The researchers determined the approximate electric field generated by an electric eel by measuring a potential difference of 5.6 V between two electrodes that were 1.0 cm apart, they calculated that the electric field produced by the eel was approximately 5,60 V/m.
The electric field strength can be calculated by dividing the potential difference by the distance between the electrodes. In this case, the potential difference measured was 5.6 V, and the distance between the electrodes was 1.0 cm (or 0.01 m).
Using the formula for electric field strength (E = V/d), we can substitute the values to find the electric field generated by the eel. E = 5.6 V / 0.01 m = 560 V/m.
However, since the potential difference was measured in volts and the distance was measured in centimeters, we need to convert the units to match. Converting the distance from centimeters to meters (1 cm = 0.01 m) and then dividing the potential difference by the converted distance, we get E = 5.6 V / 0.01 m = 560 V/m.
Therefore, the approximate electric field generated by the electric eel is 560 V/m.
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Edit: The complete question is
Researchers measured the strength of the electric field produced by an electric eel by placing electrodes inside the body of a dead prey fish. In one test, a potential difference of 5.6 V was measured between two electrodes that were 1.0 cm apart. What was the approximate electric field generated by the eel?
most of the energy we use on earth comes from the sun—how does that energy(light and thermal)end up?
As ____energy in our food
As ____energy of wind or moving water
As ____energy that was our lights
As ____energy when we move around
how does a hammer gives force to a hot iron when we hit it to make a weapon
Draw a circuit in series, 6 lamps, 3 electrical equipment, 1 power source, open
3 electrical equipments consider for this circuit diagram are,
1. Ammeter
2. Resistance
3. Resistance
The circuit diagram with 6 lamps and 3 electrical equipments and 1 power source with open circuit form is represented as,
quantization of electron energy states in an atom is better understood in terms of the electron's
Quantization of electron energy states in an atom is a fundamental concept in atomic physics and quantum mechanics. It refers to the discrete and distinct energy levels that an electron can occupy in an atom.
This quantization is better understood in terms of the electron's wave-like nature. The electron behaves like a wave, and its energy is related to the wavelength and frequency of the wave.
The wave-like behavior of the electron was first proposed by Louis de Broglie in 1924, and it was later confirmed by experiments. According to de Broglie's theory, electrons have wave-particle duality, meaning that they can exhibit both wave-like and particle-like behavior. When an electron is confined to an atom, its wave-like behavior leads to the quantization of energy levels.
The quantization of energy levels in an atom arises from the fact that electrons can only occupy specific orbitals around the nucleus. These orbitals have specific energies associated with them, and the electron can only exist in one of these energy levels. When an electron absorbs or emits energy, it must do so in discrete packets or quanta, which correspond to the energy difference between the energy levels.
In summary, the quantization of electron energy states in an atom is a consequence of the wave-like nature of the electron. It arises from the fact that electrons can only occupy specific orbitals around the nucleus, and their energies are quantized in these orbitals. This concept is fundamental to our understanding of atomic structure and has important implications for a wide range of fields, including chemistry, materials science, and electronics.
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In ionic bonding , atoms _____
Answer:
atom is formed by sharing
Explanation:
Answer:
sharing or transferring
A student, Jim, was drinking from a glass filled with ice water on a hot day.
Jim noticed that water droplets had formed on the outside of the glass and
asked where the water came from. Two other students, Maddy and Theo,
each tried to answer Jim's question.
Maddy's Viewpoint
Air contains some water. The air contains more water on hot days than on
cold days. When the air comes in contact with the cold glass, the water in the
air forms water droplets on the outside of the glass.
Theo's Viewpoint
Air does not contain water. The water droplets on the outside of the glass
must have come from inside the glass. The water can get outside the glass
in one of two ways. One way is that the water can pass through tiny pores in
the glass. Another way is that the water can make its way up the side of the
glass and over the edge Water droplets form on a glass only when the water
in the glass is colder than the outside air. So, the colder the water, the more
likely it will pass through the glass or make its way over the edge of the
glass
Condensation is the process through which water droplets develop on the outside of the glass containing ice water.
Water vapour in the surrounding air cools down due to the low temperature of the glass, changing it from a gaseous to a liquid form.
The process by which water vapour in the air is transformed into liquid water is known as condensation. This is the opposite of evaporation.
Warm air colliding with cold surfaces can cause condensation. Also, when the air is in an environment with an excessive amount of humidity.
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A student ties a ball at the end of a string and whirls the string at a constant speed. If the radius of the circle along which the ball moves is 1.2 m and the acceleration is 7.5 m/s2what is the speed of the ball?
a = v ² / R
where a is acceleration, v is speed, and R is the radius. So
7.5 m/s² = v ² / (1.2 m)
v ² = (7.5 m/s²) / (1.2 m)
v ≈ 6.8 m/s
an object in motion will have a speed which is a scaler , or ( blank ) which is a vector .
Answer:
Velocity
Explanation:
Objects in motion usually have a speed which is scalar or velocity which is a vector.
A scalar quantity is one with magnitude but has no directional attribute.
A vector quantity is one with both magnitude and directional attribute.
Speed is a scalar quantity that describes the magnitude of motion a body accrues.
Velocity is a vector quantity that describes both the magnitude of motion and the direction of motion in a body.
Hurry pls!!!!! Where on the ocean floor will you find the greatest amount of living organisms?
Answer: The majority of marine organisms are found in coastal areas.
Explanation: As opposed to the open ocean or deep water habitats. Coastal areas receive more sunlight and are usually warmer than open ocean or deep water habitats.
it's a distance of 45 m in 3 seconds what is the speed of the car in kilometer per hour
Answer:
1.33mph
Explanation:
if the period of the lowest-frequency sound you can hear is 0.0500.050 ss , then what is its frequency? express your answer to two significant figures and include the appropriate units.
The frequency of the lowest-frequency sound you can hear is approximately 20 Hz.
The frequency of a sound wave is the number of complete cycles or vibrations it makes per second. The period of a wave is the time it takes for one complete cycle.
The formula relating frequency (f) and period (T) is:
f = 1 / T
Given the period of the lowest-frequency sound as 0.050 s, we can calculate its frequency using the formula:
f = 1 / 0.050 s
= 20 Hz
Therefore, the frequency of the lowest-frequency sound you can hear is approximately 20 Hz.
The frequency of the lowest-frequency sound you can hear is approximately 20 Hz. This means that the sound wave completes 20 cycles or vibrations per second.
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During radioactive decay, ___ energy was transformed to ____
energy. This energy is released from the ____ (layer of the earth) via ____ . (type of heat transfer).
Answer:
Potential energy is transfer to kinetic energy,
If radio active substance is decayed.
an eager puppy runs in a straight line. its motion is shown on the following graph of horizontal position X vs time. What is the instantaneous speed of the puppy at t = 2s?
Answer: 0.25m/s
Explanation:
Answer:
Explanation:
Blab balh its 0.25 m/s
The ______ technique uses a radio frequency wave to excite hydrogen atoms in the brain to create an image of the living human brain.
The technique that uses a radio frequency wave to excite hydrogen atoms in the brain to create an image of the living human brain is called magnetic resonance imaging (MRI).
MRI is a non-invasive medical imaging technique that provides detailed structural and functional information about the brain. It relies on the principle of nuclear magnetic resonance (NMR), which involves the behavior of atomic nuclei in a magnetic field.
During an MRI scan, the patient is placed inside a strong magnetic field, which aligns the hydrogen atoms in the body, particularly those in water molecules, in a specific direction. Radio frequency pulses are then applied, causing the hydrogen atoms to absorb and emit energy. These emitted energy signals are detected by the MRI machine and used to construct a detailed image of the brain.
By analyzing the signals from different regions of the brain, MRI can produce high-resolution images that reveal the brain's anatomical structures and detect abnormalities or pathologies. It is widely used in clinical settings for diagnosing various conditions, such as tumors, strokes, multiple sclerosis, and traumatic brain injuries. Additionally, functional MRI (fMRI) can also be performed to study brain activity by measuring blood flow changes associated with neural activity, enabling researchers to map brain functions and understand cognitive processes.
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What is the speed of the netball as it hits
the ground? Use the information from 1.5m
above ground level
mass= 0.4
Answer:
v = 5.42 [m/s]
Explanation:
To solve this problem we have to use the concept of energy transformation which tells us that kinetic energy is transformed into potential energy and vice versa.
The potential energy can be defined by means of the following equation.
Ep = m*g*h
where:
m = mass = 0.4 [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1.5 [m]
Ep = 0.4*9.81*1.5
Ep = 5.88 [J]
Since the potential energy is equal to the kinetic energy, we can find the velocity by means of the kinetic energy equation.
Ek = 0.5*m*v²
where:
Ek = kinetic energy = 5.88 [J]
5.88 = 0.5*0.4*v²
v = 5.42 [m/s]
A student is planning to make changes to a circuit. Which change will increase the current?

A.
Add an electric bell to the circuit.

B.
Replace the existing battery with a smaller battery.

C.
Replace the wire with one that is thicker.

D.
Replace the wire with one that is thinner.
The change that will increase the current is option C: replacing the wire with one that is thicker.
To increase the current in a circuit, we need to reduce the resistance or increase the voltage. Let's analyze the given options:
A. Adding an electric bell to the circuit: This will increase the resistance in the circuit, which will decrease the current. Therefore, this change will not increase the current.
B. Replacing the existing battery with a smaller battery: A smaller battery typically has a lower voltage. Since current is directly proportional to voltage, decreasing the voltage will decrease the current. Therefore, this change will not increase the current.
C. Replacing the wire with one that is thicker: The resistance of a wire is inversely proportional to its cross-sectional area. By replacing the wire with a thicker one, the resistance of the wire decreases. According to Ohm's Law (V = IR), if the voltage (V) remains constant and the resistance (R) decreases, the current (I) will increase. Therefore, replacing the wire with a thicker one will increase the current.
D. Replacing the wire with one that is thinner: The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. By replacing the wire with a thinner one, the resistance of the wire increases. As a result, the current will decrease. Therefore, this change will not increase the current.
In conclusion, the change that will increase the current is option C: replacing the wire with one that is thicker. This reduces the resistance in the circuit and allows more current to flow. Therefore, Option C is correct.
The question was incomplete. find the full content below:
A student is planning to make changes to a circuit Which change will increase the current?
A. Add an electric bell to the circuit,
B. Replace the existing battery with a smaller battery
C. Replace the wire with one that is thicker
D. Replace the wire with one that is thinner
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A 0.50 kg mass is attached to a string 1.0 meter long and moves in a horizontal circle at a rate of 0.5 seconds per revolution.
1 - Find the centripetal acceleration of the mass.
2 - Calculate the tension in the string.
(1) First compute the linear speed of the mass. If it completes 1 revolution in 0.5 seconds, then the mass traverses a distance of 2π (1.0 m) ≈ 2π m (the circumference of the circular path), so that its speed is
v = (1/0.5 rev/s) • (2π m/rev) = 4π m/s ≈ 12.57 m/s
Then the centripetal acceleration a is
a = v² / (1.0 m) = 16π² m/s² ≈ 160 m/s²
(where r is the path's radius).
(2) By Newton's second law, the tension in the string is T such that
T = (0.50 kg) a = 8π² N ≈ 79 N
(a) The centripetal acceleration of the mass is 158 m/s².
(b) The tension in the string at the given mass is 79 N.
The given parameters;
mass, m = 0.5 kglength of the string, r = 1 mnumber of revolutions, N = 1 rev per 0.5 sThe angular speed of the attached mass is calculated as follows;
\(\omega = \frac{1 \ rev}{0.5 \ s} \times \frac{2\pi \ rad}{1 \ rev} \\\\\omega = 12.57 \ rad/s\)
The centripetal acceleration of the mass is calculated as follows;
\(a_c = \omega ^2 r\\\\a_c = (12.57)^2 \times 1\\\\a_c = 158 \ m/s^2\)
The tension in the string is calculated as follows;
\(T = ma_c\\\\T = 0.5 \times 158\\\\T = 79 \ N\)
Thus, the tension in the string at the given mass is 79 N.
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A sound wave in air travels 660 metres in 2 seconds. Calculate the speed of the sound wave.
Recall and state the equation used.
Answer:
330 meters per second
Explanation:
Δx = vt
660 = 2v
Divide both sides by 2 to get 330 = v
what is the weight of a 3.67kg ball?
Answer:
mass 3.67 kg, density 600 kg/m3) is fitted
with lead (density 1.14 * 10^4 kg/m3) so that it floats in water with
0.900 of its volume submerged. Find the lead mass if the lead is fitted
to the block’s (a) top and (b) bottom.
Calculate the pressure due to a water column of height 120m ( take density of water = 1000 kg/m raise to 3, g = 10 m/s raise to 2
Answer:
P = ρ g H familiar expression for pressure due to column of liquid
P = 1000 kg/m^3 * 10 m/s^2 ^ 120 m = 1,200,000 kg / m/s^2
Can also be written P = 1.2E6 kg / (m/s^2)
Usually written as 1.2E6 N/m^2
Standard atmospheric pressure is written as
1.01E5 N/m^2
So the pressure due to the column of water would be about 12 X
that of a column of water as given
A 0.48 kg circus monkey is about to be shot from a cannon as part of his thrilling circus act. Draw a free body diagram labeling the forces acting on him at the moment he is launched from the cannon. F_(Net= ) 86N
In a launch speed formula vx = d over t, vx is acceleration, d is distance, and t is time.
Answer:
V of x is the velocity on the x graph so it is false
Hope it helps
Answer: False
Explanation:
Vx can't be acceleration because acceleration is velocity over time not distance over time (the equation for speed)
ntally Check for Understanding
POSSIBLE POINTS: 5
In a football game, the kicker kicks the football a horizontal distance of 39 m. If the ball lands 3.9 s later, what is the football's horizontal velocity just before
it lands?
0 10 m/s
41 m/s
0 34 m/s
O 14 m/s
Answer: 34
Explanation:
34
a player catches a ball. consider the action force to be the impact of the ball against the player's glove. the reaction to this force is the friction of the ground against the player's shoes. player's grip on the glove. force the glove exerts on the ball. muscular effort in the player's arms. none of these
The reaction to this force is force the glove exerts on the ball.
When a player catches the ball, what kind of force is this?
Frictional force allows the ball to stay in the hand while muscular force is employed to stop the motion of the ball during catching.
First, second, and third laws of motion of Newton :According to the first law, until a force acts on an item, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction pressures upon one another.
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Why is the sun so much bigger & brighter than the other stars in the sky?
The Sun appears bigger and brighter than other stars in the sky because it is much closer to the Earth than any other star.
While the Sun is only an average-sized star, it is still much closer to us than any other star, so it appears larger and brighter in the sky.
Additionally, the Sun is also the closest star to the Earth that undergoes nuclear fusion, which is the process that produces its energy and makes it shine.
Other stars in the sky may be much larger or brighter than the Sun, but their distance from us makes them appear much smaller and dimmer.
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a light, rigid rod is 62.1 cm long. its top end is pivoted on a frictionless horizontal axle. the rod hangs straight down at rest with a small, massive ball attached to its bottom end. you strike the ball, suddenly giving it a horizontal velocity so that it swings around in a full circle. what minimum speed at the bottom is required to make the ball go over the top of the circle?
The minimum speed required at the bottom of the circle to make the ball go over the top is approximately 3.95 m/s.
To determine the minimum speed required to make the ball go over the top of the circle, we can use the principle of conservation of energy. At the bottom of the circle, the ball has both kinetic energy and potential energy. At the top of the circle, the ball has only potential energy, which is equal to the work done by gravity in lifting the ball to that height.
Let's assume that the bottom of the circle is at a height h above the horizontal axle. The potential energy of the ball at the bottom of the circle is zero, and its kinetic energy is given by:
\(K = (1/2)mv^2\)
where m is the mass of the ball and v is its speed. At the top of the circle, the potential energy of the ball is:
U = mgh
where g is the acceleration due to gravity.
The total energy of the ball is conserved, so we have:
K + U = mgh
Substituting the expressions for K and U, we get:
\((1/2)mv^2 + 0 = mgh\)
Simplifying and solving for v, we get:
\(v = sqrt(2gh)\)
where sqrt represents the square root function.
To find the value of h, we can use the fact that the length of the rod is 62.1 cm. When the ball is at the top of the circle, the rod is at an angle of 90 degrees to the horizontal, so the height of the top of the circle above the axle is:
\(h = 62.1 cm - r\)
where r is the radius of the ball. We can assume that the radius of the ball is small compared to the length of the rod, so we can neglect it. Therefore, h = 62.1 cm.
Substituting this value into the expression for v, we get:
\(v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 0.621 m) ≈ 3.95 m/s\)
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If an object is moving with a velocity of 24 m/s and has an acceleration of -4m/s2,
how long will it take it to stop?
A.-6s
B.6s
C.-96 s
D.20s
Answer:a
Explanation:
A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car
Answer:
\(4.5 *10^{3}\ kgm/s^{2}\)
Explanation:
Given:
\(Mass= 1.00 * 10^{3} \ kilograms,\\Acceleration =4.5\ meters/second^{2}\)
As we know that
Force=Mass * Acceleration
Putting the value of mass and Acceleration we get ,
\(Force\ = \ 1.00 * 10^{3} * 4.5\ m/s^{2}\)
\(Force\ =4.5 * \ 10^{3} \ kgm/s^{2}\)
Therefore Net force is :\(4.5 *10^{3}\ kgm/s^{2}\)
Answer:
See image
Explanation:
Plato
hi please I need help with my mMATHEMATICS ASSIGNMENTS
1. Find the value of x and y in the following ratios
a. 3:5 = x:20
b.11:35 = 66: y
2. In a village of 375 children under the age of 10. If 68% of them have had malaria, how many children have escaped the disease?
3. Five buses need 3 trips to take 450 students to the stadium to watch a concert. How many trips would the 3 buses need to take the same number of students?
4. The ratio of girls to boys in a boarding school is 2:7. If there are 1,251 students in the school:
a. How many of the students are girls?
b. What percentage of the students are boys?
5. An old carpet which now costs #1 000, was sold for #1 400 when new. Calculate the percentage decrease.
6. The cost of petrol is #65 per litre. What is the percentage increase if it is sold for #105 per litre by a dealer during fuel scarcity?
Answer:
1
(a) Ans we are applying the formula
product of means = product of extremes
So according to the formula 5x = 60
x= 60/5
x = 12
(b) Ans we are applying the formula
product of means = product of extremes
2310=11 y
y = 2310/11
y = 210
Explanation:
(a)In product of means we multiply inner values with each other like in this case for solution of a part 5 and x are inner values and in product of extremes we multiply outer value like in case of solution for a 3 and 20 are outer values.
a gas is initially at 0 gauge pressure and compressed to 1/8 of the initial volume at constant temperature. what is the new gauge pressure? (include units with answer)
Answer:
P1 V1 = P2 V2 for constant temperature
V2 = V1 / 8
P1 V1 = P2 V1 / 8 or P2 = 8 P1
P1 = A atmospheric pressure
P2 = 8 P1 = p2 + A p2 = pressure on gauge
p2 + A = 8 A
p2 = 7 A
If A = 15 lbs / in^2 then
p2 = 105 lbs / in^2
Check:
P1 = 15 lbs / in^2
P2 = 8 * p1 = 120 lbs / im^2
p2 = 120 lbs/in^2 - 15 lbs/in^2 = 105 lbs/in^2