Plz help this one is the last one of the day plz help

The first quartile of the data set represented by the box plot is 12.

The median of the data set is 16.

We have,

The box plot is drawn using five summary statistics: minimum, maximum, median, and the first and third quartiles.

The box in the plot represents the middle 50% of the data, with the lower end of the box representing the first quartile (Q1) and the upper end representing the third quartile (Q3).

The median is shown as a line inside the box.

From the box plot,

Median = 16

First quartile = 12

Third quartile = 19

Lowest value = 9

Largest value = 24

Thus,

The first quartile of the data set represented by the box plot is 12

The median of the data set is 16.

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There is no point of diminishing returns for the sales function S(x) = 204 + 6.3x - 0.25x² in the interval 0 ≤ x ≤ 12.

1.To determine the intervals where the function f(x) = √(2x + 3) is concave up or concave down, we need to find its second derivative and analyze its sign:
Step 1: Find the first derivative, f'(x):
f'(x) = (1/2)(2x + 3)^(-1/2) * (2)
Step 2: Find the second derivative, f''(x):
f''(x) = (1/4)(-1/2)(2x + 3)^(-3/2) * (2)
Step 3: Determine where f''(x) is positive (concave up) or negative (concave down):
Since the second derivative contains a negative sign, it is always negative, so the function is concave down on its entire domain.
The function f(x) = √(2x + 3) is concave down on its entire domain.
2. To find the point of diminishing returns for the sales function S(x) = 204 + 6.3x - 0.25x², we need to find its inflection point, where the second derivative changes sign:
Step 1: Find the first derivative, S'(x):
S'(x) = 6.3 - 0.5x
Step 2: Find the second derivative, S''(x):
S''(x) = -0.5
Step 3: Determine the inflection point:
Since the second derivative is constant and negative, it never changes sign, meaning there is no point of diminishing returns in the given interval.
There is no point of diminishing returns for the sales function S(x) = 204 + 6.3x - 0.25x² in the interval 0 ≤ x ≤ 12.

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Answer:

Yes it is

Step-by-step explanation:

Answer:

Clockwise

Step-by-step explanation:

Answer:

Step-by-step explanation:

No, this is not correct.

Step 1: Find the directional distance from every vertex on the blue image to  the center, Point C.

Point A is 1 unit left and 4 units upwards to Point C.

Point B is 4 units right and 5 units upwards to Point C.

Point C is the center of the dilation, so that point will not change.

Step 2: Apply the scale factor to the directional distances to know the distances of the new images.

The scale factor is 2 so

Point A' should be 2 units left and 8 units upwards to Point C.

Point B' should 8 units right and 10 units upwards to Point C.

Step 3:  Move the point in respect to Point C.

The new image should have the these points.

One point that is 2 units left and 8 units upwards to Point C.

Another point that is Point B' should 8 units right and 10 units upwards to Point C.

One point that coincides  with  Point C.

The random selection of a sample to represent the proportions of a population divided by sex and size of school attended is called stratified random sampling.

Stratified random sampling is a sampling method used when a population is divided into subgroups or strata based on certain characteristics, such as sex and size of school attended. In this method, a random sample is taken from each subgroup proportionate to its size in the population. This ensures that each subgroup is represented in the sample and reduces the chance of sampling bias.

For example, if the population of high school seniors is divided into two strata based on sex and two strata based on size of school attended, there would be four subgroups. A random sample would then be taken from each subgroup to create a representative sample of the entire population.

Stratified random sampling is commonly used in research studies and surveys to ensure that the sample accurately represents the population being studied. It allows for more precise estimates and statistical inferences to be made about the population as a whole.

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At 2.57 hours distance between them is 35 miles

(2t)2 + (2.5(t - 2))2 = 302

4t2 + (2.5t - 5)2 = 900

4t2 + 6.25t2 - 25t + 25 = 900

2.25t2 - 25t - 875 = 0

Let t (hours) be the amount of time Elsie needs to travel in order to reach a distance of 35 miles. Steve travels t + 2 miles to the north in the time it takes him since he is 2 hours early.

Solve for t, then add to 7:00 for your time.

which will give you 2.57 hours.

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The correct question will be

Steve and Elsie are camping in the desert, but have decided to part ways. Steve heads north, at 7 AM, and walks steadily at 3 miles per hour. Elsie sleeps in and starts walking west at 2.5 miles per hour starting at 9 AM.

When will the distance between them be 35 miles?

The inverse function over the domain is f⁻¹(x)  = √[(x + 1)/3]

The domain and the range are x ≥ -1 and y ≥ 0

The graph of f(x) = 3x² - 1 and f⁻¹(x)  = √[(x + 1)/3] is added as an attachment

From the question, we have the following parameters that can be used in our computation:

f(x) = 3x² - 1

So, we have

y = 3x² - 1

Swap x and y

x = 3y² - 1

Next, we have

3y² = x + 1

This gives

y² = (x + 1)/3

So, we have

y = √[(x + 1)/3]

This means that the inverse function is f⁻¹(x)  = √[(x + 1)/3]

For the domain, we have

x + 1 ≥ 0

So, we have

x ≥ -1

For the range, we have

y ≥ 0

The graph of f(x) = 3x² - 1 and f⁻¹(x)  = √[(x + 1)/3] on the same set of axes is added as an attachment

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To find the percentage, we can use the following formula:

Percentage = (Part / Whole) * 100

So, $131,701.32 is approximately 16.67% of $790,207.91.

In this case, the part is $131,701.32 and the whole is $790,207.91.

Percentage = ($131,701.32 / $790,207.91) * 100

Calculating the value:

Percentage ≈ 0.1667 * 100

Percentage ≈ 16.67%

Therefore, $131,701.32 is approximately 16.67% of $790,207.91.

Alternatively, we can calculate the percentage by dividing the part by the whole and multiplying by 100:

Percentage = ($131,701.32 / $790,207.91) * 100 ≈ 0.1667 * 100 ≈ 16.67%

So, $131,701.32 is approximately 16.67% of $790,207.91.

If you have any further questions, feel free to ask!

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Answer:

c) 2.2 feet

Step-by-step explanation:

1) Iris' puppy is 2 1/5 feet long. Which

decimal represents Iris' puppy's length?

c) 2.2 feet

Answer: \(\frac{5}{11}\)

Step-by-step explanation:

Given

Kira order 2 pieces of tuna and 5 pieces of crab

While Marcy ordered 3 pieces of tuna and 6 pieces of crab

Total tuna ordered =2+3=5 pieces

Total crab ordered=5+6=11 pieces

The ratio of Tuna and crab is   \(\frac{2+3}{5+6}=\frac{5}{11}\)

Answer:

whats the question?

Step-by-step explanation:

ok

Slope = (y2 - y1) / (x2 - x1)

P1 = (12, -4)

P2 = (14, 8)

Substitution

Slope = (8 - - 4) / (14 - 12)

= (8 + 4) / 2

= 12/2

= 6

Result

Slope = 6

Given that $OF = 9$ and $OF' = 12,$ where $F$ and $F'$ are the foci of the ellipse, we can determine the lengths of the major and minor axes.

In an ellipse, the sum of the distances from any point on the ellipse to the two foci is constant. This property is expressed by the equation:

$$PF + PF' = 2a,$$

where $P$ is any point on the ellipse and $a$ is the semi-major axis. In our case, $P = O,$ and since $OF = 9$ and $OF' = 12,$ we have:

$$9 + 12 = 2a,$$

$$21 = 2a.$$

Therefore, the semi-major axis $a$ is equal to $\frac{21}{2} = 10.5.$

The distance between the center of the ellipse and each focus is given by $c,$ where $c$ is related to $a$ and the semi-minor axis $b$ by the equation:

$$c = \sqrt{a^2 - b^2}.$$

We can solve for $b$ using the distance to one focus:

$$c = \sqrt{a^2 - b^2},$$

$$c^2 = a^2 - b^2,$$

$$b^2 = a^2 - c^2,$$

$$b = \sqrt{a^2 - c^2}.$$

Substituting the known values:

$$b = \sqrt{10.5^2 - 9^2},$$

$$b = \sqrt{110.25 - 81},$$

$$b = \sqrt{29.25},$$

$$b \approx 5.408.$$

Therefore, the semi-minor axis $b$ is approximately $5.408.$

Finally, we can determine the lengths of the major and minor axes:

The major axis $\overline{AB}$ is twice the semi-major axis, so $\overline{AB} = 2a = 2(10.5) = 21.$

The minor axis $\overline{CD}$ is twice the semi-minor axis, so $\overline{CD} = 2b = 2(5.408) \approx 10.816.$

Therefore, the major axis $\overline{AB}$ is $21$ units long, and the minor axis $\overline{CD}$ is approximately $10.816$ units long.

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The total weight is 18.5 kilograms

Answer:

They made 4 forks and 6 spoons last April.

Step-by-step explanation:

Let forks they made in april be x and spoons be y.

To make 1 fork we need $2

To make 1 spoon we need $1

They sell 1 fork for $6 and 1 spoon for the same amount So,

now,

Turning it into two equations :-

(x = number of forks and y = number of spoons)

2x + 1y = 14

6x + 6y = 60

Now,

2x + y = 14

y = 14 - 2x

Now,

6x + 6y = 60

or, 6x + 6(14-2x) = 60

or, 6x + 84 - 12x = 60

or, -6x = -24

so, x = 4

Now,

y = 14 - 2x

or, y = 14 - 2×4

or, y = 14-8

so, y = 6

Answer:

3x + 18

Step-by-step explanation:

3 ( x + 6 )

= 3*x + 3*6

= 3x + 18

Answer:

Step-by-step explanation:

expand 3(x+6)

3(x + 6) =      

3 * x + 3 * 6

3x + 18

The correct expression for the integral of (2y - x) over the region S in the uv-plane using the given transformation is: SSR(2y - x)dA = S²(v – u)dudv. So, none of the given options are correct.

To determine the correct answer from the given options, let's analyze the given information and make the necessary calculations.

First, let's calculate the Jacobian of the transformation using the given substitutions:

Jacobian (J) = ∂(x, y) / ∂(u, v)

To find the Jacobian, we need to compute the partial derivatives of x and y with respect to u and v:

∂x/∂u = ∂(2x - y)/∂u = 2

∂x/∂v = ∂(2x - y)/∂v = -1

∂y/∂u = ∂(x + y)/∂u = 1

∂y/∂v = ∂(x + y)/∂v = 1

J = |∂x/∂u ∂x/∂v| = |2 -1|

|∂y/∂u ∂y/∂v| |1 1|

Determinant of J = (2 × 1) - (-1 × 1) = 2 + 1 = 3

The determinant of the Jacobian is 3, not equal to 1. Therefore, the statement "The Jacobian is equal to 1" is not correct.

Now let's examine the statement "Under this transformation, one of the boundaries of R is the map of the line v = u."

Since u = 2x - y and v = x + y, we can find the equation for the line v = u by substituting u into the equation for v:

v = 2x - y

So the line v = u is represented by v = 2x - y.

Comparing this with the equation v = x + y, we can see that they are not equivalent. Therefore, the statement "Under this transformation, one of the boundaries of R is the map of the line v = u" is not correct.

From the given options, the correct answer is:

SSR(2y - x)dA = S²(v – u)dudv

This is the correct expression for the integral of (2y - x) over the region S in the uv-plane using the given transformation.

Please note that the other options are not correct based on the analysis provided.

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Answer: SAS similarity theorem

Proportional relationship:

\(\sf \dfrac{AB}{AC} = \dfrac{AM}{AN}\)

insert values

\(\rightarrow \sf \dfrac{21+9}{14+6} = \dfrac{21}{14}\)

simplify

\(\rightarrow \sf 1 = 1\)

L.H.S = R.H.S

The triangles are congruent and follows the rule SAS similarity theorem.

The triangles has/starts from the same angle, corner (A).

Answer:

y=2/3x +5

Step-by-step explanation:

to find the gradient

9--1/6--9

10/15

2/3

y-y1=m(x-x1)

y-9=2/3(x-6)

y-9=2/3x-4

y=2/3x+9-4

y=2/3x+5

The height of the cylinder is 14 meter.

Suppose that the radius of considered right circular cylinder be 'r' units.

And let its height be 'h' units.

Then, its volume is given as:

\(V = \pi r^2 h \: \rm unit^3\)

Given data volume of this cylinder is 8,616.16 cubic meters.

Radius=  14 m

We know that the expression for the volume of a cylinder is;

\(V=\pi r^2h\)

Now substitute;

8,616.16 =3.14 x 14^2 x h

8,616.16  = 615.44 x h

h = 8,616.16  / 615.44

h = 14

Hence the height of the cylinder = 14 meter.

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Answer:

  3/8

Step-by-step explanation:

A ratio is expressed in lowest terms by removing common factors from numerator and denominator.

  \(\dfrac{2.7\text{ hr}}{7.2\text{ hr}}=\dfrac{3\cdot0.9\text{ hr}}{8\cdot0.9\text{ hr}}=\boxed{\dfrac{3}{8}}\)

Yes, the  intersection of all of those intervals always be ope

The mathematical concept of well-defined groupings of objects, or sets, that are referred to as members or elements of the set. The only sets that are taken into consideration are those whose members are also sets because pure set theory only deals with sets.

Any union of open sets, or an unlimited number of open sets, is open. It is open where a finite number of open sets intersect.

A closed set is the complement of an open set (according to the space that the topology is specified on).

Thus, the intersection of all of those intervals always be open.

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We have proved that BC² ×AD = AC² ×BD using AAA congruence rule.

Triangles that are identical in size and shape are said to be congruent. This implies that the corresponding sides and angles are equal.

Without comparing each of the triangles' sides and angles, we can determine whether two triangles are congruent. The four rules that demonstrate triangle congruence will be discussed in this lesson. They are referred to as the SSS rule, SAS rule, ASA rule, and AAS rule.

We'll discuss the Hypotenuse Leg rule, a right triangle proof, in a later lesson. It is sufficient to demonstrate that the two triangles are congruent if only one of the rules is accurate.

Consider △ACD&△ABC

∠CAD=∠CAB

∠CDA=∠ACB

∴△ACD∼△ABC,{ By AA similarity criterion}

⟹ AC/AB = AD/AC

∴ AC ² =AB×AD  

Similarly, △BCD∼△BAC { by AA similarity criterion}

⟹ BC/BA =BD​/BC

∴BC² =BA×BD

∴ BC²/AC² = AB×BD/AB×AD

∴BC² ×AD = AC² ×BD

Thus, We have proved that BC² × AD = AC² × BD using AAA congruence rule.

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Complete question:

Triangle ABC is right angled at C and CD is perpendicular to AB. Prove that BC² ×AD = AC² ×BD

Answer:

the second one, 280/32

Step-by-step explanation:

i did the calculating

sorry if wrong

Answer:

The answer is D. Multiply 3 1/8 and 2 3/4 in order to get something close to that. Since there are no answers involving the max amount of space, this is the most likely answer.

The mean time for bicycle repairs on the first day of the race was 4.25 hours, while on the second day it decreased to 3.5 hours.

Additionally, the mean absolute deviation increased from 0.5 hour on the first day to 0.75 hour on the second day.

The change in the mean time for bicycle repairs from the first to the second day of the race indicates a decrease in the average repair time. This suggests that the riders were able to make repairs more efficiently or encountered fewer mechanical issues on the second day compared to the first day.

The decrease in mean repair time could be attributed to various factors, such as better maintenance of bicycles, improved repair skills of the riders, or reduced incidence of mechanical failures.

The increase in the mean absolute deviation from 0.5 hour on the first day to 0.75 hour on the second day implies greater variability in the repair times. This means that on the second day, the repair times were more spread out from the mean compared to the first day. The increased mean absolute deviation could be due to a wider range of repair times experienced by different riders or more unpredictable repair situations encountered on the second day.

In summary, the change in the mean time for bicycle repairs indicates a decrease from the first to the second day of the race, suggesting improved efficiency or reduced mechanical issues. However, the increase in the mean absolute deviation implies greater variability in repair times on the second day, indicating a wider range of repair experiences or more unpredictable repair situations.

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Answer:

11/100 is not wrong

Step-by-step explanation:

Convert the following into a fraction:

11%

Hint: | "Percent" (%) means "out of 100".

11% = 11/100:

Answer: 11/100

Answer:

The current of the circuit at t = 0 is equal to 0.

If we take the limit as t approaches infinity, the current is equal to ε/R or V/R.

General Formulas and Concepts:

Calculus

Differentiation

Derivative Property [Multiplied Constant]:

\(\displaystyle (cu)' = cu'\)

Derivative Property [Addition/Subtraction]:

\(\displaystyle (u + v)' = u' + v'\)

Derivative Rule [Basic Power Rule]:

Slope Fields

Integration

Integration Rule [Reverse Power Rule]:

\(\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C\)

Integration Rule [Fundamental Theorem of Calculus 1]:

\(\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)\)

Integration Property [Multiplied Constant]:

\(\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx\)

Integration Method: U-Substitution

Electricity

Ohm's Law: V = IR

Circuits

Step-by-step explanation:

*Note:

In the given equation, our variable of differentiation is x. I will rewrite this as current I for physics notation purposes.

Step 1: Define

Identify given.

\(\displaystyle L \frac{dI}{dt} + RI = V\)

[Assuming switch S is closed] Recall that an inductor is used in a circuit to resist change. After a long period of time, when it hits steady-state equilibrium, we expect to see the inductor act like a wire.

Step 2: Find Current Expression Pt. 1

Step 3: Find Current Expression Pt. 2

Identify variables for u-substitution.

Step 4: Find Current Expression Pt. 3

Recall that our initial condition is when t = 0, denoted as u₀, and we go to whatever position u we are trying to find. Also recall that time t always ranges from t = 0 (time can't be negative) and to whatever t we are trying to find.

Recall that our initial condition u₀ (derived from Ohm's Law) contains only the voltage across resistor R, where voltage is supplied by the given battery. This is because the current is stopped once it reaches the inductor in the circuit since it resists change.

Step 5: Solve

If we are trying to find the strength of the electrical current I at t = 0, we simply substitute t = 0 into our current function:

\(\displaystyle\begin{aligned}I(t) & = \frac{\mathcal E}{R} - \frac{\mathcal E}{R} e^{- \frac{R}{L}t} \\I(0) & = \frac{\mathcal E}{R} - \frac{\mathcal E}{R} e^{- \frac{R}{L}(0)} \\& = \boxed{\bold{0}}\end{aligned}\)

If we are taking the limit as t approaches infinity of the current function I(t), we are simply just trying to find the current after a long period of time, which then would just be steady-state equilibrium:

\(\displaystyle\begin{aligned}I(t) & = \frac{\mathcal E}{R} - \frac{\mathcal E}{R} e^{- \frac{R}{L}t} \\\lim_{t \to \infty} I(t) & = \frac{\mathcal E}{R} - \frac{\mathcal E}{R} e^{- \frac{R}{L}(\infty)} \\& = \boxed{\bold{\frac{\mathcal E}{R}}}\end{aligned}\)

∴ we have found the current I at t = 0 and the current I after a long period of time and proved that an inductor resists current running through it in the beginning and acts like a wire when in electrical equilibrium.

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Topic: AP Physics C - EMAG

Unit: Induction