atoms were thought of as tiny solids like balls or marbles is John Dalton.

Dalton's atomic theory, developed in the early 19th century, was based on the concept that atoms are indivisible and indestructible particles. He suggested that atoms combine to form compounds in fixed ratios and that chemical reactions involve the rearrangement of atoms.

Dalton's model of the atom as tiny solid spheres laid the foundation for our understanding of atomic structure. It was later refined by other scientists, such as J.J. Thomson and Ernest Rutherford, who discovered the existence of subatomic particles and the presence of a nucleus within the atom. Nonetheless, Dalton's model was significant in shaping our understanding of the atom as a fundamental building block of matter.

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Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

From the question

mass of object = 20 g

volume = 100 mL

Substitute the values into the above formula and solve

That's

\(Density = \frac{20}{100} \\ = \frac{2}{10} \\ = \frac{1}{5} \)

We have the final answer as

Hope this helps you

Answer: true

Explanation: same as the melting point of a gram or a tonne

The latent heat of vaporization of boiling water is 540 cal/gm. Option b is the correct answer.

It is the amount of heat needed to convert 1 gram of water from liquid to vapor state at atmospheric pressure at a constant temperature. The latent heat of vaporization for water is relatively high compared to other liquids because of the strong hydrogen bonding between water molecules. This means that water requires a lot of energy to break these bonds and change from a liquid to a gaseous state. The latent heat of vaporization is also responsible for the cooling effect of evaporation. When sweat evaporates from our skin, it absorbs heat from our body, which helps to cool us down. In conclusion, the latent heat of vaporization of boiling water is 540 cal/gm, which represents the amount of heat required to convert 1 gram of water from liquid to vapor state at atmospheric pressure at a constant temperature.

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Combustion reactions involve the oxidation of a fuel by oxygen gas to produce carbon dioxide and water.

2 C6H14(l) + 19 O2(g) -> 12 CO2(g) + 14 H2O(g).

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The number of spoonfuls required to cover a specific area could then be counted to estimate the total number of sand grains.

This method would likely lead to an estimate rather than an exact count, as the number of grains in each spoonful may vary. Another idea is to use a smaller measuring spoon, such as a teaspoon or a tablespoon, and count the number of spoonful's required to fill a container of known volume.

By dividing the total volume of the container by the volume of one spoonful, an estimate of the total number of sand grains could be obtained. This method could also lead to an estimate due to variations in the size of the grains and the accuracy of the measuring spoon.

To improve these ideas, a more precise measuring device, such as a scale, could be used to measure the exact weight of the sand. This would provide a more accurate count of the number of sand grains, rather than relying on estimates based on volume or area.

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the temperature and total enthalpy after the heating is  can be found by using the conservation of energy principle and the first law of thermodynamics.

To determine the temperature and total enthalpy in a container filled with 9.9 kg of R-134a at 300 kPa and a volume of 14 L, and then to find the temperature and total enthalpy after the pressure has been increased to 600 kPa, we need to use the refrigerant tables to look up the thermodynamic properties of R-134a.

The first step is to find the specific volume, internal energy, and enthalpy of R-134a at the initial state (300 kPa and a temperature to be determined).

Next, we can use the ideal gas law to find the temperature of R-134a at the initial state:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of refrigerant, R is the gas constant, and T is the temperature.

The number of moles can be found using the mass and molecular weight of R-134a:

n = m/M

where m is the mass of R-134a and M is its molecular weight.

Using the refrigerant tables, we can find the specific volume, internal energy, and enthalpy of R-134a at the final state (600 kPa and a temperature to be determined).

With this information, we can calculate the change in internal energy and enthalpy during the process of heating the container.

Finally, the final temperature and total enthalpy can be found by using the conservation of energy principle and the first law of thermodynamics.

This is a complex calculation that requires a good understanding of thermodynamics and the use of refrigerant tables. If you need more detailed information or have specific data, please provide it and I will do my best to assist you.

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In this investigation, the student is missing the step of analyzing the data and drawing a conclusion.

Although the student has conducted an experiment and collected data, it is crucial to analyze the data and draw meaningful conclusions based on the results.

After conducting the experiment and collecting data on turtle nests at different parts of the local beach, the student should carefully examine the collected information.

This involves organizing and interpreting the data to identify any patterns, trends, or relationships. The student should compare the number of turtle nests in different parts of the beach, evaluate the statistical significance of the findings, and consider any potential confounding factors or limitations of the study.

Based on the analysis of the data, the student can then draw a conclusion about which part of the beach contains the most turtle nests during nesting season. This conclusion should be supported by the data and any relevant scientific knowledge or theories.

By including the step of analyzing data and drawing a conclusion, the student will have completed all the essential components of the scientific method, which includes background research, hypothesis construction, experiment testing, data analysis, and conclusion drawing.

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Jean Piaget's contributions to the study of child development include the development of the cognitive developmental theory, identification of the four stages of cognitive development, and the impact of his work on developmental psychology and education.

Jean Piaget made significant contributions to the study of child development through his pioneering work on the cognitive development theory. He observed children's behaviors and interactions with their environment to understand how their cognitive abilities develop. Piaget's cognitive developmental theory has had a profound impact on developmental psychology, education, and sociology.

Piaget's contributions include the development of the cognitive developmental theory, which explains how children acquire cognitive abilities. He observed that children are naturally curious and inclined to experiment, and he proposed that cognitive development occurs through distinct stages as children grow and learn.

Piaget identified four main stages of cognitive development: the sensorimotor stage, preoperational stage, concrete operational stage, and formal operational stage. According to his theory, children progress through these stages in a sequential manner, with each stage building upon the achievements of the previous one.

His cognitive developmental theory has provided a solid foundation for the field of developmental psychology, enabling researchers to better understand how children develop cognitively over time. It has also influenced educational practices by informing teachers about the cognitive abilities and limitations of children at different developmental stages.

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Answer:

Below

Explanation:

1 meter = 100 cm

Volume =   100 cm * 100 cm * 2 cm = 20 000 cm^3  = 20 000 ml

mass = volume * density

         = 20 000 ml  *  1.42 g/ ml = 28400 g   ( or 28.4 kg)

The false statement is that adding more H2(g) rises the equilibrium constant.

Q can be utilized to predict which way a response will shift to achieve equilibrium. If K > Q, the reaction will continue, converting reagents into products. If K Q, the reaction will go in the opposite direction, converting products back into reactants. If Q = K, the system has already reached equilibrium.

Here are some examples of equilibrium: A book resting on a table. A car moving at a constant speed. A chemical reaction in which the prices of forward and reverse reactions are the same.

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The complete question is-

Consider: H2(g)+I2(s)=2HI(g)

Which of the following statements about the equilibrium is false?

A. If the system is heated, the right side is favored

B. This is a heterogeneous equilibrium

C. If the pressure on the system is increased by changing the volume, the left side is favored

D. Adding more H2(g) increases the equilibrium constant

E. Removing HI as it forms forces the equilibrium to the right

The duck is experiencing a net force of 5 newtons in the forward direction (20N forward force - 15N resistive force). This net force causes the duck to accelerate in the forward direction, increasing its velocity. However, the magnitude of this acceleration depends on the mass of the duck and the resulting acceleration can be calculated using Newton's Second Law (F=ma).

If the mass of the duck is known, the resulting acceleration can be calculated and used to predict how quickly the duck will increase its velocity.
The diagram depicts a duck swimming against the flow of a stream. The duck exerts force on the water, resulting in the water pushing the duck forward with 20 newtons of force. Simultaneously, the water's resistive force acts against the duck with 15 newtons. This scenario demonstrates the interaction of forces, specifically the forward force exerted by the duck and the resistive force exerted by the water. In this case, the net force acting on the duck is 5 newtons in the forward direction (20 newtons forward - 15 newtons resistive).

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Replace E° with the value you measured and calculate the Gibbs free energy change, ΔG°.  To calculate the Gibbs free energy (ΔG°) for the cell you constructed, we'll use the following equation: ΔG° = -nFE°

To calculate δg° for the cell of Cu/C12H22CuO14 and Sn/CuSO4, we first need to use the Nernst equation to find the standard cell potential (E°cell) for this reaction. The Nernst equation relates the cell potential to the Gibbs free energy change (δG) and the standard cell potential: E°cell = -δG°/nF + E°red,  The standard reduction potentials (E°red) for the two half-reactions involved in the cell are: Cu2+ + 2e- -> Cu (s) E°red = +0.34 V, Sn2+ + 2e- -> Sn (s) E°red = -0.14 V
E°cell = -0.83 V
E°cell = -δG°/nF + E°red
-1.17 V = -δG°/(2*96,485 C/mol)
δG° = 2*96,485 C/mol * 1.17 V

δG° = -224.44 kJ/mol
The standard Gibbs free energy change for the cell reaction is -224.44 kJ/mol. This value is negative, which means that the reaction is spontaneous under standard conditions (at 25°C, 1 atm, and with concentrations of 1 M for all species). The units for δG° are kJ/mol.

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The third equation Alcl3/CH3cl  is more favorable, starting with benzene, which of the sequences below will produce p-methylaniline as the major product of the reaction.

What is benzene?

Phenyl hydride, anulene, and mineral naphtha. CAS number 71-43-2 for the chemical reference. Chemicals used in industry frequently include benzoene. In gasoline and crude oil, benzene plays a significant role.

What is Methylaniline ?

N-Methylaniline (NMA) is a derivative of an aniline. It has the organic compound C6H5NH as its chemical formula. A clear, viscous liquid, the substance turns brown when exposed to air. Water cannot dissolve the chemical.

In the option there are two ways by which desired product can be achieved both are natural equally possible.

B,  1. HNu3, H2SO4→2.fe,HCl/3.NaoH→CH3cl/Alcl3

C, 1.CH3cl/Hlcl3→ 2.HNu3/H3So4

Option B is very less favoured because alkylation of aniline will yield side product which  N - alkylated

 Alcl3/CH3cl

Therefore the third equation Alcl3/CH3cl is more favorable, starting with benzene, which of the sequences below will produce p-methylaniline as the major product of the reaction.

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Answer:

Explanation:

Hola! ¿Cómo estás?

Los grupos funcionales se ocupan de la química orgánica y no de la química inorgánica. La química orgánica son los alcanos, alquenos, alquinos y otros. Lo que ha escrito allí como ejemplos no es química orgánica, sino química inorgánica. Eso hace que sea imposible encontrar su grupo funcional, ya que los elementos y compuestos inorgánicos no tienen grupos funcionales.

Yo espero que entiendes

Explanation:

The relative formula mass of a substance, shown in grams, is called one mole of that substance. So one mole of carbon monoxide has a mass of 28 g, and one mole of sodium oxide has a mass of 62 g

Answer:

M(CO)=28 (g/mol)

Explanation:

M= 12+16=28 (g/mol)

Answer:

6 Watts

Explanation:

From the question given above, the following data were obtained:

Current (I) = 0.05 A

Voltage (V) = 120 V

Power (P) =?

Electrical power is defined by the following equation

The power consumption while the TV is in standby can be obtained as follow:

Power (P) = Current (I) × Voltage (V)

P = IV

With the above formula, we can obtain the power consumption while the TV is in standby. This can be obtained as follow:

Current (I) = 0.05 A

Voltage (V) = 120 V

Power (P) =?

P = IV

P = 0.05 × 120

P = 6 Watts

Therefore, the power consumption while the TV is in standby is 6 Watts.

The final temperature of a 10.0 g piece of iron initially at 25°C, if supplied with 9.5 J from a stove, is 27.11°C. The change in temperature of the iron is 2.11°C.

We can use the formula:

Q = mcΔT

where Q is the heat absorbed by the iron, m is the mass of the iron, c is the specific heat capacity of iron, and ΔT is the change in temperature.

In this case, the heat absorbed by the iron is 9.5 J, the mass of the iron is 10.0 g, the specific heat capacity of iron is 0.450 J g^(-1) °C^(-1), and the initial temperature is 25°C. We want to find the final temperature.

Let's rearrange the formula to solve for ΔT:

ΔT = Q / mc

Substituting the given values, we get:

ΔT = (9.5 J) / (10.0 g x 0.450 J g^(-1) °C^(-1))

ΔT = 2.11 °C

Therefore, the change in temperature of the iron is 2.11°C.

To find the final temperature, we add the change in temperature to the initial temperature:

T_final = T_initial + ΔT

T_final = 25°C + 2.11°C

T_final = 27.11°C

Therefore, the final temperature of the iron is 27.11°C.

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