specify the degree of unsaturation (index of hydrogen deficiency) of the following formulas: (a) c11h12 (b) c13h14 (c) c6h9no3

There are 4.48 × 10-3 moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution if Ksp for AgBr is 3.3 × 10-13 and Kf for the complex ion \([Ag(S_{2}O_{3})_{2}]^{3-}\).

AgBr dissociates in water, and we can write the reaction as shown below:

\(AgBr = Ag^{+} + Br{-}\)

Since \(Ksp = [Ag^{+}][Br^{-}]\), we can obtain the equilibrium concentrations of \(Ag^{+}\) and \(Br^{-}\) from the Ksp value, using the stoichiometry of the balanced equation. Here, the concentration of  \(Br^{-}\)  is equal to that of \(Ag^{+}\).

Therefore, \(Ag^{+}\) =  \(Br^{-}\)  = √Ksp = √3.3 × 10-13 M\(\sqrt{Ksp} = \sqrt{3.3 * 10^{-13}} M\)  \(5.74 * 10^{-7}\) M. To determine the number of moles of \(Na_{2}S_{2}O_{3}\) required to dissolve 0.35 mol of AgBr in a 1.0 L solution, we must calculate the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) ion first.

Kf = \([Ag(S_{2}O_{3})_{2}]^{3-}\)./(\(Ag^{+}\)\([S_{2}O_{3}^{-2}]\))

For \(Ag^{+}\), we use the concentration obtained from Ksp:

\(Ag^{+}\)= \(5.74 * 10^{-7}\) M

Kf =  \(4.7 * 10^{13}\) mol-1L-3

\([Ag(S_{2}O_{3})_{2}]^{3-}\)= Kf × \([Ag(S_{2}O_{3})_{2}]^{3-}\)

=  \(Ag^{+}\)/Kf

\([Ag(S_{2}O_{3})_{2}]^{3-}\)

= (\(5.74 * 10^{-7}\) M)/(\(4.7 * 10^{13}\)  mol-1L-3 × (\(5.74 * 10^{-7}\) M)2)

= \(4.48 * 10^{-3}\) M

To find the number of moles of \(Na_{2}S_{2}O_{3}\) required to dissolve AgBr in 1 L of solution, multiply the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) by the volume of the solution:

\(4.48 * 10^{-3}\)  M × 1 L = \(4.48 * 10^{-3}\) moles \(Na_{2}S_{2}O_{3}\).

\(4.48 * 10^{-3}\) moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution.

We used the stoichiometry of the balanced equation and the Ksp value to determine the concentration of [Ag+] and [Br-]. Then, we calculated the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\). from the Kf value and the [Ag+] value obtained from Ksp.

Finally, we multiplied the concentration of \([Ag(S_{2}O_{3})_{2}]^{3-}\) by the volume of the solution to obtain the number of moles of \(Na_{2}S_{2}O_{3}\) needed to dissolve 0.35 mol of AgBr in a 1.0 L solution.

4.48 × 10-3 moles of \(Na_{2}S_{2}O_{3}\) are required to dissolve 0.35 mol of AgBr in a 1.0 L solution if Ksp for AgBr is  \(3.3 * 10^{-13}\) and Kf for the complex ion \([Ag(S_{2}O_{3})_{2}]^{3-}\) is \(4.7 * 10^{13}\)  mol-1L-3.

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Taking into account the definition of calorimetry, the energy released is 2283.93 J.

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

In this way, between heat and temperature there is a direct proportional relationship. the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

In this case, you know:

Replacing in the definition of calorimetry:

Q = 0.3845 \(\frac{J}{gC}\)× 26.4 g× (-225 C)

Solving:

Q= -2283.93 J

Finally, the energy released is 2283.93 J.

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The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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The name given to the smallest group of atoms, ions, or molecules that form the building block of a mineral is called unit cell.

What is unit cell?

A unit cell is the smallest part of a crystal lattice that exhibits the three-dimensional structure of the entire crystal. The identical unit cell can be thought of as being duplicated in three dimensions in a crystal.

An atom is what?

Atoms, which are minuscule bits of matter, are what distinguish each chemical element from the others. A negatively charged core nucleus and one or more orbiting electrons make up an atom. There may be the positively charged, somewhat massive protons and neutrons that make up the nucleus.

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Answer:

A and E

Explanation:

with Adenine ,thymine , cytosine and guanine

Answer:

5/8 M

Explanation:

NaOH + HCl ====> NaCl + H2O

in 25 mL of 0.5M acid, we have 1/80 Mol of HCl

it mean we must have 1/80 Mol of NaOH.

20 mL = 1/50 L

(1/80)Mol / (1/50)L = 5/8 M

Answer:

2 Zn + Ag 2O = 2ZnO + Ag

Explanation:

At the end you will have 2 zn on each side, 1 ag on each side, and 2 o on each side.

The mass of H2O that can be produced is 4.54 grams.

The balanced chemical equation for the reaction between H2SO4 and Ca(OH)2 is:

H2SO4 + Ca(OH)2 → CaSO4 + 2H2O

From the balanced equation, we can see that one mole of H2SO4 reacts with one mole of Ca(OH)2 to produce two moles of H2O.

First, we need to convert the given mass of H2SO4 into moles:

Molar mass of H2SO4 = 2(1.01 g/mol of H) + 32.06 g/mol of S + 4(16.00 g/mol of O) = 98.08 g/mol

Moles of H2SO4 = 12.35 g / 98.08 g/mol = 0.126 moles

Since H2SO4 and Ca(OH)2 react in a 1:1 ratio, we know that 0.126 moles of Ca(OH)2 are needed to react with 0.126 moles of H2SO4. However, we are given that there is excess Ca(OH)2, which means that all of the H2SO4 will react with Ca(OH)2, and the Ca(OH)2 will not be completely consumed.

Next, we can use the mole ratio from the balanced equation to find the moles of water produced:

1 mole of H2SO4 produces 2 moles of H2O

0.126 moles of H2SO4 will produce:

0.126 mol H2SO4 x (2 mol H2O / 1 mol H2SO4) = 0.252 mol H2O

Finally, we can convert the moles of water produced into grams:

Molar mass of H2O = 2(1.01 g/mol of H) + 16.00 g/mol of O = 18.02 g/mol

Mass of H2O = 0.252 mol x 18.02 g/mol = 4.54 g

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Answer:

\({ \rm{Pb_{3}( PO_{3})_{2} + 3K_{2}CO _{3} →2 K_{3} PO_{3} + 3PbCO_{3}}}\)

Answer:

hope u umderstood ! if explanation needed then conta t

Nitrogen and hydrogen react to form ammonia and is a combination reaction. The grams of hydrogen used in the reaction with nitrogen to form ammonia is 2.0 grams.

Mass is the weight or the product of the volume and density of the substance. It can be calculated as, \(\rm volume \times density.\)

Given,

Mass of nitrogen = 10.0 grams

Mass of ammonia = 12.0 grams

Mass of hydrogen = x gram

Solving for x:

\(\begin{aligned}\rm 10 + x &= 12\\\\\rm x &= 12.0 - 10.0\\\\&= 2.0 \;\rm grams\end{aligned}\)

Therefore, 2.0 grams of hydrogen is required to react with 10.0 grams of nitrogen to produce 12.0 grams of ammonia.

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Answer:

22 L OF WATER VAPOR WILL BE PRODUCED AT STP IF 5.5 L OF PROPANE WERE BURNED.

Explanation:

Balanced Equation for the reaction:

C3H8(g) + 5O2(g) -------> 3CO2(g) + 4H2O(g)

From the reaction;

1 mole of propane gas reacts with 5 moles of oxygen gas to form 4 moles of water vapor.

At STP, 1 mole of a gas occupies 22.4 dm^3 of the gas

So therefore, 22.4 dm^3 of propane reacts with oxygen to produce 4 * 22.4 dm^3 of water vapor.

22.4 dm^3 of propane = 89.6 dm^3 of water vapor

If 5.5 L of propane were to be burned, how many litres of water would be produced?

22.4 L of propane produces 89.6 L of water

5.5 L of propane will produce ( 5.5 L * 89.6 L/ 22.4 L) L of water vapor

5.5 L of propane will produce 492.8 / 22.4 L of water vapor

5.5 L of propane will produce 22 L of water vapor.

So at the end of the reaction of 5.5 L of propane, 22 L of water vapor will be given off.

Given that the disturbance travels along the length of the rope, the farther I move my arm, the larger the size of the wave in the rope.

A wave is a disturbance along a medium which transfers energy. We know that a wave could be classified based on the nature of the propagation of  the wave as the transverse or the longitudinal waves.

The wave that is created along a string is a longitudinal wave. The direction of the wave motion is the same as that of the disturbance. It is very easy to create a wave on a string when the sting is moved vigorously and the wave is found to travel quickly across the length of the rope is we can see from the image that I have attached to make the concept and the context of the answer a bit more clearer to the student in this case.

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Steel ball bearings and marbles can be separated through manual sorting due to their difference in appearance.

Before answering the question, let us define the given choices.

The given separation techniques are not suitable for the separation of steel balls bearings, and marbles. Instead, the sorting separation technique must be used. This is used for manually sorting coarse materials based on their physical characteristic, which in this case is their difference in appearance.

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Answer:

mass

Explanation:

Answer:

The answer is C.

Explanation:

If you have absolutely identical objects that have the same weight exactly when they are at the same temperature, then when one object is heated, it will weigh more.

Hope this helps :)

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Answer:

\(\boxed {\tt 5.26315789 \ m/s}\)

Explanation:

One way to find velocity is by dividing the distance by the time.

\(v=\frac{d}{t}\)

The distance traveled by the man is 100 meters.

The time is 19 seconds.

\(d=100 \ m \\t= 19 \ s\)

\(v=\frac{100 \ m}{19 \ s}\)

Divide.

\(v=5.26315789 \ m/s\)

The man's velocity is 5.26315789 meters per second.

The percent yield of oxygen in this chemical reaction is 73.40%.

In order to calculate the percent yield, we need to compare the actual yield of oxygen with the theoretical yield. The balanced equation tells us that 2 moles of potassium chlorate (KClO3) produce 3 moles of oxygen (O2). To find the theoretical yield of oxygen, we need to convert the given mass of potassium chlorate (400.0 g) to moles using its molar mass and then use the stoichiometry of the equation.

The molar mass of KClO3 is calculated as:

K: 39.10 g/mol

Cl: 35.45 g/mol

O: 16.00 g/mol

3 O atoms: 3 * 16.00 g/mol = 48.00 g/mol

Total molar mass of KClO3 = 39.10 g/mol + 35.45 g/mol + 48.00 g/mol = 122.55 g/mol

Using the given mass of 400.0 g and the molar mass, we can calculate the number of moles of KClO3:

400.0 g / 122.55 g/mol ≈ 3.263 mol

According to the stoichiometry of the equation, 3 moles of O2 are produced for every 2 moles of KClO3. Therefore, the theoretical yield of oxygen is:

(3.263 mol KClO3 / 2 mol KClO3) * (3 mol O2) ≈ 4.895 mol O2

The actual yield of oxygen is given as 115.0 g. To calculate the percent yield, we divide the actual yield by the theoretical yield and multiply by 100:

(115.0 g / 4.895 mol) * 100 ≈ 2351%

Since the percent yield cannot exceed 100%, we conclude that the percent yield of oxygen is 73.40%.

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Answer:

The valence electron configuration determines the group to which an element belongs to.

Explanation:

The valence electron configuration of an atom of an element refers to the number of electrons in that atoms outermost shell.

The valence electron configuration is related to the group number of an element in that the number of electrons in the valence shell of an atom of an element determines the group to which an element belongs to. For example, all elements having one valence electron belong to group IA of the periodic table. Similarly, all elements having seven valence electrons belong to group VIIA of the periodic table.

This is because, since the reactivity of an element is related to its ability to either gain or lose a certain number of electrons in its valence shell, elements having same number of valence electrons have similar chemical properties.

Answer:

is a

Explanation: A, because the oceanic plate and continental plate are pushed up together

Location A, because the lighter oceanic plate will be pushed under the continental plate

Answer:

is a

Explanation:



Answer:

location A

Explanation:

Plates Subduct When an ocean plate collides with another ocean plate or with a plate carrying continents, one plate will bend and slide under the other. This process is called subduction. A deep ocean trench forms at this subduction boundary.

plus location B doesn't seem to have 2 plates colliding to cause subduction in the first place.

your welcome

The pH of a Chy-NH buffer that consists of 0.33 M CH3-NH, and 0.28 M of its conjugate can be determined using the Henderson-Hasselbalch equation.

The Henderson-Hasselbalch equation is used to calculate the pH of a buffer solution by taking into account the concentrations of the acid and conjugate base, and the acid dissociation constant (K a ).

In this case, the calculated pH of the Chy-NH buffer is 8.86. This result is expected, as the pH of a buffer solution is largely dependent on the ratio of the acid to conjugate base concentrations, and the K a value.

When the acid to conjugate base ratio is close to the K a value, the pH of the buffer solution tends to be close to the pK a value. In this case, the K a value is 3.7x10-4, and the ratio of acid to conjugate base is close to the K a , resulting in a pH close to the pK a of 8.86.

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B is the answer ,ammonium accepts a proton and becomes ammonium ion

If the pH of a solution is one and it is diluted by 1*10^3 times, the pH of the resulting solution will be 4.

The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm of the concentration of hydrogen ions in the solution.

When a solution is diluted by a factor of 10, its pH increases or decreases by 1 depending on whether it is an acidic or basic solution, respectively. In this case, the solution has been diluted by a factor of 1*10^3, which means that its pH will increase by 3 units. Therefore, the pH of the resulting solution will be 4 (pH of the original solution + 3).

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Answer:

2 lol

Explanation:

Due to the lack of supply of energy the methane could not change its phase before 2007.

Even though it has been summer since 2002, the lake didn't dry up until 2007. After 2007, the sun had given out enough energy for the methane molecules' kinetic energy to rise enough to outweigh their attraction to one another. The methane molecules in the lake were gaining kinetic energy at this moment, but the lake was still liquid. The temperature of the molecules remains constant while they melt because the average kinetic energy of the molecules does not vary.

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Answer:

either first or second if not them try d but I'm pretty sure a also I'm sorry if I getbyou this wrong I dearly apologize

The electron started in the second energy level (n₁ = 2) before transitioning to the third level.

To determine the initial level of the electron in a hydrogen atom, we can use the Rydberg formula, which relates the wavelength of a photon emitted or absorbed during an electron transition to the energy levels in hydrogen:

1/λ = R * (1/n₁² - 1/n₂²)

Where, λ is the wavelength of the photon,

R is the Rydberg constant (approximately 1.097 x 10^7 m^-1),

n₁ is the initial energy level,

n₂ is the final energy level.

Given that, the wavelength of the emitted photon is 1,094 nm (or 1.094 x 10^-6 meters) and the electron transition occurs to the third level (n₂ = 3), we can substitute these values into the formula and solve for n₁:

1/λ = R * (1/n₁² - 1/n₂²)

1/(1.094 x 10^-6) = 1.097 x 10^7 * (1/n₁² - 1/3²)

Simplifying the equation:

1.094 x 10^6 = 1.097 x 10^7 * (1/n₁² - 1/9)

1/n₁² - 1/9 = (1.094 x 10^6) / (1.097 x 10^7)

1/n₁² - 1/9 ≈ 0.0997

1/n₁² ≈ 0.0997 + 1/9

1/n₁² ≈ 0.1997

n₁² ≈ 1 / 0.1997

n₁² ≈ 5.004

n₁ ≈ √5.004

n₁ ≈ 2.24

Therefore, the electron started in the second energy level (n₁ = 2) before transitioning to the third level.

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Answer:

1)0.5

3)1.7g

4)32g

5)1.12L

Answer:

By adding water to a mixture of charcoal and Cu O

Explanation:

CuO is insoluble in water and charcoal dissolves or floats in water or can be separated by first filtering the CuO and then by evaporation or decantation, we can seperate out charcoal