Prove: An odd times an odd equals an
odd.
(2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ]
= 2([ ]mn + m + 1 + 1
= odd

The tallest man had a more extreme height.

The tallest man had a z-score of 10.58. The shortest man had a z-score of -7.04

The tallest living man at one time had a height of 258 cm, and the shortest living man at that time had a height of 124.4 cm. The heights of men at that time had a mean of 176.07 cm and a standard deviation of 7.32 cm.

To determine which of these two men had a more extreme height, we can calculate the z-scores for each of them.

The z-score measures how many standard deviations an individual's height is from the mean height of the population. A positive z-score indicates that the height is above the mean, while a negative z-score indicates that the height is below the mean.

To calculate the z-score, we can use the formula:

z = (x - μ) / σ

Where:
- z is the z-score
- x is the individual's height
- μ is the mean height of the population
- σ is the standard deviation of the population

Let's calculate the z-scores for both men:

For the tallest man:
z = (258 - 176.07) / 7.32
z = 10.58

For the shortest man:
z = (124.4 - 176.07) / 7.32
z = -7.04

The z-score for the tallest man is 10.58, and the z-score for the shortest man is -7.04.

Since the z-score for the tallest man is much larger than the z-score for the shortest man, we can conclude that the tallest man had a more extreme height.

In summary:
- The tallest man had a z-score of 10.58
- The shortest man had a z-score of -7.04

Complete Question: The tallest living man at one time had a height of 258 cm. The shortest living man at that time had a height of 124.4 cm. Heights of men at that time had a mean of 176.07 cm and a standard deviation of 7.32 cm. Which of these two men had the height that was more​ extreme? What is the z score for the tallest man? What is the z score for the shortest man?

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Answer:

5,670

Explanation:

Given the expression

2(3⁴*5)7

= 2(81*5)*7

= 2(405)*7

= 2 * 405 * 7

= 14 * 405

= 5,670

hence the result of the expression is 5,670

Step-by-step explanation:

3x+3=12

3x=12-3

3x=9

3÷3=1

9÷3=3

x=3.

Answer:

Step-by-step explanation:

Answer: Also can i have brainliest?

The ball will hit the ground 5 seconds after being thrown.

Step-by-step explanation:

The correct function is: h(t)= -16t^2+64t+80

You can rewrite the Quadratic function given in the exercise with making h(t)=0. Then this is:

0= -16t^2+64t+80

Now you can simplify the equation dividing both sides by -16. So you get:

0= t^2-4t-5

To find the solution of the Quadratic equation, you can factor it. In order to do this, it is necessary to find two numbers whose sum is -4 and whose product is -5. These number would be -5 and 1.

Therefore, you get this result:

0= (t-5) (t+1)

t1=5

t2=-1

Since the time cannot be negative, you can conclude that the ball will hit the ground 5 seconds after being thrown.

A. Using the table z-value greater than 1.5 is approximately 0.0668. B. The p-value of the test is 0.0170. C. The p-value of the test is 0.0013. D. The standard error of the sample proportion is reduced.

The likelihood of receiving outcomes from a statistical hypothesis test that are at least as extreme as the actual results, assuming the null hypothesis is true, is known as the p-value in statistics. The p-value provides the minimal level of significance at which the null hypothesis would be rejected as an alternative to rejection points. The alternative hypothesis is more likely to be supported by stronger evidence when the p-value is lower.

The statistic for p-value is determined using the formula:

z = (p-hat - p) / sqrt(p * (1 - p) / n)

Substituting the value p-hat = 0.63, p = 0.60, and n = 100 we have:

z = (0.63 - 0.60) / sqrt(0.60 * 0.40 / 100) = 1.5

This is a right-tailed test (H1: p > 0.60), we need to find the probability of observing a z-value greater than 1.5 under the standard normal distribution.

Using the table z-value greater than 1.5 is approximately 0.0668.

B. For n = 200 we have:

z = (0.63 - 0.60) / sqrt(0.60 * 0.40 / 200) = 2.12 = 0.00170.

C. For n = 400:

z = (0.63 - 0.60) / sqrt(0.60 * 0.40 / 400) = 3.00 = 0.0013.

D. The standard error of the sample proportion is reduced as the sample size is increased, and the estimate of the true proportion is more precisely calculated. As a result, there is a greater z-value for a given difference between the sample percentage and the hypothesised proportion and a smaller sampling distribution. As a result, the p-value of the test falls as sample size increases, presuming all other variables stay the same.

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Answer:

B

Step-by-step explanation:

Answer:

51

Step-by-step explanation:

Because 5.1 times ten equals 51 because if you times ten by 5 u get 50 and then do .1 times ten you get 1

Answer:

481

Step-by-step explanation:

Lets say width = x

Length = x+24

Perimeter is 100 so

100=x+24+x+24+x+x

100=4x+48

100-48=4x

52=4x

x=13

So width = 13

Length = 37

37x13=481

The required mean of 2 and 12 is 7.

One kind of average is the mean.

It is calculated by dividing the total number of values in a list of values, such as measurements or numbers, by the total number of values in the list.

Add up each value in the set to determine the mean.

So, we have the values:

2 and 12

Mean formula: Sum of terms / Number of terms

Now, solve for the mean of the 2 values using the formula as follows:

Mean: Sum of terms / Number of terms

Mean: 14 / 2

Mean: 7

Therefore, the required mean of 2 and 12 is 7.

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Answer:.

Step-by-step explanation:.

Using the slope concept, it is found that the thundercloud is 6.43 miles above the ground.

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

In this problem, we have that:

Hence:

tan(65º) = h/3.

h = 3 x tan(65º)

h = 6.43 miles.

The thundercloud is 6.43 miles above the ground.

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The criteria prove that the quadrilateral is not a square

From the question, we have the following parameters that can be used in our computation:

For parallel opposite sides, we have

A = (-12, 5), B = (-7, 12), C = (5, 7) and D = (0, 0)

Calculate the slopes of opposite sides

So, we have

AD = (0 - 5)/(0 + 12) = -5/12

BC = (12 - 7)/(-7 - 5) = -5/12

AC = (7 - 5)/(5 + 12) = 2/17

BD = (12 - 0)/(-7 - 0) = -12/7

The sides AC and BD are not parallel

For the congruent sides, we have

AD = √[(0 - 5)² + (0 + 12)²] = 13

BC = √[(12 - 7)² + (-7 - 5)²] = 13

AC = √[(7 - 5)² + (5 + 12)²] = 17.11

BD = √[(12 - 0)² + (-7 + 0)²] = 13.89

The four sides are not parallel

For the right angles

The slopes calculated do not show that opposite sides have opposite reciprocals as their slopes

So, the four sides are not right angled

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Answer:

the correct answer is b

Step-by-step explanation:

i just took a quiz on ap3x, i hope this helped! have a blessed day! :))

A parabola is a mirror-symmetrical planar curve that is nearly U-shaped. The correct option is graph B.

A parabola is a mirror-symmetrical planar curve that is nearly U-shaped.

y = a(x-h)² + k

where,

(h, k) are the coordinates of the vertex of the parabola in the form (x, y);

a defines how narrower is the parabola, and the "-" or "+" that the parabola will open up or down.

Given that the function f(x)=x², which represents a parabola, therefore, the function of g(x) can be represented as,

\(g(x)=\dfrac13 f(x)\\\\g(x)=\dfrac13 x^2\)

Now, if we compare the function g(x) with the general equation of a parabola, therefore, the value of 'a' will be 1/3 which means that the function will open wider than f(x).

Thus, the correct option is graph B.

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Answer:the answer is six

Step-by-step explanation:

The dimensions of the crate with minimum possible surface area are 4 meters by 4 meters by 2 meters.

We are given that we want to design a rectangular crate with a square bottom, open top, and volume 32 cubic meters. Let's call the length of one side of the square bottom x and the height of the crate y. Then the volume of the crate is,

V = x²y = 32

We want to minimize the total surface area of the crate. This consists of the area of the square bottom, which is x², and the area of the four sides, which are all identical rectangles with dimensions y by x. Therefore, the total surface area of the crate is,

A = x² + 4xy

We can use the volume constraint to solve for y in terms of x,

x²y = 32

y = 32/x²

Substituting this expression for y into the equation for A, we get,

A = x² + 4x(32/x²) = x² + 128/x

To minimize A, we can take the derivative with respect to x and set it equal to zero,

dA/dx = 2x - 128/x² = 0

Solving for x, we get,

2x = 128/x²

x³ = 64

x = 4

Therefore, one side of the square bottom is 4 meters. Using the volume constraint, we can solve for y,

x²y = 32

4²y = 32

y = 32/16 = 2

So, the height of the crate is 2 meters. Thus, the dimensions of the crate with minimum surface area are 4 meters by 4 meters by 2 meters.

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Answer:

here is the ananswer

Step-by-step explanation:

red go to red and black to black

37.5 mile per hour

112.5 miles

rate = 60km per hour

1 mile = 1.6 kilometer

Let's convert:

The car's rate in miles per hour is 37.5 mile per hour

In 1 hour, the car travels 37.5 mile

In 3 hours, the car will travel = 3 × 37.5miles

= 112.5 miles

In 3 hours, the car will travel 112.5 miles

Answer:

we don't see the graph, so we cannot tell anything.

Answer:

B

Step-by-step explanation:

\(\huge\text{Hey there!}\)

\(\huge\boxed{\mathsf{(6y^2)^3 + 24y^6}}\)

\(\huge\boxed{\mathsf{= 6y^{2\times3} + 24^6}}\)

\(\huge\boxed{2\times3 = \bf \boxed{\bf 6}}\)

\(\huge\boxed{= \mathsf{6y^6 + 24y^6}}\)

\(\huge\boxed{= \mathsf{216y^6 + 24y^6}}\)

\(\huge\boxed{\text{COMBINE the LIKE TERMS}}\)

\(\huge\boxed{\mathsf{= 240y^6}}\)

\(\huge\boxed{\mathsf{Answer: \bf 240y^6}}\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

~\(\huge\boxed{\frak{Amphitrite1040:)}}\)

After 10 years, around 612.34 g of the initial sample will remain based on the given decay function.

(a) After 10 years, approximately 612.34 g of the sample will be left.

To find the amount of the sample remaining after 10 years, we substitute t = 10 into the given function A(t) = 800e^(-0.028t):

A(10) = 800e^(-0.028 * 10)

      = 800e^(-0.28)

      ≈ 612.34 g (rounded to the nearest hundredth)

Therefore, after 10 years, approximately 612.34 g of the initial sample will be left.

After 10 years, around 612.34 g of the initial sample will remain based on the given decay function.

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A volume of 2 liters is needed to obtain a 92 % solution.

In this problem we need to determine the volume of pure acid to be added with a volume of four liters of 88 % acid solution to get a 92 % solution. This can be done by definition of weighted average:

(88 / 100) · (4 L) + (100 / 100) · V = (92 / 100) · (4 L + V)

Where V is the volume needed of the pure acid, in liters.

3.52 L + V = 3.68 L + 0.92 · V

0.08 · V = 0.16 L

V = 2 L

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Answer:

7 miles per hour

Step-by-step explanation:

3.5 times 2.

Answer:

D would be the answer

Step-by-step explanation:

Answer:

(a) $16.25

(b) 7

Step-by-step explanation:

Rent of 1 raft for 1 day= $10

So, rent for 1 raft for half-day=10/2=$5

Charge for 1 person for half-day river trip =$15

Flat rate for half-day river trip=$200

(a) There is 4 member of the Kaplan on the trip.

One raft can hold up to 10 people, so, they need to take 1 raft on rent.

Rent of 1 raft for half-day =$5

Charge for 4 persons for half-day river trip =$15x4=$60

Total cost for the half-day trip for 4 persons=5+60=$65

Cost for half-day trip for 1 person= $65/4=$16.25

(B) Let there are n peoples on the river trip.

For the number of people up to 10, they need to take one boat on rent.

Total per person cost=(Cost for rent of 1 boat for half-day)+( Cost for half-day river trip)

=5+15n.

Cost for flat rate= (Cost for rent of 1 boat for half-day)+( Flat rate cost)

=5+100

The condition for which the flat-rate cost is less expensive than the per person rate cost is

\(5+100<5+15n\)

\(\Rightarrow 100<15n\)

\(\Rightarrow n>\frac{100}{15}\)

\(\Rightarrow n>6\frac{2}{3}\)

As n is the number od person which cant be a fractional value, so

n=7,8,9,... or \(n\geq7\)

So, a minimum of 7 people must be on the river trip to make the flat rate less expensive than the per person rate.

Answer:

Step-by-step explanation:

None

They are both imaginary or complex. You can check that out by calculating the discriminate. If you get a minus answer, then there are no real roots. Let's try it.

a = - 2

b = - 4

c = - 6

D = sqrt(b^2 - 4*a * c)

D = sqrt( (-4)^2 - 4*(-2)(-6)  )

D = sqrt( 16 - 48)

D = sqrt(-32) which is negative and there are no real roots.

Answer:B

Step-by-step explanation:

The mathematics teacher should use the data from the clicker quiz to identify the areas where her students have misconceptions or errors in their understanding of mathematical concepts.

She can then adjust her lesson plans to focus on these areas and provide additional instruction or resources to help her students improve their understanding. By analyzing the data and using it to inform her teaching strategies, the teacher can help her students develop better mathematical proficiency and achieve better results on future assessments.

Based on the given scenario, if the mathematics teacher's goal is to improve her students' mathematical proficiency, her best use of the data from the two-question clicker quiz would be to:

1. Identify areas of misunderstanding and error patterns: By analyzing the students' responses, the teacher can pinpoint specific concepts or problem-solving strategies that are causing difficulties.

2. Tailor instruction accordingly: Once the teacher has identified areas of weakness, she can adapt her lessons and teaching methods to address these issues more effectively, ensuring that students receive targeted support to improve their understanding.

3. Monitor progress over time: Regularly collecting and analyzing data from the quizzes allows the teacher to track the progress of her students and determine if her instructional adjustments are resulting in improved mathematical proficiency.

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The mathematics teacher can use the data from the clicker quiz to identify the areas where her students are struggling the most and focus her teaching on those topics.

She can also use the data to provide individualized feedback to each student, addressing their specific misconceptions and errors. By analyzing the patterns in the data, the teacher can modify her teaching strategies and methods to better suit the learning needs of her students.

In short, the data from the clicker quiz can be used to inform and improve the teacher's instruction and enhance her students' mathematical proficiency.

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