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In frustration, a junior drops the APUSH textbook 1.5 m. How long will it take to hit the ground?
Answers
The time taken for the APUSH textbook to hit the ground is determined as 0.55 seconds.
What is time of motion?The time of motion of an object is the time taken for the object to travel from its initial point to the final point.
The time taken for the APUSH textbook to hit the ground is calculated as follows;
t = √(2h/g)
where;
h is the height of fall of the textbookg is acceleration due to gravityt = √(2 x 1.5/9.8)
t = 0.55 seconds
Thus, the time taken for the APUSH textbook to hit the ground is determined as 0.55 seconds.
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Related Questions
on a whim, you are trying to stand in a cart attached to a strong spring. the spring is compressed and then released, and you oscillate back and forth, trying to maintain your balance. there is a sand bag in the cart.
Answers
The effect that this will have on the amplitude of your oscillation.is b.) The amplitude of oscillation will decrease.
What is the amplitude?The amplitude of an oscillating system is the magnitude of change in the oscillating variable with each oscillation. Sound waves in air, for example, are oscillations in atmospheric pressure, and their amplitudes are proportional to the pressure change during one oscillation.
When a wave travels through a medium, it loses energy as it moves. As the distance between the wave and its source grows, it spreads out over a larger and larger area. As the wave spreads through the medium, it loses energy and its amplitude decreases.
In this case, at the point of equilibrium, the cart and the skater will have maximum kinetic energy. By dropping the same bag, the energy is reduced. The amplitude of an oscillating pendulum decreases with time because of friction due to air
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On a whim, you are trying to stand in a cart attached to a strong spring. The spring is compressed and then released, and you oscillate back and forth, trying to maintain your balance. There is a sand bag in the cart.
At the instant you pass through the equilibrium (x=0) location of the spring, you drop the sandbag onto the ground, out of the cart.
Question: If you drop the sand bag out of the cart right at the equibrium location, what effect will that have on the amplitude of your oscillation? (choose correct choice):
a.) The amplitude of oscillation will increase.
b.) The amplitude of oscillation will decrease.
c.) There will be no effect on the amplitude.
If you double the current through a resistor, by what factor does the power dissipated by the resistor change?.
Answers
If you double the current through a resistor, the power dissipated by the resistor change by factor of 4.
What is electric current?The stream of positive charges which flow from the positive terminal to the negative terminal of the battery attached in a circuit.
Power dissipated through a resistor is related to current as
P =I²R
When the current is doubled, the new power will be
P' = (2I)²R
P' = 4 I²R
P' = 4P
Thus, the power change by the factor of 4.
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the product of m1m2 in the formula for gravitational force is always
negative, because the product of two positive numbers is negative.
positive, because the product of two positive numbers is positive.
positive, because the product of two negative numbers is positive.
negative, because the product of two negative numbers is negative.
Answers
Answer:
The correct answer is the second option
Explanation:
The formula in question (for gravitational force) is provided below
F = G.m₁.m₂/r²
Where
F = force of gravity
G = gravity constant (6.674 × 10⁻¹¹ m.kg⁻¹.s⁻²)
m₁ and m₂ = are the masses of the objects
r² = distance between the centers of the two objects
From the above, it can be deduced that m₁ and m₂ are masses and hence can only be positive. Positives multiplied together only gives positive, thus the second option is correct.
In an electrical circuit, two resistors of 2Ω & 4Ω have been connected in series to a 6V battery. The heat dissipated by the 4Ω resistor in 5s will be
Answers
R= 2+4=6Ω
in series connection, same current and different voltage
total voltage= total current × total resistance
6=I×6
I=6/6= 1A
voltage across 4Ω resistor= 1×4=4v
Therefore, heat dissipated by the 4Ω resistor in 5s= (v²/R)×t= (4²/4)× 5 = 16/4 × 5 = 20J
Imagine driving down the road and you suddenly doubled your velocity. What then happens to your overall kinetic energy?
it is halved
it remains unaffected
it is doubled
it is quadrupled
Answers
different between SI system and CGS system
Answers
Answer:The SI system, for this reason, is also called the MKS system. CGS system: On the other side or the second self-consistent system uses centimetres, grams and seconds for length, mass and time.
Explanation:
7. The S.l. unit for force is
A. kg
C. m/s
B. m/s2
D. N
Answers
How is energy stored and transferred at 5 different points during the launch and flight of the trebuchet?
Answers
The way that the energy stored and transferred at 5 different points during the launch and flight of the trebuchet are:
Energy storage during the loading phase: When the trebuchet is loaded, the counterweight and the projectile are both raised to a high point on the frame. This increases the gravitational potential energy of the counterweight and the projectile.Energy transfer during the tensioning phase: As the trebuchet is tensioned, the energy stored in the counterweight and the projectile is transferred to the tensioned ropes, cables or chains. This causes the ropes or chains to stretch and store elastic potential energy.Energy transfer during the launch phase: As the trebuchet is released, the energy stored in the tensioned ropes, cables or chains is transferred to the counterweight and the projectile. The counterweight falls, releasing its gravitational potential energy and propelling the projectile forward.Energy transfer during the flight of the projectile: As the projectile flies through the air, the energy stored in the projectile is transferred to the air through friction and air resistance. This causes the projectile to slow down and lose altitude.Energy transfer during the impact phase: As the projectile strikes its target, the energy stored in the projectile is transferred to the target, causing damage or destruction. Any remaining energy in the projectile is absorbed by the target or dissipated as heat or sound.What is the Energy about?Energy is a property of matter that allows it to do work. It is a scalar quantity, meaning it has only magnitude and no direction.
Energy can take many forms, including kinetic energy (the energy an object possesses due to its motion), potential energy (the energy an object possesses due to its position or state), and thermal energy (the energy an object possesses due to its temperature).
Therefore, Energy can also be classified as being either non-renewable or renewable. Non-renewable energy sources, such as fossil fuels, are finite and will eventually run out, whereas renewable energy sources, such as solar or wind power, are replenished naturally and can be used indefinitely.
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Can someone help
Explain what an ellipse is, and how they can change.
Answers
Answer:
In mathematics, an ellipse is a plane curve surrounding two focal points, such that for all points on the curve, the sum of the two distances to the focal points is a constant.
I don’t know how ellipse change tho sorry
typically in instrumentation and control cable only one end is grounded and the at the other end is isolated by folding it back and taping over it.
Answers
Typically in instrumentation and control cable installations, it is common practice to ground only one end of the cable, while the other end is isolated by folding it back and taping over it.
The purpose of grounding one end of the cable is to provide a reference point for electrical potential and to minimize the risk of electrical interference or noise affecting the signals being transmitted through the cable. By grounding one end, any unwanted electrical currents or potential differences can be safely discharged or directed to a common ground.
On the other hand, the isolated end of the cable is folded back and taped over to prevent any contact or connection with other electrical components or ground points. This helps to maintain the integrity of the signal being transmitted and avoids the risk of creating unwanted ground loops or electrical shorts.
By grounding one end and isolating the other, the instrumentation and control cable installation ensures proper signal transmission, reduces the likelihood of interference, and helps maintain the overall electrical safety and performance of the system.
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Acceleration = 2.8 m/s^2
If after take-off, the jet continues to accelerate at the same rate for another
15 s, how fast will it be going at that time?
Answers
Speed and velocity are similar in term of their unit. the speed of the jet is 42 m/s
What is Speed ?
Speed can simply be defined as how fast an object moves. It is the distance covered per time taken.
Given that acceleration = 2.8 m/s² and If after take-off, the jet continues to accelerate at the same rate for another 15 s, to know how fast it will be going at that time, we will use acceleration formula.
Acceleration = Velocity / time
speed = acceleration × time
speed = 2.8 × 15
Speed = 42 m/s
Therefore, the speed or the velocity of the jet is 42 m/s
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How did frank capra and john ford interact with the star system?
Answers
Both Frank Capra and John Ford, renowned filmmakers of the classical Hollywood era, had their own unique ways of interacting with the star system prevalent during that time.
1. Frank Capra:
Frank Capra was known for his directorial work on films that often focused on the common man and celebrated American values. He had a collaborative approach to working with stars, particularly his frequent collaborator Jimmy Stewart. Capra believed in creating a comfortable and supportive environment on set, allowing his actors to explore and bring their characters to life. He had a reputation for nurturing the talents of his actors and enabling them to deliver memorable performances.
2. John Ford:
John Ford, a highly influential filmmaker known for his Westerns and sweeping epics, had a different style of interaction with the star system. Ford had a long-standing collaboration with actor John Wayne, who became synonymous with his films. Wayne's rugged, masculine persona was frequently featured in Ford's Westerns, such as "Stagecoach" and "The Searchers."
Both Capra and Ford recognized the significance of stars in their films, using them as vehicles to connect with audiences. They employed different strategies to collaborate with their stars, whether it was Capra's nurturing approach or Ford's ability to harness and enhance their iconic qualities.
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Suppose that the mirror is moved so that the tree is between the focus point F and the mirror. What happens to the image of the tree?
1. the image moves behind the curved mirror.
2.The image stays the same.
3.The image appears taller and on the same side of the mirror.
4. The image appears shorter and on the same side of the mirror.
Answers
When the mirror is moved so that the tree is between the focus point F and the mirror, the image appears shorter and on the same side of the mirror.This happens because of the phenomenon known as Reflection of Light. The mirror reflects light in such a way that it appears as if the light is coming from behind the mirror.
As a result, a virtual image is formed behind the mirror. This virtual image is similar in size and shape to the object being reflected.The characteristics of the image produced by a mirror depends on the location of the object relative to the mirror. There are two types of mirrors that we use to reflect light: Concave and Convex. In the case of a concave mirror, the image produced can either be real or virtual. When an object is placed between the focus point and the mirror, a virtual and erect image is produced. This image is smaller than the actual object and appears behind the mirror. The image is virtual because the light rays do not converge at the location of the image. In the case of a convex mirror, the image produced is always virtual, erect, and smaller than the actual object. As the object moves closer to the mirror, the image gets smaller. If the object is moved to a position where it is between the focus point and the mirror, the image produced will appear shorter and on the same side of the mirror.For such more question on Concave
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Describe how rainforests are more diverse than arctic ecosystems. Give examples of ecological diversity, species diversity, and genetic diversity.
Answers
Answer:
Rainforests contain around 50% of all life on Earth and only take up 6% of the Earths surface area. It contains more species of plant and animals than any other ecosystem. It's climate and geography lend it to growing more plant life which sustains many small animals. The arctic is inhospitable to most species because of the extreme cold. It's food webs do not sustain themselves well as there are fewer species at the bottom the the chain. The genetic variations are greater at the equator than the arctic giving the organisms a greater chance to survive.
Rainforests are far more diverse than arctic ecosystems because of the amount of sunlight and the rain it receives throughout the year.
What are biomes?
Biomes can be defined as regions specified by particular biological and geographical communities that evolved because of the shared regional climate of that region.
Generally, there are mainly five major types of biomes those are forest desert grassland aquatic, and tundra.
Even though they only cover 6% of the planet's surface, rainforests are home to about 50% of all living. More plant and animal species may be found there than in any other habitat.
The high temperature of the arctic makes it uninhabitable for the majority of creatures. Because there are fewer species at the base of the food chain, its food webs are unable to support themselves.
Because there are more genetic variants around the equator than in the north, species there has a better chance of surviving.
Thus, rainforests are far more diverse than arctic ecosystems.
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What is the equation for the x axis of this FBD
Answers
To find:
The equation for the given FBD.
Explanation:
The net force acting on an object is given by the sum of all the forces acting on the object.
Thus the net force acting on the given object in the vertical direction is given by,
\(F_{net}=F-f\text{ }\to\text{ \lparen i\rparen}\)From Newton's second law, the net force acting on an object is given by,
\(F_{net}=ma\text{ }\to\text{ \lparen ii\rparen}\)Thus from equations (i) and (ii), the equation for the given FBD is given by,
\(F-f=ma\)Final answer:
Thus the correct answer is option C.
if i raise a 2 kg book 0.8m over my head determine the amount of work that i have done
Answers
If you raise a 2 kg book 0.8m over your head, the amount of work that you have done is 15.68 J
F = m g
F = Force
m = Mass
g = Acceleration due to gravity
m = 2 kg
g = 9.8 m / s²
F = 2 * 9.8
F = 19.6 N
W = F d cos θ
W = Work done
d = Distance
θ = Angle between force and displacement vector
d = 0.8 m
θ = 0
W = 19.6 * 0.8
W = 15.68 J
Therefore, the amount of work that you have done is 15.68 J
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A planet orbits a star in a planetary system, and
it takes 8.0 Earth years for the planet to
complete one revolution. If the mass of the star
is about the same as the mass of the Sun, and
the mass of the planet is the same as the mass
of Earth, the semi-major axis of the planet's
orbit is:
Answers
The semi-major axis of the planet's orbit is equal to 4 AU.
Given the following data:
Period, T = 8.0 Earth years.What is Kepler's third law?Kepler's third law of planetary motion states that the square of any planetary body's orbital period (T) is directly proportional to the cube of its orbit's semi-major axis (a).
Mathematically, Kepler's third law of planetary motion is given by this formula:
\(T^2 =a^3\)
Where:
T is the orbital period.a is the semi-major axis.Substituting the given parameters into the formula, we have;
\(8^2 =a^3\\\\a^3=64\\\\a=\sqrt[3]{64}\)
a = 4 AU.
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A car travels 500 km from home at 35 m/s, then travels back at 43 m/s. Find its average speed.
Answers
The average speed of the car is 35.6m/s
What is average speed?The average speed is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction. It is measured in meter per second
Therefore average speed = total distance / total time taken
The total distance here is 500+ 500= 1000km = 1×10⁶m
the time taken for the first journey = 500×1000/35= 14285.71 seconds
the time taken for traveling back = 500000/43= 11627.91 seconds
total time taken = 14285.71 + 11627.91 = 25913.62seconds
therefore average speed = 1000000/25913.62
= 35.6m/s
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Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ball’s journey will gravity be the greatest force acting on the ball?
Answers
Answer:
When the ball falls down.
A 1.40 mm-diameter ball bearing has 2.20×10^9 excess electrons.
What is the ball bearing's potential? Express your answer with the appropriate units.
Answers
To calculate the ball bearing's potential, we can use the equation for electric potential, which is given by:V = k * (Q / r).The ball bearing's potential is approximately 5.70 × \(10^{-7}\) volts.
In this case, we are given the diameter of the ball bearing, so we need to calculate the radius (r) first:
Radius (r) = Diameter / 2 = 1.40 mm / 2 = 0.70 mm = 0.70 × \(10^{-3}\) m
The excess charge is given as 2.20 × \(10^{9}\) electrons. To convert this to Coulombs, we need to multiply it by the elementary charge (e), which is approximately 1.602 × \(10^{-19}\) C.
Charge (Q) = (2.20 × \(10^{9}\)) × (1.602 × \(10^{-19}\)) C
Now we can calculate the potential (V):where k is the Coulomb constant (k ≈ 8.99 × \(10^{9}\)10^9 \(N m^2/C^2\)),
V = (8.99 × \(10^{9}\) \(N m^2/C^2\)) * [(2.20 × \(10^{9}\)) × (1.602 ×\(10^{-19}\) ) C] / (0.70 × \(10^{-3}\) m)
Calculating this expression gives:
V ≈ 5.70 ×\(10^{-7}\) V
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Two long parallel wires carry currents of 10 A in opposite directions. They are separated by 40 cm. What is the magnitude of the magnetic field in the plane of the wires at a point that is 20 cm from one wire and 60 cm from the other?
A) 3.3 µT
B) 6.7 µT
C) 1.5 µT
D) 67 µT
E) 33 µT
Answers
The magnetic field created by current-carrying wires can be calculated using the Biot-Savart law. In this scenario, we have two long parallel wires carrying currents in opposite directions, which means that their magnetic fields will be in the opposite direction as well. The wires are separated by a distance of 40 cm.
To find the magnetic field at a point that is 20 cm from one wire and 60 cm from the other, we can use the formula:
B = (μ0/4π) * (2I/d)
Where μ0 is the permeability of free space (4π x 10^-7 T*m/A), I is the current, and d is the distance between the wire and the point where we want to find the magnetic field.
For the wire that is 20 cm away, the magnetic field is: B1 = (μ0/4π) * (2 x 10 / 0.2) = 1.2566 x 10^-4 T
For the wire that is 60 cm away, the magnetic field is: B2 = (μ0/4π) * (2 x 10 / 0.6) = 4.1886 x 10^-5 T
Since the wires are carrying currents in opposite directions, their magnetic fields will be in opposite directions as well. The net magnetic field at the point will be the difference between the two fields: B = B1 - B2 = 8.377 x 10^-5 T
Converting to microtesla, we get: B = 83.77 µT
Therefore, the correct answer is D) 67 µT.
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the current in a 50.0-mh inductor changes with time as i = 3.00t2 − 7.00t, where i is in amperes and t is in seconds.
Answers
The main answer to the given question is that the current in the 50.0-mH inductor is given by the equation i = 3.00t^2 - 7.00t, where i is in amperes and t is in seconds.
An explanation for this is that the current in an inductor is proportional to the rate of change of the magnetic field through the inductor. In this case, the magnetic field is changing with time as t increases. The equation given for the current is a polynomial function with a squared term and a linear term. This means that the rate of change of the magnetic field is increasing as time increases. At t=0, the current is -7.00A, and it increases with time. This can be seen by taking the derivative of the given equation, which gives the rate of change of the current with respect to time. Overall, the equation for the current in the inductor provides a mathematical description of the changing magnetic field and the resulting current in the circuit.
Your question is about finding the induced voltage across a 50.0-mH inductor when the current changes with time as i = 3.00t^2 - 7.00t, where i is in amperes and t is in seconds. To find the induced voltage (V) across the inductor, we will use the formula V = L * (di/dt), where L is the inductance and di/dt is the derivative of the current with respect to time.
Step 1: Identify the given values:
Inductance, L = 50.0 mH = 0.050 H
Current function, i(t) = 3.00t^2 - 7.00t
Step 2: Find the derivative of the current with respect to time:
di/dt = d(3.00t^2 - 7.00t) / dt = 6.00t - 7.00
Step 3: Use the formula V = L * (di/dt) to find the induced voltage:
V(t) = 0.050 * (6.00t - 7.00)
Step 4: Simplify the expression:
V(t) = 0.3t - 0.35So, the induced voltage across the 50.0-mH inductor is V(t) = 0.3t - 0.35 volts, where t is in seconds.
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Chase Elliot and William Byron were racing at Daytona Superspeedway. If they
completed the 2.5 mile track in just 65 seconds how fast were they going?
Answers
Chase Elliot and William Byron were running at a speed of 138.8 miles/hr.
What is Speed?
Speed of any moving body is the distance covered by it in a unit time.
Mathematically -
Speed = Distance/Time
Given is that Chase Elliot and William Byron completed the 2.5 mile track in just 65 seconds.
Length of the track [L] = 2.5 miles.
Time taken to complete the run [T] = 65 seconds = 0.018 hr
Therefore, the speed will be -
Speed [S] = Length / Time taken
Speed [S] = L / t = 2.5/0.018 = 138.8 miles/hr
Therefore, Chase Elliot and William Byron were running at a speed of 138.8 miles/hr.
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A physical quantity, G, is defined by G = (Original mass x time)/(change in mass), what is the S.I. unit of G ?
Answers
3/2
m
3
k
g
/
s
2
But is often seen written as
⋅
N
⋅
2/2
m
2
/
k
g
2
Where N is the Newton unit. N=kg ⋅
⋅
m/s 2
2
long-term exercisers often report that __________ exercise rewards are their primary motivation.
Answers
Long-term exercisers often report that intrinsic exercise rewards are their primary motivation.
They are often report that the long-term health benefits and feeling of well-being are their primary motivation for continuing to exercise. While short-term rewards such as weight loss and increased energy are also motivating factors, it is the sustained benefits that keep dedicated exercisers committed to their fitness routine.
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What is the momentum of a car with the mass of 2,000 kg traveling north at a speed of 20 m/s
Answers
Answer:
The answer is
40,000 kgm/sExplanation:
The momentum of an object when given it's mass and velocity can be found by using the formula
momentum = mass × velocityFrom the question
mass = 2000 kg
velocity = 20 m/s
The momentum of the car is
momentum = 2000 × 20
We have the final answer as
40,000 kgm/sHope this helps you
Can you pls answer the 2 questions
Answers
Answer:
1) False, since constant speed means constant velocity, but with constant direction as well. Velocity is speed with direction. When you move in a circle, there are boundaries which means that a constant moving speed will cause the object to veer(move in different directions) to maintain movement, If it doesn't veer, the object will deflect(rebound) off the surface due to friction, and impact force or depending on its physical bond of malleability or density.
2a) Create position vectors by drawing a ray from the center(origin) of the circle to each of your desired points, it's magnitude will be the radius(how convenient). Both of these vectors go from the center of the circle to the position on the circle. In general, the distance from the origin to a point is called the radius vector.
2b)
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
low-friction wheels and as the bullet struck the target, the target with
bullet embedded bullet sped off with a velocity of 6.0 ms.
Calculate the velocity of the bullet just before it hit the stationary
target.
Answers
Answer:
306 m/s
Explanation:
Law of conservation of momentum
m1v1 + m2v2 = (m1+m2)vf
m1 is the bullet's mass so it is 0.1 kg
v1 is what we're trying to solve
m2 is the target's mass so it is 5.0 kg
v2 is the targets velocity, and since it was stationary, its velocity is zero
vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s
plugging in, we get
(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)
(0.1)(v1) + 0 = 30.6
(0.1)(v1) = 30.6
v1 = 306 m/s
The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.
What is momentum ?Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.
Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.
then, m1 u1 + m2 u2 = m1 v1 + m2 v2.
Given m1 = 5 kg
m2 = 0.1 kg
The velocity of the combined mass v = 6 m/s.
The momentum of the target is zero since it was stationary.
(0.1 × u1) = (0.1 + 5)6 m/s
(0.1 × u1) = 30.6 m/s
then u1 = 30.6/0.1 = 306 m/s
Therefore, the velocity of the bullet before hitting was 306 m/s.
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Imagine that you have an isotropic magnetized plasma with T ∥0
=T ⊥0
=T 0
. Double the magnetic field slowly compared to a gyroperiod, but fast compared to the energy transfer time between T ∥
and T ⊥
. What are the new values of T ∥
and T ⊥
(call them T ∥1
and T ⊥1
) ? Now let the plasma sit long enough for T ∥1
and T ⊥1
to mix by collisions and come to an isotropic temperature T 1
, but not long enough for the plasma to exchange energy with the outside world. What is T 1
? Reduce the magnetic field back down to its original value slowly compared to a gyroperiod, but fast compared to the energy transfer time between T ∥
and T ⊥
. What are T ∥2
and T ⊥2
? And after the plasma becomes isotropic, what is T 2
? This process is called 'magnetic pumping'.
Answers
The new values of T∥1 and T⊥1 will be equal to the original isotropic temperature T0.
When the magnetic field is doubled slowly compared to a gyroperiod but fast compared to the energy transfer time between T∥ and T⊥, the plasma remains magnetized, but the magnetic field becomes stronger. Since the energy transfer time between T∥ and T⊥ is much longer than the timescale of magnetic field doubling, the temperature anisotropy is not affected during this process. Therefore, T∥1 and T⊥1 remain equal to T0.
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(e). The three forces shown act on a particle. 65.0N 20.0 N What is the magnitude and direction of the resultant of these three forces?
Answers
The magnitude of the resultant force is 71.2 N and the direction is 24.6 degrees east of north.
To find the resultant force, we can use vector addition. We first add the two forces that are not at right angles, 65.0 N and 20.0 N, using the Pythagorean theorem to find the magnitude of their sum, which is 68.2 N. Then, we add this to the third force, 40.0 N, using vector addition.
To find the direction of the resultant force, we can use trigonometry and find the angle between the resultant force and the north direction, which is 24.6 degrees. The direction can also be described as 65.2 degrees east of west. Therefore, the magnitude of the resultant force is 71.2 N and the direction is 24.6 degrees east of north.
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