Quelqu’un pourrait m’aider en urgence s’il vous plaît c’est pour demain je n’ai pas réussi pour le x=2 mais pour x=1 oui. Voici l’exercice

Exercice 2:
L'égalité 3x + 4 = 2x+5 est-elle vraie pour x = 2 ? Justifier la réponse.
• L'égalité 3x + 4 = 2x+5 est-elle vraie x = 1 ? Justifier la réponse.

Answer:

-3

Step-by-step explanation:

we khow that the vertex form of a function is written this way :

f(x)=a(x-h)²+k

Databases of variants are crucial in helping to identify disease gene candidates. Here's how they are used:

1. Collect and store genetic variants: Databases collect and store genetic variants from various individuals, including those with specific diseases and those without.

2. Compare variants between groups: By comparing the variants in affected individuals to those in unaffected individuals, researchers can identify variants that are more common in the disease group. This helps to narrow down the list of potential disease-causing genes.

3. Calculate probability: Databases can be used to calculate the probability of certain variants appearing in the general population. If a variant is rare in the general population but more common in individuals with a specific disease, it may be more likely to be a disease-causing variant.

4. Filter out common variants: As you mentioned, variants that are common in the general population or present in individuals without the disease are less likely to cause a rare genetic disease. By filtering out these common variants, researchers can focus on rare variants that may have a stronger association with the disease.

5. Identify disease gene candidates: Through this process of comparing and filtering genetic variants, researchers can identify potential disease gene candidates that warrant further investigation.

In summary, databases of variants help researchers identify disease gene candidates by storing genetic information, enabling comparison between affected and unaffected individuals, calculating variant probabilities, filtering out common variants, and ultimately pinpointing rare variants that may be associated with specific genetic diseases.

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One number is 5 more than 9 times the other. If we represent the first number with x, we get the two numbers to be

x          and

9+5x

The sum of the two numbers is 75. Plugging the two numbers into that equation, you get

x + 9+5x = 75

You can simplify to get

6x+9 = 75

By subtrating 9 from both sides, you get

6x = 66

Now you are practically done! You just need to divide both sides by 6 to get

x = 11

The two numbers were

x         and

9+5x

By plugging x = 11 into both of the equations, you get

11         and

64                (64 is 55 + 9)

The midpoint between two co-ordinate points is the point between them.

To find the midpoint M between S and T, we use the formula below.

Formula:

From the question,

Given:

Substitute these values into equation 1

To calculate the distance between S and T, we use the formula below.

Formula:

Substituting into equation 2

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Answer:

v=20π ft/s

Step-by-step explanation:

Given:

Distance from the security car to the movie theater, D=25 ft

Distance of the reflection from the car, d=30 ft

Speed of rotation of the strobe lights, 2 rev/s

To find the speed at which the reflection of the security strobe lights is moving along the wall of the movie theater, we need to calculate the linear velocity of the reflection when it is 30 ft from the car.

We can start by finding the angular velocity in radians per second. Since the strobe lights rotate at 2 revolutions per second, we can convert this to radians per second.

ω=2πf

=> ω=2π(2)

=> ω=4π rad/s

The distance between the security car and the reflection on the wall of the theater is...

r=30-25= 5 ft

The speed of reflection is given as (this is the linear velocity)...

v=ωr

Plug our know values into the equation.

v=ωr

=> v=(4π)(5)

∴ v=20π ft/s

Thus, the problem is solved.

The speed of the reflection of the security strobe lights along the wall of the movie theater is 2π ft/s.

To solve this problem, we can use the concept of related rates. Let's consider the following variables:

x: Distance between the security car and the movie theater wall

y: Distance between the reflection of the security strobe lights and the security car

θ: Angle between the line connecting the security car and the movie theater wall and the line connecting the security car and the reflection of the strobe lights

We are given:

x = 25 ft (constant)

y = 30 ft (changing)

θ = 2 revolutions per second (constant)

We need to find the speed at which the reflection of the security strobe lights is moving along the wall (dy/dt) when the reflection is 30 ft from the car.

Since we have a right triangle formed by the security car, the movie theater wall, and the reflection of the strobe lights, we can use the Pythagorean theorem:

x^2 + y^2 = z^2

Differentiating both sides of the equation with respect to time (t), we get:

2x(dx/dt) + 2y(dy/dt) = 2z(dz/dt)

Since x is constant, dx/dt = 0. Also, dz/dt is the rate at which the angle θ is changing, which is given as 2 revolutions per second.

Plugging in the known values, we have:

2(25)(0) + 2(30)(dy/dt) = 2(30)(2π)

Simplifying the equation, we find:

60(dy/dt) = 120π

Dividing both sides by 60, we get:

dy/dt = 2π ft/s

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We found the derivative of f(x) = x² at x = 3 to be 6.

Finding the derivative of a function at a certain number involves taking the derivative using the appropriate formula, then substituting the given value to obtain the derivative at that specific point. The power rule is a useful derivative formula for power functions. In the example given, we found the derivative of f(x) = x² at x = 3 to be 6.

To find the derivative of a function at a certain number, we need to use the derivative formula. For example, let's say we want to find the derivative of the function f(x) = x² at x = 3. We start by taking the derivative of the function using the power rule, which states that if f(x) = xⁿ, then f'(x) = nxⁿ⁻¹.

So, applying the power rule to f(x) = x², we get f'(x) = 2x. To find the derivative at x = 3, we simply substitute x = 3 into the derivative formula: f'(3) = 2(3) = 6.

Therefore, the derivative of f(x) = x² at x = 3 is 6.


To find the derivative of a function at a certain point, we first need to take the derivative of the function using the appropriate derivative formula. For power functions like f(x) = x^n, we use the power rule to differentiate the function. Once we have the derivative formula, we substitute the given value into it to find the derivative at that specific point. In the example given, we found the derivative of f(x) = x² at x = 3 by applying the power rule to get f'(x) = 2x, then substituting x = 3 to get f'(3) = 2(3) = 6.



To summarize, finding the derivative of a function at a certain number involves taking the derivative using the appropriate formula, then substituting the given value to obtain the derivative at that specific point. The power rule is a useful derivative formula for power functions. In the example given, we found the derivative of f(x) = x² at x = 3 to be 6.

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The area of the field is 10,765.44 square meters.

Given that:

Diameter, d = 72 m

Width, W = 72 m

Length, L = 93 m

The area of a two - dimensional figure is the area that its perimeter encloses. The quantity of unit squares that occupy a closed figure's surface is its region.

The area of the field is calculated as,

A = (π/4)d² + W·L

A = (3.14 / 4) x 72² + 72 x 93

A = 4,069.44 + 6,696

A = 10,765.44 square meters

The area of the field is 10,765.44 square meters.

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Step 1: We need to first find the equation of the line in slope-intercept form by finding b, or the y-intercept.

\(-6 = 3(-5) + b\\\\-6 = -15 + b\\\\9 = b\)

Step 3: We now need to write the equation of the line in slope-intercept form.

\(y = 3x + 9\)

Step 3: Now we convert the above equation from slope-intercept form to standard form.

\(y = 3x + 9\\\\-3x + y = 9\\\\-3x + y - 9 = 0\)

Our equation in standard form is: B. -3x + y - 9 = 0.

MN = TS

5x -2 = 3x + 1

Add 2 to both sides:

5x = 3x + 3

Subtract 3x from both sides:

2x = 3

Divide both sides by 2

X = 3/2

Now you have x solve for TS

TS = 3x + 1 = 3(3/2) + 1 = 4 1/2 + 1 = 5 and 1/2

The smaller triangle is 2/3 the size ( 26/39 = 2/3)

5 1/2 x 2/3 =  3 2/3

Given:

The equation of a line is y = (1/2)x-3.

Another line passes perpendicular to the first line through the point,

The objective is to find the equation of the second line.

Explanation:

In general, the product of the slope of perpendicular lines will be -1.

Consider the slope of the first-line as m1 and the slope of the second-line is m2.

To find m1:

From the given equation, the slope of the first line will be,

To find m2:

Then, the slope of the second line can be calculated as,

To find the equation of the second line:

The equation of a line using the slope and the point can be calculated as,

On plugging the obtained values in the above equation.

Hence, the equation of the line is y=-2x+5.

( - 5 / 7 ) / ( 2 / 4 )

= ( - 5 / 7 ) * ( 4 / 2 ) = - 10 / 7

Answer:

-2.5

Step-by-step explanation:

I am good at math

Answer:

-1

Step-by-step explanation:

Use slope formula.

y2-y1/x2-x1

(2, -1) and (-3, 4)

4+1/-3-2=

=5/-5=-1

The slope is -1. The line is slanted down from left to right.

Hope this helps!

Please mark as brainliest if correct!

Answer:

y = - x + 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (2, - 1 ) and (x₂, y₂ ) = (- 3, 4 )

m = \(\frac{4-(-1)}{-3-2}\) = \(\frac{4+1}{-5}\) = \(\frac{5}{-5}\) = - 1 , then

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 3, 4 )

4 = 3 + c ⇒ c = 4 - 3 = 1

y = - x + 1 ← equation of line

Answer:

b=3

Step-by-step explanation:

Step 1:

Expand

22=5b + 7b - 14

Step 2:

Simplify

22=12b - 14

Step 3:

add 14 to both sides

36= 12b

Step 4:

divide both sides by 12

36/12 = 12b/12

Step 5:

3 = b

Answer:

shifted 5 up and 4 to the left

Step-by-step explanation:

Answer:

See step-by-step, as it depends which value of pi you use.

Step-by-step explanation:

Equations

Assuming the pond is circular...

Diameter of pond = 50 yd ⇒ r = 50 ÷ 2 = 25 yd

Substitute r = 25 into the equation for the area of a circle:

\(\implies A= \pi \times25^2=625\pi\) yd²

Using \(\pi =3.14\), area = 1962.5 yd²

Using \(\pi=\dfrac{22}{7}\), area = 1964.3 yd² (nearest tenth)

Using \(\pi\), area = 1963.5 yd² (nearest tenth)

The smallest number of eggs that could have been in the box is 1134

The problem is to find the smallest number of eggs that could have been in the box, given the remainder when taking them out by different numbers. Here are the moves toward tackling it:

Allow n to be the quantity of eggs in the container. Then we have the accompanying arrangement of congruences:

n ≡ 1 (mod 2)

n ≡ 1 (mod 3)

n ≡ 1 (mod 4)

n ≡ 1 (mod 5)

n ≡ 1 (mod 6)

n ≡ 0 (mod 7)

For this problem, we have k = 6 k = 6, a i = {1,1,1,1,1,0} a_i = {1,1,1,1,1,0}, M i = {1260,840,630,504,420,720} M_i = {1260,840,630,504,420,720}, and y i = {−1,−2,−3,-4,-5,-6} y_i = {-1,-2,-3,-4,-5,-6}.

Plugging these values into the formula and simplifying modulo 5040, we get:

n = (−1260 + −1680 + −1890 + −2016 + −2100 + 0) mod 5040

n = (−8946) mod 5040

n = (−3906) mod 5040

n = 1134 mod 5040

Therefore, the smallest number of eggs that could have been in the box is 1134

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The interest rate is 10.89%

1. Given,С = 200+ 0.69YI = 80 - 1,000rG = 20NX = 850.09ee = 90M = 115YL = 0.5Y - 200rY = 300Using the equation for National Saving, we get,National Saving = Investment + Government Saving + Net exports(S – I) + (T – G) + (X – M) = 0T = 0, hence (S – I) + (X – M) = 0(1 – t)Y – C – (I + G) + NX = 0Where t = 0, we get,0.5Y – 200r – 200 – 69/100Y + 80 – 850.09e = 0.5Y – 200r – 970.09e – 120 = 0.5Y – 200r – 970.09e – 120 = 0Therefore, Y = 325.0454 - 0.5r + 4.851eThis is the equation for the IS curve.On the other hand, the equation for the LM curve is given by,Ms / P = YL(i)115 / 1 = 0.5Y - 200rTherefore, Y = 400 + 400rThis is the equation for the LM curve.The interest rate is given by the point of intersection of the two curves. Equating Y from both equations, we get,325.0454 - 0.5r + 4.851e = 400 + 400rSolving the above equation for r, we get r = 0.1089 or 10.89%..

The size of the nominal money supply in the new short-run equilibrium is 121.07.

2. From the equilibrium found in Question (1), if the foreign interest rate increases by 0.05, the domestic output will change in two ways, depending on the flexibility of the nominal exchange rate.Flexible Exchange Rates:In this case, the nominal exchange rate will depreciate (e decreases). This will increase net exports and shift the IS curve to the right. The new equilibrium will be at a higher level of output.Real exchange rate will fall.Increase in output will be higher compared to the fixed exchange rate case.Fixed Exchange Rates:In this case, the nominal exchange rate will remain constant. Therefore, there will be no effect on net exports.IS curve will not shift.Real exchange rate will remain unchanged.Increase in output will be less compared to the flexible exchange rate case.The nominal money supply in the new short-run equilibrium will change in the case of Fixed Exchange Rates. In the fixed exchange rate case, the domestic interest rate will increase, leading to an inflow of capital. This will increase the money supply and the LM curve will shift downwards until it intersects the IS curve at the new equilibrium point.

Real exchange rate will remain unchanged.

3. From the equilibrium found in Question (1), if the foreign interest rate increases by 0.05, the domestic output will change in two ways, depending on the flexibility of the nominal exchange rate. Flexible Exchange Rates :In this case, the nominal exchange rate will depreciate (e decreases). This will increase net exports and shift the IS curve to the right. The new equilibrium will be at a higher level of output .Real exchange rate will fall. Value of the real exchange rate in the new equilibrium is 0.891.Fixed Exchange Rates: In this case, the nominal exchange rate will remain constant. Therefore, there will be no effect on net exports.IS curve will not shift.

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Answer:

2x^2 + 5x - 12

Step-by-step explanation:

To distribute these two factors, use FOIL(First, Outer, Inner, Last) in this order.

(2x - 3)(x + 4) = 2x(x+4) - 3(x+4) = 2x^2 + 8x - 3x - 12 = 2x^2 + 5x - 12 .

(2x - 3)(x + 4) =

(2x * x) + (2x * 4) + (-3 * x) + (-3 * 4)

___________________________

(2x - 3)(x + 4)

| | | |

F F

O O

I I

L L

A scientific calculator is typically used for pre-calculus.

This type of calculator is designed to handle more advanced mathematical functions, such as trigonometry, logarithms, and exponents, which are commonly used in pre-calculus.

It is important to have a scientific calculator for pre-calculus because it allows you to easily solve more complex equations and perform calculations quickly and accurately.

Additionally, many scientific calculators have graphing capabilities, which can be useful for visualizing equations and understanding how they behave. Overall, a scientific calculator is an essential tool for pre-calculus and can help you succeed in the course.

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Answer:

B. SAS

\( \frac{sm}{dl} = \frac{27}{9} = 3 \\ \frac{am}{el} = \frac{15}{5} = 3 \\ angle \: m= angle \: l\)

Brainliest please~

By SAS similarity, ΔASM is similar to ΔDLE. Thus, option C is correct.

The SAS theorem is also known as the side-angle-side theorem, also known as a statement in Euclidean geometry that states two triangles are congruent if their corresponding sides are both the same length and their included angles are both of the same measures.

According to the given figure,

SM=27

DL=9

MA=15

LE=5,

∠M=∠L=31°

It is required to determine the similarity postulate that applies. Therefore,

From the ΔASM and ΔDLE, we have

\(\frac{SM}{DL}=\frac{27}{9} \\=3\\\frac{ML}{LE}=\frac{15}{5}\\ =3\\ Hence, \frac{SM}{DL}= \frac{ML}{LE}\)

∠M=∠L=31°

Hence, by SAS similarity, ΔASM is similar to ΔDLE.

Therefore, it can be concluded that option C is correct.

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The cost price of the toaster is rupees 1265.

A percentage is defined as any number that is less than or equal to 100. It is denoted by the sign%. The percentage denotes "out of 100".

Let's start by calculating the selling price of the toaster after the 8% discount:

Discount = 8% of 1650

\(D = (\dfrac{8}{100}) \times 1650\)

D  = 132

Selling price = 1650 - 132 = 1518

Now, we know that the profit made on this selling price is 20% of the cost price. Let's assume that the cost price of the toaster is x.

Profit = 20% of cost price

\(P = (\dfrac{20}{100}) x\)

P = 0.2x

Selling price = Cost price + Profit

1518 = x + 0.2x

1518 = 1.2x

\(x = \dfrac{1518}{1.2}\)

x = 1265

Therefore, the cost price of the toaster is rupees 1265.

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Answer:

Step-by-step explanation:

jdjdhddhdhhdhdhdhdhbdbcbchcbcbcbbcbcbcncjhchf

cjcjcucjcuu'hfhfhfhufhchcubxhdhcbchbcbchcjchhchc

a. The composition of the transformations T(3, -2) and T(1, -1) can be written as T(4, -3).

b. The composition of the transformations T(-40) and T(-2, 5) can be written as T(-42, 5).

a. To find the composition of the transformations T(3, -2) and T(1, -1), we add the corresponding coordinates together. T(3, -2) translates points by adding 3 to the x-coordinate and -2 to the y-coordinate, while T(1, -1) translates points by adding 1 to the x-coordinate and -1 to the y-coordinate. Combining these translations, we get T(3 + 1, -2 + -1) = T(4, -3). This means that applying the transformation T(4, -3) to a point is equivalent to applying T(3, -2) and then T(1, -1) in sequence.

b. Similarly, for the transformations T(-40) and T(-2, 5), we add the corresponding coordinates together. T(-40) translates points by adding -40 to the x-coordinate, while T(-2, 5) translates points by adding -2 to the x-coordinate and 5 to the y-coordinate. Combining these translations, we get T(-40 + -2, 0 + 5) = T(-42, 5). Therefore, the composition of the transformations T(-40) and T(-2, 5) can be written as T(-42, 5), indicating that applying T(-42, 5) is equivalent to applying T(-40) and then T(-2, 5) in sequence.

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so the answer is 4

how to get the answer

\((-24)\) ÷ \(-6+10\)

take the last part

\(-6+10\)

and you would solve that

it would be 4

Answer:

144

Step-by-step explanation:

2(3x+4)+2(2x_1)=64

x=4

2x_1=9

3x+4=16

9×16=144

Answer:

BC = 10 m ; CA = 5√3 m

Step-by-step explanation:

A right triangle with an angle of 60 degrees is half of a equalteral one

BC (the hypotnuese) is double the minor length (BA)

BC = 10 m

CA (the height) can be expressed as the minor leg multiply by √3

CA = 5√3 m

Answer: BC= 10 and AC=5√3

Step-by-step explanation:

if you use the 30 60 90 special right triangle thing then 30° is x which is 5 and 2 times 5 is 10 so the 90° (BC) is 10. for the AC the formula is x√3 so plug in the 5 and it becomes AC= 5√3

Answer:

x=73

Step-by-step explanation:

The equation of the tangent line to the function y = 2x^2 + x - 4 at the point x = 1 is y + 1 = 5(x - 1).

To find the equation of the tangent line to the function y = 2x^2 + x - 4 at the point x = 1,

we will follow these steps:
Evaluate the function at x = 1 to find the point (1, y):
\(y = 2(1)^2 + 1 - 4\)
y = 2 + 1 - 4
y = -1
So, the point is (1, -1).
Find the derivative of the function to get the slope of the tangent line:
\(dy/dx = d(2x^2 + x - 4)/dx\)
dy/dx = 4x + 1
Evaluate the derivative at x = 1 to find the slope of the tangent line:
m = 4(1) + 1
m = 5
Use the point-slope form to find the equation of the tangent line:
y - y1 = m(x - x1)
y - (-1) = 5(x - 1).

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Answer:

3 student.

Step-by-step explanation:

From the first statement:

Let the total score be T

Let the total number of student be x

The average of the score = 72

Average = Tota score / number of student

72 = T/x

Cross multiply

T = 72x ..... (1)

Second statement:

One more student took the test and the average becomes 76 with the student having a score of 88.

Therefore,

Overall score = T + 88

Total student = x + 1

Average = 76

Average = overall score / total number of student

76 = (T + 88) /(x + 1)

Cross multiply

76(x + 1) = T + 88

Clear bracket

76x + 76 = T + 88

From equation 1

T = 72x

76x + 76 = 72x + 88

Collect like terms

76x – 72x = 88 – 76

4x = 12

Divide both side by the coefficient of x i.e 4

x = 12/4

x = 3

Therefore, the initial number of the student were 3.

The controllability and observability matrices of the given state-space equation were calculated, but no set of bij and Cij was found to make the system controllable or observable. Therefore, the system is not controllable or observable.

To determine whether the given state-space equation is controllable and observable, we need to check the controllability and observability matrices.

The controllability matrix is given by:

[ B AB A^2B A^3B A^4B ]

where A and B are the state and input matrices, respectively.

The observability matrix is given by:

[ C ]

[ CA ]

[ CA^2 ]

[ CA^3 ]

[ CA^4 ]

where C is the output matrix.

Using the given state-space equation, we can calculate the controllability and observability matrices as follows:

A = [ 1 0 0 0 0 ]

   [ L0 1 0 0 1 ]

   [ b12 1 0 0 0 ]

   [ 0 0 1 0 0 ]

   [ b21 bzz 0 1 1-L ]

B = [ 0 ]

   [ 0 ]

   [ 0 ]

   [ 0 ]

   [ 1 ]

C = [ 1 0 0 0 0 ]

   [ 0 1 0 0 0 ]

   [ 0 0 1 0 0 ]

Controllability Matrix:

[ B AB A^2B A^3B A^4B ] =

[ 0 0 0 0 1 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]        

[ 0 0 0 0 0 ]

[ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]        

[ 0 0 0 0 0 ]

[ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]        

[ 0 0 0 0 0 ]

[ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          [ 0 0 0 0 0 ]          

[ 0 0 0 0 0 ]

[ 0 bzz b21bzz 0 Lb51 ] [ 0 L0 b12bzz Lb51 0 ] [ L0 b12bzz L0b21bzz 0 0 ]

[ b12bzz 0 L0b21bzz 0 0 ] [ 0 0 L0b12bzz 0 0 ]

Observability Matrix:

[ 1 0 0 0 0 ] [ 1 0 0 0 0 ] [ 1 0 0 0 0 ] [ 1 0 0 0 0 ] [ 1 0 0 0 0 ]

[ 0 1 0 0 0 ] [ 0 L0 1 b12 1 ] [ L0 b12bzz L0b21bzz 0 0 ] [ b12bzz 0 L0bb21bzz 0 0 ]

To elaborate on the solution, the controllability matrix shows that some of the columns are linearly dependent on the others, which means that it is not possible to find a set of inputs that can steer the system from any initial state to any desired state in finite time. Similarly, the observability matrix shows that some of the rows are linearly dependent on the others, which means that it is not possible to uniquely determine the state of the system from the output measurements.

Therefore, the system is not controllable or observable, and it cannot be controlled or accurately estimated using the given state-space equation.

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--The given question is incomplete, the complete question is given

" Is it possible to find a set of bij and a set of Cij such that the following state-space equation is controllable? Observable? (If the answer is yes, find a set) i(t) = 1 0 0 0 LO 1 0 0 01 5611 b12 1 0 0 0 |b21 bzz 0 1 1 0 X(t) + b31 b32|u(t) 0 0 1 0 | b41 buz 0 0 0 1- Lb51 652 [C11 y(t) = C21 C31 C12 C22 C32 C13 C23 C33 C14 C24 C34 C15 C25 x(t) C35