Scientists in the laboratory create a uniform electric field E⃗ = 7.0×10^5 k^V/m in a region of space where B⃗ =0⃗ . Part A) What are the components of the electric field in the reference frame of a rocket traveling in the positive x-direction at 1.1×106 m/s ? (0, 0, 7.0×10^5 k^V/m) Correct Part B) What are the components of the magnetic field in the reference frame of the rocket?

The car's new speed will be 11.56 m/s.

Speed is the amount of distance covered in a unit of time. It refers to how quickly an object is moving. The scalar quantity speed symbolizes the size of the velocity vector. It's lost its feeling of purpose. An object is moving quicker when it is moving at a higher speed. It is moving more slowly if the speed is lower. If something isn't moving at all, it has no speed.

The momentum is conserved here, so Initial momentum = Final momentum.

Initial mass, m = 13000 kg

Initial velocity = 16 m/s

Final mass after load = 13000 + 5000 = 18,000 kg

Based on the above point,

13000 × 16 = 18000 × v

v = \(\frac{208000}{18000}\)

v = 11.56 m/s

To know more about speed, visit:

brainly.com/question/13262646

#SPJ4

The frequency is 983.56Hz, will be heard by the occupants of the car moving at the given speed.

What is Frequency?

It is the number of cycles or vibrations a body in periodic motion experiences during one unit of time, as well as the number of waves that pass, a fixed point in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration.

What are the calculations?

Given,

Speed of train = 28 m/s

Speed of car = 53 m/s

Frequency of car's horn = 580 Hz

Frequency of train's whistle = 340 Hz

When the car is behind the train, the frequency of the car is:

By using formula of frequency =  \(f_{c} = f_{t ( 1 + \frac{V_{c} }{V_{t} } )\)

Put the value into the formula =    \(fc = 340 * (1 + \frac{53}{28} )\)

                                                        \(fc =\) 983.56Hz

Hence, frequency is 983Hz, will be heard by the occupants of the car.

To know more about Frequency, check out:

https://brainly.com/question/28495377

#SPJ4

Answer:

323.4N

Explanation:

Given parameters:

Mass of the box = 33kg

Unknown:

Normal force on the body  = ?

Solution:

The normal force of a body is the vertical force the body exerts on another body.

It is expressed as;

        Normal force  = mass x acceleration due to gravity

Acceleration due to gravity  = 9.8m/s²

Normal force  = 33 x 9.8  = 323.4N

Answer:

number 1 is falling freely number 2 I think the 2nd option number 3 3rd option

1).  If you're standing on a scale in an elevator, and the scale reads much less than your real weight, then the elevator must be accelerating downward.

(Think of the extreme limit: If the elevator is in free-fall, accelerating down at 9.8 m/s², then you'll apear to be weightless ... the scale will read zero.)

2).  A 100 kg man is standing in an elevator, accelerating up at 2.0 m/s².

The net force acting on him is F = m·a = (100 kg) x (2.0 m/s²) = 200 N up.

The forces acting on  him are:

-- gravity, m·g = (100 kg) x (9.8 m/s²) = 980 N down

-- elevator floor force . . . EF up

Net force = (980N down) + (EF up)

(200N up) = (980N down) + (EF up)

Add (980N up) to each side:

(200N up + 980N up) = EF up

Elevator force = 1180N up.

Pick the second choice:  1.2 x 10³ N up

3).  My computer is resting on my desk.

There are many forces acting on my computer, and they are all balanced.

That means the NET force acting on my computer is zero.

If the net force were NOT zero, then my computer would be accelerating in the direction of the net force. But it's at rest. So the net force must be zero.

(a) The acceleration due to gravity on this asteroid is approximately 1.82 m/s². (b) The mass of the pack on the asteroid is approximately 1.78 kg.

Gravity is the force by which a planet or other body attracts objects toward its center. The force of gravity keeps all of the planets in orbit around the sun. Gravity exists between any two masses, any two bodies, any two particles. Gravity is one of the four fundamental forces of nature.

The acceleration due to gravity is the acceleration experienced by an object in freefall at the Earth's surface. It is represented by the symbol g. The acceleration due to gravity is always measured with respect to the Earth's surface.

How to calculate acceleration due to gravity?

The formula for the acceleration due to gravity is:

g = F / m

where F is the force due to gravity and m is the mass of the object experiencing the acceleration.

The formula for weight is given by:

F = m x g

where F is the force due to gravity, m is the mass of the object, and g is the acceleration due to gravity.

We know that the acceleration due to gravity in Earth is 9.806 m/s², and the mass of the pack is constant whether on Earth or on the asteroid. Using the formula, we can calculate the mass of the pack.

m = F/g

m = 17.5 N / 9.806 m/s² ≈ 1.78 kg

Using this mass, we can calculate the acceleration due to gravity on the asteroid, given that the force or weight is 3.24 N.

g = F/m

g = 3.24 N / 1.78 kg ≈ 1.82 m/s²

Learn more about acceleration due to gravity here: https://brainly.com/question/28721569

#SPJ11

Answer:

437500Joules

Explanation:

Kinetic energy=1/2mvsquare

1/2 x 1400 x 25 x25

kinetic energy= 437500Joules

The spacing between the laser modes can be expressed in terms of frequency, wavelength, and wave number. To find the spacing, we can use the following formula for each term:

1. Frequency: Δν = c / 2L
2. Wavelength: Δλ = λ^2 / 2L
3. Wave number: Δk = 2π / λ

Where c is the speed of light (3 x 10^8 m/s), L is the length of the laser cavity, λ is the wavelength of the laser light, and Δν, Δλ, and Δk represent the spacing in frequency, wavelength, and wave number, respectively.

1. For the spacing in frequency (Δν), use the formula:
Δν = c / 2L
Plug in the values for c and L to find the frequency spacing.

2. For the spacing in wavelength (Δλ), use the formula:
Δλ = λ^2 / 2L
Plug in the values for λ and L to find the wavelength spacing.

3. For the spacing in wave number (Δk), use the formula:
Δk = 2π / λ
Plug in the value for λ to find the wave number spacing.

To find the spacing between the laser modes, use the provided formulas for frequency, wavelength, and wave number spacing, and plug in the appropriate values for the speed of light, laser cavity length, and laser light wavelength. This will give you the spacings in terms of frequency, wavelength, and wave number.

To know more about speed of light visit

https://brainly.com/question/28224010

#SPJ11

The first and second blocks move at the same speed.

What is the law of conservation of mechanical energy ?

The law of conservation of mechanical energy states that the total mechanical energy of a system is constant if the only forces acting on the system are conservative.

The total mechanical energy of a system is the sum of kinetic and potential energy.

E = KE + PE

This is the total energy, kinetic energy and potential energy of the system.

The kinetic energy of the

system is:

KE = 1/2 x m x v^{2}

This is the mass and velocity of the object.

The gravitational potential energy is:

PE = mgh

Here is the acceleration of gravity and altitude.

To learn more about the law of conservation of mechanical energy from the link ;

https://brainly.in/question/1062718

#SPJ4

Answer:

mass=0.50kg

force=25N

acceleration =?

Now,

force=m×a

25=0.50×a

25÷0.50=a

50=a

acceleration =50m/s^2 answer!!!!

hope this may help you!!!!

Answer:

The answer is 50 m/s squared.

Explanation:

A=M/F

A= 25 Newtons

     ------------------  (DIVIDED BY)

      0.5 Kilograms

A= 50 m/s squared

Answer:1.36078

Explanation:

Newton's law of universal Gravity:

F = G * (M1 * M2)/ r^2

Where:

G = gravitational constant = 6.674 x10^-11 Nm^2kg^2

M1 = mass 1 = 45.9 kg

M2 = mass 2 = 5.98 x 10 ^24 kg

r = Distance between the 2 objects = 6.38 x 10 ^6 m

Replacing;

F = 450.048 N

Answer:

1) 150 [m/min]; 2) 250 [m/min].

Explanation:

1) time=10min; distance=1,5km, then the speed=distance/time=1.5/10[km/min]= 0.15 [km/min] or 150 [m/min] or 2.5 [m/s];

2) time=10 min; distance=2.5 km, the the speed=distance/time= 2.5/10= 0.25[km/min] or 250 [m/min] or ≈4.17 [m/s].

Answer:

The force must increase

Explanation:

According to newton's second law "force is the product of mass and acceleration".

      Force  = mass  x acceleration

Now, the mass of the sports car is lesser compared to that of the truck. Therefore, to take both automobiles to the same speed, enough force must be applied by the engine of the truck.

There must be an increase in the force in order to make both automobiles attain the same speed.

Radio waves are transverse waves that disturb electromagnetic fields.

Electromagnetic field, a feature of space brought on by the movement of an electric charge. Only an electric field will be generated by a stationary charge in the surrounding area. A magnetic field is also created if the charge is in motion.

A changing magnetic field can also create an electric field. An electromagnetic field is created by the mutual interaction of electric and magnetic fields. This field is thought to exist independently of any charges or currents (a stream of moving charges) to which it may be related. It is possible to think of this electromagnetic field in some situations as an electromagnetic energy-transporting wave.

Learn more about Radio waves

https://brainly.com/question/21995826

#SPJ4

Answer:

D.)

Explanation:

the current separates on each branch according to the resistance it experience.

Answer:D

Explanation:

Answer:

F = 3.01 N

Explanation:

Given that,

Mass of a block, m = 2.75 kg

Force applied to the block, F = 5.11 N

It is directed 53.8° above horizontal.

We need to find the total force acting on the block. The force acting on it is given by :

\(F=F\cos\theta\\\\F=5.11\times \cos53.8\\F=3.01\ N\)

So, 3.01 N of force is acting on the block.

3.01 works as the right answer

Answer: True

no matter can be created nor destroyed in any process. if something is burned, made in a compound or anything like that all matter is still the same amount from beginning to end.

Explanation:

Answer:

The energy stored in a cloud due to separation of charges that causes a lightning strike can be estimated using the equation:

E = (1/2) * C * V^2

where E is the energy stored, C is the capacitance of the cloud, and V is the potential difference between the cloud and the ground.

Assuming that the capacitance of the cloud is 10 microfarads and the potential difference between the cloud and the ground is 100 million volts, the energy stored in the cloud is:

E = (1/2) * 10^-5 F * (10^8 V)^2 = 5*10^13 J

Now, if 12.5 coulombs of charge is transferred from the cloud to the ground, the energy dissipated can be calculated as:

W = V * Q = V * (12.5 C)

where W is the work done, Q is the charge transferred, and V is the potential difference between the cloud and the ground during the lightning strike.

Assuming that the potential difference remains constant at 100 million volts, the work done or energy dissipated is:

W = (10^8 V) * (12.5 C) = 1.25 * 10^10 J

Therefore, the fraction of stored energy dissipated is:

Fraction = (energy dissipated) / (energy stored)

Fraction = (1.25 * 10^10 J) / (5*10^13 J)

Fraction = 0.00025 or 0.025%

Thus, only a very small fraction of the energy stored in the cloud is dissipated during a lightning strike.

As per the given statement, if 12.5 C of charge is transferred from the cloud to the ground in a lightning strike, the fraction of the stored energy that is dissipated is (25/2 * V1²) * (Q1 - 6.25) / Q1².

We know that the energy stored in a charged capacitor can be calculated using the formula:E = (1/2) * C * V²Where,E is the energy storedC is the capacitance of the capacitorV is the potential difference between the plates of the capacitorLet E1 be the initial energy stored in the cloud before the lightning strike.And E2 be the energy stored in the cloud after the lightning strike.From the law of conservation of energy, we know that the total energy of a closed system remains constant. Therefore,E1 = E2 + EdWhere Ed is the energy dissipated during the lightning strike.Let the capacitance of the cloud be C.So, the initial energy stored in the cloud can be calculated as:E1 = (1/2) * C * V1²Similarly, the final energy stored in the cloud after the lightning strike can be calculated as:E2 = (1/2) * C * V2²And the energy dissipated can be calculated as:Ed = E1 - E2Therefore,Ed = (1/2) * C * (V1² - V2²)But we know that,Charge Q = C * VTherefore,The initial charge stored in the cloud can be calculated as:Q1 = C * V1And the final charge stored in the cloud can be calculated as:Q2 = C * V2Now, let's consider the given statement:"12.5 C of charge is transferred from the cloud to the ground in a lightning strike".So, the final charge stored in the cloud can be written as:Q2 = Q1 - 12.5We need to find the fraction of energy dissipated.Using the above expressions for Ed and Q2, we get:Ed = (1/2) * C * [(Q1/C)² - ((Q1 - 12.5)/C)²]Ed = (1/2C) * [Q1² - (Q1 - 12.5)²]Ed = (1/2C) * [(Q1² - Q1² + 25Q1 - 156.25)]Ed = (25/2C) * (Q1 - 6.25)Ed/Q1 = (25/2C) * (1 - 6.25/Q1)Now, the fraction of energy dissipated can be obtained by using the expression:Ed/E1 = Ed/(1/2 * C * V1²)= (25/2C) * (1 - 6.25/Q1) / (1/2 * C * V1²)= (25/2 * V1²) * (1 - 6.25/Q1) / Q1= (25/2 * V1²) * (Q1 - 6.25) / Q1²Hence, the fraction of energy dissipated is (25/2 * V1²) * (Q1 - 6.25) / Q1².

To know more about lightning strike click here:

brainly.com/question/15733465

#SPJ11

Answer:

I believe its inference

Explanation:

Answer:

2.45 m/s²

Explanation:

From the question,

On the Earth

W = mg.................. Equation 1

Where W = weight of the alien on the earth, m = mass of the alien on the earth, g = acceleration due to gravity of the earth.

Make m the subject of equation 1

m = W/g................... Equation 2

Given: W = 3200 N

Constant: 9.8 m/s²

Substitute these value into equation 2

m = 3200/9.8

m = 326.5 kg.

Similarly,

On planet 9,

W' = mg'............... Equation 3

Where W' = weight of the alien on planet 9, g' = acceleration due to gravity on planet 9.

make g' the subject of the equation

g' = W'/m............ Equation 4

Given: W' = 800 N

Substitute into equation 4

g' = 800/326.5

g' = 2.45 m/s²

Answer:

\(5.2\ \text{m/s}\)

\(70^{\circ}\) south of east

Explanation:

\(v_a\) = 3 m/s

\(\theta_a\) = \(20^{\circ}\) north of east

\(v_b\) = 6 m/s

\(\theta_b\) = \(40^{\circ}\) south of east = \(360-40=320^{\circ}\) north of east

x and y component of \(v_a\)

\(v_{ax}=v_a\cos \theta\\\Rightarrow v_{ax}=3\times \cos 20^{\circ}\\\Rightarrow v_{ax}=2.82\ \text{m/s}\)

\(v_{ay}=v_a\sin\theta\\\Rightarrow v_{ay}=3\times \sin20^{\circ}\\\Rightarrow v_{ay}=1.03\ \text{m/s}\)

x and y component of \(v_b\)

\(v_{bx}=v_b\cos \theta\\\Rightarrow v_{bx}=6\times \cos 320^{\circ}\\\Rightarrow v_{bx}=4.6\ \text{m/s}\)

\(v_{by}=v_b\sin\theta\\\Rightarrow v_{by}=6\times \sin320^{\circ}\\\Rightarrow v_{by}=-3.86\ \text{m/s}\)

\(\Delta v=v_b-v_a\\\Rightarrow \Delta v=(4.6-2.82)\hat{i}+(-3.86-1.03)\hat{j}\\\Rightarrow \Delta v=1.78\hat[i}-4.89\hat{j}\)

Magnitude

\(|\Delta v|=\sqrt{(-4.89)^2+1.78^2}\\\Rightarrow \Delta v=5.2\ \text{m/s}\)

Direction

\(\theta=\tan{-1}|\dfrac{-4.89}{1.78}|\\\Rightarrow \theta=70^{\circ}\)

The magnitude of the change in velocity vector is \(5.2\ \text{m/s}\) and the direction is \(70^{\circ}\) south of east.

The change in velocity will be  \(\Delta V=5.2\ \frac{m}{s}\) and the direction will be \(70^o\) South to east.

Any quantity which is defined by its magnitude and direction both are called as the vector quantities.

Now the data given in the question will be given as:

\(V_a\) = 3 m/s

\(\theta\) = \(20^o\) north of east

\(V_b\) = 6 m/s

\(\theta\) =  \(40^o\)south of east =  360-40=320 north of east

Now we will find the x and y component of \(V_a\)

\(V_{ax}=V_acos\theta\)

\(V_{ax}=3\times Cos20\)

\(V_{ax}=2.82\ \frac{m}{s}\)

\(V_{ay}=V_aSin\theta\)

\(V_{ay}=3\times Sin20\)

\(V_{ay}=1.03\ \frac{m}{s}\)

Now we will find the x and y component of \(V_b\)

\(V_{bx}=V_bcos\theta\)

\(V_{bx}=6\times cos\320\)

\(V_{bx}=4.6\ \frac{m}{s}\)

\(V_{by}=V_bSin\theta\)

\(V_{by}=6\times Sin320\)

\(V_{by}=-3.86\ \frac{m}{s}\)

Now change in velocity will be

\(\Delta V=V_b-V_a\)

\(\Delta V=(4.6-2.82)i+(-3.86-1.03)j\)

\(\Delta V=1.78i-4.89j\)

The magnitude can be find out as follows:

\(\Delta V=\sqrt{(-4.89^2+(1.78^2)}\)

\(\Delta V=5.2\ \frac{m}{s}\)

The direction of the vector will be

\(\theta= tan^{-1}(\dfrac{-4.89}{1.78})\)

\(\theta=70^o\)

Thus the change in velocity will be  \(\Delta V=5.2\ \frac{m}{s}\) and the direction will be \(70^o\) South to east.

To know more about Vectors follow

https://brainly.com/question/25705666

Based on the provided information, Magnitude and direction of the position. Magnitude: 40.392 m; Direction: West.

Magnitude and direction of the velocity. Magnitude: 11.672 m/s; Direction: West.

It is given that:

Initial velocity of the particle = 20.4 m/s

Acceleration of the particle = 4.40 m/s²

Time at which the position and velocity of the particle is to be found = t = 1.98 s

We can find the position of the particle by using the formula:

position = initial_position + initial_velocity × time + (1/2) × acceleration × time² = 0 + (20.4 m/s) × (1.98 s) + (1/2) × (−4.40 m/s²) × (1.98 s)² = 40.392m west of the starting position.

Therefore, the magnitude of the position is 40.392 m. The direction of the position is west. Since the particle is moving in the opposite direction to the east.

Magnitude and direction of the velocity can be found by using the formula:

velocity = initial_velocity + acceleration × time= 20.4 m/s + (−4.40 m/s²) × (1.98 s) = 11.672 m/s directed west

Therefore, the magnitude of the velocity is 11.672 m/s. The direction of the velocity is west.

Learn more about Velocity:

https://brainly.com/question/25905661

#SPJ11

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the mass

From the question

f = 20 N

m = 5 kg

We have

\(a = \frac{20}{5} \\ \)

We have the final answer as

Hope this helps you

The most simplified form of the law of conservation of energy that describes the motion of a block sliding from the top of a table to the bottom of a ramp is:1/2mv^2i + mghi = 1/2mv^2f + mghf

In this equation, the terms represent different forms of energy. Let's break it down:

- 1/2mv^2i represents the initial kinetic energy of the block, where m is the mass of the block and vi is its initial velocity.

- mghi represents the initial potential energy of the block, where m is the mass, g is the acceleration due to gravity, and hi is the initial height of the block.

- 1/2mv^2f represents the final kinetic energy of the block, where vf is its final velocity.

- mghf represents the final potential energy of the block, where hf is the final height of the block.

This equation states that the sum of the initial kinetic energy and the initial potential energy of the block is equal to the sum of its final kinetic energy and final potential energy.

It implies that energy is conserved throughout the motion, with no energy lost or gained, neglecting any non-conservative forces or work done by friction (Wnc).

For more such questions on motion,click on

https://brainly.com/question/25951773

#SPJ11