Solve the equation and describe what your answer. What happens? 5x-7=2x+1+3x
Answers
Answer: The Answer is 0
Step-by-step explanation:
The key here is combining like terms. Here:
1) 5x-7=2x+1+3x
2) 5x-7=5x+1
Then you add 7 to both sides anywhere that there is no variable. You also subtract 5x to the other 5x
3) 0x=8
When you divide by zero on both sides, your answer should be 0
Related Questions
X squared over 5 gives you what?
Answers
Answer:(x^(2))/(5)
Step-by-step explanation
Find the decimal number halfway between the following decimal number 0.7 and 0.5
Answers
Answer:
0.6?
Step-by-step explanation:
confused by the question but thats the middle decimal..
When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object
with mass 4 kg, the acceleration of the object is 9 m/s². When the same force acts upon another object, its acceleration is 6 m/s². What is the mass of this
object?
Answers
Step-by-step explanation:
a = k/m or ma = k
using 4 and 9 4* 9 = k = 36
then the equation becomes:
ma = 36
using a = 6
6 * m = 36 shows m = 6 kg
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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HELP, ASAP PLEASE. 15 POINTS! ( Only 1 picture is attached)
Answers
The concentration of the type of antibiotic after 4 hours is; 11.04 parts per million
How to find the input values of functions?
We are told that the equation that models the concentration in parts per million of a type of antibiotic in a human's bloodstream after h hours is;
A(h) = -0.06h² + 2h + 4
where h is the time in number of hours after which the concentration is recorded.
Now, we want to find the concentration after 4 hours and as such we will input 4 for h in the equation to get;
A(4) = -0.06(4²) + 2(4) + 4
A(4) = -0.96 + 12
A(4) = 11.04 parts per million
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Given below are descriptions of two lines.
Line 1: Goes through (-15,-140) and (7,80)
Line 2: Goes through (-6,18/5) and (-1,31/10)
The slope of Line 1 is m =
The slope of Line 2 is m =
Answers
Answer:
Line 1 m = 10
Line 2 m = -1/10
Step-by-step explanation:
The slope formula is:
\(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
Line 1: By plugging in the coordinates given, we get:
\(m = \frac{80-(-140)}{7-(-15)}\\ m=\frac{220}{22}\\ m = 10\)
Line 2: By plugging in the coordinates given for this line, we have:
\(m=\frac{31/10-18/5}{-1-(-6)}\\ m=\frac{-1/2}{5}\\ m=-1/10\)
Parker has 12 blue marbles. Richard has 34
of the number of blue marbles that Parker has.
Part A
Explain how you know that Parker has more blue marbles than Richard without completing the multiplication.
Enter equal to, greater than, or less than in each box.
Multiplying a whole number by a fraction
less than
1 results in a product that is
the original whole number.
Part B
How many blue marbles does Richard have? Enter your answer in the box.
blue marbles
Answers
Solve using substitution.
4x – 7y = -18
x = 6
Answers
Answer:
6
Step-by-step explanation:
4(6) - 7y = -18
24 - 7y = -18
-7y= -42
y= 6
Answer: y=6
Step-by-step explanation:
4(6)-7y=-18
24-7y=-18 subtract 24 on both sides
-7y=-42 **then divide -7 on both sides**
and the answer is y=6
I REALLY NEED HELP with this statistics question, it would mean a lot if someone could answer it, i will give you brainliest for the correct answer :)
Answers
Answer:
Best anwser to use is Mode. Where you have the most
Step-by-step explanation:
On a given day, the flow rate F (cars per hour) on a congested roadway is
F= 3600v/(22+0.07v^2)
where v is the speed of the traffic in miles per hour. What speed will maximize the flow rate on the road?
Answers
Answer:
about 17.7 mph
Step-by-step explanation:
You want the value of v that maximizes F(v) = 3600v/(22+0.07v²).
DerivativeThe derivative of F is ...
\(F'(v)=\dfrac{3600(22+0.07v^2)-3600v(0.14v)}{(22+0.07v^2)^2}\)
MaximumThe derivative is zero at the maximum. This is the case when the numerator is zero:
3600(22 +.07v² -.14v²) = 0
.07v² = 22
v = √(22/0.07) ≈ 17.728
Flow rate is maximized at a speed of about 17.7 miles per hour.
Which expression has a value of 24?
A 12+16÷(4+2)×2
B (12+16)÷4+2×2
C. 12+16÷(4+2×2)
D. 12+(16÷4+2)×2
Answers
Answer:
the last one
Step-by-step explanation:
12+(16/4+2)2
12+(4+2)2
12+6*2
12+12
24
Answer:
D
Step-by-step explanation:
A. 17.33
B. 11
C. 14
D. 24
What is the solution to the equation 1/4x+2=-5/8-5
Answers
Answer: \(x=-61/2\)
Simplify both sides of the equation
\(1/4x+2=(-5/8+-5)\) (Combine Like Terms)
\(1/4x+2=-45/8\)
Subtract 2 from both sides
\(1/4x+2-2=-45/8-2\\1/4x=-61/8\)
Multiply both sides by 4
\(4*(1/4x)=4*(-61/8)\\x=-61/2\)
The question is asked in the attached file,. Kindly someone answer it in the best way.
Answers
According to the Empirical Rule, 99.7% of the measures fall within 3 standard deviations of the mean in the normal distribution.
What does the Empirical Rule state?The Empirical Rule states that, for a normally distributed random variable, the symmetric distribution of scores is presented as follows:
The percentage of scores within one standard deviation of the mean of the distribution is of approximately 68%.The percentage of scores within two standard deviations of the mean of the distribution is of approximately 95%.The percentage of scores within three standard deviations of the mean off the distribution is of approximately 99.7%.More can be learned about the Empirical Rule at https://brainly.com/question/10093236
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6. At what position on the number line is the red dot located?
A:1/2
B:2/5
C:4/9
D:5/9
Answers
Answer: Would you be so kind to as post the number line so I can answer the question, thanks!
Step-by-step explanation:
A triangle has side lengths of (4m +3n) centimeters, (8m + 10p) centimeters,
and (2p+ 2n) centimeters. Which expression represents the perimeter, in
centimeters, of the triangle?
Answers
Answer:
5n + 12p + 12m
Step-by-step explanation:
Perimeter means you are adding up all three sides.
4m + 3n + 8m + 10p + 2p + 2n
= 2n+3n + 10p+2p + 4m+8m
Combine like terms.
= 5n + 12p + 12m
On a coordinate plane, a parabola opens down with solid circles along the parabola at (negative 3, negative 5), (negative 2, 0), (negative 1, 3), (0, 4), (1, 3), (2, 0), (3, negative 5).
Use the drop-down menus to identify the values of the parabola
Vertex =
Domain = {x|
}
Range = {y| y ≤
Answers
The values of the parabola are: Vertex = (0, 4), Domain = {x| x ∈ R}, Range = {y| y ≤ 4}.
Given the coordinates of a parabola, we can use them to identify its vertex, domain, and range. In this case, we know that the parabola opens down, and there are solid circles along the parabola at (negative 3, negative 5), (negative 2, 0), (negative 1, 3), (0, 4), (1, 3), (2, 0), (3, negative 5).
Let us begin with identifying the vertex of the parabola.
Since it opens down, the vertex of the parabola is the highest point on the graph. To find the vertex, we first need to find the axis of symmetry, which is a vertical line that passes through the vertex.
The x-coordinate of the vertex is the same as the x-coordinate of the axis of symmetry. To find the axis of symmetry, we take the average of the x-coordinates of the two points on either side of it. Since the axis of symmetry is equidistant from the two points, the average of the x-coordinates of the points will give us the x-coordinate of the axis of symmetry.
So, we have:
Axis of symmetry: {x| x = (-3 + 3)/2 = 0}
Since the parabola opens down, the y-coordinate of the vertex is the maximum value of the function. We can find the y-coordinate of the vertex by substituting the x-coordinate into the function.
We get:
y = f(0) = 4
So, the vertex of the parabola is (0, 4).
Next, let us identify the domain of the function. Since the parabola is continuous and extends infinitely in both directions, the domain is all real numbers.
So, we have:
Domain: {x| x ∈ R}
Finally, we need to identify the range of the function.
Since the parabola opens down, the range is all y-values less than or equal to the y-coordinate of the vertex.
So, we have:
Range: {y| y ≤ 4}
Therefore, the values of the parabola are: Vertex = (0, 4), Domain = {x| x ∈ R}, Range = {y| y ≤ 4}
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Please help, thanks!
Answers
The change in function values is f(40) - f(10) = 49 - 55 = -6.
The change in x-values is 40 - 10 = 30.
Therefore, the average rate of change is -6/30, which simplifies to -1/5.
The average rate of change of the function over the interval 10 < x ≤ 40 is -1/5.
an aeroplane is flying with a help of 300 km per hour who much distance will it cover in 160 minute
Answers
Answer:
800 km
Step-by-step explanation:
Does the plane have a speed of it's own? I don't see it, so will assume the plane is simply travelling at 300 km/h.
(300 km/hr)*(1 hr/60 min) = 5 km/min
(5 km/min)*(160 min) = 800 km in 160 minutes
Angle ADB and CD are straight lines. angle ADC = 5 x angle CDB Work out the size of angle ADC.
Answers
Answer:
Step-by-step explanation:
If you are surveying people about whether they like to swim, where are you more likely to get a random sample?
A) at a local supermarket
B) at a local beach
C) at a swimsuit store
D) outside a local swimming pool
Answers
Answer:
B) a local beach.
At a local beach, you might find quiet a few different perspective from people who like or don't like swimming, whether going to a swimsuit store, you most likely will find people buying the swimsuit because they enjoy it, and plan on swimming in it.
Step-by-step explanation:
Hope it helps! =D
PLEASE HELP. I WILL GIVE BRAINLIEST TO THE PERSON WHO ANSWERS BOTH PARTS OF THE QUESTION.
Parking at the posh center costs d dollars per hour during the off hours and an extra $3 per hour during peak hours. During holidays, the basic rate of d doubles. Write an expression for how much it would cost to park for 3d hours on a holiday during peak hours.
Then, if the basic off-hours parking rate is $2.50 per hour, how much would a person pay to park for 3d hours in the situation described above?
PLEASE HELP. I WILL GIVE BRAINLIEST TO THE PERSON WHO ANSWERS BOTH PARTS OF THE QUESTION.
Answers
THINGS TO REMEMBER:
the variable d represents dollarsCosts an extra $3 per hour during peak hoursWhile holiday's are going on the amount of d doublesFind how much parking would cost on a holiday during peak hour's-----
Question: Write an expression for how much it would cost to park for 3d hours on a holiday during peak hours.
-----
Answer: 3d × 2 or 3d + 3d
-----
Explanation: This is because during holidays the amount of d doubles. However since this is on a holiday DURING peak hours it would be 3d × 2
-----
Question 2: Then, if the basic off-hours parking rate is $2.50 per hour, how much would a person pay to park for 3d hours in the situation described above?
-----
Answer: $15
-----
Explanation: Since d represents dollars we would multiply 2.50 times 3 which would give us 7.5 then we double this since it is during holidays giving us $15
-----
NOTE: I AM SO SORRY IF THIS IS WRONG AND I MISSED SOMETHING. IF IT IS WRONG THEN PLEASE MAKE SURE TO TELL ME SO I CAN FIGURE OUT WHAT I MISUNDERSTOOD
Again I'm sorry but I hope I helped a little bit.
1. Quadrilateral LBMN is the result of a 180 degree rotation of Quadrilateral ABCD around point B, write the corresponding angles and segments in the table below.
Answers
In the quadrilateral ABCD and LBNM the corresponding angles and line segments are as follow,
∠A = ∠L, ∠D =∠M , ∠C = ∠N , and
AB = LB , CD = NM , DA = ML.
Quadrilateral ABCD rotates 180 degrees around point B,
New quadrilateral formed named LBMN
The corresponding angle after rotation of 180 degrees around B is equals to,
B remain at same position.
A rotates and point L take the position of A.
D rotates and point M take the position of D.
C rotates and point N take the position of C.
Corresponding angle to A is angle L.
Corresponding angle to D is angle M.
Corresponding angle to C is angle N.
Similarly corresponding segments are of ABCD and LBNM are
Line segment AB corresponds to line segment LB.
Line segment CD corresponds to line segment NM
Line segment DA corresponds to line segment ML.
Therefore, in the quadrilateral the corresponding angles and line segments are ∠A = ∠L, ∠D =∠M , ∠C = ∠N , AB = LB , CD = NM , and DA = ML.
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Please help me this is hard
Answers
Shaded Area=11*14 -5*7= 154- 35=119 sqm
Help ASAP!!!
Suppose you buy a stock for $2,100. It decreases in value by 15% and then rises
20%. What is the new stock value? Round to the nearest cent.
A) $2,142.00
$1,785.00
B) $2,205.00
D) $2,520.00
Answers
Answer:
B
Step-by-step explanation:
20-15= 5 so you do 5% of 2100 by doing 2100 times 0.05 which gives y9u 105. you then add 2100 and 105 together
A university's freshman class has 3000 students. 21% of those students are majoring
in Engineering. How many students in the freshman class are Engineering majors?
Answers
Answer: 630
Step-by-step explanation:
\(3000 * 21 /100 = 3000 * 0.21 = 630\)
use the diagram below to find all missing angles
Answers
Answer:
Step-by-step explanation:
Soooo, angle 1 is 157 degrees
That means:
Angle 2 is 23 degrees Supplementary Angles
Angle 3 is 157 degrees Vertical Angle to Angle 1
Angle 4 is 23 degrees Vertical angle to Angle 2
Answers:
angle 2 = 23 degreesangle 3 = 157 degreesangle 4 = 23 degrees=======================================================
Explanation:
Angles 1 and 2 are supplementary as they form a straight line. So the angles add to 180
(angle1)+(angle2) = 180
angle2 = 180-(angle1)
angle2 = 180-157
angle2 = 23 degrees
Angle 4 is congruent to this because angles 2 and 4 are vertical angles. Vertical angles are always congruent. Note how angles 1 and 4 are supplementary.
Since angles 1 and 3 are the other pair of vertical angles, this must mean angle 3 is 157 degrees.
4. Which of the following angles is vertical to angle /DEB?
A
C
109°
E
D
B
Answers
Answer:
A
Step-by-step explanation:
Two companies A and B are offering 70 and 50 products respectively. Company A is offering 40 software products and 30 hardware products. Company B is offering x hardware products and y software products to be determined. If a product is selected at random, what is the probability that (a)This product is a hardware product given that is from company B? (in terms of y) (b)This product is a hardware product given that is from company A? (C) For what values of y will the probability in part (a) be greater than the probability in part (b)?
Answers
The probability that the selected product is a hardware product given that is from company B is x/50.
The probability that the selected product is a hardware product given that is from company A is 3/7.
The value of x must be greater than 21 so that the probability in part (a) is greater than the probability in part (b).
What is probability?It is the chance of an event to occur from a total number of outcomes.
The formula for probability is given as:
Probability = Number of required events / Total number of outcomes.
We have,
Company A:
Total product = 70
Software product = 40
Hardware product = 30
Company B:
Total product = 50
Software product = y
Hardware product = x
The probability that the selected product is a hardware product given that is from company B.
= x/50 ____(1)
The probability that the selected product is a hardware product given that is from company A.
= 30/70
= 3/7 _____(2)
From (1 ) and (2) we get,
x/50 > 3/7
x > 3/7 x 50
x > 21
Thus,
The probability that the selected product is a hardware product given that is from company B is x/50.
The probability that the selected product is a hardware product given that is from company A is 3/7.
The value of x must be greater than 21 so that the probability in part (a) is greater than the probability in part (b).
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Solve 2x²-x-6=0 by factorisation
Answers
Answer:
x = 2, x = -3/2
Step-by-step explanation:
Factors to be (x-2)(2x+3) = 0
x =2, x = -3/2
Answer:
Step-by-step explanation:
2x²-x-6=0
2x²-(4-3)x-6=0
2x²-4x+3x-6=0
2x(x-2)+3(x-2)=0
(x-2)(2x+3)=0
Brainliest if correct
Answers
\(\left(\dfrac{7}{4} \right)^{11} = \dfrac{7^{11}}{4^{11}}\)