SOMEONE HELP ASAP: Match the definitions

The temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

Using the ideal gas law, we can write: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. Since the mass of air is not changing, we can write: PV = constant.

Applying this to the situation where the air mass rises to a level where the pressure is 8.70×10⁴ Pa, we get:

Dividing the second equation by the first and using the fact that γ=Cp/Cv=1.40 for air, we get:

Solving for T2, we get:

Thus, the temperature of the air mass when it has risen to a level at which atmospheric pressure is only 8.70×10⁴ Pa is approximately 14.3°C.

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Answer:

Vf = 69.61 m/s

Explanation:

We will use the third equation of motion to solve this problem:

\(2gh = V_{f}^2 - V_{i}^2\\\)

where,

g = acceleration due to gravity = 9.81 m/s²

h = height of cliff = 247 m

Vf = final velocity = ?

Vi = initial velocity = 0 m/s (boulder breaks loose from rest)

Therefore,

\((2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\\)

Vf = 69.61 m/s

+500   because North is postiive direction

-300 because if you see it as a graph, left side is negative

-800 because South is downward

500-300-800 = -600

displacement is a vector, meaning it has both DIRECTION and magnitude

(literally the only physics problem i can easily solve lol)

Answer:

\(\mid D \mid = 424.26\ m\)

Explanation:

Displacement

Suppose a moving object starts from point A and travels through a determined path to point B. The distance is the sum of all the partial distances traveled, and the displacement is the vector directed from A to B.

The path of the person is shown in the image below. Note the 500 m due north and the 800 m due south produce a distance of 300 m due south. The displacement vector D is the resultant of the whole movement.

To find the magnitude of the displacement, we need to calculate the hypotenuse of a triangle of sides 300 m (already described) and 300 m, marked in red.

The magnitude of D is:

\(\mid D \mid = \sqrt{300^2+300^2}\)

\(\mid D \mid = \sqrt{90000+90000}\)

\(\mid D \mid = \sqrt{180000}\)

\(\mid D \mid = 424.26\ m\)

1) describe the life cycle of a star before it collapses into a black hole.

1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.

2) describe the life cycle of a star before it becomes a dwarf.

ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.

3) what is the likely outcome of our sun?

ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.

equal in magnitude but opposite in direction

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

A. The English system uses one unit for each category of measurement.

Answer:

A

Explanation:

Answer:

 y = 1.19 m  and λ = 8.6036 10⁻⁷ m

Explanation:

This is a slit interference problem, the expression for destructive interference is

          d sin θ = m λ

indicate that for the angle of θ = 35º it is in the third order m = 3 and the separation of the slits is d = 4.50 10⁻⁶ m

          λ = d sin  θ / m

let's calculate

          λ = 4.50 10⁻⁶ sin 35  /3

          λ = 8.6036 10⁻⁷ m

for the separation distance from the central stripe, we use trigonometry

         tan θ= y / L

         y = L tan θ

the distance L is measured from the slits, it indicates that the light source is at x = 0.30 m from the slits

         L = 2 -0.30

         L = 1.70 m

let's calculate

        y = 1.70 tan 35

        y = 1.19 m

The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.

What is Potential Energy?

Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.

The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:

GPE = mgh

Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.

Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:

GPE = mgh

GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)

GPE = 15,998.95 J (joules)

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

You got it right, didn't you?

c) vector C

Explanation:

opposite to vector V

Answer:

A, vector B

Explanation:

A negative vector is a vector which points in the opposite direction, even though it’s in a different quadranot it’s still the opposite direction.

Answer:

ΔQ = 0.1 kJ

\(\mathbf{v_f = 1.445*10^{-3} m^3}\)

\(\mathbf{P_f = 156.5 \ kPa}\)

ΔS = -0.337 J/K

The value negative is due to the fact that there is need to be the same amount of positive change in surrounding as a result of compression.

Explanation:

GIven that:

Diameter of the piston-cylinder = 12 cm

Pressure of the piston-cylinder = 100 kPa

Temperature =24 °C

Length of the piston = 20 cm

Boundary work ΔW = 0.1 kJ

The gas is compressed and The temperature of the gas remains constant during this process.

We are to find ;

a. How much heat was transferred to/from the gas?

According to the first law of thermodynamics ;

ΔQ = ΔU + ΔW

Given that the temperature of the gas remains constant during this process; the isothermal process at this condition ΔU = 0.

Now

ΔQ = ΔU + ΔW

ΔQ = 0 + 0.1 kJ

ΔQ = 0.1 kJ

Thus; the amount of heat that was transferred to/from the gas is : 0.1 kJ

b. What is the final volume and pressure in the cylinder?

In an isothermal process;

Workdone W = \(\int dW\)

\(W = \int pdV \\ \\ \\W = \int \dfrac{nRT}{V}dv \\ \\ \\ W = nRt \int \dfrac{dv}{V} \\ \\ \\ W = nRT In V |^{V_f} __{V_i}} \\ \\ \\ W = nRT \ In \dfrac{V_f}{V_i}\)

Since the gas is compressed ; then \(v_f< v_i\)

However;

\(W =- nRT \ In \dfrac{V_f}{V_i}\)

\(W =- P_1V_1 \ In \dfrac{V_f}{V_i}\)

The initial volume for the cylinder is calculated as ;

\(v_1 = \pi r^2 h \\ \\ v_1 = \pi r^2 L \\ \\ v_1 = 3.14*(6*10^{-2})^2*(20*10^{-2}) \\ \\ v_1 = 2.261*10^{-3} \ m^3\)

Replacing over values into the above equation; we have :

\(100 = - ( 100*10^3 *2.261*10^{_3}) In (\dfrac{v_f}{v_i}) \\ \\ - In (\dfrac{v_f}{v_i})= \dfrac{100}{(100*10^3*2.261*10^{-3})} \\ \\ - In \ v_f + In \ v_i = \dfrac{100}{226.1} \\ \\ - In \ v_f = - In \ v_i + \dfrac{100}{226.1} \\ \\ - In \ v_f = - In (2.261*10^{-3} + \dfrac{100}{226.1 } \\ \\ - In \ v_f = 6.1 + 0.44 \\ \\ - In \ v_f = 6.54 \\ \\ - In \ v_f = -6.54 \\ \\ v_f = e^{-6.54} \\ \\ \mathbf{v_f = 1.445*10^{-3} m^3}\)

The final pressure can be calculated by using :

\(P_1V_1 = P_2V_2 \\ \\ P_iV_i = P_fV_f\)

\(P_f =\dfrac{P_iV_i}{V_f}\)

\(P_f =\dfrac{100*2.261*10^{-3}}{1.445*10^{-3}}\)

\(P_f = 1.565*10^2 \ kPa\)

\(\mathbf{P_f = 156.5 \ kPa}\)

c. Find the change in entropy of the gas. Why is this value negative if entropy always increases in actual processes?

The change in entropy of the gas is given  by the formula:

\(\Delta S=\dfrac{\Delta Q}{T}\)

where

T =  24 °C = (24+273)K

T = 297 K

\(\Delta S=\dfrac{-100 \ J}{297 \ K}\)

ΔS = -0.337 J/K

The value negative is due to the fact that there is need to be the same amount of positive change in surrounding as a result of compression.

Answer:

r =\(\frac{ 1 \pm \sqrt{ \frac{m}{M} } }{1 - \frac{m}{M} }\)

Explanation:

Let's apply the universal gravitation law to the body (c), we use the indications 1 for the planet and 2 for the moon

          ∑ F = 0

           -F_{1c} + F_{2c} = 0

             F_{1c} = F_{2c}

let's write the force equations

             \(G \frac{m_c M}{r^2} = G \frac{m_c m}{(d-r)^2}\)

where d is the distance between the planet and the moon.

              \(\frac{M}{r^2} = \frac{m}{(d-r)^2}\)

             (d-r)² = \(\frac{m}{M} \ \ r^2\)  

              d² - 2rd + r² = \frac{m}{M} \ \ r^2

              d² - 2rd + r² (1 - \(\frac{m}{M}\)) = 0

              (1 - \(\frac{m}{M}\))  r² - 2d r + d² = 0

we solve the second degree equation

              r = [2d ± \(\sqrt{ 4d^2 - 4 ( 1 - \frac{m}{M} ) }\) ] / 2 (1- \(\frac{m}{M}\))

              r = [2d ±  2d \(\sqrt{ \frac{m}{M} }\)] / 2d (1- \(\frac{m}{M}\))

              r =\(\frac{ 1 \pm \sqrt{ \frac{m}{M} } }{1 - \frac{m}{M} }\)

there are two points for which the gravitational force is zero

The distance between object from planet will be "\(\frac{R}{[1+\sqrt{\frac{m}{M} } ]}\)".

According to the question,

Let,

As we know,

→ \(Prerequisites-Gravitational \ force = \frac{GMm}{r^2}\)

Now,

→ \(\frac{GMm_1}{x^2} = \frac{Gmm_1}{(R-x)^2}\)

→ \(\frac{(R-x)^2}{x^2} = \frac{m}{M}\)

→     \(\frac{R-x}{x} =\sqrt{\frac{m}{M} }\)

→          \(x = \frac{R}{[1+ \sqrt{\frac{m}{M} } ]}\)

Thus the answer above is appropriate.          

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No, it is not possible to produce a nuclear reactor at home in a safe and legal way.

Nuclear reactors are complex and highly regulated pieces of technology that require specialized knowledge and equipment to build and operate safely. Furthermore, attempting to build a nuclear reactor at home is not only dangerous, but also illegal in most countries. Unauthorized possession and operation of nuclear materials and equipment can result in serious legal consequences, including fines and imprisonment. It is not possible to produce a nuclear reactor at home in a safe and legal way. It is important to prioritize safety and follow legal regulations when it comes to handling nuclear materials and technology.

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Answer:

180 LUV:)

Explanation:

Answer:

c heats up cancer cells and weakens them.

Answer:

I think it is C

Explanation:

because

Answer:

a. If the frequency of light is increased above the threshold frequency, the energy of the electrons emitted will increase.

b. If the frequency of light is decreased to below the threshold frequency, the rate at which electrons are emitted will decrease.

c. If the intensity of light is decreased, the energy of the electrons emitted will remain the same, but fewer electrons will be emitted.

d. If the intensity of light is decreased, the rate at which electrons are emitted will decrease.

Answer:

It is not a me mental shortcut

Explanation:

Can be changed easily

It is not uncommon for us to hold stereotypes toward people. The main advantage of forming a stereotype is that they make fast and quick decision. The main disadvantage is that they make generalized decision.

A stereotype is a persistent, vastly oversimplified view about a particular group or category possesses. A stereotype person make his own belief for the peoples.

A stereotype has the advantage of allowing us to respond quickly to events, since we may have had a similar experience before.

One negative is that it causes us to overlook individual distinctions, leading us to believe things about others that are not always true.

It is not uncommon for us to hold stereotypes toward people. The main advantage of forming a stereotype is that they make fast and quick decision. The main disadvantage is that they make generalized decision

The correct option for the blanks are make fast and quick decision and generalized decision.

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The activation energy for the diffusion process of Al in Al2O3 is approximately 225,744 J/mol.

To calculate the activation energy for the diffusion process of Al in Al2O3, we can use the Arrhenius equation:

D = D0 * exp(-Q/RT)

where D is the diffusion coefficient, D0 is a constant, Q is the activation energy, R is the gas constant, and T is the absolute temperature.

Taking the natural logarithm of both sides, we get:

ln(D/D0) = -Q/RT

We can then use the given diffusion coefficients and temperatures to obtain two equations:

ln(D1/D0) = -Q/RT1

ln(D2/D0) = -Q/RT2

where D1 and T1 are the diffusion coefficient and temperature at 1000C, and D2 and T2 are the diffusion coefficient and temperature at 1500C.

Taking the ratio of the two equations, we get:

ln(D2/D1) = Q/R * (1/T1 - 1/T2)

Solving for Q, we get:

Q = -R * ln(D2/D1) / (1/T1 - 1/T2)

Plugging in the given values, we get:

Q = -8.314 J/mol-K * ln(2.48 x 10^-14 m^2/s / 7.48 x 10^-23 m^2/s) / (1/1273 K - 1/1773 K)

Q ≈ 225,744 J/mol

Therefore, the activation energy for the diffusion process of Al in Al2O3 is approximately 225,744 J/mol.

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Answer:

yor welcome

Explanation:

hi

To calculate the resultant force on the aircraft as it accelerates from the catapult, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.

Since all of the kinetic energy at take-off is from the work done on the aircraft by the catapult, we can equate the work done by the catapult to the kinetic energy of the aircraft at take-off, that is:

Work done by catapult = kinetic energy of aircraft at take-off

The work done by the catapult is given by the force provided by the catapult multiplied by the distance over which it acts, that is:

Work done by catapult = force × distance

The distance over which the force provided by the catapult acts is given as 150 m, so we have:

Work done by catapult = force × 150

The kinetic energy of the aircraft at take-off is given by:

(1/2) × mass × velocity^2

Since the aircraft is initially at rest, its initial velocity is zero, so we have:

kinetic energy of aircraft at take-off = 0.5 × mass × (final velocity)^2

Using the work-energy principle, we can equate the two expressions for work done and kinetic energy, that is:

force × 150 = 0.5 × mass × (final velocity)^2

Solving for force, we get:

force = 0.5 × mass × (final velocity)^2 / 150

Therefore, the resultant force on the aircraft as it accelerates is given by:

force = 0.5 × mass × (final velocity)^2 / 150

Note that we need to know the mass and final velocity of the aircraft in order to calculate the resultant force.

Answer:

C. Gas

Explanation:

Segment CD represents gaseous phase of matter as segment CD shows highest energy which is in case of gas.

Matter in chemistry, is defined as any kind of substance that has mass and occupies space that means it has volume .Matter is composed up of atoms which may or not be of same type.

Atoms are further made up of sub atomic particles which are the protons ,neutrons and the electrons .The matter can exist in various states such as solids, liquids and gases depending on the conditions of temperature and pressure.

The states of matter are inter convertible into each other by changing the parameters of temperature and pressure.The intermolecular forces of attraction are different in different states of matter.Particles of matter have different sizes.

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The distance that is covered is 150 m

The displacement is 50 m.

We have to know that the displacement has to do with the distance that is covered in a  specific direction. We have to take note of the direction that we have there as that is what does make the difference between the distance and the displacement.

The distance does not involve the direction. It can then be safe to say that displacement is a vector and that distance is a scalar. Once again let us recall that these are so because the distance does not take cognizance of the direction while the displacement would always take cognizance of the direction of the motion.

Then we have;

Distance = 50 m + 50 m + 50 m = 150 m

For displacement calculation;

Moving towards the opposite side and back = 50 m - 50 m = 0 m

Moving again to the opposite side;

Displacement = + 50 m

Note that the backward motion of the swimmer would be taken as negative.

Therefore total displacement = 50 m

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.

Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.

What exactly does the Law of Gravitation apply to  According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.

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When mass grows and distance contracts, gravity increases. Additionally, as distance and mass decrease, gravity also reduces.

Manning's universal law of gravity asserts that every atom in the cosmos pulls more or less every particle with a pressure along a connecting line, to put it in modern terms. The force is equal to the ratio of the wavelength between them and found to be proportional to the combination of their masses.

What exactly does the Law of Gravitation apply to  According to Newton's theory of Universal Gravitation, every particle in the cosmos is drawn to every other particle with a force that is equal to the product of their masses and inversely to their distance from one another.

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Answer:

8.45 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 90 Kg

Initial velocity (u) = 13 m/s

Final velocity (v) = 0 m/s

Height (h) =?

NOTE: Acceleration due to gravity (g) = 10 m/s²

The height of the hill can be obtained as follow:

v² = u² – 2gh (since the cart is going against gravity)

0² = 13² – (2 × 10 × h)

0 = 169 – 20h

Rearrange

20h = 169

Divide both side by 20

h = 169/20

h = 8.45 m

Therefore, the height of the hill is 8.45 m

The position of point C from point A  is determined as 96.4 m east.

The distance travelled by cyclist from point B to point C is calculated by applying the following kinematic equation as shown below;

d = vt

where;

Substitute the given parameters and solve for the distance travelled by the cyclist from point B to point C.

d = 18 m/s  x  2.8 s

d = 50.4 m

The position of point C is calculated by adding the distance travelled by the cyclist from point B to point C;

position of point C = 50.4 m + 46 m = 96.4 m

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