Answer:
At home, a water hammer may occur when a dishwasher, washing machine or toilet shuts off water flow. The result may be heard as a loud bang or repetitive banging since the shock wave travels back and forth in the plumbing system.
is electrical conductivity a physical property
Answer:
Yes
Explanation:
I doesn't change the substance or the chemical properties of the substance.
145 mL of 0.108 M HNO3 is needed to neutralize 237 mL of RbOH of what concentration?
What is not an example of fresh aquatic waters.
Oceans
Lakes
Swamps
Rivers
Answer:
oceans
Explanation:
Please help me! I am a bit stuck on this.
A gas has a volume of 50.0 mL at a temperature of 10.0 K and a pressure of 760. kPa. What will be the new volume when the temperature is changed to 20.0 K and the pressure is changed to 380. kPa?
To solve this problem using the gas laws, we need to use the Ideal Gas Law. This law states that the product of the pressure and the volume of a gas is proportional to the absolute temperature.
The equation of the Ideal Gas Law is the following:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\dfrac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2} } \end{gathered}$} }\)
Where:
P₁ = initial pressure = 760 kPaV₁ = initial volume = 50.0 mL = 0.050 LT₁ = initial temperature = 10.0 KP₂ = Final pressure = 380 kPaT₂ = final temperature = 20.0 KV₂ = Final volume = ?We clear for V₂:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{P_1V_1T_2}{P_2T_1 } } \end{gathered}$} }\)
Where:
P₁ = initial pressure V₁ = initial volumeT₁ = initial temperatureP₂ = Final pressureT₂ = final temperatureV₂ = Final volumeSubstituting the known values:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760\not{kPa}\times0.050 \ L\times20.0\not{k} }{ 380\not{kPa}\times10.0\not{k} } } \end{gathered}$} }\)
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2=\frac{760 \ L}{3800 } } \end{gathered}$} }\)
\(\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{V_2\approx0.2 \ Liters} \end{gathered}$} }}\)
When the temperature changes to 20.0 K and the pressure changes to 380 kPa, the new volume will be approximately 0.2 L (200.0 mL).9. A Toyota Prius hybrid gets 21 kilometers per liter in highway driving. What is
the mileage in miles per gallon. (Given 1km = 0.621mi and 1L = 0.264gal)
Answer:
...................................................................................
The mileage of the Toyota Prius hybrid in miles per gallon would be 49.39 miles/gallon.
What is a unit of measurement?A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.
As given in the problem a Toyota Prius hybrid gets 21 kilometers per liter in highway driving.
1 kilometers = 0.621 miles
21 kilometers = 21 × 0.621 miles
=13.04 miles
1 liter = 0.264 gallon
The mileage in miles per gallon = 13.04 miles / 0.264 gallon
= 49.39 miles/gallon
Thus, the mileage of the Toyota Prius hybrid in miles per gallon would be 49.39 miles/gallon.
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using the balanced equation below how many grams of lead(||) sulfate would be produced from the complete reaction of 23.6 g lead (|V) oxide
Answer:
59.8 g of PbSO₄.
Explanation:
The balanced equation for the reaction is given below:
Pb + PbO₂ + 2H₂SO₄ —> 2PbSO₄ + 2H₂O
Next, we shall determine the mass of PbO₂ that reacted and the mass of PbSO₄ produced from the balanced equation. This can be obtained as follow:
Molar mass of PbO₂ = 207 + (16×2)
= 207 + 32
= 239 g/mol
Mass of PbO₂ from the balanced equation = 1 × 239 = 239 g
Molar mass of PbSO₄ = 207 + 32 + (16×4)
= 207 + 32 + 64
= 303 g/mol
Mass of PbSO₄ from the balanced equation = 2 × 303 = 606 g
SUMMARY:
From the balanced equation above,
239 g of PbO₂ reacted to produce 606 g of PbSO₄.
Finally, we shall determine the mass of PbSO₄ that will be produced by the reaction of 23.6 g of PbO₂. This can be obtained as follow:
From the balanced equation above,
239 g of PbO₂ reacted to produce 606 g of PbSO₄.
Therefore, 23.6 g of PbO₂ will react to produce = (23.6 × 606) / 239 = 59.8 g of PbSO₄.
Thus, 59.8 g of PbSO₄ were obtained from the reaction.
A change in the number of neutrons in an atom will change an isotope. What will happen when the number of protons changes in an atom?
16. Which of the following is considered to be a vector?
A. Velocity
B. Temperature
C. Time
D. Mass
Answer:
Velocity
Explanation:
it is the rate of displacement over time in a SPECIFIED DIRECTION i.e it has both magnitude and direction
can someone help me pls
Answer:
I dont understand what the question means
Explanation:
Can someone help me with this pls 2. Which is the volume of 3.20 moles of O₂?7. Which is the volume of 100. of O₂?
2. Which is the volume of 3.20 moles of O₂?
We are told that at STP one mol of any gas occupies 22.4 L. We will use that relationship to find the volume occupied by 3.20 moles of O₂.
1 mol of O₂ = 22.4 L
volume of O₂ = 3.20 moles of O₂ * 22.4 L/(1 mol of O₂)
volume of O₂ = 71.7 L
Answer: 3.20 moles of O₂ occupies 71.7 L
7. Which is the volume of 100. g of O₂?
In this case we will use the same relationship, but we are given grams instead of moles. So first we have to convert the mass in grams into moles. To do that we use the molar mass of O₂.
atomic mass of O = 16.00 amu
molar mass of O₂ = 2 * 16.00
molar mass of O₂ = 32.00 g/mol
Once that we know that the mass of 1 mol of O₂ is 32.00 g, we can find the number of moles that we have in 100. g of it.
moles of O₂ = mass of O₂ /(molar mass of O₂)
moles of O₂ = 100. g/(32.00 g/mol)
moles of O₂ = 3.13 moles
Finally we can find the volume that 3.13 moles of O₂ occupies (remember that 1 mol of any gas occupies 22.4 L at STP).
volume of O₂ = 3.13 moles * 22.4 L/(1 mol)
volume of O₂ = 70.1 L
Answer: 100. g of O₂ occupies 70.1 L
Solid Snake is being chased up the communications tower. Solid Snake is 75 kg and is carrying 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, how much work was done against gravity?
a.
4.04 kJ
b.
109.15 kJ
c.
135.34 kJ
d.
5.01 kJ
Solid Snake (75 kg) carries 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, the work done against gravity is 135.34 kJ (c).
What is work?In physics, work is the energy transferred to or from an object via the application of force along a displacement.
In this problem, the force that does the work is the one that opposes the weight.
Step 1: Calculate the total weight of the system.Solid Snake is 75 kg and is carrying 18 kg of equipment. The total mass is:
m = 75 kg + 18 kg = 93 kg
We can calculate the weight using Newton's second law of motion.
F = m . g = 93 kg . 9.8 m/s² = 911.4 N
Step 2: Calculate the total displacement.Solid Snake climbs 27 flights of stairs, each 5.5 m in height.
27 . 5.5 m = 148.5 m
Step 3: Calculate the work done.We will use the definition of work.
w = F . s = (911.4 N) . (148.5 m) . (1 kJ/1000 J) = 135.34 kJ
Solid Snake (75 kg) carries 18 kg of equipment. If Solid Snake climbs 27 flights of stairs, each 5.5 m in height, the work done against gravity is 135.34 kJ (c).
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Reflect on the learning activities titled “Hypothesis”, “Variables and Hypothesis” and “Constructing a Hypothesis”. Describe some similarities and differences between a question that comes in response to an observation, and a scientific research question? Cite quotes from the readings to support your answer. Where do variables fit into this thinking? In other words, if you imagine a number line with observation questions at one end and scientific research questions at the other, what role do variables play anywhere along this continuum?
The learning activities titled "Hypothesis," "Variables and Hypothesis," and "Constructing a Hypothesis" all share certain similarities and differences. A question that arises in response to an observation is similar to a scientific research question in that both require some level of investigation to achieve an answer. However, scientific research questions are typically more specific and refined, with a defined methodology for obtaining data and verifying results.
The following quotes from the readings illustrate this distinction:"A scientific question is one that can be answered by using scientific investigation. In contrast, an observation question is one that comes in response to observing or experiencing something in the natural world" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."An important feature of a scientific question is that it should be answerable within a reasonable amount of time and with the resources available" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Research questions can be narrow or broad, depending on the scope of the research" (Constructing a Hypothesis).The concept of variables is crucial to both observation and scientific research questions, but they play different roles depending on where they fall on the continuum. Observation questions are usually less precise and may not require much consideration of variables. On the other hand, scientific research questions are likely to include a rigorous examination of variables and their potential effects."Variables are an essential part of a scientific experiment. They are the things that change in an experiment" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Variables are important because they can affect the outcome of the research" (Constructing a Hypothesis).In summary, observation questions and scientific research questions share some similarities, but the latter is more specific, has a defined methodology, and may require more consideration of variables.For such more question on Hypothesis
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The total number of atoms in 3.75 mol of ammonium nitrate, NH4NO3 , is
The total number of atoms in 3.75 mol of ammonium nitrate, NH4NO3, is equal to the Avogadro's number, which is 6.022 x 10^23, times the number of moles, which is 3.75 in this case.
Thus, the total number of atoms in 3.75 mol of ammonium nitrate is equal to 2.26 x 10^24 atoms.
This number can be further broken down into the number of atoms of each element present in the compound. Ammonium nitrate is composed of two elements, nitrogen (N) and hydrogen (H). For each mole of ammonium nitrate, there are 4 moles of hydrogen atoms and 2 moles of nitrogen atoms.
Therefore, in 3.75 moles of ammonium nitrate, there are 15 moles of hydrogen atoms and 7.5 moles of nitrogen atoms, which is equal to 9 x 10^24 hydrogen atoms and 4.05 x 10^24 nitrogen atoms.
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Identify and describe the three ways that mutations affect organisms?
Answer:
The ways that mutation can affect an organism include:
Changing the physical characteristics of the organism.
It can impact the way that the DNA is able to code the genetic information.
Also, mutation can lead to the death of an organism.
What is mutation?
Mutation simply means a change in the DNA sequence of an organism. It can result from DNA copying mistakes that were made during the cell division.
Mutation can affect an organism as it changes the phenotype of the organism. It can also impact the way that the DNA is able to code the genetic information and lead to the death of an organism.
A student diluted 10.0 milliliters (mL) of a 9.00 Molar (M) HCl solution in order to prepare a 0.50 M solution for his organic extraction analysis.What quantity of water, in mL, was added to make the 0.50M HCl solution?
A: 150
B: 160
C: 170
D: 180
The quantity of water in mL that was added to make the solution is 170 mL (option C)
How to determine the volume of the diluted solution Volume of stock solution (V₁) = 10 mL Molarity of stock solution (M₁) = 9 MMolarity of diluted solution (M₂) = 0.5 MVolume of diluted solution (V₂) =?M₁V₁ = M₂V₂
9 × 10 = 0.5 × V₂
90 = 0.5 × V₂
Divide both side by 0.5
V₂ = 90 / 0.5
V₂ = 180 mL
How to determine the volume of the water Volume of stock solution (V₁) = 10 mL Volume of diluted solution (V₂) = 180 mL Volume of water added =?Volume of water added = V₂ – V₁
Volume of water added = 180 – 10
Volume of water added = 170 mL
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what r variable's :) :) :) :) :)
Answer: an element, feature, or factor that is liable to vary or change.
"there are too many variables involved to make any meaningful predictions"
Explanation:
Answer:
A variable is any characteristics, number, or quantity that can be measured or counted.
Explanation:
Which option is an example of a physical property?
flammability
solubility
reactivity
toxicity
Answer:
Solubility
Explanation:
Answer:
(B) Solubility
Explanation:
Using Boyle's Law solve the following: An unknown gas has a volume of 200.0 mL and a pressure of 350.0 torr, pressure were increased to 700.0 torr, what is the resulting volume?
Answer:
400 mL
Explanation:
Boyle's Law: \(P_1*V_1 = P_2*V_2\)
Let x = the resulting volume
350 (200) = 700 (x)
x = 400 mL
A piece of notebook paper
a Element
b. Compound
c. Solution
d Heterogenous Mixture
Zeros between nonzero digits are significant
Answer:
Explanation:
If a zero is found between significant digits, it is significant
Termine whether or not the question balls bounce rivet balance right the balanced force also identify the reactants and products as equation finally label it as one of the five types of reactions accommodation decomposition substation double replacement reversible
Answer:
i dont know :( but i bet someone else does
Oxidation can be defined as which of the following?b.)a gain of electronsa.)a loss of electrons
So, rememeber that:
Oxidation is the loss of electrons. Reduction is the gain of electrons. Oxidation and reduction always occur together, even though they can be written as separate chemical equations.
To explain this concept, let me upload the image below:
Therefore, oxidation can be defined as the loss of electrons.
The specific heat of a certain type of cooking oil is 0.418 cal/(g·°C). How much heat energy is needed to raise the temperature of 1.227 kg of this oil from 23.0 °C to 60.0 °C?
The quantity of heat energy needed to raise the temperature of 1.227 kg of oil from 23.0 °C to 60.0 °C is 18.98 calories.
How to calculate heat energy?The amount of heat energy absorbed or released by an object can be calculated using the following formula:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = mass of substancec = specific heat capacity∆T = change in temperatureQ = 1.227 × 0.418 × (60°C - 23°C)
Q = 18.98 calories
Therefore, the quantity of heat energy needed to raise the temperature of 1.227 kg of oil from 23.0 °C to 60.0 °C is 18.98 calories.
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In Thomas Cole's The oxbow who is the one figure depicted in the landscape and what is he doing
Answer:
In Thomas Cole's painting "The Oxbow," Thomas Cole, the artist, shows himself sitting in the landscape while painting it.
Explanation:
In the painting called "The Oxbow" by Thomas Cole, the artist actually put himself in the picture. He's sitting right in the middle of the landscape, just like he placed himself in the painting, as if taking a selfie while working on it. It's like he took a snapshot of himself while he was working on the painting. This shows how much he cared about creating the artwork and how he felt a personal connection to the beautiful scenery. It's really fascinating because it gives us a glimpse into how he saw himself as an artist and how he wanted to capture the incredible beauty of nature through his art.
calculate the molecular dormula
Explanation:
what is your Question plese
Given the reaction: Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
The reaction occurs more rapidly when a 10-gram sample of Mg is powdered rather than in one piece, because powdered
Mg has
1. less surface area
2. more surface area
3. a lower potential energy
4. a higher potential energy
Can you look at the picture Look at the picture ASAP and help please?
Answer:
Volume of the reaction vessel is increased - shift to the left
The reaction is cooled down - shift to the right
H2 is added to the system - shift to the right
The pressure of the system is decreased - shift to the left
A catalyst is added to the system - no change
Water is removed from the system - shift to the right
Explanation:
When a constraint such as a change in temperature, pressure or volume is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.
When the volume of a reaction system is increased, the equilibrium position shifts in the direction in which there is the highest total volume. This is the left hand side.
Since the reaction is exothermic (heat is given out) when the reaction is cooled down, the forward reaction is favoured.
Adding of reactants shifts the equilibrium position to the right hand side hence when H2 is added, the equilibrium position shifts to the right.
Decreasing the pressure shifts the equilibrium position to the direction of higher total volume hence the equilibrium shifts to the left when pressure is decreased.
A catalyst has no effect on the equilibrium position. It increases the rate of forward and reverse reaction to the same extent hence the equilibrium position is unaffected.
Removal of water from the system increases the rate of forward reaction since a product is being removed from the reaction system.
Consider the reaction: CO (g) + 2 H2 (g) ⇌ CH3OH (g) where the Kp is 2.26 x 10^4 at 25°C. Calculate ΔGrxn for the reaction at 25°C when PCH3OH = 1.0 atm; PCO = PH2 = 0.010 atm
The standard reaction Gibbs free energy (ΔGrxn°) using the given partial pressures is -60,200 J/mol.
What is energy?Energy is the ability to do work, whether it be in the form of heat, light, electrical, chemical, nuclear, or mechanical energy. It is the capacity to move, change, or transform matter, and is essential for all processes of life.
ΔGrxn = -RT ln Kp
Where R is the universal gas constant (8.314 J/mol K) and T is the temperature (25°C).
Therefore, ΔGrxn = -(8.314)(298) ln (2.26 x 10⁴)
= -20,067 J/mol
Now we need to calculate the standard reaction Gibbs free energy (ΔGrxn°) using the given partial pressures:
ΔGrxn° = ∑nΔGrxn°products - ∑nΔGrxn°reactants
ΔGrxn°products = -RT ln (PCH₃OH)
= -(8.314)(298) ln (1.0)
= 0 J/mol
ΔGrxn°reactants = -RT ln (PCO) - 2(RT ln (PH2))
= -(8.314)(298) ln (0.010) - 2(8.314)(298) ln (0.010)
= -60,200 J/mol
Therefore, ΔGrxn° = ∑nΔGrxn°products - ∑nΔGrxn°reactants
= 0 - (-60,200)
= -60,200 J/mol
Finally, ΔGrxn = ΔGrxn° + RT ln Q
= -60,200 + (8.314)(298) ln (1.0)
= -60,200 J/mol.
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Which equation shows an increase in entropy?
Hint: Look at the states of matter, g s l, of the chemicals in each equation. A C2H4(g) + H2(g) + C2H6(g) в Caco3(9) + Cao(s) - CO2(g) c Fe(s) + S (s) -+ FeS (s)
The equation C2H4(g) + H2(g) + C2H6(g) → Caco3(s) + Cao(s) + CO2(g) shows an increase in entropy due to the formation of a gas as a product. Option A
In this equation, the reactants on the left-hand side consist of gases (C2H4 and H2), while the products on the right-hand side include a solid (Caco3) and a gas (CO2).
When a reaction involves a change from gaseous to solid or liquid states, there is typically a decrease in entropy because the particles become more ordered and constrained in the solid or liquid phase.
Conversely, when a reaction involves the formation of gases, there is generally an increase in entropy because gases have higher degrees of molecular motion and greater freedom of movement compared to solids or liquids.
In the given equation, the reactants include three gaseous compounds (C2H4, H2, and C2H6), and one of the products is a gas (CO2). Therefore, the overall entropy of the system increases during this reaction.
The equation Fe(s) + S(s) → FeS(s) does not show an increase in entropy. Both the reactants (Fe and S) and the product (FeS) are solids. Since solids have lower entropy compared to gases or liquids, the entropy of the system does not increase in this reaction. Option A
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