rank the free radicals (i-iii) shown below in order of decreasing stability (i.e., from most stable to least stable).
CH2CH2CH(CH3)2 CH3CH2C(CH3)2 CH3CHCH(CH3)2

Answers

Answer 1

The free radicals can be ranked in decreasing stability as follows: iii > i > ii. The stability decreases as the number of alkyl groups attached to the radical carbon decreases.

The stability of free radicals is influenced by the number of alkyl groups attached to the radical carbon. More substituted free radicals tend to be more stable due to the electron-donating inductive effect of alkyl groups.

In the given compounds, let's analyze each free radical:

i) \(CH_2CH_2CH(CH_3)_2\): This free radical has one alkyl group (two methyl groups) attached to the radical carbon. The presence of two methyl groups stabilizes the radical through the electron-donating inductive effect. Hence, it is the least stable among the three.

ii) \(CH_3CH_2C(CH_3)_2\): This free radical has two alkyl groups (one ethyl group and one methyl group) attached to the radical carbon. The presence of one ethyl group and one methyl group provides more stability compared to the first free radical (i), but it is still less stable than the third free radical (iii).

iii) \(CH_3CHCH(CH_3)_2\): This free radical has three alkyl groups (two methyl groups and one ethyl group) attached to the radical carbon. The presence of three alkyl groups imparts the highest stability among the given free radicals. The additional alkyl groups provide increased electron-donating inductive effects, making this free radical the most stable.

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Related Questions

which of the following octahedral complex ions will have the fewest number of unpaired electrons? 1) [FeF_6]^3 2)[Cr(H_2O)_6]^3+ 3) [Ni(NH_3))_6]^2+ 4) [RhCl_6]^3- 5)[V(H_2O)_6]^3+

Answers

The number of unpaired electrons in a complex ion depends on the number of electrons in the d-orbitals of the metal ion. The d-electron configuration of each complex ion is as follows: 1) d5, 2) d3, 3) d8, 4) d5, and 5) d2.

The complex ion with the fewest number of unpaired electrons will be the one with the highest d-electron pairing energy, which is the energy required to pair up electrons in the same orbital. The complex ion with the highest pairing energy is [Ni(NH3)6]2+, with all of its electrons paired up. Therefore, the answer is 3) [Ni(NH3)6]2+.

The octahedral complex ion with the fewest number of unpaired electrons is 3) [Ni(NH_3)_6]^2+. This is because Ni^2+ has an electron configuration of 3d^8, which means all its d-orbitals are either completely filled or contain paired electrons. In contrast, the other complex ions have metal ions with more unpaired electrons in their d-orbitals, such as Fe^3+ (3d^5), Cr^3+ (3d^3), Rh^3+ (4d^6), and V^3+ (3d^2). The ligands in each complex do not significantly affect the number of unpaired electrons. Thus, [Ni(NH_3)_6]^2+ has the lowest number of unpaired electrons among the given options.

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TIME REMAINING
16:31:41
What is the name of the hydrocarbon CH3(CH2)6CH3?
butane
decane
octane
propane

Answers

Answer:

octane is the answer have a good day

TIME REMAINING16:31:41What is the name of the hydrocarbon CH3(CH2)6CH3?butanedecaneoctanepropane

What does the Periodic Table not help scientists do?
A. Identify the most common compounds found on Earth.
B. Learn more about elements based on the groups and periods they are in.
C. Make predictions about what kind of properties new elements might have.
D. Determine how many protons, neutrons, and electrons an element has.

Answers

Your answer is A.

B, C, and D are all true.

A lump of zinc is tossed into a beaker of 500L of 14M hydrochloric acid. this reaction produces Hydrogen Gas and zinc (II) chloride. If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, what is the mass of the zinc?

Answers

If the hydrogen gas is combusted and produces 645L of water vapor at 400 kelvin and 1.75 atm, 2796.96 g mass of the zinc is produced .

Using the ideal gas law equation:

PV = nRT

n = (PV) / (RT)

= (1.75 atm * 645 L) / (0.0821 atm·L/(mol·K) * 400 K)

= 42.71 moles

the balanced equation for the reaction between zinc and hydrochloric acid:

Zn + 2HCl -> \(ZnCl_{2}\)  + \(H_{2}\)

1 mole of zinc produces 1 mole of hydrogen gas. Therefore, the moles of zinc are also 42.71.

The molar mass of zinc is 65.38 g/mol.

Mass of zinc = moles of zinc * molar mass of zinc

= 42.71 moles * 65.38 g/mol

= 2796.96 g

Therefore, the mass of the zinc is 2796.96 grams.

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Put the following elements in order, with the element having the most valence electrons at the top of your list and the element with the fewest valence electrons at the bottom.swap_vertAstatine (At)swap_vertArsenic (As)swap_vertCalcium (Ca)swap_vertSodium (Na)swap_vertOxygen (O)swap_vertSilicon (Si)swap_vertAluminum (Al)

Put the following elements in order, with the element having the most valence electrons at the top of

Answers

answer

1. Neon

2. Astatine

3. oxygen

4. Arsenic

5. Silicone

6. Aluminium

7. Calcium

8. Sodium

Question 2. Which two spectra can tell us the most information about chemical composition and motion?​

Answers

Answer:

The spectra can be divided into two types viz., emission and absorption spectra. The differences between them are given below. 1) The emission spectrum is obtained due to emission of radiation from the substances. The absorption spectrum is obtained when the substance absorbs the radiation.

Explanation:

give at least five insights that you learn from this lesson, as your way of recognizing the uniqueness of earth as a planet life

Answers

Answer and Explanation:

The lesson about the uniqueness of the earth allowed me to realize that the earth is the only planet that has drinking water and oxygen, thus allowing the existence of life on the planet and showing that we would not fully survive on another planet.

The lesson also shows that the earth is the only planet where rotation is capable of causing seasonal differences in different parts of the globe. This is important for several things, including food production and plant growth.

Another factor that shows the uniqueness of the land is its favorable temperature for life, allowing us to have water and to be able to live outdoors, for example. This factor is worrying, since the holes in the ozone layer have caused changes in this temperature.

I was also able to learn about the gravity of the earth, which is the only thing that allows us to do all the activities we do and allows us not to be launched into space. In addition, gravity has a strong influence on seas and agriculture.

Finally, I was able to learn about the tectonic plates, which provide the movement of our crust and influence in several geological processes.

Your company currently uses a process with a similar cost of materials that has an average

percent yield of 91 percent. If the average percent yield of this process is higher than that,

this could save the company money. What is your recommendation to the company? Please

support your recommendation using your data, calculations, and understanding of

stoichiometry gathered from this lab. /

Answers

The second method is recommended due to high efficiency.

What method should be recommended?

If the average percent yield of this process is higher than that, this could save the company money so my recommendation to the company is to adopt the other method for production because it is less costly and providing similar result.

In conclusion, the second method is recommended due to high efficiency.

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during the process of roasting copper(i) sulfide, how many grams of sulfur dioxide form when 10.0 mol of copper(i) sulfide reacts?

Answers

To determine the number of grams of sulfur dioxide formed when 10.0 mol of copper(I) sulfide reacts during the process of roasting, we need to use the balanced chemical equation and the molar masses of the compounds involved.

The balanced chemical equation for the reaction of copper(I) sulfide (Cu2S) with oxygen (O2) to form copper(I) oxide (Cu2O) and sulfur dioxide (SO2) is:

2 Cu2S + 3 O2 → 2 Cu2O + 2 SO2

From the balanced equation, we can see that for every 2 moles of Cu2S, 2 moles of SO2 are formed.

Therefore, using the stoichiometry of the reaction:

10.0 mol Cu2S * (2 mol SO2 / 2 mol Cu2S) = 10.0 mol SO2

Next, we can calculate the mass of sulfur dioxide using the molar mass of SO2, which is approximately 64.06 g/mol:

Mass of SO2 = 10.0 mol SO2 * 64.06 g/mol

= 640.6 g

Therefore, when 10.0 mol of copper(I) sulfide reacts during roasting, approximately 640.6 grams of sulfur dioxide are formed.

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Use the following terms to create a concept map:
acid, base, salt, neutral, litmus, blue, red, sour bitter, PH, alkali

this concept is for class 10

Answers

Acids and bases are chemical substances with contrasting properties. Acids taste sour, turn litmus paper red, and have a low pH. Bases taste bitter, turn litmus paper blue, and have a high pH. When an acid and a base react, they form a salt and water, resulting in a neutral solution.

Acids and bases are fundamental concepts in chemistry. Acids have a sour taste, such as vinegar or lemon juice, and turn litmus paper red. They also have a low pH value, indicating a high concentration of hydrogen ions (H+). On the other hand, bases have a bitter taste, like soap or baking soda, and turn litmus paper blue.

Bases have a high pH value, indicating a low concentration of hydrogen ions and a higher concentration of hydroxide ions (OH-). When an acid and a base react, they undergo a neutralization reaction, resulting in the formation of a salt and water. The salt is composed of a cation from the base and an anion from the acid. The resulting solution is neutral, with a pH of 7. Examples of salts include sodium chloride (table salt) and calcium carbonate (chalk). Alkalis are a type of base that can dissolve in water, forming hydroxide ions.

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complete and balance the following neutralization reaction, name the products, and write the net ionic equation.
HBr (aq) + KOH (aq) --> KBr + H_2O

Answers

The neutralization reaction between hydrobromic acid (HBr) and potassium hydroxide (KOH) can be completed and balanced as follows:

HBr(aq) + KOH(aq) → KBr(aq) + H2O(l)

The products of this reaction are potassium bromide (KBr) and water (H2O).

To write the net ionic equation, we exclude the spectator ions, which are the ions that appear on both sides of the equation unchanged. In this case, the potassium ion (K+) is a spectator ion because it appears on both sides. Therefore, the net ionic equation is:

H+(aq) + OH-(aq) → H2O(l)

In the net ionic equation, the hydrogen ion (H+) from the acid and the hydroxide ion (OH-) from the base combine to form water (H2O).

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PLeaseee ITS Timedddd + BrainlIESTT
A 6.50 gram piece of aluminum reacts with an excess of oxygen. use the balanced equation below to determine how many grams of aluminum oxide is formed during this reaction.
4 Al + 3 O2 --> 2 Al2O3
a. 662.7 grams of Al2O3
b. 6.1 grams of Al2O3
c. 24.6 grams of Al2O3
d. 12..3 grams of Al2O3

Answers

Answer:

d. 12.3 grams of Al2O3

Explanation:

The balanced equation in this question is as follows:

4Al + 3O2 → 2Al2O3

In this equation above, 4 moles of Al produces 2 moles of Al2O3

However, the moles of Al2O3 must first be found using;

mole = mass/molar mass

Molar mass of Al = 27g/mol

mole = 6.50/27

= 0.241mol of Al.

Hence, if 4 moles of aluminum (limiting reagent) reacts to form 2 moles of aluminum oxide (Al2O3).

Then, 0.241mol of Al will produce (0.241 × 2/4) = 0.241/2 = 0.121mol of Al2O3.

Convert this mole value to molar mass using mole = mass/molar mass

Molar mass of Al2O3 = 27(2) + 16(3)

= 54 + 48

= 102g/mol

mass = molar mass × mole

mass = 102 × 0.121

mass of Al2O3 = 12.34grams.

How is energy related to the change of state represented by the model
A. Atoms gain energy as a gas changes to a solid

B. Atoms gain energy as a gas changes to a liquid

C. Atoms lose energy as a gas changes to a liquid

D. Atoms lose energy as a gas changes to a liquid

How is energy related to the change of state represented by the modelA. Atoms gain energy as a gas changes

Answers

C and D I think
Tryna get to 20 characters ahhhhhh

Answer:

D

Explanation:

So on the graph for the y axis the small box is .5 so how to get .3

Answers

Changing the graph's overall width is the simplest way to alter any object's width or the distance between items. The width and spacing of the bars will alter proportionally as the graph axis is stretched or released to create broader bars.

Scales should be used such that data are simple to plot and understand. Every fifth and/or tenth line on coordinate paper is significantly thicker than the other lines; a major division-line of this nature should always represent a decimal multiple of 1, 2, or 5. (e.g., 0, 1, 2, 0.05, 20, 500, etc.). Other options (like 0.3) make it exceedingly challenging to plot and comprehend the data. Scales shouldn't be set any finer than the measurement device's lowest increment for obtaining data. For instance, it is recommended to plot data from meter sticks, which have graduations of 1 mm, on a scale no finer than 1 division = 1 mm. The data would not allow for any additional plotting precision at scales smaller than 1 div/mm.

So 0.3 spaced graphs can be obtained by proportionally spacing the overall width by narrowing the 0.5 spaced graph.

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Zinc metal is added to hydrochloric acid to generate hydrogen gas and is collected over a liquid whose vapor pressure is the same as that of pure water at 20.0°C (18 torr). The volume of the mixture is 1.7 L, and its total pressure is 0.788 atm. Determine the number of moles of hydrogen gas present in the sample.

Answers

Answer:

About 0.054 moles.

Explanation:

Apply the ideal gas law. Recall that:

\(\displaystyle PV = n RT\)

Solve for n, the number of moles:


\(\displaystyle n = \frac{PV}{RT}\)

Determine the pressure of the hydrogen gas. Recall that by Dalton's Law of Partial Pressures, the total pressure is equal to the sum of the partial pressures of each individual gas:


\(\displaystyle P_T = P_\ell + P_\text{H$_2$}\)

Convert the vapor pressure of the liquid to atm (1.00 atm = 760. torr):


\(\displaystyle 18\text{ torr} \cdot \frac{1.00\text{ atm}}{760.\text{ torr}} = 0.024\text{ atm}\)

Therefore, the partial pressure of the hydrogen gas is:


\(\displaystyle \begin{aligned} P_T & = P_\ell + P_\text{H$_2$} \\ \\ (0.788\text{ atm}) & = (0.024\text{ atm}) + P_\text{H$_2$} \\ \\ P_\text{H$_2$} & = 0.764\text{ atm}\end{aligned}\)

Therefore, the number of moles of hydrogen gas present is (the temperature in kelvins is 273.15 + 20.0 = 293.2 K):


\(\displaystyle \begin{aligned} n & = \frac{PV}{RT} \\ \\ & = \frac{(0.764\text{ atm})(1.7\text{ L})}{\left(0.08206 \text{ }\dfrac{\text{L-atm}}{\text{mol-K}}\right)(293.2\text{ K})}\\ \\ & = 0.054\text{ mol H$_2$} \end{aligned}\)

In order for a substance to be considered a mineral, it must a. be a solid, liquid, or gas. b. be abundant in the crust. c. have atoms arranged in a random, non-repeating pattern. d. contain carbon.

Answers

Answer: i think its (b) be abundant in the crust

Explanation:

Liquid water at 50 °C is heated to steam at 150 °C. Which piece of information is NOT required to determine the amount of heat that must be added for this change to occur? A) Specific heat of H00) B) Specific heat of H 0(g) C) AH(fusion) D) AH(vaporization) E) All of the above are required

Answers

The piece of information that is NOT required to determine the amount of heat that must be added is the: B) Specific heat of H⁰ and C) ΔH(fusion).

To determine the amount of heat added when liquid water is heated from 50 °C to steam at 150 °C, we need to consider several factors. The specific heat of H₂O(l) is necessary to calculate the heat required to raise the temperature of the liquid water to its boiling point.

The specific heat of H₂O(g) is not required, as we are not calculating the heat needed to raise the temperature of the steam. The ΔH(fusion) is also not needed since we are not dealing with a solid-to-liquid phase change.

However, ΔH(vaporization) is crucial, as it helps determine the heat needed for the liquid-to-gas phase change. Therefore, the information NOT required is B) Specific heat of H₂O(g) and C) ΔH(fusion).

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We have created a 95% confidence interval for μ with the result (10, 15).

a) What decision will we make if we test H0 : μ = 16 versus H1 : μ ≠ 16 at α = 0.05? Justify your answer.

A) Reject H0 in favor of H1.

B) Accept H0 in favor of H1.

C) Fail to reject H0 in favor of H1.

D) We cannot tell what our decision will be from the information given.

Answers

According to the question Fail to reject H0 in favor of H1. The 95% confidence interval (10, 15) does not contain the value of 16, so we cannot reject H0 at the 0.05 level of significance.

What is confidence interval?

A confidence interval is a range of values that is used to estimate a population parameter with a certain degree of confidence. It is calculated by taking a sample from a population and using the sample statistics to estimate the population parameter. The confidence interval is a measure of the reliability of the estimate. It is calculated by taking into account the sample size, the variability of the sample, and the level of confidence desired. By increasing the sample size and decreasing the variability, the confidence interval can be made more reliable. The confidence interval provides a range of values within which the population parameter is likely to be found.

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Based on the 95% confidence interval for μ with the result (10, 15), the decision that should be made if we test H0 : μ = 16 versus H1 : μ ≠ 16 at α = 0.05 is;

A. Reject H0 in favor of H1.

What is the 95% confidence interval for the population mean?

The 95% confidence interval for the population mean μ is (10, 15).

This means that one can be 95% confident that the true population mean falls between 10 and 15.

The null hypothesis H0: μ = 16 is to be tested against the alternative hypothesis H1: μ ≠ 16 at α = 0.05 level of significance.

The confidence interval (10, 15) does not contain the hypothesized value of μ = 16, it suggests that the population mean is significantly different from 16 at the 0.05 level of significance.

Therefore, reject the null hypothesis H0 in favor of the alternative hypothesis H1.

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a substance has neither of fixed shape nor a fixed volume state whether it is a solid or liquid or gas​

Answers

A gas because if you freeze water, it turns into a shape as where gas can’t be frozen

Hey!!!

The answer of your question is Gas.

Explanations:

Solid have a fixed shape and volume.

Liquid have a definite volume but no definite shape

Gas neither have fixed shape nor a fixed volume.

Hope it helps...

Good luck on your assignment

Please help! assign oxidation numbers to all the atoms in the following equation, write each half reaction, and then identify which element is oxidized and which is reduced.

Please help! assign oxidation numbers to all the atoms in the following equation, write each half reaction,

Answers

Answer:

Explanation:

Cl2 would be 0 and in 2HCl it would be -1 so it is reduced

In br First it would be -1 then 0 so it oxidized

Answer:

Cl2 (0)+ 2H(1+)Br(1-) --> 2H(1+)Cl(1-) +Br(0)

Oxidized= HCl, Cl is oxidized

Reduced=Br, 2HBr is reduced

Oxidized Half-Reaction= Cl + 1e--> Cl

Reduced Half Reaction= Br --> Br+ 1e

Explanation:

Chlorine loses its electron when it bonds with hydrogen= oxidation

Bromine gains electrons when it breaks its bond with hydrogen= reduction

The alcohol family has properties similar to_____. HCl H2O NaCl H2SO4

Answers

Answer: H2O

Explanation: The alcohol family has properties similar to H2O.

Answer:

H2O

Explanation:

The Bohr model of the atom suggest that the protons and neutrons are found in the nucleus and the electrons orbit the nucleus much line planets around the sun. How is our modern model of the atom different from this model?

Answers

Answer:

D) The electrons move around the nucleus in an electron cloud

Explanation:

i just did it on usa test prep !

help, also brainly dont be mean and delete this.
if you steal my points, please dont i need genuine help

Answers

Answer:

I dont understand what is the question you need help on-

Explanation:

2. Fe(s) + O2(g) → Fe3O4(s) a. When 13.54 g of O2 is mixed with 12.21 g of Fe, which is the limiting reactant? b. What mass in grams of iron oxide is produced? c. What mass in grams of excess reactant remains when the reaction is complete? d. A student performed completed this reaction in a lab and made15.88 g of Fe3O4, what was their percent yield?​

2. Fe(s) + O2(g) Fe3O4(s) a. When 13.54 g of O2 is mixed with 12.21 g of Fe, which is the limiting reactant?

Answers

The percent yield shows the extent to which the reactants are converetd into products . The limiting reactant is used up in the reaction.

What is a limiting reactant?

A limiting reactant is the reactant that is in the least amount in the system.  Now;

Number of moles of Fe =  12.21 g/56 g/mol = 0.22 moles

Number of moles of O2 = 13.54 g/32 g/mol = 0.42 moles

Balanced reaction equation;

3Fe(s) + 2 O2(g) = Fe3O4(s)

If 3 moles of Fe reacts with 2 mole of O2

0.22 moles of Fe reacts with  0.22 moles * 2 mole/3 moles = 0.15 moles

Hence, Fe is the limiting reactant

If 3 mole of Fe produces 1 mole of  Fe3O4(s)

 0.22 moles  of O2   produces   0.22 moles * 1 mole/3 moles of  Fe3O4(s) = 0.1073 moles

Mass of  Fe3O4(s) =0.1073 moles  * 232 g/mol =16.9 g

Number of moles of excess reactant = 0.42 moles - 0.15 moles = 0.27 moles

Mass of excess reactant = 0.27 moles * 32 g/mol = 8.64 g

percent yield = 15.88 g/16.9 g * 100/1

= 93.4%

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Use Le Châtelier’s Principle to predict the shift in equilibrium (Left, Right, No Change) for each of the following:

REACTIONS:

A. CH4(g) + 2 O2(g) ⇌ CO2(g) + 2 H2O(g) ΔH = -230 kJ

4 Al(s) + 3 O2(g) ⇌ 2 Al2O3(s) + 150 kJ

C. N2(g) + 3 H2(g) ⇌ 2 NH3(g) ΔH = + 22 kJ

D. 2 H2O(l) + 58 kJ ⇌ 2 H2(g) + O2(g)

_____ 1. Pressure decrease for reaction A
_____ 2. Pressure increase for reaction B
_____ 3. Adding heat in reaction C
_____ 4. Decreasing heat in reaction D
_____ 5. Increasing [N2] in reaction C
_____ 6. Decreasing [H2O] in reaction D
_____ 7. Adding heat in reaction A
_____ 8. Pressure increase for reaction D
_____ 9. Increasing [Al2O3] in reaction B
_____ 10. Pressure decrease for reaction C
_____ 11. Decreasing [CO2] in reaction A
_____ 12. Decreasing heat in reaction B
_____ 13. Addition of a catalyst to reaction B
_____ 14. Increasing [O2] in reaction B
_____ 15. Pressure increase for reaction C

Answers

1. Right
2. No Change
3. Left
4. Right
5. Right
6. Left
7. Left
8. No Change
9. No Change
10. Right
11. Left
12. Right
13. No Change
14. No Change
15. Left

Explanation:

1. According to Le Châtelier's Principle, a decrease in pressure favors the side with fewer moles of gas. In this case, the reaction will shift to the right to produce more gaseous products and decrease the pressure.

2. Increasing the pressure of a reaction favors the side with fewer moles of gas. In this case, there is no change in the number of moles of gas on either side of the reaction, so the equilibrium position will not shift.

3. Adding heat to an exothermic reaction (one with a negative ΔH value) will shift the equilibrium to the left to absorb the excess heat.

4. Decreasing heat in an endothermic reaction (one with a positive ΔH value) will shift the equilibrium to the left to generate more heat.

5. Increasing the concentration of a reactant will shift the equilibrium to the right to counteract the increase.

6. Decreasing the concentration of a reactant will shift the equilibrium to the left to counteract the decrease.

7. Adding heat to an exothermic reaction (one with a negative ΔH value) will shift the equilibrium to the left to absorb the excess heat.

8. Increasing the pressure of a reaction favors the side with fewer moles of gas. In this case, there is no change in the number of moles of gas on either side of the reaction, so the equilibrium position will not shift.

9. Adding product to a reaction will not shift the equilibrium position, according to Le Châtelier's Principle.

10. Decreasing the pressure of a reaction favors the side with more moles of gas. In this case, the reaction will shift to the right to produce more gas and increase the pressure.

11. Decreasing the concentration of a product will shift the equilibrium to the right to counteract the decrease.

12. Decreasing the temperature of an endothermic reaction (one with a positive ΔH value) will shift the equilibrium to the right to generate more heat.

13. Adding a catalyst will not shift the equilibrium position, according to Le Châtelier's Principle.

14. Increasing the concentration of a reactant will not shift the equilibrium position, according to Le Châtelier's Principle.

15. Increasing the pressure of a reaction favors the side with fewer moles of gas. In this case, the reaction will shift to the left to decrease the number of gaseous molecules and decrease the pressure.

how many particles would one formula unit of mgbr2mgbr2 produce when dissolved in solution? view available hint(s)for part a how many particles would one formula unit of produce when dissolved in solution? 1 3 0 2

Answers

A total of three ions(particles) would be liberated when one formula unit of magnesium bromide is dissolved in water.

Magnesium bromide is an ionic compound, which when dissolved in water would completely ionize to give the magnesium and bromide ions as per the reaction,

MgBr2(aq) ----------> Mg2+(aq) + 2Br- (aq)

Each unit of magnesium bromide gives one magnesium ion and two bromide ions, So a total of three ions(particles) would be liberated when one formula unit of magnesium bromide is dissolved in water.

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236U >33 Np+ ____?
92
help plzzzzz

Answers

Answer:

1

Explanation:

if 33 the answer would be 92 but u think then 92 32 1

Which one of the following salts when dissolved in water will hydrolyse?

Answers

Option c) NH4Cl will hydrolyze when dissolved in water.

Hydrolysis is a chemical reaction that occurs when a salt reacts with water, resulting in the formation of an acidic or basic solution. In this case, when NH4Cl (ammonium chloride) is dissolved in water, it undergoes hydrolysis.

The ammonium ion (NH4+) is the conjugate acid of ammonia (NH3), which is a weak base. When NH4Cl dissociates in water, the ammonium ion reacts with water to form NH3 and H3O+ (hydronium ion). This process is called hydrolysis.

NH4+ (aq) + H2O (l) ↔ NH3 (aq) + H3O+ (aq)

The formation of NH3 leads to an increase in the concentration of hydroxide ions (OH-) in the solution, making it slightly basic. At the same time, the presence of H3O+ ions makes the solution slightly acidic. Therefore, the hydrolysis of NH4Cl results in a slightly acidic and slightly basic solution.

In contrast, salts like NaCl and KCl do not undergo hydrolysis when dissolved in water because they consist of cations (Na+ and K+) and anions (Cl-) that do not react with water to form acidic or basic species.

Na2SO4 (sodium sulfate) is also an example of a salt that does not undergo hydrolysis. The sulfate ion (SO42-) does not react with water to form acidic or basic species, so the solution remains neutral.

Therefore, among the given options, only NH4Cl undergoes hydrolysis when dissolved in water.

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The question is incomplete. Find the full content below:

Which one of the following salts when dissolved in water will hydrolyse?

a) NaCl

b) KCl

c) NH4Cl

d)Na2SO4

draw the aromatic compound formed in the given reaction sequence. 1 phenylethanone reacts with l d a followed by benzyl bromide. benzyl bromide is a benzene ring wiht a substituent c h 2 b r. 1 phenyl ethanone is a carbonyl bonded to methyl and benzene.

Answers

This is the reaction that's why I have added an image kindly check the attachments.

What is an aromatic compound?

Organic compounds with one or more aromatic rings are referred to as "mono- as well as polycyclic aromatic hydrocarbons". Benzene is the parent compound of aromatic compounds. Before their basic chemical properties were understood, molecules were once grouped together based on smell, giving rise to the term "aromatic." The way that aromatic compounds are currently defined has nothing to do with how they smell. Since one of the heteroatoms—oxygen, nitrogen, or sulfur—replaces at least one carbon atom in the CH group, heteroarenes are chemical compounds that share many similarities. Furan, a heterocyclic compound with such a five-membered ring containing a single oxygen atom, as well as pyridine, a heteroatoms compound with a 6 ring containing only one nitrogen atom, are examples of non-benzene compounds to aromatic properties.

For an explanation kindly check the attachments.
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Please help me...

Atoms of elements X, Y and Z have 16, 17 and 19 electrons, respectively. Atoms of argon have 18 electrons.

a Determine the formulae of the compounds formed by the combination of the atoms of the elements:
(i) X and Z
(ii) Y and Z
(iii) X with itself.

b In each of the cases shown in
A (i)–(iii) above, name the type of chemical bond formed.

c Give two properties you would expect to be shown by the compounds formed in an (ii) and an (iii).

Answers

Answer:

a 1) XZ2

2) YZ

3) X2

b 1) Ionic bond

2) Ionic bond

3) covalent bond

c) ionic compounds has high melting and boiling point

ionic compounds can conduct electicity in aqueous form

covalent compounds have electrons shared between the atoms

covalent compounds have lower melting point compared to ionic compound

Answer:

(i) XZ = Potassium Sulfide [K2SO4]

(ii) YZ = Potassium Chloride [KCI]

(iii) X = Sulfur [S]

b) (i) Ionic Bond. (ii) Ionic Bond. (iii) Covalent Bond.

c) (i) Ionic compounds have high melting and boiling points.

(ii) Ionic compounds can conduct electricity in a molten state or a solution as they have ions that can move and carry charge.

(iii) Covalent compounds have low melting and boiling points.

(iv) Covalent compounds can not conduct electricity as all electrons are involved in bonding so there are no free electrons or ions to carry the charge.

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