Question 20
A graduated cylinder contains 100 mL of a liquid. The mass of the
graduated cylinder with the liquid is 145 grams. The mass of the
graduated cylinder when empty is 45 grams. The liquid is most likely
O Chloroform (Density = 1.492 g/mL)
Water (Density = 1 g/mL)
O Corn oil Density = 0.925 g/mL)
O Ethanol (Density = 0.789 g/mL)

The volume occupied by 1.657 moles of oxygen at STP is 37.12 L.

What is STP?

STP stands for Standard Temperature and Pressure at which a system is said to have a temperature of 0 degree Celsius and 1 atmospheric pressure. At STP, any gas is said to occupy a volume of 22.4L per mole of the gas taken.

The volume occupied by 1 mole of O2 at STP is 22.4L. So, the volume occupied by 1.657 moles of O2 at STP can be calculated as,

1.657 mol x 22.4L / mol = 37.12 L.

Therefore, the volume occupied by 1.657 moles of O2 at STP is 37.12L.

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The correct definition of vapor is: "B. A substance that is in the gas phase at a temperature at which it would normally be a solid or liquid."

A vapor is a substance that exists as a gas at a temperature that is typically associated with solids or liquids.

Unlike gases, which can exist at a wide range of temperatures, vapors specifically refer to substances that have transitioned into the gas phase despite their expected solid or liquid state under normal conditions.

This transition usually occurs due to increased temperature, causing the substance to evaporate or sublimate.

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Answer:

i think its letter d

Answer:

Mass of 6.25 moles of copper(II) nitrate = 1025 grams

Explanation:

Let us calculate the molar mass of Copper (II) nitrate

Molecular formula = Ca(NO₃)₂

Atomic mass of Ca = 40 g/mol

Atomic mass of N =14 g/mol

Atomic mass of O = 16 g/mol

molar mass of Ca(NO₃)₂ = 40 + (14 X2) +( 6X16) = 164 g/mol

moles=\frac{mass}{molarmass}moles=

molarmass

mass

therefore

mass = moles X molar mass

mass = 6.25 X 164 = 1025 grams

C. It can help us track how quickly element of the climate are changing

Answer:

Dont completly trust me here but i think its a but id try and wait for someone else just be careful

Explanation:

The reaction rate is the amount of a substance that is being reacted (or produced) over a certain period of time.

Substance is a term used to refer to a material or a substance that has mass and occupies space. It can also refer to a type of material that has unique properties and characteristics. It includes both tangible and intangible things such as liquids, solids, gases, and energy. It is a fundamental concept in chemistry and physics and is used to describe the physical properties of matter. For example, water is a substance composed of two hydrogen atoms and one oxygen atom. It has a distinct chemical formula and can be classified as a liquid at room temperature. Substance is also used in a more philosophical sense to refer to the underlying principles that compose a thing or idea.

Therefore, the reaction rate cannot be determined from the information provided.

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Answer and Explanation:

We can use the ideal gas law to solve this problem:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

First, we need to calculate the initial volume of the gasoline sample. We can assume that the volume of the cylinder remains constant during the compression process, so the initial and final volumes are the same.

We can rearrange the ideal gas law to solve for the number of moles of gas:

n = PV/RT

For the initial state:

n = (42.35 atm) V / (R * 22.74 K)

For the final state:

n = (3.52 atm) V / (R * T2)

where T2 is the final temperature.

Since the number of moles of gas is the same in both states (assuming no gas leaks or additions), we can equate the two expressions for n:

(42.35 atm) V / (R * 22.74 K) = (3.52 atm) V / (R * T2)

We can solve for T2:

T2 = (3.52 atm * 22.74 K) / 42.35 atm = 1.86 K

Therefore, the temperature of the compressed fuel-air mixture is 1.86 Kelvin. Note that this result is unphysical, as it implies that the gasoline has been cooled to an extremely low temperature during the compression process.

Orbitals

Explanation:

Electrons are found in different levels  or orbitals  surrounding the nucleus. The electrons can be found at any point in their orbital.

Hope this helped!!!

Answer:

shells or orbitalsthat

Explanation:

Answer:

heat changes energy is by the sun

the sun gives off energy

Answer:

Explanation:

The pH of 0.02 M hydrochloric acid is approximately 1.7.

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Answer:

lungs

Explanation:

Answer:

c

Explanation:

Answer:

Explanation:Density is a physical property of a substance that represents the… ... Use the mass and volume data to calculate the density of an unknown metal to the nearest hundredth. Mass of unknown metal = 222.50 g Volume of unknown metal = 25.00 What is the density of the unknown metal? 2.

Answer:

C

Explanation:

8.90 g/cm3

Answer:

C.

Explanation:

Answer:

C

Explanation:

Answer:

To regulate a pressure chamber in a lab to STP (Standard Temperature and Pressure), the conditions inside the chamber need to be set to a temperature of 0 degrees Celsius (273.15 K) and a pressure of 1 atmosphere (101.325 kPa or 1013.25 hPa).

Let's assume that the three gases introduced into the pressure chamber are carbon dioxide (CO₂), nitrogen (N₂), and oxygen (O₂), and their initial quantities are as follows:

CO₂: 0.39 moles

N₂: 0.25 moles

O₂: 0.36 moles

To regulate the pressure chamber to STP, we need to calculate the total pressure of the gases inside the chamber and adjust it to 1 atmosphere if needed.

First, we need to calculate the total number of moles of gas in the chamber by summing up the moles of each gas:

Total moles of gas = moles of CO₂ + moles of N₂ + moles of O₂

Total moles of gas = 0.39 moles + 0.25 moles + 0.36 moles

Total moles of gas = 1.0 moles

Next, we can calculate the partial pressure of each gas using Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is equal to the sum of the partial pressures of each gas:

Partial pressure of CO₂ = moles of CO₂ / total moles of gas * total pressure

Partial pressure of CO₂ = 0.39 moles / 1.0 moles * 1 atmosphere

Partial pressure of CO₂ = 0.39 atm

Partial pressure of N₂ = moles of N₂ / total moles of gas * total pressure

Partial pressure of N₂ = 0.25 moles / 1.0 moles * 1 atmosphere

Partial pressure of N₂ = 0.25 atm

Partial pressure of O₂ = moles of O₂ / total moles of gas * total pressure

Partial pressure of O₂ = 0.36 moles / 1.0 moles * 1 atmosphere

Partial pressure of O₂ = 0.36 atm

Now, we can check if the total pressure of the gases in the chamber is already at 1 atmosphere or if it needs to be adjusted.

Total pressure of gases = sum of partial pressures of each gas

Total pressure of gases = 0.39 atm + 0.25 atm + 0.36 atm

Total pressure of gases = 1.0 atm

Since the total pressure of the gases in the chamber is already 1 atmosphere, no adjustment is needed. The pressure chamber is already regulated to STP.

Explanation:

Answer:

Are held together by strong electrostatic forces of attraction between oppositely charged ions. These compounds have high melting points and high boiling points because of the large amounts of energy needed to break the many strong bonds.

Explanation:

:)

Answer:

z=16 and five p orbitals are filled and three s orbitals are filled

Answer:

the original substances in any chemical reaction. products. the resulting substances in any....chromium(III) oxide, and water. (NH4)2Cr2O7(s) → N2(g) + Cr2O3(s) + 4H2O(g).

To convert grams to atoms:

1) First, you transform grams into moles using the atomic mass of the element.

2) Transform moles into atoms using the avogrado's constant

So:

1) The atomic mass of potassium is 39.1 amu (look for it on the periodic table). This means that 1 mole of potassium has 39.1 g of potassium.

You have 1.78 grams of potassium.

1 mole of potassium ---- 39.1 g of potassium

x mol of potassium ---- 1.78 g of potassium

39.1x = 1.78

x = 1.78/39.1

x = 0.0455 moles of potassium

2) Avogrado's constant is 6.022 × 10²³ atoms = 1 mol

6.022 × 10²³ atoms ----- 1 mol

x atoms ---- 0.0455 mol

x = 2.7415 × 10²² atoms of potassium

Answer: 2.7415 × 10²² atoms of potassium

Option D, W3+ (g) → W4+ (g) + e-, requires the most energy for the ionization process.

The ionization interaction that requires the most energy is choice D, where W3+ (g) is ionized to W4+ (g) by the deficiency of one electron. This is on the grounds that the energy expected to eliminate an electron from a particle increments as the particle turns out to be all the more decidedly charged. Hence, it takes more energy to eliminate an electron from W3+ (g) than it does from W+(g), W2+ (g), or W3+ (g).

Choice An includes the expulsion of one electron from an impartial tungsten iota, and choice B includes eliminating an electron from W+. Choice C includes eliminating an electron from W2+. These ionization processes require less energy than choice D in light of the fact that the ionization energy increments as the particle turns out to be all the more emphatically charged. Hence, the ionization energy expected to eliminate an electron from W3+ is more prominent than that expected to eliminate an electron from any of the past particles.

Subsequently, choice D, W3+ (g) → W4+ (g) + e-, requires the most energy for the ionization interaction.

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The first step in describing and analyzing most phenomena in physics involves the careful drawing of a free-body diagram. Free-body diagrams have been used in examples throughout this chapter. Remember that a free-body diagram must only include the external forces acting on the body of interest. Once we have drawn an accurate free-body diagram, we can apply Newton’s first law if the body is in equilibrium (balanced forces; that is.

5. The mass (in grams) of FeCl₂ that can be produced from 5.23×10²² formula units of Fe₃(PO₄)₂ is 33.05 g

First, we shall obtain the mass of 5.23×10²² formula units of Fe₃(PO₄)₂. Details below:

From Avogadro's hypothesis,

6.022×10²³ formula units = 1 mole of Fe₃(PO₄)₂

But,

1 mole of Fe₃(PO₄)₂ = 357.55 g

Thus,

6.022×10²³ formula units = 357.55 g of Fe₃(PO₄)₂

Therefore,

5.23×10²² formula units = (5.23×10²² × 357.55) / 6.022×10²³

5.23×10²² formula units = 31.05 of of Fe₃(PO₄)₂

Finally, we shall obtain the mass of FeCl₂ produced. Details below:

Fe₃(PO₄)₂ + 6HCl -> 2H₃PO₄ + 3FeCl₂

From the balanced equation above,

357.55 g of Fe₃(PO₄)₂ reacted to produce 380.55 g of FeCl₂

Therefore,

31.05 g of Fe₃(PO₄)₂ will react to produce = (31.05 × 380.55) / 357.55 = 33.05 g of FeCl₂

Thus, the mass of FeCl₂ produced is 33.05 g

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Answer:

Explanation:

To find the concentration of a solution, we need to divide the number of moles of solute by the volume of the solution in liters.

In this case, we have 0.50 mol of NaCl dissolved in 0.30 L of solution. Therefore, the concentration of the solution can be calculated as:

Concentration = moles of solute / volume of solution

Concentration = 0.50 mol / 0.30 L

Concentration = 1.67 mol/L

Therefore, the concentration of the solution is 1.67 mol/L.

Answer:

resultant

Explanation:

Answer:

See explanation below

Explanation:

To get a better understanding watch the picture attached.

In the case of the reaction with Bromine, the -N(CH₃)₂ is a strong ring activator, therefore, it promotes a electrophilic aromatic sustitution, so, in the mechanism of reaction, the lone pair of the Nitrogen, will move to the ring by resonance and activate the ortho and para positions. That's why the bromine wil go to the ortho and para positions, mostly the para position, because the -N(CH₃)₂ cause a steric hindrance in the ortho position.

In the case of the reaction with HNO₃/H₂SO₄, the acid transform the -N(CH₃)₂ in a protonated form, the anilinium ion, which is a deactivating of the ring, and also a strong electron withdrawing, so, the electrophile will go to the meta position instead.

Hope this helps.

Increasing the amount of oxygen in the reaction would result in an increased yield of barium sulfate, as long as there is an adequate supply of barium sulfide.

In the given chemical equation, the reaction between barium sulfide (BaS) and oxygen gas (O2) produces barium sulfate (BaSO4).

When the amount of oxygen is increased in the reaction, it would favor the production of more barium sulfate. This is because oxygen acts as a reactant in the formation of barium sulfate. By increasing the concentration or availability of oxygen, more oxygen molecules will be available to react with the barium sulfide. The increase in oxygen will provide more oxygen atoms for the formation of sulfate ions (SO4^2-) from the sulfide ions (S^2-) in barium sulfide. Consequently, more barium sulfate will be produced in the reaction. Therefore, increasing the amount of oxygen in the reaction would result in an increased yield of barium sulfate, as long as there is an adequate supply of barium sulfide.

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When the equilibrium constant is higher than one, it indicates that the reaction prefers to produce products, whereas if the equilibrium constant is less than one, it indicates that the reaction prefers to produce reactants. If the equilibrium constant is equal to one, the reaction proceeds in both directions equally.

In a chemical reaction, exothermic reactions are defined as reactions that release heat into their environment. It implies that heat is given off when reactants are converted to products. At equilibrium, an exothermic reaction continues to be exothermic, meaning that heat is given off even after the reaction reaches a state of equilibrium.There are two types of reactions: exothermic and endothermic.

A reaction is classified as exothermic if it releases heat, and endothermic if it absorbs heat. The direction of the reaction is determined by whether it is exothermic or endothermic. At equilibrium, the reaction is no longer moving forwards or backwards. It's also worth noting that reactions can be exothermic in one direction and endothermic in the other.

The equilibrium constant (K) is defined as the ratio of the concentration of products to the concentration of reactants in the chemical reaction equation. It is used to express how much of the products is generated by the reaction in comparison to the reactants.  the equilibrium constant aids in the identification of the direction in which the reaction will proceed at equilibrium.

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