a) The given statement "If f'(u) = 0, then f has a local minimum or local maximum at u." is True because, f has a local minimum at that derivative.
b) The given statement "If f'(u) = 0 and f''(u) < 0, then f has a local maximum at u." is True because f''(u) is concave.
c) The given statement "If f'(x) = g'(x) for every x, then f(x) and g(x) differ by a constant." is True because, derivative of constant is 0.
a) If f'(u) = 0, then u is a critical point of f. At a critical point, f can have a local minimum, local maximum, or saddle point. To determine the nature of the critical point, we need to use the second derivative test.
b) This is because the sign of the second derivative indicates the concavity of the function. If f''(u) < 0, then the function is concave down at u, which means that it has a local maximum at u.
c) This is because the derivative of a constant is zero. Therefore, there exists a constant C such that f(x) = g(x) + C for every x. This means that the functions f(x) and g(x) differ only by a constant vertical shift.
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Find the slope of the line | (3) | A) B) C) را با اب D)
a packing lot has a rectangular area of 40,000yd2. the length is 200 yd more than twice the width. find the dimensions of the lot.
the dimensions of the lot is 100 yards by 400 yards. In this problem, a parking lot has a rectangular area of 40,000 square yards, and the length is 200 yards more than twice the width.
Determining the dimensions of a rectangular area, such as a parking lot, can be a useful task for many purposes, such as planning and designing a new lot or estimating the amount of space available for parking.
Let's call the width of the parking lot "w". Then, the length of the parking lot can be represented as 2w + 200.
The total area of the parking lot is 40,000 square yards, so we can set up an equation to solve for w: w * (2w + 200) = 40,000.
Solving for w, we get w = 100. This means that the width of the parking lot is 100 yards and the length is 2 * 100 + 200 = 400 yards.
The dimensions of the parking lot are 100 yards by 400 yards.
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Simplify the expression. In(e-ºe) -72 O In(-1) O e-72 0 -1
Explanation
Step 1
remember some properties of the potentiation
\(\begin{gathered} a^m\cdot a^n=a^{m+n} \\ \end{gathered}\)then
\(e^{-9}\cdot e^8=e^{-9+8}=e^{-1}\)Now we have
\(\ln (e^{-9}e^8)=\ln (e^{-1})\)Step 2
using some properties of ln
\(\begin{gathered} \ln (e^{-1})=-1\cdot\ln (e^{}) \\ and\text{ }\ln (e^{})=1,then \\ \ln (e^{-1})=-1\cdot1 \\ \ln (e^{-1})=-1 \\ \ln (e^{-9}e^8)=-1 \end{gathered}\)I hope this helps you
PLEASE ANSWER CORRECTLY!!! I REALLY NEED AN ANSWER! WILL MARK BRAINLIEST!!!!
Misha solves the following system of equations using the substitution method.
y=5−2x
3x−y=15
What is the single-variable equation she solves after substituting?
A. 3(5+x)=5−2x
B. 15+3x=5−2x
C. 3x−(5−2x)=15
D. 3x−5−2x=15
Answer:
C
Step-by-step explanation:
The single equation of the system of equation y=5−2x and 3x−y=15 by substitution will be 3x−(5−2x)=15 thus option (C) will be correct.
What is the equation?There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.
As per the given system of equations,
y = 5 − 2x
3x − y = 15
Substitute y = 5 - 2x into 3x − y = 15
3x - (5 - 2x) = 15
Hence "The single equation of the system of equation y=5−2x and 3x−y=15 by substitution will be 3x−(5−2x)=15".
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Oscar buys his lunch in the school cafeteria. The cost of 15 school lunches is $33.75.
which graph has a slope that best represents the average cost of the lunches in dollars per
unch?
use 3.14 for and round answers to the nearest tenth the diameter of the circle is 30
3.14 stays the same cuz 1 is in the tenths slot
and i think the answer is right
Step-by-step explanation:
is 0.35 a rational or irrational number
Answer:
I think its rational
Step-by-step explanation:
Answer: 0.35 is rational! :D Hopefully this will help others as well!
Step-by-step explanation:
Does This graph represents a proportional or not proportional relationship
The given graph is a proportional Relationship graph.
What are proportional relationship graph?A proportional relationship graph between two variables is a relationship where the ratio between the two variables is always the same.
Let us formulate a table of values of given graph
Time Distance
5 6
10 12
15 18
Now let us check whether the given values are making equivalent ratios or not by definition of proportional graphs.
5/6 is one
10/12 is 5/6
15/18 is 5/6
Hence the ratios are equivalent. The graph has same slope everywhere and passing through the origin.
Hence the graph is Proportional.
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all of the classifications for the number -8
Answer:
:)
Step-by-step explanation:
-8 is rational, and an integer.
It is a rational number because -8 is an integer or decimal from above, and not equal to 0.
It is a integer because it is a whole number, even if it is a negative!
Assuming that the ring is small enough compared to the depth of the river to be treated as a point and that depth of the Rhine where the ring goes in is 12.3 m , what is the area of the largest circle at the surface of the water over which light from the ring could escape from the water?
The area of the largest circle at the surface of the water over which light from the ring could escape is approximately 474.37 square meters.
To determine the area of the largest circle, we can use the concept of critical angle in optics. When light travels from a medium with a higher refractive index to a medium with a lower refractive index, there is a specific angle called the critical angle at which the light is totally internally reflected and does not escape.
In this case, the ring is assumed to be a point source of light. The critical angle can be calculated using the formula
sin(\(\theta\)) = n2/n1,
where n2 is the refractive index of air (approximately 1) and n1 is the refractive index of water (approximately 1.33).
Using this formula, we find that the critical angle is approximately 48.76 degrees. The circle at the surface of the water with this angle as the central angle will have the maximum area over which light from the ring could escape. The area of this circle can be calculated using the formula \(A = \pi * r^2\), where r is the radius of the circle.
Substituting the radius as the depth of the Rhine (12.3 meters), we find that the area of the largest circle is approximately 474.37 square meters.
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Brainliest if correct
Answer:
C
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
anthony sells two different size jars of peanut butter. The large size sells for 2.60 and the small size sells for 1.80. He has 80 Jars worth 164. How many of each size jar does he have?
Let's solve this problem using a system of equations. Let's denote the number of large jars as "L" and the number of small jars as "S."
According to the given information, we can set up the following equations:
The total number of jars: L + S = 80
The total value of the jars: 2.60L + 1.80S = 164
To solve this system of equations, we can use the substitution method. First, we solve equation 1 for L:
L = 80 - S
Now substitute this expression for L in equation 2:
2.60(80 - S) + 1.80S = 164
208 - 2.60S + 1.80S = 164
-0.80S = 164 - 208
-0.80S = -44
S = (-44) / (-0.80)
S = 55
Substituting this value back into equation 1
L = 80 - 55
L = 25
Therefore, Anthony has 25 large jars and 55 small jars.
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Use polar coordinates to find the volume of the given solid.
Enclosed by the hyperboloid −x2 − y2 + z2 = 6 and the plane z = 3
-x2 - y2 + 9 = 6 >>> x2 + y2= 3 so r2 = 3 >>> squart 0<=r <=3
My question is that why negative square root of 3 is not included in the range???
In polar coordinates, the radial distance "r" is defined as the distance from the origin to a point in the plane. Since distance cannot be negative, we only consider the positive square root of 3 in the range for this problem. So, the correct range for "r" is 0 ≤ r ≤ √3, and negative square root of 3 is not included because it doesn't represent a valid distance in polar coordinates.
To find the volume of the given solid enclosed by the hyperboloid −x2 − y2 + z2 = 6 and the plane z = 3 using polar coordinates, we need to express the equation of the hyperboloid in terms of polar coordinates.
Substituting x = rcosθ and y = rsinθ, we get:
−r2cos2θ − r2sin2θ + z2 = 6
Simplifying, we get:
z2 = 6 - r2
Since the plane z = 3 intersects the hyperboloid, we have:
3 = √(6 - r2)
Solving for r, we get:
r = √3
Hence, the range for r is 0 ≤ r ≤ √3.
In summary, the negative square root of 3 is not included in the range of r because r represents a distance and cannot be negative. The volume of the solid can be found by integrating the function f(r,θ) = √(6 - r2) over the range 0 ≤ r ≤ √3 and 0 ≤ θ ≤ 2π using polar coordinates. The result will be in cubic units and can be obtained by evaluating the integral.
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alan thinks of a number. he squares it, then takes away 1, next multiplies it by 2, takes away 6, divides it by 4 and finally adds 5. his answer is 11. what number did alan start with?
A number first squares it, then takes away 1, next multiplies it by 2, takes away 6, divides it by 4 and finally adds 5. the answer is 11
then the number is 4
According to the question, given that
A number first squares it, then takes away 1, next multiplies it by 2, takes away 6, divides it by 4 and finally adds 5. the answer is 11
Square of 4 = 16
16 - 1 = 15
15 * 2 = 30
30 - 6 = 24
24 ÷ 4 = 6
then add 5
6 + 5 = 11
Therefore, after solve we get 11 and the number is 4.
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A number is first squared, then multiplied by 2, then divided by 4, then added, before having 1 subtracted from it. The solution is 11.
then 4 is the number.
In response to the query, assuming that
A number is first squared, then multiplied by 2, then divided by 4, then added, before having 1 subtracted from it. The solution is 11.
Square of 4 = 16
16 - 1 = 15
15 * 2 = 30
30 - 6 = 24
24 ÷ 4 = 6
then add 5
6 + 5 = 11
Therefore, after solve we get 11 and the number is 4.
What is the surface area of the three-dimensional figure represented by this net?
The net pattern has a square base of side lengths 3 inches, 3 inches, 3 inches and 3 inches are attached with four congruent triangles of height 8 inches.
Use the on-screen keyboard to type the correct number of square inches in the box below.
$$
The surface area of the three-dimensional figure represented by this net is 54 square inches, which is calculated by multiplying the area of the base (9 square inches) by the height of the four congruent triangles (8 inches).
The surface area of the three-dimensional figure represented by this net is 54 square inches. To calculate this, first we need to find the area of the base. The base is a square, with side lengths of 3 inches each. Therefore, the area of the base is 3 x 3 = 9 square inches. Next, we need to find the height of the four congruent triangles. The height is 8 inches. Finally, we can calculate the surface area by multiplying the area of the base (9 square inches) by the height of the four congruent triangles (8 inches). This gives us a total surface area of 54 square inches.
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find evaluate the integral 5x2 squar a2 − x2 dx 0
The evaluated integral is -a^5.
To evaluate the integral of 5x^2 * sqrt(a^2 - x^2) from 0 to a, follow these steps:
1: Write down the integral
∫(5x^2 * sqrt(a^2 - x^2)) dx from 0 to a
2: Perform a substitution
Let u = a^2 - x^2, so -2x dx = du.
When x = 0, u = a^2, and when x = a, u = 0.
3: Rewrite the integral in terms of u
The integral becomes -1/2 ∫(5u * sqrt(u)) du from a^2 to 0
4: Simplify the integral
-1/2 ∫(5u^(3/2)) du from a^2 to 0
5: Integrate the expression with respect to u
-1/2 * (10/5 * u^(5/2)) | from a^2 to 0
Step 6: Apply the limits of integration
(-1/2 * (10/5 * (a^2)^(5/2))) - (-1/2 * (10/5 * (0)^(5/2)))
7: Simplify the expression
(-1/2 * (2 * a^5)) - 0 = -a^5
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14. In the figure (not drawn to scale), MO bisects LMN, mZNMO = (6x + 19), and m
14). Solve for x and find ZLMN.
L
M
A. x= 11, m LMN = 198°
B. x= 11, m ZLMN = 170°
N
C. x=8, m ZLMN = 25°
D. x=8, m ZLMN = 54°
The value of x is 11 and ∠LMN = 190°
What is Linear Equation in One Variable?
A linear equation is a one-variable equation of a straight line. The variable's only power is 1. Linear equations in one variable of the form ax + b = 0 are solved using simple algebraic techniques.
Solution:
Since, MO bisects the angle
we can say that, ∠LMO = ∠OMN
6x + 19 = 9x - 14
3x = 33
x = 11
so, ∠LMO = 66 + 19 = 85°
Therefor the ∠LMN = 190°
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determine whether the following sets are subspaces of r3 under the operations of addition and scalar multiplication defined on r3. justify your answers.
Using Scalar multiplication, If all the conditions are satisfied, then the set is a subspace of R³
Scalar multiplication is what?The result of multiplying a real number by a matrix is known as a scalar multiplication. Each entry of the matrix is multiplied by the specified scalar in scalar multiplication.
The following requirements must be met in order to establish whether a set is a subspace of R3 under addition and scalar multiplication:
Closure under addition: If elements u and v are present, then u plus v must also be present.
If u is a member of the set and k is any scalar, then ku must likewise be a member of the set. Closure under scalar multiplication.
The zero vector is contained in: The set must contain the zero vector (0, 0, 0).
includes all negative vectors; if u is in the set, then -u must also be.
These conditions must be checked for each set, and your response must be supported.
The set is a subspace of R³ if all the conditions are met.
The set is not a subspace of R³ if any of the requirements are not met.
Consequently, the set is a subspace of R³ if all of the conditions are met.
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Complete question -
Plot the image of point C under a reflection across line
When the image of point C is reflected across the line, then it's written as C'.
Joe used a project management software package and has determined the following results for a given project. Expected completion time of the project = 22 days Variance of project Completion time = 2.77. What is the probability of completing the project over 20 days?
a) 0.3849
b) 0.8849
c) 0.1151
d) 0.7642
e) 0.2358
The probability of Joe completing the project over 20 days using the given package is c) 0.1151
To solve this problem, we need to use the normal distribution formula:
Z = (X - μ) / σ
Where:
Z = standard score
X = value we want to find the probability for (in this case, 20 days)
μ = mean or expected completion time (in this case, 22 days)
σ = standard deviation (in this case, the square root of the variance, which is 1.666)
Substituting the values, we get:
Z = (20 - 22) / 1.666
Z = -1.199
Looking up the probability corresponding to a Z score of -1.199 in the normal distribution table, we get 0.1151. Therefore, the probability of completing the project over 20 days is 0.1151 or option c.
To calculate the probability of completing the project over 20 days, we need to find the z-score and then look up the corresponding probability.
First, find the standard deviation:
Standard deviation (σ) = √variance = √2.77 ≈ 1.66
Next, find the z-score:
z = (target completion time - expected completion time) / σ
z = (20 - 22) / 1.66 ≈ -1.20
Now, look up the z-score of -1.20 in a standard normal distribution table. The corresponding probability is 0.1151.
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Find and sketch the domains of the following functions: (a) f(x,y) = √ 5 −2x+√16-y^2 +2
(b) g(x,y) =(e^x^y)/√1+y-x
(c) h(x,y) = √ −x−y /ln(1 − x)
2. Use the Taylor polynomial of degree 5 to approximate 4cos(0.1).
The domains of the given functions are as follows: (a) f(x,y) is defined for all real values of x and y. (b) g(x,y) is defined for all real values of x and y except when y = 1-x. (c) h(x,y) is defined for all real values of x and y such that x < 1 and x ≠ 1. The Taylor polynomial of degree 5 is used to approximate the value of 4cos(0.1).
Let's analyze each function and find their domains:
(a) f(x, y) = √(5 - 2x + √(16 - \(y^2\)))
For the square root to be defined, the expression inside the square root must be non-negative. Hence, we have two conditions:
1. 5 - 2x + √(16 - \(y^2\)) ≥ 0
Solving this inequality, we get: √(16 - \(y^2\)) ≥ 2x - 5
To ensure the square root is defined, we need 16 - y^2 ≥ 0, which means -4 ≤ y ≤ 4.
2. 16 - \(y^2\) ≥ 0
Solving this inequality, we get: -4 ≤ y ≤ 4.
Combining both conditions, we find that the domain of f(x, y) is:
-4 ≤ y ≤ 4 and 2x - 5 ≤ √(16 - \(y^2\))
(b) g(x, y) = \(e^{(x^y) }\)/ √(1 + y - x)
The exponential function is defined for all real numbers, so there are no restrictions on x and y for \(e^{(x^y) }\) to be defined.
For the square root to be defined, the expression inside the square root must be non-negative. Hence, we have the condition:
1 + y - x ≥ 0
Simplifying, we get: y ≥ x - 1.
Therefore, the domain of g(x, y) is all real numbers where y ≥ x - 1.
(c) h(x, y) = √(-x - y) / ln(\((1 - x)^2\))
For the square root to be defined, -x - y must be non-negative, so we have the condition:
-x - y ≥ 0
Simplifying, we get: y ≤ -x.
For the natural logarithm to be defined, the denominator must be greater than 0. Hence, we have the condition:
\((1 - x)^2\) > 0
This condition is always satisfied since\((1 - x)^2\)is always positive, so no additional restrictions on the domain are imposed.
Therefore, the domain of h(x, y) is y ≤ -x.
Now let's move on to the second part of the question:
To approximate 4cos(0.1) using a Taylor polynomial of degree 5, we need to evaluate the polynomial expansion of cos(x) centered at x = 0 up to the fifth degree.
The Taylor polynomial for cos(x) up to degree 5 is given by:
cos(x) ≈ 1 - (\(x^{2}\))/2! + (\(x^4\))/4!
Plugging in x = 0.1 into the polynomial, we have:
cos(0.1) ≈ 1 - (\(0.1^2\))/2! + (\(0.1^4\))/4!
Evaluating the expression, we get:
cos(0.1) ≈ 1 - (0.01)/2 + (0.0001)/24
Simplifying further:
cos(0.1) ≈ 1 - 0.005 + 0.0000041667
cos(0.1) ≈ 0.9950041667
Therefore, using the Taylor polynomial approximation of degree 5, 4cos(0.1) is approximately equal to 3.9800166668.
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The average number of years that an employee must
work for a particular data company before earning a
promotion is Normally distributed, with a mean of 4.2
years and a standard deviation of 0.75 years.
Complete the sentence.
The Z-score for Andre's length of employment until
promotion was 0.77, so his length of employment until
promotion was about _____
years.
A. 3.44
B.3.62
C.4.78
D.4.97
Answer:
C. 4.78
Step-by-step explanation:
Just completed the assignment
Answer:
c
Step-by-step explanation:
trust
A sporting goods store has a sale on soccer balls: if you buy two soccer balls at the regular price, you get a third soccer ball for $1. Coach John bought 24 identical soccer balls during this sale for $136. What is the regular price for one of these soccer balls?
Answer:
The regular price of the balls is $8
Step-by-step explanation:
The sporting goods store sales promotion is as follows;
The price of the third ball after buying two balls at regular price = $1.00
The price of the number of balls Coach John pays for the balls he bought = $136
To buy 24 balls, we have;
2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1
Therefore;
The number of balls bought at regular price = The sum of the 2s = 16 balls
The number of balls bought for $1 = 24 - 16 = 8 balls
Let x represent the regular price of the balls, we have;
16 × x + 8 = 136
16·x = 138 - 8 = 128
x = 128/16 = 8
The regular price of the balls = x = $8.
Ten students each attempted 10 free throws. This list shows how many free throws each student made. What is the median number of free throws made
The median number of free throws made is 5.5.
To find the median, we first need to arrange the number of free throws made in order from lowest to highest:
3, 4, 5, 5, 5, 6, 6, 7, 8, 9
There are 10 numbers in the list, so the median is the average of the fifth and sixth numbers.
(5 + 6) ÷ 2 = 5.5
Therefore, the median number of free throws made is 5.5.
The median is a measure of central tendency that is used to describe the middle value or values of a dataset. It is especially useful when dealing with datasets that have extreme values or outliers, which can skew the mean.
The median is found by ordering the values in the dataset from lowest to highest and then finding the middle value(s). If there are an even number of values, the median is the average of the two middle values.
In this case, there were an even number of values, so we took the average of the fifth and sixth numbers to find the median.
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a person owns three suits, ten ties, and ten shirts. how many ways can they select a traveling wardrobe of two suits, four ties and six shirts?
There are a total of 3 x 10 x 10 = 300 possible combinations of suits, ties, and shirts that a person can select from. However, when selecting a traveling wardrobe, there are only 10 possible suit combinations, 10x10 = 100 possible tie combinations, and 10x10x10 = 1000 possible shirt combinations. This makes a total of 10 x 100 x 1000 = 100,000 possible selections of two suits, four ties and six shirts.
The sheer number of possible combinations indicates how important it is to choose wisely. The two suits should be complementary and appropriate to the occasion; the four ties can be chosen to match the suits, and the six shirts should be selected to mix and match with the ties and suits. Care should be taken to avoid repeating clothing items, and the person should also consider the climate and purpose of the trip in order to select the most suitable wardrobe.
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15 miles in 6 hours
average spedd
The average speed is:
5/3 mph
Work/explanation:
The formula for average speed is:
\(\bf{Average\:Speed=\dfrac{distance}{time} }\)
Plug in the data:
\(\begin{aligned}\bf{Average\:Speed=\dfrac{15}{6}}\\\bf{=\dfrac{5}{3} \:mph}\end{aligned}\)
Hence, the speed is 5/3 mph
What are the coordinates of the point (-4, 2) after a translation 2 units left and 2 units up?
O (-6, 4)
O (-2, 4)
O (-6, 0)
O (-2, 0)
Answer:
(-6,4)
Step-by-step explanation:
(-4,2) (x,y)
translation movements to the left or right (horizontal) affect the X-axis
translation movements upward or downward (vertical) affect the Y-axis
horizontally, we add to the right and subtract to the left
vertically. we add upwards and subtract downwards
-4-2=-6
2+2=4
✓(-6,4)
Help!
Crater Lake in Oregon in shaped like a circle with a diameter of about 5.5 miles. What is the area of the surface of crater lake?
Answer: 23.74625 miles
HELPPPPPP!!!
Select all the correct locations on the table. Select all the expressions with accurately written descriptions.
Answer:
Step-by-step explanation:
Expressions with the correct statements will be as below.
1). (y + 2)²→ The square of the sum of 2 and y
Correct
2). 7(6x² + 5x + 4) → The product of 7 and the sum of 6 time the square of y and 5 times x plus 4
Incorrect
3). 7y² - 3 → The difference of 7 times the square of y and 3
Correct
4). 5x² → Product of 5 and the square of x.
Incorrect
5). y² + 11y + 24 → The sum of y squared and 11 times y plus 24
Correct
6). 5(x² - 6) → 5 times the difference of the square of x and 6
Correct
When exposed to water, sodium catches on firo. Chamural Nhange: 14. My car traveled 6.05 miles in 5.75 minutes. If I continue driving at the same pace, how long will it take to drive 246 miles? (3 points) D= Answer: 15. A gold nugget has a mass of 21.75 g. Pure gold has a density of 19.32 g/mL. What is the volume of the gold nugget? (2 points) Answer: 16. There are 993.0 miles between Philadelphia and Orlando. How many kilometers separate these cities? Note that 1mi=1.609 km
15. If your car traveled 6.05 miles in 5.75 minutes and you continue driving at the same pace, it will take approximately 262.17 minutes to drive 246 miles.
16. The volume of the gold nugget with a mass of 21.75 g and a density of 19.32 g/mL is approximately 1.125 mL.
15. Using the given information, we can set up a proportion to find the time it will take to drive 246 miles. The proportion can be set up as: (6.05 miles / 5.75 minutes) = (246 miles / x minutes), where x represents the unknown time. Cross-multiplying and solving for x, we find that x ≈ 262.17 minutes. Therefore, it will take approximately 262.17 minutes to drive 246 miles at the same pace.
16. To calculate the volume of the gold nugget, we can use the formula: volume = mass / density. Plugging in the given values, we get: volume = 21.75 g / 19.32 g/mL. Performing the division, we find that the volume is approximately 1.125 mL. Therefore, the volume of the gold nugget is approximately 1.125 mL.
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