The volume of the nitrogen gas will be approximately 25.96 L when the pressure changes from 2.5 atm to 1.3 atm, while the temperature remains constant at 32°C.
Mathematically, we can express Boyle's Law as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given:
Initial volume V1 = 13.5 L
Initial pressure P1 = 2.5 atm
Final pressure P2 = 1.3 atm
Temperature is constant
Using Boyle's Law, we can write:
P1V1 = P2V2
Solving for V2, we get:
V2 = (P1V1) / P2
Substituting the given values, we get:
V2 = (2.5 atm x 13.5 L) / 1.3 atm
V2 = 25.96 L
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--The complete Question is, : Nitrogen gas has a volume of 13.5 L at 32°C and 2.5 atm. What is the volume when the pressure changes to 1.3 atm and temperature is 32°C?
What kind of weather is associated with high air pressure?
How many oxygen does Nitrogen Dioxide have?
Answer:
Again, nitrogen dioxide does not follow the octet rule for one of its atoms, namely nitrogen. The total number of valence electrons is 5+2(6)=17. There is persistent radical character on nitrogen because it has an unpaired electron. The two oxygen atoms in this molecule follow the octet rule.
CuBr2 percent composition
The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.
To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.
The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.
Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol
Now, let's calculate the percent composition of each element in CuBr₂:
Percent composition of copper (Cu):
Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%
Percent composition of bromine (Br):
Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%
Therefore, the percent composition of CuBr₂ is approximately:
- Copper (Cu): 28.46%
- Bromine (Br): 71.54%
These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.
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Evaporation Rate
Various Compounds
The data below shows the change in
temperature when 4 different compounds
are exposed to room temperature air for
over 2 minutes.
Compound Temperature
Change (C)
A
B
"C
-12.5
-9.2
-7.6
-4.8
D
Type of IMF
DF
DF
DF, DD
DF, DD, HB
DF-dispersion forces, DD-dipole-dipole,
HB-hydrogen bonding
What is the likely cause for the
difference in evaporation
points of the compounds A
and D?
A. The atoms have different types of bonds
holding the molecule together.
B. The molecules have different amounts of
dispersion forces.
C. The molecules have different numbers of
oxygen atoms.
D. The molecules have different
intermolecular forces.
The atoms have different types of bonds holding molecules together and leads to evaporation.
Thus, A crucial stage in the Earth's water cycle is evaporation, which is the process by which water transforms from a liquid to a gas or vapor. Evaporation at the molecular level requires the interface to break at least one extremely strong intermolecular connection between two water molecules.
The chemical mechanism by which an evaporating water molecule acquires sufficient energy to escape from the surface has remained mysterious despite the significance of this activity.
Here, we demonstrate that the high kinetic energy of the evaporated water molecule is enabled by a precisely timed formation and dissolution of hydrogen bonds involving at least three water molecules at the interface, the recoil of which allows one water molecule to escape.
Thus, The atoms have different types of bonds holding molecules together and leads to evaporation.
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24. What is the total number of grams of potassium chloride needed to saturate exactly 300 grams of water at 10°C?
1) 70 2) 90 3) 80 4) 60
Answer:
That would be 90 grams
Explanation:
This should be right but please, please, please correct me if I'm worng because I dont want anyone to fail because of me. Have a great day luv <3
The answer is option B , 90 grams of potassium chloride(KCl) is needed to saturate exactly 300 grams of water at 10°C
How do you define Solubility ?The measure of the degree to which a substance gets dissolved in a solvent to become a solution.
The solubility of KCl in water at 10°C is 31.2gm/100gm of water .
So in 300 gm of water 3 * 31.2 gm = 93.6 gm
Using Significant Figures we can select option B i.e. 90 gm.
Hence Option B , 90 grams of potassium chloride is needed to saturate exactly 300 grams of water at 10°C
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Barium chloride and sodium sulfate react according to the following equation. BaCl 2 + Na 2SO 4 → BaSO 4 + 2NaCl Answer the following question(s) about this reaction. How many grams of barium chloride are needed to make 100. grams of barium sulfate?
According to the stoichiometry and the given balanced chemical equation 89.22 g of barium chloride are needed to make 100 grams of barium sulfate.
What is stoichiometry?Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.
In the given chemical equation, 208.23 g of barium chloride produces 233.38 g of barium sulfate ,so for 100 g of barium sulfate 208.23×100/233.38 =89.22 g of barium chloride is required.
Thus, 89.22 g of barium chloride are needed to make 100 grams of barium sulfate.
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The rotational spectrum of 79BrºF shows a series of equidistant lines spaced 0-714 33 cm - apart. Calculate the rotational constant B, and hence the moment of inertia and bond length of the molecule. Determine the wavenumber of the J = 9+= 10 transition, and find which transition gives rise to the most intense spectral line at room temperature (say 300 K).
and calculate the number of revolutions per second which the Brf molecule undergoes when in (a) the J = 0 state, (b) the J = 1 state, and (c) the J = 10 state. Hint: Use E = {lwin conjunction with Eqs (2.10) and (2.13), but remember that here w is in radians per second.[its Q season 2 from fundamentals of molcular spectruscopy . banwell.c.n]
In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.
To calculate the rotational constant B, we can use the formula:
B = 1 / (2 * π * Δν)
Where:
B = rotational constant
Δν = spacing between consecutive lines in the rotational spectrum
Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:
B = 1 / (2 * π * 0.71433 cm^(-1))
B ≈ 0.079 cm^(-1)
The moment of inertia (I) of the molecule can be calculated using the formula:
I = h / (8 * π^2 * B)
Where:
h = Planck's constant
Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:
I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))
I ≈ 2.11 x 10^(-46) kg·m^2
The bond length (r) of the molecule can be determined using the formula:
r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)
Where:
μ = reduced mass of the molecule
r_e = equilibrium bond length
To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:
ν = 2 * B * (J + 1)
Substituting J = 9 into the formula, we get:
ν = 2 * 0.079 cm^(-1) * (9 + 1)
ν ≈ 1.58 cm^(-1)
To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:
I ∝ exp(-E / (k * T))
Where:
E = energy difference between the levels
k = Boltzmann constant
T = temperature in Kelvin
At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.
To calculate the number of revolutions per second, we can use the formula:
ω = 2 * π * B * J
Where:
ω = angular frequency (in radians per second)
J = rotational quantum number
For J = 0:
ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s
For J = 1:
ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s
For J = 10:
ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s
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A thermally insulated system consists of 1.00 mol of a diatomic gas at 148 K and 2.00 mol of a solid at 178 K that are separated by a rigid insulating wall. Find the equilibrium temperature of the system after the insulating wall is removed, assuming that the gas obeys the ideal-gas law and that the solid obeys the Dulong-Petit law. HINT: the gas does no work during the expansion, so Qgas = AEint = nc', AT. K Submit
169.2K is the equilibrium temperature of the system after the insulating wall is removed.
What is equilibrium?Generally speaking, a condition of equilibrium is one in which nothing is changing. A body in equilibrium won't undergo any energy exchanges, either positive or negative. Equilibrium is defined significantly differently in biology, physics, and chemistry.
Yet the underlying idea is the same. A body in balance will be least affected by outside influences. Even when external pressures are present, the opposing forces often have a balanced impact on the item under consideration.
for gas, n1=1mol
T1= 148K
for solid,n2=2mol
T2=178K
for conservation of energy, ΔQ= Qgas+ Qsolid=0
Q= CvΔT
0=Cvgas(Teql-148) + Cvsolid(Teq-178)
0= 5/2×1×R(Teql-148) + 3×2×R(Teq-178)
Tequi= 169.2K
Therefore, 169.2K is the equilibrium temperature of the system after the insulating wall is removed.
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7) How many molecules of CO2 are in 2.5 L at STP?
By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.
To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.
Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.
STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).
First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:
PV = nRT,
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Since we have STP conditions, we can substitute the values:
(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).
Simplifying the equation:
2.5 = n × 22.4149.
Solving for n (the number of moles):
n = 2.5 / 22.4149 ≈ 0.1116 moles.
Next, we can calculate the number of molecules using Avogadro's number:
Number of molecules = n × N_A.
Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).
Number of molecules ≈ 6.72 × 10^22 molecules.
Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.
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Balance the following equation and determine the coefficients in order
from left to right. Co + O2 - C0203
A 1,3,2
B 2,3,1
C 1,1,2
D 4, 3, 2
Answer:
D 4,3,2
Explanation:
4 Co + 3 O2 ----> 2 Co2O3
why are elements in the column with helium so stable ?
Answer:
Explanation:
because they have complete valence shell thats why they are not reactive towards chemical reaction and are quite stable
What characteristic should an isotope used for dating have?
O A. It should have a half-life much shorter than the age of the object
being dated.
B. It should have a half-life that is close to the age of the object being
dated.
O C. It should have a half-life that changes with time in the object being
dated.
O D. It should have a half-life much longer than the age of the object
being dated.
Answer:
B
Explanation:
took the test
D. It should have a half-life much longer than the age of the object being dated. When using isotopes for dating purposes, it is important to choose an isotope with a half-life that is significantly longer than the age of the object being dated.
What is the half-life time?The half-life is the time it takes for half of the radioactive isotopes in a sample to decay into stable isotopes. By measuring the ratio of the original radioactive isotope to the decay product, scientists can determine the age of the object.
The majority of the radioactive material would have decayed if the isotope had a half-life substantially less than the age of the artefact, making it challenging to precisely establish the age.
On the other hand, the dating procedure would become more challenging and unpredictable if the isotope in the object being dated (option C) has a half-life that varies over time.
As a result, an isotope with a long half-life offers a stronger basis for precise dating since it enables sufficient radioactive decay to take place, producing quantifiable and trustworthy data.
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A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass percent?
.
A soft drink contains 33g of sugar in 349g of H\(_2\)O. 14.3% is the concentration of sugar in the soft drink in mass percent.
One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.
In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.
Mass percent = (mass of solute/mass of solute+ mass of solvent)×100
= ( 33/ 33+ 349)×100
=14.3%
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PLEASE HURRY
50 POINTS !!!!
Select the correct compound.
Reactants undergo chemical reaction to form products.
This chemical equation represents one such reaction.
The coefficient for one of the reactants or products is incorrect.
Which part of the chemical equation is incorrect?
2C₂H₁0+ 100₂
8CO₂+ 10H₂O
The incorrect part of the chemical equation is the coefficient for the oxygen gas reactant.
The chemical equation you provided is incorrect in terms of the stoichiometric coefficients. The correct coefficients for the balanced equation should be:2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
Therefore, the incorrect part of the equation you provided is:2 C2H10 (should be C2H6) + 10 O2 → 8 CO2 + 10 H2O
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According to the Isela gas law, what happens to the volume of gas when the pressure doubled
According to the Ideal Gas Law, the volume of a gas is inversely proportional to its pressure, assuming the temperature and amount of gas remain constant. This is expressed by the following equation:
PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas in Kelvin.
If we keep the number of moles of gas, the temperature, and the gas constant (R) constant, and double the pressure (P), the volume (V) of the gas will be reduced to half its original value.
This relationship is known as Boyle's Law, which states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Therefore, if the pressure of a gas is doubled while everything else is held constant, the volume of the gas will be halved.
when we put ice into a beaker which filled with water why water has not dropped ?
Answer: Yo! hope this helps you dude
When ice is placed into a beaker filled with water, the water level does not drop because of the concept of displacement. When the ice is added, it displaces an amount of water equal to its own volume. This means that the ice takes up space in the beaker, pushing out an equal amount of water to make room for itself. Therefore, the total volume of water and ice in the beaker remains the same, and the water level does not drop.
This is due to the fact that the density of ice is lower than that of water and when the ice is placed into the water, it will float on the surface, pushing out an amount of water equal to its own volume.
Additionally, when the ice melts, it will release the same amount of water it displaced before and the water level will not change.
Explanation:
using quantum theories to study the hydrogen atom allows the prediction and experimental verification of many data about atoms such as he and li2 . some quantities that can successfully be predicted about he and li2 in this manner are ...
a. The color of the light will emit
b. Their mass
c. Their abundance in nature
d. All of the above
Answer:
c. Their abundance in nature
1. What do producers do, and what is another name for them?
Producers are the foundation of every food web in every ecosystem—they occupy what is called the first tropic level of the food web. The second trophic level consists of primary consumers—the herbivores, or animals that eat plants. At the top level are secondary consumers—the carnivores and omnivores who eat the primary consumers. Ultimately, decomposers break down dead organisms, returning vital nutrients to the soil, and restarting the cycle. Another name for producers is autotrophs, which means “self-nourishers.” There are two kinds of autotrophs. The most common are photoautotrophs—producers that carry out photosynthesis. Trees, grasses, and shrubs are the most important terrestrial photoautotrophs. In most aquatic ecosystems, including lakes and oceans, algae are the most important photoautotrophs.
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
The jumbled word "gzeysktqix" can be unscrambled to form the word "skyzigtext."
Here are possible words that can be made from this jumbled word:
Sky: Referring to the atmosphere above the Earth.
Zig: Describing a series of sharp turns or angles.
Text: Referring to written or printed words.
Six: The number following five and preceding seven.
It seems that the jumbled word has provided a mix of letters that can be rearranged to form these words. This exercise is likely intended to enhance the student's vocabulary skills, spelling ability, and problem-solving skills. By unscrambling the letters, the student is encouraged to explore different word possibilities and apply their knowledge of language. It also promotes critical thinking and creativity as they find valid words from the given set of letters.
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A nugget of gold occupies 5.64 mL of water and weighs 108.8521g. Its density is
The density of a nugget of gold which occupies 5.64 ml of water and weighs 108.85 g is 19.29 g/cm^3.
The density of a gold nugget can be calculated by using the following formula:
Density of nugget = Mass of gold nugget/Volume occupied by gold nugget
Here,
the mass of gold is given to be 108.85 grams and the volume occupied by gold is given to be 5.64 ml or 5.64 cm^3.
Putting these values in the above equation
Density = 108.85 g / 5.64 cm^3
Density = 19.29 g/cm^3
Thus, the density of a nugget of gold which occupies 5.64 ml of water and weighs 108.85 g is 19.29 g/cm^3.
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After the discovery of isotopes, scientists were able to conclude that?
O all atoms of a given element have the same mass but may have different numbers of protons
O all atoms of a given element have the same number of protons but may have different masses
Od
all atoms of a given element are identical
all atoms of a given element may have different masses and different numbers of protons
Answer:
all atoms of a given element have the same number of protons but may have different masses
Explanation:
After the discovery of isotopes, scientists were able to conclude that all atoms of a given element have the same number of protons but may have different masses.
Isotopes are atoms of an element that have the same atomic number but different mass number.
The atomic number is the number of protons within an atom.
Mass number is the number of protons and number of neutrons.
Therefore, all atoms of a given element have the same number of protons but different mass.
What is the term used to describe the scientific study of how living things are classified?
Answer:
Taxonomy
Explanation:
The term used to describe the scientific study of how living things are classified is known as taxonomy.
Taxonomy describes includes the nomenclature and classification of organisms based on several relationships between organisms.
Carl Linnaeus introduced the basis of modern classification system and this has been refined through the years.
Different relationships between organisms are used to classify them.
Please upload a document which answers each of the following questions Be sure that the answers are numbered and separated for each question 1. Air is an example of a simple mixture for which an average molecular weight may be calculated. Assuming that it consists solely of 20.00% 02and 80.00% N2 by weight, calculate Mn and Mw for air. Is either Mn or Mw greater? Briefly explain why. 2. Why does titrimetric end-group analysis become impractical for determining the M n of polymers whose average molecular weight exceeds 25,000? 3. Calculate the molarity of PMDA using the results of each standardization titration. Compute the molarity of PMDA from the mass of reagent used to make the PMDA stock solution. Compare these values and determine the percent purity of the solid reagent.
Since air is a simple mixture, Mn and Mw are equal that is 28.8g/mol.
Titrimetric end-group analysis becomes impractical As the molecular weight of the polymer increases, it becomes more difficult to measure the end-groups accurately and reproducibly, leading to increasingly large errors in the determination of M n.
The molecular weight of the polymer increases, it becomes more difficult to measure the end-groups accurately and reproducibly, leading to increasingly large errors in the determination of M n. Molarity (M) = (mass of PMDA) / (molar mass of PMDA x volume of PMDA stock solution in liters).
To calculate the average molecular weight (Mn) and the average molecular weight (Mw) for air, we need to determine the molecular weight of each component, O2 and N2, and then weight average them based on their respective concentrations.
The molecular weight of O2 is 32 g/mol and the molecular weight of N2 is 28 g/mol.
Mn = (0.20 x 32 g/mol) + (0.80 x 28 g/mol) = 6.4 g/mol + 22.4 g/mol = 28.8 g/mol
Since air is a simple mixture, Mn and Mw are equal.
Titrimetric end-group analysis becomes impractical for determining the M n of polymers whose average molecular weight exceeds 25,000 due to the limitations of the techniques used. As the molecular weight of the polymer increases, it becomes more difficult to measure the end-groups accurately and reproducibly, leading to increasingly large errors in the determination of M n.
To calculate the molarity of PMDA from the results of each standardization titration, we need the volume of PMDA used in the titration and the number of moles of the titrant used. The molarity can then be calculated using the formula:
Molarity (M) = (number of moles of titrant) / (volume of PMDA used in liters)
To calculate the molarity of PMDA from the mass of reagent used to make the PMDA stock solution, we need the mass of PMDA and the molar mass of PMDA. The molarity can then be calculated using the formula:
Molarity (M) = (mass of PMDA) / (molar mass of PMDA x volume of PMDA stock solution in liters)
The percent purity of the solid reagent can be determined by comparing the molarity calculated from the results of each standardization titration to the molarity calculated from the mass of reagent used to make the PMDA stock solution. If the molarity values are equal, the reagent is 100% pure. If the values are not equal, the percentage purity can be calculated as follows:
Percent purity = (molarity from standardization titration / molarity from mass of reagent) x 100%
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Determine the total kilojoules in two tablespoons
The total kilojoules in two tablespoons is 836.8 kJ.
To determine the total kilojoules in two tablespoons of a substance, we need to know the specific substance and its energy content per tablespoon. Different substances have different energy values, so without this information, it is not possible to provide an accurate calculation.
The energy content of food or substances is typically measured in kilocalories (kcal) or kilojoules (kJ). 1 kilocalorie is equal to 4.184 kilojoules. The energy content of a substance is often listed on food labels or in nutritional databases.
For example, if we have the energy content of a substance as 100 kilocalories (kcal) per tablespoon, we can convert it to kilojoules by multiplying it by 4.184:
100 kcal * 4.184 kJ/kcal = 418.4 kJ
So, if we have two tablespoons of this substance, the total energy would be:
418.4 kJ/tablespoon * 2 tablespoons = 836.8 kJ
It's important to note that the energy content of a substance can vary depending on its composition, density, and other factors. Therefore, it is always recommended to refer to reliable sources such as food labels, nutritional databases, or consult a qualified professional to obtain accurate information regarding the energy content of specific substances.
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If 0.652 M of KF has a volume of 723.4 mL. What mass of KF is in the solution.
Answer:
To determine the mass of KF in the solution, we can use the formula:
mass = molarity x volume x molar mass
First, we need to calculate the molar mass of KF:
KF = K + F
= 39.10 g/mol + 18.99 g/mol
= 58.09 g/mol
Now, we can plug in the values:
mass = 0.652 mol/L x 723.4 mL x 0.05809 g/mol
= 26.76 g
Therefore, there are 26.76 g of KF in the solution.
HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ
How do i determine the heat energy produced?First, we shall obtain the limiting reactant. Details below:
3H₂ + N₂ -> 2NH₃
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 gFrom the balanced equation above,
28 g of N₂ reacted with 6 g of H₂
Therefore,
2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂
We can see that only 0.43 g of H₂ is needed in the reaction.
Thus, the limiting reactant is N₂
Finally, we the amount of heat energy produced. Details below:
3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 gFrom the balanced equation above,
When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.
Therefore,
When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ
Thus the heat energy produced from the reaction is -6.61 KJ
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The 135-ohm potentiometer for controlling temperature in a refrigerator is likely to contain which of the following components?
a)
Rotating control shaft
b)
Sliding contact
c)
Transformer
d)
Resistive strip with terminals
The 135-ohm potentiometer for controlling temperature in a refrigerator is likely to contain which of the following components is sliding contact
Potentiometer is defined as the three terminal resistor having either sliding or rotating contact that forms an adjustable voltage divider and sliding contact is the electrical contact where current or signal flows through the contact and at the 135-ohm potentiometer for controlling temperature in a refrigerator is likely to contain sliding contact components
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The elementary steps for the catalyzed decomposition of dinitrogen monoxide are:
N2O (g) + NO (g) → N2 (g) + NO2 (g)
2 NO2 (g) → 2 NO (g) + O2 (g)
Which of the following statements are CORRECT?
1. The overall balanced reaction is 2 N2O (g) → 2 N2 (g) + O2 (g).
2. NO (g) is a catalyst for the reaction.
3. N2 (g) is a reaction intermediate.
4. NO2 (g) is a reaction intermediate.
A. 1, 2, and 4
B. 1, 2, and 3
C. 1 and 2
D. 1 only
E. 4 only
The correct option for the catalyzed decomposition for given dinitrogen monoxide are- A. 1, 2, and 4
Explain the formation of dinitrogen monoxide?Nitrous oxide, also referred to as laughing gas, nitrous, simply nos, is a chemical substance that has the formula N2O and is also known as dinitrogen oxide as well as dinitrogen monoxide.
It is a colorless, nonflammable gas that tastes and smells mildly sweet at normal temperature. It is used as a sedative during medical and dental operations to assist patients feel more at ease and to reduce their anxiety. The melting point of dinitrogen monoxide is -88.48 °C.The fundamental procedures for dinitrogen monoxide's catalyzed breakdown are:
N2O (g) + NO (g) → N2 (g) + NO2 (g)
2 NO2 (g) → 2 NO (g) + O2 (g)
Thus, the correct statements are-
1. The overall balanced reaction is 2 N2O (g) → 2 N2 (g) + O2 (g).
2. NO (g) is a catalyst for the reaction.
4. NO2 (g) is a reaction intermediate.
Therefore, A. 1, 2, and 4 is the correct option.
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on a piece of paper, write balanced molecular, total ionic, and net ionic equations for the reaction between aqueous solutions of sodium hydroxide and nitric acid. select the number that corresponds to the sum of the coefficient for the net ionic equation. [ select ]
Compose balanced molecule, gross ionic, as well as net ionic formulae for the interaction between sodium hydroxide plus nitric acid in aqueous solutions. The net ionic equation's coefficient sum is three.
What is the purpose of nitric acid?Ammonium nitrate, a crucial component of fertilizers, is created using nitric acid. Additionally, it is used to oxidize materials and to make explosives like trinitrotoluene (TNT) as well as nitroglycerin.
What occurs when nitric acid is touched?The liquid leads to severe burns when it comes in contact with your eyes, which could cause lifelong damage and vision loss. The liquefied or concentrated vapor causes immediate, severe, and profound burns on the skin, while acidic solution result in deep ulcers and leave a brilliant yellow stain.
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Predidt the direction and the relative value of the dipole moment of the following bond: C-Cl
A. C ← CL electronegativity difference < 0.5
B. C ← CL electronegativity difference > 0.5
C. C → Cl electronegativity difference < 0.5
D. C → Cl electronegativity difference > 0.5
Answer:
D. C → Cl electronegativity difference > 0.5
Explanation:
The electro negativity of an atom in a compound refers to its ability to attract the electrons of a bond towards itself.
On the Pauling's scale, carbon has an electro negativity value of 2.55 while that of chlorine is 3.16. The difference in electro negativity between the both atoms is about 0.61.
The dipole is aslways directed towards the more electronegative atom. Hence the direction is ; C → Cl