Solve And Graph 12 + 6 _> 42

The area of the surface formed by revolving the curve y = x³ from x = 1 to x = 2 about the x-axis  S = (π/35) [(163)^5/2 - (10)^5/2 - 18[(163)^3/2 - (10)^3/2]].

To find the area of the surface formed by revolving the curve y = x³ from x = 1 to x = 2 about the x-axis, we need to use the formula for the surface area of revolution: S = 2π ∫ [a,b] y(x) √(1 + [y'(x)]²) dx In this case, a = 1, b = 2, y(x) = x³, and y'(x) = 3x².

Substituting these values, we get: S = 2π ∫ [1,2] x³ √(1 + [3x²]²) dx Simplifying the expression inside the square root: 1 + [3x²]² = 1 + 9x^4 Taking the square root: √(1 + 9x^4) = √(1 + (3x²)²)

We can now substitute this back into the surface area formula: S = 2π ∫ [1,2] x³ √(1 + 9x^4) dx We can evaluate this integral using substitution. Let u = 1 + 9x^4, then du/dx = 36x^3 dx. Solving for dx, we get dx = du / (36x^3).

Substituting these into the integral: S = 2π ∫ [10,163] (u - 1) / (36x^3) * √u du Simplifying the expression inside the integral: (u - 1) / (36x^3) = (u / (36x^3)) - (1 / (36x^3)) Substituting this back into the integral: S = 2π ∫ [10,163] (u / (36x^3)) √u du - 2π ∫ [10,163] (1 / (36x^3)) √u du

The first integral is a simple power rule integration, which evaluates to: (2π/35) [(163)^5/2 - (10)^5/2] / (36(2)^3) The second integral can also be evaluated using power rule integration: -(2π/35) [(163)^3/2 - (10)^3/2] / (36(2)^3)

Simplifying both of these expressions and adding them together: S = (π/35) [(163)^5/2 - (10)^5/2 - 18[(163)^3/2 - (10)^3/2]] The final answer is the surface area formed by revolving the curve y = x³ from x = 1 to x = 2 about the x-axis.

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Answer:

0

Step-by-step explanation:

Plug p and q in

1+-1/2

0/2

0

If this helps please mark as brainliest

Answer:

see below

Step-by-step explanation:

p+q/2

If

p  + q/2

1 + -1/2

1/2

If (p+q)/2

 (1-1)/2

0

Answer:

300

Step-by-step explanation:

now answer me spanish question

hmmmmajahwiwnejdjdksjsnxnxjdkss

Answer:

this would be the answer 4.66666667 but when rounded it would be 5 or 4.7

Step-by-step explanation:

brainliest ???

Answer:

40.5714

Step-by-step explanation:

Based on the given conditions, formulate: 284 ÷ 7

Evaluate the equation/expression: 40.5714

get the result: 40.5714

Answer: 40.5714

Answer:

7x+7y=

Step-by-step explanation:

(x+y)7

used 7 to open the bracket.

7x+7y

In the original equation, x is a variable, hence f(x). If that term in the parenthesis changes, such as to 0 or -2, we will plug in that number in place of the current variable.

f(0) = 4(0)^2 + 3 = 0 + 3 = 3

f(-2) = 4(-2)^2 + 3 = 4(4) + 3 = 16 + 3 = 19

Hope this helps! :)

Using Complete the Square method, we find out that \(x^{2} -5x+8\) can be expressed in the form of \((x-a)^{2}+b\) as \((x-\frac{5}{2}) ^{2} +\frac{7}{4}\) where a and b are top-heavy fractions.

It is given to us that the expression is -

\(x^{2} -5x+8\) ----(1)

We have to express it in the form of\((x-a)^{2}+b\) where a and b are top-heavy fractions.

In order to achieve the required expression in the form of  \((x-a)^{2}+b\) we have to use "Completing the Square" method.

The given expression from (1) is -

\(x^{2} -5x+8\)

This expression is in the form of \(ax^{2} +bx+c\)

Adding and subtracting \((b/2)^{2}\) terms into the expression, we get

\(x^{2} -5x+[\frac{5}{2}] ^{2}-[\frac{5}{2}] ^{2}+8\) -----(2)

Equation (2) can also be represented as -

\((x-\frac{5}{2}) ^{2} -[\frac{5}{2}] ^{2} +8\)

\(= > (x-\frac{5}{2}) ^{2} -\frac{25}{4} +8\\= > (x-\frac{5}{2}) ^{2} +\frac{7}{4}\)------- (3)

We see that equation (3) is in the form of \((x-a)^{2}+b\).

So, we can derive that -

\(a=\frac{5}{2}\)

and, \(b=\frac{7}{4}\).

Thus, \(x^{2} -5x+8\) can be expressed in the form of \((x-a)^{2}+b\) through "Complete the Square" method as \((x-\frac{5}{2}) ^{2} +\frac{7}{4}\) where a and b are top-heavy fractions.

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To graph the functions y = 2sin(-x) and y = tan(x) - 2 using key points, we can calculate the function values for specific x-values and plot the corresponding points on a graph.

a. Graph of y = 2sin(-x):

Let's calculate the y-values for different x-values and plot the points:

x = -π/2: y = 2sin(-(-π/2)) = 2sin(π/2) = 2(1) = 2

x = -π/4: y = 2sin(-(-π/4)) = 2sin(π/4) = 2(0.707) ≈ 1.414

x = 0: y = 2sin(-0) = 2sin(0) = 2(0) = 0

x = π/4: y = 2sin(-(π/4)) = 2sin(-π/4) = 2(-0.707) ≈ -1.414

x = π/2: y = 2sin(-(π/2)) = 2sin(-π/2) = 2(-1) = -2

The graph will resemble a sine wave with an amplitude of 2, but reflected across the x-axis.

b. Graph of y = tan(x) - 2:

For the tangent function, we will calculate the y-values for different x-values and plot the points:

x = -π/4: y = tan(-π/4) - 2 ≈ -1.414 - 2 ≈ -3.414

x = -π/8: y = tan(-π/8) - 2 ≈ -0.414 - 2 ≈ -2.414

x = 0: y = tan(0) - 2 = 0 - 2 = -2

x = π/8: y = tan(π/8) - 2 ≈ 0.414 - 2 ≈ -1.586

x = π/4: y = tan(π/4) - 2 ≈ 1.414 - 2 ≈ -0.586

The graph will resemble a periodic wave with vertical asymptotes and horizontal shift.

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hey

wanna be friends

The annual tax revenue in City B in 2000 was $578,000.

From the graph, we can see that City B experienced a percent change of -28% from 1990 to 1995 and a percent change of -32% from 1995 to 2000

To find the annual tax revenue in City B in 2000, we start with the revenue in 1990, which is given as $800,000.

First, we calculate the tax revenue after the percent change from 1990 to 1995:

Revenue in 1995 = $800,000 + (-28% of $800,000) = $800,000 - $224,000 = $576,000

Next, we calculate the tax revenue after the percent change from 1995 to 2000:

Revenue in 2000 = $576,000 + (-32% of $576,000) = $576,000 - $184,320 = $391,680

Therefore, the annual tax revenue in City B in 2000 is $391,680, which is closest to $578,000 from the given answer choices.

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Answer:

true

Step-by-step explanation:

The expected number of black balls that we will obtain before we get the first green ball is: 7/10

We are given an urn containing 3 white balls, 2 black balls, and 2 green balls. The problem requires us to find the expected number of black balls that will be obtained before getting the first green ball.We draw balls with replacement and independently, one after another until we get the green ball. We denote the color of a ball drawn in the k-th round by X and introduce T = inf{n > 1: Xn green}.We can use the concept of conditional expectation to solve the problem.

Let EB be the expected number of black balls that we will obtain before we get the first green ball. Also, let EG be the expected number of balls that we will obtain in total until we get the first green ball.The first ball we draw is either white, black, or green. The probability of drawing a green ball on the first draw is p1 = 2/7, and the expected number of draws until we get the green ball is 1/p1 = 7/2.

The probability of drawing a black ball on the first draw is p2 = 2/7, and the expected number of black balls that we will obtain before we get the first green ball, given that we draw a black ball on the first draw, is 1 + EB. Similarly, the probability of drawing a white ball on the first draw is p3 = 3/7, and the expected number of black balls that we will obtain before we get the first green ball, given that we draw a white ball on the first draw, is EB.

Thus, using the law of total probability, we have:EG = p1(1) + p2(1 + EB) + p3(EB) Simplifying this equation, we get:EG = 1 + (2/7)EB + (3/7)EGSolving for EB, we get:EB = (7/2) - (3/4)EGThe expected number of black balls that we will obtain before we get the first green ball, denoted by k=1 ¹X₁-black, is:EB = (7/2) - (3/4)EG

Given that we draw with replacement and independently, the probability of drawing a green ball on any draw is always the same, and hence the expected number of draws until we get the first green ball is always the same. Therefore, we can use the same equation to calculate the expected number of black balls that we will obtain before we get the second, third, or any subsequent green ball, by simply replacing T with the number of draws until the desired green ball is obtained.

The expected number of black balls that we will obtain before we get the first green ball is (7/2) - (3/4)EG. Since we are interested only in the expected number of black balls that we will obtain before we get the first green ball, and not in the expected number of draws until we get the first green ball, we need to calculate EG. From the equation above, we have:EG = 1 + (2/7)EB + (3/7)EGSubstituting EB = (7/2) - (3/4)EG, we get:EG = 7/5

Hence, the expected number of black balls that we will obtain before we get the first green ball is:EB = (7/2) - (3/4)EG = (7/2) - (3/4)(7/5) = 7/10

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The vector is an eigenvector of the matrix with a corresponding eigenvalue of -4.

To determine if a vector is an eigenvector of a matrix, we need to check if the matrix-vector product is a scalar multiple of the vector. Let's denote the given matrix as A and the vector as v.

A = [-9 -8; 7 6; -5 -6; -6 10]

v = [7; -6; -6; 10]

To check if v is an eigenvector, we compute the matrix-vector product Av and check if it is a scalar multiple of v. Evaluating the product:

Av = [-9 -8; 7 6; -5 -6; -6 10] * [7; -6; -6; 10] = [-70; 49; 11; 4]

The resulting vector Av is not a scalar multiple of v, which means v is not an eigenvector of A.

However, if we made an error in the given matrix or vector, please provide the correct values so that we can re-evaluate and determine the eigenvector and corresponding eigenvalue accurately.

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Answer:

y=6x+50

Step-by-step explanation:

y is the total amount of money she is saving and y equals to the amount of money she got from walking the dog and the amount of money she was given by her grandma,so we have to find out how much she gets from walking the dogs.she gets paid 6 dollars everytime she walks the dog and we are told she walked the dog x times we will simply multiply 6 with x to get the total amount of money she earned ehich will come to a total of 6x .now that we have the money she got from dog walking we will add it up with the amount she got from her grandma which is 50 .making our answer y=6×+50

Ms. Roberts found that students who watched less TV tended to earn higher scores on their physics test. Therefore, she should conclude that there is a negative correlation between TV habits and physics test scores.

The correlation coefficient is a statistical measure that describes the direction and strength of the linear relationship between two variables.

In this case, we can infer that TV habits and physics test scores have a negative correlation coefficient, i.e., as TV habits decrease, physics test scores increase. The strength of the correlation would depend on the actual values of the correlation coefficient.

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Answer:

Let heads represent a person who exercises the given amount, and let tails represent a person who doesn’t. Because there are three people, flip the coin three times (once for each person) and note the results of each set of three flips. If all three flips land on tails, it would mean that all three randomly selected people do not exercise as much as 50% of Americans do.

Step-by-step explanation:

Answer:

AB

Step-by-step explanation:

ez

Answer:

E to C is a minor arc a major arc in this case would be E to G or F to H

Step-by-step explanation:

The coordinates of the specified vertex after the given sequence of transformations is given by;

Q' = (3, -3).

In Mathematics, the translation of a geometric figure to the right simply means adding a digit to the value on the x-coordinate (x-axis) of the pre-image of a function while a geometric figure that is translated up simply means adding a digit to the value on the y-coordinate (y-axis) of the pre-image or parent function.

Mathematically, a horizontal translation to the right is modeled by this mathematical expression g(x) = f(x + N) while a vertical translation to the positive y-direction (upward) is modeled by this mathematical expression g(x) = f(x) + N.

Where:

By translating the coordinate Q (1, 3) two (2) units to the right, we have the following:

Coordinate Q (1, 3) → Coordinate Q' (1 + 2, 3) = Q (3, 3)

In Mathematics, a reflection across the x-axis would maintain the same x-coordinate while the sign of the y-coordinate would change from positive to negative. Therefore, a reflection over the x-axis is given by this transformation rule:

(x, y)      →       (x, -y)

Coordinate Q' (3, 3) → (3, -3).

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The statement is true. If the row [0 0 0 1 0] is in echelon form of an augmented matrix, then the associated linear system is always consistent. This means there is at least one solution to the system of linear equations.

Echelon form is a type of row-echelon form that has specific properties. In echelon form, the leading coefficient (non-zero element) of each row is strictly to the right of the leading coefficient of the row above it. In the given row [0 0 0 1 0], the leading coefficient is 1, and it is the only non-zero element in the row.

In an augmented matrix, the rightmost column represents the constants or the right-hand side of the linear equations. Since the leading coefficient in the given row is 1 and there are no non-zero elements to the left of it, this implies that the associated linear equation is of the form 0x + 0y + 0z + w = 0. This equation simplifies to w = 0.

Since w is a free variable and its value can be chosen as 0, the linear system is consistent. Every consistent system has at least one solution, and in this case, the solution is when w = 0, while x, y, and z can take any values.

Therefore, if [0 0 0 1 0] is one row in an echelon form of an augmented matrix, the associated linear system is always consistent.

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Answer:

27$ for 2 and 99$ for 6

Step-by-step explanation:

you only get half off of one so 5 are still 18 and one is 9 which gives you 99.

Answer:

2 sheets 27 $ and 6 sheets 81 $

3 sheets 45$

Step-by-step explanation:

1 sheet =18$

2 sheet = 18 x 0.5 = 9$

2 sheet promotion 27$

Cost of 6 cheets 27$ x 3 = 81 $

3 sheets 18 + 9 + 18 =45$

Answer:

x = 34

Step-by-step explanation:

x/3  - 7/3 = 9

Combine like terms

(x-7)/3 = 9

Multiply each side by 3

(x-7)/3 * 3 = 9*3

x-7 = 27

Add 7 to each side

x-7+7 = 27+7

x = 34

The required positive numbers are 14.43, 14.43.

According to the statement

we have given that The product of two positive numbers is 208 and the sum is a minimum.

And we have to find these numbers.

So, For this purpose,

Let two positive numbers xy = 208

According to question xy = 208

And then

y = 208/x

and

sum of two positive numbers z=x+y

s= x+ 208/x

then

differentiate with respect to x

ds /dx = d/ dx(x+ 208/x)  -(1)

ds /dx = 1 - 208/ x^2

here ds /dx = 0. so,

1 - 208/ x^2 = 0

x^2 - 208= 0

x = 14.43.

And

differentiate the equation (1) again

d^2s /dx^2 = 0 + 416/x^2)  

then

∴ at point x= 14.43,

d^2s /dx^2 = 416/208.22

d^2s /dx^2 = 1.99

which is greater than zero.

∴ value of s minimum at point x = 14.43

so, y = 208/x

y = 208 /14.43

y = 14.43.

So, The required positive numbers are 14.43, 14.43.

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​

The two different types of factor analysis are confirmatory and exploratory.

A technique for simulating observed variables and their covariance structure in terms of unseen variables is component analysis (i.e., factors). The two different types of factor analysis are confirmatory and exploratory.

A key phase in the scale building process is exploratory factor analysis (EFA), which is a technique to examine the underlying structure of a group of observed variables. Factor extraction is EFA's first stage. We will talk about how principal components analysis and common factor analysis approach variance partitioning differently.

Confirmatory factor analysis (CFA), a technique for confirming a factor structure that has already been developed, will be covered in the seminar's last section. Identification, model fit, and degrees of freedom will be discussed in relation to the three-item, two-item, eight-item, one-factor, and two-factor CFAs. For the EFA and CFA portions of the seminar, respectively, SPSS and R (lavaan) will be used.

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A project to investigate the American West has been the Clark as well as Lewis Expedition, which was supported by the federal government.

The main goal of the mission was to study the Missouri and Columbia river in search of tributaries that would traverse from the heart of the nation to the Western Pacific.

This fleet's main goals are to investigate the Missouri River, investigate the newly acquired Lands, and discover a land way to the Pacific Ocean.

The Lewis and Clark Expedition represented the first time that Americans traveled this far out towards the West by sea and rivers.

Pike, who lost his life in the conflict, rose to fame among American soldiers. Lewis and Clark subsequently eclipsed him with his legacy. Presently, he is famed for his unsuccessful attempt to scale Pike's Peak.

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Substituting u = x^(2/3x^6) in the integral ∫ (2x^3)(x^2/3x^6)^5 dx and arriving at the solution  3∫(x^3)(u^5) du.

To evaluate the integral ∫ (2x^3)(x^2/3x^6)^5 dx, we can simplify the expression by making the substitution u = x^(2/3x^6). This substitution allows us to transform the integral into a simpler form, making it easier to evaluate.

Let's make the substitution u = x^(2/3x^6). Taking the derivative of both sides with respect to x gives us du = (2/3x^6)(x^(-1/3)) dx. Simplifying this equation, we have du = (2/3)dx.

Now, we can rewrite the original integral in terms of u as follows:

∫ (2x^3)(x^(2/3x^6))^5 dx = ∫ (2x^3)(u^5) dx.

Using our substitution, we can also rewrite x^3dx as (3/2)du. Substituting these into the integral, we have:

∫ (2x^3)(x^(2/3x^6))^5 dx = ∫ (2x^3)(u^5) dx = 2∫(x^3)(u^5)dx = 2∫(x^3)(u^5)(3/2)du.

Simplifying further, we have:

∫ (2x^3)(x^(2/3x^6))^5 dx = 2(3/2) ∫ (x^3)(u^5) du = 3∫(x^3)(u^5) du.

Now, we can evaluate this integral with respect to u, which gives us a simpler expression to work with. Once we find the antiderivative of (x^3)(u^5) with respect to u, we can substitute u back in terms of x to obtain the final result.

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Complete question:

evaluate the integral ∫ (2x^3)(x^2/3x^6)^5 dx by making the substitution u = x^(2/3x^6)

The new functions are:

(f + g)(x) = 3x - 4

(g - h)(x) = 6x - 4

(f o g)(x) = 2x - 4

(g o h)(x) = -8x - 1

And the value of (f-g)(3) = -2.

To find new functions, we can combine the given functions using arithmetic operations.

(f + g)(x) = f(x) + g(x) = (x - 1) + (2x - 3) = 3x - 4

(g - h)(x) = g(x) - h(x) = (2x - 3) - (1 - 4x) = 6x - 4

(f o g)(x) = f(g(x)) = f(2x - 3) = (2x - 3) - 1 = 2x - 4

(g o h)(x) = g(h(x)) = g(1 - 4x) = 2(1 - 4x) - 3 = -8x - 1

To find (f-g)(3), we need to evaluate the function (f - g) at x = 3:

(f - g)(3) = f(3) - g(3) = (3 - 1) - (2(3) - 3) = 1 - 3 = -2

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The given question is incomplete, the complete question is

If  f(x) = x -1, g(x) = 2x - 3, and h(x) = 1 - 4x, find the following new functions, as well as any values (f-g)(3)

(f + g)(x)

(g - h)(x)

(f o g)(x)

(g o h)(x)

you have to subtract from the $92.74 the $10 of the monthly fee, and then that is divided by the additional amount per minute, so that gives us the result I use it 1379 minutes

Answer:

(3,1) should be the answer

Step-by-step explanation:

Hope this helps!

The ordered pair at this point is (3,1)

Suppose the graph is drawn on the coordinate plane.

Let the shifting be (x,y) → (x+a, y+b)

Then, add 'a' to all x coordinates of the graph's points. Add 'b' to all y coordinates of the graph's points.

The resultant set of new points will be plotted.

Given;

From origin; move to right 3units

                     move upward 1unit

Moving to right 3units;

(0,0)= (3,0)

Move upward 1unit;

(3,0)= (3,1)

Therefore, the point on graph after shifts will be (3,1)

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The gallons needed to paint the silo is 10.

A cylinder is a three-dimensional object. It is a prism with a circular base. The total surface area of cylinder can be determined by adding the area of all its faces.

Total surface area of the cylinder excluding its base = 2πrh +πr²

Where:

TSA = (2 x 3.14 x 10 x 30) + (3.14 x 10²)

314 + 1884 = 2198 ft²

Number of gallons needed = 2198 / 224 = 9.81 = 10 gallons

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