Simple harmonic motion for a block of mass.
the problem gives x(t)= A cos( (k/m)^(1/2) * t) A block of mass m is attached to a spring whose spring constant is k. The other end of the spring is fixed so that when the spring is unstretched, the mass is located at x=0. Assume that the +x direction is to the right.

Answers

Answer 1

we obtain  v0 =−xm ωsinϕ=3.06m/s.

What is  harmonic motion?

When the restoring force is proportionate to the displacement but acting in the opposite direction, an oscillating mass moves in a manner known as harmonic motion. The sine wave has a constant frequency and amplitude and can be used to describe harmonic motion because it is periodic.

What is mass?

The amount of matter in a particle or object is represented by its mass, which is denoted by the symbol m. In the International System (SI), the kilogram serves as the default unit of mass (kg).

ω= mK = 2.00kg/10100Nm

=7.07rad/s.

Energy methods provide one method of solution. Here, we use trigonometric techniques based on Eq.  x=x m cos(ωt+ϕ)  and Eq.  v=−ωx

msin(ωt+ϕ).

(a) Dividing Eq.  v=−ωxm

sin(ωt+ϕ)  by  Eq.x=xmcos(ωt+ϕ),  we obtain  

xv=−ωtan(ωt+ϕ)  

So that the phase  (ωt+ϕ) is found from ωt+ϕ=tan−1( ωx−v )=tan −1( (7.07rad/s)(0.129m)

−3.415m/s).

With the calculator in radians mode, this gives the phase equal to  –1.31rad.  Plugging this back into Eq.x=xmcos(ωt+ϕ),  leads to  0.129m=xmcos(−1.31) ⇒xm=0.500m.

(b) Since  ωt+ϕ=–1.31rad  at  t=1.00s, we can use the above value of  ω  to solve for the phase constant  ϕ. We obtain  ϕ=–8.38rad  (though this, as well as the previous result, can have  2π  or  4π  (and so on) added to it without changing the physics of the situation). With this value of  ϕ, we find  x0=xmcosϕ=−0.251m.

(c) And we obtain  v0 =−xm ωsinϕ=3.06m/s.

Therefore, we obtain  v0 =−xm ωsinϕ=3.06m/s.

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Related Questions

1. Each of four boys were given
some marbles.
have
day.
punc
exan
class
Joe: sixth multiple of eight
Khal: quarter of a gross
mar
Tate: 4 dozen
Tevin: one score plus a dozen
Which two boys r3eceived the same
number of marbles?
A. Joe and Tate
B. Joe and Khal
C. Tate and Tevin
D. Joe and Tevin​

Answers

Answer:

the answer is A because

from tate 4 dozen is 48 and from joe the sixth multiple of eight is 48

The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths (the reddest colors) to the shortest wavelengths (the deepest violet colors) our eyes can detect. Wavelengths near 655 nm are perceived as red. Those near 515 nm are green and those near 475 nm are blue. Calculate the frequency of light (in Hz) with a wavelength of 655 nm, 515 nm, and 475 nm.
HINT
(a)
655 nm
Hz
(b)
515 nm
Hz
(c)
475 nm
Hz

The rainbow of visible colors in the electromagnetic spectrum varies continuously from the longest wavelengths

Answers

Answer:

The frequency of light can be calculated using the formula:

`c = λv`

Where `c` is the speed of light in a vacuum, `λ` is the wavelength of light, and `v` is the frequency of light.

The speed of light in a vacuum is `3.00 × 10^8 m/s`.

To convert the wavelength from nanometers to meters, we need to divide by `1 × 10^9`.

Thus, the frequency of light with a wavelength of 655 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(655 × 10^-9 m)`

`v = 4.58 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`.

Similarly, the frequency of light with a wavelength of 515 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(515 × 10^-9 m)`

`v = 5.83 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz`.

Finally, the frequency of light with a wavelength of 475 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(475 × 10^-9 m)`

`v = 6.32 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

So, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz` and the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

The speed limit on some interstate highways is roughly 90 km/h. (a) What is this in meters per second

Answers

Answer:

25 m/s

Explanation:

⠀⠀⠀⇒ Speed = 90 km/h

⠀⠀⠀⇒ Speed = 90 km/60 min [As 1 hr = 60 min]

⠀⠀⠀⇒ Speed = (90 × 1000) m/(60 × 60)sec

⠀⠀⠀⇒ Speed = 90000 m/3600 sec

⠀⠀⠀⇒ Speed = 900 m/36 sec

⠀⠀⠀⇒ Speed = 300 m/12 sec

⠀⠀⠀⇒ Speed = 100 m/4 sec

⠀⠀⠀⇒ Speed = 25 m/s


What is the most significant change in the comet's energy as it moves from
point D to point A?
OA. KE decreases, GPE decreases
OB. KE decreases, GPE increases
OC. KE increases, GPE decreases
OD. KE increases, GPE increases

What is the most significant change in the comet's energy as it moves frompoint D to point A?OA. KE decreases,

Answers

The most significant change in the comet's energy as it moves from point D to point A KE increases, GPE decreases.Option C is correct.

What are comets?

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ice.

They range from a few miles to tens of miles wide, but as they orbit closer to the Sun, they heat up and spew gases and dust into a glowing head that can be larger than a plane.

As the comet transitions from point D to point A, the biggest energy shift is seen. GPE declines as KE rises. The right answer is C.

Hence option C is correct.

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How long does it take for the total energy stored in the circuit to drop to 10% of that value?

Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.

Answers

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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Simple physics (Final) (Pic provided)

Simple physics (Final) (Pic provided)

Answers

Answer:

15m/s

Explanation:

Divide distance by time

How do I find an apparent weight in N for a metal connected to a string submerged in water if a scale shows the mass 29.52 g when it is submerged ? Also how do I measure its density

Answers

The Tension of the string is going to be less when submerged in water by a value called the buoyancy force, so below in the attached file is explanation on how to calculate the apparent weight and density of the submerged object

How do I find an apparent weight in N for a metal connected to a string submerged in water if a scale

Which of the following is a pure substance?

Which of the following is a pure substance?

Answers

the answer to your question is D
Yes I agree that it is D as well

The middle ear provides impedance matching between air and fluid by?


Answers

The middle ear provides impedance matching between air and fluid by the reduction in area between the tympanic membrane and the stapes footplate.

What is the middle ear?

Middle ear is part of ear that separates the outer ear from the inner ear.

The middle ear consists of the following bones:

hammer (malleus),

anvil (incus), and

stirrup (stapes).

The middle ear provides impedance matching between air and fluid by

the reduction in area between the tympanic membrane and the stapes footplate and

the mechanical advantage of the lever formed by the malleus and incus.

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Using the given temperature and pressures, determine: a) the diameter of the water scale model balloon (m), b) the weight of the scale model, c) the specific gravity of the buoyant material such that the model conditions will be similar to the full-scale balloon.

Answers

Complete Question

Complete Question is attached below

Answer:

a)  \(D=0.7\)

b)  \(W=1787.5N\)

c)  \(\rho'=998.19kg/m^3\)  

Explanation:

From the question we are told that:

Hot air:

Temperature \(T_a=360K\)

Pressure \(P_a=100kPa\)

Distance \(d=12m\)

Weight \(W=1400N\)

Water:

Temperature \(T_w=300K\)

Pressure \(P_w=100kPa\)

Since we have The same Reynolds number

a)

Generally the equation for equal Reynolds number is mathematically given by

Re_{air}=Re_{water}

Therefore

\(\frac{\rho V D}{\mu_{air}}=\frac{p_{water}*V*D}{\mu_{water]}}\)

\(\frac{100*12}{300*0.28*1.81*10^{-3}}}=\frac{998*D}{0.000890}\)

\(D=0.7\)

b)

Generally the equation for Weight of scale is mathematically given by

\(W=\rho*V*g\)

\(W=998*\frac{4}{3}*\pi*0.35^3*9.81\)

\(W=1787.5N\)

c)

Generally the equation for Density of buoyant material is mathematically given by

\(\rho'=\frac{w}{g*V}\)

\(\rho'=\frac{1781.5}{\frac{4}{3}*\pi*0.35^3*9.81}\)

\(\rho'=998.19kg/m^3\)

Using the given temperature and pressures, determine: a) the diameter of the water scale model balloon

Weather hazards and natural disasters such as tsunamis, earthquakes, and flooding are considered which type of migration factor?
A. Pull factor
B. Both push and pull factors
C. Neither push or pull factor
D. Push factor

Answers

Push factor.

Push factors lead people to leave their current location
Pull factors lead people to come to a specific location

[brainliest appreciated]

Answer:

D. Push Factor

Explanation:

Pull factors are known as positive aspects of a place that make people want to stay/remain in that area.Push factors are known as negative aspects of a place that make people want to leave/depart from that area.

Weather hazards and natural disasters are horrendously negative things that people actively seek to avoid; they make people want to leave or depart from an area in order to escape them. As such, they are considered push factors.

(Weather hazards and natural disasters are not pull factors because when discussing push vs pull we are specifically describing the mentioned factor. This aspect is not considered both because the migration factor mentioned in this question actively makes people want to move to any area that avoids their issue. Remember that pull factors make people want to move to a specific place for a unique advantage, while push factors make people want to move to any general place for a common advantage.)

Which of the following is not a sub-discipline of basic sciences?

a.
Physics

b.
Chemistry

c.
Mathematics

d.
Logic​

Answers

Answer:

D

Explanation:

Physics and Chemistry are the most basic disciples in science, so the answer is not A or B.

Mathematics is the language of science; it could be the answer.

Most likely, you are looking for logic which describes the validity of an argument that has already been developed. I would pick D, but your marker may not agree.

B. Calculate the total resistance of the circuit below. (4 points)



c. In the circuit diagram above, meters 1 and 2 are connected as shown. Write 2 - 3 sentences identifying each type of meter and how it is connected with the 30.0 Ω resistor in the circuit. (4 points)




d. In the circuit diagram above, predict which resistors (if any) will stop working when the switch is opened. Write 2 - 3 sentences explaining your reasoning. (4 points)

B. Calculate the total resistance of the circuit below. (4 points)c. In the circuit diagram above, meters

Answers

B. The equivalent resistance of the two resistors is 20.0 ohms.

C. The voltmeter will measure the voltage across the 30.0 ohm resistor.

D. The 30.0 ohm resistor will stop working.

How to determine resistance?

B. The total resistance of the circuit is 60.0 ohms. This is because the 30.0 ohm resistor and the 60.0 ohm resistor are in parallel, and the equivalent resistance of two resistors in parallel is equal to the product of the resistors divided by the sum of the resistors.

R_T = 1/(1/R_1 + 1/R_2 + ...)

In this case, the product of the resistors is:

30.0 ohms × 60.0 ohms = 1800 ohms,

and the sum of the resistors is:

30.0 ohms + 60.0 ohms = 90.0 ohms.

Therefore, the equivalent resistance of the two resistors is 1800 ohms / 90.0 ohms = 20.0 ohms.

C. Meter 1 is an ammeter, and it is connected in series with the 30.0 ohm resistor. This means that the ammeter will measure the current flowing through the 30.0 ohm resistor.

Meter 2 is a voltmeter, and it is connected in parallel with the 30.0 ohm resistor. This means that the voltmeter will measure the voltage across the 30.0 ohm resistor.

D. When the switch is opened, the 30.0 ohm resistor will stop working. This is because the switch is in series with the 30.0 ohm resistor, and when the switch is opened, the circuit is broken.

The 60.0 ohm resistor will continue to work, because it is in parallel with the switch, and the current will continue to flow through the 60.0 ohm resistor even when the switch is opened.

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A rigid body acted upon by a set of forces . The magnitude of the forces are as follows F1=3N,F2=6N,F3=3N,F4=4N,F5=3Nand F6=3N. Identify the couple among these forces

Answers

The forces F3 and F6 form a couple since they are parallel, act in the same directions, and have the same magnitude (both are 3N), but they do not have the same point of application.

A couple is a pair of equal but disjointed forces that act in opposite directions and along parallel lines of force.

The rigid body rotates about its center of mass as a result of the forces acting on it at various places.

We can observe that the forces F3 and F6 in the provided set of forces are parallel, have the same magnitude of 3N, and act in opposite directions.

However, because they are applied to various locations on the rigid body, the body will rotate as a result. The stiff body tends to rotate around its center of mass because of this phenomenon, which is known as a couple.

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An electron confined to a one-dimensional box of width 0.52 nm by infinite potential energy barriers emits a photon when it makes a transition from the third excited state to the ground state. Find the wavelength of the emitted photon (in nm).

Answers

Answer:

24.8 :D

Explanation:

A car travels at a constant 60 km per hour in the positive direction down a straight line highway. What is the displacement, in standard units, of the car 45 minutes later? A.

Answers

Answer:

s = 45000 m

Explanation:

The displacement covered by a person or an object traveling at a constant speed can be calculated by the following formula:

s = vt

where,

s = displacement = ?

v = velocity of car = (60 km/h)(1 h/3600 s)(1000 m/1 km) = 16.67 m/s

t = time taken = (45 min)(60 s/1 min) = 2700 s

Therefore,

s = (16.67 m/s)(2700 s)

s = 45000 m

specific heat of a substance depends on which factor ​

Answers

Answer:

Explanation:

It depends on the substance's weight/capacity.

3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?​

Answers

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Select the correct answer.
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?
O A 100 khmeters/hour south
OB. 200 kilometers/hour
Ос.
200 kilometers/hour north
OD.
100 kilometers/hour

Answers

Answer:

D

Explanation:

The velocity of the car would be 100 kilometer per hour.

D that should be correct boo

Outline 3 disadvantages and advantage of water and alcohol as a template liquid​

Answers

Answer:

Advantages of mercury as a thermometric liquid.

-It is a good conductor of heat and therefore the whole liquid reaches the temperature of the surroundings quickly.

-It does not wet (cling to the sides of) the tube.

-It has a high boiling point

-It expands uniformly (linear expansion) and responds quickly to temperature changes, hence is sensitive.

-It has a visible meniscus.

Disadvantages

-Mercury is very poisonous.

-its expansively is fairly low

-it is expensive

-It has a high freezing point therefore it cannot be used in places where the temperature gets very low.

Alcohol has a thermometric fluid

-Alcohol expands uniformly.

-It has a low freezing point (-115 degreecentigrade) therefore it is very suitable for place where the temperature gets very low.

-It has a large expansively

-It is an easily available cheap liquid, which is safe to use

Disadvantages of alcohol

-it wets the tube

-it has a low boiling point (cannot be used in places with high temperatures)

-it does not react quickly to changes in temperature

-It needs to be dyed, since it's colourless.

Disadvantages of water

-Water has high specific heat capacity. So it cannot be used for measuring small temperature differences.

- Water will wet the surface of the glass tube. It is a sticky substance.

- Water is transparent

Explanation:

In a certain lab experiment, a spring gun was placed on a table and fired a steel ball horizontally outward. A student determines that the ball starts 1.0 m above the floor and travels 2.7 m before striking the floor

In a certain lab experiment, a spring gun was placed on a table and fired a steel ball horizontally outward. A student determines that the ball starts 1.0 m above the floor and travels 2.7 m before striking the floor.

(a) Determine the time that the ball is in the air. (2 pts)
(b) Determine the initial velocity of the ball. (2 pts)

Answers

a) The time that the ball is in the air is 0.23 second.

b)  The initial horizontal velocity of the ball is 11.74 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction.

Vertical height of the point = 1.0 meter.

The horizontal distance travelled by the ball = 2.7 m.

a) The time that the ball is in the air is = √(H/2g)

= √(1.0/2×9.8)

= 0.23 second

b) The initial horizontal velocity of the ball is = 2.7 m/0.23 s

= 11.74 m/s

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An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike

Answers

The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Which definition best explains coping strategy? the way a person handles an abusive relationship the thoughts and actions used to deal with changes in life a method of increasing stress and conflict a method used to escape a potentially dangerous event, such as using a whistle

Answers

Answer:

it is B

Explanation:

just took quiz

Answer:

B

Explanation:

When an aluminum bar is connected between a hot reservoir at 860 K and a cold reservoir at 348 K, 2.40 kJ of energy is transferred by heat from the hot reservoir to the cold reservoir
(a) In this irreversible process, calculate the change in entropy of the hot reservoir.
_______ J/K
(b) In this irreversible process, calculate the change in entropy of the cold reservoir.
_______ J/K
(c) In this irreversible process, calculate the change in entropy of the Universe, neglecting any change in entropy of the aluminum rod.
_______ J/K
(d) Mathematically, why did the result for the Universe in part (c) have to be positive?

Answers

Answer:

a) \(\Delta S_{in} = 2.791\,\frac{J}{K}\), b) \(\Delta S_{out} = 6.897\,\frac{J}{K}\), c) \(S_{gen} = 4.106\,\frac{J}{K}\), d) Due to irreversibilities due to temperature differences.

Explanation:

a) The change in entropy of the hot reservoir is:

\(\Delta S_{in} = \frac{2400\,J}{860\,K}\)

\(\Delta S_{in} = 2.791\,\frac{J}{K}\)

b) The change in entropy of the cold reservoir is:

\(\Delta S_{out} = \frac{2400\,J}{348\,K}\)

\(\Delta S_{out} = 6.897\,\frac{J}{K}\)

c) The total change in entropy of the Universe is modelled after the Second Law of Thermodynamics. Let assume that process is steady:

\(\Delta S_{in} - \Delta S_{out} + S_{gen} = 0\)

\(S_{gen} = \Delta S_{out} - \Delta S_{in}\)

\(S_{gen} = 6.897\,\frac{J}{K} - 2.791\,\frac{J}{K}\)

\(S_{gen} = 4.106\,\frac{J}{K}\)

d) Since irreversibilities create entropy as process goes by. The main source of irreversibilities is the existence of temperature differences.

A speed-time graph is shown below:
What is the average acceleration of the object represented
in the graph above over the eight seconds?
01.0 cm/s²
01.5 cm/s²
Speed vs. Time
O2.0 cm/s²
Time (s)

Answers

The average acceleration of the object represented in the given graph above over eight seconds is equal to 0.5 m/s².

What is acceleration?

Acceleration can be defined as the rate change of velocity with respect to time. The acceleration is a vector parameter with both magnitudes as well as directions.

Acceleration can be determined as the first derivative of the velocity of an object w.r.t. time.

\(\displaystyle a =\frac{v_f-v_o}{t}\)

From Newton's 2 law of motion, acceleration can be determined as:

a = F/m

Given, the initial velocity at time t = 0 is v = 0 m/s

The final velocity at time t = 8 is v = 4 m/s

\(\displaystyle a =\frac{4-0}{8}\)

a = 0.5 m/s²

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A speed-time graph is shown below:What is the average acceleration of the object representedin the graph

An alien spaceship traveling at 0.550c toward the Earth launches a landing craft. The landing craft travels in the same direction with a speed of 0.790c relative to the mother ship (as measured by aliens on the mother ship). As measured on the Earth, the spaceship is 0.160 ly from the Earth when the landing craft is launched.
(a) What speed do the Earth-based observers measure for the approaching landing craft?
c
(b) What is the distance to the Earth at the moment of the landing craft's launch as measured by the aliens (mother ship)?
ly
(c) What travel time is required for the landing craft to reach the Earth as measured by the aliens on the mother ship?
yr
(d*) What travel time is required for the landing craft to reach the Earth as measured by Earth-based observers?
yr
(e*) What travel time is required for the landing craft to reach the Earth as measured by those on the landing craft?
yr

Answers

(a)The velocity (Xv) of the craft as measured from the earth is given as follows:

Vx = v¹x+v/1+( v¹x+v/c²) = 0.79∝ + 0.550c/1+(0.79c)(0.550c)

= Vx = 0.434c

Hence Vx is the velocity of the craft with respect to the mother ship and the velocity of the mother ship with respect to earth.

(b) distance between craft and earth, as measured by the mother ship as follows.

\(L0 = \sqrt[L]{\frac{1-V^{2} }{C^{2} } } = (0.160ly)\sqrt{1-(\frac{0.550}{c})^{2} }\)

L0 = 0.1336ly.

(c)The velocity of craft with respect to earth as measured from the mother ship is as follows:

VCO = Vcmt + Vme

= 0.790 + 0.550 = 1.34c

Time taken by craft to land on earth as measured by the mother ship is as follows:

t =  0.1336ly/1.34 =  0.0997yr

(d) Time taken by craft to reach earth as measured from the earth is as follows:

t = 0.60ly/0.934c

t = 0.171yr

(e) Time taken by the craft to reach earth with respect to its rest frame is as follows:

to =\(\sqrt[t]{1-\frac{v^{2} }{c^{2} } }\)

= 0.171 yr \(\sqrt{1-\frac{(0.934c)^{2} }{c^{2} } }\)

to = 0.0610yr

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What does density show? Explain.​

Answers

Answer:

What is Density? The density of material shows the denseness of that material in a specific given area. A material's density is defined as its mass per unit volume. Density is essentially a measurement of how tightly matter is packed together.

Explanation:

Answer:

 The density of material shows the denseness of that material in a specific given area. A material's density is defined as its mass per unit volume. Density is essentially a measurement of how tightly matter is packed together.

cheese is made of cheese

Answers

Cheese is made of casein protein, which is originally made from milk and is high in protein. The texture of the cheese is determined by the quality of the milk, so cow's milk cheese differs from goat's milk cheese.

What is a dairy product?

Diary products are made from milk, such as cheese, curd, yogurt, etc., but all of them have different nutrients. The quality of these dairy products depend upon the quality of the milk, as some milking animals have a higher concentration of fats in their milk than other animals. These dairy products are used in different industrial sectors, such as for making ice cream, chocolate, and different food products.

Hence, cheese is made up of casein proteins that are present in the milk.

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А
mass exerts force of
5.6 X 10^-10N on
another mass
when
seperated 93cm apart. If
one mass is the square root of
the other
Find
value of
the two masses.

Answers

Answer:

i hope it will be useful for you

Explanation:

F=5.6×10^-10N

R=93cm=0.93m

let take m1 and m2 =m²

according to newton's law of universal gravitation

F=m1m2/r²

F=m²/r²

now we have to find masses

F×r²=m²

5.6×10^10N×0.93m=m²

5.208×10^-9=m²

taking square root on b.s

√5.208×10^-9=√m²

so the two masses are m1=7.2×10^-5

and m2=7.2×10^-5

Karen claps her hand and hears the echo from
a distant wall 0.519 s later.
How far away is the wall? The speed of
sound in air is 343 m/s.
Answer in units of m.

Answers

Answer:

89 m

Explanation:

Applying

v = 2d/t................... Equation 1

Where v = velocity of sound in air, d = distance of the wall from Karen, t = time taken to hear the echo.

make d the subject of equation 1

d = vt/2..................... Equation 2

From the question,

Given: v = 343 m/s, t = 0.519 s

Substitute these values into equation 2

d = (343×0.519)/2

d = 89.01 m.

d ≈ 89 m

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