Read: https://kids.britannica.com/kids/article/DNA/390730 (Links to an external site.)

Answer the following questions:

1. What sort of things does DNA determine for a creature? (Think physical traits)

2. Sometimes there are mistakes in DNA, what are these mistakes called? what sort of things can these mistakes cause?

3. What makes up the sides of the DNA structure?

4. There are four different bases in DNA: adenine, thymine, guanine, and cytosine. About how many total pairs do humans have in their DNA?

The new planet is suitable for human life because it is similar to planet earth.

The new planet has similar atmosphere just like the earth's atmosphere. It has large amount of vegetation that can hold large amount of animals. It is suitable for growing for different crops that provide food to humans.

So we can conclude that the new planet is suitable for human life because it is similar to planet earth.

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The ideal gas law may be used to determine the volume of oxygen created in the electrolysis that produces 548 litres of hydrogen at STP (Standard Temperature and Pressure). PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature, according to the ideal gas equation.

The pressure is 1 atm, the temperature is 273 K, and the number of moles of hydrogen is 548/22.4 = 24.5 in this example. We may compute the volume of oxygen created by rearranging the ideal gas law: V = nRT/P = 24.5*0.082*273/1 = 483.3 litres.

As a result, the volume of oxygen created in the electrolysis at STP that produces 548 litres of hydrogen is 483.3 litres.

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To prepare 70 mL of zinc sulfate eyedrops APF, you would need the following ingredients:

Zinc sulfate monohydrate: 0.07 g

Chlorobutol aqueous solution: 10.45 mL

Boric acid powder: 0.7 g

Glycol aqueous solution: 0.14 mL

To calculate the amount of each ingredient needed to prepare 70 mL of zinc sulfate eye drops APF, we'll follow these steps:

Step 1: Determine the concentration of zinc sulfate needed. Since the recipe doesn't specify the concentration, we'll assume a standard concentration of 0.1% w/v.

Step 2: Calculate the amount of zinc sulfate required. The desired concentration is 0.1% w/v, and we need to prepare 70 mL of the eye drops. Therefore, the amount of zinc sulfate needed can be calculated as follows:

Amount of zinc sulfate (g) = (Desired concentration (g/100 mL) * Volume (mL))/100

                       = (0.1 * 70)/100

                       = 0.07 g

Step 3: Determine the amounts of other ingredients based on the provided ratios. The chlorobutol solution is at a concentration of 0.67% w/v, so we need to calculate the volume required using the ratio:

Volume of chlorobutol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of chlorobutol (%)

                                  = (0.07 * 100)/0.67

                                  = 10.45 mL

The boric acid powder doesn't specify the concentration, so we'll assume it to be 1% w/v. Using the same logic, we can calculate the amount of boric acid powder required:

Amount of boric acid powder (g) = (Desired concentration (g/100 mL) * Volume (mL))/100

                             = (1 * 70)/100

                             = 0.7 g

Finally, the glycol solution is at a concentration of 50% w/v, so the volume required can be calculated as:

Volume of glycol solution (mL) = (Amount of zinc sulfate (g) * 100)/Concentration of glycol (%)

                            = (0.07 * 100)/50

                            = 0.14 mL

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13.5 x \(10^-2\) g of aluminium will be produced if 1.0 g of Ba reacts with 1.80 g of \(Al_2(SO_4)3\).

The mole is the amount of substance of a system which contains as many elementary entities as there are atoms in 0.012 kilograms of carbon 12; its symbol is “mol”.

Balanced Equation:

\(3Ba + Al_2(SO_4)_3\) → \(2Al+3BaSO_4\)

Grams of Ba: 1.0 g

Grams of \(Al_2(SO_4)_3\): 1.8g

Calculate the moles of Ba and \(Al_2(SO_4)_3\):

\(\frac{1g Ba}{137.3}\) = 7.3 x\(10^{-3}\)mol

1.8g \(Al_2(SO_4)_3\)/ 342 = 5.3 x \(10^-3\) mol \(Al_2(SO_4)_3\)

Find the limiting reactant:

Ba has a coefficient of 3 in the balanced equation, so we divide the  moles of Ba by 3 to get  7.3 x \(10^-3\) mol Ba ÷3 = 2.43 x \(10^-3\)

\(Al_2(SO_4)_3\) has a coefficient of 1, so if we divide by 1, we get the same number of 5.3 x\(10^-3\)

2.43 x \(10^-3\) is smaller than 5.3 x \(10^-3\), therefore Ba is the limiting reactant.

finally, we just find the number of moles of Al

The ratio of Al to Ba is 2:3

7.3 x \(10^-3\) x (2÷3) = 5 x \(10^-3\) mol Al

Convert into mass.

5 x \(10^-3\) mol Al  x 27 = 13.5 x \(10^-2\) g

Hence, 13.5 x \(10^-2\) g of aluminium will be produced if 1.0 g of Ba reacts with 1.80 g of \(Al_2(SO_4)3\).

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Answer:

\(C_3H_8O_2\)

Explanation:

Hello,

In this case, for the given combustion process, we can compute the present moles of carbon atoms by considering that the only product containing carbon is CO2, thus, we have:

\(n_C=4.171gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.095molC\)

Next, we compute the moles of hydrogen that is present at the water only as a product:

\(n_H=2.268gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O} =0.252molH\)

Then, we compute the moles of oxygen by considering the oxygen present in both the CO2 and H2O and the initial sample:

\(m_O=2.400g-0.095molC*\frac{12gC}{1molC} -0.252molH*\frac{1gH}{1molH} \\\\m_O=1.008gO\\\\n_O=1.008gO*\frac{1molO}{16gO} =0.063molO\)

Now, we divide the moles of C, H and O by the moles of O since they are lower amount, in order to compute the subscript in the empirical formula:

\(C=\frac{0.095}{0.063}=1.5\\ \\H=\frac{0.252}{0.063}=4\\ \\O=\frac{0.063}{0.063}=1\)

But the smallest whole number is:

\(C_3H_8O_2\)

Regards.

The volume of the gas at 101.3 kPa and 24°C will be 24.58 L.

Gas law is a set of empirical laws that describe the physical behavior of a gas. They are derived from experiments on gases, and they relate the pressure, volume, and temperature of a gas. The most famous gas law is the Ideal Gas Law, which states that the pressure, volume, and temperature of an ideal gas are related by the equation PV=nRT, where P is the pressure, V is the volume, n is the amount of gas, R is the gas constant, and T is the temperature.

At constant pressure, the volume of a gas will increase as its temperature increases. This is because the molecules are moving faster, so they take up more space. Therefore, the volume of the gas at 101.3 kPa and 24°C will be greater than 0.8 L. To calculate the exact volume, you would need to use the ideal gas law:
PV = nRT
where P is pressure,
V is volume,
n is the number of moles of gas,
R is the ideal gas constant, and
T is temperature in Kelvin.
Solving for V, we get:
V = (nRT) / P
Plugging in the given values, we get:
V = (n * 8.314 * 297.15) / 101.3
V = 24.58 L
Therefore, the volume of the gas at 101.3 kPa and 24°C will be 24.58 L.

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Answer:

B

Explanation:

The scientist had a wrong hypothesis?

Answer:

it would be C.

Explanation:

becuase the scientist would know what to to next time for his next experiment. even if it went wrong, he can try to get it right again.

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Answer:

The final temperature of the copper would be 311.3°C.

I hope this helps you

Answer:

87.6 %

Explanation:

Step 1: Write the balanced equation

LiOH + KCl ⇒ LiCl + KOH

Step 2: Calculate the theoretical yield of LiCl

We will use the following relations:

The theoretical yield of LiCl from 20.0 g of LiOH is:

\(20.0gLiOH \times \frac{1molLiOH}{23.95gLiOH} \times \frac{1molLiCl}{1molLiOH} \times \frac{42.39gLiCl}{1molLiCl} = 35.4gLiCl\)

Step 3: Calculate the percent yield of LiCl.

We will use the following expression.

\(\%yield = \frac{real\ yield}{theoretical\ yield} \times 100\% = \frac{31.0g}{35.4g} \times 100\% = 87.6 \%\)

Answer:

88.6%

Explanation:

Hello,

In this case, considering the given reaction, we notice a 1:1 molar relationship between lithium hydroxide (molar mass=23.95 g/mol) and lithium chloride (molar mass=42.394 g/mol), for that reason, we are able to compute the theoretical yield of lithium chloride by stoichiometry:

\(m_{LiCl}^{theoretical}=20.0gLiOH*\frac{1molLiOH}{23.95gLiOH}*\frac{1molLiCl}{1molLiOH} *\frac{42.394 gLiCl}{1molLiCl}=35.4gLiCl\)

Next, by knowing the actual yield of 31.0 g, we compute the percent yield as:

\(Y=\frac{m_{LiCl}^{actual}}{m_{LiCl}^{theoretical}} *100\%=\frac{31.0g}{35.4g}*100\%\\ \\Y=87.6\%\)

Therefore, among the given, the answer should be 88.6%

Best regards.

Go to the Data tab > Sort & Filter group, and click Clear.

Go to the Home tab > Editing group, and click Sort & Filter > Clear.

The partial pressure of nitrogen on Venus is approximately 321.914 kPa.

To find the partial pressure of nitrogen on Venus, we need to calculate the partial pressure using the mole fraction of nitrogen and the total atmospheric pressure. First, we convert the total atmospheric pressure from psi to kilopascals (kPa) since the mole fraction is given in terms of kPa.

1 psi = 6.89476 kPa

Therefore, the total atmospheric pressure on Venus is:

1334 psi × 6.89476 kPa/psi = 9197.53 kPa

Next, we can calculate the partial pressure of nitrogen using the mole fraction. The mole fraction of nitrogen is given as 0.035, which means that nitrogen makes up 3.5% of the total moles of gas in the atmosphere.

The partial pressure of nitrogen is given by:

Partial pressure of nitrogen = Mole fraction of nitrogen × Total atmospheric pressure

Partial pressure of nitrogen = 0.035 × 9197.53 kPa

Partial pressure of nitrogen = 321.914 kPa

Therefore, the partial pressure of nitrogen on Venus is approximately 321.914 kPa.

It's important to note that the given atmospheric composition of Venus's atmosphere and the total atmospheric pressure are approximate values and can vary depending on specific conditions and measurements.

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Answer:

0.0457 M

Explanation:

Concentration is the amount of a substance in a predefined volume of space. The basic measurement of concentration in chemistry is molarity or the number of moles of solute per liter of solution. What is the molarity of a solution containing 9.478 grams of RuCl₃, in enough water to make 1.00 L of solution?

Step 1: Given data

Step 2: Calculate the moles corresponding to 9.478 g of RuCl₃

The molar mass of RuCl₃ is 207.4 g/mol.

9.478 g × 1 mol/207.4 g = 0.04570 mol

Step 3: Calculate the molarity of the solution

We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.04570 mol / 1.00 L = 0.0457 M

ANSWER

STEP-BY-STEP EXPLANATION

Given information

The next step is to balance the above reaction

From the reaction, we can see that the

To make a stock solution, weigh out the proper amount of a pure solid or measure out the proper amount of a pure liquid, put it in the right flask, and then dilute it to the desired volume. Depending on the intended concentration unit, many methods can be used to measure the reagent.

If you take a 13.0- mL portion of the stock solution and dilute it to a total volume of 0.650 L , what will be the concentration of the final solution?

"The final solution's concentration would be 0.26M."

By adding extra solvent, you are lowering the concentration of the stock solution in the issue (This process is known as dilution).

Since you increased the volume of the fluid from 13 to 650 milliliters, it was diluted:

50 times = 650 mL / 13 mL

We must now take the concentration of the stock solution in order to determine the concentration of a final solution.

If the standard solution is 13M, then

The final solution's concentration would be 13M / 50 = 0.26M.

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Answer:

It will take 6486.92 minutes  for [H2O2] to fall from 0.95 M to 0.33 M

Explanation:

The order of reaction is defined as the sum of the powers of the concentration terms in the equation. Order of a reaction is given by the number of atoms or molecule whose concentration change during the reaction and determine the rate of reaction.

In first order reaction;

\(In \dfrac{a}{a_o-x}= k_1 t\)

where;

a = concentration at time t

\(a_o\) = initial concentration

and k = constant.

\(In (\dfrac{0.33}{0.95})= -1.63 \times 10^{-4} \times t\)

\(-1.05736933 = -1.63 \times 10^{-4} \times t\)

\(t = \dfrac{-1.05736933}{ -1.63 \times 10^{-4} }\)

t = 6486.92 minutes

Answer:

The first one is ground and the second one is excited  

Explanation:

Answer:

The balanced chemical equation will be "\(NO_{2}+O\rightarrow NO+O_{2}\)".

Explanation:

The given equation is:

\(2NO_{2}\rightarrow 2NO+O_{2}\)

Step 1:

\(2NO_{2}\rightarrow NO+O\)...(equation 1)

Step 2:

\(NO_{2}+O\rightarrow NO+O_{2}\)...(equation 2)

On adding "equation 1" and "equation 2", we get

⇒  \(NO_{2}+NO_{2}+O\rightarrow NO+O+NO+O_{2}\)

⇒  \(2NO_{2}\rightarrow 2NO+O_{2}\)

The second step:

⇒  \(NO_{2}+O\rightarrow NO+O_{2}\)

Answer:

A

Explanation:

I took the test 100%, good luck

Erosion and deposition work together to form sand dunes as waves cause erosion along coastlines and deposit sand away from the shore. So the correct option is A.

Erosion is the removal of the material's surface from the crust of the Earth. It is mainly the debris of soil and rock. The eroded materials are transported by natural agents such as water or wind from the point of their removal.

The term erosion gives an explanation for the wearing down and molding of the landforms on the surface of Earth. This includes the rock weathering from its original position, the transport of this weathered material, and the erosion which is the result of the action of wind or glacial processes, etc.

The more appropriate term for this would be denudation or degradation. This includes processes of mass movement. This is a definition of erosion that is very narrow and excludes the process of the transport of eroded material by natural agencies.

Therefore, the correct option is A.

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The equilibrium constant for the reaction is 0.0052.

Here are the steps to calculate the equilibrium constant for the reaction:

Write the equilibrium constant expression. The equilibrium constant expression for the reaction is:

K = \([SO3]^2 / [SO2]^2 * [O2]\)

Calculate the equilibrium concentrations of the reactants and products. The equilibrium concentration of oxygen is given as 0.25 mol.dm^3.

One can compute the equilibrium concentration of sulfur dioxide by applying the subsequent formula:

.

\([SO2] = (10 mol - 2 * 0.25 mol) / 2 dm^3 = 4.5 mol.dm^3\)

The equilibrium concentration of sulfur trioxide can be calculated using the following equation:

\([SO3] = (2 * 0.25 mol) / 2 dm^3 = 0.5 mol.dm^3\)

Substitute the equilibrium concentrations into the equilibrium constant expression and solve for K.

K = \((0.5 mol.dm^3)^2 / (4.5 mol.dm^3)^2 * (0.25 mol.dm^3)= 0.0052\)

Therefore, the equilibrium constant for the reaction is 0.0052.

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Answer:

0.85 mL

Explanation:

Step 1: Given data

Step 2: Calculate the volume of the aluminum block

Density is an instrisic property. It is equal to the mass of the block divided by its volume.

ρ = m/V

V = m/ρ

V = 2.3 g/(2.7 g/mL)

V = 0.85 mL

Answer:

2Hgo —>2Hg + O2

Explanation:

Answer:

Look at the picture below

Explanation:

Minerals resource used by the power plants in the large amount.

Most power plants use one or more alternators that convert mechanical energy. The most common fuels are coal, natural gas, and uranium (nuclear power). These electricity dynamo power plants were from fossil fuels such as coal, natural gas, petroleum, and other gases. About 19% was from nuclear energy, and about 20% was from continual energy sources. Nuclear, coal, and wind are just three types of energy that are used to generate electricity in power plants across the world. In normal power plants, oil, coal, natural gas, nuclear steam is generated at a force of 40 to 200 bar g and fed to a turbine, which converts the conventional power plants.

So we can conclude power plants comprise a boiler, steam turbine and generator, and another assistant.

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Answer:

Ebenezer Scrooge's business is to take care of his own establishment and thus, refused to donate/ contribute any to the charity.

He feels this way because he thinks that it is not one's business to interfere in another's business.

Explanation:

Charles Dickens's play "A Christmas Carol," tells the story of the protagonist Ebenezer Scrooge and his 'hatred' of the Christmas festival. But it was during this time of the year that he got 'inspired' by the ghost of his late partner c um friend Marley, teaching him a life lesson that changed Scrooge for the better.

When the two gentlemen came to visit the workplace of Scrooge expecting some donation for charity, Scrooge refused to give a single penny. According to him, the suffering of the people and their need is none of his business. He exclaims "I don’t make merry myself at Christmas and I can’t afford to make idle people merry. I help to support the establishments I have mentioned—they cost enough; and those who are badly off must go there." Rather, his business is to take care of his company, which "occupies [him] constantly" and thus, it's not his business to "not to interfere with other people’s".

he felt this way because he thinks that it is "unfair" and unbecoming to get involved in someone's business.

Lead 214 emits then beta electrons to transform into bismuth 214 and polonium 214, which produces lead 210 through the emission of a third alpha particle. This series of transformations take place in a time span roughly equal to an hour.

Hope this helps, if I am right, brainliest? :))))

Acetone has a concentration of 0.74 Mm.

Acetone is an organic chemical that is colorless, combustible, volatile, and has a distinctively strong odor. It is a solvent that is frequently used in a variety of commercial and domestic settings. It also serves as a starting point for the synthesis of other chemicals. Acetone has the chemical formula CH3COCH3 and a molecular weight of 58.08 g/mol.

We must first determine how many moles of acetone are present in the solution.

Per kilogram of solvent, one molal equals one mole of solute.

Since 1 kilogram is equivalent to 1000 milliliters of ethanol, it is possible to compute the number of moles of acetone as follows:

1000 mL/kg times 1.00 mol/kg is 1.00 mol.

The mass of acetone in the solution can then be determined using the molar mass of acetone (58.08 g/mol):

1 mole * 58.08 g/mol = 58.08 g

The volume of acetone can then be calculated by dividing the mass by the density:

58.08 g/0.788 g/mL equals 73.56 mL.

Finally, the molality of acetone can be determined as follows:

0.0074 mol/L (1.00 mol)/1.00 mol/(73.56 mL + 1000 mL) = 0.74 mM.

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Answer:

4 millllllermeeters jb

Answer:

All would be the correct answer! I hope this helps. :)

Answer:

experiment and investigation and procedure

Explanation:

you want to check how other people did the experiment so that you have an idea of how they did the investigation. they are all correct

Answer:

1. Write the balanced chemical equation for the reaction

2. Identify all important information provided in the word problems or data table.

3. Solve for the theoretical yield of the reaction, following all the steps of a stoichiometry calculation organizer. Use two calculations if both reactants are provided.

4. Use the percent yield equation to calculate the percent yield of the reaction.

Explanation:

its comes right from the 5.06 lesson