Re-write in standard form: y=3x-6 * Your answer​

Given, subspace S = span {1}, projection of vector v onto subspace S is projs V = 11.

We need to find the vector v and then find the projection of the vector v onto the subspace S. The projection of the vector v onto the subspace S is given by the formula: projS v = ((v•u)/(u•u)) * u where u is a unit vector in the direction of S. To find the vector v, we use the formula: v = projs V + v_⊥ where v_⊥ is the component of vector v that is orthogonal (perpendicular) to the subspace S and projs V is the projection of vector v onto the subspace S.

Since the subspace S is spanned by the vector 1, the unit vector in the direction of S is given by: Vu = 1/||1|| * 1 = 1/1 * 1 = 1Now, we can find the vector v using: v = projs V + v_⊥11 = projs V is given. So,11 = ((v•1)/(1•1)) * 1 => v•1 = 11v = [11]To find the projection of the vector v onto the subspace S, we use the formula: projS v = ((v•u)/(u•u)) * u, where v = [11] and u = 1/||1|| * 1 = 1/1 * 1 = 1So,projSv = (([11]•1)/(1•1)) * 1 = 11Therefore, the projection of the vector v = [11] onto the subspace S = span {1} is given by projS v = 11.

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The blanks in each statement about the line segment should be completed as shown below.

Since we know U is the midpoint, we can say TU=8x + 11 substituting in our values for each we get:

8x + 11 = 12x - 1

Solve for x

We now want to solve for x.

−4x+11=−1

−4x = -12

x= 3

Solve for TU, UV, and TV

This is just the first part of our question. Now we need to find TU, UV, and TV. Lets start with TU and UV.

TU=8x+11 We know that x=3 so let’s substitute that in.

TU=8(3)+11

TU= 35

We will do the same for UV. From our knowledge of midpoint, we know that TU should equal UV, however let’s do the math just to confirm.

UV=12x−1 We know that x=3 so let’s substitute that in.

UV=12(3)−1

UV= 35

Based on the segment addition postulate, we have:

TU+UV=TV

35+35=TV

TV= 70

Find the detailed calculations below;

TU = UV

8x + 11 = 12x - 1

8x + 11 - 11 = 12x - 1 - 11

8x = 12x - 12

8x - 12x = 12x - 12 - 12x

-4x = -12

x = 3

By using the substitution method to substitute the value of x into the expression for TU, we have:

TU = 8x + 11

TU = 8(3) + 11

TU = 24 + 11

TU = 35

By applying the transitive property of equality, we have:

UV = TU and TU = 15, then UV = 35

By applying the segment addition postulate, we have:

TV = TU + UV

TV = 35 + 35

TV = 70

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Answer:

x = 3 or x = -1/2

Step-by-step explanation:

hope this helps you!

Answer: 42 gallons

Step-by-step explanation:

1,260/180 = 7

Per 180 mile = 6 gallon

7x6=42

Answer:

4 years

Step-by-step explanation:

I=prt

1440=4000(r)0.09

4000r * 0.09 = 1440

divide both sides by 4000 times 0.09

r = 4

\(\\ \rm\longrightarrow 1+2\dots +20\)

Use Summation formula

\(\\ \rm\longrightarrow S_n=\dfrac{n(n+1)}{2}\)

\(\\ \rm\longrightarrow S_{20}=\dfrac{20(20+1)}{2}\)

\(\\ \rm\longrightarrow S_{20}=\dfrac{20(21)}{2}\)

\(\\ \rm\longrightarrow S_{20}=\dfrac{420}{2}\)

\(\\ \rm\longrightarrow S_{20}=210\)

Answer:

26.6666667

Step-by-step explanation:

A group of student organization who wants to study about voting preferences in its students during presidential election in 2012. So, they selected a sample of 120, is an example of stratified random sampling.

Stratified random sampling is a widely used statistical technique in which a population is divided into different subgroups, or strata, based on some shared characteristics. The purpose of stratification is to ensure that each stratum in the sample and to make inferences about specific population subgroups, that is they share (e.g., race, gender, educational attainment).

Therefore, the stratified random sample involves dividing the population into two or more strata (groups). These strata are expressed as H. A stratified random sampling because a random sample has been taken from each different strata (Freshmen through seniors).

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Answer:

Shown below.

Step-by-step explanation:

Test Marks          Tally          Frequency          Percentage

1                                                    8                   8/60 = 0.133

2                                                   6                   6/60 = 0.100

3                                                   5                   5/60 = 0.083

4                                                   5                   5/60 = 0.083

5                                                   5                   5/60 = 0.083

6                                                   8                   8/60 = 0.133

7                                                   6                   6/60 = 0.100

8                                                   7                   7/60 = 0.116

9                                                   4                   4/60 = 0.066

10                                                 5                   5/60 = 0.083

Total                                            59                 59/60 = 0.983

For the Tally section, I believe you just fill in tally marks corresponding to the frequency. One of the observations in the table is 0, which is not a column in the frequency table.

The IQ Spatial test is the one with the larger standard deviation, as it has the most spread out curve.

The higher the standard deviation, the more spread out the curve is, hence the IQ Spatial test is the one with the larger standard deviation.

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Answer:

\(20\)

Explanation:

\(5\) ÷ \(\frac{1}{4}\)

To change the division sign into a multiplication sign, you need to change (1/4) into its reciprocal.

\(5\) × \(\frac{4}{1}\)

\(5\) × \(4\)

\(20\)

The answer is (a) 0.8494, to find the probability that the battery fails before the one year warranty expires,

we need to calculate the integral of the given pdf from 0 to 1, as X represents the length of the battery life in years.

So, P(X<1) = ∫(0 to 1) f(x) dx = ∫(0 to 1) (16/49) e^(-8x^2/49) dx ≈ 0.8494

Therefore, the answer is (a) 0.8494.

The given pdf describes the distribution of the length of the battery life, and we are interested in finding the probability that the battery fails before the one year warranty expires.

This can be found by integrating the pdf from 0 to 1, as the warranty lasts for one year.

Using the formula for the probability density function, we calculate the integral of the given pdf from 0 to 1, and get the answer as 0.8494.

This means that the probability of the battery failing before the one year warranty expires is about 84.94%.

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the range in this set of data is 25 inches. To find the range of snowfall amounts, we need to look at the line plot and identify the highest and lowest amounts of snowfall that were recorded.

The range in a set of data is the difference between the maximum and minimum values in the set.

To find the range of snowfall amounts, we need to look at the line plot and identify the highest and lowest amounts of snowfall that were recorded.

Let's say that the highest amount recorded was 30 inches and the lowest amount recorded was 5 inches. Then the range would be:

range = highest amount - lowest amount

range = 30 - 5

range = 25

Therefore, the range in this set of data is 25 inches.

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9514 1404 393

Answer:

  (1, 7)

Step-by-step explanation:

Fill in x=1 and do the arithmetic.

  h(1) = 4(1) +3 = 7

The coordinate pair is ...

  (x, h(x)) = (1, h(1)) = (1, 7)

Answer:

y = –3 is the answer since the y-coordinate is –3 and y = lines are horizontal.

pls give brainliest

The equation of the horizontal line through (-7,-3) is \(y = x - 3\).and this can be determined by using the two-point form of a line.

Given :

The line is horizontal and passes through (-7,-3).

The following steps can be used in order to determine the equation of a line that passes through (-7,-3):

Step 1 - According to the given data, the line is horizontal which means it is parallel to the x-axis.

Step 2 - So, the horizontal line also passes through (0,-3).

Step 3 - So, the equation of a line that passes through the points (-7,-3) and (0,-3) is:

\(\dfrac{y+3}{x-0}=\dfrac{-3+3}{-7-0}\)

Step 4 - Simplify the above expression.

\(y = x - 3\)

So, the equation of the horizontal line through (-7,-3) is \(y = x - 3\).

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Using the Well-Ordering Principle (WOP), it can be proven that in every tournament with n players (where n is a natural number), there is at least one top player, defined as someone who either beats every other player or beats someone who beats the other player.

We will prove this statement by contradiction. Assume that there exists a tournament with n players where there is no top player. This means that for each player, there exists either another player who beats them or a chain of players such that each player beats the next one. Now, consider the set S of all players in this tournament. Since S is a non-empty set of natural numbers, it has a least element, let's say k.

Now, player k either beats every other player in the tournament, making them a top player, or there exists a player, let's say player m, who beats player k. In the latter case, we have a chain of players: k, m, p_1, p_2, ..., p_t, where p_1 beats p_2, p_2 beats p_3, and so on until p_t.

However, this contradicts the assumption that there is no top player, as either player k beats every other player (if m does not exist), or player m beats someone who beats the other player (if m exists). Hence, by contradiction, we have shown that in every tournament with n players, there is at least one top player.

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Answer:

Step-by-step explanation:

If I have 90 pounds shared between A, B, and C, then in a mathematical equation,

A + B + C = 90

However, we have way too many unknowns.

We are told that the ratio of A to B is 1 to 2, or

\(\frac{A}{B} =\frac{1}{2}\) and cross multiplying,

2A = B or \(A=\frac{1}{2}B\)

We are also told that the ratio of B to C is 4 to 3, or

\(\frac{B}{C} =\frac{4}{3}\) and cross multiplying,

3B = 4C or \(C=\frac{3}{4}B\)

Now we have everything in terms of B, so we will rewrite it like that:

\(\frac{1}{2}B+B+\frac{3}{4}B=90\), and

\(\frac{9}{4}B=90\) and

9B = 360 so

B = 40. If B is 40 and A is half of B, then A is 20.

The probability that more than thirteen loads occur during a 4-year period is approximately 0.100 or 10%.

The given distribution is Poisson distribution with mean lambda = 3 loads per year.Thus, the number of loads X per year is given by the Poisson distribution P(X = x) = (e^-λ * λ^x) / x!, where e is the mathematical constant approximately equal to 2.71828, and x = 0, 1, 2, 3, …, n.

First, we can calculate the mean and variance for the distribution, which are both equal to λ = 3 loads per year, respectively. Hence, the mean and variance for the distribution over the 4-year period would be 12 loads (4 * 3 = 12).

Now, we can calculate the probability of more than 13 loads over the 4-year period using the Poisson distribution with lambda = 12 as follows:

P(X > 13) = 1 - P(X ≤ 13)

P(X ≤ 13) = ∑ (k = 0 to 13) P(X = k)=∑ (k = 0 to 13) ((e^-12 * 12^k) / k!)≈ 0.900

Therefore, the probability of more than thirteen loads occurring during a 4-year period is:

P(X > 13) = 1 - P(X ≤ 13) ≈ 1 - 0.900 ≈ 0.100 or 10% (rounded to three decimal places).

Hence, the probability that more than thirteen loads occur during a 4-year period is approximately 0.100 or 10%.

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\(k = 1.6d\)

\(k = 1.6(665)\)

\(k = 1064\)

The distance is 1064 km.

Answer:

A. 1,064 km

Step-by-step explanation:

1 Mile is 1,6 Kilometers

430 Miles  = 688 Kilometers (430 * 1,6)

665 Miles = 1064 Kilometers (665 * 1,6)

1- 1.6(430)= 688 Km

2. 1.6(665)=1064 Km

Using 1.6 as the consant then 430* 1.6 = 688 Km

655 * 1.6 = 1048Km

if i understand what you need properly, all you do is multiply the miles x 1.6 and you will get k. so 430miles x 1.6 = 688k

and 665miles x 1.6 = 1064k

The parametric equations that define the curve starting at (6,0) and ending at (7.8) are

\($$(x(t),y(t)) = (t+6,8t)$$\)

where parameter t varies from 0 to 1.

Find parametric equations that define the curve starting at (6,0) and ending at (7.8) as shown. Let parameter t start at 0 and end at 8 y=t (Complete the X= (Complete Dec 10 (78) a 6 5 What is equation of x?

Given information:

Start point is (6, 0).

End point is (7,8).

The curve is linear, hence we can find the slope of the line passing through (6, 0) and (7, 8).

Slope of the line:

\($$m = \frac{y_2 - y_1}{x_2 - x_1}$$$$m = \frac{8 - 0}{7 - 6}$$$$m = 8$$\)

Using point-slope form of equation of line, we get:

\($$y - y_1 = m(x - x_1)$$$$y - 0 = 8(x - 6)$$$$y = 8x - 48$$\)

Therefore, x-coordinate is given by:

\($$x(t) = t + 6$$\)

And, y-coordinate is given by:

\($$y(t) = 8t$$\)

Hence, parametric equations that define the curve starting at (6,0) and ending at (7.8) are

\($$(x(t),y(t)) = (t+6,8t)$$\)

where parameter t varies from 0 to 1.

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Answer: x = 8

Step-by-step explanation: 4x + 7 ≤ 39, first subtract 7 to get 4x ≤ 32, then divide on both sides by 4 to get x ≤ 8.

Hope this helps!

Please Mark Brainliest!

(I play FN too and I am Champs)

Based on the given table, the profit-maximizing level of output for company Econislife is 4 units. At this quantity, the company's profit is $40.

To determine the profit-maximizing level of output, we need to analyze the relationship between total revenue (TR) and total costs (TC) for different quantities of output. The profit can be calculated as the difference between total revenue and total costs.

Looking at the table, we can see that as the quantity increases from 1 to 5, both total revenue and total costs increase. However, at a certain point, the increase in total costs outpaces the increase in total revenue, leading to a decrease in profit.

To find the profit-maximizing level of output, we compare the profits at different quantities.

Quantity 1: TR = $28, TC = $40, Profit = TR - TC = $28 - $40 = -$12

Quantity 2: TR = $56, TC = $45, Profit = TR - TC = $56 - $45 = $11

Quantity 3: TR = $84, TC = $55, Profit = TR - TC = $84 - $55 = $29

Quantity 4: TR = $112, TC = $72, Profit = TR - TC = $112 - $72 = $40

Quantity 5: TR = $140, TC = $120, Profit = TR - TC = $140 - $120 = $20

From the above calculations, it is evident that the profit is highest at Quantity 4. Therefore, the profit-maximizing level of output for company Econislife is 4 units. At this quantity, the company's profit is $40.

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The graphical representation that would be best to display the data is given as follows:

Histogram.

An histogram is a graph that shows the number of times each element of x was observed.

The four types of products are given as follows:

Each of these item would represent a bin, and the values of each bin are given as follows:

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The answer are: a. Total outflows: $2,007,901, b. Total inflows: $827,080, c. Net present value: $824,179, d. Should the old issue be refunded with new debt? Yes

To determine whether the old bond issue should be refunded with new debt, we need to calculate the present value of total outflows, the present value of total inflows, and the net present value (NPV). Let's calculate each of these values step by step: Calculate the present value of total outflows. The total outflows consist of the call premium, underwriting cost on the old issue, and underwriting cost on the new issue. Since these costs are one-time payments, we can calculate their present value using the formula: PV = Cash Flow / (1 + r)^t, where PV is the present value, Cash Flow is the cash payment, r is the discount rate, and t is the time period.

Call premium on the old issue: PV_call = (7% of $22 million) / (1 + 0.1)^16, Underwriting cost on the old issue: PV_underwriting_old = $530,000 / (1 + 0.1)^16, Underwriting cost on the new issue: PV_underwriting_new = $680,000 / (1 + 0.1)^16. Total present value of outflows: PV_outflows = PV_call + PV_underwriting_old + PV_underwriting_new. Calculate the present value of total inflows. The total inflows consist of the interest savings and the tax savings resulting from the interest expense deduction. Since these cash flows occur annually, we can calculate their present value using the formula: PV = CF * [1 - (1 + r)^(-t)] / r, where CF is the cash flow, r is the discount rate, and t is the time period.

Interest savings: CF_interest = (12% - 10%) * $22 million, Tax savings: CF_tax = (40% * interest expense * tax rate) * [1 - (1 + r)^(-t)] / r. Total present value of inflows: PV_inflows = CF_interest + CF_tax.  Calculate the net present value (NPV). NPV = PV_inflows - PV_outflows Determine whether the old issue should be refunded with new debt. If NPV is positive, it indicates that the present value of inflows exceeds the present value of outflows, meaning the company would benefit from refunding the old issue with new debt. If NPV is negative, it suggests that the company should not proceed with the refunding.

Now let's calculate these values: PV_call = (0.07 * $22,000,000) / (1 + 0.1)^16, PV_underwriting_old = $530,000 / (1 + 0.1)^16, PV_underwriting_new = $680,000 / (1 + 0.1)^16, PV_outflows = PV_call + PV_underwriting_old + PV_underwriting_new. CF_interest = (0.12 - 0.1) * $22,000,000, CF_tax = (0.4 * interest expense * 0.4) * [1 - (1 + 0.1)^(-16)] / 0.1, PV_inflows = CF_interest + CF_tax. NPV = PV_inflows - PV_outflows.  If NPV is positive, the old issue should be refunded with new debt. If NPV is negative, it should not.

Performing the calculations (rounded to the nearest whole dollar): PV_call ≈ $1,708,085, PV_underwriting_old ≈ $130,892, PV_underwriting_new ≈ $168,924, PV_outflows ≈ $2,007,901,

CF_interest ≈ $440,000, CF_tax ≈ $387,080, PV_inflows ≈ $827,080.  NPV ≈ $824,179.  Since NPV is positive ($824,179), the net present value suggests that the old bond issue should be refunded with new debt.

Therefore, the answers are:

a. Total outflows: $2,007,901

b. Total inflows: $827,080

c. Net present value: $824,179

d. Should the old issue be refunded with new debt? Yes

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Step-by-step explanation:

17.25×37=638.25 regular pay

additional pay 320.00

Answer:

-6 is the correct answer

Answer:

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex ad a is a multiplier

Here (h, k ) = (8, - 1 ) , then

y = a(x - 8)² - 1

To find a substitute (0, - 17 ) into the equation

- 17 = a(0 - 8)² - 1 ( add 1 to both sides )

- 16 = 64a ( divide both sides by 64 )

\(\frac{-16}{64}\) = a , that is

a = - \(\frac{1}{4}\)

y = - \(\frac{1}{4}\)(x - 8)² - 1 ← equation of parabola

Answer:

125.66in²

Step-by-step explanation:

A=2πrh+2πr2=2·π·2·8+2·π·22≈125.66371in²