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Answer: c

Explanation: just took the test and got it right

Explanation:

The reactant contains 2N and 6H

The product contains 2N and 6H

Therefore, the chemical equation is balanced

From the equation, for every 1 mole of N2 that reacts, 3 moles of H2 are required.

We know 28.6 grams of N2 reacted, but we don’t know the mass ratio but just the mole ratio, so we have to convert 28.6 grams of N2 to the corresponding moles of N2.

From the periodic table, the molar mass of N is about 14 g/mol, so the molar mass of nitrogen gas or N2 is two times of that which is 28 g/mol.

With this, we can calculate moles of N2, but we also need to make sure the equation is setted up the right way.

Looking at the units, if we cancel out the grams, we are left with mol. We also know that in multiplication, numerator of one number cancel with the denominator of another number and vice versa

So the equation looks like this 28.6g * mol/28g = 1.021 mol N2

So the number of moles of H2 required is 1.021 mol N2 * 3 mol H2/1 mol N2 = 3.063 mol H2 (notice that mol N2 canceled out, so the equation is set up correctly)

However, the question ask for number of grams of H2 needed, so we need the molar mass of hydrogen gas or H2, which is 1*2 = 2 g/mol

3.063 mol H2 * 2 g H2/ mol H2 = 6.126 g H2

Ans: 6.126 g H2

The pressure inside the tire is approximately 1.970796 newtons per square centimeter (N/cm²) when measured in those units.

To convert the pressure from pounds per square inch (psi) to newtons per square centimeter (N/cm²), we need to use the conversion factors between these units.

First, let's convert pounds to newtons:

1 pound = 0.45359237 kilograms

1 kilogram = 9.80665 newtons

Next, let's convert square inches to square centimeters:

1 square inch = 6.4516 square centimeters

Now, we can perform the conversion:

1 psi = (0.45359237 kg) × (9.80665 N/kg) / (6.4516 cm²)

≈ 0.070307 N/cm²

Therefore, the pressure inside the tire of 28.0 psi is approximately equal to 28.0 × 0.070307 N/cm², which is approximately 1.970796 N/cm².

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Answer:

When the batter hits the ball, there is a force applied, and energy is transferred. The ball will move in the direction the force is pushing it. If two objects collide, energy will be transferred between both, and there will be a change in motion.

Explanation:

Since the number of atoms which are reacting are equal to the number of to the number of atoms in the product, this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.

Any system that is closed to all exchanges of matter and energy is subject to the law of conservation of matter, which is a general law of physics and chemistry. This law states that regardless of how the components rearrange themselves, the mass of an object or group of things remains constant over time.

A chemical reaction is a procedure that causes one group of chemical components to change chemically into another. Chemical reactions, which can frequently be described by a chemical equation, traditionally include changes that solely affect the locations of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei.

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Answer:25.75

Explanation:

Answer:

1 × 10⁻² M

Explanation:

Step 1: Given data

Absorptivity of a dye (ε): 1 × 10² cm⁻¹M⁻¹

Absorbance (A): 1.0

Length of the cuvette (l): 1 cm

Concentration of a dye (C): ?

Step 2: Calculate the concentration of the dye

We will use Beer's Law.

A = ε × l × C

C = A / ε × l

C = 1.0 / 1 × 10² cm⁻¹M⁻¹ × 1 cm

C = 1 × 10⁻² M

The concentration of the dye is 1 × 10⁻² M.

Answer:

Combustion

Explanation: Because a reactant is reacting with O2.

The freezing point of the solution can be obtained from ΔT = K x molality

The question is incomplete but I can see that you want to learn how to calculate the freezing point of a solution and I would help you out with that.

The freezing point of a solution can be calculated using the freezing point depression equation. This equation takes into account the fact that the freezing point of a solution is lower than that of the pure solvent due to the presence of solute molecules.

The equation is as follows:

ΔT = K x molality

where:

ΔT is the change in freezing point (in degrees Celsius)

K is the freezing point depression constant for the solvent (in units of degrees Celsius per mol per kilogram)

molality is the concentration of the solute in the solution, expressed as the number of moles of solute per kilogram of solvent.

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The new volume of the balloon after heating it to a temperature of 51 °C is approximately 2.39 L.

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Given that:

Substituting the given values and solve for V₂:

\(V_1T_2 = V_2T_1\\\\V_2 = \frac{V_1T_2}{T_1} \\\\V_2 = \frac{2.2\ *\ 324.15}{298.15 }\\ \\V_2 = 2.39 \ L\)

Therefore, the final volume is 2.39 litres.

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According to the research, the false statement is B. "In eukaryotes, it is composed of many DNA molecules attached end to end" doesn't describe a chromosome.

They are the structures that carry the genetic material, that is, the information encoded by deoxyribonucleic acid, they are visible in the nucleus of the cells and whose shape varies according to the cell stage.

In this sense, eukaryotic chromosomes are made up of DNA and other proteins, as histones and other non-histones are found in pairs, they have telomeres that provide them with stability.

Therefore, we can conclude that chromosomes are structures where most of the genetic information of an individual resides, thus the false statement is B.

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The instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

To find the instantaneous rate of reaction at 17 minutes, we can use the concept of differential calculus and estimate the slope of the tangent line at t=17 on the graph of rate versus time.

To do this, we can use the formula for the slope of a line

slope = (change in y) / (change in x)

In this case, the "y" values are the rates of reaction and the "x" values are the times. We want to find the slope at t=17, so we can choose two points that are very close to t=17, such as t=15 and t=20. Then, we can use these values to estimate the slope at t=17

slope = (rate at 20 min - rate at 15 min) / (20 min - 15 min)

slope = (0.135 - 0.223) / (20 - 15)

slope = -0.178

This slope represents the instantaneous rate of reaction at t=17. However, since it has a negative value, it means that the rate of reaction is decreasing at t=17.

Therefore, the instantaneous rate of reaction at 17 minutes is approximately -0.178 mol dm⁻³

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The pH at the equivalence point for the titration of 0.25 M HCOOH versus 0.25 M NaOH is 8.5.

Let's consider the following neutralization reaction.

HCOOH + NaOH ⇒ HCOONa + H₂O

At the equivalence point, 0.25 M HCOOH completely reacted with 0.25 M NaOH to form 0.25 M HCOONa.

HCOONa undergoes hydrolysis. The net ionic equation is:

HCOO⁻(aq) + H₂O(l) ⇄ HCOOH(aq) + OH⁻(aq)

Given the concentration of HCOO⁻ is 0.25 M (Cb) and the basic dissociation constant of HCOO⁻ is 4.8 × 10⁻¹¹ (Kb), we can calculate the concentration of OH⁻ using the following expression.

\([OH^{-} ] = \sqrt{Kb \times Cb } = \sqrt{(4.8 \times 10^{-11} ) \times 0.25 } = 3.5 \times 10^{-6} M\)

The pOH of the solution is:

\(pOH = -log [OH^{-} ] = -log (3.5 \times 10^{-6} ) = 5.5\)

The pH of the solution is:

\(pH = 14 -pOH = 14 -5.5 = 8.5\)

The pH at the equivalence point for the titration of 0.25 M HCOOH versus 0.25 M NaOH is 8.5.

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The pOH of the 0.001 M NaOH solution is approximately 3.

To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.

In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.

The pOH is calculated using the equation:

pOH = -log[OH-]

Substituting the concentration of hydroxide ions, we have:

pOH = -log(0.001)

Using a calculator, we can evaluate the logarithm:

pOH ≈ 3

Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.

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The proper numbering is 4, 2, 1, and 3.

The following sequence of actions can be used to describe how an undersea sedimentary rock is formed.

Sedimentary Rock

In a basin, sediments and animal skeletons start to accumulate.

The material that has been deposited starts to become bound together by a glue ingredient brought in by running water, such as calcite or clay. The deposits start to become harder.

The deposits eventually transform into rock that is solid and hard. The new rock is a mixture of several organic and inorganic components.

Existing rocks become sediments as a result of weathering.

What causes sedimentary rocks to form?

Sedimentary rocks are formed when previously existing rocks or pieces of extinct animals accumulate on the surface of the Earth. Sediment that has been buried deeply becomes compacted

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Answer:

Answer: 35.9 g

Explanation:

What would be the mass of 1.20 x 1024 molecules of water? Where —number of the moles, —Avogadro number, 6.02 * 1023 mol-1, —molar mass of water, 18 g/mol. = 1.2 ∗ 1024 6.02 ∗ 1023 ∗ 18 = 35.9

The substance that changed phase would have less heat capacity than the other thus the bonds in it were broken more easily.

We have to note that the phase change has to do with the conversion of a liquid to a solid or the conversion of a liquid to a gas. A phase is essentially a  given state of matter.

In the case of the question that we have here, we are told that the two substances that are tested are liquids. It is now clear that the substance that changed phase would have a lower heat capacity.

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Answer:

water vapour I guess I the answer of your question

Answer:

The enthalpy of vaporization of water at 273 K and 1 bar = 44.9 KJ/mol

Explanation:

Enthalpy of vaporization of water at 273 K, ΔHvap(T₂) is given as;

ΔHvap(T₂) = ΔHvap(T₁) + ΔCp * (T₂ - T₁)

where ΔCp = molar heat capacity of gas - molar heat capacity of liquid

Therefore, ΔCp = (33.6 - 75.3) = -41.70 J/(mol K) = 0.0417 kJ/(molK)  

substituting  ΔCp = 0.0417 kJ/(mol K)  in the initial formula

;

ΔHvap(T) = ΔHvap(T1) + ΔCp * (T₂ - T₁)

ΔHvap(T₂)= 40.7 kJ/mol + {-0.0417 kJ/(mol K) * (272 - 373 K)}

ΔHvap(T₂) = 44.9 kJ/mol

Therefore,  enthalpy of vaporization of water at 273 K and 1 bar = 44.9kJ/mol

Answer:

It is not 100% silver, but it contains a high percentage (more than the 98% for sure) of silver.

Explanation:

Hello,

In this case, since the density of silver is 10.49 g/cm³, we can substantiate if the given sample is silver by computing is density as shown below:

\(\rho =\frac{m}{V}=\frac{1.7kg}{0.164L}*\frac{1000g}{1kg} *\frac{1L}{1000cm^3}\\ \\\rho=10.37g/cm^3\)

In such a way, since we find a slight difference in the computed density, we can say it is not 100% silver, but it contains a high percentage (more than the 98% for sure) of silver.

Regards.

The pH of 500ml of water to which 20ml of 0.1M HNO3 has been added is  = 4.8 and The PH of 500ml of water to which 15.0ml of 1.0M KOH has been added is  = 10.12

a. The pH of 500 mL of water to which 20.0 mL of 0.1 M HNO3 has been added can be calculated as follows:

First, calculate the volume-to-volume ratio of the HNO3 solution to the water: V_HNO3 / V_water = 20.0 mL / 500 mL = 0.04

Next, calculate the amount of HNO3 added to the water: n_HNO3 = 0.1 M * 20.0 mL * 0.04 = 8.0 x \(10^{5}\) mol

Finally, calculate the new concentration of HNO3 in the solution and use the equation for the pH of a strong acid solution to find the pH: C_HNO3 = n_HNO3 / (V_water + V_HNO3) = 8.0 x \(10^{-5}\)mol / (500 mL + 20.0 mL) = 1.6 x \(10^{-5}\) M pH = -log[H+] = -log(1.6 x \(10^{-5}\)) = 4.8

b. The pH of 500 mL of water to which 15.0 mL of 1.0 M KOH has been added can be calculated as follows:

First, calculate the volume-to-volume ratio of the KOH solution to the water: V_KOH / V_water = 15.0 mL / 500 mL = 0.03

Next, calculate the amount of KOH added to the water: n_KOH = 1.0 M * 15.0 mL * 0.03 = 4.5 x \(10^{-4}\)mol

Finally, calculate the new concentration of OH- in the solution and use the equation for the pH of a strong base solution to find the pH: C_OH- = n_KOH / (V_water + V_KOH) = 4.5 x \(10^{-4}\) mol / (500 mL + 15.0 mL) = 7.5 x \(10^{-5}\) M pH = 14 + log[OH-] = 14 + log(7.5 x\(10^{-5}\)) = 10.12.

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Answer:

The orange line is the best option

Explanation:

As I was typing my answer I just saw that you have in your question "It was orange" so ig I can't say it is the maroon line :/

The orange line on the graph to the right best represents the data table. Therefore, the correct option is option A among all the given options.

In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way. The relationships among two or more items are frequently represented by the points on a graph. A bar graph can also be used to display the data. Bar graphs show how many of each supply there are.

Here, as instance, we may plot a graph showing the kind and quantity of school supplies in use by pupils in a class based on the data provided below. Each supply is first counted, and the data is then shown in a table with certain colors in a logical sequence. The orange line on the graph to the right best represents the data table.

Therefore, the correct option is option A among all the given options.

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Answer:

Sulfuric acid

Explanation:

Hope that helps!

From the Herszsprung -Russel Diagram presented it is to be noted that if a star has an absolute magnitude of 10 and a temperature of 20,000 K, the spectral class under which the star would be classified is; O-Types. (Option B).

These stars have a blue-white appearance and are characterized by strong emission lines in their spectra, which are caused by the high temperatures in their atmospheres.

The absolute magnitude of a star is not directly related to its spectral class, but it can be used to estimate the distance of a star from Earth. A star with an absolute magnitude of 10 would be relatively faint if it were close to Earth, but it could be much brighter if it were farther away.

Hence, if a star has an absolute magnitude of 10 and a temperature of 20,000 K, it would be classified as an O-type star.

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1) Hypothetical chemical equation

2) The equilibrium constant expression is

3) Option D. The equilibrium law constant is equal to the product of the equilibrium concentrations of the products divided by the product of the equilibrium concentrations of the reactants raised to the power of their respective coefficients in the balanced equation.

Answer: 3 qualitative: the word pharmacology is written in blue, the stairs are gray, the tile on the first floor is yellow. 3 quantitative: there are four people wearing yellow, there are Four pink boxes, there are two floors.

Inference: there are many people performing experiments so it’s a lab.

Explanation:

Answer:

Qualitive - The bars are yellow, The floor is green, and the floor has pharmacology on it.

Quantitative - There are 8 support bars, There is 3 gray coats, and there is 27 pills that I can see on that picture.

Inference - There are many people doing experiments because the word pharmacology is on the floor.

Explanation:

This picture tells you that pharmacology is a form of study of medicine and drugs.

Answer:

Explanation:

The original volume can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

Since we are finding the original volume

\(V_1 = \frac{P_2V_2}{P_1} \\\)

From the question we have

\(V_1 = \frac{458 \times 1072}{760} = \frac{490976}{760} \\ 646.021052...\)

We have the final answer as

Hope this helps you