The mean of the given grouped data is 68.3.
To calculate the mean, we need to find the midpoint of each interval and multiply it by its corresponding frequency. Then, we sum up the products and divide by the total number of observations.
The midpoint of each interval can be calculated by taking the average of the lower and upper bounds. For example, for the interval [50-58), the midpoint is (50 + 58) / 2 = 54.
Next, we multiply each midpoint by its corresponding frequency and sum up the products. For the given data:
(54 * 3) + (62 * 7) + (70 * 12) + (78 * 0) + (86 * 2) + (94 * 6) = 162 + 434 + 840 + 0 + 172 + 564 = 2172.
Finally, we divide the sum by the total number of observations, which is the sum of all the frequencies: 3 + 7 + 12 + 0 + 2 + 6 = 30.
Mean = 2172 / 30 = 72.4.
Therefore, the mean of the given grouped data is approximately 72.4.
2.2 The first quartile cannot be determined with the given grouped data.
The first quartile, denoted as Q1, represents the value below which 25% of the data falls. In order to calculate the first quartile, we need to know the individual data points within each interval. However, the grouped data only provides information about the frequency within each interval, not the individual data points.
Without the specific data points, we cannot determine the position of the first quartile within the intervals. Therefore, it is not possible to calculate the first quartile using the given grouped data.
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At 2:00 p.m. a car is traveling at 22 mph. Four minutes later the car is traveling at 32 mph. Was the car ever moving at 30 mph over this interval? Why or why not?
Select one:
a. The question cannot be answered since there is no way of knowing how the car moved over the 4-minute interval.
b. No, the car was not ever moving at 30 mph since there is no way to determine when the car would move at that speed.
c. No, the car was not ever moving at 30 mph since the car only moved at 22 mph and 32 mph.
d. Yes the car was moving at 30 mph at least once over the interval. The reason is that the car had to accelerate through 30 mph to reach 32 mph.
d. During the interval, the car did, in fact, go at least once at 30 mph. The vehicle had to speed through 30 mph in order to reach 32 mph.
The speed and direction of an object's stir are measured by its haste. In kinematics, the area of classical mechanics that deals with the stir of bodies, haste is a abecedarian idea.
A physical vector volume called haste must have both a magnitude and a direction in order to be defined. Speed is the scalar absolute value( magnitude) of haste; it's a coherent deduced unit whose volume is measured in metres per second( m/ s or m/ s1) in the SI( metric system).
For case," 5 metres per second" is a scalar while" 5 metres per alternate east" is a vector. An object is considered to be witnessing acceleration if there's a change in speed, direction, or both.
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Find the equation of the line.
GIVING BRAINIEST TO WHOEVER HELPS ME AND GETS IT RIGHT!!!
Answer:
y= -3x + 7
Step-by-step explanation:
y intercept= 7
slope= -3
Answer:
\(gradient = \frac{7 - 1}{0 - 2} \\ = - 3 \\ y = mx + c \\ at \: (1, \: 2) \\ 2 = ( - 3 \times 1) + c \\ c = 5 \\ substitute \: in \: y = mx + c \\ y = - 3x + 5\)
Which of the following are properties of the normal curve?Select all that apply.A. The high point is located at the value of the mean.B. The graph of a normal curve is skewed right.C. The area under the normal curve to the right of the mean is 1.D. The high point is located at the value of the standard deviation.E. The area under the normal curve to the right of the mean is 0.5.F. The graph of a normal curve is symmetric.
The correct properties of the normal curve are:
A. The high point is located at the value of the mean.
C. The area under the normal curve to the right of the mean is 1.
F. The graph of a normal curve is symmetric.
Which of the following are properties of the normal curve?Analyzing each of the options we can see that:
The normal curve is symmetric, with the highest point (peak) located exactly at the mean.
It has a bell-shaped appearance.
The area under the entire normal curve is equal to 1, representing the total probability. The area under the normal curve to the right of the mean is 0.5, or 50% of the total area, as the curve is symmetric.
The normal curve is not skewed right; it maintains its symmetric shape. The value of the standard deviation does not determine the location of the high point of the curve.
Then the correct options are A, C, and F.
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The following are properties of the normal curve: A. The high point is located at the value of the mean, C. The total area under the normal curve is 1 (not just to the right), and F. The graph of a normal curve is symmetric.
Explanation:Based on the options provided, the following statements are properties of the normal curve:
A. The high point is located at the value of the mean: In a normal distribution, the high point, which is also the mode, is located at the mean (μ). C. The area under the normal curve to the right of the mean is 1: Possibility of this statement being true is incorrect. The total area under the normal curve, which signifies the total probability, is 1. However, the area to the right or left of the mean equals 0.5 each, achieving the total value of 1. F. The graph of a normal curve is symmetric: Normal distribution graphs are symmetric around the mean. If you draw a line through the mean, the two halves would be mirror images of each other.
Other options do not correctly describe the properties of a normal curve. For instance, normal curves are not skewed right, the high point does not correspond to the standard deviation, and the area under the curve to the right of the mean is not 0.5.
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Find The Remainder Term Rn In The Nth Order Taylor Polynomial Centered At A For The Given Function. Express The Result
find the remainder term Rn for the nth order Taylor polynomial centered at a for a given function. The remainder term is given by:
Rn(x) = f(n+1)(c) / (n+1)! * (x-a)^(n+1)
where c is some value between x and a.
This formula tells us that the error between the actual value of the function and the nth order approximation is proportional to the (n+1)th derivative of the function evaluated at some point c between x and a, multiplied by (x-a)^(n+1) divided by (n+1)!.
In other words, the higher the (n+1)th derivative of the function is, the larger the remainder term will be. Additionally, the further away x is from a, the larger the remainder term will be.
It's worth noting that this formula assumes that the function is well-behaved and has enough continuous derivatives in the interval [a, x]. If the function is not well-behaved, or if it doesn't have enough continuous derivatives, then the Taylor series may not converge or may converge to something other than the original function.
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In need of help it’s due in an hour!! I’ll give brainliest to the best answer
Please and thx
20.
\( \sqrt{ {(0 - 4)}^{2} + {(4 - 7)}^{2} } = 5\)
closest square root of 59.4
Answer:
8
Step-by-step explanation:
Answer:
the Square root is 7.7 which is rounded up to 8.
Step-by-step explanation:
Work out the size of angle x.
Answer:
13 degrees.
Step-by-step explanation:
First we calculate the other 2 angles of the triangle of which < x is a part.
The bottom angle = 85 (vertical angles are equal).
The top one = 180 - 98 = 82. ( corresponding and adjacent angles).
So angle x = 180 - (85 + 82).
= 180 - 167
= 13 degrees.
A dangling modifier
defines a noun or verb somewhere in a sentence
does not clearly describe a word or phrase in a sentence
enhances a target word or phrase in a sentence
is a phrase loosely attached to the end of a sentence
Answer:
does not clearly describe a word or phrase in a sentence
Step-by-step explanation:
Not sure that this is math but...
Answer:
The answer is B
Step-by-step explanation:
B) does not clearly describe a word or phrase in a sentence
Which of the following functions has an initial value of 3/2 and a rate of change of -2/3?
A. y=2/3x+3/2
B. y=−3/2x−2/3
C. y=3/2x−2/3
D. y=−2/3x+3/2
Answer:
The right answer is Option D: \(y = -\frac{2}{3}x+\frac{3}{2}\)
Step-by-step explanation:
Given that initial value of 3/2 and rate of change is -2/3
The given functions can be observed and it can be concluded that the functions are in the form
\(y = mx+c\)
Here m is the slope which is also called rate of change and c is the y-intercept.
The y-intercept is the initial value when input is zero.
So we have to look for a function that has 3/2 in place of c and -2/3 in place of m.
From the given options,
\(y = -\frac{2}{3}x+\frac{3}{2}\) is the matching function
Hence,
The right answer is Option D: \(y = -\frac{2}{3}x+\frac{3}{2}\)
Which of the following is not a method for proving triangles congruent? Select one: O a. SSA O b. SSS O c. AAS O d. SAS O e. ASA
Answer:
The answer is A
Step-by-step explanation:
The answer is A, how I learned this was making sure that any combination of a and s would not spell out a bad word! With this in mind, we know that AS$ and SSA are not valid methods for proving triangles congruent!
Hope this helps!
(I had to use a $ symbol because there was an inappropriate word)
Jori has 2 gallons of distilled water and uses 7/6 gallon in a science experiment. What fraction of a gallon does she have left?
Answer:
Step-by-step explanation:
6/6 = 1 gallon
12/6 = 2 gallons
12/6 - 7/6 = 5/6
5/6 should be the answer
Help give u 10 point urgent
Answer:
60.6 cm
Step-by-step explanation:
The perimeter P is the sum of the 4 sides, that is
P = 14.8 + 12.5 + 16.3 + 17 = 60.6 cm
Find the indicated segment.
(3x + 4) (x + 12)
Answer:
Step-by-step explanation:
i'm kinda bad at math but i think it's 9=9 or x+26. i'm not sure.try x+26 you can see if i'm incorrect or correct. i only gave you the 2 answer's i'm sure of well god bless :DIf you were going to place a streetlight so it was equidistant from three sidewalks, would you use the incenter or circumcenter to find the best location?
We can use the incenter to find the best location, because the point that is equidistant to all sides of a triangle is called the incenter.
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Now, We know that;
The incenter is equidistant from the sides of the triangle and the point that is equidistant to all sides of a triangle.
Hence, We can use the incenter to find the best location, to place a streetlight so it was equidistant from three sidewalks.
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Solve for the missing part of the proportion. 1327 = ?324
Answer:
156
Step-by-step explanation:
1. cross multiply
2. Divide both sides
i hope i helped
No one is answering my questions I’m feeling so bad and tomorrow is my exam also pls help someone pls :((giving brainliest to the one who answers )pls help
Answer:
a) 180° - (55°+65°) = 180 - 120 = 60
again bc x and C both give 180° as a lying angle.
c= 60°.
x= 180 - 60 = 120°
x=120°
Step-by-step explanation:
b is the same.
Plz help it is over due
Answer:
32/9
Step-by-step explanation:
(4/1) (9/8)=
32/9
Write the domain of the following graph.
Answer:
See below ( MIGHT choose (-2,+2) but it is incorrect)
Step-by-step explanation:
DOMAIN is the values of 'x' a function can have
NONE of the answers are correct
it should be (-3,+3) <=====not an option
Please help falling behind and grade is low!!!
Find the missing values in the table below so that it represents a linear function. Enter
Y2, 93, and y4 in order, in the boxes below.
(Picture bow)
The slope of a linear function is always the same thus the missing values are y₂ = 5 , y₃ = 8, and y₄ = 12.
What is a linear function?A straight line on the coordinate plane is represented by a linear function.
A linear function always has the same and constant slope.
In another word, a linear function is a function that varies linearly with respect to the changing variable.
As per the given table,
Take (2,3) and (6,19)
Slope = (19 - 3)/(6 - 2) = 4
To maintain the same slope,
(y₂ - 3)/(3 - 2) = 4
y₂ = 5
(y₃ - 4)/(4 - 3) = 4
y₃ = 8
(y₄ - 8)/(5 - 4) = 4
y₄ = 12
Hence "The slope of a linear function is always the same thus the missing values are y₂ = 5, y₃ = 8, and y₄ = 12".
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The interquartile range is used as a measure of variability to overcome what difficulty of the range?Choose one answer.a. the range is influenced too much by extreme valuesb. the sum of the range variances is zeroc. the range is difficult to computed. the range is negative
The interquartile range is a useful tool for measuring variability in a set of data because it overcomes the difficulty of the range being influenced too much by extreme values
The interquartile range is a measure of variability that is commonly used in statistics to describe the spread of a set of data. It is particularly useful because it overcomes the difficulty of the range being influenced too much by extreme values.
In mathematical terms, the interquartile range is defined as the difference between the upper quartile (Q3) and the lower quartile (Q1).
The upper quartile represents the 75th percentile of the data and the lower quartile represents the 25th percentile of the data.
This means that 25% of the data falls below the lower quartile and 75% of the data falls above the upper quartile.
The interquartile range provides a better representation of the spread of the data because it eliminates the influence of extreme values.
These values, also known as outliers, can have a significant impact on the range and can make it appear as though the data is more spread out than it actually is.
By using the interquartile range, the outliers are excluded and a more accurate representation of the spread of the data is obtained.
Therefore, option (a) is correct.
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Two numbers each with two decimd
places round to 312 to one decima
place. The total of the numbers is
62.4, What could the numbers be?
You need to be clear on their understands
of rounding and what it means when f
Says two numbers each with two
decimal places, for example, they may
choose 3121+ 3419 both of which
round
to 31.2 when rounded to
I decimal place.
Fows on knowing that when rounding.
it is
Can they find all of these using
Systematic approach.
It is not possible to find two numbers with two decimal places that round to 312 when rounded to one decimal place and have a total of 62.4.
To solve this problem systematically, we can break it down into smaller steps:
Let's assume the two numbers are x and y, both with two decimal places.
We can represent them as x = a.b and y = c.d, where a, b, c, and d are digits.
Rounding x and y to one decimal place gives us the following equations:
Round(x) = a.b ≈ 312
Round(y) = c.d ≈ 312
Since the total of the numbers is 62.4, we have the equation:
x + y = a.b + c.d
= 62.4
From Step 2, we know that both a.b and c.d are approximately equal to 312.
So, we can write:
a.b ≈ 312
c.d ≈ 312
Since a.b and c.d are rounded to one decimal place, we can rewrite them as:
a.b = 312 + p
c.d = 312 + q
p and q are the decimal parts that were rounded.
Substituting the new representations of a.b and c.d into the equation from Step 3, we get:
(312 + p) + (312 + q) = 62.4
Simplifying the equation gives us:
624 + (p + q) = 62.4
Solving for (p + q), we have:
p + q = 62.4 - 624
= -561.6
Since p and q are decimal parts, they must be between 0 and 1. -561.6 is outside this range, which means there are no values for p and q that satisfy the given conditions.
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Someone, please help me with this
Answer:
C = (0, 6)
E = (7, 0)
F = (0, -7)
Step-by-step explanation:
Answer: F is (0,-7)
C is (0,6)
E is (7,0)
Step-by-step explanation:
why do we use the absolute value of x or of g(x) in the derivative formulas for the natural logarithm
The natural logarithm function, ln(x), is only defined for positive values of x.
To clarify, let's consider the derivative formula for the natural logarithm of a function:
1. If we have y = ln(x), then the derivative dy/dx = 1/x.
2. If we have y = ln(g(x)), then the derivative dy/dx = g'(x)/g(x).
In both cases, x and g(x) must be positive for the natural logarithm to be defined. By using the absolute value, we ensure that the values of x or g(x) are always positive, which allows us to calculate the derivatives correctly.
1. Determine whether the derivative formula involves ln(x) or ln(g(x)).
2. If it involves ln(x), ensure x is positive by using the absolute value |x|.
3. If it involves ln(g(x)), ensure g(x) is positive by using the absolute value |g(x)|.
4. Apply the appropriate derivative formula (1/x for ln(x) or g'(x)/g(x) for ln(g(x))).
5. Ensure the result is accurate and applicable within the domain of the natural logarithm function.
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Mrs. Cochran bought 1.5 lb. of ground beef.
How many ounces did she buy?
Answer:
24 oz
Step-by-step explanation:
16 oz to a pound
16 x 1.5 = 24 oz
Answer:
24 ounces
Step-by-step explanation: One pound equal 16 ounce plus a half a pound which is 8 equals 24
Isaac's goal is to earn at least $80 toward a week at soccer
camp. He has earned $32 so far. How much more does he need
to earn?
Which inequality fits this situation?
Answer:
x greather than equal to 48
Step-by-step explanation:
Look he needs AT LEAST $80. So the sign is greater than or equal to.
So the inequality is x+32 is greater than or equal to 80
x greater than or equal to 48
2 + (8 - 2)(32+5(1 +2)
A school book fair has 72 non fiction books and 328fiction books for sale. What percent of the book fair is non fiction books
Answer:
18%
Step-by-step explanation:
total = 72 + 328 = 400
percent non-fiction = 72/400 × 100% = 18%
Use double integrals to find the area of the region bounded by the parabola y=2-x^2, and the lines x-y=0, 2x y=0.
The area of the region bounded by the parabola y=2-x^2, and the lines x-y=0 and 2x-y=0 is 2.667 square units.
To find the area, we set up a double integral over the given region. The region is bounded by the curves y=2-x^2, x-y=0, and 2x-y=0. We need to determine the limits of integration for x and y. The parabola intersects the x-axis at x=-2 and x=2.
The line x-y=0 intersects the parabola at x=-1 and x=1. The line 2x-y=0 intersects the parabola at x=-√2 and x=√2. Therefore, the limits for x are -√2 to √2, and the limits for y are x-y to 2-x^2. Integrating the constant 1 over these limits, we obtain the area as approximately 2.667 square units.
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Which expression is not equivalent to logp 36? 1. 6 log 2 2. log 9+ Iog, 4 O 3 2 logb 6 4. log 72 logp 2
log 30+ log 6 is not equivalent to log 36
What is equivalent expressions?Equivalent expressions are expressions that perform the same function not with standing their appearance. If two algebraic expressions are equivalent, they have the same value when the same value(s) for the variable are used (s).
The original phrase is as follows
Log 36
Following that, we write the alternatives (a) log 2+ log 18
Apply the logarithmic rule log 2+ log 18 log (218)
Log 2 plus log 18 log (36)
Remove the bracket
Log 2 plus log 18 log36
(a) Log 2+ Log 18 is the same as log 36.
(b) Log 30 plus log 6
Use the logarithms’ law. 30 logs or more 6 logs (30 x 6)
Log 30 plus log 6 Equals log (180)
Remove the bracket
Log 30-plus log 6-log180
Hence,
(c) Log 30+log 6 does not equal log 36.
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What is the solution for the equation? 14. 8 = n minus 0. 3 n = negative 15. 1 n = negative 14. 5 n = 14. 5 n = 15. 1.
Answer:
Step-by-step explanation;
3, 4, 5), while (m, n) = (5,2) gives the ... x 2 + 29x + 210 = (x + 15)(x + 14) and x2 + 29x - 210 = (x + 35)(x - 6)