PLS HELP
4.8kg=_______mg
3.2kg=_______dg
mg=milligarm
dg=decigram

Answer:

15

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

To find 10% you multiply by 0.1.

0.1 × 150 = 15

Answer:

10 water and 4 cheese sticks

Step-by-step explanation:

water

5 10 15 20 25 30 35 40 45 50<--

cheese sticks

12 24 38 50<--

Answer:

720

Step-by-step explanation:

Answer:

720

Step-by-step explanation:

There are two 1/2 miles in a mile. this means there are 12 half miles in 6 miles. So take 60*12 to get 720.

Red Circle:

First find the diameter

We can do that by counting the squares

Diameter:4

The radius is half of the diameter

4/2=2

Radius of the Red Circles:2

Blue Circle:

Diameter: 2

2/2=1

Radius of the Blue Circle:1

a. The probability that the sample mean will be within ±5 of the population mean is the area under the normal curve between these two z-scores. b. The lower bound z-score is (-10 - 0) / 10 = -1, and the upper bound z-score is (10 - 0) / 10 = 1. We can use the same normal distribution table or technology to find the probability associated with these z-scores.

(a) To find the probability that the sample mean will be within ±5 of the population mean, we can use the Central Limit Theorem (CLT) and the properties of a normal distribution.

The sample mean, is an unbiased estimator of the population mean, μ. According to the CLT, the distribution of sample means approaches a normal distribution with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

     = 200 / √400

     = 200 / 20

     = 10

To find the probability that the sample mean will be within ±5 of the population mean, we can standardize the interval using the z-score:

For the lower bound (-5), the z-score is (-5 - 0) / 10 = -0.5.

For the upper bound (+5), the z-score is (5 - 0) / 10 = 0.5.

We can now use a standard normal distribution table or technology (such as a calculator or statistical software) to find the probability associated with the z-scores -0.5 and 0.5. The probability that the sample mean will be within ±5 of the population mean is the area under the normal curve between these two z-scores.

(b) To find the probability that the sample mean will be within ±10 of the population mean, we follow the same steps as in part (a).

The lower bound z-score is (-10 - 0) / 10 = -1, and the upper bound z-score is (10 - 0) / 10 = 1. We can use the same normal distribution table or technology to find the probability associated with these z-scores.

Note: Since the question mentions rounding answers to four decimal places, please use the appropriate table or technology to obtain the precise probabilities for parts (a) and (b).

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The linear system can be solved using Cramer's rule. None of the provided vectors belong to the set W. The value of A₂₃ - A₁₂ is 5.The linear system has no solution.

For the first question, we need to determine the correct statement for the given linear system:

⎧

⎨

⎩

3x₁ - 3x₃ + x₂ = 1

6x₁ + 5x₂ + 7x₃ = 2

7x₁ + x₂ + 4x₃ = 3

To determine the solution, we can analyze the properties of the linear system. One approach is to check the determinant of the coefficient matrix A, denoted as det(A). If det(A) is non-zero, the system has a unique solution. If det(A) is zero, there are either no solutions or infinite solutions.

To determine if we can apply Cramer's rule, we need to calculate the determinant of the coefficient matrix A. Let's denote the matrix A as:

A = ⎣⎡

3 -3 1

6 5 7

7 1 4

⎦⎤

Calculating det(A), we find:

det(A) = 3(54 - 17) - (-3)(64 - 17) + 1(61 - 57)

= 3(20 - 7) - (-3)(24 - 7) + 1(6 - 35)

= 3(13) - (-3)(17) + 1(-29)

= 39 + 51 - 29

= 61

Since det(A) is non-zero (61 ≠ 0), we can apply Cramer's rule to solve the given linear system. Therefore, the correct statement for this linear system is "We can apply Cramer's rule to solve the given linear system."

For the second question, we need to determine which vector belongs to the set W. The set W is defined as vectors of the form:

⎣⎡

a

0

a² + 2b²

⎦⎤

By comparing the given vectors, we can see that none of them matches the form specified by set W. Therefore, the correct answer is "none of the others."

For the third question, we are given a matrix A and asked to calculate A₂₃ - A₁₂:

A = ⎣⎡

3 2 7

0 3 9

-3 5 -8

⎦⎤

A₂₃ represents the element in the second row and third column of matrix A, which is 7. A₁₂ represents the element in the first row and second column of matrix A, which is 2.

Therefore, A₂₃ - A₁₂ = 7 - 2 = 5. Hence, the value of A₂₃ - A₁₂ is 5.

For the last question, we need to determine the correct statement for the given linear system:

⎧

⎨

⎩

-8x₁ + 12x₃ + 4x₂ = 8

2x₁ - 2x₂ + 14x₃ = 0

4x₁ + 2x₂ + 10x₃ = 10

Similar to the first question, we can calculate the determinant of the coefficient matrix A to determine the nature of the solution. After calculating det(A), we find that det(A) = 0.

Since det(A) is zero, the linear system either has no solution or infinite solutions. Therefore, the correct statement for this linear system is "The linear system has no solution."

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Bonnie earns $1750 a month and claims 2 exemptions. Exemptions are a type of tax deduction that reduces the amount of income that is subject to tax.

The more exemptions an individual claims on their W-4 form, the less tax will be withheld from their paycheck. Therefore, claiming 2 exemptions means that Bonnie will have less tax withheld from her paycheck than if she claimed 0 or 1 exemption. The exact amount of tax withheld depends on factors such as her tax bracket, filing status, and other deductions or credits she may be eligible for. Claiming exemptions does not affect how much tax an individual owes for the year; it only affects how much tax is withheld from their paycheck throughout the year.

If too little tax is withheld, the individual may owe money when they file their tax return. If too much tax is withheld, they will receive a refund. Bonnie's specific tax situation will depend on a variety of factors, so it is not possible to determine her exact tax liability without additional information.

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4x (4x+3)(4x-3) is the given expression. Here we can use the formula of special products to multiply the given expression.The formula for special product is (a+b)(a-b)=a²-b² .

Consider a=4x and b=3. Substituting the values in the formula, we get

(a+b)(a-b)=a²-b² (4x+3)(4x-3) = (4x)² - (3)²  = 16x² - 9

The given expression 4x (4x+3)(4x-3) can be simplified as 4x(16x² - 9).The next step is to simplify the given expression. Multiply 4x by 16x² and 4x by -9. We get, 4x(16x²) + 4x(-9) = 64x³ - 36x.

Therefore, 4x (4x+3)(4x-3) simplified is 64x³ - 36x.The expression to be solved is (6x + 7)(x+6). Multiplying the given expression (6x + 7)(x+6), using special product method, we get

(6x + 7)(x+6)=6x(x+6) + 7(x+6)= 6x² + 36x + 7x + 42= 6x² + 43x + 42.

Therefore, (6x + 7)(x+6) = 6x² + 43x + 42.

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a. A function that represents the balance (in dollars) or the future value of the savings account after t years is C. s(t) = 6,000(1 + 0.045/12)^12t.

b) The balance (future value) of the account after 6 years, to the nearest cent, is $7,855.82.

The future value can be computed using the FV formula or function below:

s(t) = 6,000(1 + 0.045/12)^12t

s(t) = 6,000(1 + 0.045/12)^12(6)

= $7,855.8186

= $7,855.82

This future value can also be computed using an online finance calculator as follows:

N (# of periods) = 72 months (6 years x 12)

I/Y (Interest per year) = 4.5%

PV (Present Value) = $6,000

PMT (Periodic Payment) = $0

Results:

Future Value (FV) = $7,855.82

Total Interest = $1,855.82

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The length of MN, to the nearest tenth of a unit is equal to: C. 14.4 units.

In order to determine the missing side length of a geometric figure with the adjacent and hypotenuse side lengths given, you should apply the law of cosine:

C² = A² + B² - 2(A)(B)cosθ

Where:

A, B, and C is the length of side of a given triangle.

By substituting the given side lengths and angle into the law of cosine formula, we have the following;

MN² = LM² + LN² - 2(LM)(LN)cosθ

MN² = 12² + 10² - 2(12)(10)cos(52)

MN² = 144 + 100 - 147.76

MN = √96.24

MN = 9.8 units.

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Answer:

-5b <= -34

Step-by-step explanation:

The inequality phrase, "at most" is same as "less than or equal to". So the algebraic inequality would be -5b <= -34. To solve for b, divide both sides by -5 and make sure to switch the inequality symbol to >= when dividing or multiplying inequalities by a negative number. So b >= 34 / 5.

Answer:

Step-by-step explanation:

Since it's a right angled triangle we can use trigonometric ratios to find the value of x

To find the value of x we can use either sine or cosine

\( \sin(30) = \frac{5}{x} \\ x \sin(30) = 5 \\ x = \frac{5}{ \sin(30) } \\ x = \frac{5}{0.5} \\ \\ \\ \boxed{x = 10}\)

\( \cos(60) = \frac{5}{x} \\ x \cos(60) = 5 \\ x = \frac{5}{ \cos(60) } \\ x = \frac{5}{0.5} \\ \\ \\ \boxed{x = 10}\)

Hope this helps you

Answer:

y=15

Step-by-step explanation:

Answer:

y=15

Step-by-step explanation:

To find y:

8y=120 –––Divide both sides by 8 so you can get y alone

y=15

Answer:

Its C

Step-by-step explanation:

2 more than 2 times means 2+2x

Pls give brainliest

Answer:

c

Steps

x is how much bill ate so bill at 2 times as much and then 2 more.

Answer:

42

Step-by-step explanation:

Answer:

Hint: You are essentially using the transitive property of equality; "If a = b and b = c, then a = c". (Also look at the step by step explanation for more elaboration).

Step-by-step explanation:

Since we know that line AC is equal to 120, that allows us to add lines AB and BC to give us 120. Simply put, 4x + 6 + 7x + 15 = 120. I got 4x + 6 from line AB and 7x + 15 from line BC. You are essentially using the transitive property of equality; "If a = b and b = c, then a = c". All that is left to do is solve to find x and substitute it into 4x + 6. (Sorry if I may have worded it wrong, like putting lines instead of segments. I have been forgetful of what term to use). Hoped it helped. :)

P.S, If you still need help, please respond back.

Answer:

61992

Step-by-step explanation:

Answer:

\(\huge\boxed{Answer\hookleftarrow}\)

\(123 \times 504 \\ = 61992\)

Answer:

can't see proprly

Step-by-step explanation:

The required, (i) number of Gonjas in the rally is 130, and (ii) The difference in fantes and Nzema are 26.

Given:

Total number of people at the rally = 520

Percentage of Fantes = 30%

Percentage of Nzema = 25%

Percentage of Gas = 20%

I) Number of Gonjas:

Number of Gonjas = Total number of people - (Number of Fantes + Number of Nzema + Number of Gas)

Number of Gonjas = 520 - (30% of 520 + 25% of 520 + 20% of 520)

Number of Gonjas = 520 - 390

Number of Gonjas = 130

Therefore, there were 130 Gonjas at the rally.

II) Difference between Fantes and Nzema:

Difference = Number of Fantes - Number of Nzema

Difference = 30% of 520 - 25% of 520

Difference = 26

Therefore, there were 26 more Fantes than Nzema at the rally.

III) Pie chart: has been shown below.

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Answer: 15 and 165

1. The sum of the angles here is 180 degrees and we have 2 values for both the angles, 2x-15 and 11x

2. We make an equation to find the value of x, 2x-15+11x=180

3. After solving we get 195=13x and when divided we get x=15

4. Plug 15 into both angle mesurements and we get <AOB is 15 and <BOC is 165

(a) The point estimate of the mean value of coating thickness is approximately 1.29875.  (b) The point estimate of the median of the coating thickness distribution is 1.44.  (c) The point estimate of the value that separates the largest 10% of all values from the remaining 90% is approximately 1.3375.  (d) The estimated proportion of all thickness values less than 1.6 is 0.75.  (e) The estimated standard error of the estimator used in part (b) is approximately 0.103.

(a) To calculate a point estimate of the mean value of coating thickness, simply find the average of the observations. Add up all the values and divide by the number of observations:

0.85 + 0.88 + 0.88 + 1.02 + 1.09 + 1.18 + 1.29 + 1.31 + 1.39 + 1.49 + 1.59 + 1.62 + 1.65 + 1.71 + 1.76 + 1.83 = 20.78

Divide 20.78 by the number of observations (16):

20.78 / 16 ≈ 1.29875

So, the point estimate of the mean value of coating thickness is approximately 1.29875.

(b) To calculate a point estimate of the median of the coating thickness distribution, arrange the observations in ascending order and find the middle value. Since we have an even number of observations, take the average of the two middle values:

0.85, 0.88, 0.88, 1.02, 1.09, 1.18, 1.29, 1.31, 1.39, 1.49, 1.59, 1.62, 1.65, 1.71, 1.76, 1.83

The middle two values are 1.39 and 1.49. Take their average:

(1.39 + 1.49) / 2 = 1.44

So, the point estimate of the median of the coating thickness distribution is 1.44.

(c) To calculate a point estimate of the value that separates the largest 10% of all values in the thickness distribution from the remaining 90%, multiply the number of observations (16) by 0.10:

16 * 0.10 = 1.6

Since we don't have an exact value at the 10th percentile, we can use linear interpolation to estimate. From the ordered observations, the 10th value is 1.39 and the 11th value is 1.49. Interpolate:

1.39 + (1.49 - 1.39) * (0.10 - 10/16) = 1.39 + 0.1 * (0.10 - 0.625) ≈ 1.39 + 0.1 * (-0.525) ≈ 1.39 - 0.0525 ≈ 1.3375

So, the point estimate of the value that separates the largest 10% of all values from the remaining 90% is approximately 1.3375.

(d) Since we don't know the values of μ and σ, we cannot directly calculate the probability. However, we can estimate it using the given data. Count the number of observations that are less than 1.6:

1.02, 1.09, 0.85, 0.88, 0.88, 1.18, 1.29, 1.31, 1.39, 1.49, 1.59, 1.62

There are 12 observations that are less than 1.6. Divide this by the total number of observations (16):

12 / 16 = 0.75

So, the estimated proportion of all thickness values less than 1.6 is 0.75.

(e) The estimated standard error of the estimator used in part (b), the median, is given by the formula:

SE = 1.253 * (IQR / √n)

Where IQR is the interquartile range, and n is the number of observations.

First, find the IQR. To do this, find the 75th percentile (Q3) and the 25th percentile (Q1):

Q3 = 1.62
Q1 = 1.29

IQR = Q3 - Q1 = 1.62 - 1.29 = 0.33

Now, substitute the values into the formula:

SE = 1.253 * (0.33 / √16) = 1.253 * (0.33 / 4) ≈ 0.103

So, the estimated standard error of the estimator used in part (b) is approximately 0.103.

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The total number of girls in Class B is 7

Let's solve the problem step by step:

We know that the number of boys in both classes is 26. Since the problem states that there are 4 more girls than boys in Class A, we can subtract 4 from the total number of students in Class A to find the number of boys in Class A. This gives us (26 - 4) = 22 boys in Class A.

Since the total number of boys and girls in both classes is 49, we can subtract the number of boys from this total to find the number of girls. Thus, there are (49 - 26) = 23 girls in both classes.

Now, we are given that in Class B, there are twice as many boys as girls. So, let's assume the number of girls in Class B is 'x'. Therefore, the number of boys in Class B would be 2x.

Adding the number of girls and boys in Class B, we get x + 2x = 3x.

We know that the total number of girls in both classes is 23, so we can set up the equation 3x = 23.

Dividing both sides of the equation by 3, we find x = 23/3 ≈ 7.67.

Since the number of girls must be a whole number, we round down to the nearest whole number. Therefore, the number of girls in Class B is 7.

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In the standard normal distribution N(0,1), the cumulative distribution function (CDF) is well-known and can be denoted as Φ(z), where z is the standardized variable.

The first quartile, denoted as Q1, is the value of z for which the cumulative proportion is 0.25. Mathematically, we have:

Φ(Q1) = 0.25

Using a standard normal distribution table or a calculator, we can find that Q1 is approximately -0.6745.

Similarly, the third quartile, denoted as Q3, is the value of z for which the cumulative proportion is 0.75. Mathematically, we have:

Φ(Q3) = 0.75

Using a standard normal distribution table or a calculator, we can find that Q3 is approximately 0.6745.

Therefore, the quartiles of the standard normal distribution N(0,1) are Q1 = -0.6745 and Q3 = 0.6745.

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The example for a discrete sample space among the options given is option c, which is the number of possible values of heights of students. A discrete sample space refers to a set of possible outcomes that can be counted or listed, and this is the case with the possible values of heights of students.

On the other hand, options a, b, and d do not represent a discrete sample space because they involve continuous variables that can take on any value within a range, such as the number of outcomes when 100 coins are tossed or the maximum temperature recorded on a day. Overall, it is important to understand the concept of sample space in probability theory and how it relates to the nature of variables and possible outcomes.
a. Number of outcomes when 100 coins are tossed together.

Discrete sample spaces consist of a finite or countable number of outcomes, whereas continuous sample spaces have an infinite number of possible outcomes. In this case, tossing 100 coins results in a finite number of outcomes (2^100), making it a discrete sample space.

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a) With 95% confidence the proportion of all smart phones that break before the warranty expires is between 0.0525 and 0.0635.

b) If many groups of 1666 randomly selected smart phones are selected, then a different confidence interval would be produced for each group. About 95 percent of these confidence intervals will contain the true population proportion of all smart phones that break before the warranty expires and about 5 percent will not contain the true population proportion.

A smart phone manufacturer is interested in constructing a 95% confidence interval for the proportion of smart phones that break before the warranty expires. 95 of the 1666 randomly selected smart phones broke before the warranty expired.To calculate the confidence interval for the proportion of smart phones that break before the warranty expires, we must first calculate the point estimate of the population proportion of smart phones that break before the warranty expires:95/1666 = 0.057 (rounded to three decimal places)Then, we have to find the margin of error that is, the maximum distance between the point estimate and the confidence interval limits.

We can do that with the help of the following formula:margin of error = critical value × standard errorThe critical value can be found in the z-table or t-table, depending on the sample size. Since we do not know the population standard deviation, we can use the t-distribution. The degrees of freedom are n − 1 = 1666 − 1 = 1665.Using the t-table with degrees of freedom 1665 and level of significance α = 0.05, the critical value is:t* = 1.96 (rounded to two decimal places)The standard error can be calculated using the following formula:standard error = √[(p-hat (1-p-hat))/n] = √[(0.057(1-0.057))/1666] ≈ 0.0083 (rounded to four decimal places)Finally, we can calculate the confidence interval using the following formula:confidence interval = point estimate ± margin of error confidence interval = 0.057 ± 1.96(0.0083) = (0.0525, 0.0635)The 95% confidence interval for the proportion of all smart phones that break before the warranty expires is between 0.0525 and 0.0635.

If many groups of 1666 randomly selected smart phones are selected, then a different confidence interval would be produced for each group. About 95 percent of these confidence intervals will contain the true population proportion of all smart phones that break before the warranty expires and about 5 percent will not contain the true population proportion.

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Answer:

yea by using a resipe

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

you need eggs, butter, flour, sugar, salt, oil (i prefer olive oil) and baking powder.

fruit if you like them in your sweets.

this makes 12 muffins

2 cups flour

3 tsps baking powder

1/2 tsp salt

3/4 cup sugar

1 egg

1 cup milk

1/4 cup oil

preheat oven. i usually do 350 F, increase the temperature if youd like them to cook faster but keep in mind youll need to check on them often with increased heat.

stir together your dry ingridents and in a seperate bowl beat your egg with a fork. stir in the milk and oil with the egg.

pour into your dry ingriedeints until everything is well mixed.

bake until golden

if you like fruit id suggest blueberries, 1 cup

The first graph is the exponential function.

The exponential function serves as the  positive-valued function with respect to real variable. and  the values denoted as X which is exponential is  all real numbers.

Analyzing the first graph, moving down the graph, we can see that  x value increases.

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Answer:

First Graph

Step-by-step explanation:

Edge

Answer:

-8

Step-by-step explanation:

I’ll substitute x for the blank space:

-2 = x + 6

-2 - 6 = x

x = -8

-8 + 6 = -2 ✅

Answer:

y = x + 3

y = 3x + 1

Step-by-step explanation:

This does it in two equations.

y = x + 3 and  y = 3x + 1 equation will send 2 different lines through the coins to capture them

using the slope intercept equation,

y = mx + b

m = slope

b = y-intercept

let's pick 2 coordinate from the graph,

(-2, 1)(-1, 2)

m = 2 - 1 / -1 - (-2)  = 1 / 1 = 1

1 =  -2 + b

b = 3

Therefore,

y = x + 3

let check for another equation that will work for another line. Let's use the coordinates (-1, -2)(0, 1) to find slope.

Therefore,

m = 1 - (-2) / 0 - (-1) = 3 / 1 = 3

y = 3x + b

1 = 3(0) + b

b = 1

y = 3x + 1

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The percentage strength of neomycin in the final compounded product is approximately 2.5%.

To determine the percentage strength of neomycin in the final compounded product, we need to calculate the weight of neomycin in the cream and divide it by the total weight of the cream.

Neomycin (5%) cream: 30g

The neomycin content is 5% of the total cream weight. To find the weight of neomycin in the cream, we multiply the cream weight by the neomycin percentage:

Weight of neomycin = 30g × 0.05 = 1.5g

Now, to calculate the percentage strength of neomycin in the final compounded product, we divide the weight of neomycin by the total weight of the cream and multiply by 100:

Percentage strength of neomycin = (Weight of neomycin / Total weight of cream) × 100

Percentage strength of neomycin = (1.5g / 60g) × 100 ≈ 2.5

Therefore, the percentage strength of neomycin in the final compounded product is approximately 2.5%.

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