SOH CAH TOA

I don't understand this stuff I have a test coming up can someone pls help me with this i am stuck​

No as their no difference in Mr. Goodman's evaluation and the History department

What is Statistics ?

The study of statistics is the field that deals with the gathering, structuring, analyzing, interpreting, and presenting of data. In order to apply statistics to an issue in science, business, or society, it is customary to start with a statistical population or a statistical model that will be investigated.

descriptive statistics types in mathematics The data in this type of statistics is summarized using the provided observations. Statistics that are inferential. To interpret the meaning of descriptive statistics, this kind of statistics is employed. Example of Statistics.

Seeing the data we can conclude that their no difference in Mr. Goodman's evaluation and the History department

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Answer:

A

Step-by-step explanation:

not sure gusto ko lang tumulong

If JK║LM, all of the statements that are true include the following:

A. JK and LM do not intersect.

B. JK and LM are parallel.

D. JK and LM lie in the same plane.

In Mathematics and Geometry, parallel lines can be defined as two (2) lines that are always the same (equal) distance apart and never meet or intersect.

Based on the information provided about line segment JK and line segment LM, we can reasonably infer and logically deduce the following true statements:

In conclusion, line segments JK and LM are both parallel lines.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

y - 13 = 3(x - 5)

Step-by-step explanation:

x represents week and y represents inches. Week 2 and week 5 = 2 to 5 = three number difference. The inches which is 4 and 13 have a 9 inched difference. So like I said week represents x and y represent inches so now u have to find the slope, which would be y/x so replace it with the numbers we got so it would now be 9/3. The simplified version would be 3. So the slope is 3.

Point-slope equation: y-y^1=m(x-x^1), y^1 and x^1 are just some random points on the graph, but since we don't have a graph we can use either week 2 and 4 inches or week 5 and 13 inches because if this were a graph, those would be existing points on the graph. And m is the slope so just replace m with 3. We'll use 5 and 13 so: y - 13 = 3(x - 5)

side note: kinda took a long time sorry haha, I had to refresh my knowledge on point-slope equations since it's been a long time since i learned it.

The solution to the system of equations is (45, –30)

The equations are given as:

y =-4/5x + 6

y = –30

Substitute y = –30  in y =-4/5x + 6

-30 =-4/5x + 6

Subtract 6 from both sides

-36 = -4/5x

Divide both sides by -4

9 = 1/5x

Multiply both sides by 5

x = 45

So, we have:

(x,y) = (45, –30)

Hence, the solution to the system of equations is (45, –30)

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Answer:

(45, –30)

Step-by-step explanation:

Answer:

yessir

Step-by-step explanation:

The solution of the given initial value problem, x'' + 33.64x = 4cos(6t), with x(0) = x'(0) = 0, can be expressed as a sum of the homogeneous solution and the particular solution.

To find the solution, we start by solving the homogeneous equation, x'' + 33.64x = 0. The characteristic equation associated with this homogeneous equation is \(r^2 + 33.64 = 0\), which yields the roots

r = ±i√33.64. Thus, the homogeneous solution can be expressed as

x_h(t) = A*cos(√33.64*t) + B*sin(√33.64*t),

where A and B are constants determined by the initial conditions.

Next, we need to find the particular solution for the forced oscillation. Since the right-hand side of the equation is of the form Acos(ωt), where ω = 6, we assume a particular solution of the form x_p(t) = C*cos(ω*t + φ), where C and φ are constants to be determined. Taking the derivatives, we have x_p''(t) = -ω^2*C*cos(ω*t + φ) and x_p'(t) = -ω*C*sin(ω*t + φ). Substituting these into the original equation, we obtain -ω^2*C*cos(ω*t + φ) + 33.64*C*cos(ω*t + φ) = 4*cos(ω*t).

To satisfy this equation, the coefficient of the cosine term must be 4, while the coefficient of the sine term must be zero. This gives us two equations: -ω^2*C + 33.64*C = 4 and -ω*C = 0. Solving these equations, we find C = 4/(33.64 - ω^2) and φ = 0. Therefore, the particular solution is x_p(t) = (4/(33.64 - ω^2))*cos(ω*t).

Finally, we combine the homogeneous solution and the particular solution to obtain the complete solution:

x(t) = x_h(t) + x_p(t) = A*cos(√33.64*t) + B*sin(√33.64*t) + (4/(33.64 - ω^2))*cos(ω*t).

By substituting the initial conditions x(0) = x'(0) = 0 into this equation, we can determine the values of A and B. With the obtained values, the final solution for the initial value problem can be expressed in terms of the given constants and the trigonometric functions involved.

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Answer:

No.

Step-by-step explanation:

Here i put it in a graph for you to see.

Answer:

the awnser is 30

Step-by-step explanation:

mario and peach equal the same, so you would have to do 36÷3 and that equals 12, so then you look at mario divided by toad, and you would do 12÷2 to get 6, so toad would be 6, and that make bowser 0. so it would be 12+0+12+6=30

Answer:

25 is A , 26 is B , 27 is C , and 28 is C

Step-by-step explanation:

hope this helped

mark me brainilest :D

Answer:

25 is A , 26 is B , 27 is C , and 28 is C

Step-by-step explanation:

The cubic equation is used to describe the glide path of a plane. The given information states that the plane is in level flight at an altitude of 1 mile and starts its descent 6 miles east of the airport.

The question provides information about the altitude of the plane is in and starts its descent 6 miles east of the airport. However, since the equation itself is not provided, we cannot determine the exact shape or characteristics of the glide path.
To better understand the glide path described by the cubic equation, we need to know the equation itself. Unfortunately, the equation is not provided in the question. Without the equation, we cannot determine the exact shape or characteristics of the glide path.
However, a cubic equation typically has the form:
y = ax^3 + bx^2 + cx + d
Where x represents the horizontal distance and y represents the vertical distance (altitude) from the ground. The coefficients a, b, c, and d determine the specific shape of the curve.
Without the specific equation, we cannot provide explanation or examples based on the given information. We would need the equation to calculate and visualize the glide path accurately.
In summary, the question provides information that the plane is in level flight at an altitude of 1 mile and starts its descent 6 miles east of the airport, about a plane's glide path being described by a cubic equation. However, since the equation itself is not provided, we cannot determine the exact shape or characteristics of the glide path.

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Answer:

b

Step-by-step explanation:

Answer:

B. 8\(\sqrt{2}\)

Step-by-step explanation:

if angle A is 90 and B is 45 then C must be 45 (all three angles must add to 360)

this is an isosceles right triangle and the ratio of legs to hypotenuse is 1 : \(\sqrt{2}\)

so if each leg is 8 then the hypotenuse is that value multiplied by \(\sqrt{2}\)

The slope of a logarithmic graph depends on the type of logarithm used.

For a logarithmic function in the form y = log(b,x) where b is the base of the logarithm, the slope of the graph is undefined for x=0 and for x<0 because logarithmic functions are not defined in those cases.

For a natural logarithm, the slope is negative infinity at x=0 and positive for x > 0. As x increases, the slope becomes closer to zero.

For a common logarithm, the slope is negative infinity at x=0 and positive for x > 0. As x increases, the slope becomes closer to zero.

It's important to note that logarithmic functions are not linear functions, and therefore they do not have a constant slope, the slope of a logarithmic graph will change throughout the graph.

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We have one possible triangle, ABC, with angles A = 33 degrees, B ≈ 82.2 degrees, and C ≈ 64.8 degrees, and sides a = 15 in., b ≈ 16.7 in., and c ≈ 12.6 in.

We can use the sine formula to find the length of side b:

sin(A) = opposite/hypotenuse

sin(33) = 9/b

b = 9/sin(33) ≈ 16.7 in.

Now, we can use the law of cosines to find the length of side c:

c^2 = a^2 + b^2 - 2abcos(C)

cos(C) = (a^2 + b^2 - c^2)/(2ab)

cos(C) = (15^2 + 16.7^2 - c^2)/(215*16.7)

cos(C) ≈ 0.417

C ≈ 64.8 degrees

So we have one possible triangle, ABC, with angles A = 33 degrees, B ≈ 82.2 degrees, and C ≈ 64.8 degrees, and sides a = 15 in., b ≈ 16.7 in., and c ≈ 12.6 in.

However, we could also have another triangle, DEF, with angles D = 147 degrees, E ≈ 82.2 degrees, and F ≈ 10.8 degrees, and sides d = 9 in., e ≈ 16.7 in., and f ≈ 15 in. This is because the given measurements only determine the ratios of the sides of a triangle, and it is possible to construct a triangle with the given ratios but with different angles.

Therefore, there are two distinct triangles that can be made with the given measurements.

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Answer:

5

Step-by-step explanation:

the are is pi times radius times radius

so do the square root of 25, which is 5.

this means that the radius is 5

Answer:

five (5).

Step-by-step explanation:

Area of circle =pi r^2

given that area is 25pi

now equate both .....we get

25pi=pi r^2

25=r^2

r=5

The sample space when choosing one marble is C. S = {g, r, b, y, o}

A sample space is a collection of potential outcomes from a random experiment, it should be noted. The sample space is identified by the letter "S." Events are a subset of the potential outcomes of an experiment. The results in a sample space can vary depending on the experiment.

A set of potential outcomes from a random experiment is known as a sample space. The sample space is the collection of all possible values that an event set might have. The size of the sample space is determined by the total number of outcomes.

In conclusion, since the paper bag has five colored marbles. The marbles are red, green, blue, yellow, and orange. The correct option is C.

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Answer:

x=8.5

y=-3.5

Step-by-step explanation:

lets say  x=5-y

substituting x in the other equation gives -3(5-y)+2y=5

-15+3+2y=5

2y=5+15-3

2y=17

y=8.5

from equation 1    : x+8.5=5

x=5-8.5

x=-3.5

Answer:

Please see the attached picture for full solution...

Hope it helps...

Good luck on your assignment...

Answer: 3.33

Step-by-step explanation:

Multiplication and division should be solved left to right.

\(37/100*9\\\\Divide(100)\\\\0.37*9\\\\Multiply(9)\\\\3.33\)

Hope it helps <3

Answer:

=37/100×9=.

=divide 37 by 100

=0.37 ×9

=3.33

The integral using integration by parts with the indicated choices of u and dv is equal to,   \(\int\limits 5x^{2} lnx dx\) = \(\frac{5x^{3} }{3} (ln(x)-\frac{1}{3} )\) + c

Basic Power Rule:

f(x) = cxⁿ

f’(x) = c· n xⁿ⁻¹

Integration

Integrals

[Indefinite Integrals] Integration Constant C

Integration Property [Multiplied Constant]:              

\(\int\limits cf(x)dx\) = c \(\int\limitsf(x) dx\)

Integration Rule [Reverse Power Rule]:

\(\int\limits x^{n} dx\) = \(\frac{x^{n+1} }{n+1}\) + c

Integration by Parts:  

\(\int\limits u dv\) = uv - \(\int\limits v du\)

Given that,

= \(\int\limits 5x^{2} lnx dx\)

Rewrite [Integration Property - Multiplied Constant]:

\(\int\limits 5x^{2} lnx dx\) = 5 \(\int\limits x^{2} lnx dx\)

Set u:  

u = \(lnx\)

[u] Logarithmic Differentiation:          

du = \(\frac{1}{x}\) dx

Set dv:  

dv = \(x^{2}\)                                                                                                        

[dv] Integration Rule [Reverse Power Rule]:  

v = \(\frac{x^{3} }{3}\)

Integration by Parts:  

\(\int\limits 5x^{2} lnx dx\) = 5 \(( \frac{x^{3}ln(x) }{3} - \int\limits \frac{x^{2} }{3} dx )\)

Rewrite [Integration Property - Multiplied Constant]:  

\(\int\limits 5x^{2} lnx dx\) = 5 \((\frac{x^{3}ln(x) }{3} -\frac{1}{3} \int\limits x^{2} dx )\)

Factor:  

\(\int\limits 5x^{2} lnx dx\) = \(\frac{5}{3} (x^{3} ln(x) - \int\limits x^{2} dx )\)

Integration Rule [Reverse Power Rule]:  

\(\int\limits 5x^{2} lnx dx\) = \(\frac{5}{3} (x^{3} ln(x) - \frac{x^{3} }{3} )\) + c

Factor:

\(\int\limits 5x^{2} lnx dx\) = \(\frac{5x^{3} }{3} (ln(x)-\frac{1}{3} )\) + c

Therefore,

The integral using integration by parts with the indicated choices of u and dv is equal to,   \(\int\limits 5x^{2} lnx dx\) = \(\frac{5x^{3} }{3} (ln(x)-\frac{1}{3} )\) + c

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Based on the differential equation a) Solving the DE subject to P(0) = P0 will yield P = ((kP0 - h)e^(kt) + h)/k. b) For the three cases given (P0 > h/k, P0 = h/k, P0 = 0), the behavior of the population P(t) is will be population will grow without bound, the population will remain constant, and the population will decrease and approach zero as t approaches infinity respectively. c) The fish population will go extinct in finite time if there exists a time T > 0 such that P(T) = 0. At T = (1/k)ln(-h/(kP0 - h)) the fish population will go extinct.

(a) To solve the differential equation (dP/dt) = kP - h subject to P(0) = P0, we need to separate the variables and integrate both sides:

(dP/dt) = kP - h

dP/(kP - h) = dt

∫dP/(kP - h) = ∫dt

ln|kP - h| = kt + C

kP - h = e^(kt + C)

P = (e^(kt + C) + h)/k

Using the initial condition P(0) = P0, we can solve for C:

P0 = (e^(k*0 + C) + h)/k

P0 = (e^C + h)/k

e^C = kP0 - h

C = ln(kP0 - h)

Substituting back into the equation for P, we get:

P = (e^(kt + ln(kP0 - h)) + h)/k

P = ((kP0 - h)e^(kt) + h)/k

This is the solution to the differential equation subject to the initial condition P(0) = P0.

(b) The behavior of the population P(t) for increasing time depends on the initial condition P0:

- If P0 > h/k, then the term (kP0 - h)e^(kt) will be positive and will increase exponentially as t increases, so the population will grow without bound.

- If P0 = h/k, then the term (kP0 - h)e^(kt) will be zero and the population will remain constant at P = h/k for all time.

- If P0 < h/k, then the term (kP0 - h)e^(kt) will be negative and will decrease exponentially as t increases, so the population will decrease and approach zero as t approaches infinity.

(c) The fish population will go extinct in finite time if there exists a time T > 0 such that P(T) = 0. From the equation for P, we can see that this will happen if and only if P0 < h/k:

P(T) = ((kP0 - h)e^(kT) + h)/k = 0

(kP0 - h)e^(kT) = -h

e^(kT) = -h/(kP0 - h)

Since the exponential function is always positive, this equation has no solution for P0 > h/k or P0 = h/k. However, if P0 < h/k, then the term (kP0 - h) is negative and the equation has a solution:

kT = ln(-h/(kP0 - h))

T = (1/k)ln(-h/(kP0 - h))

This is the time at which the fish population will go extinct.

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Answer:

i think its a. 13

Step-by-step explanation:

ok, so with the angles we are given, its an equalateral triangle. (all angles are 60*) with this we know everything is equal to each other. so if thats the case, it should be 13

Weighing the available information and assigning a probability.

A sort of probability called subjective probability is one that is based on a person's subjective assessment or personal knowledge of the likelihood of a particular result. It solely represents the subject's thoughts and prior experience and does not include any formal computations. A "gut instinct" used when making a deal is an illustration of subjective probability.

So, as per the definition of subjective probability

Dividing the number of favourable events by the number of possible events and Studying the fraction of times in the past a particular event has happened, both can be determined through calculations mathematically accurate but for Weighing the available information and assigning a probability we might use a "gut instinct". Thus

Weighing the available information and assigning a probability.

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Answer:

x = 2, y = - 25

Step-by-step explanation:

(1)

note that 36 = 6² , then

\(6^{x}\) = 6²

Since bases on both sides are equal then equate the exponents

x = 2

------------------------------------------

(2)

Using the rule of exponents

\((a^m)^{n}\) = \(a^{mn}\)

note that 25 = 5² , then

\(25^{11+3y}\) = \((5^2)^{11+3y}\) = \(5^{22+6y}\)

Then

\(5^{5y-3}\) = \(5^{22+6y}\)

Since bases on both sides are equal then equate the exponents

22 + 6y = 5y - 3 ( subtract 5y from both sides )

22 + y = - 3 ( subtract 22 from both sides )

y = - 25

The area of the composite shape is 155 yd². And the right option is A-155 yd².

A composite shape is any shape that is made up of two or more geometric shapes.

The area of the composite shape can be calculated using the formula below

Note: The composite shape in the question, is made up of a tripezium and a parallelogram.

Formula:

Where:

From the diagram,

Given:

Substitute these values into equation 1

Hence, the area is 155 yd².

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A coordinate system is a two-dimensional number line, for example, two perpendicular number lines or axes.

This is a typical coordinate system:

coordinate plane1

The horizontal axis is called the x-axis and the vertical axis is called the y-axis.

The center of the coordinate system is called the origin. The axes intersect when both x and y are zero. The coordinates of the origin are (0, 0).

An ordered pair contains the coordinates of one point in the coordinate system. That is named by its ordered pair of the form of (x, y).

The first number corresponds to the x-coordinate and the second to the y-coordinate.

To graph a point, we have to draw a dot at the coordinates that correspond to the ordered pair. It is one of the best ways to start at the origin.

The x-coordinate shows how many steps have to take from positive to negative on the x-axis, the same as the y-coordinate tells how to have many steps from positive to negative on the y-axis.

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Step-by-step explanation:

See image below

Answer:

Width = 3 m

Step-by-step explanation:

Formula for perimeter:

P = l + w + l + w

Plug in what we know:

14 = 4 + w + 4 + w

Isolate variable w (width):

14 = 8 + 2w

6 = 2w

3 = w

Check your work:

14 = 4 + 3 + 4 + 3

14 = 7 + 7

14 = 14

Correct!

(Don't forget to add units in your answer!)

Answer: x=0, y=56

Step-by-step explanation:

If both triangles are proportional, plug in the equations.

As you can see, you have two equations to work with.

10x+y=56

3x+6=9

get rid of x as a variable first by multiplication.

30x+3y=168

30x+60=90

3y=168

168/3=56

y=56

Now solve for x.

10x+(56)=56

10x=0

x=0