Solve the problem.
The total cost in dollars for a certain company to produce x empty jars to be used by a jelly
producer is given by the function C(x)=0.8x + 40,000. Find C(50,000), the cost of producing 50,000
jars.
A) $40.80
B) $80,000 C)$50,040
D) $40,000

To calculate the average speed of the horse in miles per hour, holding the all-time record for running a 2-kilometer race in 1 min and 59.4 sec, we do the necessary conversions over distance from kilometers to miles and over time from minutes and seconds to hours.

The average speed thus calculated is 393.2722 miles per hour.

The average speed of any object is the ratio of the total distance the object travels, and the total time taken by the object to cover that distance.

Thus, Average speed = Total Distance/Time taken.

In the question, we are informed that a horse holds the all-time record for running a 2-kilometer race in 1 min and 59.4 sec.

We are asked for the necessary conversions required to calculate the average speed of the horse for the race in miles per hour.

The necessary conversions that will be required will be:

Distance: 2 kilometers to miles.

Time: 1 minute 59.4 secs to hours.

To convert from kilometers to miles, we follow the conversion rate:

1 kilometer = 0.621371 miles.

Thus, distance = 2 kilometers = 2 * 0.621371 miles = 1.24274 miles.

For the time, we first convert seconds to time, using the conversion rate:

1 second = 1/60 minutes,

Therefore, 59.4 seconds = 59.4/60 minutes = 0.99 minutes.

Thus, the total time = 1.99 minutes.

To convert from minutes to hours, we follow the conversion rate:

1 minutes= 1/60 hours.

Thus, time = 1.99 minutes = 1.99/60 hours = 0.03316 hours.

Thus, the average speed of the horse = Distance/Time = 1.24274/0.003316 miles per hour = 393.2722 miles per hour.

Thus, to calculate the average speed of the horse in miles per hour, holding the all-time record for running a 2-kilometer race in 1 min and 59.4 sec, we do the necessary conversions over distance from kilometers to miles and over time from minutes and seconds to hours.

The average speed thus calculated is 393.2722 miles per hour.

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Answer:

if y is the normal number of sweets then the normal number plus 40 percentage equals 42

y+4y=42

1.4y=42

y=42/1.4=30

hope this helps!

please mark me as the brainiest answer and please follow me for more answers.

Answer:

area = 10.28 units²

Step-by-step explanation:

Smallest prime numbers I can think of is 2, 3 & 5 but that will not make a triangle.

3, 5, & 7 will

area = 1/2(7)(2.9375) = 10.28 units²

Answer:

resistant

because the median is not affected by the size of an outlier and does not change even if a particular outlier is replaced by an even more extreme value, we say the median is resistant to outliers.

The grid-based method first quantizes the object space into a finite number of cells that form a grid structure and then performs clustering on the grid structure.

The grid-based methods are used in data mining and are based on a multi-resolution grid data structure. In the grid-based methods the space of instance is divided into a grid structure. Following the division, clustering techniques are employed using the cells of the grid as the base units instead of individual data points. The great advantage of grid-based clustering technique is its significant reduction of the computational complexity, especially for clustering very large data sets and improving the processing time.

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The original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

To show that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves, we need to take the derivative of the equation and set it equal to -1/b^2, the slope of the orthogonal line.

First, we take the derivative of the equation with respect to x:

2x/a^2 = -2y/b^2 * dy/dx

Simplifying, we get:

dy/dx = -b^2*x/a^2*y

Now, we set this equal to -1/b^2:

-b^2*x/a^2*y = -1/b^2

Cross-multiplying and simplifying, we get:

x/a^2*y = 1/b^2

Finally, we can rearrange this equation to get:

y = b^2*x/a^2

This equation represents the orthogonal family of curves to the original family of conics. Since the original equation and the orthogonal equation are the same, we can conclude that the family of conics with the same focus x^2/a^2+C + y^2/b^2+C = 1 is its own orthogonal family of curves.

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The least number of seats the manger could order to 270 seats

The information that the the seats are sold only in groups of 10 will help to know that the order will be in a multiple of 10.

The manager wants to order 267 seats and this is not a multiple of 10 the nearest multiple of 10 is 270.

This is because, 260 will be short of want the manager want however ordering for 270 will be in excess with three seats.

Hence the manager will order 270 and heave 3 extra seats

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The binary relation s on the set of ordered pairs of integers, defined as (a, b)s(c, d) ↔ a d = b c, is not an equivalence relation because it fails to satisfy all three properties of reflexivity, symmetry, and transitivity.

To determine if the relation s is an equivalence relation, we need to check if it satisfies the properties of reflexivity, symmetry, and transitivity.

1. Reflexivity: For any pair (a, b), we should have (a, b)s(a, b). However, this is not always true for the given relation. If we substitute (a, b) into the definition, we get a b = b a, which is not always satisfied. Therefore, the relation is not reflexive.

2. Symmetry: For any pairs (a, b) and (c, d), if (a, b)s(c, d), then (c, d)s(a, b) should also hold. However, this is not true for all pairs. If we substitute (a, b) and (c, d) into the definition, we get a d = b c, but swapping the variables results in c b = d a, which is not always satisfied. Thus, the relation is not symmetric.

3. Transitivity: For any three pairs (a, b), (c, d), and (e, f), if (a, b)s(c, d) and (c, d)s(e, f), then (a, b)s(e, f) should hold. However, this property also fails for the given relation. If we substitute the pairs into the definition, we get a d = b c and c f = d e, but combining these equations does not necessarily yield a f = b e. Therefore, the relation is not transitive.

Since the relation s fails to satisfy all three properties, it is not an equivalence relation.

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Answer to this question is 3001pi

Answer:

all 3 options are true : A, B, C

Step-by-step explanation:

warning : it has come to my attention that some testing systems have an incorrect answer stored as right answer for this problem.

they say that A and C are correct.

but I am going to show you that if A and C are correct, then also B must be correct.

therefore, my given answer above is the actual correct answer (no matter what the test systems say).

originally the information about the alignment of the point F in relation to point E was missing.

therefore, I considered both options :

1. F is on the same vertical line as E.

2. F is not on the same vertical line as E.

because of optical reasons (and the - incomplete - expected correct answers of A and C confirm that) I used the 1. assumption for the provided answer :

the vertical line of EF is like a mirror between the left and the right half of the picture.

A is mirrored across the vertical line resulting in B. and vice versa.

the same for C and D.

this leads to the effect that all 3 given congruence relationships are true.

if we consider assumption 2, none of the 3 answer options could be true.

but if the assumptions are true, then all 3 options have to be true.

now, for the "why" :

remember what congruence means :

both shapes, after turning and rotating, can be laid on top of each other, and nothing "sticks out", they are covering each other perfectly.

for that to be possible, both shapes must have the same basic structure (like number of sides and vertices), both shapes must have the same side lengths and also equally sized angles.

so, when EF is a mirror, then each side is an exact copy of the other, just left/right being turned.

therefore, yes absolutely, CAD is congruent with CBD. and ACB is congruent to ADB.

but do you notice something ?

both mentioned triangles on the left side contain the side AC, and both triangles in the right side contain the side BD.

now, if the triangles are congruent, that means that each of the 3 sides must have an equally long corresponding side in the other triangle.

therefore, AC must be equal to BD.

and that means that AC is congruent to BD.

because lines have no other congruent criteria - only the lengths must be identical.

Answer:

(y+2)•(y-6)

Step-by-step explanation:

y(y-6)+2(y-6)

y^2-6y+2y-12

y^2-4y-12

Answer:

The line's slope equals the difference between points' y-coordinates divided by the difference between their x-coordinates. Select any two points on the line of best fit. These points may or may not be actual scatter points on the graph. Subtract the first point's y-coordinate from the second point's y-coordinate.

The statement that m∠C = 130°-m∠B is the correct statement for the triangle ABC whose measure of angle A is 50 degrees.

Given, a triangle ABC in which angle A is 50 degrees and we have to conclude the statement or results that holds true for the measure of angle C. Let's proceed in order to solve the question.

We know that, by angle sum property of triangle the sum of angles of triangle is 180°.

⇒m∠A+m∠B+m∠C = 180°

⇒50°+m∠B+m∠C = 180°

⇒m∠B+m∠C = 180°-50°

⇒m∠B+m∠C = 130°

⇒m∠C = 130°-m∠B

Therefore, the measure of angle C is equal to 130°-m∠B.

Hence, m∠C = 130°-m∠B is the correct statement that can be concluded for a triangle ABC, in which the measure of angle A is 50 degrees.

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The 18th term of the arithmetic sequence is 45.2, while the balance in an account with a $8,600 deposit and 12% annual interest after 5 years is $14,311.39. With a $6,284 deposit and 14% annual interest after 30 months, the account balance will be $7,463.17. Borrowing $1,709 at a 182% annual interest rate, the monthly payment for 16 months will be $202.06.

1. Arithmetic sequence: The formula to find the nth term of an arithmetic sequence is given by:

nth term = first term + (n - 1) * common difference

Here, the 4th term is given as 6 and the common difference is 2.9.   Plugging in these values, we can calculate the 18th term as follows:

18th term = 6 + (18 - 1) * 2.9 = 6 + 17 * 2.9 = 45.2

2. Compound interest: For the first scenario, where $8,600 is deposited into an account that pays 12% simple annual interest compounded monthly for 5 years, we can calculate the final balance using the formula for compound interest:

A = P * \((1 + r/n)^{(n*t) }\)

Here, P is the principal amount, r is the annual interest rate (in decimal form), n is the number of times interest is compounded per year, and t is the number of years. Plugging in the values:

P = $8,600, r = 12% = 0.12, n = 12 (monthly compounding), t = 5

A = 8600 * \((1 + 0.12/12)^{(12*5)}\)= $14,311.39

3. Similarly, for the second scenario, where $6,284 is deposited into an account that pays 14% simple annual interest compounded monthly for 30 months:

P = $6,284, r = 14% = 0.14, n = 12 (monthly compounding), t = 30/12 = 2.5

A = 6284 * \((1 + 0.14/12)^{(12*2.5)}\) = $7,463.17

4. Monthly payment: To calculate the monthly payment amount for borrowing $1,709 from The Saver at a 182% simple annual interest rate, we can divide the total amount by the number of payments. The formula for calculating the monthly payment for a loan is:

Monthly payment = Total amount / Number of payments

Here, the total amount is $1,709 and the number of payments is 16. Plugging in the values:

Monthly payment = 1709 / 16 = $202.06

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Answer:

25.3m³

Step-by-step explanation:

Answer:

1. area
2. multiply
3. 2
4. circumference
5. multiply
6. height
7. add

Step-by-step explanation:

The formula for surface area of a cylinder is 2πrh + 2π\(r^{2}\), which consists of the formula for curved surface area, 2πrh, and 2 bases for the top and bottom of the cylinder, which is the formula 2π\(r^{2}\).

Answer:

a. The result is always an integer because integers are not fractions or decimals.

b. Sorry I don't have an answer for b i don;t know what that means. :(

\(( {x}^{2} + 6x + 8)( {x}^{2} + 6x + 13) =0 \\ \)

_________________________________

\( {x}^{2} + 6x + 8 = 0 \)

\((x + 2)(x + 4) = 0\)

##############################

\(x + 2 = 0\)

\(x = - 2\)

##############################

\(x + 4 = 0\)

\(x = - 4\)

_________________________________

\( {x}^{2} + 6x + 13 = 0 \)

\(∆ = {b}^{2} - 4ac \)

\(a = coefficient \: \: of \: \: {x}^{2} = 1 \)

\(b = coefficient \: \: of \: \: x = 6\)

\(c = the \: \: alone \: \: number \: = 13 \\ \)

Thus ;

\(∆ = ({6})^{2} - 4 \times (2) \times (13) \)

\(∆ = 36 - 104\)

\(∆ = - 68\)

=======================================

Point :

Remember from now on ,

In quadratic functions ;

if :

\(∆ > 0\)

The function has two roots

if :

\(∆ = 0\)

The function has just one root

if :

\(∆ < 0\)

The function doesn't have any root.

=======================================

Thus , ( x² + 6x + 13 ) doesn't have any root.

So ; ( x = - 2 ) & ( x = - 4 ) are the only roots.

_________________________________

And we're done....♥️♥️♥️♥️♥️

Answer:

c)-2,-4,-3+2i,-3-2i

Step-by-step explanation:

edge2020

29.13 square units is the area of the composite figure.

The given composite figure is a triangle and a semicircle. Then formula for the area is expressed as:

A= area of triangle + area of semicircle

Area of triangle = 0.5(5)(6)
Area of triangle = 15 square units

Area of semicircle = πr²/2

Area of semicircle = 3.14(3)²/2

Area of semicircle = 14.13 square units

Area of the shape = 15 square units + 14.13 square units

Area of the shape = 29.13 square units

Hence the given area of the figure is  29.13 square units

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Main Answer:The equations :xcosx - 2x^2 + 3x - 1 = 0 on [1.2, 1.3]

x - (lnx)^x = 0 over [4, 5] have at least one solution on the given interval.

Supporting Question and Answer:

What is the Intermediate Value Theorem?

The Intermediate Value Theorem states that if a function is continuous on a closed interval and takes on values of opposite signs at the endpoints of the interval, then it must have at least one root (or solution) within that interval.

Body of the Solution:To show that the equations have at least one solution on the given intervals, we can use the Intermediate Value Theorem. According to the theorem, if a function is continuous on a closed interval and takes on values of opposite signs at the endpoints of the interval, then it must have at least one root within that interval.

Let's analyze each equation separately:

xcosx - 2x^2 + 3x - 1 = 0 on [1.2, 1.3]

To apply the Intermediate Value Theorem, we need to show that the function is continuous on the interval and takes on values of opposite signs at the endpoints.

First, let's check the continuity of the function. Both xcosx and -2x^2 + 3x - 1 are continuous functions on their respective domains. Thus, their sum, xcosx - 2x^2 + 3x - 1, is also continuous on the interval [1.2, 1.3].

Next, we evaluate the function at the endpoints:

f(1.2) = (1.2)cos(1.2) - 2(1.2)^2 + 3(1.2) - 1

≈ 0.0317

f(1.3) = (1.3)cos(1.3) - 2(1.3)^2 + 3(1.3) - 1

≈ -0.0735

Since f(1.2) is positive and f(1.3) is negative, the function changes sign within the interval [1.2, 1.3]. Therefore, by the Intermediate Value Theorem, the equation xcosx - 2x^2 + 3x - 1 = 0 has at least one solution within the interval [1.2, 1.3].

x - (lnx)^x = 0 over [4, 5]

Again, we need to verify the continuity of the function and the sign change at the endpoints.

The function x - (lnx)^x is continuous on the interval [4, 5], as both x and lnx are continuous functions on their respective domains.

Evaluating the function at the endpoints:

f(4) = 4 - (ln4)^4

≈ -3.9616

f(5) = 5 - (ln5)^5

≈ 3.0342

Since f(4) is negative and f(5) is positive, the function changes sign within the interval [4, 5]. By the Intermediate Value Theorem, the equation x - (lnx)^x = 0 has at least one solution within the interval [4, 5].

Final Answer:In both cases, we have shown that the equations have at least one solution within the given intervals using the Intermediate Value Theorem.

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The equations :xcosx - 2x²  + 3x - 1 = 0 on [1.2, 1.3]

x - (lnx)^x = 0 over [4, 5] have at least one solution on the given interval.

The Intermediate Value Theorem states that if a function is continuous on a closed interval and takes on values of opposite signs at the endpoints of the interval, then it must have at least one root (or solution) within that interval.

To show that the equations have at least one solution on the given intervals, we can use the Intermediate Value Theorem. According to the theorem, if a function is continuous on a closed interval and takes on values of opposite signs at the endpoints of the interval, then it must have at least one root within that interval.

Let's analyze each equation separately:

xcosx - 2x²  + 3x - 1 = 0 on [1.2, 1.3]

To apply the Intermediate Value Theorem, we need to show that the function is continuous on the interval and takes on values of opposite signs at the endpoints.

First, let's check the continuity of the function. Both xcosx and -2x²  + 3x - 1 are continuous functions on their respective domains. Thus, their sum, xcosx - 2x²  + 3x - 1, is also continuous on the interval [1.2, 1.3].

Next, we evaluate the function at the endpoints:

f(1.2) = (1.2)cos(1.2) - 2(1.2)²  + 3(1.2) - 1

≈ 0.0317

f(1.3) = (1.3)cos(1.3) - 2(1.3)²  + 3(1.3) - 1

≈ -0.0735

Since f(1.2) is positive and f(1.3) is negative, the function changes sign within the interval [1.2, 1.3]. Therefore, by the Intermediate Value Theorem, the equation xcosx - 2x² + 3x - 1 = 0 has at least one solution within the interval [1.2, 1.3].

x - (lnx)ˣ = 0 over [4, 5]

Again, we need to verify the continuity of the function and the sign change at the endpoints.

The function x - (lnx)ˣ is continuous on the interval [4, 5], as both x and lnx are continuous functions on their respective domains.

Evaluating the function at the endpoints:

f(4) = 4 - (ln4)⁴

≈ -3.9616

f(5) = 5 - (ln5)⁵

≈ 3.0342

Since f(4) is negative and f(5) is positive, the function changes sign within the interval [4, 5]. By the Intermediate Value Theorem, the equation x - (lnx)^x = 0 has at least one solution within the interval [4, 5].

In both cases, we have shown that the equations have at least one solution within the given intervals using the Intermediate Value Theorem.

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Answer:

the answer is

-7 (x-5)x

Answer:

The second and third are correct

Step-by-step explanation:

It gain value by 25 percent

30 times 1.25 is 37.5

Answer:

$36

Step-by-step explanation:

$540÷15 = $36

a. (g∘f) is equal to -3/sqrt(2-8x). b. The domain of (g∘f)(x) in interval notation is (-∞, 0) ∪ (0, 1/8].

a. To find (g∘f), we need to substitute f(x) into g(x). Since g(x) = -3/x, we replace x in g(x) with f(x), which gives us (g∘f) = -3/f(x). Substituting f(x) = sqrt(2-8x), we get (g∘f) = -3/sqrt(2-8x).

b. To determine the domain of (g∘f)(x), we need to consider the restrictions on x that keep the expression defined. In this case, the denominator of (g∘f)(x) is sqrt(2-8x). For the expression to be defined, the denominator cannot be equal to zero. Thus, we need to find the values of x that make the denominator zero and exclude them from the domain.

Setting the denominator equal to zero, we have 2-8x = 0. Solving for x, we get x = 1/8. Therefore, the domain of (g∘f)(x) is all real numbers except x = 1/8. In interval notation, the domain is (-∞, 0) ∪ (0, 1/8].

Thus, (g∘f) is equal to -3/sqrt(2-8x), and the domain of (g∘f)(x) is (-∞, 0) ∪ (0, 1/8].

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Answer:

$26.25

Step-by-step explanation:

I'm not completely sure if I did this right because I haven't used this in a while, but let's say sodas are x and hot dogs are y. The first equation would be  3x+4y=15 and in order to solve for x or y you have isolate them to seperate sides because if there is not letter on the other side, it will just end up being zero... if that makes sense. subtract 3x so the equation is now 4y=15-3x and divide everything by 4, to make the equation y=3.75-3/4x. Do the same thing but subracting the 4y and dividing by 3 to get the x value. Now we're left with y=-3/4+3.75 and x=5-4/3y (or x=5-1 1/3y). remember that x=sodas and y=hotdogs. The equation we need to create has seven hot dogs and no sodas, so we simply need to take the equation for y and substitute y for 7 because we have 7 hot dogs and y is the symbol used for hot dogs. This equation would now be 7(-3/4x+3.75) because hotdog=y=-3/4x+3.75, so hotdog=-3/4+3.75 and we have 7 hot dogs so you just multiply that by 7

The sum of the x-values where f(x) = g(x) is 3

From the question, we have the following parameters that can be used in our computation:

f(x) = 3(2)ˣ

g(x) = 6x

When f(x) = g(x), we have

3(2)ˣ = 6x

Solving for x, we have

x = 1 and x = 2

When these values are added, we have

Sum = 1 + 2

Evaluate

Sum = 3

Hence, the sum of the x-values where f(x) = g(x) is 3

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