S Review. Two identical hard spheres, each of mass m and radius r, are released from rest in otherwise empty space with their centers separated by the distance R . They are allowed to collide under the influence of their gravitational attraction. (b) What If? Find the magnitude of the impulse each receives during their contact if they collide elastically.

Answer:

v = 27.5 m/s

Explanation:

p = m × v

6,875 = 250 × v

250v = 6,875

v = 6,875/250

v = 27.5 m/s

The effect is that the electrons shield the nucleus from the magnetic field.

A magnetic field is a vector field that explains the magnetic influence on moving electric charges, electric currents, and magnetic materials.

A force perpendicular to the charge's own velocity and the magnetic field acts on it when it moves through a magnetic field.

Moving electric charges generate magnetic fields.

Everything is constructed of atoms, and each atom has an orbiting nucleus that is composed of protons and neutrons.

Compass, motors, refrigerator magnets, railroad tracks, and modern roller coasters are all examples of objects that use magnetic force.

Charges that travel across its areas feel a force. All moving charges produce a magnetic field.

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Measuring the density of DI water, a balance or scale with high precision and accuracy would be expected to give the greatest accuracy since it can measure the mass of the water with high accuracy and low systematic and random errors.

In the calculation of the density of DI water, several measuring devices can be used to determine the mass and volume of the water, such as a balance or scale for mass measurement and a graduated cylinder or burette for volume measurement. The accuracy of the measuring device can affect the accuracy of the calculated density.

In general, the measuring device with the greatest accuracy is the one with the smallest systematic and random errors. Systematic errors are those that affect the accuracy of the measurement consistently, while random errors are those that affect the accuracy randomly and independently. Therefore, a measuring device with a small systematic error and low random error will give the greatest accuracy.

A graduated cylinder or burette may introduce some errors due to the uncertainties in reading the volume, but these errors can be reduced by using a smaller volume measuring device or increasing the number of readings taken.

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Answer:

(I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

Explanation:

Given that,

Mass of black hole \(m= 1\times10^{8} M_{sun}\)

(I). We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Where, G = gravitational constant

M = mass

c = speed of light

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times1\times10^{8}\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=2.94\times10^{8}\ km\)

(II). Mass of block hole \(m= 6 M_{sun}\)

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times6\times1.989\times10^{30}}{(3\times10^{8})^2}\)

\(R_{g}=17.7\ km\)

(III). Mass of block hole m= mass of moon

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times7.35\times10^{22}}{(3\times10^{8})^2}\)

\(R_{g}=1.1\times10^{-7}\ km\)

(IV). Mass = 50 kg

We need to calculate the Schwarzschild radius

Using formula of radius

\(R_{g}=\dfrac{2MG}{c^2}\)

Put the value into the formula

\(R_{g}=\dfrac{2\times6.67\times10^{-11}\times50}{(3\times10^{8})^2}\)

\(R_{g}=7.4\times10^{-29}\ km\)

Hence, (I). The Schwarzschild radius is \(2.94\times10^{8}\ km\)

(II). The Schwarzschild radius is 17.7 km.

(III). The Schwarzschild radius is \(1.1\times10^{-7}\ km\)

(IV). The Schwarzschild radius is \(7.4\times10^{-29}\ km\)

The energy conservation allows to find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

The schwarschild radius is defined as the distance from a black hole center at radius  which the escape velocity is equal to the light speed, in some cases it is also called the event horizon.

Let's use Newton's second law where force is the universal law of attraction and acceleration is centripetal.

        F = ma

        F = \(G \frac{Mm}{r^2}\)        

Where F is the force, M the mass of the black hole, m the handle of the body, r the radius and v the speed of the body.

The energy of the gravitational field is

        F = \(- \frac{dU}{dr }\)  

         U = \(-G \frac{Mm}{r}\)  

Let's use conservation of energy

        Em₀ = K + U = ½ m v² -  \(G \frac{Mm}{r}\)  

In infinity the energy

        Em_f = 0

energy is conserved

       Em₀ = Em_f  

       ½ m v² - \(G \frac{Mm }{r}\)  = 0

       r = \(\frac{2GM}{v^2}\)

From the definition of the Schwarschild radius this speed is equal to the light speed

        v = c

        r = \(\frac{2GM}{c^2 }\)  

They ask to calculate the radius for several cases of different mass, claculate the constant value

      V = \(\frac{2 \ 6.67 \ 10^{-11} }{(3 \ 10^8) ^2 }\)  

      V =  1.482 10⁻²⁷

1) A black hole of mass M = 1 10⁸ \(M_{sum}\)

The tabulated mass of the sun is \(M_{sum}\) = 1.989 10³⁰ kg

Let's  substitute

        r =  1.482 10⁻²⁷   1 10⁸ 1.989 10³⁰

        r = 2.94 10⁸ km

With two significant figures

        r = 2.9 10⁸ km

2) A black hole of mass M = 6 \(M_{sum}\)

        r =  1.482 10⁻²⁷ 6 1.989 10-30

        r = 17.7 km

3) a mini black hole with the mass of the moon

    Tabulated mass of the moon M = 7.35 10²² kg

       r =  1.482 10⁻²⁷  7.35 10²²    

       r = 1.1 10⁻⁷ km

4) A person of M = 50 kg

    r =  1.482 10⁻²⁷ 50

    r=  7 10-29 km

In conclusion using the conservation of energy we can find the Schwarschild radius for several bodies of different masses are:

  1)  Black hole quasar is:  r = 2.9 10⁸ km

  2) Blsck hole supernove is:  r = 17.7 km

  3)  Mini black hole is:   r = 1.1 10⁻⁷ km

  4) Human body is:  r=  7 10⁻²⁹ km

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Answer:

A) The ball will roll forever in a straight path.

For compound microscope:  the objective lens produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image.

For simple microscope: The objective lens produces a real, inverted image that is viewed directly by the eye without the need for an eyepiece lens.

For telescope: The objective lens or mirror produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image. The eyepiece can be positive or negative depending on the desired magnification.

The following are some signs (positive or negative) of objective and eyepiece lenses in microscopes and telescopes:

Objective lens:

Eyepiece lens:

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Answer:

connect two 9 ohms resistance in series now it becomes 18 ohm

Answer:

deers...?

Explanation:

Answer:

Deers, rabits, and trees.

Explanation:

thats my answer

Answer:

Acids break down fabrics and can cause burns if the acids are strong.

Explanation:

When working with acids, it is advisable for a scientist for wear a protective apron or lab coat because acids break down fabrics and can cause burns.

Acids are chemical substances that produces excess hydroxonium ions in solutions.

Answer:

C. Acids break down fabrics and can cause burns if the acids are strong.

Explanation:

i did the quiz on edg

Answer:

C.

Explanation:

Because the speed pf the boat will depends of the driver.

Answer:

I think lead is the heaviest one

Answer:

B. 40 m/s

Explanation:

v=vo+at

a= 10m/s squared

t=4s

vo=0

v=?

v=4(10)

v=40m/s

-Have a great day!

The velocity of the object just before it hits the ground is 40 m/s

The given parameters;

time of the pebble, t = 4 s

To find;

The following kinematic equation will be used;

\(v = v_0 + gt\)

where;

g is the acceleration due to gravity = 10 m/s²;

\(v = 0 + 10 \times 4\\\\v= 40 \ m/s\)

Thus, the velocity of the object just before it hits the ground is 40 m/s

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Answer:

The automobile's acceleration in that time interval is -2 m/s^2

Explanation:

The acceleration is defined as the rate of change of the velocity.

The average acceleration in a given lapse of time is calculated as:

A = (final velocity - initial velocity)/time.

In this case, we have:

initial velocity = 31 m/s

final velocity = 15 m/s

time = 8 seconds.

Then the average acceleration is:

A = (15m/s - 31m/s)/8s = -2 m/s^2

Answer:

mean= sum of all values/ total no. of values

values given= 4,6,8,20,12

= 4+6+8+20+12/5

=50/5=10

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While stirring, solid table salt is added to a beaker of water until no more salt will dissolve and salt crystals are visible at the bottom of the beaker. When the beaker is heated, the crystals dissolve  effect of heat in this situation D increased the solubility of the salt crystals

Solubility  can be described as the term that is been used in chemistry which express the  ability of a substance,  known as the solute, to form a solution .

The substance that this solute form a substance with an be regarded as the  solvent howevr the solubility of different compound is differnt from each other.

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Electron must pass the potential difference of ΔV ≈ -798.1 V to accomplish this.

The negative sign indicates that the electron needs to pass through a potential difference of 798.1 V (volts) in the opposite direction of the electric field to achieve the desired acceleration.

To calculate the potential difference through which an electron must pass to accelerate from a velocity of 5.00×10^6 m/s to 7.00×10^6 m/s, we can use the kinetic energy equation for a moving charged particle:

ΔK = qΔV

where ΔK is the change in kinetic energy, q is the charge of the electron, and ΔV is the potential difference.

The change in kinetic energy can be calculated using the formula:

ΔK = (1/2)mv^2_final - (1/2)mv^2_initial

where m is the mass of the electron, v_final is the final velocity, and v_initial is the initial velocity.

Substituting the given values:

ΔK = (1/2)(9.11×10^-31 kg)(7.00×10^6 m/s)^2 - (1/2)(9.11×10^-31 kg)(5.00×10^6 m/s)^2

ΔK ≈ 1.277 × 10^-16 J

Since the charge of the electron is -1.6 × 10^-19 C, we can rearrange the equation to solve for the potential difference:

ΔV = ΔK / q

ΔV = (1.277 × 10^-16 J) / (-1.6 × 10^-19 C)

ΔV ≈ -798.1 V

The negative sign indicates that the electron needs to pass through a potential difference of 798.1 V (volts) in the opposite direction of the electric field to achieve the desired acceleration.

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Answer:

1.234gk

Explanation:

The equation that describes the vertical position y of the box as a function of the horizontal position x of the box is y = 1/2 x^2 + 0.5xt.

A crane and box are both initially at rest. At time t=0s, the crane begins to drive forward at a constant speed of 0. 5ms, while also lifting the box with an upward acceleration of 1ms2.

This equation agrees with the sketch in part (b) because it shows that the vertical position of the box increases as the horizontal position increases, as shown in the sketch. This equation also shows that the vertical position of the box increases with time at a rate of 1 m/s^2, which is the value used for the upward acceleration of the box.

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To calculate the power required to do 6 kJ of work in three minutes, we need to use the formula P = W/t, where P is the power in watts, W is the work done in joules, and t is the time taken in seconds.

First, we need to convert the time from minutes to seconds. Since one minute equals 60 seconds, three minutes would be 3 x 60 = 180 seconds. Next, we can substitute the values into the formula: P = 6,000 / 180 = 33.33 watts. Therefore, the power required to do 6 kJ of work in three minutes is 33.33 watts. It's important to note that power is a measure of how quickly work is done. In this case, the power required to do 6 kJ of work in three minutes is relatively low, which suggests that the work is being done at a slower rate. In contrast, if a higher power output was required to do the same amount of work, it would indicate that the work was being done more quickly. Understanding power requirements is important in a wide range of fields, including engineering, physics, and energy production.

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When a positive charge moves in the presence of a magnetic field, it experiences a force that is perpendicular to both its direction of motion and the direction of the magnetic field. This is known as the magnetic force or the Lorentz force.

In each of the six cases shown in the diagram, the direction of the magnetic force on the positive charge can be determined using the right-hand rule. Here are the steps to use the right-hand rule:1. Point the thumb of your right hand in the direction of the velocity of the positive charge.

Curl your fingers in the direction of the magnetic field.3. The direction in which your palm faces is the direction of the magnetic force on the positive charge.Using this rule, we can determine the direction of the magnetic force in each of the six cases as follows.The magnetic force is downwards4. The magnetic force is upwards5. The magnetic force is to the left6.

The magnetic force is to the right In summary, the direction of the magnetic force on a positive charge that moves in the presence of a magnetic field can be determined using the right-hand rule. The direction of the magnetic force is perpendicular to both the velocity of the charge and the direction of the magnetic field.

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Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δ\(x=\frac{(Wavelength)(Distance between slit and screen)}{Width}\)

Δ\(x=\frac{(590/10^{9})(1.90) }{(2.30)}\)

Δ\(x=0.000000487 m\)

Hope this helps!

The distance between the first-order and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

Given:

wavelength, λ = 590 nm = 590 × 10⁻⁹ m

Distance between the slit and screen, D = 1.90 m

Width of slit, d = 2.30 m

Calculation:

We know that the distance between two slits is given as:

Δx = λD / d

where  λ is the wavelength of light

           D is the distance between the slit and screen

           d is the width of the slit

Applying values in the above equation we get:

Δx = (590 × 10⁻⁹ m)(1.90 m) / (2.30 m)

    = 4.874 × 10⁻⁷ m

    = 4.874 × 10⁻⁵ cm

Therefore, the distance between the first- and second-order dark fringes on the screen will be 4.874 × 10⁻⁵ cm.

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The equilibrium law for the nuclide is 0.388 days per one, according to the announcement.

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The phrase "parallel adaptive fluid–structure interaction simulation of explosions impacting on building structures" refers to a computational method used to study the effects of explosions on buildings. Let's break it down step by step:

"Parallel adaptive": This refers to the use of parallel computing techniques, where multiple processors or cores work together to solve the simulation problem faster. It allows for efficient computation of complex simulations by dividing the workload.

"Fluid–structure interaction": This term describes the interaction between a fluid (such as air or water) and a solid structure (such as a building) in a simulation. It considers how the fluid affects the structure and vice versa. In this case, it refers to how the explosion impacts the building and how the building responds to the explosion.

"Simulation of explosions impacting on building structures": This means that the simulation aims to model the effects of explosions on buildings. It can help researchers and engineers understand how buildings behave under explosive forces, and can be used to design safer structures or develop strategies to mitigate the damage caused by explosions.

The phrase refers to a computational method that uses parallel computing techniques to simulate the interaction between fluids and structures, specifically focusing on explosions impacting building structures. This simulation can provide valuable insights into the behavior of buildings under explosive forces.

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When the difference is small, that is the starting orbit is just one level above the ending orbit, the wavelength of the photon will have a relatively small value.

Atomic emission is the process of light emission from an atom that occurs when the atom gets excited by either heating, bombarding with electrons, or a discharge of electric current. When an atom is excited, the electrons gain energy and move to a higher energy level or shell. When they return to the lower energy state, they emit energy in the form of electromagnetic radiation or light.

The energy of the emitted photon or light is directly proportional to the difference in the energy levels of the atom before and after the emission process. The relationship is given by:E=hfwhere E is the energy of the emitted photon, h is the Planck's constant, and f is the frequency of the emitted photon. The frequency of the emitted photon can be calculated using the formula:f=c/λwhere c is the speed of light and λ is the wavelength of the photon.

Thus, for an atom to emit radiation of a particular wavelength, the difference in energy levels of the atom must correspond to that wavelength. If the difference is small, the wavelength of the emitted photon will also be small, and if the difference is large, the wavelength of the emitted photon will be large.

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As it is a result of external forces acting upon it rather than a failure to maintain its state of motion.

The observation that a ball rolling down a bowling alley moves slightly slower with time does not violate Newton's first law of motion, also known as the law of inertia.

Newton's first law states that an object at rest will remain at rest, and an object in motion will remain in motion with a constant velocity (which includes moving at a constant speed in a straight line or moving with a constant speed in a curved path) unless acted upon by an external force. In other words, an object will maintain its state of motion (or lack thereof) unless an external force is applied to it.

In the case of a ball rolling down a bowling alley, the ball is subject to various external forces that act upon it and cause it to slow down. These forces include friction between the ball and the lane, air resistance, and deformation of the ball itself. These forces act in the opposite direction of the ball's motion and cause it to lose speed over time, as the ball's kinetic energy is dissipated into other forms of energy.

Therefore, the ball's decrease in speed over time is not a violation of Newton's first law, as it is a result of external forces acting upon it rather than a failure to maintain its state of motion.

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The reaction is the force applied by the player's glove on the ball.

Newton's third law of motion states that when one body exerts a force on the other body, the first body experiences a force which is equal in magnitude in the opposite direction of the force which is exerted”.

The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.

The direction of the force on the first object is opposite to the direction of the force on the second object.

According to this question, a player catches a ball. The action is the force to the ball against the player's glove while the reaction or opposite force will be the player's glove against the ball.

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Answer:

a = G M / R^2      acceleration due to gravity

aE /aP = (ME / RE^2) / (MP / RP^2) = (ME / MP) * (RP^2 / RE^2)

Since MP = 2 ME   and RP = 2 RE

aE / aP = 1/2 * 2^2 = 2

So the gravitational field strength of the planet is 1/2 that of the earth or 4.9 N/kg

Electromagnetic induction is the process of generating an electric current by moving a conductor through a magnetic field. When a conductor moves through a magnetic field, a voltage is induced in the conductor. This is known as Faraday's Law of Electromagnetic Induction.

This voltage can be used to create an electric current in the conductor.To perform an electromagnetic induction lab, you will need materials such as a magnet, a coil of wire, a battery, and a galvanometer. The following are the steps to perform the experiment:

Step 1: Connect the galvanometer to the coil of wire.Step 2: Attach the magnet to the battery.Step 3: Move the magnet back and forth across the coil of wire.Step 4: Observe the reading on the galvanometer.

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