PLZ HELP WILL GIVE BRAINLIEST!!!!!!! Write each repeating decimal using bar notation.
. 0.9222….

It is not necessary to tabulate Φ(z) for negative z-values since we can always use the symmetry property to find the corresponding area for positive z-values. This property holds because the standard normal curve is symmetric around its mean of 0.

a. To compute P(-1.72 ≤ Z ≤ -0.55) when Appendix Table A.3 only contains Φ(z) for z ≥ 0, you can use the property of symmetry of the standard normal curve. Since the curve is symmetric around z = 0, Φ(-z) = 1 - Φ(z). So, you can find the values for positive z and use the symmetry property:
P(-1.72 ≤ Z ≤ -0.55) = Φ(-0.55) - Φ(-1.72) = (1 - Φ(0.55)) - (1 - Φ(1.72)) = Φ(1.72) - Φ(0.55)
b. To compute P(-1.72 ≤ Z ≤ 0.55), you can break it into two parts: P(-1.72 ≤ Z ≤ 0) and P(0 ≤ Z ≤ 0.55). Then, use the symmetry property for the negative part:
P(-1.72 ≤ Z ≤ 0.55) = P(-1.72 ≤ Z ≤ 0) + P(0 ≤ Z ≤ 0.55) = Φ(0) - Φ(-1.72) + Φ(0.55) - Φ(0) = Φ(1.72) + Φ(0.55)
It is not necessary to tabulate Φ(z) for z negative because the standard normal curve is symmetric around z = 0, and we can use the property Φ(-z) = 1 - Φ(z) to find probabilities for negative z values. This property allows us to calculate probabilities for negative z values without needing a separate table for them.

If Appendix Table A.3 only contained Φ(z) for z ≥0, we could still compute P( –1.72≤ Z ≤–.55) and P( –1.72≤ Z ≤ .55) by using the symmetry property of the standard normal curve. This property states that the area under the curve to the left of a negative z-score is the same as the area to the right of the corresponding positive z-score.
To apply this property, we would first find the z-scores for the given ranges by using the formula z = (x – μ)/σ, where μ and σ are the mean and standard deviation of the standard normal distribution, respectively. For P( –1.72≤ Z ≤–.55), the negative z-scores would correspond to positive x-values, so we would need to use the symmetry property to find the corresponding area for positive z-scores. Specifically, we would find P( .55 ≤ Z ≤ 1.72) using the table, and then subtract this from 1 to get P( –1.72≤ Z ≤–.55).

Similarly, for P( –1.72≤ Z ≤ .55), the negative z-score would correspond to negative x-values, so we would use the symmetry property to find the area for positive z-scores from 0 to .55, and then double this to account for the area to the left of 0.
It is not necessary to tabulate Φ(z) for negative z-values since we can always use the symmetry property to find the corresponding area for positive z-values. This property holds because the standard normal curve is symmetric around its mean of 0, meaning that the area to the left of any negative z-score is the same as the area to the right of the corresponding positive z-score.

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Yes , the integer k is divisible by 4 and statement (1) alone is sufficient to determine that k is divisible by 4.

Given data ,

Let the equation be represented as A

Now , the value of A is

a)

To determine if the integer k is divisible by 4, let's analyze the given statements:

Statement (1): 8k is divisible by 16.

This means that 8k is a multiple of 16. Since 16 is divisible by 4, we can conclude that k must be divisible by 4 as well. Therefore, statement (1) alone is sufficient to determine that k is divisible by 4.

8k = 16

k = 2

b)

This statement does not provide direct information about the divisibility of k by 4. While 12 is divisible by 4, the fact that 9k is divisible by 12 does not guarantee that k itself is divisible by 4.

9k = 12

k = 12/9

k = 4/3

So , it is not an integer

In conclusion, statement (1) alone is sufficient to determine that k is divisible by 4. Statement (2) is not sufficient on its own.

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The solution of the system of equations is \(\[x=3,\text{ }y=0,\text{ and }z=2\]\).

As per data the system of linear equations,

\(\[ \left\{\begin{array}{c} x+2 y+3 z=9 \\ 2 x-y+z=8 \\ 3 x-z=3 \end{array}\right. \] 1)\)

Write the system in the matrix form \(\( A . X=B \)\)

We know that the matrix form of the system of linear equations is as follows.

\(\[A. X = B\]\)

Where

\(\[A=\begin{pmatrix} 1 & 2 & 3 \\ 2 & -1 & 1 \\ 3 & 0 & -1 \end{pmatrix}\[X=\begin{pmatrix} x \\ y \\ z \end{pmatrix}\]\)

and

\(\[B=\begin{pmatrix} 9 \\ 8 \\ 3 \end{pmatrix}\]2)\)

To solve the system, we can use row reduction method.

\(\[\begin{pmatrix} 1 & 2 & 3 & 9 \\ 2 & -1 & 1 & 8 \\ 3 & 0 & -1 & 3 \end{pmatrix}\]\)

Applying the elementary row operations

\(\[R_{2}\to R_{2}-2R_{1}\]\)

and

\(\[R_{3}\to R_{3}-3R_{1}\]\)

we get,

\(\[\begin{pmatrix} 1 & 2 & 3 & 9 \\ 0 & -5 & -5 & -10 \\ 0 & -6 & -10 & -24 \end{pmatrix}\]\)

Now applying the elementary row operations

\(\[R_{3}\to R_{3}-(6/5)R_{2}\]\)

we get,

\(\[\begin{pmatrix} 1 & 2 & 3 & 9 \\ 0 & -5 & -5 & -10 \\ 0 & 0 & -1 & -2 \end{pmatrix}\]\)

Now, we need to apply back substitution method. Using the third row, we can get the value of z as z = 2.

Now, using the second row,

\(\[-5y - 5z = -10\]\\\-5y - 5(2) = -10\]\)

Solving this equation, we get y = 0.

Finally, using the first row, we can get the value of x as

\(\[x + 2y + 3z = 9\]\\x = 3\]\)

Hence, the solution of the system of equations is \(\[x=3,\text{ }y=0,\text{ and }z=2\]\).

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The values that represent the possible distance, d, in miles, between Lincoln, NE, and the third city are given as follows:

300 < d < 699.

A set of measurements can represent a triangle if the sum of the two smaller measurements is greater than the greater measures.

The measurements for this problem are given as follows:

Then if 500 miles is the largest distance, we have that:

x can be between 300 and 500.

If x is the largest distance, we have that:

x can be between 501 and 699.

Then the range of possible distances is given as follows:

300 < d < 699.

(which are the distances for each case).

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Answer:

see picture

Step-by-step explanation:

Answer:

there are 40% black ball a

white ball we don't know

so, we let = x

40\100 × x

now we cutting

ans is 10x

Answer:

A and B are correct

Step-by-step explanation:

A)

Regular price=$24.30

Markdown=15%

Markdown Price=$24.30 * 15%

Markdown price=$3.645

Sale Price=$24.30-$3.645

Sale Price=$20.66

B)

Regular price=$66.50

Markdown=15%

Markdown price=$66.50 * 15%

Markdown price=$9.975

Sale Price=$66.50-$9.975

Sale Price=$56.53

If you need to ask any question, please let me know.

Sorry for bad handwriting

if i was helpful Brainliests my answer ^_^

0.0001660749

29÷0174620= 0.0001660749

hope this helped you- have a good day bro cya)

Answer:166.0749055091055

Answer:

look below

Step-by-step explanation:

first distribute 3/4 into (x-8)= 3/4x-6

3/4x-6=12

then add 6 to both sides to get rid of -6

3/4x=18

Now multiply 4 times 18 to get rid of division (72)

now you are left with 3x=72, so you now divide by 3 and you get x=24

Answer:

The correct answer is C

Answer:

false

Step-by-step explanation:

To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:

ρ(r) = ρ₀(1 - r/R) for r ≤ R,

ρ(r) = 0 for r > R,

where ρ₀ = 3Q/πR³.

To find the total charge, we integrate ρ(r) over the volume:

Q = ∫ρ(r) dV,

where dV represents the volume element.

Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.

The integral becomes:

Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.

Evaluating this integral gives:

Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.

Simplifying further, we get:

Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].

Simplifying the expression inside the parentheses:

Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].

Simplifying once more:

Q = ρ₀ * π * (R³ - R³/3),

Q = ρ₀ * π * (2R³/3),

Q = (3Q/πR³) * π * (2R³/3),

Q = 2Q.

Therefore, the total charge contained in the charge distribution is Q.

To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.

By Gauss's law, the electric field through a closed surface is given by:

∮E · dA = (1/ε₀) * Qenc,

where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.

Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.

For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q,

Simplifying:

E = Q / (4πε₀r²).

This is the same expression as the electric field created by a point charge Q at the origin (r = 0).

To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.

The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.

By Gauss's law, we have:

∮E · dA = (1/ε₀) * Qenc.

Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².

Plugging these values into Gauss's law:

E * 4πr² = (1/ε₀) * Q.

Simplifying:

E = Q / (4πε₀r²).

This expression represents the electric field inside the charge distribution for r ≤ R.

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Check the picture below.

so from the provided information, we can say that the parabola has a vertex at (3 , 45) and it has a zero at (6 , 0) or we can say is just another point at (6 , 0)

\(~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{a~is~negative}{op ens~\cap}\qquad \stackrel{a~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\)

\(\begin{cases} h=3\\ k=45\\ \end{cases}\implies y=a(~~x-3~~)^2 + 45\hspace{4em}\textit{we also know that} \begin{cases} x=6\\ y=0 \end{cases} \\\\\\ 0=a(6-3)^2+45\implies -45=9a\implies \cfrac{-45}{9}=a\implies -5=a \\\\\\ ~\hfill {\Large \begin{array}{llll} y=-5(x-3)^2 + 45 \end{array}} ~\hfill\)

As given by the question,

There are given that the equation:

Now,

First, suppose any number, for which the given equation has satisfied.

So, the number is, x = 2 and y = 6

Then,

Put both values into the given equation

Then,

Put the same value of x and y into the given option and check whether it is satisfied:

So,

From option 3:

Hence, the correct option is 3.

The upper control limit (UCL) with three-sigma limits for the mean of software upgrade time in minutes can be determined by multiplying the standard deviation by three and adding it to the mean. However, since the mean and standard deviation are not provided in the question, a specific numerical answer cannot be given.

In statistical process control, the three-sigma control limits are commonly used to establish the range within which a process is considered to be in control. The three-sigma limits represent a statistical measure that encompasses approximately 99.7% of the data if the process is stable and normally distributed.

By calculating the UCL using the mean and standard deviation, organizations can set an upper boundary that helps monitor the software upgrade time. If any data point exceeds the UCL, it suggests a potential variation or issue in the process, warranting further investigation and corrective actions to ensure the software upgrade time remains within acceptable limits. The UCL serves as a reference point for identifying significant deviations from the expected mean and facilitates continuous process improvement in software upgrade operations.

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Answer:

The answer is "31.888".

Step-by-step explanation:

If their respective angles become congruent or the side lengths get a constant relation, they realize that two quadrilaterals are similar

EFGH is similar to IJKL  because of quadrilateral

\(\to \frac{FG}{JK} =\frac{GH}{KL}=\frac{HI}{LM}=\frac{FI}{JM}\\\\\to \frac{GH}{KL} =\frac{HI}{LM}\\\\\to \frac{7}{KL}= \frac{9}{41}\\\\\to KL=\frac{7 \times 41}{9}=31.888\)

Answer:

correct do

Step-by-step explanation:

Answer: X=50

Step-by-step explanation:

Data: 4 less than half of a number(x) is 21

Step one, make an equation

(x/2)-4=21

The reason for this is that since we know that 21 is 4 less than half the number(x) we can assume that dividing x by 2 will get half of it and by subtracting 4, we can get 21 which why it equals 21. By having it in an equation, it makes it easier to solve.

Step two, Start isolating x by adding 4 on both sides

(x/2)-4+4=21+4=(x/2)=25

The reason for this is that we have to find what x is which is done by isolating it. So if you add 4, you get rid of the -4 which helps isolate x and what you do to one side, you do to the other so you add 4 to 21 as well

Step three, multiply by 2 on both sides

(x/2)x2=25x2=X=50

The reason for this is that /2 is next to x so to isolate you have to get rid of it by multiplying by 2 and since what you do to one side you do to the other, you multiply 25 by 2 to get 50.

Answer: X=50

I hope this helps!

The frequency of mice that are heterozygote is 0.3492

It is required to find the frequency.

The number of waves that pass a fixed point in unit time being, measured in hertz(Hz).The number of cycles or vibrations undergone during one unit of time by a body in periodic motion.

Given:

Population =200 mice

Gray fur mice= 120 mice

By the use of Hardy-Weinberg equation we have,

Hardy-Weinberg equation is given by

p² + 2pq + q² = 1 and p + q = 1

where, 2pq is the heterozygote frequency.

p² = 120/200

p = 0.7746

p + q = 1

q = 0.2254

Heterozygote frequency = 2pq = 2(0.2254)(0.7746) = 0.3492

Therefore, the frequency of mice that are heterozygote is 0.3492.

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Step-by-step explanation:

the answer is 2.50+1.50+733=737

Answer:

Im pretty sure it is c

Step-by-step explanation:

it gives us 2 angles add up to 180, but they are right next to each other. So we cant determine parallel lines.

Can i have brainliest now? im trying to work up the ranks

Answer:

8th grader

Step-by-step explanation:

They walked the the fastest since they walked 50 feet more than the 6th grader in 5 more seconds ( im sorry if you dont understand! i tried my best explaining it! hope this helps :) )

The value of the middle of the three is 25.

Let x be the first odd integer, then the next two consecutive odd integers are x+2 and x+4. The sum of these three consecutive odd integers is given as 75, so we can write the equation:

x + (x+2) + (x+4) = 75

Simplifying the left side of this equation gives:

3x + 6 = 75

Subtracting 6 from both sides gives:

3x = 69

Dividing by 3 gives:

x = 23

So the first odd integer is 23, and the next two consecutive odd integers are 25 and 27. The middle of these three is the second consecutive odd integer, which is 25. Therefore, the value of the middle of the three is 25.

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Step-by-step explanation:

(2³ × 2¹)²

(2⁶ × 2²)

for indices , × become +, plus

÷ become -, minus

so

2⁶+²

2⁸

The company survey 307 customers in order to get 98% confidence.

Sample proportion (p) = 0.5 (as no estimate is given)

α = 1 - 92% = 0.08.    Therefore, α/2 = 0.08/2 = 0.04

Z(α/2) = Z(0.04) = 1.751

Estimate = 5% = 0.05

Now, E = Z(α/2) * sqrt (p(1-p)/n)

n = (1.751/0.05)2 * 0.5 * (1-0.5)

n = 307

Hence, the company should survey 307 customers in order to be 98% confident that the estimated (sample) proportion is within 2 percentage points of the true population proportion of customers who are over the age of forty.

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Answer:

Step-by-step explanation:

\(f(x) = 2^{x}\)

translate 3 units up will change the y coordinate so will add 3 to y or f(x)

\(f(x) = 2^{x} +3\)

translate 4 units to the left will change the x coordinates so will add 4 to the x to move towards left

\(f(x) = 2^{x+4} +3\)

Based on the information provided in the histogram, the percent of students that type less than 30 words per minute is 30%.

A histogram is used to represent data graphically. The histogram is made up of rectangles whose area is equal to the number of students and whose width is equal to the words per minute.

Percentage of students who type less than 30 words per minute = (number of students that type less than 30 words per minute) / total number of students) x 100

[(10 + 5) / 50] x 100 = 30%

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Answer:

D. 115

Step-by-step explanation:

because if Angle 6 is 115 then so is Angle is 4 due to AIA (alternate Interior Angles)