Answers
The total radiated intensity of the star is approximately 2.2 x 10¹⁵W/m². Therefore, the peak-intensity wavelength of the star is approximately 121 nanometers.
What is the stars' highest wavelength?The peak wavelength of a star is the wavelength at which it produces the most light. The diagram to the right demonstrates that the highest wavelength of this star is 4000 Angstroms.
(a) The Stefan-Boltzmann law can be used to determine the star's overall radiated intensity (I):
I = σT⁴
Substituting the given values, we get:
I = (5.67 x 10⁻⁸ W/m²K⁴) × (24000 K)⁴
I ≈ 2.2 x 10¹⁵W/m²
(b) The Wien's displacement equation can be used to determine the peak-intensity wavelength (max):
λmax = b / T
Substituting the given value, we get:
λmax = (2.898 x 10⁻³m·K) / (24000 K)
λmax ≈ 1.21 x 10⁻⁷ m.
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Related Questions
position (m)
80!
В
с
60
40
20
A
- 20
-40
10
20
30
40
50
time (sec)
Answers
Answer:
hola bb como estas dime bb en que te ayudo
Explanation:
6. An α particle is a positively charge particle which is the nucleus of a helium atom He. An engineer who studied
Physics 158 E&M is designing a detector using a long metal wire and a uniform plastic plate. The details are as follows
-- the long line carrying a uniform linear charge density +50.0 μC/m runs parallel to and 10.0cm from the surface of a
large, flat plastic plate that has a uniform surface charge density of −100μC/m2 on one side.
a) Determine the individual Electric Fields of the wire and the plate.
b) Determine the total Electric Field of the wire and plate.
c) Determine the location of all points where an α particle would feel no force due to this arrangement of
charged objects. Assume the plastic plate lies in the (x,y) plane.
Look at the attached image please.
Answers
The electric field due to the line and plate can be obtained by plugging
the values of +50μC/m and -100 μC/m² into the respective formulas.
Responses:
\(a) \hspace{0.15 cm} Electric \ field \ of \ the \ line, \ E_z \approx \underline{\dfrac{899180.469}{z}}\)
\(Electric \ field \ from \ the \ plate, \ E_p = \underline{ 5649717.51 \ N/C}\)
\(b) \hspace{0.15 cm}Total \ electric \ field, \ E_{Total} = \underline{\left(\dfrac{899180.469}{z}+ 5649717.51 \right) \ N/C}\)
c) The alpha particle will feel no force at a distance 15.9 cm from the line in the z-plane
Which method can be used to calculate the electric fields in the system?The electric field of the line is given as follows;
\(E_z = \mathbf{\dfrac{\lambda}{2 \cdot \pi \cdot \epsilon _0 \cdot z}}\)Where;
λ = +50.0 μC/m
ε₀ = The permittivity of free space = 8.85 × 10⁻¹² F/m
z = The distance from the plate
Therefore;
\(Electric \ field \ of \ the \ line, \ E_z = \dfrac{+50 \times 10^{-6}}{2 \times \pi \times 8.85 \times 10^{-12} \cdot z} \approx \underline{\dfrac{899180.469}{z}}\)The electric field due to the plate is given as follows;
\(\mathbf{Potential} \ at \ a \ distance \ x, \ V = -\dfrac{\sigma \cdot x }{2 \cdot \epsilon _0}\)
Which gives;
\(Electric \ field \ from \ the \ plate, \ E_p= \mathbf{-\dfrac{\sigma }{2 \cdot \epsilon _0}}\)
Therefore;
\(Electric \ field \ from \ the \ plate, \ E_p= -\dfrac{ -100 \times 10^{-6} \ C/m^2 }{2 \times 8.85 \times 10^{-12} \, C^2/(N \cdot m^2)} = \underline{ 5649717.51 \ N/C}\)b) The total electric field of the wire and the plate is therefore;
\(E_{Total} = \mathbf{ E_z + E_p}\)
Which gives;
\(Total \ electric \ field, \ E_{Total} = \underline{\left(\dfrac{899180.469}{z}+ 5649717.51 \right) \ N/C}\)c) The points at which an alpha particle will fill no force is found as follows;
F = Q·E
The charge on an alpha particle, Q = 3.2 × 10⁻¹⁹ C
At the point the alpha particle feels no charge, we have;
\(\dfrac{899180.469 \times 3.2 \times ^{-19}}{z}= \mathbf{5649717.51 \right) \times 3.2 \times ^{-19}}\)
Which gives;
\(z = \dfrac{899180.469 \times 3.2 \times ^{-19}}{5649717.51 \times 3.2 \times ^{-19}} \approx \mathbf{ 0.159}\)
The distance from the long line at which an alpha particle will feel no force is z ≈ 0.159 m = 15.9 cm Which gives;
A radius of 15.9 cm in the z-planeLearn more about electric field here:
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1. A car travels at 55 km/h for 6.0 hours. How far does it travel?
Answers
Answer:
330 km
55*6= 330 km. An easy formula for this is multiplying time with speed.
Explanation:
330 kilometros
55 * 6 = 330 km. Una fórmula fácil para esto es multiplicar el tiempo por la velocidad.
Answer:330 km
Explanation:55*6= 330 km. An easy formula for this is multiplying time with speed.
An archer shoots an arrow over flat ground. The speed of the arrow is 45m/s. (3 questions)
A.) What is the maximum possible range of the arrow?
B.) At this range, what is the maximum height?
C.) What 2 angles will give a range of 90 meters?
Answers
An archer shoots an arrow with a velocity of 45.0 m/s at an angle of 50.0° with the horizontal. An assistant standing on the level ground 150 m downrange from the launch point throws an apple straight up with the minimum initial speed necessary to meet the path of the arrow. (a) The initial speed of the apple is 30.352m/s. (b)The time taken by arrow to reach this point is 5.185 s. So, the apple should be thrown 2.09s after the arrow launch.
What is velocity?Velocity is a term defines that a particle covered distance in a particular time. It is a vector quantity. it can be measured in m/s or cm/s.
How can we calculate the velocity?(a) To calculate the velocity we are using the formula, y₂=v*t - 1/2 *g*t²
Now we are given,
Let the speed of apple be v(min)
Time taken by arrow to reach P is
t = (x₂- x₁)/(v₁ * cosθ )
t= (150m)/(45*cos 50°)
t= 5.185s
Vertical distance covered by arrow
y₂ = y₁ + (v₁ * sin θ) * t - 1/2 * g * t²
y₂ = (45sin 50 deg)(5.185) - (4.9) * (5.185)²
y₂= 47.0046m
The apple also covers the same distance (vertically) in this time
So, for the apple
v₁*t - 1/2*g*t² = 47.0046m
4.9t² - v*t + 47.0046 = 0
v = (1/t) * [4.9t² + 47.0046]
v= 4.9t + 47.0046/t
For minimum velocity of apple,
(dv)/(dt) = 0
4.9 - 47.0046/(t²) = 0
t = 3.0972s
v(min) =v (at,3.0972)
= 4.9 * 3.0972 + (47.0046/3.0972)
= 30.352m/s
According to the calculation we can say that, The initial speed of the apple is 30.352m/s.
(b) From part (a) we knew that for v(min) , t = 3.0972s and the time taken by arrow to reach this point is 5.185 s.
So, the apple should be thrown 5.185 - 3.0972 = 2.0878s
= 2.09s
after the arrow launch.
According to the calculation we can say that, The time taken by arrow to reach this point is 5.185 s. So, the apple should be thrown 2.09s after the arrow launch.
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An archer shoots an arrow with a velocity of 45.0 m/s at an angle of 50.0° with the horizontal. An assistant standing on the level ground 150 m downrange from the launch point throws an apple straight up with the minimum initial speed necessary to meet the path of the arrow.
(a) What is the initial speed of the apple?
(b) At what time after the arrow launch should the apple be thrown so that the arrow hits the apple?
In the figure, a 32 cm length of conducting
wire that is free to move is held in place
between two thin conducting wires. All of the
wires are in a magnetic field. When a 6.0 A
current is in the wire, as shown in the figure,
the wire segment moves upward at a constant
velocity.
The acceleration of gravity is 9.81 m/s?.
a) Assuming the wire slides without friction
on the two vertical conductors and has a mass
of 0.13 kg, find the magnitude of the minimum
magnetic field that is required to move the
wire.
Answer in units of T. b) What is the direction?
Answers
Answer:
.66354 T
Explanation:
Use F=ILB
B = \(\frac{F}{IL}\)
B = Magnetic field
F= force due to magnetic
I= current
L= length in meters
F = mg
Final formula:
B=\(\frac{mg}{IL}\)
B=\(\frac{(.13)(9.8)}{(6)(.32)}\)
B= .66354
ayo btw ion know how to find direction, my b G
The minimum magnetic field required to move the wire is 66354 T.
The direction of magnetic field is normal to the page outwards.
What is magnetic field?The region surrounding a magnet that experiences the effects of magnetism is known as the magnetic field. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.
Given parameter:
Current passing through the wire, I = 6.0 A.
Length of the wire ,L = 32 cm = 0.32 m.
Mass of the wire, m = 0.13 Kg.
Acceleration due to the gravity, g = 9.8 m/s².
We know that, force acting on a current caring wire due to magnetic field is, F=ILB
Where,
B = Required magnetic field.
To find the minimum magnetic field that is required to move the
wire, force acting on a current caring wire due to magnetic field is equal to weight the wire, that is, mg.
Hence, we can write,
mg = ILB
⇒ B = mg/IL
= (0.13 * 9.8)/(6.0 * 0.32)
=0.66354 Tesla
Hence, the minimum magnetic field is 0.66354 Tesla.
b) By using Maxwell's right hand thumb Rule along current flow, the direction of magnetic field is determined as normal to the page pointing outwards.
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Four-wheel drive trucks do not stop better on icy
roads than a car. Is what law of motion (Newton's laws)
Answers
Use g = 9.80 m/s2 (down]
1. What velocity does a freely falling object reach after 4.0 s if it starts from rest?
Answers
Vf = 0 + (9.80)(4)
Vf = 39.2 m/s down
Hope a monkey breaks Arnold’s leg!
The velocity of the freely falling object reached after 4.0 s is equal to 39.2 m/s.
What is the equation of motion?A relation can be established between the velocity of the body and acceleration of the body when the body is moving along a straight line with uniform acceleration. The distance traveled by the body in a specific time has expressed a set of equations called equations of motion.
The first equation of motion can be expressed as follows:
v = u + at
Where u is the initial velocity, v is the final velocity and a is the acceleration and t is the time of the object.
Given, the acceleration of the falling object, g = 9.8 m/s²
The initial velocity of the object, u = 0, and the time = 4 sec
The velocity of the object after time, t = 4 sec.
v = (0) + (9.80)× (4)
v = 39.2 m/s
Therefore, the velocity of the falling object will be 39.2 m/s after 4 seconds.
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What impact does your family have on air pollution? Find out how much carbon dioxide your family’s car releases.
a. First find out how many gallons of gasoline your family’s car holds when the tank is full. (Often this is stated somewhere in the owner’s manual.)
b. Estimate how many gallons of gasoline are used each week by your family. You can do this by finding out how many times a week gasoline is put in the car and about how many gallons is put in each time.
c. Now calculate how many pounds of carbon dioxide are emitted each week by your family’s use of the car. How many pounds are emitted each month? Each year?
Answers
My family car has a tank size of 19 gallons, and it is fueled twice a week at about 8 gallons each time. It's yearly carbon emission is about 16,254 pounds per year.
The family car's emissionTo estimate the weekly gasoline consumption, we multiply the number of refills (2) by the amount of gasoline added each time (8 gallons):
Therefore weekly gasoline consumption 2 refills/week at 8 gallons per refill = 16 gallons/week
c. The emission factor for carbon dioxide is approximately 19.55 pounds per gallon.
Therefore, to obtain the weekly emissions,
Multiply the weekly gasoline consumption 16 gallons by the emission factor of carbon dioxide 19.55 pounds per gallon.
Weekly carbon dioxide emissions is 16 gallons/week * 19.55 pounds/gallon
= 312.8 pounds/week
Monthly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a month approximately 4.35) to get the monthly carbon dioxide emissions
Monthly carbon dioxide emissions is 312.8 pounds per week * 4.35 weeks per month
≈ 1,359 pounds/month
Yearly emissions: Multiply the weekly emissions 312.8 pounds by the number of weeks in a year approximately 52 to get the yearly carbon dioxide emissions.
Yearly carbon dioxide emissions is 312.8 pounds per week * 52 weeks per year
≈ 16,254 pounds/year
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How much pressure is created when you apply a
50.0N force on a syringe plunger that has a diameter of 0.4
Answers
= Force/Area
Area = π(d^2)/4
= π(0.4^2)/4
=0.126 m2
Pressure
= 50/0.126
= 396.825 Pa
Which of the following X-Y tables agrees with
the information in this problem?
A)
Vi
Vf
a
ΔΧ
t
A plane is flying east at 115 m/s. The wind
accelerates it at 2.88 m/s² directly northwest.
After 25.0 s, what is the velocity of the plane?
X
115
?
Y
115
?
88 2.88
2.88
25
25
B) X
V₁
Vf
a 2.04 2.04
ΔΧ
t
Y C) X
V₁ 115
V₁
?
0115
25
25
a -2.04
ΔΧ
t
25
Y
0
?
2.04
25
Answers
Table A agrees with the information in the problem. After 25.0 seconds, the velocity of the plane is 187 m/s.
Based on the given problem, we need to determine the velocity of a plane after 25.0 seconds. The plane is initially flying east at a velocity of 115 m/s, and it experiences an acceleration of 2.88 m/s² in the northwest direction.
Let's analyze each option and calculate the final velocity (Vf) of the plane after 25.0 seconds:
Option A:
Vi = 115 m/s
a = 2.88 m/s²
t = 25.0 s
Using the equation Vf = Vi + at, we can calculate:
Vf = 115 m/s + (2.88 m/s²)(25.0 s) = 115 m/s + 72 m/s = 187 m/s
Option B:
V₁ = 2.04 m/s
a = 2.04 m/s²
t = 25.0 s
Using the equation Vf = V₁ + at, we can calculate:
Vf = 2.04 m/s + (2.04 m/s²)(25.0 s) = 2.04 m/s + 51 m/s = 53.04 m/s
Option C:
V₁ = 115 m/s
a = -2.04 m/s²
t = 25.0 s
Using the equation Vf = V₁ + at, we can calculate:
Vf = 115 m/s + (-2.04 m/s²)(25.0 s) = 115 m/s - 51 m/s = 64 m/s
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Studies have found that certain chemicals that help repair damaged cells only
function while we sleep. What theory best explains this?
OA. 80
OB. 30
OC. 20
о D. 50
Answers
Write a multiplication sentence that you could use to calculate the volume for each rectangular pris
Problem 1. Include the units in your sentences.
a.
C.
REKA
TH*
TION
Student
Lesson 4:
b.
O Great Minds PBC TEKS Edition |
greatminds.org/Texas
d.
Use multiplication to calculate volume.how do I solve
Answers
The formulated sentences for each will be:
A: If length is 5cm, width 2cm, height 4cm, volume: 40 cubic centimeters.
B: If the length is 3cm, width 4cm, height 2cm, then Volume is: 24 cubic centimeters.
C: If the length is 6cm, width 2cm, height 3cm, the volume is 36 cubic centimeters.
D: If the length is 3cm, width 2cm, height 4cm, the volume 24 cubic centimeters.
What is the rectangular prism?To calculate the volume of a rectangular prism using multiplication, you need to multiply the length, width, and height of the prism. The multiplication sentence for this is:
Volume = length (m) x width (m) x height (m)
For a. The multiplication sentence for calculating the volume of rectangular prism C is:
Volume = Length x Width x HeightVolume = 6 cm x 2 cm x 3 cmVolume = 36 cubic centimetersb. The multiplication sentence for calculating the volume of rectangular prism B is:
Volume = Length x Width x HeightVolume = 3 cm x 4 cm x 2 cmVolume = 24 cubic centimetersc. The multiplication sentence for calculating the volume of rectangular prism C is:
Volume = Length x Width x HeightVolume = 6 cm x 2 cm x 3 cmVolume = 36 cubic centimetersLastly, for d. The multiplication sentence for calculating the volume of rectangular prism D is:
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Find the work done when the speed of a 3.00 kg object increases from rest to 23.0 m/sec.
Answers
Answer:
793.5 Joules
Explanation:
The work–energy theorem states that the net work done on an object equals the object’s change in kinetic energy.
So we can say W=ΔKE.
The equation for kinetic energy is
\(KE=\frac{1}{2}mv^2\)
Therefore
\(W=\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2\)
\(W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}\)
We are given
\(m=3\)
\(v_i=0\)
\(v_f=23\)
Lets solve for \(W\).
\(W=\frac{3*23^2}{2}-\frac{3*0^2}{2}\)
\(W=\frac{3*23^2}{2}\)
\(W=\frac{3*529}{2}\)
\(W=\frac{1587}{2}\)
\(W=793.5\)
A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answers
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
Kira and Alyssa were best friends in middle school. When they went started high
school, Kira took more theater classes and was in several plays and musicals. Alyssa
tried out for the soccer team and started hanging out more with her teammates. By
the end of 9th grade, they realized that they didn't have much in common any more,
and were much closer with their new groups of friends. This is an example of
social facilitation
O central route of persuasion
Odcindividuation
O groupthink
Ogroup polarization
Answers
Answer:
divide
Explanation:
you have to divide to see the cost of each 9th grade
Which of the following statements best support the claim that human actions decreased the whooping crane population? (1
The sharp decline of Burmese pythons, a predator to the whooping crane, have occurred in areas with high whooping crane populations-
o Other bird species such as the California Condor have been placed on the endangered species list.
The Migratory Bird Treaty Act, signed by Congress, has made hunting whopping cranes illegal.
O The draining of wetlands to build housing, farm, and look for oil and gas has led to the loss of habitats.
Answers
Answer:
D
Explanation:
A is incorrect because it would actually increase the population...
B is incorrect because other birds do not matter, it is only whooping cranes...
C is incorrect because it would also increase the population.
why an object weighs less on moon than earth?
Answers
Since the moon has considerably less mass than the Earth, it will not pull objects toward itself at the strength that Earth will
817 cm3 at 80.8 kPa to 101.3 kPa: __________ cm3 (No temp. change)
Answers
The final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.
To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law can be represented by the equation: P₁V₁ = P₂V₂
Where P₁ and V₁ are the initial pressure and volume, and P₂ and V₂ are the final pressure and volume.
Given:
Initial volume, V₁ = 817 cm³
Initial pressure, P₁ = 80.8 kPa
Final pressure, P₂ = 101.3 kPa
We need to find the final volume, V₂.
Using Boyle's Law equation, we can rearrange it to solve for V₂:
V₂ = (P₁V₁) / P₂
Plugging in the given values:
V₂ = (80.8 kPa * 817 cm³) / 101.3 kPa
Simplifying the expression:
V₂ ≈ 652.9 cm³
Therefore, the final volume of the gas, when the pressure changes from 80.8 kPa to 101.3 kPa at constant temperature, is approximately 652.9 cm³.
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the international space station orbits the earth at a speed of 7660m/s.If it has a kinetic energy of 1.24 x 1013J, what is its mass
Answers
Answer:
4.2 x 10⁵kg
Explanation:
Given parameters:
Speed of orbit = 7660m/s
Kinetic energy = 1.24 x 10¹³J
Unknown:
Mass = ?
Solution:
Kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;
K.E = \(\frac{1}{2}\)mv²
m is the mass
v is speed
Now insert the parameters and find the mass;
1.24 x 10¹³ = \(\frac{1}{2}\) x m x 7660²
1.24 x 10¹³ = 2.93 x 10⁷m
m = \(\frac{1.24 x 10^{13} }{2.93 x 10^{7} }\) = 0.42 x 10⁶kg = 4.2 x 10⁵kg
Seismic waves are the waves that transport energy away from the focus of an
earthquake. Seismometers, such as the one shown here, measure the
shaking of the Earth as a result of earthquakes. The black arrows show the
relative motion of the sensor on the seismometer. What characteristic of a
seismic wave is this motion showing?
OA. The period of the seismic wave
OB. The amplitude of the seismic wave
4
Answers
The characteristic of a seismic wave that the motion shown by the sensor on the seismometer represents is the amplitude of the seismic wave.
Seismic waves are waves that transport energy away from the focus of an earthquake, and they cause the ground to shake. Seismometers are instruments that measure the shaking of the Earth caused by seismic waves. The black arrows in the picture show the relative motion of the sensor on the seismometer. The sensor moves back and forth as the ground shakes, and the amplitude of this motion represents the intensity of the seismic wave.The amplitude of a seismic wave is a measure of the strength or energy of the wave. It is the maximum displacement of the ground from its resting position during the passage of the wave. The greater the amplitude of the seismic wave, the stronger the shaking of the ground and the more damage it can cause. The amplitude of a seismic wave is usually measured in millimeters or centimeters.In summary, the motion shown by the sensor on the seismometer represents the amplitude of the seismic wave. This is an important characteristic of a seismic wave as it determines the intensity of the shaking and the potential damage that the earthquake can cause. Seismologists use this information to study earthquakes and to understand their effects on the Earth.
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The greater the distance between two objects in space, the _______ their gravitational
Answers
Answer is Weaker. If it is talking about the objects' gravitational forces.
What characteristics determine how easily two substances change temperature? Check all that apply.
volume of the two substances in contact
amount of time the two substances are in contact
Oarea in contact between the two substances
specific heat of the material that makes up the substances
density of the two substances in contact
Answers
Answer:
The characteristics that determine how easily two substances change temperature are:
specific heat of the material that makes up the substancesarea in contact between the two substancesThe volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.
Explanation:
Pls help!!
Which situation describes a system with increasing gravitational potential energy?
a boy jumping down from a tree limb
a girl stretching a horizontal spring
a bicyclist riding up a steep hill
a train speeding up on a flat track
Answers
C) a bicyclist riding up a steep hill
The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:
A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.
Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.
Where Is Earth's heat energy most concentrated?
A
The mantle
B
The lithosphere
С
The core
D
The crust
Answers
Answer:
C. the core
Explanation:
since it has the most energy and the hottest layer
An electron is travelling in the positive x direction. A uniform electric field is in the negative y direction. If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero. The appropriate direction for the magnetic field is:Group of answer choicesthe negative y directioninto the pageout of the pagethe negative x directionthe positive y direction
Answers
Answer:
into the page
Explanation:
Since the uniform electric field is in the negative y direction so its is -E and the electron is travelling in the positive x direction, it experiences an electric force F = -e × -E = + eE, so the electric force is in the positive y direction. Now since the net force on the electron is zero in the region of the magnetic field, it follows that the direction of the magnetic force is opposite to that of the electric force. Since the electric force is in the positive y direction, the magnetic force is in the negative y direction.
By the right hand rule, since the magnetic force is in the negative y direction and the electron moves in the positive x direction, it follows that the magnetic field is in the positive z direction, into the page.
a ball rolling down a hill was displaced 21.9 m while using uniformly accelerating from rest, If the final velocity was 7.14 m/s, what was the rate of acceleration?
Answers
Answer:
a = 1.16 m/s²
Explanation:
In order to find the rate of acceleration of the ball, we will use third equation of motion, as follows:
2as = Vf² - Vi²
where,
a = rate of acceleration = ?
s = distance covered by the ball = 21.9 m
Vf = Final Velocity of the ball = 7.14 m/s
Vi = Initial Velocity of the ball = 0 m/s (Since, the ball started from rest)
Therefore,
2(a)(21.9 m) = (7.14 m/s)² - (0 m/s)²
a = (50.97 m²/s²)/(43.8 m)
a = 1.16 m/s²
Which bibliographic description for a book is correct, based on the Harvard Method in your study guide?
Answers
An annotated bibliography is a list of citations to books, articles, and documents. Each citation is followed by a brief descriptive and evaluative paragraph, the annotation. The purpose of the annotation is to inform the reader of the relevance, accuracy, and quality of the sources cited.
The cue column is typically located on the left-hand side of the page and is used to jot down keywords or questions that serve as cues for recalling the main points of the lecture or reading. The note-taking area is located on the right-hand side of the page and is used to write down detailed notes about the lecture or reading.
The summary section is located at the bottom of the page and is used to summarize the key points of the notes. Overall, the Cornell method is an effective way to organize and retain information during lectures and readings.
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#1 A boy pushes forward a cart of groceries with a total mass of 40 kg. What is
the acceleration of the cart if the net force on the cart is 60 N?
Answers
Explanation:
∑F = ma
60 N = (40 kg) a
a = 1.5 m/s²
Please help me in this question
Answers
Answer:
A. Yes, the force of the engine does work on the car as it makes the car move forward.
B. Yes, the kinetic energy of the car increases as the car gains speed due to the force of the engine.
C. The gravitational potential energy of the car remains constant as the car is moving on a horizontal road, and there is no change in its height.
D. Yes, the tractive force of the engine changes the mechanical energy of the car as it is a type of external force that transfers energy to the car and increases its kinetic energy.
Explanation:
7. A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the
planet's surface, the scale indicates a force of 10,000 Newtons. Calculate the surface area of the scale,
given that atmospheric pressure on the surface of Physica is 80,000 Pascals.
Known Variables:
Equation:
Solution:
P =
F=
A =
Answers
A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.
To calculate the surface area of the scale, we can use the formula:
P = F/A
where P is the pressure, F is the force, and A is the surface area.
Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:
80,000 Pa = 10,000 N / A
To solve for A, we can rearrange the equation:
A = 10,000 N / 80,000 Pa
A = 0.125 m²
In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.
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