PLS HELP! WILL BE MARKING BRAINLIEST!!!!!!!!

Answer: 8 hours

Step-by-step explanation:  240 mph ÷ 30 = 8 hours

The solutions to the quadratic equation f(x) = x² + 10x - 1 are x = -5 + √26 and x = -5 - √26

To solve the quadratic equation f(x) = x² + 10x - 1

we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

For the given equation, a = 1, b = 10, and c = -1.

Substituting these values into the quadratic formula:

x = (-(10) ± √((10)² - 4(1)(-1))) / (2(1))

= (-10 ± √(100 + 4)) / 2

= (-10 ± √104) / 2

Simplifying further:

x = (-10 ± 2√26) / 2

= -5 ± √26

Therefore, the solutions to the quadratic equation f(x) = x² + 10x - 1 are:

x = -5 + √26 and x = -5 - √26

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By evaluating a proportional relation, we can see that if 10 fiction books are sold, then 13 non-fiction books are sold.

Here we know that 3 fiction books are sold for every 4 non-fiction books sold.

Then if x fiction books are sold, the number of non-fiction books sold are given by the proportional relation:

y = (4/3)*x

Here we know that 10 fiction books are sold, so x = 10, replacing that we will get:

y = (4/3)*10 = 40/3 = 13.33

So 13 non-fiction books are sold.

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Answer:

is this question in Spanish?

Answer:

The first choice is correct. ii only.

Step-by-step explanation:

A rigid transformation changes the location of the shape without changing its size. There are three basic rigid transformations: reflections, rotations, and translations.

We are given these properties:

i. Increases or decreases the size of the figure

ii. Moves the location of the figure.

iii. Changes the shape of the figure.

Let's analyze each choice below:

O ii only . This is true. The other two properties are non-rigid transformations. Correct

O i and ii . This is not true. Increasing or decreasing the size of the figure is a non-rigid transformation. Incorrect.

O ii and iii. Changing the shape of the figure is a non-rigid transformation. Incorrect.

O i, ii, and iii. Properties i and iii are non-rigid transformation. Incorrect.

Answer:

y=3x+4 I think I am correct hola amigo señorita a person in my class is called adiola adiola adiola hah

Answer:

Its inconsistent

Step-by-step explanation:

If you are doing 5.11 Unit Test: Systems of Equations - Part 1 from K12, this is your answer

The graphs of the lines do not intersect, so the graphs are parallel and there is no solution. Since there are no solutions, its inconsistent.

If it has at least ONE solution, its consistent.

If it has EXACTLY ONE solution, its consistent in dependable

If it has INFINITE AMOUNT of solutions, its consistent dependable

Answer:

a.12.6   b.8.0

Step-by-step explanation:

Answer:

6. x + 6

7. −2.6y + 86.5

Answer:

Option (1) and (3)

Step-by-step explanation:

Properties for the similarity of two figures,

1). Angles of the figures should be same.

2). Corresponding sides of both the figures should be proportional.

Since all the pairs have same angles, we will use the second property to prove these polygons similar.

Option (1)

If both the polygons are similar,

\(\frac{3}{7.5}=\frac{5}{12.5}\)

\(\frac{1}{2.5}=\frac{1}{2.5}\)

Since, sides are proportional,

Both the polygons are similar.

Option (2)

If the given triangles are similar,

Ratio of the sides of both the triangles will be proportional,

\(\frac{18}{8}= \frac{24}{15}\)

\(\frac{19}{4}=\frac{8}{5}\)

But \(\frac{19}{4}\neq \frac{8}{5}\)

Therefore, triangles are not similar.

Option (3)

If both the rectangles are similar,

\(\frac{22}{13.75}=\frac{16}{10}\)

1.6 = 1.6

True.

Therefore, both the rectangles are similar.

Option (4)

If both the triangles are similar,

\(\frac{8}{5}=\frac{7}{5}\)

1.6 = 1.2

But 1.6 ≠ 1.2

Therefore, these triangles are not similar.

Let's start by setting up some equations based on the given information.
Let's call the width of the rectangle "w" and the length "l". We know that:
l = 2w - m  (since the length is "m less than twice its width")

When we add "m" to the width, we get a square with an area of:
(w + m)^2 =
We can set up another equation based on the fact that the area of the original rectangle is:
A = lw =
Now, we can use the information we have to solve for the dimensions of the original rectangle. We can start by simplifying the equation for the area of the square:
(w + m)^2 =
w^2 + 2wm + m^2 =
Now we can substitute our expression for "l" in terms of "w" and "m":
w(2w - m) =
Expanding this out gives us:
2w^2 - wm =
We can substitute this expression for "lw" in our equation for the area of the square:
2w^2 - wm =
w^2 + 2wm + m^2 =
Now we can simplify this equation by expanding out the square on the left side:
2w^2 - wm =
w^2 + 2wm + m^2 =
2w^2 - wm =
w^2 + 2wm + m^2 =
w^2 + wm + m^2 =
Now we can solve for "m" by subtracting the first equation from the second:
3wm + m^2 =
Subtracting "w^2" from both sides gives us:
wm + m^2 =
Now we can solve for "m" using the quadratic formula:
m =
We can use this value for "m" to solve for the dimensions of the original rectangle. Substituting into our equation for "l" in terms of "w" and "m", we get:
l = 2w - m =
And substituting into our equation for the area of the rectangle, we get:
A = lw =
So the dimensions of the original rectangle are:
Width: w =
Length: l =

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Answer:

I believe its 20% not exactly sure tho.

Step-by-step explanation:

You're welcome.

It's easy it's : 7.50=750% 9.00=900

good luck!:)

The probability that the two given players play each other at any point in the tournament is 1/105.

It is a measure of the likelihood or chance of an event occurring, expressed as a number between 0 and 1, where 0 indicates that the event is impossible, and 1 indicates that the event is certain.

In probability theory, we use probability to quantify the uncertainty associated with a particular event or outcome. For example, if we toss a fair coin, the probability of getting heads is 0.5, because there are two possible outcomes (heads or tails) and each outcome has an equal chance of occurring.

Let's assume the two given players are player A and player B.

In the first round, player A has to be paired with one of the 15 remaining players. The probability of this happening is 1/15.

Assuming player A wins their first match, they will be paired with one of the 7 remaining players in the second round. The probability of player B being matched up with player A at this point is 1/7.

So the probability of player A and player B playing each other in the tournament is the product of the probabilities of these two events occurring:

P(A and B play each other) = P(A and B are paired in the first round) × P(B is paired with A in the second round, assuming A wins the first round)

= (1/15) × (1/7)

= 1/105

Therefore, the probability that the two given players play each other at any point in the tournament is 1/105.

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a)The eigenvalues of A are λ1 = -4,  λ2 = -4,  λ3 = -4,  λ4 = -2

b)The orthonormal eigenbasis of matrix A is \($\begin{pmatrix}0&-1&0&0\\0&0&-1&0\\0&0&0&-1\\1&0&0&0\end{pmatrix}$\).

Given a symmetric matrix A = \($\begin{pmatrix}-4&0&0&-2\\0&-4&-2&0\\0&-2&-4&0\\-2&0&0&-4\end{pmatrix}$\).

Step 1: The eigenvalues of A is given by |A- λI| = 0

where I is the identity matrix of the same order as A.

|A- λI| = \($\begin{vmatrix}-4- λ&0&0&-2\\0&-4- λ&-2&0\\0&-2&-4- λ&0\\-2&0&0&-4- λ\end{vmatrix}$\)

Expanding the above determinant along the first column, we get:

|A- λI| = \($(-1)^1(-4- λ)\begin{vmatrix}-4- λ&-2&0\\-2&-4- λ&0\\0&0&-4- λ\end{vmatrix} + 2\begin{vmatrix}0&0&-2\\-4- λ&-4- λ&0\\-2&0&-4- λ\end{vmatrix}$\)

|A- λI| =\($(-1)^1(-4- λ)\begin{vmatrix}-4- λ&-2\\-2&-4- λ\end{vmatrix}(−4−λ)2 + 2(−2)\begin{vmatrix}-4- λ&-4- λ\\-2&-4- λ\end{vmatrix}(−4−λ)3|A- λI| \\= $(λ+4)^3(λ+2)$\)

Hence, the eigenvalues of A are

λ1 = -4,

λ2 = -4,

λ3 = -4,

λ4 = -2

Step 2: We need to find the eigenvectors of matrix A associated with each eigenvalue obtained in step 1.

By solving the equation Ax = λx, we can obtain the eigenvectors.

x1 = \($\begin{pmatrix}0\\0\\0\\1\end{pmatrix}$, \\x2 = $\begin{pmatrix}-1\\0\\0\\0\end{pmatrix}$, \\x3 = $\begin{pmatrix}0\\-1\\0\\0\end{pmatrix}$, \\x4 = $\begin{pmatrix}0\\0\\-1\\0\end{pmatrix}$\)

Now we have found the eigenvectors of matrix A associated with each eigenvalue obtained in step 1.

To obtain the orthonormal eigenbasis of A, we need to normalize these eigenvectors.

The eigenvectors of A form an orthonormal eigenbasis for A when they are normalized.

To normalize the eigenvectors, we need to divide each eigenvector by its corresponding length.

To obtain the lengths of each eigenvector, we use the formula;

\($||x|| = \sqrt{\sum_{i=1}^{n}x_i^2}$\)

where n is the order of the matrix.

Here n = 4 and ||x|| is the length of each eigenvector.

The length of eigenvector x1 is ||x1|| = 1

The length of eigenvector x2 is ||x2|| = 1

The length of eigenvector x3 is ||x3|| = 1

The length of eigenvector x4 is ||x4|| = 1

Hence, the orthonormal eigenbasis of matrix A is \($\begin{pmatrix}0&-1&0&0\\0&0&-1&0\\0&0&0&-1\\1&0&0&0\end{pmatrix}$\)

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Answer:

-32.4

Step-by-step explanation:

What you do is the -4 x the 8. after that you should get 32. Then you do 4 x the 1. Hence, you should get 4. Because of that you put the 32 and 4 together. your final answer is -32.4

Answer:

The answer is A. -32.4

Step-by-step explanation:

What you do is the -4 x the 8. after that you should get 32. Then you do 4 x the 1. Hence, you should get 4. Because of that you put the 32 and 4 together. your final answer is -32.4

Hope this helps  :)

Answer:

200 in^2

Step-by-step explanation:

If it only asking the area in yellow, then it is consisted of two squares, for each square, it is 10in * 10 in for area, so for two squares, the area will be 2*10*10 = 200 in^2.

False. The margin of error only accounts for sampling variability (the fact that my sample will be different that many other people's and therefore provide different statistics.

Statistics is a technique for interpreting, analyzing, and summarizing data in mathematics. In light of these characteristics, the various statistical types are divided into: Statistics that are descriptive and inferential. We analyze and understand data based on how it is presented, such as through graphs, bar graphs, or tables.

Inferential statistics, which draws conclusions from information using statistical tests like the student's t-test, is one of the two main statistical methods used in data analysis. Descriptive statistics presents data using indices like mean and median.

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To show that β=3α, where β represents the volumetric thermal expansion coefficient and α represents the linear thermal expansion coefficient, we can calculate the infinitesimal change in volume (dv) of a cube with sides of length l when the temperature changes by dt.

The linear thermal expansion coefficient α is defined as the fractional change in length per unit change in temperature. Similarly, the volumetric thermal expansion coefficient β is defined as the fractional change in volume per unit change in temperature.

Let's consider a cube with sides of length l. The initial volume of the cube is \(V = l^3\). Now, when the temperature changes by dt, the sides of the cube will also change. Let dl be the infinitesimal change in length due to the temperature change.

The infinitesimal change in volume, dv, can be calculated using the formula for differential calculus:

\(\[dv = \frac{{\partial V}}{{\partial l}} dl = \frac{{dV}}{{dl}} dl\]\)

Since \(V = l^3,\) we can differentiate both sides of the equation with respect to l:

\(\[dV = 3l^2 dl\]\)

Substituting this back into the previous equation, we get:

\(\[dv = 3l^2 dl\]\)

Now, we can express dl in terms of dt using the linear thermal expansion coefficient α:

\(\[dl = \alpha l dt\]\)

Substituting this into the equation for dv, we have:

\(\[dv = 3l^2 \alpha l dt = 3\alpha l^3 dt\]\)

Comparing this with the definition of β (fractional change in volume per unit change in temperature), we find that:

\(\[\beta = \frac{{dv}}{{V dt}} = \frac{{3\alpha l^3 dt}}{{l^3 dt}} = 3\alpha\]\)

Therefore, we have shown that β = 3α, indicating that the volumetric thermal expansion coefficient is three times the linear thermal expansion coefficient for a cube.

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Answer:

23.2 cm

Step-by-step explanation:

For the angle of 53.2 deg, x is the opposite leg. The hypotenuse is 29 cm.

sin A = opp/hyp

sin 53.2 deg = x/29 cm

x = 29 cm * sin 53.2 deg

x = 23.2 cm

it is not possible for det A to equal 3 if the entries of both A and A^-1 are integers.

The determinant of a matrix and its inverse are multiplicative inverses of each other, meaning that det(A)det(A^-1) = 1. If det A = 3, then det(A^-1) = 1/3. However, since the entries of both A and A^-1 are integers, this is a contradiction, as the determinant of a matrix with integer entries must also be an integer. Therefore, it is impossible for det A to equal 3 in this scenario.

it explains the reasoning behind the solution and provides a deeper understanding of the concept of determinants.

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Answer:

562 = 85x +52

x is the number of days

Veronica traveled for 7 days

Step-by-step explanation:

562 = 85x + 52

510 = 85x Subtract 52 on both sides

6 = x Divide by 85 to isolate x

Even though Veronica only had to drive 52 miles on the last day of her trip, it still counts as a day of driving. Hence, she traveled 7 days in total.

Answer:

its a variable it stands for a number that you have to figure out yourself

Step-by-step explanation:

Answer:

b is the y-intercept

Step-by-step explanation:

In case you dont know what the y-intercept is.

The y-intercept of this line is the value of y at the point where the line crosses the y-axis.

To simplify the process of expanding a binomial of the type (a+b) n (a + b) n, use Pascal's triangle. The same numbered row in Pascal's triangle will match the power of n that the binomial is being raised to.

A triangular array of binomial coefficients known as Pascal's triangle can be found in algebra, combinatorics, and probability theory. Even though other mathematicians studied it centuries before him in India, Persia, China, Germany, and Italy, it is called after the French mathematician Blaise Pascal in a large portion of the Western world. Traditionally, the rows of Pascal's triangle are listed from row =0 at the top (the 0th row). Each row's entries are numbered starting at k=0 on the left and are often staggered in relation to the numbers in the next rows. The triangle could be created in the manner shown below: The top row of the table, row 0, contains one unique nonzero entry.

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Answer:

b po sana po maka tulong

Step-by-step explanation:

pa brainliest po

Since in the figure, m || n, the value of x is equal to 13.

In Mathematics, corresponding angles can be defined as a postulate (theorem) which states that corresponding angles are always congruent when the transversal intersects two (2) parallel lines. This ultimately implies that, the corresponding angles will be always equal (congruent) when a transversal intersects two (2) parallel lines.

By applying corresponding angles theorem to lines a and b, we have the following:

∠m ≅ ∠n

7x - 1 = 8x - 14

8x - 7x = 14 - 1

x = 13

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Answer:

what is this pls isit a question

The Answer is x2=4, x1=0, and x3=0; S1=1, S2=0. Therefore, S2=0 is basic and S1=1 is nonbasic. x1=0 is basic and X1=6, X2=4, and X3=0 are nonbasic.

The basic feasible solution from the given tableau X1 X2 Хз S1 S2 Z 0 0160 6 -1 1 1 0 148 2 4 0 -6 -10 -5 0 0 1143 is:x2=4, x1=0, and x3=0; S1=1, S2=0. Therefore, S2=0 is basic and S1=1 is nonbasic. x1=0 is basic and X1=6, X2=4, and X3=0 are nonbasic. The basic feasible solution is achieved when all the constraints in a linear programming problem are met. The constraints can be in the form of equations or inequalities. The linear programming problem provides the optimal values for a given objective function. The optimal values are determined by the constraints that are involved in the problem. In the given problem, X2 and S1 are basic, and X1, Xx3, and S2 are nonbasic. Indicate which variables are basic and which are nonbasic.The variables that are basic and nonbasic can be calculated from the tableau. The basic variables are those that have the coefficients of 1 in the final column. The nonbasic variables are those that have the coefficients of 0 in the final column. Therefore, x2=4, x1=0, and x3=0; S1=1, S2=0. Therefore, S2=0 is basic and S1=1 is nonbasic. x1=0 is basic and X1=6, X2=4, and X3=0 are nonbasic.

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A unit tangent vector to the level curve at the point (5,2) with a positive x component is approximately <0.128, -0.991>.

To find the unit tangent vector, we first need to calculate the gradient of the function f(x, y) = -2e^(-5x) sin(y). The gradient vector represents the direction of steepest ascent of the function.

The gradient of f(x, y) is given by ∇f(x, y) = (∂f/∂x, ∂f/∂y). Taking the partial derivatives, we have:

∂f/∂x = 10e^(-5x) sin(y)

∂f/∂y = -2e^(-5x) cos(y)

At the point (5, 2), we evaluate these partial derivatives to obtain:

∂f/∂x = 10e^(-25) sin(2)

∂f/∂y = -2e^(-25) cos(2)

Next, we normalize the gradient vector by dividing it by its magnitude to obtain a unit tangent vector:

T = (∂f/∂x, ∂f/∂y) / ||(∂f/∂x, ∂f/∂y)||

Calculating the magnitudes and performing the division, we find that the unit tangent vector with a positive x component is approximately <0.128, -0.991>.

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