Select the correct answer.
The image shows the combustion of methane. Which equation represents this chemical reaction?

OA CH4 + O₂ CO₂ + H₂O

OB. 2CH4+202 - CO₂ + 2H₂O

OC. CH4+202-2CO₂ + H₂O

OD. CH4 +0₂-2CO₂ + 2H₂O

OE. CH4 +202- CO₂ + 2H₂O

1.True, for a reaction to occur, the collision must occur with adequate energy.

2.True, the rate of reaction depends on the rate of reactant collisions.

3.False, Activation energy increases as temperature decreases

The activation energy decreases as temperature increases, not increases.

To calculate the activation energy, we can use the Arrhenius equation:

k2/k1 = exp[(Ea/R)(1/T1 - 1/T2)]

where k1 and k2 are the rate constants at temperatures T1 and T2 respectively, Ea is the activation energy, and R is the gas constant.

We can solve for Ea by plugging in the given values:

80 = exp[(Ea/8.314)((1/308)-(1/341))]

Ea = 60 kJ/mol

When it comes to the response mechanism:

A byproduct of this process is water. (True)

In this reaction, H+ acts as a catalyst. (False)

Rate=k([H2O2][I-]) is the reaction's rate law (True)

Intermediates in a reaction include both HOI and OH-. (True)

Due to its higher activation energy than the second step, the first step is the slower step. In a response system, the step that determines the rate is always the one that moves slowly.

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Approximately 70.57 mL of 1.00 M NaOH should be added to 250 mL of 0.50 M CH3CO₂H to produce a buffer with a pH of 4.50.

To determine the volume of 1.00 M NaOH required to produce a buffer with a pH of 4.50 when added to 250 mL of 0.50 M CH3CO₂H, we need to consider the Henderson-Hasselbalch equation and the stoichiometry of the reaction.

The Henderson-Hasselbalch equation for a buffer solution is given as:

pH = pKa + log([A-]/[HA])

In this case, CH3CO₂H (acetic acid) acts as the weak acid (HA) and CH3COO- (acetate ion) acts as its conjugate base (A-). We are given that the desired pH is 4.50, and we can determine the pKa value for acetic acid from reference sources, which is approximately 4.75.

Using the Henderson-Hasselbalch equation, we can rearrange it to solve for the ratio [A-]/[HA]:

[A-]/[HA] = 10^(pH - pKa)

[A-]/[HA] = 10^(4.50 - 4.75) = 10^(-0.25) = 0.5623

This means that the ratio of the acetate ion to acetic acid in the buffer solution should be approximately 0.5623.

To calculate the required volume of NaOH, we need to consider the stoichiometry of the reaction. Acetic acid reacts with hydroxide ions (OH-) to form acetate ions and water:

CH3CO₂H + OH- → CH3COO- + H2O

The stoichiometric ratio between acetic acid and hydroxide ions is 1:1. Therefore, the volume of 1.00 M NaOH needed can be calculated using the equation:

Volume (NaOH) × 1.00 M = Volume (CH3CO₂H) × 0.50 M × 0.5623

Volume (NaOH) = (Volume (CH3CO₂H) × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) = (250 mL × 0.50 M × 0.5623) / 1.00 M

Volume (NaOH) ≈ 70.57 mL

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The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.

The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.

Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.

Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.

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Answer: i think its empirical

Explanation:

Answer

.

Explanation

Given:

Mass of Mg = 10.800 g

Molar mass of Magnesium phosphate = 262.86 g/mol

Required: Mass of Magnesium phosphate.

Solution:

Step 1: Calculate the number of moles of magnesium

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 10.800g/24.305g/mol

n = 0.444 mol

Step 2: Use the stoichiometry to calculate the moles of Mg3(PO4)2

The molar ratio between Mg and M3(PO4)2 is 3:1

Therefore the number of moles of Mg3(PO4)2 = 0.444 mol x (1/3) = 0.148 mol

Step 3: Use the moles to calculate the mass of Mg3(PO4)2

m = n x M

m = 0.148 mol x 262.86 g/mol

m =

150 grams of NaOH is approximately equal to 2.256 x 10^24 particles of NaOH.

To convert grams of NaOH to particles of NaOH, we need to use the concept of molar mass and Avogadro's number. The molar mass of NaOH is calculated by adding the atomic masses of sodium (Na), oxygen (O), and hydrogen (H) together. It can be determined as follows:

Na: 22.99 g/mol

O: 16.00 g/mol

H: 1.01 g/mol

Molar mass of NaOH = (22.99 g/mol) + (16.00 g/mol) + (1.01 g/mol) = 40.00 g/mol

Now, we can use the molar mass to convert grams of NaOH to moles. Since 1 mole contains Avogadro's number (approximately 6.022 x 10^23) particles, we can determine the number of particles as follows:

150 g NaOH * (1 mol NaOH / 40.00 g NaOH) * (6.022 x 10^23 particles / 1 mol NaOH) ≈ 2.256 x 10^24 particles

It's important to note that this calculation assumes the substance is pure NaOH and that the molar mass and Avogadro's number are accurate.

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When fossil fuels burn, several forms of energy are produced, including:

Heat energy: The primary form of energy released during fossil fuel combustion is heat. Fossil fuels contain chemical energy stored for millions of years, and when they burn, this energy is released in the form of heat. The heat energy can be harnessed for various purposes, such as heating buildings or generating steam to drive turbines.

Light energy: Burning fossil fuels can also produce light energy in the form of flames or glowing embers. This light energy is a byproduct of combustion.

Mechanical energy: Heat generated by burning fossil fuels can be converted into mechanical energy. This is typically achieved by using heat to produce steam, which drives a turbine connected to a generator. The rotating turbine converts the heat energy into mechanical energy, which is further transformed into electrical energy.

Electrical energy: Through the process described above, burning fossil fuels can ultimately generate electrical energy. The mechanical energy produced by the turbine is converted into electrical energy by the generator. Electrical energy can power various devices, appliances, industries, and infrastructure.

It's critical to note that while burning fossil fuels can produce useful forms of energy, it also results in the release of carbon dioxide and other greenhouse gases. This contributes to climate change and environmental concerns. As a result, there is a global shift towards cleaner and renewable energy sources to mitigate these negative impacts.

Answer:

Limiting reactant

Explanation:

The limiting reactant is completely is completely consumed in a reaction since it's not in excess and does not give a good yield of the product hence an excess reactant must have reacted with limiting reactant.

Answer:

Less than 7

Explanation:

during the titration of strong acid and weak base, the weak base is usually kept in the flask and strong acid is kept in the burette. So when we add strong acid slowly drop by drop, slowly the pH level of solution starts to decrease and at equivalence point the acid overpowers the base as a strong acid was taken over a weak base.

Answer:

Explanation:

The equation must be balanced on both sides to show the law of conservation of mass. So, as long as it is equaled, the law is shown.

Answer:

Option 4, \(O^{2-}\)

Explanation:

Step 1:  Determine which option is correct

We know that Ne has 10 electrons therefore we need to find a different ion that has the same amount.  

Option 1 → Ca has 20 electrons and with 2+ we would remove 2 of those which would leave us with 18.

Option 2 → Cl has 17 electrons and with a - we would add 1 of those which would leave us with 18.

Option 3 → Li has 3 electrons and with a + we would remove 1 of those which would leave us with 2.

Option 4 → O has 8 electrons and with a 2- we would add 2 of those which would leave us with 10.  

Since the only one that matches up in the number of electrons is \(O^{2-}\) we can conclude that option 4 is correct.

Answer:  Option 4, \(O^{2-}\)

First-order wrt HgCl2, second-order wrt C2O42–, third-order overall, k = 7.6x10–3 M–2min–1    

Calculation:

rate= k [HgCl2]x [C2O4-2]y

data1 ,2,3

1.8x 10-5=k [0.105]x [0.15]y ..............(1)

7.2x 10-5=k [0.105]x [0.30]y.................. (2)

3.6x 10-5=k [0.0525]x [0.30]y ................... (3)

by solving 1 and 2 we get  y= 2

by solving 2 and 3 we get x =1

rate= k [HgCl2]1 [C2O4-2]2

total order = 1+2 = 3

from 1

1.8x 10-5=k [0.105]1 [0.15]2 .....................(1)

k = 7.6 x 10^-3 M–2min–1

Chemical kinetics is the study of reaction rates, how they change under different conditions, and the mechanisms by which reactions occur. There are five general properties that affect reaction kinetics. The concentration of reactants. The more you concentrate, the faster you go.

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The molar mass in grams of "one mole" of each substance is:

Fe: 55.845 g/mol

\(Cl_2\): 70.906 g/mol

\(FeCl_3\): 162.204 g/mol

To calculate the molar mass in grams of "one mole" of each substance, we need to determine the atomic masses of the elements involved in the equation.

The atomic mass of iron (Fe) is 55.845 g/mol.

For chlorine (\(Cl_2\)), we need to consider that the molar mass of \(Cl_2\) is twice the atomic mass of chlorine because the formula shows that two chlorine atoms combine to form one molecule of \(Cl_2\). The atomic mass of chlorine is 35.453 g/mol, so the molar mass of \(Cl_2\) is 2 * 35.453 g/mol = 70.906 g/mol.

The formula for iron(III) chloride (\(FeCl_3\)) indicates that one mole of \(FeCl_3\)contains one mole of iron and three moles of chlorine. Therefore, we can calculate the molar mass of \(FeCl_3\)by summing the atomic masses of iron and chlorine:

Molar mass of \(FeCl_3\)= (1 * atomic mass of Fe) + (3 * atomic mass of Cl)

Substituting the values, we have:

Molar mass of \(FeCl_3\) = (1 * 55.845 g/mol) + (3 * 35.453 g/mol)

= 55.845 g/mol + 106.359 g/mol

= 162.204 g/mol

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Answer:

so so

Explanation:

this your question?? <_>

There are 0.161 moles of copper atoms in a 25.7 g sample of CuSO4.

To determine the number of moles of copper atoms in a sample of CuSO4, we first need to know the molar mass of CuSO4.

The molar mass of CuSO4 can be calculated by adding the atomic masses of copper, sulfur, and four oxygen atoms:

1 x Cu = 63.55 g/mol

1 x S = 32.06 g/mol

4 x O = 15.99 g/mol x 4 = 63.96 g/mol

Molar mass of CuSO4 = 63.55 g/mol + 32.06 g/mol + 63.96 g/mol = 159.57 g/mol

Now that we know the molar mass of CuSO4, we can use it to calculate the number of moles of copper atoms in a 25.7 g sample:

moles of Cu atoms = mass of CuSO4 / molar mass of CuSO4

moles of Cu atoms = 25.7 g / 159.57 g/mol

moles of Cu atoms = 0.161 moles

Therefore, there are 0.161 moles of copper atoms in a 25.7 g sample of CuSO4.

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Answer:

I would serve nothing

Explanation:

thank you bye\

Answer:

Explanation:

I would not serve it because what if Their is some dangerous chemical

Answer:

4.62

so 5

the ratio is 2 na chlorates for 3 O2 so multiply 7 by 2/3

Explanation:

The number of moles of  NaClO3 that would be needed to produce 7 moles of O2 would be 5 moles of NaClO3 approximately.

From the equation of the reaction:

2NaClO3 --> 2NaCl +3O2

The mole ratio of NaClO3 to O2 is 2:3.

Thus, every 3 moles of O2 require 2 moles of NaClO3 .

7 moles of O2 will, therefore require:

                                     = 2 x7/3

                                              = 4.6666 moles of NaClO3

To the nearest whole number = 5 moles of NaClO3

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According to the description of an ionic bond, the last choice is the right response: Ca and Br are the two components that will combine to form an ionic connection. Bromine gets electrons quickly whereas calcium loses them easily.

Between metallic and non-metallic atoms, an ionic bond is created in which all of the electrons from one atom are transferred to the other. One atom loses electrons and another receives them during this process, resulting in the formation of ions.

In general, nonmetals are willing to take electrons to form anions while metal elements are willing to donate them to make cations.

On the other hand, the octet rule describes an attribute of atoms that they require eight electrons to complete their final energy level in order to ensure stability. The noble gases that have served as the foundation for this rule.

In order to adhere to the octet rule and ensure that the elements are stable, electrons are transferred in the ionic connection in this manner.

Ca and Br are the two elements that will combine to form an ionic connection because Ca is a metal and will give electrons while Br is a non-metal and will accept them.

The final option, Ca and Br, is the pair of elements that will form an ionic bond, making it the correct response. Bromine gets electrons quickly whereas calcium loses them easily.

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According to the Foliated Metamorphic Rock Chart slate, phyllite, schist, and gneiss can all have the same parent rock (shale) is a true statement.

Slate, phyllite, schist, and gneiss are all types of metamorphic rocks that can be formed from shale, which is a sedimentary rock composed of clay and other fine-grained minerals. The specific type of metamorphic rock that is formed from shale depends on the conditions under which the shale undergoes metamorphism, including the temperature, pressure, and presence of fluids.

Slate is a fine-grained metamorphic rock with a uniform, flat surface and a layered structure. It is formed when shale undergoes low-grade metamorphism, which occurs at relatively low temperatures and pressures.

Therefore, Gneiss, on the other hand, is a medium- to coarse-grained metamorphic rock with a banded or wavy texture. It is formed when shale undergoes high-grade metamorphism, which occurs at higher temperatures and pressures.

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Answer: 0.052moles

Explanation:

number of moles = given mass (g) / molar mass(g/mol)

n=m/M

n= 5.2g/ (40 + 12 + 48)g/mole

n=5.2g/100g/mol

n=0.052 moles

Answer:

1120 gm

Explanation:

6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)

(a) Balance the equation.

(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete

combustion reaction?

FIRST, CORRECT THE EQUATION THEN BALANCE

2C2H6(G) + 7O2------------>  4CO2  + 6H2O

so for 10 moles of ethane, we need

7 X 5 = 35 MOLES O2

=35 MOLES O2

O2 HAS A MOLAR MASS OF 2X16 = 32 gm

35 MOLES OF O2 HAS A MASS OF 35 X 32 =1120 gm

Answer:

Explanation:

Here, we want to answer the questions after balancing the chemical reaction

We have this balanced chemical reaction as follows:

We have balanced the chemical reaction, we can now proceed to answer the questions:

1) In the balanced reaction, we can see 6 nitrate molecules on the reactant side, and we have 6 nitrate molecules on the product side

2) Here, we want to describe the steps involved in balancing a chemical reaction:

a) We count the number of each of the atoms or molecules on both the reactant and product side

b) We place the right coefficients at the front of each element or group of elements and see if the particular element is of the same count on both the reactant and product side

c) We repeat steps a and b until we have a chemical reaction that is balanced

3) To indicate the physical state, we use the first letter in the name of the state, place in parentheses and use as a subscript

For the gaseous state, we have the indication as (g)

For the liquid state, we have the indication as (l)

For the solid-state, we have the indication as (s)

The exception is the aqueous state where we have (aq) as the indication

An equilibrium reaction occurs when the rates of forward and backward reactions are equal. Therefore, the correct equation representing an equilibrium system is:

2Mg(s) + O₂(g) ⇌ 2MgO(s)

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Answer:

Given : Diatomic molecule at 273K

'q' absorbed = positive = +100Cal = 100 x 4.184J = 418.4J

'W' done by system = negative = -209J

By first law of thermodynamics;

ΔU = q + W = 418.4 + (-209) = 209.4J

We know for diatomic molecule Cv=25R and CvΔT=ΔU

CvΔT=209.4

 25RΔT=209.4

ΔT=5R209.4×2

And, Heat exchange=Cm×ΔT 

where; Cm is molar heat capacity

Cm=ΔTHeat Exchange

substituting values for Heat Exchange = 418.4 and ΔT=5R209.4×2

Cm=5R

Answer:

23.12 atm

Explanation:

First, add together the moles of the two samples:

5.25 moles + 4.20 moles = 9.45 moles

273 + 25 = 298 K for the temperature

volume is 10.0 L

Since we have moles now, we have to rearrange our ideal law equation to solve for pressure:

\(P = \frac{nRT}{V}\)

\(\frac{(9.45 moles) X (0.08206) X (298 K)}{10.0 L}\)

9.45 X .08206 X 298 all divided by 10.0 = 23.09202 atm (or 23.12)

Answer:63.9%

Explanation: The percentage composition of chlorine in CaCl2 is derived as follows:

The molecular mass of the entire compound is:

Ca = 40.078 × 1 = 40.078

Cl2 = 35.4527 × 2 = 70.9054

40.078 + 70.9054 = 110.9834 (110.983 rounded)

The atomic mass of each element (or its multiple) is divided by the molecular mass of the compound:

Ca = 40.078 ÷ 110.983 = 0.361

Cl2 = 70.9054 ÷ 110.983 = 0.639

Multiplying each by 100 will turn these into percents. Therefore, the percentage composition of chlorine is 63.9%.

Answer:

SCl4

oxidation state of sulphur=+4

oxidation state of chlorine=-4

oxidation state of one chlorine atom=-1

Answer:

-3.72 (or -3.70 depending on what values you used)

Explanation:

First, use the molar mass of Cl2 convert the mass of Cl2 to moles.

1.48 g Cl2(1 mol70.906 g)=0.02087 mol Cl2

Note that we are given ΔH=−886kJ. This refers to the enthalpy change associated with the reaction of 5mol of Cl2 by the balanced equation shown below.

2P+5Cl2⟶2PCl5ΔH=−886kJ

Therefore, to determine the enthalpy change associated with the reaction of 1.48gCl2, divide ΔH by 5molCl2 to determine the enthalpy change per mole of Cl2, then multiply by 0.02087 mol Cl2.  (note: if you round up here to .021 mol of Cl2 you will get the final answer of -3.72 later)

0.02087 mol Cl2(−886 kJ5 mol Cl2)=−3.698 kJ

Rounding the answer should to three significant figures, we find that the enthalpy change associated with the reaction of 1.48gCl2 is −3.70 kJ.

Notice that coefficients in stoichiometric equations (indicating numbers of moles) are exact, so they do not constrain the number of significant figures.

The enthalpy change for the reaction when 1.48 g of Cl₂ reacts with excess P is –3.69 KJ.

We'll begin by calculating the number of mole of in 1.48 g of Cl₂. This can be obtained as follow:

Molar mass of Cl₂ = 2 × 35.5 = 71 g/mol

Mass of Cl₂ = 1.48 g

Mole = mass / molar mass

Mole of Cl₂ = 1.48 / 71

Finally, we shall determine the enthalpy change for the reaction. This can be obtained as follow:

2P + 5Cl₂ —> 2PCl₂  ΔH = −886 KJ

From the balanced equation above,

5 moles of Cl₂ reacted to produce an enthalpy change of −886 KJ.

Therefore,

0.0208 mole of Cl₂ will react to produce an enthalpy change of = \(\frac{0.0208 * - 886}{5}\\\\\) = –3.69 KJ.

Thus, the enthalpy change for the reaction when 1.48 g of Cl₂ reacts with excess P is –3.69 KJ.

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