select the correct answer what is the solution for X in the equation

2x-3x-18= -18+2x+5x​

The solution to the system of equations is x = 1 and y = -3.

To solve the system of equations using the substitution or elimination method, let's start with the substitution method.

Given equations:

y = 4x - 7

4x + 2y = -2

We'll solve equation 1) for y and substitute it into equation 2):

Substituting y from equation 1) into equation 2):

4x + 2(4x - 7) = -2

4x + 8x - 14 = -2

12x - 14 = -2

Now, we'll solve this equation for x:

12x = -2 + 14

12x = 12

x = 12/12

x = 1

Now that we have the value of x, we can substitute it back into equation 1) to find y:

y = 4(1) - 7

y = 4 - 7

y = -3

Therefore, the solution to the system of equations is x = 1 and y = -3.

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Answer:

?=2 (ik i answered but i kinda want the points)

Step-by-step explanation:

first look at the problems ? x (3+5) = 6 +10

so ? x 8 = 16 so dvide 16 by 8 and you'll end up with a solid 2

Answer:

solution,

Similar Right triangles:

\( \frac{c}{h} = \frac{h}{d} \\ {h}^{2} = cd \\ {y}^{2} = 4 \times 9 \\ {y = 36 }^{2} \\ y = \sqrt{ {(6)}^{2} } \\ y = 6\)

Hope this helps..

Good luck on your assignment..

Answer:whats the measure of x i really need help

Step-by-step explanation:

Answer:

i dont know

Step-by-step explanation:

uhhh

Answer:

42% chance

Step-by-step explanation:

Since there are 21 red marbles and 29 blues ones, the total amount of marbles is 50. There are only 21 red marbles out of 50 marbles so there is a 21/50 chance that you will pick a red marble.

The domain of the function f(x) = -3x + 2 is (-∞, +∞), representing all real numbers, and the range is (-∞, 2], representing all real numbers less than or equal to 2.

The function f(x) = -3x + 2 is a linear function defined by a straight line. To determine the domain of this function, we need to identify the range of values for which the function is defined.

The domain of a linear function is typically all real numbers unless there are any restrictions. In this case, there is no explicit restriction mentioned, so we can assume that the function is defined for all real numbers.

Therefore, the domain of the function f(x) = -3x + 2 is (-∞, +∞), which represents all real numbers.

Now, let's analyze the range of the function. The range of a linear function can be determined by observing the slope of the line. In this case, the slope of the line is -3, which means that as x increases, the function values will decrease.

Since the slope is negative, the range of the function f(x) = -3x + 2 will be all real numbers less than or equal to the y-intercept, which is 2.

Therefore, the range of the function is (-∞, 2] since the function values cannot exceed 2.

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Answer:

A, B, E

Step-by-step explanation:

I'm not too sure about B, but A and E are definitely true

Simultaneous equations are two or more algebraic equations that share variables. They are solved at the same time (with the same variables).

Simultaneous equations can have one or more variables (unknown values) but the value of each variable is the same in all the sets of simultaneous equations:

Example: Two simultaneous equations share variables x and y, then the value of x is the same in both equations and the value of y is the same in both equations.

Then, simultaneous equations can have one or more unkown values (variables)

Answer:

The correct option is D

Step-by-step explanation:

From the question we are told that

   The sample size for male car occupant is  \(n_1 = 2450\)

   The number that wear seat belt is \(k_1 = \frac{76}{100} * 2450 = 1862\)

   The sample size for female car occupant is \(n_2 = 2900\)

   The number that wear a seat belt is   \(k_2 = \frac{74}{100} * 2900 = 2146\)

Generally the population proportion is mathematically represented as

       \(p = \frac{x_1 + x_2 }{n_1 + n_2 }\)

=>    \(p = \frac{1862 + 2146 }{2450 + 2900 }\)

=>  \(p = 0.7492\)

The sample proportion for male  car occupant is  

        \(\^ p_1 = \frac{k_1}{n_1}\)

=>     \(\^ p_1 = \frac{1862}{2450}\)

=>     \(\^ p_1 = 0.76\)

The sample proportion for female car occupant is  

        \(\^ p_2 = \frac{k_2}{n_2}\)

=>     \(\^ p_2 = \frac{2146}{2900}\)

=>     \(\^ p_1 = 0.74\)

The null hypothesis is  \(H_o : p_1 = p_2\)

The alternative hypothesis is  \(H_a : p_1 \ne p_2\)

Generally the standard error is mathematically represented as

        \(SE = \sqrt{\frac{p(1 -p )}{ n_1 + n_2} }\)

=>    \(SE = \sqrt{\frac{0.7492 (1 -0.7492 )}{ 2450 + 2900} }\)  

=>    \(SE = 0.005926\)

Generally the test statistics is mathematically represented as

     \(z = \frac{\^ p_1 - \^ p_2}{SE}\)    

=>   \(z = \frac{0.76 -0.74}{0.005926}\)

=>   \(z = 3.37\)

From the z table  the area under the normal curve to the right  corresponding to  3.37 is  

       \(P(Z > 3.37) = 0.00037584\)

Generally the p-value is mathematically represented as

      \(p-value = 2 * P(Z > 3.37)= 2* 0.00037584 = 0.0007 5\)

From the value obtained we see that  \(p-value < \alpha\)  hence  

The decision rule is  

  Reject the null hypothesis

The conclusion is

 There appears to be a gender gap because there is a significant difference in the proportions

Allison feeds 11 horses in a day.

Horses are herbivores and, as such, they need a very specific diet. They must consume lots of fiber to keep their extremely long and sensitive digestive tract working and they must eat little and often, almost all day long.

A horse's feed should consist primarily of grass or roughage. However, hay is insufficient to provide a complete nutritional profile. Important minerals and nutrients will be added by adding grains and concentrates, but calories will also be added. Roughage, feeds, and concentration types are listed below, from least to most "complete."

Given,

Allison feeds 2 quarter horses and 3 paint horses the same amount each day.

Therefore, she feeds 2*4+3 = 11 horses in a day.

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If Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

To show that x is also an eigenvector of QT, we need to demonstrate that QT * x is a scalar multiple of x.

Given that Q is an orthogonal matrix, we know that QT * Q = I, where I is the identity matrix. This implies that Q * QT = I as well.

Let's denote x as the eigenvector corresponding to the eigenvalue λ1 This means that Q * x = λ1 * x.

Now, let's consider QT * x. We can multiply both sides of the equation Q * x = λ1 * x by QT:

QT * (Q * x) = QT * (λ1 * x)

Applying the associative property of matrix multiplication, we have:

(QT * Q) * x = λ1 * (QT * x)

Using the fact that Q * QT = I, we can simplify further:

I * x = λ1 * (QT * x)

Since I * x equals x, we have:

x = λ1 * (QT * x)

Now, notice that λ1 * (QT * x) is a scalar multiple of x, where the scalar is λ1. Therefore, we can rewrite the equation as:

x = λ2 * x

where λ2 = λ1 * (QT * x).

This shows that x is indeed an eigenvector of QT, with the eigenvalue λ2 = λ1 * (QT * x).

In conclusion, if Q is an orthogonal matrix with an eigenvalue λ1 = 1, then x, the eigenvector corresponding to λ1, is also an eigenvector of QT with an eigenvalue λ2 = λ1 * (QT * x).

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Answer:

4

Step-by-step explanation:

The first value (10) is the x value. 10 is positive so the point is on your right. The second value (-1) goes down below the x axis. because it is minus. right and down means you are in the 4th quadrant.

Answer:

IV

Step-by-step explanation:

In the picture below, it shows the model of all quadrants. Since the point (10, -1) has a positive as the x, you can eliminate quadrant II and III. The ones left are I and IV. Since y is a negative, you eliminate I because it is only positives while IV has a negative as it's y.

Hope this helps.

Answer:

\(-\frac{2}{3}.\)

Step-by-step explanation:

1) the required slope can be calculated if to use the ratio:

slope=(y(B)-y(A))/(x(B)-x(A)), where x(A)=-3; y(A)=4; x(B)=0 and y(B)=2;

2) according to the formula above:

s=(2-4)/(0+3)=-2/3.

The slope of the line through the given points is: -2/3.

Slope of a line= change in y / change in x = rise/run.

Given the points:

(-3, 4) = (x1, y1)

(0, 2) = (x2, y2)

Slope = (4 - 2)/(-3 - 0)

Slope = 2/-3

Slope of the line = -2/3

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There are 120 different combinations of 3 programmers that can be chosen to transfer to the new department

From the question, we have

Total number of programmers, n = 10

Numbers to programmers to select, r = 3

The number of ways of selection could be drawn is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 10 and r = 3

Substitute the known values in the above equation

Total = ¹⁰C₃

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 10!/(7! * 3!)

Evaluate

Total = 120

Hence, the number of ways is 120

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The y-intercept (0, 120), and the point (55, 17), on the graph of the exponential function of the population of mammals with the population decreasing at 3.5% per year indicates;

A. The y-intercept represents the number of mammals when they were originally counted was 120

B. The line y = 0 is an asymptote of the graph

D. The y-intercept is 120

F. The asymptote indicates that as years pass, the number of mammals will approach 0

An asymptote is a line on a graph that the curve of a graph approaches as the values of the graph increases to infinity.

The points on the graph of the exponential function are;

(0, 120) and (55, 17)

The rate at which the population is decreasing = -3.5%

The output of the graph, y = The number of mammals x years after counting

The key features of the exponential function are;

The y-intercept of the graph is the point x = 0, which corresponds to year 0, or the time when the mammals were originally counted and the y-value at the y-intercept represents the number of mammals when they were counted originally, therefore option A is correct

The coordinates of the y-intercept is (0, 120)

The y-intercept is therefore the point y = 120

Therefore, option D is correct

The general form of the growth exponential function is presented as follows;

f(x) = a·bˣ + k

r = b - 1

b = 1 + r

Therefore;

b = 1 - 0.035 = 0.965

a = The first term = 120

Plugging in the known values from the graph, we get;

f(0) = 120 = a + k

120 = 120 + k

k = 120 - 120 = 0

k = 0 = The asymptote

Therefore, an asymptote is the line y = 0 option B is therefore correct

The  number of mammals approach the asymptote, y = 0 as the number of mammals approach infinity

Therefore as the years pass the number of mammals will approach 0, option F is correct

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Answer:

203/1250

Step-by-step explanation:

16.24% is equivalent to 0.1624

I used a calculator to convert.

Note the following points:

If a number "a" is positive, and the nth root, n, is even, then there are two nth real roots

If a number "a" is positive and the nth root, n, is odd, then there is just one nth real roots

If a number "a" is negative and the nth root, n, is even, then there are zero nth real roots

If a number "a" is negative and the nth root, n, is odd, then is only one real nth roots

Let us match the statements now:

If n is even and a > 0, a has two nth real roots/solutions (g)

If n is odd and a > 0, a has one nth real root/solution (c)

If n is is odd and a < 0, a has one nth real solution (i)

If n is even and a < 0, a has zero nth real solution (f)

Answer:

4/15

Step-by-step explanation:

2/5 drive

1/3 bus

and rest walk

fraction of those who walk is 1-(2/5+1/3)

2/5+1/3=(6+5)/15=11/15

15/15-11/15=4/15

0 > 1 if and only if 2 > 1. Because the first assertion is untrue and the second is true, the outcome is untrue.

Here is an example of a compound assertion with two biconditionals: "If the rectangle is indeed a square, it has four equal-length sides as well as four sharp angles; and, when a quadrilateral has four equal-length sides and four sharp angles, it is a plaza."

Definition. An action on two logical values, usually the virtues of two propositions, is referred to as logical equivalence (also known as biconditional), and it yields a value of true if and only both operands are untrue or both operands are true.

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The hypotheses to test if this sample indicates a significant change in the average number of hours spent studying is:

0: µ = 14 (null hypothesis)

1: µ ≠ 14 (alternative hypothesis)

Option B is the correct answer.

We have,

The null hypothesis states that the population mean for the number of hours spent studying by full-time students at 4-year colleges in the United States is equal to 14 hours per week,

while the alternative hypothesis states that it is different from 14 hours per week.

By using a two-tailed test, we are checking for any significant change in either direction, whether the average number of hours spent studying has increased or decreased from 14 hours per week.

Thus,

The hypotheses to test if this sample indicates a significant change in the average number of hours spent studying is:

0: µ = 14 (null hypothesis)

1: µ ≠ 14 (alternative hypothesis)

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Answer:

256

Step-by-step explanation:

(a^n)^m = a^nm

=(8^⅔)⁴ =8^⅔×⁴

=2³×⅔×⁴ (8 = 2³)

=2^8 =256

Answer:

Step-by-step explanation:

8 = 2*2*2 = 2³

\(\left[8^\left(\dfrac{2}{3}\right) \right]^{{4}}=\left[2^{3}^\left(\dfrac{2}{3}\right) \right]^{{4}}\\\\\\=2^{3*\dfrac{2}{3}*4}\\\\\\=2^{2*4}\\\\\\=2^{8}\)

Answer:

A

Step-by-step explanation:

X=-7

Answer:

$181.4

Step-by-step explanation:

Note,

Therefore, the store applied a discount price of $181.4 to the set of golf clubs.

Answer:

35.46

Step-by-step explanation:

34 x 1.043=35.46

The CD will earn $459.375 interest in 30 months and the balance at maturity will be $10,959.375.

Here, we are given that Ralph deposited $10,500 in an CD account that pays 1.75% simple interest for 30 months.

Simple interest can be calculated using the following formula-

Simple interest = Principle(P) × Time(t) × Rate(r)/ 100

Here,

P = 10,500

t = 30/12

r = 1.75

Thus,

Simple interest = 10,500 × 30/12 × 1.75/ 100

= 10,500 × 5/2 × 175/ 10000

= 10,500 × 5/2 × 7/ 400

= 26,250 × 7/ 400

= $459.375

Thus, the CD will earn $459.375 interest in 30 months.

Balance on maturity will be-

$10,500+ $459.375 = 10,959.375

Thus, the balance at maturity will be $10,959.375.

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The two expressions that are less than 7/8 are 7/8 x 9/19 and 7/8 x 3/4.

To determine which expressions are less than 7/8, we can compare them individually to 7/8 and evaluate their values.

Let's consider each expression one by one:

7/8 x 9/19:

To compare this expression to 7/8, we multiply the fractions:

(7/8) x (9/19) = 63/152.

Since 63/152 is less than 7/8, this expression is less than 7/8.

7/8 x 3/4:

Multiplying the fractions:

(7/8) x (3/4) = 21/32.

Since 21/32 is less than 7/8, this expression is less than 7/8.

7/8 x 9/9:

The fraction 9/9 simplifies to 1, so the expression becomes:

(7/8) x 1 = 7/8.

Since 7/8 is equal to 7/8 (not less than), this expression is not less than 7/8.

7/8 x 4/3:

Multiplying the fractions:

(7/8) x (4/3) = 28/24.

We can simplify 28/24 to 7/6.

Since 7/6 is greater than 7/8, this expression is not less than 7/8.

Therefore, the two expressions that are less than 7/8 are 7/8 x 9/19 and 7/8 x 3/4.

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In a case whereby Juan buys candy that costs $8 per pound and will spend at least $48 on candy  the possible numbers of pounds he will buy written in inequality is is p>5 (at least 5 pounds).

Inequality in math refers to a statement that one quantity is either greater than, less than, or not equal to another quantity. Inequalities are often represented using symbols such as "<" (less than), ">" (greater than), or "≤" (less than or equal to) and "≥" (greater than or equal to). For example, the inequality "x > 3" states that the variable "x" is greater than the value of 3. The inequality "y ≤ 5" means that the variable "y" is less than or equal to 5.

From the question, p = number of pounds Juan will buy.

candy=costs $8 per pound

$20/$4 = 5 pounds

p>5

at least 5 pounds

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There are three area options for the number of bricks:

The number of bricks that can be painted out is equal to the paint area (A), in square centimeters, divided to the area of a brick (A'), in square centimeters. That is:

n = A / A'

A' = w · h

Where:

There are three possible answers:

Case 1: A = 93750 cm², w = 22.5 cm, h = 10 cm

A' = 22.5 · 10

A' = 225

n = 93750 / 225

n = 416.667

n = 416

Case 2: A = 93750 cm², w = 22.5 cm, h = 7.5 cm

A' = 22.5 · 7.5

A' = 168.75

n = 93750 / 168.75

n = 555.556

n = 555

Case 3: A = 93750 cm², w = 10 cm, h = 7.5 cm

A' = 10 · 7.5

A = 75

n = 93750 / 75

n = 1250

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Nathaniel drinks 3 glasses of water in one hour.

To find out how many glasses of water Nathaniel drinks in one hour, we need to calculate his drinking rate per hour.

In 2 2/5 hours, Nathaniel drinks 4/5 of a 10-ounce glass of water.

Let's convert the mixed number of hours to an improper fraction:

\(2\frac{2}{5} = \frac{(5 \times2 + 2)}{5}\)

\(=\frac{12}{5}\)

Now, we can set up a proportion to find his drinking rate per hour.

We know that \(\frac{12}{5}\) hours corresponds to \(\frac{4}{5}\) of a glass of water.

Let's assign "x" as the number of glasses he drinks in one hour.

The proportion is then

\(\frac{(\frac{12}{5} hours) }{(x glasses) } =\frac{(\frac{4}{5} glass)}{(1 hour)}\)

Cross-multiplying gives us

\((\frac{12}{5} )\times1=\frac{4}{5}\times(x)\)

Simplifying, we get

\(\frac{12}{5} =\frac{4}{5}\times x\)

Dividing both sides by \(\frac{4}{5}\), we find x:

\(x=\frac{(\frac{12}{5} )}{\frac{4}{5} }\)

\(x=\frac{12}{4}\)

\(x = 3.\)

Therefore, Nathaniel drinks 3 glasses of water in one hour.

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