Sources of error could have come from friction that may result in energy losses during the collision, The gliders may not be perfectly elastic, which means that some energy may be lost during the collision
are these errors random or systematic errors?

Sources of error could have come from small amounts of friction, and glider 2 could have not been totally at rest. These errors are systematic errors.
Are these errors random or systematic?

Answers

Answer 1

Answer:

The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.

The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.

Explanation:


Related Questions

How much work is it to push a box (mass 150 kg) up an incline (angle 15 degrees with the horizontal) that is 8.1 meters long, if the coefficient of kinetic friction between the box and the incline is 0.4

Answers

Given that,

Mass of a box, m = 150 kg

It is pushed at an angle of 15 degrees with the horizontal.

It is 8.1 m long.

The coefficient of kinetic friction between the box and the incline is 0.4

To find,

The work done in pushing the box.

Solution,

First let's see the net force acting on the box.

\(F_{net}=mg\sin\theta+f_k\\=mg\sin\theta+\mu_k mg\cos\theta\)

Work done is given by :

W = force × displacement

\(W=(mg\sin\theta+\mu_k mg\cos\theta)\times s\\\\=150\times 10(\sin15+8.1\times \cos15)\times 8.1\\\\=98206.24\\\\or\\\\=98.2\ kJ\)

So, the required work done is 98.2 kJ.

How much work is it to push a box (mass 150 kg) up an incline (angle 15 degrees with the horizontal)

What is the acceleration of a softball with a mass 0.5kg that is thrown with a force of 25 N?

Answers

Answer:

50 m/s^2

Explanation:

F=ma

25 N= 0.5 kg • a

divide both sides by 0.5 kg

a=50 m/s^2

Which is not an example of resonance?1) a basketball is dribbled down the court2) a car bumper bounces back after a collision3) a child swings higher as she is pushed on a swing4) a guitar string is repeatedly plucked

Answers

The correct answer is (2)

A car bumper bounces back after a collision is not an exampl

A race car makes one lap around a track of radius 50 m in 9.0 s. What was the car's centripetal acceleration?

Answers

The velocity of the car is 5.5 m/s. Then the centripetal acceleration of the car will be 0.6 m/s².

What is centripetal acceleration?

Acceleration is a physical quantity measuring the rate of change in velocity. It has both magnitude and direction.

Centripetal acceleration is the acceleration of an  object moving through a circular path. Thus its measures the rate of change in velocity of the body moving in the curvature path.

The centripetal acceleration = V²/R.

Where R is the radius of the curvature path.

The car moves 50 m in 9 seconds. Its velocity is 50/9 = 5.5 m/s.

Thus, centripetal acceleration = (5.5 × 5.5) m/s/ 50 m = 0.6 m/s².

Therefore, the centripetal acceleration of the car moving at a speed of 9 m/s through curvature path is 0.6 m/s².

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6. A 1.0-kg ball on the end of a string is whirled at a constant speed of 2.0 m/s in a
horizontal circle of radius 1.5 m. What is the work done by the centripetal force
during one revolution?

Answers

The work done by the centripetal force during one revolution is 25.12 J.

What is workdone?

Work is said to be done when ever a force moves moves a body through a certain distance.

To calculate the workdone by the centripetal force during one revolution, we use the formula below.

Formula:

W = (mv²/r)2πr........................ Equation 1

Where:

W = Work done by the centripetal force during one revolutionr = Radius of the circlev = Speed of the ball around the circlem = Mass of the ball

From the question,

Given:

m = 1 kgv = 2 m/sr = 1.5 m/sπ = 3.14

Substitute these values into equation 1

W = (1×2²/1.5)×2×3.14×1.5W = 25.12 J

Hence, the work done is 25.12 J.

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Newton’s third law in football?

Answers

Newtons third law of motion applies to football as when the ball is thrown, force is applied to the football thrown forward and also force back to the player. Therefore it states that every action has a reaction. The player does not get a huge force back from throwing the football due to the player having a bigger mass than the football being thrown.

In short, when the football is throw, there is a reaction with the ball and the player accordingly with the force put into the ball.

A freight car moves along a frictionless level railroad track at constant speed. The freight car is open on top. A large load of coal is suddenly dumped into the car. What happens to the speed of the freight car

Answers

Answer:

The speed of the freight car decreases.

Explanation:

According to the law of conservation of momentum indicates that for colliding in an isolated system, the total momentum pre and post collision is same for the two objects this is done because the momentum that one item has lost is same for the momentum that the other received

In the given situation, the freight car travels at constant speed along a frictionless railroad line. The top floor freight car is open. Then a huge load of coal is dumped inside the car.

Therefore the speed of the freight car decreased by applying the law of conservation of momentum i

Which statement describes the density of the inner planets?

All the inner planets are dense.
The inner planets are less dense than the outer planets.
Earth is dense, while the other inner planets are not.
Mercury and Venus are dense, while Earth and Mars are no

Answers

Answer:

The inner planets are less dense than the outer planets

Please brainliest my answer iam begging you for god sake

Answer:

The inner planets are less dense than the outer planets .

Explanation:

Please Mark Me As a brainliest

Wire A X is fold back at p such that /AP/= 40cm and its parallel with px which is 60cm long to form parallel combination. Calculate the effective resistance of the parallel combination if the resistance per unit length of the material of tge wire

Answers

Answer: To find the total resistance of the wires, we need to use a formula that takes into account the length and cross-sectional area of the wires and the resistivity of the material they are made of. By plugging in the appropriate values for the length, cross-sectional area, and resistivity of the wires in the formula, we can find the individual resistances of the wires. Then, by using another formula for the total resistance of a parallel combination, we can find the effective resistance of the wires in parallel.

Explanation:R = ρ * (L / A)

where R is the resistance of the wire, ρ is the material's resistivity (resistance per unit length), L is the length of the wire, and A is the cross-sectional area of the wire.
according to the given data
AP= 40 cm
px=60cm

Next, we need to calculate the wire PX's length and cross-sectional area. The length is given as 60 cm, and we can assume the same diameter of 1 mm, giving a cross-sectional area of 0.785 mm^2.

Now we can calculate the resistance of each wire using the formula above:

R_AX = ρ * (80 cm / 0.785 mm^2) = 101.91 * ρ

R_PX = ρ * (60 cm / 0.785 mm^2) = 76.43 * ρ

The total resistance of the parallel combination is given by the formula:

1/R_total = 1/R_AX + 1/R_PX

Substituting the values of R_AX and R_PX, we get:

1/R_total = 1/(101.91 * ρ) + 1/(76.43 * ρ)

1/R_total = (1.55 / ρ)

R_total = ρ / 1.55

therefore, the effective resistance of the parallel combination is (ρ / 1.55) ohms

A square plate of copper with 50.0-cm sides has no net charge and is placed in a region of a uniform electric field of 80.0 kN/C directed perpendicularly to the plate. Find (a) the charge density of each face of the plate and (b) the total charge on each face.

Answers

Answer:

σ = ±708 nC/m²

Q = ±177 nC

Explanation:

given data

Side of copper plate L = 50 cm

Electric field, E = 80 kN/C

solution

we get here Charge density,σ that is express as

σ = E x ε₀         ....................1

here ε₀ is Permittivity of free space that is 8.85 x 10⁻¹² C²/Nm²

so put value in eq1we get

σ = 80 x 10³ x 8.85 x 10⁻¹²

σ = 708 x 10⁻⁹ C/m²

σ = 708 nC/m²

and

now we get here total change on each faces

Q = σ  A    ...............2

Q = 708 x 10⁻⁹ x (0.50)²

Q = 177 nC

A perpendicular force is applied to a certain area and produces a pressure P. If the
same force is applied to a twice bigger area, the new pressure on the surface is:

Answers

Answer:

p/2

Explanation:

Convert 56,340,040 meters into scientific notation?

Answers

Answer:

5.634004 × 10^7

Explanation:

the number 7 is for the numbers before the number 5

5.6340040 x 10^7 Because the 10^7 represents the ten millions place.

what’s the answer?? middle question

whats the answer?? middle question

Answers

The new volume = 3 x 52.6 that’s because as the pressure decreases by 1/3 the volume increases x3

A measure of the disorder of a system is called

Answers

Answer:

Entropy is typically defined as either the level of randomness (or disorder) of a system or a measure of the energy dispersal of the molecules in the system.

Answer:

entropy

Explanation:

edge2021

nuclear energy is a clean energy source with virtually no greenhouse gas emissions. t or f

Answers

The given statement about “Nuclear energy is a clean energy source with virtually no greenhouse gas emissions.” is true, because Nuclear is a zero-emission clean energy source.

Fission is the process by which atoms of uranium are separated to release energy, and this is how nuclear power plants produce electricity. Electricity is produced without the emission of hazardous pollutants often associated with the combustion of fossil fuels by using the heat released by fission to create steam that turns a turbine. The Nuclear Energy Institute (NEI) estimates that in 2020 the United States will have prevented the release of about 471 million metric tons of carbon dioxide. That's more than all other forms of clean energy put together, and it's the same as taking 100 million cars off the road. In addition to preventing acid rain, pollution, lung cancer, and cardiovascular illness, it also cleans the air by thousands of tons annually.

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Samir is waiting for a slow reaction to finish. What is the best way to make the reaction go faster?

Question 12 options:

Put it in the fridge where it is cold


Cover it with a blanket so it's dark


Warm it up on the stove


There is nothing you can do to change the speed of the reaction

Answers

In general, option c - warming it up on the stove - is often an effective method to increase the reaction rate.

Increasing the temperature of a reaction generally leads to faster reaction rates. This is because higher temperatures provide more thermal energy to the reactant particles, causing them to move faster and collide more frequently. The increased collision frequency and energy lead to more successful collisions and a higher likelihood of effective molecular interactions, which speeds up the reaction. On the other hand, options a and b - putting it in the fridge where it is cold or covering it with a blanket to make it dark - are unlikely to have a significant effect on the reaction rate. While temperature can influence reaction rates, cooling the reaction or making it dark typically reduces the kinetic energy of the particles, resulting in slower reaction rates. Option d - there is nothing you can do to change the speed of the reaction - is not accurate. The reaction rate can be influenced by various factors such as temperature, concentration, catalysts, and surface area, among others. By manipulating these factors, it is often possible to control and change the speed of a reaction. Hence option c, is correct

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please read the question and answer. it is quite complicated so someone clever please reply. many thanks :)​

please read the question and answer. it is quite complicated so someone clever please reply. many thanks

Answers

Answer:

If he's 500 kg and 1 kg = 10 N then it would be 5,000 N

Explanation:

The surface area is unimportant and they'll use it to trick you.

When a 480 Hz. tuning fork and a piano key are struck together, four beats per second are heard. When a 470 Hz. tuning fork and a piano key are struck together, four beats per second are heard. What is the frequency of the piano key? unknown piano key = _____Hz 476 478 477 475

Answers

the frequency of the piano key is 476 Hz.

What is frequency?

Frequency describes the number of waves that pass a fixed place in a given amount of time. In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.

Given, When a 480 Hz. tuning fork and a piano key being struck together, four beats per second are heard.

The frequency of the tuning fork, Nf = 480 Hz

Beats heard at this frequency, x = 4 beats/second

When a 470 Hz. tuning fork and a piano key being struck together, four beats per second are heard.

The equation for the Frequency of the piano,

Np = Nf - x

Np = 480 - 4

Np = 476 Hz

When tension has increased the frequency also increased. As the number of beats decreased, the frequency of the string must be less than 480 Hz.

Therefore, the frequency of the piano key is 476 Hz.

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When practicing reading skills, you should focus on _______.

content recall
comprehension
speed
all of the above

Answers

Answer:

I would say the answer is All the above.

Explanation:

If this wasn't what you were looking for please don't hesitate to comment again! Have a nice day/night! :)

Answer:

all the above

Explanation:

A certain radar installation transmits electromagnetic radiation with a wavelength of 3.5 cm. What is the frequency of this radiation?

Answers

Answer:

The frequency of the radiation = 10GHz

Explanation:

The wavelength of the electromagnetic radiation, λ = 3.5 cm

λ = 3.5/100 m

λ = 0.035 m

The speed of light, c = 3 x 10⁸ m/s

Calculate the frequency (f) of the radiation using the formula:

\(\begin{gathered} f=\frac{c}{\lambda} \\ \\ f=\frac{3\times10^8}{0.035} \\ \\ f=10^{10}Hz \\ \\ f=10\times10^9Hz \\ \\ f=10GHz \end{gathered}\)

The frequency of the radiation = 10GHz

The force exerted by the wind on the sails of a sailboat is Fsail = 330 N north. The water exerts a force of Fkeel = 210 N east. If the boat (including its crew) has a mass of 260 kg, what are the magnitude and direction of its acceleration? magnitude m/s2 direction ° north of east

Answers

Answer:

The magnitude of the acceleration is \(a_r = 1.50 \ m/s^2\)

The direction is  \(\theta = 32.5 6^o\) north of  east

Explanation:

From the question we are told that

   The force exerted by the wind is  \(F_{sail} = (330 ) \ N \ north\)

   The force exerted by water is  \(F_{keel} = (210 ) \ N \ east\)

      The mass of the boat(+ crew) is  \(m_b = 260 \ kg\)

Now Force is mathematically represented as

      \(F = ma\)

Now the acceleration towards the north is mathematically represented as

      \(a_n = \frac{F_{sail}}{m_b}\)

substituting values

       \(a_n = \frac{330 }{260}\)

      \(a_n = 1.269 \ m/s^2\)

Now the acceleration towards the east is mathematically represented as

       \(a_e = \frac{F_{keel}}{m_b }\)

substituting values

      \(a_e = \frac{210}{260}\)

      \(a_e =0.808 \ m/s^2\)

The resultant acceleration is  

      \(a_r = \sqrt{a_e^2 + a_n^2}\)

substituting values

     \(a_r = \sqrt{(0.808)^2 + (1.269)^2}\)

      \(a_r = 1.50 \ m/s^2\)

The direction with reference from the north is evaluated as

Apply SOHCAHTOA

        \(tan \theta = \frac{a_e}{a_n}\)

       \(\theta = tan ^{-1} [\frac{a_e}{a_n } ]\)

substituting values

     \(\theta = tan ^{-1} [\frac{0.808}{1.269 } ]\)

    \(\theta = tan ^{-1} [0.636 ]\)

   \(\theta = 32.5 6^o\)

     

   

       

In a nuclear power plant, a 1.0 kg of water at 58.6 °C is converted into 1.0 kg of steam at 131.8 °C. The total heat (in kcal) supplied by the plant is: Use cwater = 1.00 kcal/(kg.°C), csteam = 0.48 kcal/(kg.°C), and Lv = 540.0 kcal/kg

Answers

The total heat supplied by the plant to convert the water to steam is 596.7 kcal.

What is heat capacity?

Heat capacity is the quantity of heat required to raise the temperature of entire mass of a substance.

Q = Heat supplied to the water to the boiling point + Heat supplied to vaporize the water.

Q = mc₁Δθ + mc₂Δθ + mLv

where;

m is the mass of the waterc₁ is specific heat capacity of waterc₂ is specific heat capacity of steamΔθ is change in temperatureLv is latent heat of vaporization

Substitute the given parameters and solve for the heat supplied in the process.

Q = (1)(1)(100 - 58.6) + (1)(0.48)(131.8 - 100)  + 540(1)

Q = 41.4 + 15.264 + 540

Q = 596.7 kcal

Thus, the total heat supplied by the plant to convert the water to steam is 596.7 kcal.

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15. A vessel containing a liquid 'L' is balanced by a solid 'S' as shown below. Now, two identical pieces of cork (which float on the liquid) are placed gently, one on the solid and one in the liquid. What will happen to the balance?

Answers

Answer:

  C)  There will be no change in the balance

Explanation:

Before and after the cork is placed, the masses in each pan are the same. There will be no change in the balance.

A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the mass has a velocity of 6 ft/sec. Suppose the object is displaced an additional 6 inches and released.

Required:
a. Find an equation for the object's displacement, u(t), in feet after t seconds.
b. What is the mass of the object?
c. What is the damping coefficient?
d. What is the spring constant?

Answers

Answer:

a)

\(u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)\)

b)

m = 48lb

c)

b = 144.76lb

Explanation:

The general equation of a damping oscillate motion is given by:

\(u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)\)    (1)

uo: initial position

m: mass of the block

b: damping coefficient

w: angular frequency

α: initial phase

a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:

\(|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s\)

Then, you obtain by replacing in (1):

6in = 0.499 ft

\(u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)\)

b.

mass, m = 48lb

c.

b = 144.76 lb/s

Lamont and Lydi are siblings that went to a healer to help with some physical aches and pains from playing sports.
Lamont and Lydi were given a 25-question survey to describe their physical, emotional, and mental states. Their auras were the read by the healer to see if their colors matched their survey responses.
The healer determined that while Lamont was showing blue and green colors, Lydi was displaying browns and grays. The healer determined that Lamont was in good physical shape, but Lydi needed to do some specific mental and physical exercises to help with her problems.
Lamont had read the study by University of Grenada and said that this information had to be valid because a scientific study was done on it. Lydi was not as convinced.

Do you agree with Lamont? explain why and determine if the healers knowledge is based on science or pseudoscience. Give Atleast 2 examples to support your claim.
Be sure to use at least two of the six criteria for scientific claims in your examples.

Please help

Answers

The claims of the healers are merely pseudoscience because we can not be able to back it empirically or reproduce the results.

What is science?

In order to answer the question that is before us, we would have to look closely at the idea of science. We know that science depends on empiricism. This implies that we must be able to have verifiable and reproducible evidences for whatever proposition that is to be made in the field of science. This is a key fact that we must have in mind.

On the other hand, pseudoscience only depends on subjective views and principles that could be determined by individuals and is not independently verifiable by means of controlled experiments.

As such, the ideas of the healers are based on pseudo science because as we said, real science must be reproducible and the claims of the results independently verifiable but the results that is obtained by the healers dos not meet any of these criteria.

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Vector Q is 0.321 m long in a
123° direction. Vector S is
0.876 m long in a -32.1°
direction.
Find the direction of their
vector sum.
direction (deg)

Vector Q is 0.321 m long in a123 direction. Vector S is0.876 m long in a -32.1direction.Find the direction

Answers

Answer:

-19.09°.

Due to several approximations been applied in the detailed process, the angle given on image 2 (-18.17°) is slight minor compared to what can be obtained through direct calculations (-19.09°).

Check images below.

Note: If you want to calculate the length of the new vector, just need to apply the pythagorean theorem and taking the components of the result vector as if they were the 2 sides of a right triangle.

Vector Q is 0.321 m long in a123 direction. Vector S is0.876 m long in a -32.1direction.Find the direction
Vector Q is 0.321 m long in a123 direction. Vector S is0.876 m long in a -32.1direction.Find the direction
Vector Q is 0.321 m long in a123 direction. Vector S is0.876 m long in a -32.1direction.Find the direction

A circular ice rink is 20 m in diameter and is to be temporarily enclosed in a hemispherical dome of the same diameter. The ice is maintained at 270 K. On a particular day the inner surface of the dome is measured to be 290 K. Estimate the radiant heat transfer from the dome to the rink if both surfaces can be taken as blackbody.

Answers

570k or 1050k

270k+290k= 570k

270k•290k = 1050k

An environmentally conscious physics student 250 N
mows her lawn with a push mower, exerting
a force of 250 N along the handle as shown. 40°
How much force is actually being used to push
the mower along the grou

Answers

The force actually being used to push the mower along the ground is 191 N.

When the physics student exerts a force of 250 N along the handle of the push mower, it's important to consider the components of this force that contribute to the actual force used to push the mower along the ground.

To determine the force used to push the mower along the ground, we need to find the horizontal component of the applied force. The angle of 40° indicates that the applied force can be broken down into two components: the horizontal component and the vertical component. The vertical component of the force is perpendicular to the direction of motion and does not contribute to pushing the mower forward.

To find the horizontal component, we can use trigonometry. The horizontal component is given by the formula:

Horizontal component = Applied force * cos(angle)

Plugging in the values, we get:

Horizontal component = 250 N * cos(40°)

Calculating this value, we find that the horizontal component of the applied force is approximately 191 N.

Therefore, the force actually being used to push the mower along the ground is 191 N. This is the component of the applied force that contributes to the forward motion of the mower, while the remaining vertical component is directed perpendicular to the ground and does not assist in pushing the mower forward.

By exerting a force of 250 N along the handle at a 40° angle, the student effectively applies 191 N of force to push the mower along the ground, ensuring efficient use of their effort while considering the environmental impact.

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Quick Check:
12-17-20
Conservation of Energy
In the use of an energy resource like coal, do you get all
the energy back in one form(100%)? (circle one)
Yes
No

Answers

Answer:

Quick Check:

12-17-20

Conservation of Energy

In the use of an energy resource like coal, do you get all

the energy back in one form(100%)? (circle one)

Yes

No

Explanation:

Not sure

How far does a roller coaster travel if it accelerates at 2.83 m/s2 from an initial
velocity of 3.19 m/s for 12.0 s?

Answers

Answer:

b

Explanation:

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