Answer:
The answer is 20%.
Step-by-step explanation:
Answer:
20%
Step-by-step explanation:
To write the decimal as a percent, we multiply it by 100
0.20 = 0.20 × 100 = 20%
Hence, 0.20 is the same as 20%.
Lorelei and Chance run a bakery. They have been making wedding cakes for several years and they have found the time L it takes Lorelei to frost a randomly selected 3-layer cake is approximately Normally distributed with a mean of 37 minutes and a standard deviation of 12 minutes. The time C it takes Chance to decorate a randomly selected 3-layer cake is approximately Normally distributed with a mean of 52 minutes and a standard deviation of 7 minutes. Assume that L and C are independent random variables.
Use the z-table to answer the question.
Let the random variable T = L + C be the total time it takes Lorelei, then Chance to each totally finish a different randomly selected 3-layer wedding cake.
The shape of T is
.
The center of T is Mu Subscript T =
.
The variability of T is Sigma Subscript T =
.
The probability that Lorelei and Chance totally finish a randomly selected 3-layer wedding cake in under 90 minutes is
Where the above conditions exist,
The shape of T is also Normally distributedMu_T = 89Var(T) = 193Sigma_T = 13.89the probability that Lorelei and Chance totally finish a randomly selected 3-layer wedding cake in under 90 minutes is 0.5287. What is the rationale for the above response?The random variable T = L + C represents the total time it takes Lorelei and Chance to finish a randomly selected 3-layer wedding cake. Since L and C are independent and Normally distributed, T is also Normally distributed with mean:
Mu_T = Mu_L + Mu_C = 37 + 52 = 89
and variance:
Var(T) = Var(L) + Var(C) = 12^2 + 7^2 = 193
So the standard deviation of T is:
Sigma_T = sqrt(Var(T)) = sqrt(193) = 13.89
The shape of T is also Normally distributed, since it is a sum of two independent Normally distributed variables.
To find the probability that Lorelei and Chance finish a randomly selected 3-layer wedding cake in under 90 minutes, we need to calculate the z-score for this value and then find the corresponding probability from the z-table. The z-score is:
z = (90 - 89) / 13.89
= 0.072
From the z-table, we find that the probability of a Z-score less than or equal to 0.072 is 0.5287.
Therefore, the probability that Lorelei and Chance totally finish a randomly selected 3-layer wedding cake in under 90 minutes is 0.5287 or approximately 53%.
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Stacy rented a truck for one day there was a base fee of $16.95 and there was an additional charge of 93 cents for each model driven. stacy had to pay $143.43 when he returned the truck. for how many miles did she drive the truck
Answer:
Stacy rented a truck for one day there was a base fee of $16.95 and there was an additional charge of 93 cents for each model driven. stacy had to pay $143.43 when he returned the truck. for how many miles did she drive the truck
Step-by-step explanation:
Let's start by subtracting the base fee from the total cost:
$143.43 - $16.95 = $126.48
Now, we can divide the remaining cost by the cost per mile:
$126.48 ÷ $0.93/mile ≈ 136 miles
Therefore, Stacy drove the truck for approximately 136 miles.
help me with this ques. (need solution and answer both) thanks so much <3
Answer:
1.) 27a^11 + 18a^9 -72a^7
2.) 6p^4q^3 - 10p^3q + 4p^2q3
Step-by-step explanation:
1.) Distribute and do the math
-9a^5 x (-3a^6) - 9a^5 X (-2a^4) - 9a^5 x 8a^2
27a^11 + 18a^9 -72a^7
2.) Distribute and do the math
2pq^2q x 3p^2q^2 - sp^2q x 5p + 2p^2q x 2q^2
6p^4q^3 - 10p^3q + 4p^2q3
Evaluate - 2(3k+9x) when k= -8 and x= -9
Answer:
210
Step-by-step explanation:
When you have questions that says evaluate [insert equation here] and it gives you variables thats inside the equation, replace the equation with that value.
The question is telling you that k is equal to -8 and x is equal to -9. So replace k and x with their numerical values so you can proceed with math.
-2(3k+9x) turns into: -2(3(-8)+9(-9)).
-2(3k+9x) (or -2(3(-8)+9(-9))) evaluates to 210.
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Answer:
The choose;
\(3 \frac{9}{10} \)
Step-by-step explanation:
\(2 \frac{3}{5} \div \frac{2}{3} \\ \\ = \frac{13}{5} \div \frac{2}{3} \\ \\ =\frac{13}{5} \times \frac{3}{2} = \frac{39}{10} \\ \\ = 3 \frac{9}{10} \)
I hope I helped you^_^
If the 6am temperature in Durango, Colorado was -8° F and the temperature rose 15° by 2pm, then what would the temperature be at 2pm?
Find the quotient of the quantity 21 times ten raised to the negative twenty first power end quantity divided by the quantity 7 times ten raised to the negative twenty first power end quantity.. write the final answer in scientific notation. 3 x 10−42 3 x 100 3 x 1021 3 x 1042
Answer:3x10^0 or 3x10 to the power of 0
Step-by-step explanation:
I did the same exact one with my teacher i hope this helps you
A bag contains three red pens five blue pens and a black pen. Zoe takes out one pin at random for her schoolwork one morning but does not put it back in the bag. That afternoon she takes another pen out of the bag. What is the probability that the two pens chosen that day were of the same color? 
The probability that the two pens chosen that day
were of the same color is 7/36.
There are nine pens in the bag in total, thus the likelihood that Zoe will choose a red pen on the first draw is three out of nine, a blue pen on the first draw is five out of nine, and a black pen on the first draw is one out of nine. There are now 8 pens in the bag for the second draw, presuming Zoe chose a pen of a certain color on the first draw. There are two red pens and six non-red pens left in the bag if Zoe chose a red pen during the initial draw. As a result, there is a 2/8 chance that the second draw will provide another red pen. Similarly, if Zoe picked a blue pen on the first draw, there are 4 blue pens and 4 non-blue pens left in the bag, so the probability of picking another blue pen on the second draw is 4/8. Finally, if Zoe picked the black pen on the first draw, there are no black pens left in the bag, so the probability of picking another black pen is 0.
So, to find the probability that Zoe picks two pens of the same color, we need to consider all the possible combinations of the first and second draws: Zoe picks a red pen first, and then another red pen: (3/9) x (2/8) = 1/12
Zoe picks a blue pen first, and then another blue pen: (5/9) (4/8)= 5/18
Zoe picks the black pen first, and then cannot
pick another black pen: 1/9 × 0 = 0
Therefore, the overall probability of Zoe picking (1/12)+(5/18)+0=7/36
two pens of the same color is:
So the probability that the two pens chosen that day were of the same color is 7/36.
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Started at –20° and changed 0° whats is the slope
Answer:
See below
Step-by-step explanation:
Start out -20 and change 0° ?
then there is zero slope as this would be a horizontal line.
Jayden made 5% of his free throws over the season. If he shot 120 free throws, how many did he make? Divide/scale down to solve for the missing percent.
Answer:6
Step-by-step explanation:If jayden made 5% of his free throws and he shot 120 free throws you have to find 5% of 120.
5% of 120 = 6
So Jayden shot a total of 6 free throws during the season
Find the value of p if (3, 2) is a solution of px – 5y + p2 = 0.
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Substitute the x and y values in:
p^2 + 3p - 5(2) = 0
p^2 + 3p - 10 = 0
Factorise this:
(p - 2)(p + 5)
p = 2
p = -5
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The recipe uses 1/2 cup of sugar for 1 cup of flour...how much flour should there be if there is 2 cups of sugar? *
Answer:
4 cups
Step-by-step explanation:
2 divided by 1/2 is 4 so there are 4 half cups of sugar.
Since the sugar is multiplied by 4 you have to multiply the flour by 4.
1*4=4
giving brainliest for correct answer
Answer:
x≥-2
Step-by-step explanation:
dark circle means equality and all numbers are greater than -2
it can also be written as
[-2,∞)
During one day in a hardware tore, 37 people came in and made a purchae, and 13 people looked around but didn’t purchae anything
The required ratios: a. Purchasers to non purchasers is 37:13 b. Non Purchasers to purchasers is 13:37 c. Purchasers to total customers is 37:50 d. Non Purchasers to total customers is 13:50
So, based on the information-
Non purchasers = 13
Purchasers = 37
Total customers = 50
Finding ratio by keeping the values as per the requirement -
a. Purchasers to non purchasers = 37:13
b. Non Purchasers to purchasers = 13:37
c. Purchasers to total customers = 37:50
d. Non Purchasers to total customers = 13:50
Hence, the ratios are a. 37:13, b. 13:37, c. 37:50 and d. 13:50.
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Don’t get this problem
Answer:
why does it say right twice? ...
liam has ten apples.he gives 5 away to his friend cherry.how many apples do liam have left?
Answer: 5
Step-by-step 10-5=5
Answer:
5 apples
Step-by-step explanation:
Liam has 10 apples and he gives 5 away to his friend cherry
10-5= 5
He has 5 apples left
1. Jemima wants to make chocolate chip walnut brownles. Chocolate chips come in a 12oz bag that costs $3. Walnuts
come in a 4oz bag that costs $2. If Jemima needs three pounds of chocolate chips and walnuts combined, and has $15
to spend, how many bags of each can she buy?
Answer:
4 bags of chocolate chips and 1 bag of walnuts.
Step-by-step explanation:
Find how many ounces are in 3 pounds:
16 oz = 1 lb
16 oz × 3 = 3 lbs
48 oz = 3 lbs
Variable x = number of chocolate chips
Variable y = number of walnuts
4x + 1y = 15
Keep in mind it must equal up to 48 oz and be $15 or under.
4 bags × 12 oz = 48 oz
1 bag × 4 oz = 4 oz
48 oz + 4 oz = 52 oz > 48 oz
4 bags × $3 = $12
1 bag × $2 = $2
$12 + $2 = $14 < $15
Both requirements have been met.
Find the product.
(n+7)(n − 2)
Need help please fast
Answer:
n² + 5n - 14
Step-by-step explanation:
(n + 7)(n - 2) =
= n² - 2n + 7n - 14
= n² + 5n - 14
Answer:
\(n^2 + 5n - 14\)
Step-by-step explanation:
Expand the factored expression.
(n + 7)(n - 2)
= n · n + n · (-2) + 7 · n + 7 · (-2)
= n^2 - 2n + 7n - 14
= n^2 + 5n - 14
\(= n^2 + 5n - 14\)
Riddle: The more you take the more you leave behind you. What is the answer?
Answer:
Footsteps
Step-by-step explanation:
When you take footsteps, you leave them behind as well.
determine the function f satisfying the given conditions. f ' (x) = ex/8 f (0) = 17 f (x) = a e^bx + c. A = ____. B = _____. C = _____
A = 1/8
B = 1
C = 135/8
To solve this problem, we first need to integrate f'(x) = ex/8. We can do this by multiplying both sides of the equation by dx and then integrating:
∫ f'(x) dx = ∫ ex/8 dx
f(x) = 8e^(x/8) + C
We now need to use the given initial condition f(0) = 17 to find the value of C:
f(0) = 8e^(0/8) + C = 8 + C = 17
C = 9
So, the function f(x) that satisfies the given conditions is:
f(x) = 8e^(x/8) + 9
We can rewrite this function in the form f(x) = a e^bx + c by comparing the coefficients with the given expression. We see that:
a = 8
b = 1/8
c = 9
Therefore, A = 8, B = 1/8, and C = 9.
To find the function f(x) that satisfies the given conditions, we need to integrate f'(x) and apply the initial conditions. Given f'(x) = e^x/8, we can integrate with respect to x:
f(x) = ∫(e^x/8)dx = (1/8)∫(e^x)dx = (1/8)e^x + C_1, where C_1 is the constant of integration.
Now, we apply the initial condition f(0) = 17:
17 = (1/8)e^0 + C_1 => 17 = (1/8)(1) + C_1 => C_1 = 17 - 1/8 = 135/8.
So, f(x) = (1/8)e^x + 135/8.
Now, we need to match this to the form f(x) = a*e^(bx) + c. Comparing the coefficients, we can determine the values of a, b, and c:
A = 1/8
B = 1
C = 135/8
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7. Charlie went to Juarez, Mexico, on a shopping trip.
He bought silver rings at $5 each and bracelets at $8
each. If he bought a total of 19 items and spent $131,
how many bracelets and rings did he buy?
whats the answer for 5x5/2
Patrick is excited to attend his son’s soccer game tomorrow
evening, but he also needs to ensure his daughter arrives at her
coding class on time. Patrick is debating whether taking the train
or his
Personal car would be the best option to manage both tasks efficiently. While the train is a reliable mode of transportation, it may have fixed schedules that might not align perfectly with Patrick's needs.
On the other hand, using his personal car provides more flexibility and allows him to tailor the departure time according to his daughter's coding class schedule.
If Patrick decides to take the train, he would need to check the train schedule to see if there are convenient departure and arrival times for both the soccer game and the coding class. This option would require planning and coordination to ensure he arrives at the game on time and can pick up his daughter afterward.
Using his personal car gives Patrick the freedom to leave at a time that accommodates both the soccer game and the coding class. He can drop off his daughter at her coding class, attend the soccer game, and then pick her up afterward without being restricted by train schedules.
Considering the circumstances, Patrick might find it more convenient to use his personal car to manage both tasks effectively and ensure he can attend his son's soccer game while also ensuring his daughter arrives at her coding class on time.
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find the cost price of an article which is sold for #31,960 at a loss of 6%
\(\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{6\% of 31960}}{\left( \cfrac{6}{100} \right)31960}\implies 1917.6~\hfill \underset{cost~price}{\stackrel{31960-1917.6}{30042.4}}\)
Does the variance of a sum equal the sum of the variances?
The statement "the variance of a sum equals the sum of the variances" is true. This can be proven mathematically by using the formula for the variance of a sum of two random variables:
\(Variance of a sum = Var(X + Y) = Var(X) + Var(Y)\)
This formula states that the variance of a sum is equal to the sum of the variances of each individual random variable.
Addition is one of the mathematical operations.
What is addition for?Addition helps us to do mathematical calculations, its purpose is the combination of quantities in order to have a single result.
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what is the sum of 3,9
Answer:
3 + 9 = 12 !
Step-by-step explanation:
Find the surface area of the composite figure.
8 cm
6 cm
7 cm
8 cm
SA =
6 cm
[ ? ] cm²
9 cm
6 cm
If you'd like,
you can use a
calculator.
Enter
Answer:
The Answer Is 382...
Step-by-step explanation:
A Credit Default Swaps (CDS)¹ is a contract where one party (credit protection buyer) pays the other one (credit protection seller) a fixed periodic coupon for the life of the contract on a specified reference asset. The party paying the premium is effectively buying insurance against specific credit events, such as default, bankruptcy or failure-to-pay or debt restructuring. If such a credit event occurs, the party receiving the premium makes a payment to the protection buyer, and the swap then terminates. Consider now that party A wishes to get covered from a potential loss of the face value (VA) of an asset in case of a credit event. Hence, party A decides to purchase today (to = 0) some protection from party B that lasts until some specified maturity date T. To pay for this protection, party A makes a regular stream of payments to party B. The size of these payments is a fixed percentage of the face value of the asset being insured and it is based on the yearly contractual spread W₁y, which represents the percentage used to determine the payments' amount over one year. The payments are made every 3 months until maturity of the contract or until a credit event occurs, whichever occurs first. Assume that the credit event occurs as the first event of a Poisson counting process and hence default time is exponentially distributed with parameter λ. Denote the short rate with r. The aim is to value the premium leg, i.e. to write a mathematical expression for this stream of payments taking into account both the appropriate discounting and the probabilities of default events. a) Illustrate the problem with a sketch representing the various payments occurring over the considered time period. Make sure you include the time at which the payments are made and the size of each undiscounted payments. b) Express the discounting factor at time t, where i E {0,1,..., N}. c) Express the probability that a credit event occurs before time t, (P) and the survival probability at time t₁, i.e. the probability that no credit event has occurred before time t (PND). d) Using the above, write down the full expression for the premium leg. e) Using the values that correspond to your Group, calculate the premium leg and price the CDS.
The problem involves valuing the premium leg of a Credit Default Swap (CDS) contract, where one party (credit protection buyer) pays the other party (credit protection seller) a fixed periodic coupon for the life of the contract on a specified reference asset.
In a Credit Default Swap (CDS), party A purchases protection from party B against a potential loss in the face value of an asset due to credit events. Payments are made every 3 months based on the contractual spread and the face value of the asset. The first step is to sketch the payment schedule, indicating the time of each payment and its size.
Next, the discounting factor at time t needs to be expressed. This factor accounts for the time value of money and is used to discount future payments to their present value.
The probability of a credit event occurring before time t (P) and the survival probability at time t (PND) are important in valuing the CDS. P represents the likelihood of a default event occurring, while PND represents the probability that no default event has occurred before time t.
Based on the above, the full expression for the premium leg can be written, considering both the discounting factor and the probabilities of default events.
Finally, using the provided values, the premium leg can be calculated, and the CDS can be priced.
By following these steps and incorporating the relevant mathematical expressions, the premium leg of the CDS can be evaluated, providing a valuation for the contract.
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What theorem proves the congruency of these triangles?
HELP ME PLZZ !!
the range of numbers in the data series that controls the minimum, maximum, and incremental values on the value axis is referred to as the:
The range of numbers in the data series that controls the minimum, maximum, and incremental values on the value axis is referred to as the "axis scale" or "axis range."
It determines the span of values displayed on the value axis of a graph or chart. The axis scale is typically set based on the minimum and maximum values present in the data series, and the incremental values (tick marks) are placed at regular intervals within that range.
It represents the span of values that will be displayed on the value axis of a graph or chart. The data range determines the scale and divisions of the axis, allowing the viewer to interpret the data accurately and understand the relative magnitude of the values being presented.
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