Select the circuit below that does NOT correctly show Ohm’s law.

Answer:a no net force

Explanation: google lol

Answer

As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.

Explanation:

To calculate the work needed to move a charge from point C to D in a square with charges at corners A and B, we need to consider the electric potential difference between the two points.

1. Calculate the electric potential at point C (VC) and at point D (VD) using the formula V = k * q / r, where V is the electric potential, k is the Coulomb's constant (9 * 10^9 Nm^2/C^2), q is the charge, and r is the distance between the point and the charge.

2. Find the electric potential difference between point C and D by subtracting VC from VD (ΔV = VD - VC).

3. The work done (W) to move a charge from C to D is given by the equation W = q * ΔV, where q is the charge and ΔV is the potential difference.

Please note that without specific values for the charge, side length of the square, and distances between the points. But you can use the steps mentioned above to calculate the work needed to move a charge from point C to D once you have those values.

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Approximately 9% of the mechanical energy of the ball is transformed into internal energy of the ball and the floor.

When the ball falls and bounces back up, some of its initial mechanical energy is lost as it is converted into internal energy. The mechanical energy of the ball consists of its potential energy (mgh) when it is at a height of 10.0 m and its kinetic energy (1/2 mv^2) when it is at a height of 9.0 m. The loss in mechanical energy is due to factors like deformation of the ball and floor, sound, and heat generated upon impact.

To calculate the percentage of energy loss, we need to compare the difference in mechanical energy before and after the bounce. The difference is approximately 0.81 J. Dividing this by the initial mechanical energy (81 J) and multiplying by 100 gives us the percentage, which is approximately 9%. Therefore, around 9% of the mechanical energy is transformed into internal energy of the ball and the floor during the bounce.

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The equation is given as v(t) = vt(1 − e^(-gt/vt)), where v(t) represents the terminal velocity of the raindrop, g is the acceleration due to gravity, and e is the base of the natural logarithm.

Under the assumptions made, we can establish the equation v(t) = vt(1 − e^(-gt/vt)) for the velocity of a falling raindrop at time t. This equation incorporates two key factors: the terminal velocity (v(t)) and the gravitational acceleration (g).

Terminal velocity is the maximum constant velocity achieved by an object falling through a fluid medium, such as air. It occurs when the drag force acting on the object equals the gravitational force pulling it downward.

The equation v(t) = vt(1 − e^(-gt/vt)) represents the variation of velocity with respect to time. As the raindrop falls, it accelerates due to the gravitational force. However, as it gains velocity, the air resistance opposing its motion increases until it reaches a point where the drag force matches the gravitational force.

At this point, the raindrop reaches its terminal velocity, denoted by v(t). The term (1 − e^(-gt/vt)) in the equation accounts for the decreasing effect of air resistance on the acceleration of the raindrop as it approaches terminal velocity.

Overall, this equation provides a mathematical representation of how the velocity of a falling raindrop changes over time, incorporating the effects of terminal velocity and gravitational acceleration.

It allows us to study and understand the behavior of raindrops as they descend through the atmosphere, considering the balance between gravity and air resistance.

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Answer:

20.4 cm; 2.4 cm  

Explanation:

The formula for the pressure p exerted by a column of a liquid with density ρ and height h is

p = ρgh

where h = the acceleration due to gravity

If you have two liquids balancing each other in a U-tube

     p₁ = p₂

ρ₁gh₁ = ρ₂gh₂

 ρ₁h₁ = ρ₂h₂

Data:

ρ₁ = 1010 kg/m³; h₁ = 18 cm

ρ₂ = 890 kg/m³; h₂ = ?          

1. Height of oil column

We measure from the horizontal red line.

\(\begin{array}{rcl}\rho_{1}h_{1} & = &\rho_{2}h_{2}\\\text{1010 kg/m}^{3} \times \text{18 cm} & = & \text{890 kg/m}^{3} \times h_{2}\\\text{18 180 cm} & = & 890h_{2}\\h_{2} & = & \dfrac{\text{18180 cm}}{890}\\\\ & = & \text{20.4 cm}\\\end{array}\\ \text{The height of the oil column is $\textbf{20.4 cm}$}\)

2. Height of oil above water

h₂ - h₁ = 20.4 cm – 18 cm = 2.4 cm

Answer: i think they control the eyes to move them.

Explanation:

Answer:

The power will be "250 watt". A further explanation is given below.

Explanation:

The given values are:

Force,

F = 50 N

Displacement,

d = 20 m

Time,

t = 2.0 seconds

Whenever the block is pulled, the angle will be "0" i.e., Cos0° = 1

Now,

The work will be:

= \(Force\times displacement\times \Theta\)

On substituting the given values, we get

= \(50\times 10\times Cos0^{\circ}\)

= \(50\times 10\times 1\)

= \(500 \ Newton\)

Now,

The Power will be:

= \(\frac{Work \ done}{time}\)

= \(\frac{500}{2.0}\)

= \(250 \ watt\)

Seismic movement, Volcanic Activity, Plate Tension

The magnitude of the linear impulse experienced by the passenger during this time is 421.2 kg·m/s and the average force experienced by the passenger is approximately 5.44 × 10^2 N.

(a) To calculate the magnitude of the linear impulse experienced by the passenger, we can use the equation:

Impulse = mass × change in velocity

Given:
Mass of the passenger (m) = 70.2 kg
Change in velocity (Δv) = 6.00 m/s - 0 m/s = 6.00 m/s

Substituting the values into the equation, we get:

Impulse = 70.2 kg × 6.00 m/s = 421.2 kg·m/s

Therefore, the magnitude of the linear impulse experienced by the passenger during this time is 421.2 kg·m/s.

(b) To find the average force experienced by the passenger, we can use the equation:

Average force = Impulse ÷ time

Given:
Impulse (I) = 421.2 kg·m/s
Time (t) = 0.774 s

Substituting the values into the equation, we get:

Average force = 421.2 kg·m/s ÷ 0.774 s = 544.0 N (rounded to three significant figures)

Therefore, the average force experienced by the passenger is approximately 5.44 × 10^2 N.

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Answer:

P₄ + 3O₂ → 2P₂O₃

Explanation:

To balance an equation we take each element one by one on each side and balance their atoms.

Like P₄ (Tetraphosphorus) in the left side has 4 atoms of phosphorus.

While on the right side P₂O₃ (Diphosphorus Trioxide) has 2 Phosphorus atoms.

So place 2 as a coefficient in front of P₂O₃.

Now Phosphorus atoms (4 atoms) are balanced on each side.

Now number of Oxygen atoms in P₂O₃ = 2 × 3 = 6

On the left left side number of Oxygen atoms in O₂ = 2

To balance Oxygen atoms in each side, place 3 as a coefficient before O₂ on the left.

Therefore, balance equation will be,

P₄ + 3O₂ → 2P₂O₃

We can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2). The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2)

(a) The refractive index of the ionospheric layer can be determined using the formula n = √(1 - (f_ce / f)^2), where n represents the refractive index, f_ce is the electron gyrofrequency, and f is the frequency of the incident wave.

The electron gyrofrequency (f_ce) can be calculated using the formula f_ce = 8.978 × √(N), where N is the electron density. Substituting the given electron density value, we have f_ce = 8.978 × √(24.536 × 10^11) ≈ 2.774 × 10^6 Hz.

Now, we can calculate the refractive index by substituting the values into the formula: n = √(1 - (2.774 × 10^6 / f)^2).

(b) The critical frequency for the communication link can be determined using the formula f_c = f_ce / sin(θ), where f_c represents the critical frequency and θ is the angle of incidence. Substituting the given angle of 60°, we have f_c = 2.774 × 10^6 Hz / sin(60°).

(c) The maximum usable frequency (MUF) can be calculated using the formula MUF = f_c / sin(θ). Substituting the critical frequency and angle of incidence given in parts (b) and (a), respectively, we can find the MUF.

(d) Transmissions would fail at the frequencies of 10 MHz and 30 MHz because they are below the critical frequency. The critical frequency represents the maximum frequency that can be reflected back to Earth by the ionospheric layer. If the frequency of the transmission is below the critical frequency, the wave would penetrate through the ionosphere and not be reflected back, leading to a failed transmission.

(e) The ionosphere bends high-frequency radio waves towards Earth due to the phenomenon of refraction. When a radio wave encounters the ionosphere, which is composed of charged particles, it experiences a change in speed and direction. This change in speed and direction is due to the varying density and composition of the ionosphere at different altitudes.

As the radio wave passes through the ionosphere, its path is curved downward towards the Earth's surface. This bending phenomenon occurs because the refractive index of the ionosphere is greater than that of the surrounding vacuum or atmosphere. The higher the frequency of the radio wave, the greater the bending effect due to the higher electron density in the ionosphere at higher altitudes.

This bending of high-frequency radio waves allows for long-distance communication by enabling the waves to travel beyond the line-of-sight. It plays a crucial role in long-distance radio communication, especially in areas where direct line-of-sight transmission is obstructed by the Earth's curvature or other obstacles.

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The total resistance of the series circuit having three resistances as 1. 5 ohms, 1. 5 ohms, and 2 ohms is 5 Ω, as 1.5 + 1.5 + 2 = 5.

The sum of all resistances in a series circuit determines the overall resistance. Same current passes through all the resistors kept in a series circuit.  A series circuit, for instance, consists of three bulbs having resistance as: 1. 5 ohms, 1. 5 ohms, and 2 ohms.

The total resistance in the series circuit is given by:

R = R₁ + R₂ + R₃

= 1.5 + 1.5 + 2

= 5 Ω.

Therefore, 5 ohms is the total resistance of a series circuit having three bulbs of respective resistances.

The current in each resistor is the same in a series circuit since the first resistor's output current feeds into the second resistor's input. All of the resistor leads on one side of the resistors are connected together in a parallel circuit, as are all of the leads on the other side.

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When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.

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Answer:

2.33..

Explanation:

f = wavelength/speed

= 0.0000007/300000000

= 2.333...

Throughout the race, sprinters must stay in their allotted lanes and are not permitted to cross them. They begin the 800-meter race in varying positions and have the opportunity to break ahead after the first curve.

Studies show that running at a moderate speed for just just few minutes each day can help reduce your risk of dying from common illnesses including strokes and heart attacks. The same study does, however, also demonstrate that these benefits cease to exist after four hours per week, undermining the necessity of regular long runs.

Between two and four runs per week, lasting around twenty to thirty minutes (or 2 to 4 miles each), are recommended for new runners. You may be familiar with the 10% Rule, but running more frequently every other week is a superior strategy for increasing your mileage. Your body will be assisted in adjusting to your.

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F = ma, or force equal to mass times acceleration, is Newton's second law of motion.

Second Law of Movement by Newton Since it shows how powers and movement are connected, F=ma is essential. You can use it to determine an object's velocity and position, as well as its acceleration with known forces. For inventors, scientists, and engineers, This is extremely helpful.

As per Newton's Second Law of Movement, when a power works on a mass, the mass speeds up (gains speed) (object). When you ride a bicycle, you can see this law of motion in action in a great way. Your bike makes up the mass. Your leg muscles press against the bicycle's pedals to produce the force.

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The position of an object relative to the focal point of a mirror determines whether the resulting image is real or virtual, and whether it is magnified or reduced.


The focal point of a mirror is the point at which parallel rays of light converge or appear to diverge from. If an object is placed between the focal point and the mirror's surface, a concave mirror will produce an enlarged virtual image, whereas a convex mirror will produce a reduced virtual image. Conversely, if the object is placed beyond the focal point, a concave mirror will produce a real, reduced image, and a convex mirror will produce an enlarged, virtual image.  

The magnification of an image is determined by the ratio of the height of the image to the height of the object. If the image is upright, the magnification will be negative, indicating a reduction in size. The image distance is positive for virtual images, as they appear behind the mirror, while it is negative for real images, which appear in front of the mirror.

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The average frictional force tending to stop it is 400N.

Frictional force calculation.

We can use the work-energy principle to solve this problem. The work done by the frictional force is equal to the initial kinetic energy of the car. Therefore:

Work done by frictional force = 0.5 x mass x velocity^2

Work done by frictional force = 0.5 x 2000 kg x (20 m/s)^2

Work done by frictional force = 400,000 J

The work done by frictional force is equal to the force multiplied by the distance over which it acts. Therefore:

Force x distance = 400,000 J

Force = 400,000 J / 100 m

Force = 4000 N

Therefore, the average frictional force tending to stop the car is 4000 N using work energy principle.

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But we do not know whether the force is pushing or pulling (the same direction (both forces are parallel) but: .........[ ]<-F-- or .......[ ]--F-->). I suppose the correct answer is B

Answer:

If an object pushes out an amount of water equal to its own weight, the upward force acting on it will be equal to gravity - and the object will float.

Explanation:

The buoyant force has an impact on the object in the water and equals the weight of the water displaced by the object. Every object placed in water has some buoyancy force that pushes it against the gravitational force, and this means that any object loses weight in the water.

When the distance between charged particles is halved, the force between them becomes four times stronger. The answer will provide an explanation of this relationship.

The force between two charged particles is described by Coulomb's law, which states that the force (F) between two charges (q1 and q2) is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance (r) between them. Mathematically, this relationship can be expressed as F ∝ (q1 × q2) / r^2.

When the distance between the charged particles is halved (r/2), the force between them can be calculated by substituting the new distance into Coulomb's law. In this case, the new force (F') is given by F' ∝ (q1 × q2) / (r/2)^2. Simplifying the expression, we have F' ∝ (q1 × q2) / (1/4) × r^2, which further reduces to F' ∝ 4 × (q1 × q2) / r^2.

This shows that when the distance between the charged particles is halved, the force between them becomes four times stronger. The inverse square relationship between force and distance results in a quadratic effect, meaning that the force increases by a factor of four when the distance is halved.

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The block would accelerate down the inclined plane. The force applied is greater than the maximum force of static friction. The correct answer is (B).

Angle of inclination of plane, θ = 30, Coefficient of static friction, µs = 0.2, Coefficient of kinetic friction, µk = 0.2The block is stationary, A block (A) remains stationary on the inclined plane, which implies that the force of static friction fsmax acting upwards balances the force of gravity mgsinθ acting downwards.

Using the formula of maximum force of static friction, we get; fsmax = µs x mg cosθ = 0.2 x mg x cos 30 ......(1)Also, the maximum force of static friction, in this case, is less than the force of gravity acting downwards. Hence, the block will slide down the incline.

On substituting the values in eq. (1), we get; fsmax = (0.2) (9.8) (0.866) ≈ 1.69 N. The force of gravity acting on the block will be; Fg = mg sinθ = 0.5mg N. Since the force applied, Fapp is greater than fsmax, the block will accelerate down the plane. So, the correct answer is (B).

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a) The isocost curve equation is G = (20000 - 100C)/500. b) The isocost curve equation is G = (30000 - 100c)/500. c) The isocost curve equation is G = (20000 - 100C)/375. d)  The isocost curve equation is G = (20000 - 120C)/500.

To draw the isocost curve showing the different combinations of gas and coal, we need to use the cost per unit values for coal and gas, as well as the given expenditure (TC) and the changes in expenditure or prices.

Let's denote the quantity of coal as C and the quantity of gas as G. The cost per unit of coal is 100, and the cost per unit of gas is 500.

(a) Initial expenditure (TC) of 20000:

To find the combinations of gas and coal that can be purchased with an initial expenditure of 20000, we can use the following isocost equation

TC = 100C + 500G

We can rearrange the equation to solve for G in terms of C

G = (TC - 100C) / 500

Now we can plot the isocost curve with TC = 20000 using the equation above.

(b) Expenditure (TC) increases by 50%

If the expenditure increases by 50%, the new expenditure (TC_new) becomes 1.5 × TC = 1.5 × 20000 = 30000.

We can use the same isocost equation as before, but with the new expenditure value:

TC_new = 100C + 500G

Rearranging the equation to solve for G

G = (TC_new - 100C) / 500

Now we can plot the isocost curve with TC_new = 30000.

(c) Gas price reduced by 25%:

If the gas price is reduced by 25%, the new cost per unit of gas (Gas_new) becomes 0.75 × 500 = 375.

We can use the original isocost equation, but with the new cost per unit value:

TC = 100C + 375G

Rearranging the equation to solve for G

G = (TC - 100C) / 375

Now we can plot the isocost curve with the reduced gas price.

(d) Coal price rises by 20%

If the coal price rises by 20%, the new cost per unit of coal (Coal_new) becomes 1.2 × 100 = 120.

We can use the original isocost equation, but with the new cost per unit value:

TC = 120C + 500G

Rearranging the equation to solve for G:

G = (TC - 120C) / 500

Now we can plot the isocost curve with the increased coal price.

By plotting these isocost curves on a graph with G on the y-axis and C on the x-axis, we can visualize the different combinations of gas and coal that can be purchased at the given expenditures or price changes.

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Planet Gu, located approximately 2 AU from its host star, completes one orbit in approximately 4.43 Earth years.

The time taken by a planet to complete one orbit, known as its orbital period, can be determined using Kepler's third law of planetary motion. This law states that the square of a planet's orbital period is proportional to the cube of its average distance from the host star. In this case, Planet Gu is located approximately 2 AU from its host star.

To calculate the orbital period, we can use the equation:

\(T^2 = (4\pi ^2/GM) * r^3\)

where T represents the orbital period, G is the gravitational constant, M is the mass of the host star, and r is the average distance between the planet and the star.

Since the planet is moving along its orbit at a constant speed, we can assume that it has a roughly circular orbit. Therefore, the average distance between the planet and the star is equal to its distance of 2 AU.

Plugging in the values and solving for T, we find:

\(T^2 = (4\pi ^2/GM) * (2 AU)^3\)

Using the appropriate values for G, M, and converting AU to kilometers, we can calculate the orbital period T. The result is approximately 4.43 Earth years.

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Answer: Yes!

Explanation: Think of a number graph. If we go right it will be positive and if we go left it'll be negative. Like this the velocity can me negative or positive based on the direction.

It is gravity that causes planets to orbit around each othe—for example, Earth orbits around the Sun. During the daytime of its orbit, the Sun provides sunlight that produces vegetation for creatures to eat and light for us to see. However, it can cause a thunderstorm and when it comes, it can set trees on fire releasing carbon dioxide into the atmosphere and producing global warming, melting glaciers.

Answer:

b.

Explanation:

Mitosis is important for growth and development  of living organisms.

The major importance of mitosis is growth and development. The correct option is B.

Mitosis is the method by which a cell replicates as well as then segregates its chromosomes, and generates two identical nuclei in order to divide.

Mitosis is basically followed by the equal division of the cell's contents into two daughter cells with identical genomes.

Mitosis occurs in the following stages:

One cell divides once during mitosis to form two identical cells. Mitosis is primarily responsible for cell growth and replacement.

Thus, the correct option is B.

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Answer:

a. Aim of the experiment: To identify the magnetic fields around the bar magnet.

b. After tapping the paper, the iron filings align themselves according to the lines of the magnetic force of bar magnet. The magnetic field is more concentrated at the ends of poles as most of the iron fillings are attracted at the poles and the pattern form by iron filling shows the magnetic field of the bar magnet.

c. If iron filings will be replaced with grit, there will be no magnetic movement around bar magnet as grit is not a metal and do not have any magnetic properties.

Explanation:

a) The experiment with paper, iron sprinkles and bar magnet was performed to show the presence of the magnetic field around the magnet.

o) In the experiment, when we placed two opposite poles and sprinkled the iron over, the iron filings were aligned between forces applied by the opposite poles that are they attract each other. When the same poles were placed facing each other, the iron sprinkles were arranged away from each other. This shows that opposite poles attract each other while the same poles repel each other.

c) If iron filings were replaced with the grit, the magnetic field will be stronger.