Simplify
What is 315/6 simplified

The time-series model that assumes that demand in the next period will be equal to the most recent period's demand is A) Naive approach.

This model is based on the simplest assumption of all, that the next period's demand will be equal to the current period's demand. It is called the naive approach because it assumes no underlying pattern in the data and provides a baseline prediction. The formula for the naive approach is as follows:

y(t) = y(t-1) where y(t) represents the demand in period t and y(t-1) represents the demand in the previous period.

Although this model is simple, it is often used as a benchmark for comparison with more complex models and can provide reasonable results for stable demand patterns.

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The height of the cylinder is 10.81 cm and the radius of the cylinder is 5.41 cm

The volume of the cylinder can = 1000 cubic cm

Consider the height of the cylinder as h and the radius of the base is r

Volume of the cylinder = π\(r^2\)h = 1000

h = 1000 / π\(r^2\)

The surface area of the cylinder

A = 2π\(r^2\) + 2πrh

A = 2π\(r^2\) + 2πr(1000 / π\(r^2\) )

A = 2π ( \(r^2\) + 1000 / π\(r^2\))

Differentiate the terms

A' =  2π (2r + 1000 / π\(r^3\))

When the minimum surface area

2π (2r + 1000 / π\(r^3\)) = 0

r = \((1000/2\pi )^\frac{1}{3}\)

r = 5.41 cm

Then,

h =  1000 / π\(r^2\)

= 1000 / (π × 5.41 × 5.41)

= 1000 / 91.94

= 10.87 cm

Hence, the height of the cylinder is 10.81 cm and the radius of the cylinder is 5.41 cm

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Answer:9

Step-by-step explanation:

Answer: x = 14/5 or x = 2.8

Step-by-step explanation:

Step 1: Divide both sides of the equation by five: a common nonzero real number.

(5x)/5= 14/5

Step 2: Simplify

x = 14/5

Let the number of weeks required be T

42 + 7T = 133

7T = 133 - 42

7T = 91

Divide both sides by 7

T = 91/7

T = 13

13 weeks is required.

TCP provides error checking to ensure reliable data delivery, making option A the correct answer. Only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

TCP (Transmission Control Protocol) provides error checking as part of its services. It ensures reliable data delivery by using acknowledgments and sequence numbers to detect and recover from packet loss, errors, or out-of-order delivery. When a TCP receiver receives data, it sends an acknowledgment (ACK) back to the sender to confirm the successful reception of packets. If the sender does not receive an ACK for a particular packet within a specified timeout period, it assumes the packet was lost or damaged and retransmits it.

TCP provides error checking to ensure reliable data delivery, making option A the correct answer.

The propagation delay is the time it takes for a signal to travel from the source to the destination. It is determined by the physical distance between the devices and the speed of signal propagation in the transmission medium. The propagation delay is an inherent characteristic of the medium and cannot be eliminated by switching devices or other strategies.

The other three options—processing delay, queuing delay, and transmission delay—are all caused by the store-and-forward strategy used by switching devices. Processing delay refers to the time taken to examine and process the packet headers. Queuing delay occurs when packets have to wait in a queue before being transmitted. Transmission delay is the time it takes to push the bits onto the transmission medium.

Among the given options, only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

3. The correct answer is A. The system is very well-engineered.

In a statistical multiplexing system, the queuing delay is the delay experienced by packets waiting in a queue before being transmitted. If the average queuing delay is very close to zero, it indicates that the system is well-engineered and efficiently managing its resources. A well-designed system can minimize or eliminate queuing delays by appropriately allocating resources and ensuring efficient scheduling algorithms.

Traffic intensity, which represents the ratio of the average traffic load to the transmission capacity, does not directly determine the queuing delay. It is possible to have low queuing delays even with high traffic intensity if the system is well-designed.

When the average queuing delay is close to zero, it suggests that the system is well-engineered and efficiently utilizing its resources, as stated in option A.

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Answer:

2

Step-by-step explanation:

3.60+3.60=7.20 thats correct

Marks of Bobbie = x

Then, marks of Georgia

= 3 times marks of Bobbie

= 3 times m

= 3 × m

= 3m

a) The parameter of interest is the percentage of mail items received at the dorm that are considered packages. This can be denoted as p, where p is the proportion of packages out of all mail items received at the dorm. A confidence interval would be most appropriate for this inference procedure.

b) The parameter of interest is the difference in the average number of packages sent from online retailers to a neighborhood in Champaign and the average number of packages sent from online retailers to a neighborhood in Urbana. This can be denoted as μ1 - μ2, where μ1 is the average number of packages sent to Champaign and μ2 is the average number of packages sent to Urbana. A hypothesis test would be most appropriate for this inference procedure.

c) The parameter of interest is the difference in store pick-up rates between all cookies and all cakes sold by the bakery. This can be denoted as p1 - p2, where p1 is the proportion of cookies that are picked up in store and p2 is the proportion of cakes that are picked up in store. A confidence interval would be most appropriate for this inference procedure.

d) The parameter of interest is the association between the weight of the package and the delivery time. This can be denoted as ρ, where ρ is the correlation coefficient between the weight of the package and the delivery time. A hypothesis test would be most appropriate for this inference procedure.

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Answer:

0.89 g/cm³

Step-by-step explanation:

used the formula d=M/V

M is mass which is = 80g

V is volume which is = 90cm³

d = 80/90

d = 0.89 g/cm³

Answer: -7.6n + 11.1

Step-by-step explanation:

We will simplify the given expression by combining like-terms.

   Given:

3.1 - 4.6n - 3n + 8

  Subtract like-terms:

3.1 - 7.6n + 8

   Add like-terms:

11.1 - 7.6n

Answer:

\( \sf \: -7.6n + 11.1 \)

Step-by-step explanation:

Now we have to,

→ Simplify the given expression.

The expression is,

→ 3.1 - 4.6n - 3n + 8

Let's simplify the expression,

→ 3.1 - 4.6n - 3n + 8

→ -4.6n - 3n + 3.1 + 8

→ (-4.6n - 3n) + (3.1 + 8)

→ (-7.6n) + (11.1)

→ -7.6n + 11.1

Hence, the answer is -7.6n + 11.1.

Answer: the answer is C

Answer:

x = 154°

Step-by-step explanation:

Given information,

→ The line l & m are parallel to each other.

Now we have to,

→ Find the required value of x.

We know that,

→ Parallel lines are equal to each other.

Forming the equation,

→ x + 26° = 180°

Then the value of x will be,

→ x + 26° = 180°

→ x = 180° - 26°

→ [ x = 154° ]

Hence, the value of x is 154°.

The area of a rectangle can be calculated with this formula:

Where "l" is the length and "w" is the width.

The area of a circle can be found with this formula:

Where "r" is the radius of the circle.

Let be "d" the diameter of the circle shown in the picture. Since it touches the rectangle at two points, you can identify that:

Since the radius of a circle is half the diameter, in this case this is:

Therefore, the area of the circle is:

Now you must find the total area of the rectangle. Knowing that:

You get:

In order to find the total area of the shaded region, you must subtract the total area of the rectangle and the area of the circle. Then, this is:

The answer is: Option D.

To determine whether there is enough evidence to reject the null hypothesis, we need to compare the computed test statistic to the critical value.

In this case, the computed test statistic is 2.50 and the critical value is 2.33. If the computed test statistic falls in the rejection region beyond the critical value, we can reject the null hypothesis. Conversely, if the computed test statistic falls within the non-rejection region, we fail to reject the null hypothesis.In this scenario, since the computed test statistic (2.50) is greater than the critical value (2.33), it falls in the rejection region. This means that the observed data is unlikely to occur if the null hypothesis were true.

Therefore, based on the given information, there is enough evidence for the emergency room nurse to reject the null hypothesis. This suggests that there is sufficient evidence to support the claim that the average number of cases of upper respiratory infections per day at the hospital is over 21 cases.

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There is enough evidence to reject the null hypothesis in this case because the computed test statistic (2.50) is higher than the critical value (2.33). This suggests the average number of daily respiratory infections exceeds 21, providing substantial evidence against the null hypothesis.

Yes, there is enough evidence for the emergency room nurse to reject the null hypothesis. The null hypothesis is typically a claim of no difference or no effect. In this case, the null hypothesis would be an average of 21 upper respiratory infections per day. The test statistic computed (2.50) exceeds the critical value (2.33). This suggests that the average daily cases indeed exceed 21, hence providing enough evidence to reject the null hypothesis.

It's crucial to understand that when the test statistic is larger than the critical value, we reject the null hypothesis because the observed sample is inconsistent with the null hypothesis. The statistical test indicated a significant difference, upheld by the test statistic value of 2.50. The significance level (alpha) of 0.05 is a commonly used threshold for significance in scientific studies. In this context, the finding suggests that the increase in respiratory infection cases is statistically significant, and the null hypothesis can be rejected.

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The annual interest rate for the bank account is r = 3.7 %

Given data ,

A = P(1 + r/n)^(nt)

where A is the amount after t years, P is the principal (initial amount), r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time in years.

a)

To find the principal, we can use the information from the first year:

$1739.50 = P(1 + r/n)^(n*5)

$1739.50 = P(1 + r/n)^5

We don't know the values of P, r, or n, but we can simplify the equation by dividing both sides by (1 + r/n)^5:

$1739.50 / (1 + r/n)^5 = P

Now we can use the information from the second year to solve for r:

$1803.40 = P(1 + r/n)^(n*6)

$1803.40 = ($1739.50 / (1 + r/n)^5) * (1 + r/n)^6

Simplifying, we get:

$1803.40 = $1739.50 * (1 + r/n)

Dividing both sides by $1739.50, we get:

1.036928 = 1 + r/n

Subtracting 1 from both sides, we get:

0.036928 = r/n

b)

To find the annual interest rate, we need to solve for r.

We know that r/n = 0.036928, so we can solve for r by multiplying both sides by n:

r = 0.036928n

$1739.50 = P(1 + r/n)^5

Substituting r = 0.036928n, we get:

$1739.50 = P(1 + 0.036928n/n)^5

Simplifying, we get:

$1739.50 = P(1.036928)^5

Dividing both sides by (1.036928)^5, we get:

P = $1500

Now we can substitute P = $1500 and r/n = 0.036928 into the equation r = 0.036928n and solve for r:

r = 0.036928n = 0.036928 * 1 = 0.036928

Hence , the annual interest rate is 3.7%

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Answer: 2

Step-by-step explanation:

Answer:

x = a²

Step-by-step explanation:

To undo the square root, you have to square both sides of the equation so it becomes...

(√x )² = a²

That undoes the square soot so it is

x = a²

As the sample size (n) increases, the power of the statistical test also increases.

The power of a statistical test measures the ability of the test to detect a true effect or reject a false null hypothesis. In this case, the investigator states that the power of his test at a significance level of 1% is 0.87. If the sample size (n) increases, the power of the test increases.

Increasing the sample size generally leads to an increase in the power of a statistical test. This is because a larger sample size provides more information and reduces the variability in the data. With a larger sample size, the test has a greater chance of detecting a true effect and rejecting the null hypothesis when it is false. Consequently, the power of the test increases.

In summary, as the sample size (n) increases, the power of the statistical test also increases. This is because a larger sample size enhances the test's ability to detect true effects and reject false null hypotheses, resulting in higher statistical power. Therefore, in this scenario, increasing the sample size would lead to an increase in the power of the test.

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Answer:

4z-12

Step-by-step explanation:

the perimeter is the sum of all sides

so

\(P=(z+3)+(z-9)+(z+3)+(z-9)\\\\P=z+3+z-9+z+3+z-9\\\\P=4z+6-18\\\\P=4z-12\)

The rate of change or essentially the slope is a numerical value that describes the direction and the steepness of the line.

To find the slope, we just need any two points on the line

       --> Let's pick (0,2) and (2,6)

The slope's equation = \(\frac{y2-y1}{x2-x1}\)

Let's plug the known quantities into the equation

     \(\frac{y2-y1}{x2-x1}=\frac{6-2}{2-0} =\frac{4}{2} =2\)

Therefore the rate of change is 2 km/trip

Hope that helps!

Answer:

(-1,2) is domain

Step-by-step explanation:

The probability that the mean cost for plan Amazing will be more than the mean cost for plan Best is 0.9975.

To calculate the probability that the mean cost for plan Amazing will be more than the mean cost for plan Best, we first need to calculate the difference between the two means. The difference between the two means is $1.99. We then need to calculate the standard error of the difference. The standard error of the difference is calculated by taking the square root of the sum of the squared standard deviations divided by each sample size. In this case, the standard error of the difference is 0.6. Finally, we use the z-score formula to calculate the probability. The z-score formula is (mean difference - 0)/standard error of the difference. In this case, the z-score is 3.31. Using a z-score table, we can find that the probability that the mean cost for plan Amazing will be more than the mean cost for plan Best is 0.9975.

Standard Error of Difference = sqrt((13.58^2/37)+(7.18^2/40)) = 0.6

z-score = (1.99-0)/0.6 = 3.31

Probability = 0.9975

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If a car traveling at 40 mph requires 80 feet to stop, the stopping distance S of a car varies directly as the square of its speed v and is equal to 180 feet.


Given, the stopping distance S of a car varies directly as the square of its speed v. So the relation can be represented as,

S ∝ v2

Here, the constant of proportionality is k.

S = kv2 ——— (1)

Given, when the speed v = 40 mph, stopping distance s = 80 feet.

Therefore, from equation (1), we have

80 = k × 402

k = 80/1600

k = 0.05

Hence, the relation between the stopping distance S and the speed v of the car can be given as

S = 0.05v2

To find the stopping distance S of the car at speed v = 60 mph, substitute v = 60 in the above equation.

S = 0.05 × 602

S = 0.05 × 3600

S = 180 feet

Therefore, the stopping distance of a car traveling at 60 mph would be 180 feet.


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Answer:

6000.000 + 900.000 + 0 + 5 + 3/10 + 2/100 + 7/1000

six thousand nine hundred and five ones point(.) three tenths two hundredths and seven thousandths

Step-by-step explanation:

right!!!

Answer:

632.4

Step-by-step explanation:

Answer:

C=2πr=2·π·32≈201.06193in

Answer:

D is the answer gggcvfffbhfdchj