Q14. A particle starts from rest and moves with a constant acceleration of 0. Sms-s. What is the distance covered by the particle in 10s. ​

No, the system is not in equilibrium because the forces are not balanced which caused acceleration In system.

In mechanics, a force is any action that seeks to preserve, modify, or deform a body's motion. Isaac Newton's three principles of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the idea of force (1687).

Newton's first law states that unless a force is applied to a body, it will stay in either its resting or uniformly moving condition along a straight path. According to the second law, when an external force applies on a body, the body accelerates (changes velocity) in the force's direction.

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Answer:

11.5

Explanation:

Answer:

60 Ω

Explanation:

R(com) = 15 Ω

1/R(com) = 1/R1 + 1/R2 + 1/R3 ..... + 1/Rn

1/15 = 1/20 + 1/R2

1/R2 = 1/15 - 1/20

1/R2 = (4 - 3) / 60

1/R2 = 1/60

R2 = 60 Ω

así, la combinada de resistencia necesaria es 60 Ω

As the number of minutes it takes to make a single unit of the product decreases, the number of units of the product that are made per day increases.

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The tension at the top of the horizontal circle is T = m (v²/r - g ).

The tension at the bottom of the horizontal circle is m (v²/r + g ).

The tension at the bottom and top of he rope is calculated by applying the following formula as shown below;

The tension at the top of the horizontal circle is calculated as;

T = ma - mg

T = mv²/r - mg

T = m (v²/r - g )

where;

The tension at the bottom of the horizontal circle is calculated as;

T = ma + mg

T = mv²/r + mg

T = m (v²/r + g )

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The complete question is below:

Find the expression for the tension at the bottom and top of the circle

If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.

Option A is correct.

impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.

If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.

Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.

As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.

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Answer:

B. period of the sound wave

Energy is a fundamental concept in physics that represents the ability or capacity of a system to do work.

It is a scalar quantity, meaning it has magnitude but no specific direction. Energy exists in various forms and can be converted from one form to another. The characteristics of energy include:

1. Forms of Energy: Energy can exist in different forms such as kinetic energy (energy of motion), potential energy (stored energy), thermal energy (heat), chemical energy, electrical energy, and many more.

2. Conservation of Energy: The law of conservation of energy states that energy cannot be created or destroyed; it can only be transformed from one form to another. The total amount of energy in a closed system remains constant.

3. Transfer and Conversion: Energy can be transferred from one object to another or converted from one form to another. For example, electrical energy can be converted into light energy in a light bulb.

4. Units of Measurement: Energy is typically measured in joules (J) in the International System of Units (SI). Other common units include kilowatt-hours (kWh) for larger quantities of energy and calories (cal) for thermal energy.

5. Energy and Work: Energy is closely related to the concept of work. When work is done on an object, energy is transferred to it or from it, resulting in a change in its energy state.

Understanding the nature and characteristics of energy is crucial in various fields, including physics, engineering, and environmental science, as it plays a central role in explaining and analyzing various phenomena and processes.

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Explanation:

V = 3 cm/s = 0.03 m/s. BY THE FORmULA OF K.E. K.E = 1/2 mV^2. 300 =1/2 m (0.03)^2. m = 300 x 2/0.0009.

Answer: 1.2 mm

Explanation:

Time= 140 sec

Initial Velocity= 0

Average Velocity= 2.4 mm/s

Displacement=  0.5* (2.4/140) *140 = 1.2 mm

Explanation:

Here is the first one....you should try the second one...

Answer:

The more velocity an object has the harder it is to slow it down

Explanation:

slow it down

We must do 113 J of work to push the crate a distance of 3.00 m up the ramp at constant velocity.

What is constant velocity ?

Constant velocity is a term used to describe the motion of an object that is moving in a straight line with a constant speed. In other words, if an object is traveling at a constant velocity, its speed and direction of motion are both constant and unchanging. This means that the object is not accelerating, which in turn means that the net force acting on it is zero.

It is important to note that constant velocity does not mean that the object is at rest, as it can still be moving at a constant speed. Additionally, if the velocity of an object changes, even if its speed stays the same, it is still considered to be accelerating.

Since the crate is moving at a constant velocity, the net force acting on it must be zero. This means that the force you are applying to push the crate up the ramp must be equal in magnitude and opposite in direction to the force of friction acting on the crate. Using Newton's second law, we can write:

ma = F_push - F_friction

where m is the mass of the crate, a is its acceleration (which is zero since it is moving at constant velocity), F_push is the force you are applying to push the crate up the ramp, and F_friction is the force of kinetic friction acting on the crate.

The force of friction can be found using the coefficient of kinetic friction and the normal force. The normal force is equal in magnitude and opposite in direction to the component of the weight of the crate that is perpendicular to the ramp. Using trigonometry, we can find that:

N = mg cosθ

where g is the acceleration due to gravity and θ is the angle of the ramp. The force of friction is then:

F_friction = kN = kmg cosθ

So we can rewrite Newton's second law as:

ma = F_push - kmg cosθ

Solving for F_push, we get:

F_push = ma + kmg cosθ

The work done by a force is given by:

W = Fd cosφ

where F is the force, d is the distance moved, and φ is the angle between the force and the direction of motion. In this case, the force and the displacement are in the same direction, so φ = 0 and the work done by the pushing force is simply:

W_push = F_push d

Plugging in the given values, we get:

W_push = (ma + kmg cosθ) d

= (20.0 kg)(0 m/s^2 + 0.200(9.81 m/s^2) cos31.0°)(3.00 m)

= 113 J

Therefore, we must do 113 J of work to push the crate a distance of 3.00 m up the ramp at constant velocity.

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The time taken by parcel to cover the vertical distance is,

Plug in the known values,

The horizontal distance covered by parcel is,

Substitute known values,

Thus, the horizontal distance covered by parcel is 18503.2 m.

The scientific study of physics focuses on the underlying concepts that underpin the laws of nature. It investigates how matter, energy, space, and time behave and interact. Physics' fundamental goal is to comprehend the underlying laws and forces that create our universe.

Physics has developed theories and rules to explain a wide variety of events, from the motion of celestial bodies to the behaviour of subatomic particles, via meticulous observation, investigation, and mathematical analysis.

These theories offer a framework for comprehending and forecasting the behaviour of physical systems, such as Newton's laws of motion and Einstein's theory of relativity.

From the tiniest particles to the biggest cosmic structures, physics has enhanced our understanding of the world and sparked a host of technological advances.

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Answer:

Gravity...this was proven by NASA and was examined by Leonardo da Vinci.

Answer:

Gravity

Explanation:

In the absence of air resistance, Gravity accelerates all objects at the same rate of 9.8 m/s2

33,638.08 Joules of energy are needed to chill 116 g of water from 85°C to 15°C.

Calculate the necessary mass of ice by applying the law of conservation of heat or by equating the heat gained by the ice, water, and calorimeter. Heat gained by the ice equals Heat lost by the water and calorimeter. Thus, we calculated the mass of the ice to be 50g using the law of conservation of heat energy.

Water has a specific heat capacity of 4.184 J/g°C. We can use the following formula to determine how much energy is needed to chill 116 g of water from 85°C to 15°C:

Q = m * c * ΔT

where:

Q = amount of energy required to cool the water (in Joules)

m = mass of water (in grams)

c = specific heat capacity of water (4.184 J/g°C)

ΔT = change in temperature (in °C)

Plugging in the values, we get:

Q = 116 g * 4.184 J/g°C * (85°C - 15°C)

Q = 116 g * 4.184 J/g°C * 70°C

Q = 33,638.08 J.

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Answer:

i dont know

Explanation:

i dont know

Answer:

The mass will be 227kg.

Explanation:

Mass is a measure of how much "stuff" is in an object. It's a measure of the number and type of atoms in something, and is fixed. If you and I went to the moon right now, our bodies wouldn't change what they were made of. I would still be made up of all the same "stuff," as would you! So my mass would be the same and so would yours.

Weight would change on the moon, because weight is a measure of the local pull of gravity on an object's mass. Earth's gravitational force is about 10m/s2 and the moon's is about 1.6m/s2. So on the moon, I would have a weight of about 1/6 my weight on Earth... but I'd still wear the same size jeans!

A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.

To calculate the surface area of the scale, we can use the formula:

P = F/A

where P is the pressure, F is the force, and A is the surface area.

Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:

80,000 Pa = 10,000 N / A

To solve for A, we can rearrange the equation:

A = 10,000 N / 80,000 Pa

A = 0.125 m²

In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Answer:

Density of liquid

Depth of liquid

Acceleration due to gravity

Explanation:

F = ma

\(a = \frac{f}{m} \)

\(a = \frac{1500}{500} = 3\)

\(a = \frac{v2 - v1}{t} \)

\(3 = \frac{v2 - 10}{10} \)

v2 (final) = 40 m/s to the right direction

The acceleration of the system is 2.77 m/s² and the tension in the string is 127.4 N, given the provided values.

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In an open circuit like the picture the light bulb will be off. So, option (C) is correct.

Electric circuit is a way for current to flow through electricity. An electric circuit consists of a source of energy for the charged particles that make up the current, like a battery or generator; sources of current-using equipment, like lamps, electric motors, or computers; and the connecting wires or transmission lines.

Ohm's law and Kirchhoff's rules are two of the fundamental mathematical laws that define how electric circuits function.

In the given diagram, the circuit is open. So, no current passes through it and the light bulb will be off. Hence, option (C) is correct.

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If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.

I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.

Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.

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The period of the wave  that have  Ф = 0 and ω = 2π /6 \(s^{-1}\) is 6 sec and  the phasor representation of the wave at the three different times t = 0,2,4s is plotted in the graph .

1.1 - Given Ф = 0 , w = 2π /6 \(s^{-1}\)

     we know , ω = 2π / T    , T =period

      2π /6  =  2π / T

      T = 6 sec

1.2 - y(x,t) = A cos ( ωt )  , here  Ф = 0 , \(p_{0}\) is ignored .

       At t = 0 sec  ⇒ y(x,0)  = Acos( ω * 0 )  

                                            =A cos0

                                    y(x , 0) = A

       At t = 2 sec  ⇒ y(x,2)  = Acos( 2π /6 *2)

                                            = A cos( 2π /3)

                                     y(x,2) = \(\frac{-A}{2}\)

        At t = 4 sec  ⇒ y(x,4)  = Acos( 2π /6 *4)

                                            =Acos( 4π /3)

                                      y(x,4) =  \(\frac{-A}{2}\)

The pattern of disruption brought on by energy moving away from the sound source is known as a sound wave. Longitudinal waves are what make up sound. An example of an energy type that propagates across a material via adiabatic loading and unloading is acoustic waves. 

When energy moves through a medium (such as air, water, or any other liquid or solid substance), it creates a pattern of disruption that propagates away from the source of the sound.

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Question:

Imagine that you are sitting a distance away from a speaker, which is emitting sound waves. the air pressure, evaluated right at your ear is oscillating in time as y(x, t)=A cos ( ωt- Ф )+\(P_{0}\)

1.1 For question ,suppose that Ф = 0 and ω = 2π /6 \(s^{-1}\).what is the period of the wave?

1.2 plot the phasor representation of the wave at the three different times t = 0,2,4s