solve equation
|3x+5|=5x+2​

48 points gained in those 3 days.

Subtract 220 with 48, then add 96. Last step would be subtracting 220 with the amount they have now in those 3 days to find how much points the stock market gained in those 3 days.

Subtract 220-48.It‘ll be 172.

Add 172 with 96. 172+96=268.

Subtract 268 with how much points the stock market had 3 days ago. 268-220. So it would be about 48 points gained.

(9) The slope of a line perpendicular to the line, f(x) = 0.75x + 6 is - 4/3.

(10) The slope of a line parallel to this line, y = 10 -8x is -8.

The slope of a line perpendicular to the line is the negative reciprocal of the slope of the line equation.

Question 9.

f(x) = 0.75x + 6

where;

The slope of a line perpendicular to this line = -1/0.75 = -100/75 = -4/3

Question 10.

For the equation of another line, y = 10 - 8x

The slope of a line parallel to this line is equal to the slope of this line and it is calculated as follows;

y = 10 - 8x

where;

slope of a line parallel to the line = -8

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Step-by-step explanation:

We need to find the area of the shaded region. We see that the region next to that has a central angle of 120°. Also we know that angle in a straight line is 180° . So the measure of central angle of that shaded region will be 180° - 120° = 60° . Now we can use the formula of area of sector to find out the area of the shaded region.

\(\tt\to Area = \dfrac{\Theta}{360^o}\times \pi r^2 \\\\\tt\to Area = \dfrac{60^o}{360^o}\times \pi (8cm)^2 \\\\\tt\to Area =\dfrac{\pi \times 64}{6}cm^2\\\\\to\boxed{\orange{\tt Area_{(Shaded)}= 10.66\pi cm^2}}\)

Answer:

1) Congruent

2) Alternate exterior angles

3) 15x = 12x + 15

4) x = 5

Hope this helps!

Answer:

the answer is D. F(x) = 1/x(x-3)

Step-by-step explanation:

Answer:

$15.48

Explanation:

100 ÷ 6.46 = 15.479876

Answer:

The answer toy our problem is, The maximum number of days by which the completion of work can be delayed is 15.

Step-by-step explanation:

We are given that the penalty amount paid by the construction company from the first day as sequence, 4000, 5000, 6000, ‘ and so on ‘. The company can pay 165000 as penalty for this delay at maximum that is

 \(S_{n}\)​ = 165000.

Let us find the amount as arithmetic series as follows:

4000 + 5000 + 6000

The arithmetic series being, first term is \(a_{1}\) = 4000, second term is \(a_{2}\) = 5000.

We would have to find our common difference ‘ d ‘ by subtracting the first term from the second term as shown below:

\(d = a_{2} - a_{1} = 5000 - 4000 = 1000\)

The sum of the arithmetic series with our first term ‘ a ‘ which the common difference being, \(S_{n} = \frac{n}{2} [ 2a + ( n - 1 )d ]\) ( ‘ d ‘ being the difference. )

Next we can substitute a = 4000, d = 1000 and \(S_{n}\) = 165000 in “ \(S_{n} = \frac{n}{2} [ 2a + ( n - 1 )d ]\) “ which can be represented as:

Determining, \(S_{n} = \frac{n}{2} [ 2a + ( n - 1 )d ]\)

⇒ 165000 = \(\frac{n}{2}\) [( 2 x 4000 ) + ( n - 1 ) 1000 ]

⇒ 2 x 165000 = n(8000 + 1000n - 1000 )

⇒ 330000 = n(7000 + 1000n)

⇒ 330000 = 7000n + \(1000n^2\)

⇒ \(1000n^2\) + 7000n - 330000 = 0

⇒ \(1000n^2\) ( \(n^2\) + 7n - 330 ) = 0

⇒  \(n^2\) + 7n - 330 = 0

⇒ \(n^2\) + 22n - 15n - 330 = 0

⇒ n( n + 22 ) - 15 ( n + 22 ) = 0

⇒ ( n + 22 )( n - 15 ) = 0

⇒ n = -22, n = 15

We need to ‘ forget ‘ the negative value of ‘ n ‘ which will represent number of days delayed, therefore, we get n=15.

Thus the answer to your problem is, The maximum number of days by which the completion of work can be delayed is 15.

Answer:

75

Step-by-step explanation:

f(4) means to use 4 in place of x.

f(x) = 3(5)^(x-2)

fill in 4 for

f(4) = 3(5)^(4-2)

do the 4-2 subtraction first

f(4) = 3(5)^2

do the 5 to the 2nd power next.

f(4) = 3(25)

last, multiply.

f(4) = 75

This is just following the typical order of operations.

0.5 because if you look at 1, d is basically half the size

The correct sentences in the passage are option A, option B, and option E.

Let's check all the options, then we have

Any two squares are either similar or congruent. The statement is true.

If two lines are parallel, they never intersect. The statement is true.

If all the angles of a polygon are congruent, then it is a square. The statement is false because a regular polygon has an equal angle but it may be a pentagon, hexagon, etc.

The intersection of two lines always forms 4 congruent angles. The statement is false because opposite angles are the same. But if adjacent angles become the same, then the statement will be true.

A line can be drawn through any two distinct points. The statement is true.

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The Propositions are resulting

(a) ∀x∃y(x = y²) is False

(b) ∀x∃y(x² = y) is True.

(c) ∃x∀y(xy = 0) is True.

(d) ∀x∃y(x + y = 1) is True.

(a) ∀x∃y(x = y²)

This proposition states that for every x, there exists a y such that x is equal to y². To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any positive value for x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4 = 2². Similarly, if x = 9, then y = 3 satisfies the equation since 9 = 3².

Therefore, the proposition (a) is false.

(b) ∀x∃y(x² = y)

For any given positive or negative value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4² = 2. Similarly, if x = -4, then y = -2 satisfies the equation since (-4)² = -2.

Therefore, the proposition (b) is true.

(c) ∃x∀y(xy = 0)

The equation xy = 0 can only be satisfied if x = 0, regardless of the value of y. Therefore, there exists an x (x = 0) that makes the equation true for every y.

Therefore, the proposition (c) is true.

(d) ∀x∃y(x + y = 1)

To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 2, then y = -1 satisfies the equation since 2 + (-1) = 1. Similarly, if x = 0, then y = 1 satisfies the equation since 0 + 1 = 1.

Therefore, the proposition (d) is true.

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The surface area of the table top that is not covered by the mirror in the form of algebraic expressions is \(5x^2 - 17x +6\,\,m^2\) .

The length of the table top = 5x - 2 m.

The width of the table not covered by mirror is x-3 m.

The surface area of the table top not covered by the mirror is

\($(5x-2)(x-3) = 5x^2 -15x -2x +6 \,\,m^2\)

\($=5x^2 -17x +6\,\, m^2\) in the form of algebraic expressions.

Surface area of cylinder of radius r and height h = \(2\pi r^2 + 2\pi rh\)

Surface area of a cuboid of side length a = \(6a^2\)

Outside area for a sphere of radius r = \(4\pi r^2\)

Surface area of a regular tetrahedron of edge length a = \(\sqrt{3}\,a^2\)

Surface area of a right angled cone of base radius r, and lateral height l = \(\pi r^2 + \pi r l\)

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Answer:

add my sc = bmic ava, no spaces

or add my discord = XoXo_ava

Step-by-step explanation:

Also have a great day and remember youre worth, dont let no boy/girl tear u down. leave them h*es aside and focus on yo self!!!

The area of the figure ABDECA, and the coordinates of the points on the quadrilateral are;

1. The area is about 15.16 units²

2. The coordinates of the points are;

(i) B(5, 8)

(ii) C(8.58, 4)

(ii) D(8,58, 1.21)

A quadrilateral is a four sided polygon.

1. The coordinate of the point C can be found as follows;

Let (x, y) represent the coordinates of the C, we get;

(x + 8)/2 = 5

x = 2 × 5 - 8 = 2

(y + 8)/2 = 6

y = 2 × 6 - 8 = 4

The coordinates ot the point C (2, 4)

The length of the segment BC = √((8 - 2)² + (8 - 4)²) = 2·√(13)

Length of the side AB = √((8 - 6)² + (8 - 11)²) = √(4 + 9) = √(13)

The area of the triangle ABC = (1/2) × 2·√(13) × √(13) = 13

CE is perpendicular to DE, let (a, b), represent the coordinates of the point E, therefore;

(4 - y)/(2 - x) = -(5 - x)/(6 - y)

y - 4 = (-4/7)(x - 2)

y - 6 = (7/4)(x - 5)

(-4/7)(x - 2) + 4 = (7/4)(x - 5) + 6

x = (17/5) = 3.4

y = (7/4)((17/5) - 5) + 6 = 3.2

The coordinates of the point E is (3.4, 3.2)

The length of the side DE = √((5 - 3.4)² + (6 - 3.2)²) = √(10.4)

Length of the side CE = √((3.2 - 2)² + (3.4 - 4)²) = √(1.8)

Area of the triangle ΔCDE = (1/2) × √(10.4) × √(1.8)

Area of the figure is therefore;

2. The equation of the line AB is; y - 6 = (1/3)·(x - (-1))

y - 6 = (1/3)·(x + 1)

y = (1/3)·(x + 1) + 6

The slope of the segment AE = (4 - 6)/(3 - (-1)) = -1/2

Slope of the segment BE = -1/(-1/2) = 2

Equation of BE is; y - 4 = 2·(x - 3)

y = 2·(x - 3) + 4 = (1/3)·(x + 1) + 6

Therefore, x = 5

y = (1/3)·(5 + 1) + 6 = 8

(ii) Area of the triangle EBC = 24 unit²

EB = (1/2) × √((5 - 3)² + (8 - 4)²) = √20

Therefore;

BC = 24/(√20) = 12/√5 = 12·√5/5 = √(28.8)

(x - 5)² + (y - 8)² = 28.8

y = 4, therefore;

(x - 5)² + (4 - 8)² = 28.8

(x - 5)² = 28.8 - (4 - 8)² = 12.8

x = √(12.8) + 5

(iii) The equation of the segment AD is; y - 4 = (-1/2)(x - 3)

x = √(12.8) + 5

Therefore;

y - 4 = (-1/2)((√(12.8) + 5) - 3)

y = (-1/2)((√(12.8) + 5) - 3) + 4 ≈ 1.21

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the cost for using 20 HCF of water is $47.36

Explanation:

Linear function is in the form: y = mx + c

Let the monthly cost (in dollars) of water = y

the amount of water used (in hundreds of cubic feet, HCF) = x

when y = $38.46, x =14 HCF

Inserting in the equation of line:

38.46 = 14m + c ...equation 1

when y = $73.26, x = 38 HCF

73.26 = 38m + c ...equation 1

To get m = slope = change in y/ change in x

(x, y) = (14, 38.46) and (38, 73.26)

m = (73.26-38.46)/(38-14)

m = 34.8/24

m = 1.45

Insert the value of m in any of the equation to get intercept (c):

using 73.26 = 38m + c

73.26 = 38(1.45) + c

c = 73.46 - 55.1

c = 18.36

The equation of the function becomes: y = 1.45x + 18.36

To get the cost for using 20 HCF of water, we will use the equation:

y = 1.45x + 18.36

x = 20HCF, y = ?

y = 1.45(20) + 18.36

y = 29+18.36

y = 47.36

Therefore, the cost for using 20 HCF of water is $47.36

Answer:  -7j+3

Step-by-step explanation:Simplify

Answer:

B

Step-by-step explanation:

Trust me on this one..

Answer:

  a. {1, 2, 3, 4, 5, 6, 7}

  b. {1, 2, 3, 4, 5, 6, 8}

  c. {4, 5, 7}

  d. {1, 4, 5}

Step-by-step explanation:

The union of two sets is the list of elements in either set. The intersection of two sets is the list of elements in both sets. The complement of a set is the list of elements in the universal set that are not in the set being complemented. The complement of a set can be indicated with an apostrophe: A' is the complement of set A, for example.

B∪C = {2, 5, 6, 7} ∪ {3, 4, 6, 7} = {2, 3, 4, 5, 6, 7}

A∪(B∪C) = {1, 4, 5, 7} ∪ {2, 3, 4, 5, 6, 7} = {1, 2, 3, 4, 5, 6, 7}

B∩C = {2, 5, 6, 7} ∩ {3, 4, 6, 7} = {6, 7}

A ∩ (B∩C) = {1, 4, 5, 7} ∩ {6, 7} = {7}

(A∩(B∩C))' = {7}' = {1, 2, 3, 4, 5, 6, 8}

A∩Β = {1, 4, 5, 7} ∩ {2, 5, 6, 7} = {5, 7}

Α∩C = {1, 4, 5, 7} ∩ {3, 4, 6, 7} = {4, 7}

(A∩B)∪(A∩C) = {5, 7} ∪ {4, 7} = {4, 5, 7}

(A∩B')∪(A∩C') = A∩(B'∪C') = A∩(B∩C)'

(B∩C)' = {6, 7}' = {1, 2, 3, 4, 5, 8}

A∩(B∩C)' = {1, 4, 5, 7} ∩ {1, 2, 3, 4, 5, 8} = {1, 4, 5}

__

Additional comment

In part (d) we made use of De Morgan's law for sets:

  B'∪C' = (B∩C)'

We also made use of the distributive property for sets:

  A∩(B∪C) = (A∩B)∪(A∩C)

Answer:

D. quadrant III

Step-by-step explanation:

The worker recieves 3 hours of break time per day.

Given is that a a fast-food worker works Monday through Friday, 8 hours per day. Daily, the worker receives a hour break in the morning, a hour break for lunch, and a hour break in the afternoon.

The worker recieves three breaks, meaning it recieves 3 hours of break time per day.

Therefore, the worker recieves 3 hours of break time per day.

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The probability that a student is a female or major in civil engineering is 62%

At a certain college, 49% of the students are female, and 21% of the students major in civil engineering. Furthermore, 8% of the students both are female and major in civil engineering. What is the probability that a randomly selected female student majors in civil engineering?

Let A represent Female and B represents civil engineering.

The above representation means that the given parameters are:

The required probability is calculated as:

P(A or B) = P(A) + P(B) - P(A and B)

This gives

P(A or B) = 49% + 21% - 8%

Evaluate

P(A or B) = 62%

Hence, the probability that a student is a female or major in civil engineering is 62%

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Answer:

1.3n + 9.6

Step-by-step explanation:

3.4n + 9.6 - 2.1n

So you can rearrange it to make it visually easier (but it's not needed)

3.4n - 2.1n + 9.6

Subtract like terms

1.3n + 9.6

Answer:

The negative sign outside the absolute value function causes a few different things when multiplied. When a negative is multiplied outside of the function, the transformation that exists will be a vertical reflection.  A horizontal shift to the left 1 unit will happen because of g(x)=f(x+1). The graph will make a vertical shift down 2 units because of g(x)=f(x)−2. The value of (a) would be -1 and since it is less than 1, and it causes the graph to be wider because of vertical compression. Placing a minus sign outside absolute value bars gives you a negative result.

I hope this is what you were looking for and I hope it helps also you might need to recheck your answers on your paper. I will add a picture of my findings. Good Luck!

The average rate of change for the interval from x =  7 to x =  8 is 35.  

To calculate the average rate of change for the interval from x =  7 to x =  8, we need to find the difference in y- values and divide it by the difference inx-values within that interval.

Let's calculate it step by step using the given table  

For the interval from x =  7 to x =  8  x1 =  7, y1 = -37  x2 =  8, y2 = -2   Difference in y- values Δy =  y2- y1 = -2-(- 37) =  35  

Difference inx-values Δx =  x2- x1 =  8- 7 =  1  

Average rate of change =  Δy/ Δx =  35/ 1 =  35  

Thus, the average rate of change for the interval from x =  7 to x =  8 is 35.   Note: It's important to mention that the values calculated then are grounded solely on the given data. Please  insure you  corroborate the  delicacy of the  handed data and  environment before using the answer in any important or critical  operations.

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Answer:

5 mins

Step-by-step explanation:

30 / 6 = 5

hope this helps...

Step-by-step explanation:

the songs were 5 min long

The total number of points scored is given by the equation A = 23 points

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the total points scored be represented as A

Now , the equation will be

Substituting the values in the equation , we get

A = 3x + 2y + z   be equation (1)

where x = red team = 3 points

y = yellow team = 5 points

z = blue team = 2 points

So , A = 3 ( 3 ) + 2 ( 5 ) + 2

A = 9 + 10 + 2

A = 21 points

Hence , the equation is A = 21 points

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Answer:

Think about the PEMDAS rules for order of operations.

Multiplication comes before addition or subtraction, so first we have "the product of a number and 5" - that's 5x. Then "six more" than that would be 5x + 6. "Equals" means the "=" sign, so the final answer is 5x + 6 = 8.

a. The cost of the stock is $19

b.  Tanya Elliot paid total amount of $ 7629.95.

The cost of preferred stock to a company is effectively the price it pays in return for the income it gets from issuing and selling the stock.

a. It is given that , each share= $19.00

Total number of shares = 400

Price for 400 shares be,

= 400 x $19.00

= $7600.00

Cost of the stock= \(\frac{ 7600}{400}\)

                            = $19

b. Total paid by Tanya = $7600.00 +$29.95

                                      = $7629.95

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