quick!! please help me i dont get it​

Answer: $250

Step-by-step explanation:

100 x 500 = 50,000

50,000 divided by 200= 250

Answer:

x = 70

Step-by-step explanation:

Answer:

Step-by-step explanation:

b/c we know that the inside angles of a triangle add to 180

180 = 38 + x + x + 2

180 = 40 + 2x

140 = 2x

70 = x

Answer:

D

Step-by-step explanation:

It makes sense, the others don't.

The x coordinate is the temperature, and the y coordinate is the number of cups sold.

Hope this helped! :)

Given parameters:

Coordinates of the two points = (-5, 6) and (8,-4)

Unknown:

Distance between the two points.

To find the distance between two points, use the expression below;

  Distance ²  = (x₂ - x₁)² + (y₂ - y₁)²

where;

(-5, 6) and (8,-4)

         x₂ = 8 , x₁ = -5 , y₂ = -4 and y₁ = 6

Input the parameters and solve;

 Distance²  =  (8-(-5))²  +  (-4 - (6))²

                    = 169 + 100

                    = 269

Distance = \(\sqrt269}\)   = 16.4

The distance between the two points is 16.4

Jane should land 1.5 mi down the shoreline and walk the remaining 4.5 mi to the village to minimize her travel time.

Let x = distance travelled along the shore over water.

Then, 6 − x = distance travelled along the shore over land.

Let T = the total time taken to reach the destination.

T = distance/velocity = √(4 + x²)/3 + (6-x)/5 on [0, 6].

Note that T must be non negative and that x = 6 means the destination

is reached solely by rowing and without the benefit of faster land

travel. In actual fact, T is valid over [0, ∞) but [0, 6] is reasonable here.

T' = x/3√(4 + x²) - 1/5 = 5x - 3√(4 + x²) = 0

⇒5x = 3√(4 + x²)

⇒25x² = 9(4 + x²)

⇒16x² = 36

⇒x = ±6/4 = ±1.5

The negative x value is discarded since it does not belong to [0,6].

T(0) = 28/15 = 1.8667

T(1.5) = 1.733

T(6) = 2.1082

Therefore, Jane should land 1.5 mi down the shoreline and walk the

remaining 4.5 mi to the village to minimize her travel time.

Her minimum travel time will be T(1.5) = 1.733 hrs. or 1hr 44 min.

--The given question is incomplete, the correct question is

"Jane is 2 mi, offshore in a boat and wishes to reach a coastal village 6 mi, down a straight shoreline from the point nearest the boat. She can row at 3mph and can walk at 5 mph. Where should she land her boat to reach the village in the least amount of time?"--

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The values of the sets are

Union in set 3

The expression of set 3 is represented as:

{rationals} u {irrationals}

The above means that we determine the union of rational and irrational numbers.

So, we have:

{rationals} u {irrationals} = {rationals or irrationals}

When rational and irrational numbers are combined, the set is the set of real numbers.

So, we have:

{rationals} u {irrationals} = {real numbers}

Hence, {rationals} u {irrationals} = {real numbers}

Union and intersection in set 4

The expression of set 4 is represented as:

((3, 7) n (1, 5)) u [1, 11)

The above means that we determine the union and sets of numbers.

So, we have:

((3, 7) n (1, 5)) u [1, 11)

Evaluate the intersection set

((3, 7) n (1, 5)) u [1, 11) = (4) u [1, 11)

Evaluate the union set

((3, 7) n (1, 5)) u [1, 11) = [1, 11)

Hence, ((3, 7) n (1, 5)) u [1, 11) = [1, 11)

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Answer:

15

Step-by-step explanation:

9/v=27/45 Cross multiply

405=27v Divide by 27 on both sides

15=v

Answer:

THX FOR POINTS

Step-by-step explanation:

Answer:

x = 4\(\sqrt{3}\), y = 8\(\sqrt{3}\)

Step-by-step explanation:

Using the tangent ratio in the right triangle and the exact value

tan30° = \(\frac{\sqrt{3} }{3}\) , then

tan30° = \(\frac{opposite}{adjacent}\) = \(\frac{x}{12}\) = \(\frac{\sqrt{3} }{3}\) ( cross- multiply )

3x = 12\(\sqrt{3}\) ( divide both sides by 3 )

x = 4\(\sqrt{3}\)

------------------------------------------------------------

Using Pythagoras' identity in the right triangle

y² = x² + 12² = (4\(\sqrt{3}\) )² + 144 = 48 + 144 = 192 ( take square root of both sides )

y = \(\sqrt{192}\) = \(\sqrt{64(3)}\) = 8\(\sqrt{3}\)

Answer: L=A/W

Or you can plug in the values for Area and width.

Step-by-step explanation:

If you divide the total area by the width, you get the length

A: 400

L: ?

W: 50

400=50L

400/50=50L/50

8=L

L=400/50

L=8

Hope this helps!

Average speed of Usain Bolt is 10.41 m/s.

The distance travelled by an object in relation to the amount of time it takes to travel that distance can be used to define speed. In plainer terms, it is a gauge of how quickly an object moves.

Average speed = (Total distance travelled)/(Total time required)

SI unit of speed is m/s.

Distance Travelled by Usain Bolt = 100m

Time required to travel this distance =  \(9\frac{3}{5}\) = 48 ⁄ (5 sec)

Average speed = (Total distance travelled)/ (Total time required)

Average speed = 100/ (48/5)

                          = 500/48

                          = 10.41 m/s

Therefore, average speed of Usain Bolt is 10.41 m/s.

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Answer:

A OPTION IS THE INVERSE OF YOUR QUESTION

Answer:

Step-by-step explanation:

The measure of angle c is 70 degrees.

If angle a and angle b are complementary, it means that the sum of their measures is equal to 90 degrees.

Given:

Measure of angle a = 10x + 10

Measure of angle b = 20

We can set up the equation:

(10x + 10) + 20 = 90

Simplifying the equation:

10x + 30 = 90

Subtracting 30 from both sides:

10x = 60

Dividing both sides by 10:

x = 6

Now, we have found the value of x to be 6.

To find the measure of angle c, we can substitute the value of x into the equation for angle a:

Measure of angle a = 10x + 10

Measure of angle a = 10(6) + 10

Measure of angle a = 60 + 10

Measure of angle a = 70

As a result, angle c has a measure of 70 degrees.

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Answer:

the y-intercept is -3

Step-by-step explanation:

x+y=3

-x      -x

y=-x-3

b=-3

Answer: Slope = -2.000/2.000 = -1.000

x-intercept = -3/1 = -3.00000

y-intercept = -3/1 = -3.00000

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x+y-(-3)=0

STEP

1

:

Equation of a Straight Line

1.1 Solve x+y+3 = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line x+y+3 = 0 and calculate its properties

Graph of a Straight Line :

Calculate the Y-Intercept :

Notice that when x = 0 the value of y is -3/1 so this line "cuts" the y axis at y=-3.00000

y-intercept = -3/1 = -3.00000

Calculate the X-Intercept :

When y = 0 the value of x is -3/1 Our line therefore "cuts" the x axis at x=-3.00000

x-intercept = -3/1 = -3.00000

Calculate the Slope :

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is -3.000 and for x=2.000, the value of y is -5.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of -5.000 - (-3.000) = -2.000 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

Slope = -2.000/2.000 = -1.000

Geometric figure: Straight Line

Slope = -2.000/2.000 = -1.000

x-intercept = -3/1 = -3.00000

y-intercept = -3/1 = -3.00000

To solve questions 1 and 2, convert your weight of 130 pounds to 58.5 kilograms by multiplying by 0.45. Convert your height of 5'2" to 1.57 meters by converting feet to inches and then to meters using the provided conversion factor.

For question 1, convert your weight from pounds to kilograms by multiplying it by the conversion factor 0.45 kg/lb. In this case, 130 pounds would be equal to 58.5 kilograms (130 * 0.45).

For question 2, convert your height from feet and inches to meters. First, convert your height in feet to inches by multiplying it by 12 (since 1 foot = 12 inches). Then, add the inches to the total. Next, convert the total inches to meters by multiplying it by the conversion factor 0.0254 m/inch.

In this case, 5 feet and 2 inches would be equal to 1.57 meters ((5 * 12 + 2) * 0.0254).

By converting your weight to kilograms and your height to meters, you can now express your weight and height in metric units.

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Yοu need apprοximately 1017.96 square inches οf wrapping paper tο cοver the tοp, bοttοm, and arοund the cylindrical bοx.

One needs apprοximately 1017.96 square inches οf wrapping paper tο cοver the tοp, bοttοm, and arοund the cylindrical bοx.

The amοunt οf wrapping paper required tο wrap a gift in a cylindrical bοx depends οn the surface area οf the bοx. Tο find the surface area οf a cylinder, we use the fοrmula:

Surface Area = 2πr² + 2πrh

where r is the radius οf the cylinder and h is the height οf the cylinder.

In this case, the given cylinder has a radius οf 9 and a height οf 5. Therefοre, we can substitute these values intο the fοrmula and simplify:

Surface Area = 2 * 3.14 * 9² + 2 * 3.14 * 9 * 5

Surface Area = 1017.96

Therefοre, yοu need apprοximately 1017.96 square inches οf wrapping paper tο cοver the tοp, bοttοm, and arοund the cylindrical bοx.

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Answer:

5 SETS OF 10 WE CAN MAKE, 8 OBJECTS WILL LEFT.

Step-by-step explanation:

Answer:

We can Make 5 sets of 10 and have 8 left over :)

Step-by-step explanation:

we have 58 objects and we make them into sets of 10

1 set=10

1 set  2 set  3 set 4 set 5 set        |       1 one 2 one 3 one 4 one 5 one 6 one 7               ()        ()          ()       ()       ()             |       one 8 one

can i get brainliest

The time interval when the speed is decreasing 0< t<3

Instatenous speed is the speed of a object in motion at any given moment of time.

When the speed starts deceasing the instatenous acceleration dv/dt<0

differentiating the distance with time with second order

dv/dt= d^2x/dt^2

dv/dt= 18t- 54

dv/dt<0

18t-54<0

18t<54

t<3

Therefore the time interval when the speed start deceasing is 0 to 2

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Yes, y = e^xy  is an implicit solution of the differential equation

(1-xy)y'=y^2

Here,

The differential equation (1-xy)y' = y^2

And,  y = e^xy is an implicit solution of the differential equation

(1-xy)y'=y^2.

What is Differential equation?

A differential equation is a mathematical equation that relates some function with its derivatives.

Now,

To show y = e^xy is an implicit solution of the differential equation

(1-xy)y'=y^2, we have to find the solution of differential equation.

The differential equation is;

\((1-xy)y'=y^2\\\\\\\\\)

\((1-xy) \frac{dy}{dx} = y^2\)

\(\frac{dx}{dy} + \frac{x}{y} = \frac{1}{y^{2} }\)

It is form of  \(\frac{dx}{dy} + Px = Qy\),

Where, P is the function of y and Q is the function of x.

Hence, Integrating factor = \(e^{\int\limits {\frac{1}{y} } \, dy} = e^{lny} = y\)

The solution is;

\(x y = \int\limits {\frac{1}{y^{2} }y } \, dy + c\)

\(xy = lny + c\)

Take c = 0, we get;

\(xy = lny\\\\y = e^{xy}\)

Hence, y = e^xy  is an implicit solution of the differential equation

(1-xy)y'=y^2

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The sequence an = ln(3n^2 + 4) − ln(n^2 + 4) converges to ln(3) as n approaches infinity.

To find the limit of the sequence an = ln(3n^2 + 4) − ln(n^2 + 4) as n approaches infinity, we can use algebraic manipulation and properties of limits

an = ln(3n^2 + 4) − ln(n^2 + 4)

= ln[(3n^2 + 4)/(n^2 + 4)]

= ln[3 + 4/n^2]/[1 + 4/n^2]

= ln(3) + ln[1 + (4/n^2)] − ln[1 + (4/n^2)]

= ln(3)

As n approaches infinity, the expression inside the natural logarithm approaches 3, so the limit of the sequence is ln(3):

\(\lim_{n \to \infty} a_n\)  = ln(3)

Therefore, the sequence converges to ln(3).

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The given question is incomplete, the complete question is:

A) Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)

an = ln(3n^2 + 4) − ln(n^2 + 4)

lim n→∞ an = ?

Work Shown:

\(f(x) = -2(0.8)^x\\\\f(0) = -2(0.8)^0\\\\f(0) = -2(1)\\\\f(0) = -2\\\\\)

In the third step, I used the idea that \(x^0 = 1\) where x is any nonzero number.

Answer:

∠ 4 = 130°

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 4 is an exterior angle of the triangle , so

∠ 4 = ∠ 1 + ∠ 2 ( substitute values )

11x + 9 = 6x + 6 + 4x + 14 , that is

11x + 9 = 10x + 20 ( subtract 10x from both sides )

x + 9 = 20 ( subtract 9 from both sides )

x = 11

Then

∠ 4 = 11x + 9 = 11(11) + 9 = 121 + 9 = 130°

your friend may have only calculated ∠ 1

∠ 1 = 6x + 6 = 6(11) + 6 = 66 + 6 = 72°

Answer: =

0.720 is the same as 0.72.

= means equal to.

The answer is =.

The angle θ between them can be determined using the equation:

cos(θ) = (A ⋅ B) / (|A| |B|)

The dot product, also known as the scalar product or inner product, is an operation performed between two vectors to produce a scalar quantity. It is defined as the product of the magnitudes of the vectors and the cosine of the angle between them. Mathematically, the dot product of two vectors A and B is given by:

A ⋅ B = |A| |B| cos(θ)

where |A| and |B| represent the magnitudes of vectors A and B, and θ is the angle between them.

Orthogonal vectors, also known as perpendicular vectors, are two vectors that are at right angles to each other. This means that the dot product of two orthogonal vectors is zero. Geometrically, orthogonal vectors form a 90-degree angle between them.

If two vectors are neither parallel nor orthogonal, the angle between them can be calculated using the dot product. Given two vectors A and B, the angle θ between them can be determined using the equation:

cos(θ) = (A ⋅ B) / (|A| |B|)

Using this equation, you can find the angle between two non-parallel and non-orthogonal vectors.

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Answer:

The right solution is "y(0) = 30 m" and "y'(0) = -6 m/s²".

Step-by-step explanation:

Given,

Velocity,

u = -6 m/s

Height,

h = 30 m

Now,

By using shifting of origin, we get

⇒  \((y-30)=-6t+\frac{1}{2}(-9.8)t^2\)

       \(y-30=-6t-4.9t^2\)

               \(y=30-6t-4.9t^2\)

hence,

The value of y(0) is:

y(0) = \(30-0-0\)

      = \(30 \ m\)

The value of y'(0) is:

y'(t) = \(-6-9.8t\)

y'(0) = \(-6 \ m/s^2\)

The following algebraic expression are trinomial.

The term expression in math is also known as algebraic expression consists of unknown variables, numbers and arithmetic operators.

Here we must know what is meant by trinomial,

The term trinomial is referred as

Here we have given algebraic expression that is written as  x³ + x² - √x is a trinomial with one variable ‘x’ and it having three non-zero terms.

Then the next given algebraic expression which is 2x³ - x², is NOT a trinomial. Because this expression is a binomial with one variable ‘x’, having two non-zero terms.

Then the another given algebraic expression that is 4x³ + x² - 1/x, is a trinomial with one variable ‘x’, having three non-zero terms.

Finally the given algebraic expression which can be written as x⁶ - x +√6, is a trinomial with one variable ‘x’, having three non-zero terms.

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a) The sample space for four flights selected at random, with arrival status "O" for on-time and "L" for late, is given as {OOOO, OOOL, OOLO, OOLL, OLOO,  OLOL, OLLO, OLLL, LOOO, LOOL, LLOO, LLOL, LLLO, LLLL}.

b) The probability that a randomly selected flight is from Airline A and on-time, denoted as P(A), is calculated by multiplying the probability of being on-time for Airline A (75/100) with the proportion of flights operated by Airline A out of the total (320/1000), resulting in P(A) = 24/100.

c) The probability that a randomly selected flight is either from Airline C or on-time, denoted as P(C), is obtained by dividing the sum of flights on-time (700) and flights operated by Airline C (240) by the total number of flights (1000), giving P(C) = 94/100.

d) The probability that a flight is from Airline B given that it is late, denoted as P(B | L), is computed by multiplying the proportion of late flights (300/1000) with the probability of being from Airline B (35/100), resulting in P(B | L) = 77/300.

e) The probability that a flight is late given that it is from Airline A, denoted as P(L | A), is calculated by multiplying the proportion of flights on-time for Airline A (25/100) with the proportion of flights operated by Airline A (320/1000), resulting in P(L and A) = 8/100. Therefore, P(L | A) = 1 - P(A | L) = 11/15.

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The probability of an x that is at least 2 is 0.70.

The probability of an event is a number that indicates how likely the event is to occur. It is expressed as a number in the range from 0 and 1, or, using percentage notation, in the range from 0% to 100%.

P(E) means the probability of an event to occur.

P(E) is that of at least 2 means P(E) is greater than equals to 2, so we will take value greater than and equal to 2 i.e., 2,3,4

P(E) = P (X \(\geq\) 2)

      = P(X=2) + P(X=3) + P(X=4)

      = 0.35 + 0.25 + 0.10

      = 0.70

Therefore, the required probability is 0.70.

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Answer: D) square root 49

Step-by-step explanation: a rational number is a number that eventually ends. Square root 49 is the answer, because it terminates.