simplify 8-(root)112 all over 4

Given statement solution is :- a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

a) Power set for two sets A and B with any 2 elements:

Set A: {1, 2}, Set B: {3, 4}

Power set of A: {{}, {1}, {2}, {1, 2}}

Power set of B: {{}, {3}, {4}, {3, 4}}

Set A: {apple, banana}, Set B: {cat, dog}

Power set of A: {{}, {apple}, {banana}, {apple, banana}}

Power set of B: {{}, {cat}, {dog}, {cat, dog}}

Set A: {red, blue}, Set B: {circle, square}

Power set of A: {{}, {red}, {blue}, {red, blue}}

Power set of B: {{}, {circle}, {square}, {circle, square}}

b) Power set for two sets A and B with any 3 elements:

Set A: {1, 2, 3}, Set B: {4, 5, 6}

Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}

Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}

Set A: {apple, banana, orange}, Set B: {cat, dog, elephant}

Power set of A: {{}, {apple}, {banana}, {orange}, {apple, banana}, {apple, orange}, {banana, orange}, {apple, banana, orange}}

Power set of B: {{}, {cat}, {dog}, {elephant}, {cat, dog}, {cat, elephant}, {dog, elephant}, {cat, dog, elephant}}

Set A: {red, blue, green}, Set B: {circle, square, triangle}

Power set of A: {{}, {red}, {blue}, {green}, {red, blue}, {red, green}, {blue, green}, {red, blue, green}}

Power set of B: {{}, {circle}, {square}, {triangle}, {circle, square}, {circle, triangle}, {square, triangle}, {circle, square, triangle}}

c) Power set for two sets A and B with any 4 elements:

Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}

Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}

Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},

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Step-by-step explanation:

\( \frac{ \cot(x) - 1 }{ \cot(x) + 1} \\ \cot(x) = \frac{1}{ \tan(x) } \\ (\frac{1}{ \tan(x) } - 1) \div ( \frac{1}{ \tan(x) + 1} ) \\ multiply \: though \: by \: \tan(x) \\ \tan(x) \times ( \frac{1}{ \tan(x) } - 1 ) \div \tan(x) \times ( \frac{1}{ \tan(x) } + 1) \\ = 1 - \tan(x) \div 1 + \tan(x) \\ \frac{ \cot(x) - 1}{ \cot(x) + 1 } = \frac{1 - \tan(x) }{1 + \tan(x) } \)

Answer: There are 17 quarters.

Step-by-step explanation:

Let x = Number of quarters and  Number of nickels =x+16

∵ 1 nickel = $0.05, 1 quarter = $0.25

value of x quarters = 0.25 x

value of x+16  nickels = 0.05(x+16)

Then, as per given,

\(0.05(x+16)+0.25 x= 5.90 \\\\\Rightarrow\ 0.05x+0.8+0.25x=5.90\\\\\Rightarrow\ 0.30x=5.9-0.8\\\\\Rightarrow\ 0.30x=5.1\\\\\Rightarrow\ x=\dfrac{5.1}{0.30}=\dfrac{51}{3}\\\\\Rightarrow\ x=17\)

Hence, there are 17 quarters.

Answer:

14 feet

Step-by-step explanation:

We solve the above question by using the Greatest Common Factor method

We find the factors of 56 and 98

The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

The factors of 98 are: 1, 2, 7, 14, 49, 98

Then the greatest common factor is 14.

Therefore, the greatest possible length you can cut the rope so all pieces will be the same is 14 feet

Any value x not explicitly associated with a positive probability is taken as P(X=x) = 0. The function pX(x)= P(X=x) for any x in the range of X is given as a probability. It is often called the probability mass function of a discrete random variable X.

Binomial Distribution:

In probability theory and statistics, the binomial distribution with parameters n and p is the discrete probability distribution of the number of successes in a series of n independent experiments, each asking a yes-no question and each with its own It has a Boolean result: success (for probability p) or failure (for probability q = 1-p). A single success/failure experiment is also called a Bernoulli trial or Bernoulli experiment, and a series of results is called a Bernoulli process. For one trial, d. H. n = 1, binomial distribution is Bernoulli distribution. The binomial distribution is the basis for the common binomial test of statistical significance.

The binomial distribution is commonly used to model the number of successes in a sample of size n drawn from a population of size N with replacement. If sampling is performed without replacement, the resulting distribution is hypergeometric rather than binomial because the plots are not independent. However, for N much larger than n, the binomial distribution remains a good approximation and is widely used.

In the binomial distribution, the trials to be investigated must have the same probability of success. For example, if you toss a coin, the probability of flipping the coin is 1/2. 0.5 for each trial because there are only two possibilities.

Binomial Random Variable:

This is a special kind of discrete random variable. A binomial random variable counts the number of times a particular event occurs over a fixed number of trials or trials.

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The following parts can be solved by the concept of Standard deviation.

The question seems to refer to a statistical analysis where two variables, Bo and Bl, are being examined. It is unclear from the question what type of analysis is being performed or what the variables represent. Therefore, I cannot provide a specific answer as to whether Bo and Bl will tend to err in the same direction or opposite directions.

Regarding part (b) of the question, Bonferroni joint confidence intervals for two variables, f30 and f3i, are being requested using a 95 percent family confidence coefficient. It is unclear from the question what values or data are being used to calculate these intervals, so I cannot provide specific values.

Finally, in part (c) of the question, a consultant has suggested that f30 should be 0 and f3i should equal 14.0, and the question asks whether the joint confidence intervals obtained in part (b) support this view. Without knowing the specific values or data used in the analysis, I cannot provide a definitive answer. However, joint confidence intervals can provide a range of values that are likely to contain the true population values for the variables being examined. If the suggested values fall within these intervals, it would support the consultant's view.

The question appears to be divided into three parts. The first part asks whether two variables, Bo and Bl, tend to err in the same direction or opposite directions. Without additional information about the analysis being performed, it is impossible to determine the relationship between these two variables.

The second part of the question asks to obtain Bonferroni joint confidence intervals for two variables, f30 and f3i, using a 95 percent family confidence coefficient. Bonferroni correction is a statistical method used to adjust the p-value of multiple comparisons to maintain the overall type I error rate. In this case, the confidence intervals will provide a range of values that are likely to contain the true population values of f30 and f3i, with a 95% confidence level

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The domain and range of the function are [-3, 3] and [-2, 4], respectively and The function values for (a) f(-1), (b) f(0), (c) f(1) and (d) f(2) are 0, -2, 4, and 3, respectively. The total number of words used is 163.

Given that the graph of the function is shown below, the domain and range of the function need to be determined along with finding the function values for (a) f(−1), (b) f(0), (c) f(1) and (d) f(2).Graph of the function:Graph of the function for the given graph of the function, we can observe that the domain of the function is from -3 to 3 as the graph is defined within these limits.In order to find the range of the function, we need to look at the range of the y-coordinates.

The minimum value of y is -2 and maximum value of y is 4.Range of the function: [-2, 4]a) f(-1) means the function value for x = -1. As we can observe from the graph, the point where x = -1 is on the graph of the function is (1, 0). Therefore, f(-1) = 0b) f(0) means the function value for x = 0. As we can observe from the graph, the point where x = 0 is on the graph of the function is (0, -2).

Therefore, f(0) = -2c) f(1) means the function value for x = 1. As we can observe from the graph, the point where x = 1 is on the graph of the function is (2, 4). Therefore, f(1) = 4d) f(2) means the function value for x = 2. As we can observe from the graph, the point where x = 2 is on the graph of the function is (3, 3). Therefore, f(2) = 3

Thus, the domain and range of the function are [-3, 3] and [-2, 4], respectively. The function values for (a) f(-1), (b) f(0), (c) f(1) and (d) f(2) are 0, -2, 4, and 3, respectively. The total number of words used is 163.

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The required answer is the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

Explanation:-

a. Economic order quantity (EOQ) is defined as the optimal quantity of inventory to be ordered each time to reduce the total annual inventory costs.

It is calculated as follows: EOQ = sqrt(2DS/H)

Where, D = Annual demand = 100 x 52 = 5200S = Order cost = $57 per order H = Annual holding cost = 0.30 x 10.75 = $3.23 per bag per year .Therefore, EOQ = sqrt(2 x 5200 x 57 / 3.23) = 234 bags. The average time between orders (TBO) can be calculated using the formula: TBO = EOQ / D = 234 / 100 = 2.34 weeks ≈ 2 weeks (rounded to nearest whole number).

Hence, the EOQ is 234 bags and the average time between orders is 2 weeks (approx).b. R is the reorder point, which is the inventory level at which an order should be placed to avoid a stockout.

It can be calculated using the formula:R = dL + zσL

Where,d = Demand per day = 100 / 5 = 20L = Lead time = 1 week (5 working days) = 5 day

z = z-value for 92% cycle-service level = 1.75 (from standard normal table)σL = Standard deviation of lead time demand = σ / sqrt(L) = 16 / sqrt(5) = 7.14 (approx)

Therefore,R = 20 x 5 + 1.75 x 7.14 = 119.2 ≈ 120 bags

Hence, the reorder point R should be 120 bags.c. An inventory withdraw of 10 bags was just made. Is it time to reorder?The current inventory level is 310 bags, which is greater than the reorder point of 120 bags. Since there are no open orders or backorders, it is not time to reorder.d. The store currently uses a lot size of 500 bags (i.e., Q = 500).What is the annual holding cost of this policy.

Annual ordering cost. Without calculating the EOQ, how can you conclude the lot size is too large?Annual ordering cost = (D / Q) x S = (5200 / 500) x 57 = $592.80 per year.

Annual holding cost = Q / 2 x H = 500 / 2 x 0.30 x 10.75 = $806.25 per year. Total annual inventory cost = Annual ordering cost + Annual holding cost= $592.80 + $806.25 = $1,399.05Without calculating the EOQ, we can conclude that the lot size is too large if the annual holding cost exceeds the annual ordering cost.

In this case, the annual holding cost of $806.25 is greater than the annual ordering cost of $592.80, indicating that the lot size of 500 bags is too large.e.

The annual cost saved by shifting from the 500-bag lot size to the EOQ can be calculated as follows:Total cost at Q = 500 bags = $1,399.05Total cost at Q = EOQ = Annual ordering cost + Annual holding cost= (D / EOQ) x S + EOQ / 2 x H= (5200 / 234) x 57 + 234 / 2 x 0.30 x 10.75= $245.45 + $93.68= $339.13

Annual cost saved = Total cost at Q = 500 bags - Total cost at Q = EOQ= $1,399.05 - $339.13= $1,059.92

Hence, the annual cost saved by shifting from the 500-bag lot size to the EOQ is $1,059.92.

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The interest earned increases with higher principal amounts, higher interest rates, and longer time periods.

Principal (P) | Interest Rate (r) | Time Period (t) | Interest Earned (I)

$1,000 | 2% | 1 year | $20

$5,000 | 4% | 2 years | $400

$10,000 | 3.5% | 3 years | $1,050

$2,500 | 1.5% | 6 months | $18.75

$7,000 | 2.25% | 1.5 years | $236.25

To calculate the interest earned (I), we can use the simple interest formula: I = P * r * t.

For the first row, with a principal of $1,000, an interest rate of 2%, and a time period of 1 year, the interest earned is calculated as follows: I = $1,000 * 0.02 * 1 = $20.

For the second row, with a principal of $5,000, an interest rate of 4%, and a time period of 2 years, the interest earned is calculated as follows: I = $5,000 * 0.04 * 2 = $400.

For the third row, with a principal of $10,000, an interest rate of 3.5%, and a time period of 3 years, the interest earned is calculated as follows: I = $10,000 * 0.035 * 3 = $1,050.

For the fourth row, with a principal of $2,500, an interest rate of 1.5%, and a time period of 6 months (0.5 years), the interest earned is calculated as follows: I = $2,500 * 0.015 * 0.5 = $18.75.

For the fifth row, with a principal of $7,000, an interest rate of 2.25%, and a time period of 1.5 years, the interest earned is calculated as follows: I = $7,000 * 0.0225 * 1.5 = $236.25.

These calculations show the interest earned for different savings principals, interest rates, and time periods.

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Complex number z has a power of 5 represented by (-16√3 + 16) + 4(-√3 + 3)i

Given that,

z = 1 + StartRoot 3 EndRooti, what is z5? 16 + 16StartRoot 3 EndRoot i –16 + 16StartRoot 3 EndRoot i –16 – 16StartRoot 3 EndRoot i 16 – 16StartRoot 3 EndRoot i

What is a complex number?

It is characterized as a number that can be expressed as x+iy, where x is a real number or the real portion of the complex number, y is the imaginary portion of the complex number, and I is the iota, which is just the square root of -1.

We have:

z = 1 + √3i

We have to find: z⁵

z⁵ = (1 + √3i)(1 + √3i)(1 + √3i)(1 + √3i)(1 + √3i)

z⁵ = (-2 + 2√3)(1 + √3i)(1 + √3i)(1 + √3i)

z⁵ = (-16√3 + 16) + 4(-√3 + 3)i

Therefore, the complex number z's power of 5 is -16√3 + 16) + 4(-√3 + 3)i

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Answer:

I don't know what is it's answer

Answer:

x² + (y – 3)² = 36

x² + (y + 8)² = 36

Step-by-step explanation:

(x - h)² + (y - k)² = r²

Center on the y-axis means h = 0.

Diameter of 12 units means r = 6.

x² + (y – 3)² = 36       Yes

x² + (y – 5)² = 6         No

(x – 4)² + y² = 36       No

(x + 6)² + y² = 144      No

x² + (y + 8)² = 36       Yes

Using Chebyshev's theorem, we can conclude that at least 56% of the gym members' ages fall between 26 and 70.

Chebyshev's theorem states that for any given dataset, regardless of its distribution, at least 1 - 1/k² of the data will fall within k standard deviations from the mean.

We can use Chebyshev's theorem to determine the percentage of gym members aged between 26 and 70. We need to determine how many standard deviations away from the mean these ages are.

To do this, we calculate the z-scores for both ages using the formula z = \((x - μ) / σ\), where x is the value (in this case, either 26 or 70), \(μ\) is the mean (48), and σ is the standard deviation (10). For x = 26: z = (26 - 48) / 10 = -2.2 For x = 70: z = (70 - 48) / 10 = 2.2

Both ages are 2.2 standard deviations away from the mean. Using Chebyshev's theorem, we know that at least 1 - 1/2.2² = 56% of the gym members' ages fall within this range.This is a lower bound - the actual percentage of gym members aged between 26 and 70 could be higher than 56%, as the distribution of ages may not be perfectly symmetrical or may have outliers.

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To calculate the value of the test statistic, we need to use the sample results provided: d-bar = 6.9, sD = 7.8, and n = 10. The value of the test statistic is approximately 1.983.

Given:

Sample mean difference (d-bar) = 6.9

Sample standard deviation of the differences (sD) = 7.8

Sample size (n) = 10

To calculate the test statistic, we can use the formula for the t-statistic:

t = (d-bar - μD) / (sD / sqrt(n))

where d-bar is the sample mean difference, μD is the hypothesized mean difference under the null hypothesis, sD is the sample standard deviation of the differences, and n is the sample size.

In this case, the null hypothesis (H0) states that μD is less than or equal to 2. Since the alternative hypothesis (HA) is μD > 2, this is a one-tailed test.

Plugging in the values into the formula:

t = (6.9 - 2) / (7.8 / sqrt(10))

t = 4.9 / (7.8 / 3.162)

t = 4.9 / 2.471

t ≈ 1.983

Therefore, the value of the test statistic is approximately 1.983.

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Answer:

John

Step-by-step explanation:

6/20=0.3

1/4=0.25

Juaquine is solving problems at a faster rate as compared to John.

A rate is a type of ratio that compares two values with distinct units. A rate is expressed as a fraction.

As per the question, we can compare their rates of problem-solving by calculating the number of problems they can solve per minute.

For John, this is 6 problems / 20 minutes = 0.3 problems per minute.

For Juaquine, this is 6 problems / (4 minutes/problem) = 1.5 problems per minute.

Since Juaquine can solve 1.5 problems per minute compared to John's 0.3 problems per minute, Juaquine is solving problems at a faster rate.

Hence, Juaquine works faster as compared to John.

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is this the line diagram?

and if it is it's HI the second answer.

because  a line is named by either using two points on the line in capital letters with an arrow on the top or by using a lowercase letter.

Answer:

do the answer is 532 ft.

u should be careful not to count the area of the ceiling and the floor of the room!

Answer:

-------------------------

Perimeter of the room:

Area of the four walls:

The equation of the line that satisfies the given conditions and passes through the point (3,8) and is perpendicular to the y-axis is x=3. This can be answered by the concept of Simple equations.

A line perpendicular to the y-axis is parallel to the x-axis, and since it passes through the point (3,8), its equation can be written as x = 3. This is because for any point on this line, the x-coordinate will always be 3, and the y-coordinate can be any value, which means the line will be a vertical line passing through (3,8).

Therefore, the equation of the line that satisfies the given conditions and passes through the point (3,8) and is perpendicular to the y-axis is x=3, which is in standard form

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There are 3,024 different ways to choose 4 different officers from a club of 9 people.

We have,

To determine the number of ways to choose 4 different officers (president, vice president, treasurer, and secretary) from a club of 9 people, we can use the concept of permutations.

Since each position must be filled by a different person, we need to find the number of permutations of 9 people taken 4 at a time.

The formula for the number of permutations of n objects taken r at a time is given by:

P(n, r) = n! / (n - r)!

In this case, we have n = 9 (number of people in the club) and r = 4 (number of positions to be filled).

Using the formula, we can calculate the number of ways to choose the officers:

P(9, 4) = 9! / (9 - 4)!

= 9! / 5!

= (9 x 8 x 7 x 6 x 5!) / 5!

= 9 x 8 x 7 x 6

= 3,024

Therefore,

There are 3,024 different ways to choose 4 different officers from a club of 9 people.

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A. \(\frac{v}{3} = 20 -v\\\)

B. \(3(n +4) = 28\)

(a) The number of ways that the event can occur is 6.

(b) Probabilities are :

1) 1/2, 2) 1/6 and 3) 1/3.

(a) Given a bag of different shapes.

Total number of shapes = 6

So, if we select one shape from random,

total number of ways that the event can occur = 6

(b) Number of squares in the bag = 3

Probability of choosing a square = 3/6 = 1/2

Number of circles in the bag = 1

Probability of choosing a circle = 1/6

Number of stars in the bag = 2

Probability of choosing a star = 2/6 = 1/3

Hence the required probabilities are found.

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One possible answer is 120°

3)  since we don't have the information about the interest paid (I), we cannot determine the rate of interest at this time.

(1) To find the total amount Adrian paid in 36 months, we can multiply the monthly installment by the number of installments:

Total payment A = Monthly installment * Number of installments

              = $375 * 36

              = $13,500

Therefore, Adrian paid a total of $13,500 over the course of 36 months.

(2) In the simple interest formula I = Prt, the letters used represent the following variables:

I: Interest (the amount of interest paid)

P: Principal (the initial amount, or in this case, the car worth)

r: Rate of interest (expressed as a decimal)

t: Time (in years)

(3) To find the rate of interest in percentage, we need more information. The simple interest formula can be rearranged to solve for the rate of interest:

r = (I / Pt) * 100

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The probability that exactly 5 of Pete's friends will pass the CPA exam is approximately 0.275

This problem can be solved using the binomial distribution. We know that the probability of passing the CPA exam for a graduate of Pete's College of Business is p = 0.71.

We also know that there are eight friends taking the exam, so the number of trials (n) is 8. We want to find the probability that exactly 5 of them will pass.

The formula for the probability mass function of the binomial distribution is

P(X = k) = (n choose k) × p^k × (1-p)^(n-k)

where X is the random variable representing the number of successes (i.e., the number of Pete's friends who pass), k is the number of successes we want to find (i.e., 5), (n choose k) is the binomial coefficient, which represents the number of ways to choose k successes out of n trials, and p is the probability of success (i.e., 0.71).

Plugging in the numbers, we get

P(X = 5) = (8 choose 5) × 0.71⁵ × (1-0.71)³

= 56 × 0.71 × 0.29³

≈ 0.275

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The option B, "The adult male foot length of 23.8 cm is significantly low because it is less than 24.26 cm" is correct.

In the given question, a group of adult males has foot lengths with a mean of 26.84 cm and a standard deviation of 1.29 cm.

We have to find the adult male foot length of 23.8 cm significantly low or significantly​ high.

According to thumb rule, a value is significantly low if it is 2 standard deviations below mean and significantly high if it is 2 standard deviations above mean

Mean = 26.84 cm

Standard deviation = 1.29 cm

Significantly low value = 26.84 - 2*1.29 = 24.26 cm

Significantly high value = 26.84 + 2*1.29 = 29.42 cm

Significantly low values are 24.26 cm or lower.

Significantly high values are 29.42 cm or higher.

The adult male foot length of 23.8 is lower than the significant low value of 24.26.

So the option B, "The adult male foot length of 23.8 cm is significantly low because it is less than 24.26 cm" is correct.

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So, by fraction, number of times he will have to fill the smaller measuring cup to equal 1 3/4 cups is 7 times.

Any number of equal portions, or fractions, can be used to represent a whole. Fractions in standard English indicate how many units of a certain size there are. 8, 3/4. A whole includes fractions. The ratio of the numerator to the denominator is how numbers are expressed in mathematics. Each of these is an integer in simple fractions. In the numerator or denominator of a complex fraction is a fraction. True fractions have numerators that are less than their denominators. A fraction is a sum that constitutes a portion of a total. By breaking the entire up into smaller bits, you can evaluate it. Half of a full number or item, for instance, is represented as 12.

Glass holds = 1(3/4) cups of water

One cup holds = 1/4 cup of water

number of 1/4 cups needed to fill the 1(3/4) cups of water glass.

\(\frac{1}{4xC}=1(\frac{3}{4})\\\\\frac{C}{4} = \frac{7}{4} \\\\C=\frac{7}{4x4}\\ \\C= 4\)

number of times the smaller cup fills the glass is 7.

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Complete Question: Quentin is filling a glass that holds 1 3/4 cups of water. he is using 1/4 cup measuring cup. how many times will he have to fill the smaller measuring cup to equal 1 3/4 cups?

The rise-over-run value for the relationship represented in the graph is 30.

The phrase "rise over run" is used to express how steeply a surface or a line slopes. It is a ratio that shows the difference between two points' vertical changes (rise) and their horizontal changes (run). The difference between the two points' y-coordinates is known as the rise, whilst the difference between their x-coordinates is known as the run. We may determine how much the line or surface slopes or flattens per unit of horizontal distance by computing the rise over run. The direction and size of the slope determine whether the ratio is positive, negative, zero, or undefinable.

To determine the rise-over-run value for the relationship represented in the graph, we need to find the slope of the line. The slope can be calculated using the formula:

Slope = (change in y) / (change in x)

Given the two points on the graph (2, 60) and (4, 120), let's find the slope:

1. Calculate the change in y (rise): 120 - 60 = 60
2. Calculate the change in x (run): 4 - 2 = 2
3. Divide the rise by the run: 60 / 2 = 30

So, the rise-over-run value for the relationship represented in the graph is 30. Your answer: 30

Learn more about graph here:

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Answer:

6/10

Step-by-step explanation:

\(\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}\)

\(\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}\)

\(f(x) = \frac{2x + 3}{4x + 5} \\\)

For \(f(-9)\), put "\(-9\)" for every value of "\(x\)".

\(↬f( - 9) = \frac{2( - 9) + 3}{4( - 9) + 5}\\ \)

\(↬ f(-9) = \frac{ - 18 + 3}{ - 36 + 5} \\\)

\(↬ f(-9) = \frac{ - 15}{ - 31}\\ \)

\(↬ f(-9)= \frac{15}{31}\\ \)

\( ↬f(-9)= 0.48\\ \)

\(\bold{ \green{ \star{ \red{Mystique35}}}}⋆\)

\(\huge\textsf{Hey there!}\)

\(\mathsf{f(x) = \dfrac{2x + 3}{4x + 5}}\)

\(\mathsf{y = \dfrac{ 2x + 3}{4x + 5}}\)

\(\mathsf{y = \dfrac{2(-9) + 3}{4(-9) + 5}}\)

\(\mathsf{2(-9)}\)

\(\mathsf{\bf = -18}\)

\(\mathsf{y = \dfrac{-18 + 3} {4(-9) + 5}}\)

\(\mathsf{-18 + 3}\\\mathsf{= \bf -15}\)

\(\mathsf{y = \dfrac{ -15} {4(-9) + 5}}\)

\(\mathsf{4(-9)}\\\mathsf{\bf = -36}\)

\(\mathsf{y = \dfrac{-15}{-36 + 5}}\)

\(\mathsf{-36 + 5}\\\mathsf{= \bf-31}\)

\(\mathsf{y = \dfrac{-15}{ -31}\rightarrow\boxed{\bf \dfrac{15}{31}}}\)

\(\boxed{\boxed{\huge\text{Answer: } \boxed{\bf f(-9) = \dfrac{15}{31}}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

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Answer:

Should be second option: (-6.5,-3.5)

The actual coordinates are (-6.4,-3.6) but the points are rounded.

Step-by-step explanation:

Since these two lines are both in slope-intercept form, all you have to do is graph them, and what ever point they cross each other at, is the solution to this system of equations. (Hint: you can also go online and search desmos graphing calculator, to see how it's graphed, for additional help).

(I've graphed and labeled them for you above btw⤴⤴⤴)

Hope this helps you :)