Problem 2 For this problem, use the following circuit Vin n Rc A m 2400240 A single-phase 50-kVA, 2400/240-volt, 60-Hz distribution transformer has a 1 Ω equivalent leakage reactance (Xeq) and a 5000 12 magnetizing reactance (Xm) referred to the high-voltage side. If rated voltage is applied to the high-voltage winding, calculate the open-circuit secondary voltage. Neglect Req and Re

Answers

Answer 1

The open-circuit secondary voltage is 240 V.

To calculate the open-circuit secondary voltage, we will use the transformer turns ratio formula:
Turns ratio (N) = V_primary / V_secondary
We are given:
- Single-phase transformer with 50 kVA capacity
- Primary voltage (V_primary) = 2400 V
- Secondary voltage (V_secondary) = 240 V

First, we find the turns ratio:
N = V_primary / V_secondary

N = 2400 / 240

N = 10

Since the transformer is under open-circuit conditions, the secondary voltage will not be affected by the leakage reactance (Xeq) or the magnetizing reactance (Xm). Therefore, when the rated voltage is applied to the high-voltage winding, the open-circuit secondary voltage will be equal to the rated secondary voltage.

So, the open-circuit secondary voltage is 240 V.

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Related Questions

10C of charge flow through a resistor in 4 seconds. What is the current?

Answers

Answer:

Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.

Explanation:

The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps

Given Data

Charge = 10 Columbs

Time = 4 seconds

Current = ?

Current, charge and time Relationship

Electrical current is defined by how much electric charge has been transferred per second, giving the following relationship:

Charge = Current*Time

Rearranging this we get:

Current = Charge/Time

The symbol for charge is Q , it is measured in coulombs (C).

The symbol for current is I , it is measured in amperes (A).

The symbol for time is T, it is measured in seconds (s).

Substituting our given Data into the expression we have

Current = 10/4

Current = 2.5 Amps

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fast moving rivers of air which move at 75 to 150 miles per hour

Answers

Fast moving rivers of air, known as jet streams, can reach speeds of 75 to 150 miles per hour (mph).

Determine the Jet streams?

Jet streams are narrow bands of strong winds that flow in the upper levels of the atmosphere, typically between 25,000 and 35,000 feet above the Earth's surface.

These high-speed air currents are driven by the temperature and pressure gradients in the atmosphere, particularly between warm and cold air masses.

The jet streams flow in a wavy pattern from west to east, influenced by the rotation of the Earth and atmospheric conditions. They can extend thousands of miles in length and a few hundred miles in width.

Jet streams play a crucial role in weather patterns, affecting the movement of storms and the distribution of temperature and precipitation.

Aviation and weather forecasting heavily rely on understanding and monitoring the jet streams. Their high speeds can benefit air travel by reducing flight times for planes flying with the jet stream and increase fuel efficiency.

However, flying against the jet stream can result in longer flight durations and higher fuel consumption.

In summary, jet streams are fast-moving rivers of air with speeds ranging from 75 to 150 mph. They are important atmospheric phenomena that impact weather patterns and have implications for aviation and weather forecasting.

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A 2kg body is moving a long a horizontal circular path of radius 2m with constant speed of 6m/s . what is the magnitude of the force acting on the body ? ​

Answers

The magnitude of force acting on the body is 36N

The picture shows a bicycle’s pedals. Look at the shaft that the pedals are attached to. Do you think the shaft is a lever? Why or why not?

The picture shows a bicycles pedals. Look at the shaft that the pedals are attached to. Do you think

Answers

Answer:

yes

Explanation:

A shaft instead of a chain to transmit power from the pedals to the wheel.

Yes, the shaft that the pedals are attached to in a bicycle can be considered a lever.

A lever is a simple machine that consists of a rigid object that rotates around a fixed point called the fulcrum. In the case of the bicycle pedals, the shaft acts as the lever arm, and the fulcrum is the point where the shaft is attached to the bicycle frame.

The characteristics of a lever apply to the shaft in the bicycle pedals:

1. Fulcrum: The fixed point of rotation in the lever system is provided by the bearing or axle that holds the shaft in place on the bicycle frame. This allows the shaft to rotate freely.

2. Effort and Load: The rider applies an effort or force on the pedals by pushing down with their feet. This effort is transmitted to the shaft, which in turn rotates the bicycle's crankset.

3. Mechanical Advantage: The shaft in the bicycle pedals can provide mechanical advantage by amplifying the force applied by the rider. By having longer pedals or using different gear ratios, the effective lever arm length can be modified, allowing the rider to exert more force with less effort or cover a greater distance with each pedal stroke.

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below are four different objects. their centre of mass c is shown. which object is not in equilibrium?

Answers

option B. The ruler is the object that is not in equilibrium. Option B.

The ruler is not in equilibrium. What is equilibrium? Equilibrium is a state of balance in which all the forces and moments on a body are equal and balanced, resulting in no net force or acceleration. When an object is at equilibrium, it is either at rest or moving with a constant velocity. The stability of an object is determined by the location of its center of mass. If the object's center of mass is above its base of support, it is unstable and will tip over.To determine whether the four given objects are in equilibrium, we must first determine their centers of mass. In the figure, the black dot indicates the center of mass. Let's start with object A: A metal sphere: The center of mass is located at the center of the sphere, which is also the geometric center, so the sphere is in equilibrium. Object B: A ruler: The center of mass is located at the center of the ruler, which is also the geometric center. However, the base of the ruler is not wide enough to support it when it is not vertical, so it is not in equilibrium. Object C: A box: The center of mass is located at the center of the box, which is also the geometric center, so the box is in equilibrium. Object D: A cone: The center of mass is located slightly above the geometric center, which is at the bottom of the cone. The base of the cone, however, is wide enough to support it, so it is in equilibrium.

The ruler is the object that is not in equilibrium. Option B.

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if your fixture contains a 60 w bulb at 120v, and your local power utility sells energy at 8 cents per kilowatt hour, how much will it cost to leave the bulb on for the whole month

Answers

The cost to leave the bulb on for the whole month $3.46 is

How does a circuit respond to an increase in current?

When the voltage rises while the current stays the same, the resistance also rises. Alternately, if the voltage is held constant while the current increases, the resistance will decrease.

Energy is characterized as having the "ability to do work, which is the capacity to exert a force sufficient to move an object." Despite this unclear definition, the meaning is actually quite straightforward: energy is simply the force that moves things.

Energy = power × time

Energy = 60w × 1month × 30days/1month×24hrs/1day ×1kw/1000w

Energy = 43.2kw.h

Cost = energy × rate

Cost = 43.2×$0.8kw/h

Cost = $3.46.

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Which sport requires the least amount of agility? HELLLLPPP
1.volley ball
2.golf
3.football
4.basketball

Answers

Answer:

golf

Explanation:

it's less physical strength in more of you hitting the ball with whatever the stick is called

which of the following list adt implementations gives us an o(1) time for removeatend, i,e removing an element from the end of the list? i. a singly-linked list with only a head pointer. ii. a singly-linked list with head and tail pointers. iii. a doubly-linked list with only a head pointer. iv. a doubly-linked list with head and tail pointers. (a) i and iii (b) i, iii and iv (c) none of the other options is correct (d) ii and iv (e) i, ii, iii and iv

Answers

Both a singly-linked list with head and tail pointers and a doubly-linked list with head and tail pointers can perform removeAtEnd operations in O(1) time complexity.
Option d is correct.


Removing an element from the end of a list typically requires us to traverse the entire list until we find the last node, and then remove that node from the list. This means that the time it takes to remove an element from the end of a list is directly proportional to the length of the list - in other words, it's an O(n) operation, where n is the length of the list.

However, there are certain data structures that can make removing an element from the end of a list faster. One example is a doubly-linked list with a tail pointer. In this data structure, each node has a reference to the previous node as well as the next node, and there is a special pointer to the last node in the list (the tail). When we want to remove the last element, we can simply update the tail pointer to point to the second-to-last element, and then remove the last element from the list. Since we don't need to traverse the entire list to find the last element, this operation takes constant time - O(1).

A singly-linked list with a tail pointer would also give us O(1) time for removeatend. However, a singly-linked list with only a head pointer (option i) or a doubly-linked list with only a head pointer (option iii) both require us to traverse the entire list to find the last element, so they would not give us O(1) time for removeatend.

Therefore, the correct answer is (d) ii and iv, as both of these options include a tail pointer that allows for O(1) removal of the last element. Option (e) i, ii, iii and iv is incorrect because option i and iii do not have tail pointers, which means they cannot support O(1) removal of the last element.


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Use Q=mCΔt : PCl3 is a compound used to manufacture pesticides. A reaction requires that 96.7 g of PCl3 be raised from 31.7 oC to 69.2 oC. How much energy will this require given that the specific heat of PCl3 is 0.874 J/g oC? Please explain fully . Im trying to understand this

Answers

The quantity of heat required is 1229.1 J

What is specific heat capacity?

The specific heat capacity of a substance is the quantity of heat required to increase the temperature of a unit mass of the substance by 1°C or 1k. it measure in J/kg/k.

The specific heat capacity of a substance is denoted by 'C'. And it is expressed as C = Q/m∆t

where ∆t is the change in temperature, Q is the quantity of heat energy required and m is the mass of the substance.

therefore Q=mCΔt

Q= 96.7× 0.874×(69.2-31.7)

Q= 1229.1J

Thereore the heat required to increase the temperature from 31.7°C to 69.2°C is 1229.1J

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the local units are not internationally accepted for measurement why​

Answers

i hope you will accept my answer and please put a picture next for your next question

how to light prodeced by nature

Answers

Natural sources of light include our sun and other stars, where the source of energy is nuclear energy (recall that the moon does not produce light but merely reflects sunlight), lightning, where the source is electrical, and fire, where the energy source is chemical.

Answerssssssssssssssssssssssss

Answerssssssssssssssssssssssss

Answers

Answer:

hola

Explanation:

Answer:

Graph 2

Explanation:

4. What is the acceleration of a car traveling at 65 mph that keeps a constant speed over
75 seconds?
a. 0.0 mphis
b. 65 m/s2
c. 75 mphis
d. 75 m/s2
e. Not enough data is given.

Answers

Answer:

a.

Explanation:

Remeber speed and velocity are the same concept, it just speed is scalar, meaning it doesn't have a direction nor it negative.

So technically thr car had a constant speed over 75 seconds.

If thr car has a constant speed, the car isn't speeding up or slowing down so it has accleration of 0 so the answer is a.

What label should mateo place in the marked cell? uses electrical energy provides electrical energy measures electric current controls electric current

Answers

The product label which Mateo should place in the marked cell is that it: B. provides electrical energy.

What is a product label?

A product label refers to a paper-document which contains information about the chemical elements, nutrients, and other compounds that are present in a product and its function.

In this scenario, the product label which Mateo should place in the marked cell is that this product was designed and developed to provide electrical energy, based on the electrical symbol for battery shown in the image attached below.

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What label should mateo place in the marked cell? uses electrical energy provides electrical energy measures

A plate falls to the floor. When is its potential energy
the lowest?
1.in mid-fall
2.Immediately after it begins to fall
3.When its kinetic energy is the highest
4.Before it falls

Answers

Answer:

I think it's 3

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

the element niobium, which is a metal, is a superconductor (i.e., no electrical resistance) at temperatures below 9 k . however, the superconductivity is destroyed if the magnetic field at the surface of the metal reaches or exceeds 0.10 t . part a what is the maximum current in a straight, 2.80- mm -diameter superconducting niobium wire? express your answer with the appropriate units.

Answers

The maximum current in a straight, 2.80-mm-diameter superconducting niobium wire is 1.39 x 10⁵ A (amperes).

The maximum current that a superconducting niobium wire can carry can be calculated using the critical magnetic field and the formula for the magnetic field inside a long straight wire:

B = (μ0I)/(2πr)

where B is the magnetic field, μ0 is the vacuum permeability (4π x 10⁻⁷ T m/A), I is the current, and r is the radius of the wire.

The critical magnetic field for niobium is 0.10 T, so we can use this value to find the maximum current that the wire can carry without destroying its superconductivity:

0.10 T = (4π x 10⁻⁷ T m/A) * I / (2π * (2.80/2 x 10⁻³ m))

Solving for I, we get:

I = (0.10 T) * (2π * (2.80/2 x 10⁻³ m)) / (4π x 10⁻⁷ T m/A)

I = 1.39 x 10⁵ A

Therefore, the maximum current in a straight, is 1.39 x 10⁵ A (amperes).

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An eagle is flying horizontally 16.4 meters above a lake at a speed of 9.3 m/s, carrying a small pumpkin in its talons. The pumpkin slips free. How far horizontally will the pumpkin travel after it slips from the eagle until it hits the ground?

Answers

Answer:

The horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m

Explanation:

Given;

height above the ground, h = 16.4 m

speed of the eagle, v = 9.3 m/s

The time it will take the pumpkin to fall at the given height is calculated as;

\(t = \sqrt{\frac{2h}{g} }\\\\t = \sqrt{\frac{2*16.4}{9.8} }\\\\t = 1.83 \ s\)

The horizontal distance traveled at this time is given by;

x = vt

x = (9.3)(1.83)

x = 17.02 m

Therefore, the horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m

Two balloons of different mass hang from strings near each other. You charge them about the same amount by rubbing each balloon with wool.Draw a force diagram for each of the balloons.
Draw the vectors starting at the balloons. The location and orientation of the vectors will be graded. The length of the vectors will not be graded.

Answers

The diagrams of two vectors is shown below in pictorial representation.

Since the two balloons are charged with the same amount and are hanging from strings near each other, they will experience electrostatic repulsion due to their like charges.

Therefore, the force diagrams for each of the balloons will include a repulsive electrostatic force pointing away from the other balloon.

In addition to the electrostatic force, each balloon will experience a gravitational force due to its mass and the force of tension from the string that is holding it up.

Since the two balloons have different masses, the force diagram for each balloon will be slightly different.

For the lighter balloon, the force diagram would look something like this:

  /        \

 /          \

|            |

|            |

|  Electro-  |

|  static    |

|   force    |

|            |

|            |

|            |

 \          /

      |

      |

  Tension

  force

      |

      |

   Gravitational

   force

      |

      |

     Mass

For the heavier balloon, the force diagram would look similar, but with a larger gravitational force vector and a smaller tension force vector due to the increased weight of the balloon:

  /        \

 /          \

|            |

|            |

|  Electro-  |

|  static    |

|   force    |

|            |

|            |

|            |

 \          /

      |

      |

  Tension

  force

      |

      |

     Gravitational

     force

      |

      |

     Mass

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An ideal gas initially at 300 K undergoes an isobaric expansion at 2.50 kPa. If the volume increases from 1.00 m3 to 3.00 m3 and 12.5 kJ is transferred to the gas by heat, what are a. the change in its internal energy and b. its final temperature?

Answers

Answer:

a) \( \Delta U = 7.5 kJ \)

b) \(T_{f} = 900 K \)

Explanation:

a) To find the change in its internal energy (U) we need to use the following equation:

\( \Delta U = W + Q \)

Where:

W: is the work done on the system

Q: is the energy transferred into the system by heat = 12.5 kJ

Since we have an isobaric expansion, the work is:

\( W = - P\Delta V = - P(V_{f} - V_{i}) \)

Where:

\(V_{f}\): is the final volume = 3.00 m³

\(V_{i}\): is the initial volume = 1.00 m³

P: is the pressure = 2.50 kPa

\( W = -P(V_{f} - V_{i}) = -2.5 \cdot 10^{3} Pa(3.00 m^{3} - 1.00 m^{3}) = -5.00 \cdot 10^{3} J \)

Now, we can find the change in its internal energy:

\( \Delta U = W + Q = -5.00 \cdot 10^{3} J + 12.5 \cdot 10^{3} J = 7.5 \cdot 10^{3} J \)

b) The final temperature can be found as follows:

\( \frac{V_{i}}{V_{f}} = \frac{T_{i}}{T_{f}} \)

\( T_{f} = \frac{T_{i}*V_{f}}{V_{i}} = \frac{300 K*3.00 m^{3}}{1.00 m^{3}} = 900 K \)

Hence, the final temperature is 900 K.

I hope it helps you!

atomic number of metal and the atomic mass

Answers

Answer:

there are many metals in the periodic table and all have different atomic number and mass

Explanation:

A 2 km long optical fiber uses a fiber core with n_f = 1.6 and a cladding with n_c = 1.57. Compute the maximum data rate f_p The operating frequency is 100 THz. a. 2.453 Mbits/s b. 2.543 Gbit/s c. 1.272 Mbit/s d. 5.086 Gbit/s

Answers

The maximum data rate of the optical fiber is 2.543 Gbit/s. So, the correct answer is B).

The maximum data rate f_p for an optical fiber can be calculated using the formula:

f_p = (2/3) * (c/n_f) * (log_2(N))² * B

where c is the speed of light in vacuum, N is the number of levels, and B is the bandwidth.

To calculate N, we use the equation:

N = (V²)/2

where V is the normalized frequency, given by

V = 2pi(a/λ)*(n_f² - n_c²\()^{0.5}\)

where a is the radius of the fiber core, λ is the wavelength of the light, and n_f and n_c are the refractive indices of the core and cladding, respectively.

Substituting the given values, we get

a = 2 km / 2 = 1 km

λ = c/f = 310⁸ m/s / 10010¹² Hz = 310⁻⁶ m

V = 2pi*(1 km)/(310⁻⁶ m)(1.6² - 1.57²\()^{0.5}\) = 52.44

Using V, we can calculate N

N = (V²)/2 = (52.44²)/2 = 1373.99 ≈ 1374

Substituting the values of c, n_f, log_2(N), and B, we get

f_p = (2/3) * (310⁸ m/s/1.6) * (log_2(1374))² * 10010¹² Hz = 2.543 Gbit/s

Therefore, the answer is (b) 2.543 Gbit/s.

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Are these statements about the Fluid mechanics true?
Statement 1: Fluid mechanics is a branch in chemistry that involves study of fluids.
Statement 2: Fluid mechanics can be divided into 2 major categories.
a) True, False
b) True, True
c) False, True
d) False, False

Answers

Announcement 1: Fluid mechanics is a branch of chemistry that involves having a look at fluids:  c) False, True

Fluid mechanics is the branch of physics concerned with the mechanics of fluids and the forces on them. It has programs in an extensive variety of disciplines, such as mechanical, aerospace, civil, chemical, and biomedical engineering, geophysics, oceanography, meteorology, astrophysics, and biology. Fluid mechanics is the look at of the forces of the fluid and the way fluids flow. Fluid mechanics may be divided into parts: fluid statics and fluid dynamics. Fluid statics is the observation of fluids at rest, and fluid dynamics is the study of fluids in motion.

Fluid mechanics is the look at fluid behavior (beverages, gases, blood, and plasmas) at relaxation and in movement. Fluid mechanics has a huge variety of packages in mechanical and chemical engineering, organic structures, and in astrophysics.

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HELPPPPP!!!!! ME PLSSSS I don't know the answer!!!****URGENT****

HELPPPPP!!!!! ME PLSSSS I don't know the answer!!!****URGENT****

Answers

Answer:

D is the Answer

Explanation:

I know D is the answer because I calculated it and got answer choice D

The magnetic force on a straight wire 0.30 m long is 2.6 x 10^-3 N. The current in the wire is 15.0 A. What is the magnitude of the magnetic field that is perpendicular to the wire?

The magnetic force on a straight wire 0.30 m long is 2.6 x 10^-3 N. The current in the wire is 15.0 A.

Answers

Answer:  the magnitude of the magnetic field perpendicular to the wire is approximately 1.93 x 10^-3 T.

Explanation:

The magnetic force on a straight wire carrying current is given by the formula:

F = B * I * L * sin(theta),

where F is the magnetic force, B is the magnetic field, I is the current, L is the length of the wire, and theta is the angle between the magnetic field and the wire (which is 90 degrees in this case since the field is perpendicular to the wire).

Given:

Length of the wire (L) = 0.30 m

Current (I) = 15.0 A

Magnetic force (F) = 2.6 x 10^-3 N

Theta (angle) = 90 degrees

We can rearrange the formula to solve for the magnetic field (B):

B = F / (I * L * sin(theta))

Plugging in the given values:

B = (2.6 x 10^-3 N) / (15.0 A * 0.30 m * sin(90 degrees))

Since sin(90 degrees) equals 1:

B = (2.6 x 10^-3 N) / (15.0 A * 0.30 m * 1)

B = 2.6 x 10^-3 N / (4.5 A * 0.30 m)

B = 2.6 x 10^-3 N / 1.35 A*m

B ≈ 1.93 x 10^-3 T (Tesla)

PART ONE In a 52 s interval, 381 hailstones strike a glass window of area 1.124 m^2at an angle 43◦to the window surface. Each hailstone has a mass of 5 g and speed of 6 m/s. If the collisions are elastic, find the average force on the window.
Answer in units of N.
PART TWO Find the pressure on the window. Answer in units of N/m^2.

Answers

Answer:

Each hailstone has a mass of 7 g and a speed of 4.5 m /s. If the collisions are elastic, what is the average force on the window? ... strike a glass window of an area of 0.954 m2 at an angle of 25◦ to the window surface.

Explanation:

Thats all i hope this helps lol

A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.

Answers

Given:

The initial height of the ball, h=1.6 m

The initial speed of the ball, u=14 m/s

To find:

a) The time of flight of the ball.

b) The range of the ball.

Explanation:

As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.

Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.

The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.

a)

From the equation of motion,

\(h=u_yt+\frac{1}{2}gt^2\)

Where g is the acceleration due to gravity and t is the time of flight of the ball.

On substituting the known values,

\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)

b)

The range of the ball is given by,

\(R=u_xt\)

On substituting the known values,

\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)

Final answer:

a) The time of flight of the ball is 0.57 s

b) The range of the ball is 7.98 m

Brian made this table to organize his notes on changes of state.

A 2-column table with 4 rows. The first column titled change of state has entries melting, freezing, deposition, condensation. The second column labeled energy change has entries gain, lose, gain, lose.

Which change of state has the wrong energy change listed?

condensation
deposition
melting
freezing

Answers

Answer:

Deposition

Explanation:

I took the quiz

Deposition is accompanied by a loss in energy as the particles become less energetic hence the entry involving deposition is wrong.

What is phase change?

The term phase change simply means a change from one state of matter to another. Phase changes are often accompanied by a loss or gain in energy depending on what process occurred.

The phase change deposition is accompanied by a loss in energy as the particles become less energetic hence the entry involving deposition is wrong.

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the back wall of an auditorium is 25.0 m from the stage. part a if you are seated in the middle row, how much time elapses between a sound from the stage reaching your ear directly and the same sound reaching your ear after reflecting from the back wall? the speed of sound in the air is 343 m/s .

Answers

The difference of time between a sound from the stage reaching your ear directly and the same sound reaching your ear after reflecting from the back wall would be 0.036s.

What does a sound wave echoe mean?

An echo is a reflection of sound that comes to the audience with a delay after the direct sound in audio signal processing and acoustics. The delay is directly proportionate to the separation between the source and the listener of the reflecting surface. One the kind audio effect that involves significantly delaying a signal is an echo effect. In this instance, after some period of time, listeners hear the same signal repeated clearly. When there is a noticeable delay in the sound, listeners can differentiate individual echoes.

The person seated in the middle row:

The distance sound traveled to middle row => 25/2 = 12.5m

The total distance the sound traveled to full length of auditorium and to the middle row => 25+12.5 => 37.5m

t1 => d1/v => 12.5/343 => 0.036s

t2 => d2/v => 25/343 => 0.072s

t2-t1 => 0.036s

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a simple pendulum makes 130 complete oscillations in 3.10 min at a location where g = 9.80 m/s2. (a) find the period of the pendulum. s (b) find the length of the pendulum. m

Answers

A simple pendulum makes 130 complete oscillations in 3.10 min at a location where g = 9.80 m/s²: (a) The period of the pendulum is approximately 1.43 seconds (s). (b) The length of the pendulum is approximately 0.80 meters (m).

(a) The period of a simple pendulum is the time taken for one complete oscillation. We can calculate the period (T) using the formula:

T = (time taken for oscillations) / (number of oscillations)

Given that the pendulum makes 130 complete oscillations in 3.10 minutes, we need to convert the time to seconds:

T = (3.10 min × 60 s/min) / 130

T ≈ 1.43 s

Therefore, the period of the pendulum is approximately 1.43 seconds.

(b) The length of a simple pendulum can be determined using the formula:

L = (g × T²) / (4π²)

Substituting the value of the period (T) calculated in part (a) and the acceleration due to gravity (g = 9.80 m/s²), we can find the length (L):

L = (9.80 m/s² × (1.43 s)²) / (4π²)

L ≈ 0.80 m

Thus, the length of the pendulum is approximately 0.80 meters.

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An object is taken to Mars. It’s mass is 15kg, it’s weight on Mars is 55.5N

What is the gravitational field strength on Mars?

Answers

Answer:

Approximately \(3.7\; {\rm N \cdot kg^{-1}}\) (or equivalently, \(3.7\; {\rm m\cdot s^{-2}}\).)

Explanation:

Gravitational field strength measures the force (weight) that the field exerts on object of unit mass (e.g., \(1\; {\rm kg}\).)

Divide the weight of the object by its mass to find the gravitational field strength at the position.

In this question, \(\text{weight} = 55.5\; {\rm N}\) while \(\text{mass} = 15\; {\rm kg}\). Therefore, the gravitational field strength will be:

\(\begin{aligned} & (\text{gravitational field strength}) \\ =\; & \frac{(\text{weight})}{(\text{mass})} \\ =\; & \frac{55.5\; {\rm N}}{15\; {\rm kg}} \\ =\; & 3.7\; {\rm N \cdot kg^{-1}} \end{aligned}\).

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