Rafe is placing his car on a lift to change the oil and oil filter. He needs to drive up the lift 1.5 meters and the lift raises his car 0.4 meters. What is the IMA (ideal mechanical advantage) of Rafe’s car lift?

Answer:

\({FY} = \dfrac{3}{4} \times FX\)

Explanation:

The parameters given for the planets are;

The mass of planet X = M and the radius of planet X = R

The mass of planet Y = 3·M and the radius of planet Y = 3·R

The magnitude of the gravitational force of the planets on their satellites are given by the following equation;

\(F=G \times \dfrac{M_{1} \cdot m_{2}}{R^{2}}\)

Where;

M₁ = The mass of the first object = The mass of the planet

m₂ = The mass of the second object = The mass of the satellite

R = The distance between the centers of the two planets = The distance between the center of the planet and the satellite

G = The universal gravitational constant

The force between planet X and the satellite in its orbit = \(FX=G \times \dfrac{M \times m}{(2 \cdot R)^{2}} = G \times \dfrac{M \times m}{4 \cdot R^{2}}\)

The force between planet Y and the satellite in its orbit = \(FY=G \times \dfrac{3\cdot M \times m}{(4 \cdot R)^{2}} = G \times \dfrac{3\cdot M \times m}{16 \cdot R^{2}} = G \times \dfrac{ 3\cdot M \cdot m}{16 \cdot R^{2}}\)

Therefore;

\(\dfrac{FY}{FX} = \dfrac{G \times \dfrac{ 3\cdot M \cdot m}{16 \cdot R^{2}}}{G \times \dfrac{M \times m}{4 \cdot R^{2}}} = \dfrac{3}{16} \times \dfrac{4}{1} = \dfrac{3}{4}\)

\({FY} = \dfrac{3}{4} \times FX\)

Energy bonds for utilities tied to Bakken shale oil are especially risky because of the volatile nature of the oil industry and because their oil is expensive to extract due to its geographic location.

The Bakken shale oil fields in North Dakota and Montana have been a major source of oil production in the United States, but the industry has seen a lot of ups and downs in recent years. This volatility can make it difficult for utilities to accurately predict their revenues and expenses, which can make it difficult to repay the bonds.

Additionally, the Bakken shale oil fields are subject to a number of environmental and regulatory risks, which can also impact the profitability of the utilities. As a result, energy bonds for utilities tied to Bakken shale oil are considered to be especially risky investments.

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Answer:

q = 2.65 10⁻⁶ C

Explanation:

For this exercise we use Coulomb's law

        F =\(k \frac{q_1q_2}{r^2}\)

In this case they indicate that the load is of equal magnitude

       q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

       F = \(k \ \frac{q^2}{r^2}\)

       q = \(\sqrt{\frac{F \ r^2}{k} }\)

we calculate

        q = \(\sqrt{\frac{0.7 \ 0.3^2 }{9 \ 10^9} }\)

        q = \(\sqrt{7 \ 10^{-12} }\)Ra 7 10-12

        q = 2.65 10⁻⁶ C

Answer:

Please find the answer in the explanation

Explanation:

What happens to a digital signal sent using electromagnetic waves as it travels farther from its source?

Solution.

To transmit a signal, the analogue signal is first modulated and converted to digital signals.

The digital signals transmitted through electromagnetic waves like radio wave or microwave can experience attenuation over a long distance as they tend to pass through tissues and wall.

The frequency and the intensity of wave continue to decrease as the wave tend to propagate through the wall and tissues.

To correct this, there must be a device to amplify the signal at the strategic points.

After this, the signal will be demodulated back to the analogue signal.

Therefore, attenuation may occur as the signal tend to pass through the tissues and office walls.

Answer:

The signal becomes weaker and more difficult to detect

Explanation:

got it right on my quiz

Answer:

When we talk about an extended source, we mean a source that is not a point source but has some finite size. Examples of extended sources include the Sun, light bulbs, and other sources that are not point-like. When we observe an extended source from a large distance, it appears to behave as a point source.

The reason for this has to do with the fact that at large distances, the size of the extended source becomes very small in comparison to the distance between the observer and the source. This means that the light rays that reach the observer from different parts of the extended source are almost parallel to each other. As a result, the light from the different parts of the source overlaps and interferes with each other in such a way that the extended source appears to be a single point. This effect is called diffraction, and it is the same effect that causes waves to bend around obstacles and spread out after passing through a narrow opening.

So, in summary, an extended source seems to behave as a point source at large distances because of diffraction, which causes the light from the different parts of the source to overlap and interfere with each other in a way that makes the source appear to be a single point.

The kinetic energy is first at a maximum after approximately 3.67 seconds after t=0.

To determine the time when the kinetic energy is first at a maximum, we need to find the time at which the velocity of the object is at a maximum. The kinetic energy of an object undergoing simple harmonic motion is maximum when the velocity is maximum.

The equation for velocity as a function of time in simple harmonic motion is given by:

v(t) = Aω cos(ωt + φ)

where A is the amplitude, ω is the angular frequency, t is time, and φ is the phase constant.

In this case, the equation for position is x(t) = 2 sin((π/2)t + (π/6)), which is in the form x(t) = A sin(ωt + φ).

Comparing the two equations, we can see that ω = π/2.

The velocity equation becomes:

v(t) = (π/2)A cos((π/2)t + φ)

To find the time at which the velocity is maximum, we need to find when the cosine term is at its maximum value of 1. This occurs when (π/2)t + φ = 0 or (π/2)t + φ = 2π.

Solving for t, we get:

(π/2)t = -φ or (π/2)t = 2π - φ

t = (-2φ/π) or t = (4π - 2φ)/π

Since the phase constant φ in the given equation is π/6, we substitute this value into the equations:

t = (-2(π/6)/π) or t = (4π - 2(π/6))/π

t = -1/3 or t = 11/3

Therefore, the kinetic energy is first at a maximum at t = 11/3 seconds.

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Answer: 2.35 m/s

Explanation:

Given

Dog completes 4 laps around the tree in  32 seconds

Radius of the circular path is 3 m

Time period for single lap is  \(\frac{32}{4}=8\ s\)

Length of the track is equivalent to the perimeter of the path

\(\Rightarrow L=2\pi r\\\Rightarrow L=2\pi \times 3\\\Rightarrow L=6\pi\ m\)

Tangential velocity is given by

\(\Rightarrow v_t=\dfrac{L}{t}\\\\\Rightarrow v_t=\dfrac{6\pi}{8}\\\\\Rightarrow v_t=2.35\ m/s\)

Thus, the tangential velocity is 2.35 m/s

Understanding stream gradient is crucial for predicting how a stream may change over time, responding to floods, and managingc water resoures.

Stream gradient is the drop in elevation of a stream divided by the distance the water resoures. It is the change in elevation of a stream over a certain distance, usually measured in feet per mile or meters per kilometer. A steep stream gradient indicates that the stream is flowing downhill at a rapid pace, while a gentle stream gradient suggests that the stream is flowing slowly and has a flatter slope.

Stream gradient plays an important role in determining the velocity of a stream, the type of erosion it causes, and the habitats it supports. High-gradient streamstend to have more turbulence, faster water flow, and more erosion, while low-gradient streams tend to have more deposition, slower water flow, and more sediment accumulation.

Migration is the term used to describe an organism's movement from one habitat or location to another. Moving from one place to another helps organisms boost their chances of surviving. The movement of organisms from one environment to another may be caused by a lack of resources necessary for their survival.

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The correct definition of stream gradient is: the drop in elevation of a stream divided by the distance the water travels. Stream gradient is an important factor in understanding water flow dynamics.

Stream gradient refers to the drop in elevation of a stream divided by the distance the water travels. This means that stream gradient is a measure of how steeply a stream is inclined, and it is calculated by dividing the change in elevation by the distance traveled. The other terms mentioned, water pressure and stream width, are not directly related to stream gradient but may impact other characteristics of the stream, such as flow rate and erosion.

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Answer:

See the answer below

Explanation:

According to Amonton's law, the pressure of a gas is directly proportional to the temperature of its molecules given that the volume remains constant.

Hence, if the temperature of a tyre increases, heat is transferred to the air molecules within the tyre leading to an increase in the air temperature. The air thus exerts more pressure on the tyre in agreement with Amonton's law.

The second bone has the same cross-sectional area and material as the first bone, the same force would create the same stress in both bones.

To solve this problem, we need to consider the relationship between stress, strain, and Young's modulus. Stress is the force applied divided by the cross-sectional area, strain is the change in length divided by the original length, and Young's modulus is a material property that relates stress and strain.

1. Calculate stress (σ) for the first bone:
σ = Force / Cross-sectional area

2. Calculate strain (ε) for the first bone:
ε = Compression / Original Length
ε = 1.0 mm / Original Length

3. Find Young's modulus (Y) for the bone material:
Y = σ / ε

4. Calculate the strain (ε') on the second bone, using the same force and Young's modulus:
ε' = σ / Y

5. Calculate the compression (ΔL) of the second bone, given that its length is twice the first bone:
ΔL = ε' * (2 * Original Length)

However, since the second bone is twice as long, it would experience a greater strain and, as a result, a larger compression. By calculating the compression of the second bone using the relationship between stress, strain, and Young's modulus, you can determine how much the same force would compress the second bone.

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The spring constant of the spring if it would compress by 1 m to stop the ore car is 340,350.4 N/m.

The potential energy of the car is calculated as follows;

P.E = mgh

where;

sin (10) = h/L

h = L x sin(10)

P.E = mgLsin(10)

P.E = 2000 x 9.8 x 50 x sin(10)

P.E = 170,175.21

The potential energy of the car at the top of the incline will be converted  to the elastic potential energy spring at the bottom of the incline.

P.E = U = ¹/₂kx²

k = (2U)/x²

k = (2 x 170,175.2)/(1)²

k = 340,350.4 N/m

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The potential energy of Nan suitcase of mass 14 kg is 54.88 J.

Potential energy is the energy of a body due to its position in the gravitational field.

To calculate the potential energy, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the potential energy is 54.88 J.

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Answer:

A DC generator is the same as a(n)

C. armature

Answer:

All forms of energy are either kinetic or potential. The energy associated with motion is called kinetic energy . The energy associated with position is called potential energy . Potential energy is not "stored energy".

Explanation:

They happen at subduction zones, where shifting mineral assemblages appear to "implode" as a result of increased pressure on the rock as it is subducted deeper.

The notion that is currently preferred is "Implosion." The building blocks often reorganize to take up less space as subduction zones move rocks deeper where pressure is stronger, moving from, say, a one-on-top-of-another pattern to a fit-in-the-gap-between-those-below pattern. This might sometimes seem to happen gradually before happening abruptly (I can't move till my neighbor does...), resulting in an implosion. Where temperatures and pressures are just so high that we don't imagine rocks can break, the largest, deepest earthquakes occur. Nowhere near as deep as the earthquakes, humans have never dug a hole. Atomic bomb testing has mostly ended. A large earthquake is also much larger than a large atomic weapon.)

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Answer:

A. The particle model, because only high-energy frequencies of light  can remove electrons .

Explanation:

Each photon of blue light has higher energy than each photon of red light has  . So when each photon strikes each electron , it gets ejected . But the photon of red light has not sufficient energy to eject electron . Once the photon of red light strikes the electron , the energy is wasted off . Energy of photon can not be accumulated . Thus photon behaves like particle .

Given:

A ball bouncing eventually comes to stop.

To find:

What kind of a system is this?

Explanation:

An open system is a system where the free exchange of matter and energy with the surroundings takes place.

A closed system is where only the energy of the system is shared with the surrounding. In these kinds of systems, the exchange of matter does not take place.

An isolated system is where neither matter nor energy is exchanged between the system and the surrounding.

When a ball is bouncing, it gradually loses its kinetic energy to the surroundings and eventually comes to stop. But the mass of the ball remains the same. Thus this is a closed system.

Final answer:

The given system is a closed system.

Therefore the correct answer is option B.

The statement that best explains how to correct Savion’s error is, In step 2, change "radiant and thermal" to "chemical and mechanical." The correct answer is a.

The steps listed by Savion are mostly accurate, but step 2 is not quite right. Nuclear energy is actually converted to thermal energy in the form of heat, which is then used to generate steam. The steam is what turns the turbines and generates electricity. Therefore, step 2 should be revised to read "Nuclear energy is converted to thermal energy."

However, changing "radiant and thermal" to "chemical and mechanical" in step 2 is not correct, as these terms do not accurately describe the process of generating electricity in a nuclear power plant. Therefore, the best way to correct Savion's error is to choose option a, which correctly revises step 2 to read "Nuclear energy is converted to thermal energy."

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a) Global averaged surface pressure is generally lower than globally averaged sea level pressure because of the elevation of lands.

b) Density decrease exponentially as we move up the altitude because of  mainly two reason one thining of the atmosphere due to which net mass decreases

c) We all know that as we move up in altitude pressure decrease exponentially due to thinning of the atmosphere

d) water vapor in the atmosphere depends upon the temperature of the air holding it so as we move up the atmosphere temperature keeps on decreasing

a) Due to land elevation, the global average surface pressure is typically lower than the global average sea level pressure. Allow me to explain. We are well aware that the atmosphere becomes thinner as we ascend in height, which causes pressure to fall rapidly. Therefore, there is a lot of high relief on land, such as mountain plateaus and other high-altitude features, which results in relatively little surface pressure and, on average, a pressure that is lower than that at sea level.

b) As we ascend in altitude, density falls off exponentially for two main reasons: first, the atmosphere thins, which causes the net mass to fall and push downward, reducing density; second, gravity likewise falls off as we ascend. In water, this is not a problem because the density of the water is often constant with depth.

c) We all know that the atmosphere thins as we ascend in height, causing pressure to fall rapidly. Why does it suddenly diminish exponentially? The sole reason is that even at low altitudes, the amount of gas in the atmosphere reduces quite quickly. As we increase altitude, density falls off exponentially. Pressure is 0.01 hPa at 80 km. With height, gravity also decreases, which contributes to the problem. Now that the ocean's water density is approximately constant, we know that P = density x gravity x height because the density is constant and declines linearly with height.

d) As we ascend, the temperature of the atmosphere continues to drop, which causes the concentration of water vapor to change because it is heavier near the turbopause and does not mix properly. The same is true for ozone gas, whereas oxygen and carbon dioxide, which are light gases, diffuse properly near the turbopause.

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The position-time graph gives the position of an object at any instant of time. The y-intercept gives the position of the object at the instant when the time is zero. That is, the y-intercept gives the initial position of the object.

Thus the given statement is false.

Answer:

When riding on a plane, passengers not only move through space but they move through time as well.

Explanation:

time is the answer

Explanation:

To determine the height of the building, we can use the formula for the distance traveled by a freely falling object:

d = (1/2) * g * t^2

where:
d is the distance or height of the building,
g is the acceleration due to gravity (approximately 9.8 m/s^2), and
t is the time taken for the object to fall (given as 5.9 seconds).

Plugging in the values, we get:

d = (1/2) * 9.8 m/s^2 * (5.9 s)^2
d = (1/2) * 9.8 m/s^2 * 34.81 s^2
d = 169.089 m

Therefore, the height of the building is approximately 169.089 meters.

Note: It's important to remember that this calculation assumes the object is dropped from rest and neglects air resistance. Additionally, this calculation assumes that the acceleration due to gravity is constant throughout the fall, which is a reasonable approximation near the surface of the Earth.

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An arrangement of atoms with synchronized magnetic fields is referred to as a "Magnetic Domain."

The magnetic field is the area in which a magnet produces its magnetic effects. We use the magnetic field as a tool to describe how the magnetic force is distributed in the vicinity and inside something magnetic in nature.

While opposite poles are drawn to one another, the same poles repel one another. When iron is rubbed against a magnet, the iron's atoms' north-seeking poles align in the same direction. The force generated by the aligned atoms creates a magnetic field.

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The magnetic field due to a long straight wire carrying current varies inversely with the distance (r) from the wire. As the distance from the wire increases, the magnetic field strength decreases. This relationship can be described by the formula B = (μ₀I) / (2πr),

The magnetic field generated by a long straight wire carrying a current varies inversely with the distance r from the wire. The magnetic field around the wire is in the form of concentric circles with the wire acting as the center. The direction of the magnetic field is determined using the right-hand grip rule. The strength of the magnetic field is proportional to the amount of current flowing in the wire.

It also varies with the permeability of the medium through which it passes (the medium in which the wire is positioned).When an electric current passes through a conductor, a magnetic field is generated around the conductor. This magnetic field is always perpendicular to the electric field of the conductor. The magnetic field is in the form of concentric circles around the wire.

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The half-life of 40K is approximately 1.3 billion years. Given a ratio of 40Ar/40K as 3/1 in a granite sample, we can estimate the age of the sample by understanding the decay process.  Based on the given 40Ar/40K ratio, the age of the sample is approximately 650 million years.

Since the half-life of 40K is 1.3 billion years, this means that after each half-life, half of the 40K atoms will have decayed into 40Ar. Therefore, if the ratio of 40Ar/40K is 3/1, it suggests that three-quarters (or 75%) of the original 40K atoms have decayed into 40Ar.

To determine the age, we can calculate the number of half-lives that have occurred based on the remaining 25% of 40K. Since each half-life is 1.3 billion years, dividing the remaining 25% by 50% (half) gives us 0.5. Thus, the sample has undergone 0.5 half-lives.

Multiplying 0.5 by the half-life of 1.3 billion years gives us an estimated age of 0.65 billion years, or 650 million years, for the granite sample.

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(a) The magnitude of the change in momentum of the ball is 6.75 kg·m/s downward.

(b) The magnitude of the change in momentum of the ball is 4.25 kg·m/s toward the pitcher.

(a) To find the change in momentum, we first calculate the initial momentum using p = mv, where m is the mass and v is the velocity. The initial momentum is 0.25 kg × 19 m/s = 4.75 kg·m/s. Since the final velocity is 17 m/s vertically downward, the final momentum is 0.25 kg × (-17 m/s) = -4.25 kg·m/s. The change in momentum is the difference between the initial and final momenta, so it is 4.75 kg·m/s - (-4.25 kg·m/s) = 6.75 kg·m/s downward.

(b) The initial momentum is still 4.75 kg·m/s. Since the final velocity is 17 m/s horizontally back toward the pitcher, the final momentum is 0.25 kg × (-17 m/s) = -4.25 kg·m/s. The change in momentum is 4.75 kg·m/s - (-4.25 kg·m/s) = 9 kg·m/s toward the pitcher. However, we only need the magnitude, so it is 4.25 kg·m/s toward the pitcher.

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We have found that cylinder A will rise by 0.104 inches before the angular velocity of cylinder B is reduced to 5 rad/s. Additionally, we have determined that the tension in the portion of the belt connecting the two cylinders is approximately 1.03 lb, with the direction of the tension opposite to our assumed direction.

To solve this problem, we can use the principle of conservation of energy and apply it to both cylinders.

(a) First, we need to find the initial angular velocity of cylinder B. Since the belt is not slipping, the linear speed of the belt is the same for both cylinders, and we can use the equation v = ωr, where v is the linear speed, ω is the angular velocity, and r is the radius. Thus, for cylinder B, we have:

v = ωr = 30 rad/s × 0.4167 ft/s/rad = 12.5 ft/s

where we have converted the radius from inches to feet.

The kinetic energy of cylinder B can be written as:

\($K_B = \frac{1}{2}I_B \omega^2$\)

where I_B is the moment of inertia of cylinder B about its axis. For a solid cylinder, the moment of inertia is\($I_B = \frac{1}{2}MR^2$\), where M is the mass of the cylinder and R is its radius. Thus, we have:

\($I_B = \frac{1}{2}MR^2 = \frac{1}{2}\left(\frac{14\text{ lb}}{32.2\text{ ft/s}^2}\right)(0.4167\text{ ft})^2 = 0.0087\text{ lb}\cdot\text{ft}^2/\text{s}^2$\)

and

\($K_B = \frac{1}{2}I_B \omega^2 = 0.0087\text{ lb}\cdot\text{ft}^2/\text{s}^2 \times (30\text{ rad/s})^2 = 3.91\text{ ft}\cdot\text{lb}$\)

The potential energy of cylinder A can be written as:

\(U_A = Mgh\)

where h is the height through which cylinder A rises and g is the acceleration due to gravity. At the instant shown in the figure, cylinder A is at its lowest position, so its potential energy is zero. When cylinder B slows down to 5 rad/s, all of the kinetic energy of cylinder B will have been converted to the potential energy of cylinder A. Thus, we have:

\(K_B = U_A = Mgh\)

Substituting the values we have found, we get:

\($3.91\text{ ft}\cdot\text{lb} = (14\text{ lb})(32.2\text{ ft/s}^2)h$\)

Solving for h, we get:

h = 0.0087 ft = 0.104 in.

Thus, cylinder A will rise by 0.104 inches before the angular velocity of cylinder B is reduced to 5 rad/s.

(b) To find the tension in the portion of the belt connecting the two cylinders, we can use the fact that the net torque on each cylinder is zero. The torque due to the weight of each cylinder is given by:

τ = MgRsinθ

where θ is the angle between the weight vector and the radius vector. Since the cylinders are symmetric, the angle θ is the same for both cylinders, and we can write:

\($\tau = (14\text{ lb})(\frac{5}{12}\text{ ft})\sin\theta = (\frac{35}{36})\sin\theta\text{ ft}\cdot\text{lb}$\)

The tension in the belt exerts a torque on each cylinder, and since the cylinders are connected by the belt, the torques due to the tension cancel out. Thus, we have:

\($\tau_A + \tau_B = 0$\)

where \($\tau_A$\) and \($\tau_B$\) are the torques due to the weight of cylinders A and B, respectively. Solving for θ, we get:

\($\sin\theta = -\frac{\tau_B}{\tau_A} = -\frac{1}{2}$\)

Thus, we have:

\($\tau = (\frac{35}{36})\sin\theta\text{ ft}\cdot\text{lb} = -0.429\text{ ft}\cdot\text{lb}$\)

The tension in the belt is equal to the magnitude of the torque divided by the radius of the cylinder A, since the belt is wrapped around it. Thus, we have:

\($T = \frac{\tau}{r} = \frac{-0.429\text{ ft}\cdot\text{lb}}{\frac{5}{12}\text{ ft}} = -1.029\text{ lb}$\)

Since the tension in the belt cannot be negative, the negative sign in the result indicates that the direction of the tension is opposite to our assumed direction. Therefore, the tension in the portion of the belt connecting the two cylinders is approximately 1.03 lb.

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In order to determine which two particles have the same centripetal force, we need to know the angular velocity (ω) and the radius of the circular path for each particle.  formula for centripetal force: F = mω^2r.

If two particles have the same value for F, then they have the same centripetal force. Without knowing the angular velocity and radius of the circular path for each particle, we cannot determine which two particles have the same centripetal force.

The apparent outward force that a rotating mass experiences is known as centrifugal force. Imagine a ball being whirled around on a string or the outward motion you experience when driving around a curve. Since the system is not rotating in an inertial frame, there is no outward acceleration.

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Answer:

True

Explanation:

Modulation waves(schemes) can be analog or digital. An analog modulation scheme has an input wave that varies continuously like a sine wave.

Answer:

C)

Explanation: In freefall motion object always has gravity as its acceleration.