starting with the following equation, fe₂o₃(s) al(s) → fe(l) al₂o₃(s) calculate the moles of fe₂o₃ that will be required to produce 975 grams of fe.

Precipitates are insoluble ionic solid products of a reaction, formed when certain cations and anions combine in an aqueous solution. The determining factors of the formation of a precipitate can vary.

Explanation:

................easy ngl

Answer:

for protons going down it is:

(already given)

6

6

8

8

17

17

for neutrons going down it is:

6

7

8

(already given)

10

18

20

for electrons going down it is:

6

6

8

8

(already given)

17

Explanation:

bascially the number of protons is the bottom number to the left and the number of electrons is the same as the number of protons and the number of neutrons is basically the mass number (the top right one) minus the proton number

hope this helps:)

Answer:

The answer is "10.2".

Explanation:

Please find the complete question in the attachment file.

Calculating  the pH after adding 180.0 mL of \(NaOH \ to\ H_2A\) acid:  

Get balance moles as follows:

\(\to H_2A + OH^{-} \rightleftharpoons HA^{-} +H_2O \\\\I(mol) \ \ \ \ \ 0.02 \ \ \ \ \ 0.036 \ \ \ \ \ 0 \\\\C(mol) \ \ \ \ \ -0.02 \ \ \ \ \ -0.02 \ \ \ \ \ + 0.02 \\\\E (mol) \ \ \ \ \ \approx 0 \ \ \ \ \ \approx 0.016 \ \ \ \ \ 0.02\\\\\)

In the second equilibrium:  

\(\to HA^{-} + OH^{-} \rightleftharpoons A^{2-} + H_2 O \\\\I(mol) \ \ \ \ \ 0.02 \ \ \ \ \ 0.016 \ \ \ \ \ 0 \\\\C(mol) \ \ \ \ \ -0.016 \ \ \ \ \ -0.016 \ \ \ \ \ + 0.016 \\\\E (mol) \ \ \ \ \ 0.004 \ \ \ \ \ \approx 0 \ \ \ \ \ 0.016\\\\\)

\(pH= pK_{a_2} + \log \frac{A^{2-}}{HA^{-}} \\\\\)

      \(= 9.60 + \log \frac{0.016}{0.004} \\\\ = 10.2\)

The difference in boiling points between cis-but-2-ene and trans-but-2-ene is due to the presence of different intermolecular interactions.

In cis-but-2-ene, the molecules have a dipole-dipole interaction, which is stronger as compared to the intermolecular force in trans-but-2-ene and this stronger interaction requires more energy to break, resulting in a higher boiling point of cis-but-2-ene (3.7 °C) as compared to trans-but-2-ene (0.9 °C).

Boiling point is that temperature at which any substance changes from liquid to gaseous phase at specific pressure. It is an important physical property of the substance and that is influenced by factors, like intermolecular forces, molecular size and molecular shape.

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The molarity of a solution made by dissolving 45.6 g glucose, C₆H₁₂O₆, in enough water to make 350.0 ml of solution is 0.722 M.

given that :

volume = 350 mL = 0.350 L

mass of glucose = 45.6 g

molar mass of glucose = 180.15 g/mol

the number of moles of glucose = mass / molar mass

                                                      = 45.6 / 180.15

                                                      = 0.253 mol

the molarity expression is given as follows :

Molarity = moles / volumes in L

              = 0.253 / 0.350

              = 0.722 M                  

Thus, the molarity of the solution to make 350.0 mL of solution is 0.722 M.          

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The amount of diamine silver chloride = 8.87 g

Given

10 g AgCl

1.00 L of 0.100 M NH3

Required

the amount of diamine silver

Reaction

AgCl + 2 NH₃ → [Ag(NH₃)₂]Cl

mol AgCl :

= mass : MW

= 10 g : 143,32 g/mol

= 0.0698

mol NH₃ :

= M x V

= 0.1 x 1

= 0.1

NH₃ as a limiting reactant

mol [Ag(NH₃)₂]Cl based on NH₃ :

= 1/2 x mol NH₃

= 1/2 x 0.1

= 0.05

Mass diamine silver :

= 0.05 x  177.3822 g/mol

= 8.87 g

Answer:

Jeniah's calculation of the molar mass of hydrogen peroxide is correct.

Explanation:

Here is a step-by-step explanation of how she arrived at the answer:

In this case, the molar mass of hydrogen peroxide that Jeniah calculated is 18 grams per mole, which is the correct molar mass for this compound. This means that if Jeniah uses this amount of hydrogen peroxide, she will have the correct amount of the compound needed for her experiment. However, it's important to note that in addition to knowing the amount of a substance needed for an experiment, it's also important to handle the substance safely and follow all necessary precautions to avoid accidents or harm.

Answer:

"2.Orbital." I think

Explanation:

Risk*

Answer:

yes the answer is c

Explanation:

When balancing a chemical reaction, you can only change the coefficients or numbers in front of the chemical formulas. The goal of balancing a chemical equation is to ensure that the number of atoms of each element on both sides of the equation is equal.

Coefficients are used to represent the number of molecules or moles of a substance in a chemical equation. By adjusting these coefficients, you can balance the equation by making the number of atoms of each element the same on both sides.

However, you cannot change the subscripts within a chemical formula when balancing a reaction. The subscripts represent the number of atoms of each element within a molecule or formula unit and are fixed for a given compound. Changing the subscripts would result in a different compound with different properties.

In summary, when balancing a chemical reaction, you can only change the coefficients in front of the chemical formulas to achieve the balance of atoms on both sides of the equation.

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Answer:

tae hahahah joke lang hindi ko alam ehh

0.0463 mol KCl

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

3.45 g KCl

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of KCl - 39.10 + 35.45 = 74.55 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.046278 mol KCl ≈ 0.0463 mol KCl

Answer:

It is less than the density of a solid.

Explanation:

Gases have more volume since the particles are more spread out.

Hydrogen bonds are responsible for base pair formation of in the DNA. Covalent bonds are found in each linear strand  of the DNA double Helix.

The DNA double helix is held together by two types of bonds. Those are covalent and hydrogen. Covalent bonds occur within each linear strand of DNA. It strongly bond the bases, sugars, and phosphate groups  that both within each component and between components. Hydrogen bonds occur between the two strands and involve a base from one strand with a base from the second in complementary pairing in the DNA. The hydrogen bonds are individually weak but quite strong together. A hydrogen bond donor includes the hydrogen atom and the atom to which it is most tightly linked with.

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c i think

Explanation:

if it's not look it up

The labs in this chemistry class use a green approach, which means they prioritize environmentally friendly practices.

In this chemistry class, the term "green approach" refers to a set of practices and principles that prioritize environmental sustainability and minimize negative impacts on the ecosystem. These labs aim to reduce their carbon footprint, conserve resources, and promote responsible waste management. By adopting a green approach, the class strives to align its scientific pursuits with the goal of environmental stewardship.

One of the key aspects of the green approach in these chemistry labs is the conscious selection and utilization of environmentally friendly materials and chemicals. This includes opting for safer alternatives to hazardous substances whenever possible, such as using non-toxic solvents or reagents. Additionally, the labs may encourage the use of renewable resources and promote the recycling or repurposing of materials to reduce waste generation.

Another important component of the green approach is energy conservation. The labs may employ energy-efficient equipment and lighting systems, as well as implement strategies to minimize energy consumption during experiments. For instance, they may encourage students to turn off equipment when not in use and adopt efficient heating or cooling methods.

Furthermore, the labs may focus on water conservation by promoting responsible water usage and minimizing water wastage during experiments. This could involve using water-efficient techniques, such as microscale experiments that require smaller amounts of water, or implementing recycling systems to capture and reuse water when appropriate.

By embracing a green approach, these chemistry labs aim to instill environmental awareness and responsibility in students while demonstrating that scientific progress can coexist with sustainable practices. Through this approach, students gain valuable knowledge and skills that they can apply in their future scientific endeavors, contributing to a more sustainable and eco-friendly society.

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(alt + F4) might be the answer you are looking

Explanation:

I'm not exactly sure how I came up with this answer but it is for sure the answer

Answer:

There is no bar graph attached to this question, however, the question can be answered based on the information given in the question.

The answer is A) average level of happiness

Explanation:

In an experiment, the dependent variable is the variable which is measured by the experimenter. It is the variable that responds to changes made to another variable called independent variable.

In the case of this question, it can be determined, even without the bar graph, that the experiment entails how candy allowance affects a child's happiness. Hence, the candy allowance is changed to influence or cause a response in the child's happiness, which is then measured. Therefore, the AVERAGE LEVEL OF HAPPINESS is the dependent variable.

1. The particles are in constant motion.

2. The average energy of the particles depends on the temperature.

3. Volume of the particles doesn't affect the behavior of the gas.

Answer:

Explanation:

Frozen water is known to have more volume, but less density. When water slowly gets unfrozen, it'd volume decreases and its density increases. Hence, when the water gets unfrozen, it's volume decreases.

To solve this problem, we can use the Nernst equation:
Ecell = E°cell - (RT/nF)ln(Q)
Where E°cell is the standard cell potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons transferred in the cell reaction, F is Faraday's constant, and Q is the reaction quotient.

For the given cell, the overall reaction is:
Mn(s) + 2 Pb2+(aq) -> Mn2+(aq) + 2 Pb(s)
The standard reduction potentials for the Mn/Mn2+ and Pb/Pb2+ half-cells are:
Mn2+(aq) + 2 e- -> Mn(s)      E° = -1.18 V
Pb2+(aq) + 2 e- -> Pb(s)      E° = -0.13 V
Using the reduction potentials, we can calculate the standard cell potential:
E°cell = E°(cathode) - E°(anode) = (-0.13 V) - (-1.18 V) = 1.05 V
Now we can plug in the given values into the Nernst equation:
0.44 V = 1.05 V - (0.0257 V/K)(ln(Q)/2)
Solving for ln(Q):
ln(Q) = -25.16
Taking the exponential of both sides:
Q = e^-25.16 = 3.49 x 10^-11
We can use the reaction quotient to find the concentrations of the ions at equilibrium:
Q = [Mn2+] [Pb2+]^2
Substituting [Mn2+] = 1.5 M and solving for [Pb2+]:
[Pb2+] = sqrt(Q/[Mn2+]) = sqrt((3.49 x 10^-11)/(1.5)) = 5.33 x 10^-6 M
Therefore, [Pb2+] = 5.33 x 10^-6 M (in scientific notation).

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Answer:

Kindly check the explanation section.

Explanation:

PS: Note that enough information are not being provided and we do not know the experiment this question is all about. However, some information are provided below which is going to aid in solving when you get access to the main question.

The determination of the heat transferred from one substance to another is one of the important aspect in science. The method in which this heat is being measured is known as calorimetry and the instrument used in this technique is known as the calorimeter.

When the energy content of a snack is needed to be calculated, there is the need use a type of instrument known as bomb calorimeter.

Most of the calorimeters used by students are not so expensive like the used in the industries. Most of these calorimeters operates at a constant pressure while the Bomb Calorimeter operates at constant volume.

Chromatography is a method of separating out materials from a mixture.

Aim:  To separate the dye present in ink by the process of evaporation.

Materials required:  Beaker, watch glass, water, ink and stove.

Procedure: Take a beaker and fill it to half its volume with water.  Keep 3, glass on the mouth of a beaker.  Put few drops of ink on the watch glass. Heat the beaker and observe the watch glass.  

Observations:   We observe some fumes coming from the watch glass.   Continue heating till you do not observe any further change on the watch glass.   A small residue will be remained on the watch glass.  

Inference:   We know that ink is a mixture of a dye in water.   The residue remained on the watch glass is the dye present in the ink.

Chromatography is a method of separating out materials from a mixture. Ink is a mixture of several dyes and therefore we can separate those colors from one another using chromatography.

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"the number of ions produced by one formula unit of the electrolyte," refers to the van't Hoff factor (i) in an ideal solution of a strong electrolyte. It represents the extent of dissociation of the electrolyte into ions.

In an ideal solution of a strong electrolyte, the van't Hoff factor (i) represents the number of ions that are produced when one formula unit of the electrolyte dissociates completely in the solution. It is a measure of the extent of dissociation of the electrolyte.

For example, for a strong electrolyte such as sodium chloride (NaCl), when it dissolves in water, it completely dissociates into sodium ions (Na+) and chloride ions (Cl-). In this case, the van't Hoff factor (i) would be 2 because one formula unit of NaCl produces two ions (Na+ and Cl-).

Similarly, for other strong electrolytes, the van't Hoff factor (i) can be determined based on the number of ions produced per formula unit. It is important to note that for non-electrolytes or weak electrolytes, the van't Hoff factor (i) is typically less than 1, indicating partial dissociation or no dissociation in the solution.

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Substance A is  liquid at room temperature and pressure, while substance B is  gas under the same conditions.Based on this observation, we can say that intermolecular attractions in substance A are stronger than those in substance B.

Intermolecular attractions  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

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The transition that represents the smallest energy change would be from energy level 4 to energy level 3. This is because the energy levels are closer together as you move from higher to lower energies.

Based on the energy levels shown, a transition from energy level 2 to energy level 1 is not possible. This violates the principle that an electron cannot occupy energy levels lower than its ground state.

The transition from energy level 5 to energy level 2 represents the reddest wavelength. This is because the energy difference between these levels corresponds to a lower energy photon with a longer wavelength, which is perceived as red.

The transition from energy level 3 to energy level 1 represents the bluest wavelength. This is because the energy difference between these levels corresponds to a higher energy photon with a shorter wavelength, which is perceived as blue.

The transition from energy level 5 to energy level 1 results in a photon with the same energy as that absorbed originally. This corresponds to the electron returning to its original energy level, releasing a photon with the same energy as the absorbed photon.

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Your question is incomplete, but most probably your full questions was,

Answer the following Critical Thinking Question. Explain your answers.You may respond to the answers of the other students after you have answered the question.

A schematic of the energy levels of a hypothetical atom is shown below. An electron has been excited from energy level 1 to energy level 5 by absorbing a photon.