Predict how the cooling rate used to solidify a glass can affect atomic structure, density, and refractive index.

Answer:

D

Explanation:

These all can impact the magnetic properties

Answer:

The property of sugar which makes it different from sand is that sugar can dissolve in water. Explanation: however the power of dissolving of sand is not present. This is due to the presence of interaction between sugar and water.

Explanation:

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It will be very difficult to if you could travel back to the time when the Earth first formed as a planet.

When Earth first formed as a planet, the surface would be extremely hostile and inhospitable and life won't be possible. It was just molten volcanic land with no water or ocean.

Atmosphere and life were also not formed at that time. During the first period of time the temperature of Earth's atmosphere was extremely high and collisions were continuously happening between celestial bodies.

The heat produced in the atmosphere  thus was in a state of molten volcanic state. Just magma and lava. High temperature prevented the formation of oceans and thus life also.

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Answer:

Selenium dichloride

Explanation:

Selenium (Se) and Chlorine (Cl) are both elements capable of combining together to form a compound with the chemical formula; SeCl2. Since the chlorine atom is more electronegative than selenium atom, the chlorine pulls more electrons towards itself to form an IONIC bond.

The SeCl2 compound formed is called Selenium dichloride as two atoms of Chlorine are needed to combine with one atom of Selenium to form the compound.

The name of the molecular compound is selenium dichloride (SeCl2).  

• Due to sharing of electrons between selenium and chlorine, Selenium dichloride is considered as covalent compound.  

• Both the elements are non-metals, and thus, would give rise to covalent bond.  

• Selenium is the least electronegative element of the two, so it is written first.  

• After that the more electronegative element is written, and then addition of suffix is done, that is, -ide.  

• If atoms of an element is more than one, then prefixes are supplemented that is mono for 1 atom, di for two atoms, and tri for three atoms.  

Thus, the name of the molecular compound is selenium dichloride.

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The observational evidence that distinguishes halo stars from disk stars is their difference in motion, metallicity, and age.

Halo stars, found in the outer regions of a galaxy, move in highly elliptical orbits around the galactic center, while disk stars, located in the flat, disk-like structure of a galaxy, have more circular orbits. This difference in motion can be detected through the Doppler effect and proper motion measurements. Furthermore, halo stars have low metallicity, meaning they contain a smaller amount of elements heavier than helium compared to disk stars, which have higher metallicity. This difference in metallicity can be observed using spectroscopy.

Lastly, halo stars are typically older than disk stars, as they formed during the early stages of galaxy formation. This age difference can be determined through methods such as analyzing the stars' color-magnitude diagrams and the Hertzsprung-Russell diagram. In summary, the motion, metallicity, and age of halo stars serve as key observational evidence distinguishing them from disk stars.

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Astronomers would use the method of "spectroscopic parallax" to find the distance to a remote quasar.

Explanation:

Spectroscopic parallax is a technique used to determine the distance to a celestial object using its spectrum. In this method, astronomers analyze the spectrum of a quasar and compare it to the spectrum of a nearby star with a known luminosity. By comparing the two spectra, they can determine the quasar's luminosity, and then use that information to calculate its distance using the inverse square law. This method is particularly useful for distant objects, like quasars, which are too far away to be measured using traditional parallax methods.

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The final speed of the ball before it strikes the ground can be calculated using the equation of motion, considering that the initial velocity is 5 m/s, the initial height is 1.0 meter and acceleration due to gravity is 9.8 m/s^2. The equation of motion is given by:

v^2 = u^2 + 2as

where,

v = final velocity

u = initial velocity (5 m/s)

a = acceleration due to gravity (9.8 m/s^2)

s = height travelled (1.0 m)

Substituting the values, we get

v^2 = 5^2 + 2 * 9.8 * 1.0

v^2 = 25 + 19.6

v^2 = 44.6

v = sqrt(44.6)

So the final speed is v = 6.68 m/s

Hence, the final speed of the ball right before it strikes the ground is approximately 6.68 m/s.

Speed ​​is a derived quantity derived from the principal quantities of length and time, where the formula for speed is distance divided by time. Velocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second.

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The situations in which it is reasonable to ignore the presence of the transmission line in the solution of the circuit are (b) l=50 km, f=60 Hz and (d) l=1 mm, f=100GHz.

A transmission line of length l connects a load to a sinusoidal voltage source with an oscillation frequency f. Assuming the velocity of wave propagation on the line is c, it is reasonable to ignore the presence of the transmission line in the solution of the circuit if its length is much smaller than the wavelength of the signal.

The wavelength of a signal can be determined by the following formula: wavelength = velocity / frequency.

Therefore, we can determine the wavelength and compare it to the length of the transmission line. If the length of the transmission line is much smaller than the wavelength, then we can ignore its presence in the circuit.

(a) l=20 cm, f=20kHz: The wavelength of the signal is given by wavelength = velocity / frequency = 3 x 10^8 / (20 x 10^3) = 15 km. Since the length of the transmission line is much smaller than the wavelength, we cannot ignore its presence.

Hence, this situation is not reasonable to ignore the presence of the transmission line in the solution of the circuit.

(b) l=50 km, f=60 Hz: The wavelength of the signal is given by wavelength = velocity / frequency = 3 x 10^8 / 60 = 5 x 10^6 m. Since the length of the transmission line is much smaller than the wavelength, we can ignore its presence. Hence, this situation is reasonable to ignore the presence of the transmission line in the solution of the circuit.

(c) l=20 cm, f=600MHz: The wavelength of the signal is given by wavelength = velocity / frequency = 3 x 10^8 / (600 x 10^6) = 0.5 m. Since the length of the transmission line is much smaller than the wavelength, we cannot ignore its presence. Hence, this situation is not reasonable to ignore the presence of the transmission line in the solution of the circuit.

(d) l=1 mm, f=100GHz: The wavelength of the signal is given by wavelength = velocity / frequency = 3 x 10^8 / (100 x 10^9) = 0.003 m. Since the length of the transmission line is much smaller than the wavelength, we can ignore its presence. Hence, this situation is reasonable to ignore the presence of the transmission line in the solution of the circuit.

Therefore, the situations in which it is reasonable to ignore the presence of the transmission line in the solution of the circuit are (b) l=50 km, f=60 Hz and (d) l=1 mm, f=100GHz.

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Answer: Kinetic energy is the energy that an object possesses due to its motion and potential energy is the energy that an object possesses due to its position

Explanation:

Kinetic energy is the energy that a body or item has as a result of its motion.

Example: A ball that starts rolling down a hill has kinetic energy because of its motion.

Potential energy is known as the energy that an object has as a result of its position.

Example: A drawn bow can store energy because of its position.

Answer:

The solid separates and disperse uniformly throughout the solution.

Answer:

272.727mph(miles per hour)

Explanation:

Answer:

He should report his findings to a reputable science journal.

Answer: The system of unit which is most convenient for use is the MKS unit.

Explanation:

System of units is defined as the complete set of units which comprises of both the fundamental units and the derived units. The mass, length and time are considered to be the fundamental quantities and their units are called the fundamental units. The systems of unit which are in common use can be compared through their description below:

--> MKS system of unit: In this system of unit, the unit of length is in meter (m). The unit if mass is in kilogram (k). The unit of time is in seconds (s). Hence the name m.k.s system of unit.

--> CGS system of unit: In this system of unit, the unit of length is in centimeter (cm). The unit if mass is in grams (g). The unit of time is in seconds (s). Hence the name c.g.s. system of unit.

--> FPS system of unit: In this system of unit, the unit of length is in foot (Ft). The unit if mass is in pound (Lb). The unit of time is in seconds (s). Hence the name m.k.s system of unit.

The system of unit which is most CONVENIENT for use is the MKS unit. This is because of the introduction of the international system of units (S.I unit). This unit was endorsed by the International Standard Organisation (ISO) to form a logical and interconnected framework for all measurements in science and technology. The MKS system of unit was made the SI units enabling physical quantities to be represented by only one unit.

Answer:

3 m/s²

Explanation:

Initial Velocity, u = 18

Final velocity, v = 36

Time, t = 6 seconds

Acceleration is the change in velocity of a body with time. It obtained using the relation :

Acceleration = (v - u) / t

Acceleration = (36 - 18) / 6

Acceleration = 18 / 6

Acceleration = 3m/s²

Hence, acceleration of the skier is 3m/s²

The axial resistance of an axon is calculated using the formula R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. In this case, the axial resistance is 11.28 MΩ.

The resistance along the axon is calculated using the following formula:

R = ρL/A

where:

R is the resistance in ohms

ρ is the resistivity in ohms per meter

L is the length in meters

A is the cross-sectional area in meters squared

In this case, we have:

ρ = 1.6 x 107 Ω.m

L = 0.5 mm = 0.0005 m

A = πr² = π(5 x 10-6)² = 7.854 x 10-13 m²

Therefore, the resistance is:

R = ρL/A = (1.6 x 107 Ω.m)(0.0005 m) / (7.854 x 10-13 m²) = 11.28 MΩ

Therefore, the axial resistance of the axon is 11.28 MΩ.

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The magnitude of the acceleration of the 5kg crate is 11.69 m/s^2. This means that the crate is accelerating towards the south-east direction with a magnitude of 11.69 m/s^2 due to the net force acting on it.

To find the magnitude of the acceleration, we need to calculate the net force acting on the crate and then use Newton's second law of motion (F=ma) to solve for the acceleration.

First, we need to resolve the two forces into their horizontal and vertical components. The 60N force to the north has no horizontal component, so its vertical component is 60N. The 8N force to the west has no vertical component, so its horizontal component is 8N.

Next, we need to add the horizontal and vertical components of the forces separately to get the net force acting on the crate. The vertical component of the net force is the sum of the vertical components of the two forces, which is:

60N - 0 = 60N (upwards)

The horizontal component of the net force is the sum of the horizontal components of the two forces, which is:

0 - 8N = -8N (to the left)

So the net force acting on the crate has a magnitude of:

|Fnet| = sqrt((60N)^2 + (-8N)^2) = 60.8N

Now we can use Newton's second law of motion to solve for the acceleration:

Fnet = ma

a = Fnet/m = 60.8N/5kg = 11.69 m/s^2 (to the south-east)

The magnitude of the acceleration of the 5kg crate is 11.69 m/s^2. This means that the crate is accelerating towards the south-east direction with a magnitude of 11.69 m/s^2 due to the net force acting on it.

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The weight of a 1 in x 1 in steel bar if it were 27 in long would be 7.64 lbs.

Density of steel is approximately = 0.283 lbs/in³

Dimensions of steel bar is= 1 in x 1 in

Steel bar is 27 inches long

We have to calculate weight of steel bar

Formula used for calculation

Density = mass/volume

Weight = density x volume

We can get the volume of steel bar as

Volume of steel bar = length x breadth x height

Volume of steel bar = 1 x 1 x 27Volume of steel bar = 27 in³

Now, we will calculate the weight of the steel bar

Weight = density x volume

Weight = 0.283 x 27Weight = 7.641 lbs

So, the weight of a 1 in x 1 in steel bar if it were 27 in long would be 7.64 lbs.

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The given position equation of a particle is, s=102−23t+t2Here, t is in seconds.The first derivative of s is its velocity: v = ds/dt - 23 + 2tThe second derivative of s is the particle's acceleration:

The total distance traveled is the sum of all distance travelled in each interval of time: D = ∫|v|dt + ∫|v|dt + ... (From t 0 s to t = 17 s)From the graph of the velocity, the particle is moving to the left and toward the right side. The velocity-time graph is linear, which means that the acceleration is constant and uniform. Hence, the conclusion we can draw is that the particle is moving with uniform acceleration.  a = dv/dt = 2The given equations are: s=102−23t+t2v

=−23+2ta

=2Plot of s-t and v-t graphs:

Net displacement (Δs) during the interval of 17 seconds can be calculated as:Δs = s(17) - s(0)Δs 

= 102 - (2 × 3² / 2) - (23 × 3) + (17² / 2) - 102Δs 

= -4 mmThe particle moves to the left side.

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Answer:

Magnitude of A=5

Magnitude of B=5.39

Explanation:

The magnitude of Vectors in Rectangular Form

Given a vector v in its rectangular form:

\(\mathbf{v}=x\hat i+y\hat j\)

The magnitude of v is:

\(\mid\mid\mathbf{v}\mid \mid=\sqrt{x^2+y^2}\)

We are given the vectors

\(\mathbf{A}=4\hat i+3\hat j\)

\(\mathbf{B}=5\hat i-2\hat j\)

Their magnitudes are:

\(\mid\mid\mathbf{A}\mid \mid=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}\)

\(\mid\mid\mathbf{A}\mid \mid=5\)

\(\mid\mid\mathbf{B}\mid \mid=\sqrt{5^2+(-2)^2}=\sqrt{25+4}=\sqrt{29}\)

\(\mid\mid\mathbf{B}\mid \mid=\sqrt{29}=5.39\)

Answer:

1e , 2j , 3c , 4d , 5k , 6a , 7i , 8b , 9m , 10h ,11g , 12f , 13l .

If a reddish and a bluish star have the same luminosity, then the reddish star must be larger than the bluish star. This is again due to the Stefan-Boltzmann law; since the cooler, red star must have more surface area than a hot blue star to produce the same luminosity.

It is 1.93 metres away from the post.

for vertical motion

\(S= u t + \frac{1}{2} g t^{2}\)

S = 0 +  \(\frac{1}{2} g t^{2}\)

1.7 = \(\frac{1}{2} 9.8 t^{2}\)

t = 0.589 sec

using law of  conservation of momentum, on the horizontal motion

\(m_{bullet} \ v_{bullet i} = m_{bullet} \ v_{bullet f} + m_{tin} \ v_{tin}\)

\(0.0020 = 0.0020 \ 3 \ 720 + 0.11 \ v_{tin}\)

\(v_{tin}\) = 3.273 m/s

S = \(v_{tin} \ t\)

   = 3.273 m/s * 0.589 s

   = 1.93 m

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The existence of black holes does not provide direct evidence for the Big Bang theory. The other options all have a direct connection to the Big Bang theory.

It is a faint, uniform glow of microwave radiation that fills the entire universe. The CMB was first detected in 1964, and its discovery is considered one of the most important pieces of evidence in support of the Big Bang theory.

The CMB is thought to be the residual heat left over from the Big Bang itself.

The abundance of light elements, such as hydrogen and helium, in the universe is another important piece of evidence in support of the Big Bang theory.

According to the theory, the universe began as a hot, dense, and uniform state, and as it expanded and cooled, protons and neutrons began to combine to form the nuclei of atoms.

.

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The “sum of forces” acting on a cart can be explained as the net force or resultant force acting on it. This term refers to the total amount of force acting on an object, considering both the direction and magnitude. The cart's acceleration is influenced by this force, which is critical in the laws of physics.

The following is a description of the “sum of forces” acting on a cart: The sum of forces can be calculated using the formula F = ma, where F is the force acting on the cart, m is the mass of the cart, and a is the acceleration produced by the force. If there is more than one force acting on the cart, it is necessary to calculate the net force, which is the sum of all the forces acting on the cart.
The sum of forces can be split into two components: internal and external forces. Internal forces are those generated within the object, whereas external forces are exerted by other objects. The frictional force between the wheels of the cart and the surface is an example of an internal force acting on the cart.
The gravitational force exerted by the Earth is an example of an external force acting on the cart. If there are more than two forces acting on the cart, vector addition must be used to determine the net force.
The sum of forces acting on the cart is critical in the laws of physics. If the sum of forces acting on the cart is zero, it implies that there is no net force acting on it, and it is either stationary or moving at a constant velocity. If the sum of forces is nonzero, it implies that there is a net force acting on the cart, and it is either accelerating or decelerating.

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Answer:

Metals

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Answer:

The new force of attraction would be 36 units

Explanation:

Law of Universal Gravitation

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.  

This statement can be expressed with the formula:

\(\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}\)

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: \(6.67\cdot 10^{-11}~Nw*m^2/Kg^2\)

Now suppose two given objects attract with a force of F=16 units, thus:

\(\displaystyle G{\frac {m_{1}m_{2}}{r^{2}}}=16\)

And now the masses of both objects is tripled, i.e., m1'=3m1, m2'=3m2, and the distance between them is doubled, r'=2r. The new force is:

\(\displaystyle F'=G{\frac {3m_{1}3m_{2}}{(2r)^{2}}}\)

Operating:

\(\displaystyle F'=G{\frac {9m_{1}m_{2}}{4r^{2}}}\)

\(\displaystyle F'=\frac{9}{4}G{\frac {m_{1}m_{2}}{r^{2}}}\)

Substituting the value of the initial force:

\(\displaystyle F'=\frac{9}{4}\cdot 16\)

\(F'=36\ units\)

The new force of attraction would be 36 units

To determine the initial velocity of the vehicles after the collision, we need to find the momentum of each vehicle before the collision and the total momentum after the collision.

The momentum of the car before collision = mass x velocity

= 1.4 x 103 kg x 37.0 km/hr

= 52.18 x 103 km/hr

The momentum of the truck before collision = mass x velocity

= 2.0 x 10 kg x 35 km/hr

= 70.0 x 10 km/hr

Total momentum before collision = momentum of car + momentum of the truck

= 52.18 x 103 kgm/hr + 70.0 x 10 km/hr

= 52.25 x 103 km/hr

After the collision, the two vehicles lock together and form a combined mass of (1.4 x 103 kg) + (2.0 x 10 kg) = 3.4 x 103 kg

Initial velocity after collision = total momentum / combined mass = 52.25 x 103 kgm/hr / 3.4 x 103 kg = 15.37 km/hr

Therefore, the initial velocity of the vehicles after the collision is 15.37 km/hr.

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Answer:

C

Explanation:

the region marked melting

Explanation:

option C is correct answer.

the region marked as melting, where solid turn to liquid.

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